Friday

August 28, 2015
Total # Posts: 336

**altitude triangle inequality**

hi guys ive be struggling on this problem for a couple of days, so please help if you can Problem:Two altitudes of a triangle have lengths 12 and 14. What is the longest possible length of the third altitude, if it is a positive integer? Thanks in advance and merry christmas: ...
*December 31, 2012*

**math**

ok, so its kinda like multiplying fractions except u flip the second one upside down(reciprocal): so 1/2 divided by 2 = 1/2 divided by the reciprocal of 2 which is 1/2 so 1/2 * 1/2 = 1/4 thus, in this case, it would be 7/9 divided by reciprocal of 3/6 = 6/3 so 7/9* 6/3 = 7/9...
*December 31, 2012*

**geometry inequality triangles help if you can**

I meant the total number of possibilities. Thanks anyway!
*December 31, 2012*

**geometry inequality triangles help if you can**

thanks a lot the answer is 18 right? merry christmas and happy new year to y
*December 31, 2012*

**geometry inequality triangles help if you can**

Two sides of an obtuse triangle are 16 and 21. How many possible lengths are there for the third side, if it is a positive integer? i know that in an obtuse triangle a^2+b^2<c^2 a+b>c but i tried plugging in and it wont work so couldyou guys help me? btw merry christmas ...
*December 31, 2012*

**math problem triangle inequality help**

Two sides of a triangle are 11 and 17. How many possible lengths are there for the third side, if it is a positive integer? I tried listing them all but I get confused...Please help thank you!
*December 26, 2012*

**algebra**

for 1 (4x-3)(x-2) for 2 (3x-3)(3x-7)
*December 19, 2012*

**algebra**

for number 2, (7g-3)(5g+3)
*December 19, 2012*

**Help triangle angles!**

Points D, E, and F are the midpoints of sides BC, CA, and AB of ABC, respectively, and CZ is an altitude of the triangle. If <BAC=71, <ABC=39, and <BCA=70, then what is <EZD+<EFD in degrees? Please help I tried making a picture but its not helping....please help!
*December 19, 2012*

**math**

64z^2 - 1 => (8z-1)(8z+1)
*December 19, 2012*

**algebra**

How long does it stay in the air? The problem needs more information or else it is unsolvable.
*December 19, 2012*

**double square root problem?**

Hi I do not how to simplify the problem x^2 =40+12sqrt2 what would be x? BTW if you sqrt both sides it would be double square root so what then? how to simplify?
*December 19, 2012*

**HISTORY HELP ME**

its probably C
*December 19, 2012*

**help hexagon geometry**

A regular hexagon is inscribed in a circle and another regular hexagon is circumscribed about the same circle. What is the ratio of the area of the larger hexagon to the area of the smaller hexagon? Express your answer as a common fraction. How is this done? Would we divide it...
*December 19, 2012*

**please help - area of a dodecagon?**

The distance between two opposite vertices of the dodecagon is 2. Find the area of the dodecagon. first, what is the area of a dodecagon and second how to find it with just the distance between two oppositve vertices. i found that a dodecagon can be divided into 24 triangles: ...
*December 18, 2012*

**Math probability**

1/4 of all cards are clubs. use probability.
*December 18, 2012*

**Mathsa**

c should be the right answer....
*December 13, 2012*

**Mathsa**

the stuff on one side has to equal the other side : x =x infinite solutions 5=5 infinite solutions etc
*December 13, 2012*

**Mathsa**

solve for x and y in each equation a 7x=3, x=3/7 no b y=12, no c 7x+5 = 7x+5 => 5=5 YES d 6y-2 = 2y-2 => 4y=0 y=0 no
*December 13, 2012*

**Math**

x *x+2 = 82, x^2 +2x = 82. use the quadratic formula to find the answer
*December 13, 2012*

**Spainsh**

So wouldn't it be a noun...?
*December 13, 2012*

**math**

this is a mixed hypothetical statement. there are 4 forms, 2 are valid 2 are not. let the antecedent of the first statement be t, and consequent be e. ~p = not p thus we get t } e ~e :; ~t This is modus tollens literally the way that denies by denying, which is a valid argument.
*December 11, 2012*

**A probability question i think**

ok thanks alot steve you really help alot
*December 11, 2012*

**A probability question i think**

In a chess variant, a "lord" can move one space at a time, either upward, or to the right, or diagonally upward and to the right. How many ways are there for a lord to move from the bottom left to top right corner of the 8 by 8 chessboard? Thanks in advance for ...
*December 11, 2012*

**Math**

for 2nd equation, we get x = 2y-3 thus plugging into first equation gets (2y-3)^2+9y^2 = 37. 4y^2-12y+9+9y^2 = 13y^2-12y+9=37 = 13y^2-12y-28 = 0. Solving with the quadratic formula gives us: 2,-14/13
*December 11, 2012*

**math**

let t = team wins let r = team remains in playoffs let c be championship within reach let } = If x then y (The if, then part) let :; = therefore Thus, t } r r } c :;t } c This is a pure hypothetical statement. FYI in the argument t } r, t is the antecedent and r is the ...
*December 11, 2012*

**7th grade math please check ASAP please!**

We could go see by the logical way.... tom's tax is 7% cousin's tax is 4% tom's price is higher than cousin's... hmm... who has more tax?
*December 5, 2012*

**7th grade math please check ASAP please!**

1.07 * 22 = tom's price 1.04 * 18 = his cousin's price then to see who spent more on tax, 0.07*22 = how much tom spent on tax 0.04*18 = how much cousin spent on tax
*December 5, 2012*

**please help this is a geometry question**

An equilateral triangle of side 14 centimeters is revolved about an altitude to form a cone. What is the number of cubic centimeters in the volume of the cone? Express your answer to the nearest whole number, without units. I have tried solving this but it is hard how to ...
*December 5, 2012*

**I am really struggling on this problem - geometry**

Please help guys if you can, this is a really hard problem I am trying to solve Four circles of unit radius are drawn with centers (1,0),(0,1) ,(-1,0) ,(0,-1) and . A circle with radius 2 is drawn with the origin as its center. What is the area of all points which are ...
*December 5, 2012*

**Math could you help this is kinda hard and urgent**

The diagonals of a trapezoid are perpendicular and have lengths 8 and 10. Find the length of the median of the trapezoid. I tried figuring this out... by the way i got median times height is 40 and also notice that we are talking about the diagonals not the bases....that is ...
*December 4, 2012*

**maths**

35/100 * 20 = 35/5 = ?
*December 4, 2012*

**PLEASE HELP geometry trapezoid problem please help**

THANKS ALOT STEVE THANKS ALOT I REALLY APPRECIATE IT!!
*December 4, 2012*

**PLEASE HELP geometry trapezoid problem please help**

The diagonals of a trapezoid are perpendicular and have lengths 8 and 10. Find the length of the median of the trapezoid. I don't get it... i got as far as the area is 40, and m (median) times the height is 40 as well... please help!
*December 4, 2012*

**MATH**

Oh sorry Ms. Sue is right...
*December 3, 2012*

**MATH**

Hello. This a simple d = rt problem. Distance (70 m) = 40 miles * hour. Thus, it would take 70/40 hours to travel 70 miles at the constant speed of 40 miles per hour. (I don't know why the driven about 30 m was stuck in)
*December 3, 2012*