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September 17, 2014

Posts by JungJung


Total # Posts: 1

Trig
prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2) then multiply that out 1-2CosX^2 + cos^4 - cosX^2 + 2cos^4 -cos^6 add that on the left to the cos^6, and combine terms.. 1-3CosX^2 + 3cos^4 1-3cos^2x...
December 8, 2006

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