Wednesday

November 25, 2015
Total # Posts: 27

**Chemistry**

Molecules A and B react to produce molecule AB. If 60 mLs of 0.025 M A is added to 18 mLs of 0.175 M B, then how many moles of unreacted A or B will be left over? How many moles of AB will be produced?
*March 22, 2015*

**math**

a pulley is used to lift a mass with a force of 900N to a height of 10 metres in 2 minutes.find the work done by the force and also the power
*February 5, 2015*

**english**

what is a nouns
*September 22, 2014*

**government**

I was going to post it anyway
*September 22, 2014*

**maths**

the distance between two stations is 340 km two trains start simultaneously on parallel tracks to each other . the speed of one of them is greater than that of the other by 5 km/hr. if the distance between the two trains after 2 hrs of their start is 30 km , find the speed of ...
*July 15, 2013*

**Exponential**

Consider a = (x^2 -17x +71) and b = (x^2 -34x +240). case 1: let a = 1, b may be anything. x^2 -17x +71 = 1, which gives x = 7 or 10. case 2: let b =0 and a non-zero. x^2 -34x +240 = 0, gives x = 10 or 24. case 3 : let a = -1 and b = even. x^2 -17x +71 = -1, gives x = 9 or 8. ...
*May 30, 2013*

**physic**

a sportcar moving from rest 0 to 100km/h ..there hanging a pendulum in the car..what will be the angle pendulum can make with vertical line??
*May 27, 2013*

**Algebra**

the ans is 0
*March 18, 2013*

**chemistry**

for depolarization of 1 mole of KMnO4, the moles of H2O2 required is_________
*October 15, 2012*

**College Physics**

A body of mass m breaks up into 2 parts of rest mass m1 and m2 with velocity v1 and v2 ,what will be the energies of m1 and m2 in terms of m,m1,m2 and c,the velocity of light.
*October 4, 2012*

**Physics**

A body of mass m breaks up into 2 parts of rest mass m1 and m2 with velocity v1 and v2 ,what will be the energies of m1 and m2 in terms of m,m1,m2 and c,the velocity of light.
*October 4, 2012*

**chemistry**

2.35*10^-4M,,Mg(OH)2 what is the pH of this solution
*June 18, 2012*

**Chemistry**

SIR PLEASE EXPLAIN THE ANSWER
*April 1, 2012*

**calculus--please helpp**

thanks so much!
*October 14, 2011*

**calculus--please helpp**

if the line 3x-4y=0 is tangent in hte first quadrant to the curve y=x^3+k, find k. all i know is that its related to finding a derivative and i m basically completely lost....can please someone provide me some help?????
*October 14, 2011*

**Physics**

What is boyle's law?
*August 23, 2011*

**maths**

I think almost everyone forgetting the first line of the problem." A VAMPIRES A TOWN AND BITES TWO PERSONS EVERY NIGHT ". 1st night= 2 (bitten by original vampire) 2nd night= 2 +4(bitten by 2 persons turned vampires previous night) 3rd night= 2 +4(bitten by 2 ...
*August 8, 2011*

**puzzle**

Who to join 9 points place in a form of square in only 4 moves witg the help of two points place in outer square
*June 5, 2011*

**Chemistry **

C6H6 + (CH3)3Cl -AlCl3---> C6H5(CH3)3 C6H5(CH3)3 ---- HNO3/H2SO4--> para-NO2 C6H5(CH3)3---- major ortho-NO2 C6H5(CH3)3---- minor
*February 17, 2011*

**Chemistry**

Quinine has a tertiary amine group so acts as base QN + H2O -----> QNH+ + OH- given pka is 8.52 -log ka=8.52 ka= 3*10^-09, for conjugate acid base pair at 25degrees Celsius kw= ka*kb therefore Kb= kw/ka = 10^-14/ 3*10^-09 = 3.4 *10^-06 from eqation kb=[QNH+][OH-]/[QN] QN + ...
*October 29, 2010*

**algrebra 2**

x=(-6,0) y=(0,18)
*September 19, 2010*

**Physics**

C=qy
*August 10, 2010*

**Physics**

Assume that a deposit of oil is located 2000 m directly below. Estimate the size of the deposit, assumed spherical.
*April 7, 2010*

**college**

i have free speech.my topic is have ever done anything that you wish you hadn't done?what happened and how the situation might have been different if you had acted or thought differently. really i dont know,how can i speak because i dont know about this.can you help me,can...
*June 29, 2009*

**chem**

the answer is not clear
*April 23, 2009*

**university of the south Pacific**

Is sodium chloride an Ionic bonding or covalent bonding?
*April 6, 2008*

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