Thursday
May 23, 2013

Posts by KokkoDeRas


Total # Posts: 20

physics
x=vt+(1/2)*a*(t)^2 x=7*15-(1/2)*4*(15)^2

math
i)the area of rectangle is x*y (whit x,y side)=>x*y=3200 Ya^2 ii)the condition imposed from the questions is: x+y+y=200 Ya (i have choise two y because the text not exsplicit the misure of one the side): x+2y=200 => x=200-2y Ya for (i) (200-2y)*y=3200 Ya^2 200y-2y^2=3200...

math
F d -inf;+inf r [-19;+inf[ Y d -inf;+inf r [-3;+3] G d -inf;+inf r ]0;+inf[

math
i forgot to specify in ii) x=-b/(2a) => 2=-b/(2a)

Math
strange way to write an equation! i) 30x+10x=40 => 40x=40 => x=40/40; x=1 ii) 16x+8=40 => 16x=40-8 => x=32/16; x=2 ...perhaps

algebra
sorry.....yes, the 4h-1 is on top of 1+h explain what?

algebra
you need to know if h>0

math
no is right 12

math
for Ms.Sue I understand but you have to choose an answer ... but maybe I'm wrong For jhonn YES

math
the test gives you the possible number of smaller cubes [a)4 b)16 c)1/4 d)-1/5 e)1] they must be the solutions the cube root of an integer, example [a)4 b)16 c)1/4 d)-1/5 e)8] smaller cubes (e)8 cube 2 2*2*2=8 1*1*1=1

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