i)the area of rectangle is x*y (whit x,y side)=>x*y=3200 Ya^2 ii)the condition imposed from the questions is: x+y+y=200 Ya (i have choise two y because the text not exsplicit the misure of one the side): x+2y=200 => x=200-2y Ya for (i) (200-2y)*y=3200 Ya^2 200y-2y^2=3200...
F d -inf;+inf r [-19;+inf[ Y d -inf;+inf r [-3;+3] G d -inf;+inf r ]0;+inf[
i forgot to specify in ii) x=-b/(2a) => 2=-b/(2a)
strange way to write an equation! i) 30x+10x=40 => 40x=40 => x=40/40; x=1 ii) 16x+8=40 => 16x=40-8 => x=32/16; x=2 ...perhaps
sorry.....yes, the 4h-1 is on top of 1+h explain what?
you need to know if h>0
no is right 12
for Ms.Sue I understand but you have to choose an answer ... but maybe I'm wrong For jhonn YES
the test gives you the possible number of smaller cubes [a)4 b)16 c)1/4 d)-1/5 e)1] they must be the solutions the cube root of an integer, example [a)4 b)16 c)1/4 d)-1/5 e)8] smaller cubes (e)8 cube 2 2*2*2=8 1*1*1=1
e)1 only with whole cube root
i) i suppose that the water behaves like a solid so the force of the water, componentY, is m*g=65kg*9.81m/s2 ii) the force the water is only vertical and vanishes with the weight force(if no sinks or flies) iii)Component X is 0 the water-skier feels only the force of the rope
to solve this problem we need trigonometry therefore takes the radiant 67°*3,14/180=1,17 rad.= a point P=50m height tower H=? L=hypotenuse of the right triangle LPH P=Lcos(a)=> (i)L=p/cos(a) (ii)H=Lsen(a) (i)+(ii)H=[p/cs(a)]*sn(a) tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m
i do not know if i uderstand the question but i'll try: money Fariq call them x Edward money x+40 If Edward gives 1/5 of his money to Fariq => Fariq as x+ 1/5 Edward money(x+40)/5, Fariq as x+(x+40)/5 i did not understand if Fariq has 7/8 of the money that now Edward. i...
i do not know if this is process you'll be fine. after finding the spatial coordinates of tha sobstitute in the distans equation between two points: first aircraft angle a1=24.5*2Pg/360=0.43Rad second aircraft angle a2=16.0*2Pg/360=0.28Rad first aircraft d1=20000m x1=d1*se...
sorry.....errata corrige: iii)B average (between 80=> B=(x+y+z)/3>80 iiii)B average...and 89 inclusive)=> B=(x+y+z)/3<89
i set the equation end give you the solutions but you try to get there x=first test, y=second test z= three test i)second test score was 8 points higher than her first score => y=x+8 ii)Her third score was 88=> z=88 iii)B average (between 80=> B=(x+y+z)/3<80 iiii)B...