make a plot rounding to the nearest ten: (1, 630); (2, 670); (3, 740); (4,650); . . . then a plot rounding to the nearest 100: (1, 600); (2, 700); (3, 700); (4, 700) . . . c. What is the average El Nino rain (628 + 669 + 740 + . . . + 872) / 23 Is this less or greater than the...
Q = m*c*(130- -22) where m is the mass of the water, c is the specific heat of water, which you will have to look up; Make sure it matches with your units of mass and temperature
If she had worked those two days, she would make +$200 Instead, she spends $180 + $198 = $378 The total opportunity cost is 378 + 200 = 578. This is how much money she'll lose by going on the trip instead of working
centripetal acceleration is v^2/r The tension in the chain is m*v^2/r where v is the speed = 2*PI*r*f where f is the frequency; r is the radius; m is the mass v = 2*PI*1.2*0.432 solve for the acceleration and tension using the above equations
v = 2*PI*r/T where T is the period 2010 = 2*PI*0.15/T centripetal acceleration = v^2/r Force = m*v^2/r
The greatest coin is a quarter; If you choose three quarters, you only have $0.75, so $5.00 is greater.
Take components of the force: F1x = 364*cos(33) F1y = 364*sin(33) F2x = 522*cos(11) F2y = 522*sin(11) Fnetx = F1x + F2x Fnety = F1y + F2y Fnet = ((Fnetx)^2 + (Fnety)^2)^0.5 at an angle theta given by tan(theta) = Fnety/Fnetx where Fnet = m*a = 3050*a Solve for a, the acceleration
lamda * f = c where c is the speed of light = 3*10^8 m/s; f is the frequency; lambda is the wavelength.
vf - vi = 5*10^6 - 2*10^6 = 3*10^6 where vf is the final speed and vi is the initial speed. Assuming a constant deceleration, the electron passes through 2.1 multiply 4cm = 8.4 cm of paper. 8.4 = 1/2*a*t^2 deltav = 3*10^6 = a*t where a is the acceleration, t is the time. You h...
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