Monday

March 30, 2015

March 30, 2015

Total # Posts: 2,086

**physics**

y = y0 + v0*t - 1/2*g*t^2 where y0 is the initial height = 0, v0 is the initial speed, and g is the acceleration due to gravity, t is time, and y is the vertical position. The ball reaches it's maximum height when dy/dt = 0 = v0 - g*t and y = 5, so 5 = v0*t - 1/2*g*t^2 Use...
*November 29, 2012*

**Linear equation**

Start making a table of points. For y=4, for any value of x, y = 4 x y -4 4 -3 4 -2 4 -1 4 0 4 1 4 2 4 3 4 The graph will be a horizontal line through (0, 4)
*November 29, 2012*

**Algebra2**

Get all equations in the form y = m*x + b. Once it's in this form, m is the slope, b is the y intercept. 1. 2x-3y=6 2x - 6 = 3y y = 2/3x - 2 The slope is 2/3, the y intercept is -2 2. y=-2x y = -2x + 0 The slope is -2, the y-intercept is 0. 3. y = 3 y = 0*x + 3 The slope ...
*November 29, 2012*

**pre algebra**

-5 x 1 x 11 x 4 Look for multiplying numbers together that end up being multiples of 10; -5*4 = -20, so using the associative property -5 x 1 x 11 x 4 = (-5 x 1 x 11) x 4 Using the commutative property: = 4*(-5 x 1 x 11) = 4*-5 x 1 x 11 = (4*-5) x (1 x 11) = -20 * 11 Factoring...
*November 28, 2012*

**Physics**

For an elastic collision, both kinetic energy and momentum are conserved. Conservation of momentum m(He)*v(He,initial) = m(He)*v(He,final) + m(H)*v(H) where m(He) is the mass of the Helium, v(He, inital) is the initial speed of the Helium , etc. . . Conservation of kinetic ...
*November 28, 2012*

**Physics**

.92^3
*November 28, 2012*

**Physics**

Set the force of gravity equal to the force of the centripetal acceleration: G*m*M/r^2 = m*v^2/r r is radius of orbit, G is gravitational constant, M is mass of earth, m is mass of satellite (which cancels out of both equations), v is the speed of the orbit
*November 28, 2012*

**College Algebra**

h = 0.62*w where h is height, w is width P = 2*h + 2*w = 2 = 2*0.62*w + 2*w solve for w, then use first equation to solve for h
*November 28, 2012*

**5th math**

1: 2 2: 5 3: 3 4: 5 5: 4 6: 5 You'll notice that all the even numbered terms in the sequence(2nd term, 4th term, 6th term, etc.) are 5 The odd numbered terms in the sequence each increase by 1. So the next three terms should be 5, 5, 6
*November 28, 2012*

**Probabilty**

For each coin toss, the probability of x=1 is 0.4. The mean value of X for n tries is : (0.4(1)*n)/n = 0.4
*November 28, 2012*

**Calculus**

dy/dx = (x*y)^0.5 Integrate and solve for y, find the constant by making sure it passes through (1/2)
*November 27, 2012*

**college algebra**

log10(7^x) = log10(8) Using log rules (log(a^b) = b*log(a)) x*log10(7) = log10(8) x*.845 = .903 = log(8)/log(7) x = 1.068 to 3 decimals
*November 27, 2012*

**trig**

Should this be Q IV (quadrant 4) tan-1(-4/3) = -53.13 degrees (-53.13 degrees = 360 + -53.13 = 306.87, is in quadrant 4) Evaluate with your calculator cos(2*306.87)
*November 27, 2012*

**calculus**

Use some trig identities: tan(-x) = tan(x) csc(x) = 1/sin(x) tan(x) = sin(x)/cos(x) tan(-x)*csc(x) = tan(x)*(1/sin(x) = (sin(x)/cos(x))*(1/sin(x) = 1/cos(x) = sec(x)
*November 27, 2012*

**calculus**

cos(theta) = 3/5 Use your calculator: cos-1(3/5) = theta = 53.13 degrees This is the value that your calculator gives, and it is in quadrant; To find the value theta corresponding to quadrant 4, notice the symmetry in a graph of cos x, which is that cos(x), cos(x) = cos(360 - ...
*November 27, 2012*

**math**

The slope m of a line passing through two points (x1, y1), (x2, y2) is given by m = (y2-y1)/(x2-x1) m = (-5/6 - -5/4) / (-3-2/3) = (5/12) / (-11/3) = -15/132 = -5/44 The equation for a straight line is of the form y = m*x + b where m is the slope and b is the y-intercept. So ...
*November 27, 2012*

**Physics**

Use conservation of momentum Initial momentum: The momentum of inertia of the objects the students is m*r^2 (3.0 + 3.4*1^2 + 3.4*1^2)*wi = (3.0 + 3.4*.45^2 + 3.4*.45^2)*wf where wi = 0.75 is the initial angular momentum, and wf is the final angular momentum. Solve for wf b) ...
*November 27, 2012*

**college algebra, Please help!!**

log(1.9)= log(a^6) log(1.9) = 6*log(a) log(a) = (log(1.9))/6
*November 27, 2012*

**calculus**

The distance from a point on the line from the origin is ((y-0)^2 + (x-0)^2)^0.5 = (x^2+y^2)^.5 = (x^2 +(x+4)^0.5) evaluate d/dx((x^2 +(x+4)^0.5)) = 0 This is the x value of the point closest to the origin, plug x into y = sqrt(x+4) to find the y value of this point
*November 27, 2012*

**physics**

I'll choose to place the piano 1/4 way from the right end Fr= force right Fl=force left Fr+Fl-W-mg=0 where mg is the weight of the beam, W is the weight of the piano (The sum of the forces in the vertical direction is zero because nothing is moving) Then sum of the torques...
*November 27, 2012*

**math**

Use the pythagorean theorem 3.75^2 + 2.84^2 = d^2, where d is the diagonal. Solve for d.
*November 21, 2012*

**Maths - HELP PLZ**

Put into your graphing calculator the equation y = 3x^2 + 10x-8 Then describe the regions of x for which the y-values are greater than 0.
*November 21, 2012*

**Physics**

v = omega/k The wave equation is of the form D(x,t) = A*sin(k*x-omega*t) k = 5.36 omega = 6.71 solve for v, the wave speed
*November 21, 2012*

**Physics**

The wavelength, lamda is 4.48 m The frequency f is 13/5.97 v = lamda*f where v is the wave speed
*November 21, 2012*

**Physics**

Use conservation of momentum: m1*v1 = m2*v2 Where m1 and v1 are the mass and speed of the initial system, m2 and v2 are the mass and speed of the final system 10*v1 = (10+3990)*50
*November 21, 2012*

**Math Functions**

f(x)= 3x+2/2x+4 graph the function horizontal and vertical asymptotes. Show the table. I found the horizontal and vertical asymptotes, but im confused on how to do a table
*November 19, 2012*

**math 104**

From a survey of 100 college students, a marketing research company found that 50 students owned iPhones, 45 owned cars, and 35 owned both cars and iPhones.
*November 18, 2012*

**physics**

After the light passes through the first Polaroid, it's intensity is 1/2Io. Now the light is polarized After the second sheet, it is now 1/2I0*((cos(59))^2) After the third sheet it is 1/2I0*((cos(59))^2)*((cos(59))^2) . . Do this up to the 6th sheet, and divide by I0
*November 16, 2012*

**Probability**

1/3 He asks three person a question, and only one of them tells the truth. The probability of getting the truthful man to answer is 1/3
*November 16, 2012*

**Physics**

y = y0 + vy*t + 1/2*ay*t^2 Where y is the distance in the vertical direction, y0 is the initial y position, vy is the speed in the y direction, ay is the acceleration in the y direction, t is time. Choose a coordinate system so that y0 equals zero at the baseball player's ...
*November 15, 2012*

**Physics**

1 decibel = A*log(P/P0) = A*log(1.122) Where P0 is the initial pressure, P is the pressure 1 decibel = 0.05*A A = 20 L = 20*log(P/P0) 8 = 20*log(P/P0) Solve for P/P0
*November 15, 2012*

**physics PLEASE HELP**

The difference in decibels between the two is defined to be 10 * log (P2/P1) Where the log function is in base 10, and P2 and P1 are the power of the sources at r2 and r1 6.5 = 10*log(P2/P1) 0.65 = log(P2/P1) 10^0.65 = P2/P1 = 4.46 Power is proportional to the radius squared, ...
*November 15, 2012*

**Physics**

d1*V1 = d2*V2 where d1 and V1 are the density and volume of object 1; d1 and V2 are the density and volume of the fluid Then V2 = 0.14*V1 d1*V1 = d2*0.14*V1 d1 = d2*0.14 Look up the density of water at 0 degrees C (= d2). Solve for d1 b) d1*V1 = d2*V2 You know d1 from a. You ...
*November 15, 2012*

**Physics**

P(water) = P0 + d*g*h where P is the pressure of water, P0 is the atmospheric pressure of the air at the surface of the water, d is the density of water, g is the constant acceleration due to gravity, and h is the depth of the water beneath the surface 1000*P0 = P0 + 1025*9.8...
*November 15, 2012*

**chem**

A solution is prepared by dissolving 25 grams of sodium sulfate in enough water to give a total volume of 500. mL. The molar mass of sodium sulfate is 142 grams per mole. What is the molarity of the solution?
*November 14, 2012*

**finite math**

There are 4 aces in a deck of 52 cards. The probability of an ace being in any position in the deck is 4/52 = 1/13. The probability of an ace being in the 3rd position is 1/13
*November 13, 2012*

**Physics**

x = vx*t y = 0.95 - 1/2*g*t^2 where x is the displacement in the horizontal direction, y is the displacement in the vertical direction, and t is time, vx is the speed of the cart in the x direction, and g is the acceleration due to gravity = 9.8 At it's landing, x = 0.4, y...
*November 13, 2012*

**math**

Go through the numbers 1 through 100, cross out all the numbers that are divisible by 2 (except 2), then the numbers that are divisible by 3(except three), then the numbers that are divisible by 5 (4 should be crossed out because it was divisible by 2) Do this all the way up ...
*November 13, 2012*

**math**

The factors of 100 are 1, 2, 5, 10, 20, 25, 50, 100 8%
*November 13, 2012*

**math**

8x/y2*4y/7x
*November 12, 2012*

**physics**

The rotational energy of each astronaut is 1/2 * I * omega^2 where I is the moment of inertia, and omega is the angular speed. The moment inertia of the astronaut is m*r^2 r = 12.0 / 2 = 6 m v = 5 m/s = omega*r The total rotational energy is 1/2 * I * omega^2 + 1/2 * I * omega...
*November 11, 2012*

**Physics**

Set the centripetal acceleration to the acceleration of gravity v^2/r = g
*November 11, 2012*

**physics**

F*r = I*alpha where F is the force, r is the radius, I is the moment of inertia, and alpha is the radial acceleration 470*0.370 = I * 0.8
*November 11, 2012*

**math**

5 out of 10 columns are multiples of 2, so 50% of all numbers are multiples of 2 2 out of 10 columns are multiples of 5, so 20% of all numbers are multiples of 5. The % of the numbers that are multiples of both 2 and 5 us 50% * 20% = 10%
*November 11, 2012*

**calculus**

Imagine what is happening from (-infinity < x < infinity) 1). from -infinity to x = -2, the graph is going up, then reaches a maximum at x = -2 2). From x = -2 to x = 1, the graph is going down to the minimum at x = 1 3). From x = 1 to x = 6, the graph goes up again to ...
*November 11, 2012*

**Physics**

You have two components of acceleration: a(centripetal) = v^2/r, which is the centripetal acceleration directed inward towards the center of the circle. dtheta/dt = omega = 2*a*t v = omega*r The second component of acceleration is the tangential acceleration, a(tangential) = (...
*November 11, 2012*

**physical science**

1/p + 1/q = 1/f M = -q/p where p is the distance of the object from the lens, q is the distance of the image from the lens, M is the magnification of the object. If M is positive the image is virtual and inverted; if M is negative the image is real and upright (erect). f is ...
*November 10, 2012*

**Algebra**

fc + (11-4)*b = fc + 7*b = 33 fc + (19-4)*b = fc + 15*b = 55 where fc is the fixed charge of the first 4 bushels, and b is the price per bushel of each additional bushel over 4 Use algebra to solve these two equations for b and fc: fc + 7*b = 33 fc + 15*b = 55
*November 10, 2012*

**algebra**

For every unit of increase in x, there is a 2 unit increase in y: k = 2 y = 2*x - 3
*November 10, 2012*

**science**

(p+q)^2 = 1 30% of the population have tt: q^2 = 0.3 p^2 + 2*p*(0.3^0.5) + 0.3 = 1 Solve for p p^2 is predicted frequency of TT 2*p*q is predicted frequency of Tt q^2 is predicted frequency of tt
*November 10, 2012*

**Physics**

F - csf*N = 0 N - m*g = 0 where F is the force, csf is the coefficient of static friction, N is the normal force, m is the mass of the cabinet, and g is the gravitational constant.
*November 10, 2012*

**Physics**

a) diameter = 2*radius = 0.15 m; radius = 0.15/2 area = pi*radius^2 b)Work = Force*distance = 160*0.15
*November 10, 2012*

**probability**

5*4 (color1, style1), (color1, style2), (color1, style3), (color1, style4), (color2, style1) . . .
*November 10, 2012*

**Science**

Looks good to me
*November 10, 2012*

**Physics**

a) The center of mass of the can is halfway up; the center of mass of the soda in the can is also halfway up when the can is full of soda, so the center of mass is (0.135*(12.4/2) + 1.25*(12.4/2))/(0.135+1.25) b) After the can loses all the soda, the center of mass is the ...
*November 9, 2012*

**Physics or Math**

The torque is about the point (-1.3, 2.4), so treat this as your origin,. . . This makes the r vector (4.3, -2.4, 0)
*November 9, 2012*

**Physics**

Use conservation of momentum: (65+0.18)*2.47 = .18*24.3 + 65*vf where vf is final speed of the ice skater b).Again, use conservation of momentum: 0.18*24.3 = (62+0.18)*vf
*November 9, 2012*

**Physics**

sum(F) = m*a where sum(F) is the sum of the forces, m is mass, and a is acceleration: 30 - 20 = 50*a
*November 9, 2012*

**Physics**

400 = 2*a(cb) where a(cb) is acceleration of the cannon ball 400 = 500*a(c) where a(c) is acceleration of the cannon
*November 9, 2012*

**Physics**

F = m*a where F = force, m is mass, and a is acceleration 25 = m * 5
*November 9, 2012*

**college algebra, Please help!!**

A. is f(-2) = 9? if it is, then the point (-2,9) is on the graph. Otherwise, it's not on the graph B.Plug 2 into f(x) f(2) = 2 * (2^2) - 2 - 1 The points on this graph are (2, f(2)) C. Solve -1 = 2*x^2-x-1 You should find two solutions for x. D. The domain of f is the ...
*November 9, 2012*

**Physics**

For an elastic collision, both momentum and kinetic energy are conserved. m1 = mass of colliding ball m2 = mass of ball initially at rest v1i = initial speed of colliding ball v1f = final speed of colliding ball v2i = initial speed of at rest ball = 0 v2f = final speed of at ...
*November 9, 2012*

**math**

I say c 127.1 / (127.1+32.1) = %Cu 32.1 / (127.1 += 32.1) = %S
*November 9, 2012*

**physical science**

F*d = W Where F is force, d is distance moved, and W is work
*November 8, 2012*

**math**

$3.96 = 396 cents 396 cents / 17 ounces is price in cents/ounces
*November 8, 2012*

**math**

8:9
*November 8, 2012*

**Science**

Look up the speed of sound, then multiply this number by 6 s.
*November 8, 2012*

**Physical Science**

v = f*lambda where v is the speed of sound, f is the frequency, and lambda is the wavelength
*November 8, 2012*

**physics**

For an elastic collision, both momentum and kinetic energy are conserved. Conservation of momentum: m1*v1 + m2*v2 = m1*v1f + m2*v2f where m1 and m2 are the mass of the car and truck, v1 and v2 are the initial speeds of mass 1 and mass 2, and v1f and v2f are the final speed of ...
*November 8, 2012*

**math**

There are a total of 6*6 =36 possible combinations for a sum of 8, you can have: (6,2) (2,6) (3,5) (5,3) (4,4) Probability = 5/36 For a sum of 9, you can have: (6,3) (3,6) (4,5) (5,4) Probability of 4/36 For a sum of 10, you can have: (5,5) (6,4) (4,6) For a probability of 3/36
*November 8, 2012*

**PHYSICS**

The buoyant force acting on the balloon is (p1V1 - p2V2)g where V1 = V2 = 318 m3 p1 is the density of air p2 is the density of helium c) The net force is the buoyant force - m*g, where m is the mass of the balloon. If the net force is positive, the balloon will rise d BF - m*g...
*November 8, 2012*

**Math **

What value of b makes the equation below true? b+1/4=12/12 Please show work Thanks
*November 7, 2012*

**Math **

What value of b makes the equation below true? b+1/4=12/12 Please show work Thanks
*November 7, 2012*

**math HELP!!!!!!!!!**

Just multiply each coordinate by two (–1, 2) and (3, –3) gives ( -2 . . . . )
*November 7, 2012*

**Chemistry**

P1*V1 = P2*V2 when the temperature remains constant. P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
*November 7, 2012*

**physics**

Centripetal acceleration is given by a = v^2/r = omega^2*r where a is the centripetal acceleration, v is the speed, r is the radius, and omega is the angular speed in rad/s Convert rev/s to radians per second 595 rev/s * (2*pi radians/rev) = ____ = omega a = omega^2 * 0.02 m b...
*November 7, 2012*

**physics**

-k*x = -Ke*q1*q2/r^2 where k is the spring constant, x is the distance stretched by the spring, Ke is Coulomb's constant, r is the distance between the charges. r = 9.00 cm = 0.09 m x= 5 mm = 0.005 m q1 = 2.70 uC = 2.7 * 10^-6 C q2 = -8.6 uC = -8.6 * 10^-6 C Ke = 8.9 * 10^9
*November 7, 2012*

**physics**

T = 1/f where f is frequency = 1.5, T is period
*November 7, 2012*

**algebra**

v - c = 1.5 v + c = 3.5 where v is Camille's speed in still water, c is the speed of the current Solve for v
*November 7, 2012*

**math**

dp/dx = 0, or -20x + 1700 = 0 Solve this for x for part 1, then plug this value of x into p(x) for the answer to part 2
*November 7, 2012*

**Math**

Write 2 24/12 as a whole number. Show work.
*November 5, 2012*

**Math**

At whole foods market 5/6 of the vendors sell vegetable and 2/4 sell fruit. What fraction of the vendor sell fruit or vegetable?
*November 5, 2012*

**Math**

Brenda mixed together 11/12 quart of cranberry juice and 8/15 quart of ginger ale to make punch. How much punch did Brenda make?
*November 5, 2012*

**Math **

C+1/5=9/20
*November 5, 2012*

**Math**

A capybara is the worlds largest rodent . It can grow to be 1 3/10 m long. Write an improper fraction that represents the length of the capybara? Please show work of how you got answer. Thanks
*November 5, 2012*

**Math**

An average 10 yr boy weighs 86 1/2 pounds and has muscles that weigh 34 1/5 pounds. An average 10 yr old girl weigh 82 1/3 pounds and has muscles that weigh 31 1/4 pounds. How much do an average 10 yr old boy and girl weigh together ? With answer can you tell me how you got it...
*November 5, 2012*

**Numerical Analysis**

xcosx-2x2+3x-1=0 Evaluate the function at 0.2 and 0.3: 0.2*cos0.2-2*0.2^2+3*0.2-1 = -.280 0.3*cos0.3-2*0.3^2+3*0.3-1 = 0.019 In order for the function to go from y=-.280 to y=0.019 on the interval [0.2,0.3], it must pass through y = 0 at least once. -x*sinx -4x + 3 =0
*November 2, 2012*

**Numerical Analysis**

The Taylor series about f(1) to fourth order is: f(x) = f(1) + f'(1)*(x-1) + f''(1)*(x-a)^2/2! + f'''(1)*(x-a)^3/3! The derivative of ln(x) is 1/x f''(x) = -1/x^2 f'''(x) = 2/x^3 f(1) = 0 f'(1) = 1 f''(1) = -1 f''...
*November 2, 2012*

**Numerical Analysis**

6 because there are 6 digits in 2.71828
*November 2, 2012*

**Numerical Analysis**

The Taylor expansion abour x = pi/4 to sixth order is f(x) = f(pi/4) + f'(pi/4)*(x-pi/4) + f''(pi/4)*(x-pi/4)^2/2! + f'''(pi/4)*(x-pi/4)^3/3! + f''''(pi/4)*(x-pi/4)^4/4! + f'''''(pi/4)*(x-pi/4)^5/5! f(x) = cos(x) f&#...
*November 2, 2012*

**Physics**

m*v^2/r <= cf*N where m is the mass of the object, v is the speed of the object, r is the radius, cf is the coefficient of static friction, and N is the normal force = m*g Solve for v
*November 1, 2012*

**science**

250 milliliters = 0.25 L; To make a 3.0 M NaOH solution from 6.0 M NaOH, you need equal parts of water and NaOH solution You need 0.25 Liters of the solution, so you need 1/2 * 0.25 = 125 milliliters 6.0 M NaOH, and 125 milliliters water
*November 1, 2012*

**Physics**

(1/p) + (1/q) = 1/f M = h'/h = -q/p, Where p is distance of object from lens, q is distance of image from lens, f is focal length of the lens, and M is the magnification f is positive when the lens is convex: 1/50 + 1/q = 1/15 q = 21.4 cm M = -21.4/50
*November 1, 2012*

**Physics**

F*r = I * a Where F is the force on the merry-go-round, r is the radius, I is the moment of inertia of the merry-go-round, and a is the angular acceleration for a solid, horizontal disk, the moment of inertia is: 1/2*m*r^2 F*r = 1/2*m*r^2*a F = 1/2*m*r*a w = w0 + a*t where w ...
*November 1, 2012*

**math**

Type 2 + (3/4) into your calculator
*November 1, 2012*

**physics**

The time elapsed between 12:35 and 3:10 is 2 hr, 35 min or 2 and 35/60 hours distance = 45 * (2 and 35/60)
*October 31, 2012*

**Physics**

dsin12.23 = ml, m = 0, 1, 2, â€¦.` where l = 550 * 10^-9 m d = 1/55000 solve for m
*October 31, 2012*

**algebra**

2(2-x)<-3x-2 Just start working with the equation as if the < sign was an = sign 4 - 2x < -3x -2 4 + x < -2 x < -6
*October 31, 2012*

**alegbra 1**

1). 3y=11-2x 2). 3x=y-11 Using equation 1: y = (11-2x)/3 Substituting into equation 2 3x = (11-2x)/3 - 11 x = (11 -2x)/9 - 11/3 x + 2x/9 = 11/9 - 11/3 11x/9 = 11/9 - 11/3 solve for x Then plug x into either equation 1 or 2, and solve for y 2) Use a similar procedure, as shown ...
*October 31, 2012*

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