I imagine you're supposed to solve for the missing variables. I'll do a couple so you get the idea. 1) 2a - a/5 = 2/3 adding like terms: 1.8 a = 2/3 9/5 a = 2/3 a = 10/27 2) 3(a+4)+1 = a/2 3*a + 12 + 1 = a/2 3*a + 13 = a/2 13 = -2.5a a = 13/-2.5 . . .
Algebra 1- Math
2x - y = -4 -3x + y = -9 From the first equation: y = 2x + 4 Substitute this into the second equation: -3x + 2x + 4 = -9 -x + 4 = -9 -x = -13 x = 13 Then plug this answer back into the first equation 2*13 - y = -4 26 - y = -4 -y = -30 y = 30
You need to calculate the equilibrium constant K, which for C would be ([H2BO3-]*[CO3 2-]) / ([HCO3-]*[HBO3 2-]) Look up the equilibrium concentrations  of the various compounds, and solve. If K > 1, products are favored. If K is less than 1, than reactants are favored
First, plot the parallelogram on graphing paper. Next, calculate the length of each side using the formula for the distance between 2 points (x1, y1), (x2, y2): ((x1-x2)^2 + (y1-y2)^2)^0.5 Then calculate the slope of each line passing through these two points: slope = (y2-y1)/...
why don't you try getting out your compass, following each of the student's steps, and see which one yields a parallelogram PQRS?
Let P be the principal invested. The amount at the end of four years will be for each scenario 1: P*(1+0.0225/2)^(4*2) 2: P*(1+0.0225/4)^(4*4) 3: P*(1.0195^4)
I. 71. The mode, by definition is the answer that appears most frequently. II. The midrange is 64, which is by definition the arithmetic mean of the largest and the smallest values in a sample or other group. The range is 55. Let H = highest score, and L = lowest score. Then,...
suppose that the times taken to complete an online test are normally distributed with a mean of 45 minutes and a standard deviation of 12 minutes. find the probability a. that for a randomly selected test, the time taken was more than 1 hour. b. that the mean number of minutes...
The length of the telescope is 0.2 + 1.6