Molecules A and B react to produce molecule AB. If 60 mLs of 0.025 M A is added to 18 mLs of 0.175 M B, then how many moles of unreacted A or B will be left over? How many moles of AB will be produced?
March 22, 2015
the distance between two stations is 340 km two trains start simultaneously on parallel tracks to each other . the speed of one of them is greater than that of the other by 5 km/hr. if the distance between the two trains after 2 hrs of their start is 30 km , find the speed of ...
July 15, 2013
Consider a = (x^2 -17x +71) and b = (x^2 -34x +240). case 1: let a = 1, b may be anything. x^2 -17x +71 = 1, which gives x = 7 or 10. case 2: let b =0 and a non-zero. x^2 -34x +240 = 0, gives x = 10 or 24. case 3 : let a = -1 and b = even. x^2 -17x +71 = -1, gives x = 9 or 8. ...
May 30, 2013
A body of mass m breaks up into 2 parts of rest mass m1 and m2 with velocity v1 and v2 ,what will be the energies of m1 and m2 in terms of m,m1,m2 and c,the velocity of light.
October 4, 2012
if the line 3x-4y=0 is tangent in hte first quadrant to the curve y=x^3+k, find k. all i know is that its related to finding a derivative and i m basically completely lost....can please someone provide me some help?????
October 14, 2011
I think almost everyone forgetting the first line of the problem." A VAMPIRES A TOWN AND BITES TWO PERSONS EVERY NIGHT ". 1st night= 2 (bitten by original vampire) 2nd night= 2 +4(bitten by 2 persons turned vampires previous night) 3rd night= 2 +4(bitten by 2 ...
August 8, 2011
Quinine has a tertiary amine group so acts as base QN + H2O -----> QNH+ + OH- given pka is 8.52 -log ka=8.52 ka= 3*10^-09, for conjugate acid base pair at 25degrees Celsius kw= ka*kb therefore Kb= kw/ka = 10^-14/ 3*10^-09 = 3.4 *10^-06 from eqation kb=[QNH+][OH-]/[QN] QN + ...
October 29, 2010
i have free speech.my topic is have ever done anything that you wish you hadn't done?what happened and how the situation might have been different if you had acted or thought differently. really i dont know,how can i speak because i dont know about this.can you help me,can...
June 29, 2009