chemistry
hi kinda stuck :) 100.0 ml of 0.100 M H2NNH2 (kb =3.0 x10^-6) is titrated by 0.200M calculate PH after adding the following volumes of HNO3 a 0 b 25.0 ml c 50.0 ml d 60.0 ml ----------------------------------------- A) N2H4 + HNO3 --> N2H5+ + NO3- .100 0 0 3.0 x 10-6= x2/.1...
chemistry
thanks. Damn your smart dr.bob
chemistry
how bout if 200ml of koh is added ? the answer is 8.78 im getting 12.82
chemistry
how bout if 200ml of koh is added ?
chemistry
thanks i found the lr then plugged did some extra stuff that i should have thanks again Jim
chemistry
hi im having problems figuring this out. consider the titration of 100 ml of 0.200 acetic acid by 0.100 koh. Calculate the ph if 250 ml of koh is added ? I tried to find the limiting reagent and go from there but it was a no go then i used the kb for find the poh and then the ...
chemistry
here's what i finally ended up with I don't know why u used 59 grams nac2h302 x 3h20---> na + c2h302 + 3h20 sodium acetate trihydrate=acetic ions .3470 g nac2h302 x 3h20 /136.10= 2.550 x 10-3 mol acetic ions formed 2.550 x 10-3 M/.0150 L=.17 ka= (5.0 x 10-5)(.17)/(....
chemistry
thanks i got ka=2.5 x 10^-5 and 2.5 x 10-6 thanks again Jim
chemistry
oh This is an acid base experiment this is the last stage. There are two parts: part 1) 0.3470g sodium acetate trihydate is added to 15.00 ml acetic acid (concentration is 0.20) then its mixed and a ph is taking--i got 4.30 PH part II) Added 0.7618 g of sodium acetate trihydra...
chemistry
ok im not sure how to do this 15.00ml of acetic acid is pipetted into a flask 0.35 grams of sodium acetate trihydrate is added and mixed then 0.75 of the hydrate is added 1)i assumed that the volume(s) are additions. 15.00ml x .35g *m/1.45g and for the second part 15.00 + 0.35...
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