Wednesday
September 17, 2014

Posts by JessieLynne


Total # Posts: 11

Algebra
I have a question-If I'm finding the midpoint between points (4,6) and (-8,-7) it would be (-4/2,-1/2), correct? should I reduce it to (-2,-1/2)
October 27, 2011

Algebra
Could someone please show me how to write this equation in standard form? x^2 + y^2 - 6x+8y+9=0
October 24, 2011

Algebra II-Reiny could you relook at my comments,please?
I'm not suppose to copy the coordinates off the unit circle-I'm suppose to actually solve for the coordinates-like how do you get the coordinates for 60 degrees? that's where I'm confused
January 3, 2011

Algebra II-Reiny-Could you please show me how to do these
Please help me with above post-thank you
January 3, 2011

Algebra II
Could someone please help me or direct me where to get help What is the exact value of cos 60 as found on the unit circle? and the value of cos 5pi/3 Please show me the steps so I understand Thank you
January 3, 2011

Physics-Please check calculations
Thank you
January 2, 2011

Physics-Please check calculations
I posted this earler and you gave me help, could you please check what I did? Thank you If a car drives off a 40 m high cliff with a horizontal velocity of 15 m/s, how far from the base of the cliff will the car strike the ground? Could someone help with the equation, please ...
January 2, 2011

Physics-Please check
So I say: 40 m = 1/2 (9.8) * t^2 40/4.9 = 8.16(t^2) sqrt of 8.16 = 2.86 = time 15 * 2.86 = 42.9 for how far from the base of the cliff the car stuck the ground Is this correct? Thank you for helping- I'm homeschooled and trying to learn Physics on my own
January 2, 2011

Physics
If a car drives off a 40 m high cliff with a horizontal velocity of 15 m/s, how far from the base of the cliff will the car strike the fround? Could someone help with the equation, please
January 2, 2011

Algebra
Thank you so it would be a=5, correct
December 27, 2010

Algebra
I I have the hypotenuse of a right triangle that is 50 yds long and the other two sides are equal in length, how do I find one of the sides. Thank you
December 27, 2010

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