Monday
December 22, 2014

Posts by MARKO


Total # Posts: 408

ALGEBRA
NEED TO WRITE AN EXPRESSION AND SOLVE AN AIRPLANE LEFT CHGO WHRE THE TEMP WAS 42 FAREHEIGHT . WHEN IT LANDED ANCHORAGE THE TEMP WAS 60 DEGREE LOWER WHAT WAS THE TEMPERATURE IN ANCHORAGE? 60 - 42 = WOULD IT BE 42 + (-60) = -18
September 14, 2011

ALGEBRA
-5
September 14, 2011

ALGEBRA
-12 + (-6) + 15 + (-2)
September 14, 2011

ALGEBRA
-7 - (-5) -3 =
September 14, 2011

ALGEBRA
-7 - (-5) -3
September 14, 2011

ALGEBRA
-4 -3 = -7 3 - (-2)
September 14, 2011

geometry
u do it
May 11, 2011

Physics
2gh=v^2 2*0.7*g=1.51^2 1.4g=1.51^2 /g 1.4=2.2801g g=1.4/2.2801 g=0.6140081575 m/s^2 1.63m/s^2 is not the correct answer, take for example this: 10=5g What is 'g'? g=10/5=2
February 3, 2011

Pages: <<Prev | 1 | 2 | 3 | 4 | 5

Search
Members