Tuesday

April 28, 2015

April 28, 2015

Total # Posts: 1,772

**math**

recall that the area of a triangle is A = bh/2 b = base and h = height substituting the values: 90 = b*12/2 90 = b*6 b = 15 meters hope this helps~ :)
*March 7, 2011*

**Geometry**

recall some formulas: Volume of Sphere = (4/3)*pi*(r^3) Surface Area of Sphere = 4*pi*(r^2) since we do not know the value of radius, we get it from the surface area: 804 = 4*pi*r^2 now solve for r with your calculator~ after solving r, plug in this value to the formula for ...
*March 7, 2011*

**math**

first, we convert the given in same units,, let's use ft as units,, since 12 inches = 1 foot, we convert the given dimensions for the tiles into ft: 12 inches = 1 ft 12 inches = 1 ft then we get the areas of both tiles and floor area to be installed by tiles: A,tile = 1*1...
*March 7, 2011*

**maths**

i think you mean, x^2 + 5x - 36 = 0 to factor this, first we get the factors of the constant (which is 36),, the factors of 36 are: +- 1, 2, 3, 4, 6, 9, 12, 18, 36 now, we see from the given equation that 36 is negative,, thus we choose two factors from this set which are in ...
*March 7, 2011*

**Alegbra 1**

the 500 pounds represent the Ao in the equation (Ao is the initial amount),, since there is time given (x = 140 years), we can substitute the values directly: A = Ao*e^(-0.01386x) A = (500)*e^(-0.01386*140) A = ? now plug in these values in calculator and you'll get A~ ...
*March 7, 2011*

**Trigonometry**

values in x column will change, as well as the values in y column, but you will see a pattern --- you would observe that the pattern repeats every pi interval,, remember that you'll graph this in rectangular (Cartesian) coordinate plane, not in polar coordinates,, to get ...
*March 7, 2011*

**Math**

it has 5 sides, so it's a pentagon~ :)
*March 6, 2011*

**Algebra/geometry **

let x = length of the original rectangle let x-4 = width of the original rectangle using the conditions given by the 2nd statement, new width: (x-4) + 5 new length: x - 3 using the next condition given in the problem, and recalling that the area of a rectangle is just length*...
*March 6, 2011*

**mathh**

let n = number half the number, so n/2 three less than, so - 3 putting them together, three less than half a number is: n/2 - 3 hope this helps~ :)
*March 6, 2011*

**mathh**

let n = number half the number, so n/2 three less than, so - 3 putting them together, three less than half a number is: n/2 - 3 *i just reposted my reply :)
*March 6, 2011*

**math**

let x = number of candy bars of Neil 3 less than 4 times as many candy bars as Neil means: 4x - 3 hope this helps~ :)
*March 6, 2011*

**Algebra**

3x^2 - 15x + 18 do you need to factor this??? if so, first since the numerical coefficients (the number before the variable x) are all multiples of 3, we can factor out 3: 3(x^2 - 5x +6) then we factor the term inside the parenthesis: 3(x-2)(x-3) hope this helps~ :)
*March 6, 2011*

**Algebra**

let x = area to be painted (in sq ft) let y = gallons of paint needed therefore, using the second statement of the problem, we can find the ration of sq ft area painted per gallon: 10000 sq ft / 20 gallon = 500 sq ft / gallon thus, to get the number of gallons needed, we ...
*March 6, 2011*

**geometry**

first we get the ratio of the arclength to circumference: 60 cm / 240 cm = 1/4 since the arc covers 1/4 of the circumference, it also means that it forms 1/4 of the total angle of a circle. angle of a circle is 360 degrees, thus central angle associated by XW is: (1/4)*360 = ...
*March 6, 2011*

**Algebra**

let x = number of bracelets you will make since you ill use 30 beads per bracelet, the total number of beads you will use is 30x, and this total number of beads must be no more than 145 beads (or it will not exceed 145),, therefore: 30x < 145 to see if you can make 4 ...
*March 6, 2011*

**precalculus**

to solve for the vertex, there are actually many ways, but i think the fastest is to get the derivative (since the derivative is either a maximum or a minimum --- like the vertex, which can be a maximum if parabola is concave downward, or a minimum if it is concave upward) ...
*March 5, 2011*

**Calculus 12th grade.**

recall that velocity is the change in position over change in time, or: v = dx/dt where x=distance, and t=time thus equating this to the given function, dx/dt = 9t^2 + 2t dx = (9t^2 + 2t)dt integrating, x - xo = 3t^3 + t^2 + C if we assume that the initial displacement is zero...
*March 5, 2011*

**Calculus 12th grade.**

first, we find where the curve touches the x-axis, or simply get the roots,, to get the roots, equate y = 0: 0 = 4x - x^2 0 = x(4-x) x = 0 and x = 4 this will be our boundary conditions for integration,, we'll use integration since area under the curve: integral (4x - x^2...
*March 5, 2011*

**advanced math**

what method would be the best if i want to solve more than one ordinary differentials equations? or how would i attack this kind of problem? for example: dy/dt = (1-y)/(1+x+y) dx/dt = (y-x)/[2(1+x+y)] i just need a starting point cause i couldn't think of a way~ :P any ...
*March 5, 2011*

**math **

first represent unknowns using variables: let x = rate of Mill let x+6 = rate of Julie recall that rate (or speed) is the distance travelled over time, or: v = d/t therefore, since 714 miles is their distance after 6 hours, and noting that they travel in opposite directions: v...
*March 5, 2011*

**algebra**

the first term.. is that (-6^v2 + 2v + 4)?? if it is, then, you almost got the correct answer---you just forgot to put a negative sign before 12v^2 :)
*March 5, 2011*

**algebra**

for similar triangles, the ratio of the sides of the first triangle is equal to the ration of the corresponding sides of the second triangle,, like: let h1 = height of 1st triangle let h2 = height of 2nd triangle let b1 = base of 1st triangle let b2 = base of 2nd triangle ...
*March 5, 2011*

**algebra**

recall the formula for midpoint: let Xm = x-coordinate of the midpoint let Ym = y-coordinate of the midpoint Xm = (X1 + X2)/2 Ym = (Y1 + Y2)/2 therefore: Xm = (2+4)/2 = 6/2 = 3 Ym = (-3+9)/2 = 6/2 = 3 thus midpoint is at (3,3) hope this helps~ :)
*March 5, 2011*

**algebra**

the max distance in a rectangular solid is its diagonal,, like in a rectangle, the max distance is the diagonal,, recall: the square of the diagonal of a rectangular solid the sum of the squares of its sides, or: L^2 + W^2 + H^2 = D^2 where L=length, W=width, H=height, D=...
*March 5, 2011*

**Math**

but we do not see the figure.
*March 5, 2011*

**Grade 10 Math**

sorry for the first post by the way~ ^^; i just accidentally hit the enter button~ ^^;
*March 5, 2011*

**Grade 10 Math**

(a) no solution recall that two linear equations have no solution if they are parallel (solution means they meet at a certain point),, thus the two equations, in order to be parallel must have the SAME SLOPE. to determine the slope of the given equation, we rewrite it in this ...
*March 5, 2011*

**Grade 10 Math**

(a) no solution
*March 5, 2011*

**Alg 2**

first get the roots,, (x-7)(x+3)=0 thus equating each term inside the parenthesis to zero, x-7=0 and x+3=0 therefore, x=7 and x=-3 the roots are 7 and -3 sum: 7 + (-3) = 4 product: 7(-3) = -21 the questions asks for the difference between the sum and product, therefore: 4 - (-...
*February 28, 2011*

**algebra**

3x / (x^(-1)) recall some laws of exponents: a number raised to a negative exponent is equal to its reciprocal raised to the positive exponent for example, 3^(-1) = (1/3)^1 = 1/3 5^(-2) = (1/5)^2 = 1/25 therefore, here, the x^(-1) becomes (1/x)^1 or simply 1/x 3x / (x^(-1)) 3x...
*February 28, 2011*

**math**

6x + 2y = -2 4x + y = 1
*February 15, 2011*

**Algebra**

recall: speed (v) is distance (d) travelled over a certain period of time (t), or v = d/t since Suzi is faster that Jim given their speeds, we can get the difference of their speeds: 69 - 41 = 28 mph *this 28 mph only means that after 1 hour, the gap or distance between them ...
*February 6, 2011*

**Math**

first recall law of exponents,, if terms have the same base (or the number which is raised to a certain exponent), we can add the exponents,, thus: 8^(8) * 8^(-8) we can rewrite this as: 8^(8-8) 8^(0) since any number (expect zero) raised to zero is one, 8^(0) = 1 hope this ...
*February 6, 2011*

**Algebra**

wait, it should be t > -2 *i forgot to tell that if you divide both sides by a negative number, the inequality sign becomes the opposite,, that's why (<) becomes (>) and so please don't mind the "thus t is any number less than 2, so it can be 1.7, 1, 0, -...
*February 6, 2011*

**Algebra**

so it's an inequality~ i think for the first equation you've written, you mean: r > -0.075t + 3.85 because you've written -0.075t + 3.85 < 3.7 (it's the same as r > -0.075t + 3.85 ; the left side just became the right side of the inequality and vice-...
*February 6, 2011*

**9th grade**

you multiply the term to each term inside the parenthesis and then combine them,, for example, 3(x+2y+2) multiply 3 to each term: 3*x + 3*(2y) + 3*2 3x + 6y + 6 hope this helps. :)
*November 11, 2010*

**math**

discount: amount of money you can save (amount that is deducted from the original price),, discount = %discount * original price first convert 5% to decimal,, just move 2 places to the left of decimal point: 5% = 0.05 therefore, discount = 0.05 * 8.49 = ?
*November 11, 2010*

**6th grade**

first represent unknowns using variables: let x = first decimal let y = second decimal then set up equations using conditions given: (1) x + y = 3.9 (according to first statement) (2) x - y = 0.9 (according to second statement) (3) xy = 3.9 i think there's something wrong ...
*November 11, 2010*

**Math**

Volume of a cylinder = area of the base * height, or: V = pi*(r^2)*h therefore, V = pi*(5^2)*4 V = pi*25*4 simplify this. units is in cubic units. Volume of cube is s^3,, solving for the length of one side: V = 27 = s^3 cuberoot(27) = s s = 3 inches Surface area of cube = 6*...
*November 11, 2010*

**math**

first represent the unknowns using variables: let x = age of the Emma let 9x+7 = age of Karen (according to first statement) then set-up equation using the given conditions: x + (9x+7) = 57 combine similar terms,, for terms with the same variable, add the numerical coefficient...
*November 11, 2010*

**4th grade**

let n be the number for instance, five less than the number means 5 is subtracted to the number: n - 5
*November 11, 2010*

**physics**

since given angle is 30 deg to the horizontal, the horizontal force is just, Fx = F*cos(theta) Fx = 70*cos(30) now simplify this.
*November 11, 2010*

**5th grade**

if 5/17 is shaded, then the rest is not, therefore, 1 - 5/17 in order to subtract this, we first convert 1 into a fraction such that its denominator (*denominator is the number below the line of a fraction) is the same as the second term (which is 17),, thus we can rewrite 1 ...
*November 11, 2010*

**algebra**

(7/3)x + (1/3)x = 4x + 48/3 + (8/3)x combine similar terms,, for terms with same variables, add the numerical coefficient (number before the variable) and copy the variable: (7/3 + 1/3)x = 4x + 48/3 + (8/3)x *since 7/3 and 1/3 have the same denominator, just add the numerator...
*November 11, 2010*

**calculus**

y1 = x^2 + 3x - 1 y2 = x - 5 for y1 - y2, combine similar terms,, for terms with same variables, add their numerical coefficients (number before the variable) and copy the variable: x^2 + 3x - 1 -(x - 5) x^2 + 3x - 1 - x + 5 x^2 + 3x - x - 1 + 5 *i just rearrange the terms* x^...
*November 11, 2010*

**geometry**

recall the properties of parallelogram,, one of the properties of a parallelogram is that the opposite angles are congruent/equal,, since you are given angles A and C, and they are opposite, equate them to get x: 4x - 57 = x + 3 combining similar terms, 4x - x = 57 + 3 *when ...
*November 11, 2010*

**Precalculus**

x-intercept occurs when y = 0, thus substitute zero value to y: 0 = -0.01x^2 + 0.7x + 6.1 since this is not factorable, use the quadratic formula: x = [-b +- sqrt(b^2 - 4*a*c)]/(2*a) note: +- is plus or minus where a = -0.01, b = 0.7 and c = 6.1 substitute these values and ...
*November 11, 2010*

**algebra**

shift to the left: y = x + 1 then shift to one space up,thus: y - 1 = x + 1 or y = x + 2
*November 10, 2010*

**math**

speed is distance traveled over unit time: v = d/t rearranging, d = vt let v = speed going there (forth) since in the problem, you traveled the same distance, d,forth = d,back 3v = 5(16) 3v = 80 v = 80/3 or 26.67 k/h
*November 10, 2010*

**algebra**

#1 , #2 and #4 are correct. :) for #3, you have two cases, first: 7-x > 2 (positive case). thus, -x > 2-7 -x > -5 x < 5 second: -(7-x) > 2 (negative case). thus, -7+x > 2 x > 2+7 x > 9 thus, it should be x < 5and x > 9 or (-infinity, 5) U (9, +...
*November 10, 2010*

**Math**

-11x-24 < 27-10x combine similar terms: -11x + 10x < 27 + 24 *when transposing terms to other side of equation, the sign must become the opposite* then, -x < 51 multiply by -1 to get positive x: x > -51 *note that when all terms are multiplied or divided by a ...
*November 10, 2010*

**math**

*when in percent and you want to convert into decimals, just move the decimal point 2 place to the right: 3.5% = 0.035 rewriting this using equation: 0.035*d = 0.105 note that "of" means multiply and "is" is equals. to get d alone, divide all terms by the ...
*November 8, 2010*

**algebra**

first represent the unknowns with variables: let x = first number let x+2 = second number let x+4 = third number *since they are consecutive, and all of them are odd, they have a difference of 2, that's why it's x, x+2, x+4* now, setup equation using the given ...
*November 8, 2010*

**math**

using long division, first, since 34 is the one that is divided, 34/123.08 must be written like this: 123.08 ) 34 since the divisor (the 123.08) has five digits, and the dividend has only 2 digits, we write zeros to the right of decimal point of 34: 34 becomes 34.000 (now it ...
*November 8, 2010*

**algebra**

-3/7x = 6/35 to get x alone, you must divide all terms by the numerical coefficient (the number before the variable) of x, thus: (-3/7)x/(-3/7) = (6/35)/(-3/7) = -(6/35)/(3/7) *i just rewrite the negative sign outside* on the left side, -3/7 will be cancelled, and on the right...
*November 8, 2010*

**integrals!!**

first graph y = 2x + 8,, now, using the boundaries given, find the value of y at x = -4, and find the value of y at x = 1: at x=-4, y = 2(-4) + 8 = 0 at x=1, y = 2(1) + 8 = 10 now, look for these points on your graph and draw a vertical line (this is only a guide) from this ...
*November 8, 2010*

**calculus**

first, you have to get the value of x where |x^2 - 1| becomes zero, thus x = -1 and 1 since the boundaries given are only from 0 to 4, we consider only what happens to the graph at x = 1 (because 1 is within the boundaries) first, draw or imagine the graph. the graph of x^2-1 ...
*November 8, 2010*

**math**

right. :) but since it's amount per pound, the units must be in dollars/pound.
*October 29, 2010*

**math**

right. :) now, subtract them to get amount per pound that can be saved.
*October 29, 2010*

**math**

right. :) how about 15.5/25 = ?
*October 29, 2010*

**math**

you have to solve for amount per pound of each: 23.5/50 = ? 15.5/25 = ? then subtract the answers you got to get the amount per pound that can be saved by buying the lower unit price. hope this helps. :)
*October 29, 2010*

**chem**

are 7.60 and 3.00 in moles? if it is, recall the formula relating moles (n) and volume (V), at a constant P and T: n1 / V1 = n2 / V2 plug in the given values to the equation: 7.60 mol/ 31.0 = (7.60 + 3) mol / V2 then solve for V2. hope this helps. :)
*October 29, 2010*

**math**

is a and b restricted only to positive numbers (or can they be negative)?
*October 29, 2010*

**math**

useful conversion: 1 km = 1000 m 1 hr = 60 min = 60*60 s *note: you can rewrite 846 km/hr into: (846 km)*(1/hr) thus, using dimensional analysis to cancel units, (846 km)*(1000 m / 1 km) = 846*1000 m (1/hr)*(1 hr / 60*60 s) = 1 / 60*60 s now multiply both: 846*1000 * 1/(60*60...
*October 29, 2010*

**Chemistry**

molarity is moles of solute per liter of solution: M = moles/L plug in the given values in the equation, therefore: M = 1.77 / 30.6 = 0.0578 M is it required to write the answer in correct number of significant figures? if not, i think 0.06 M is acceptable ; but if yes, it ...
*October 29, 2010*

**Physics**

nope. it's not D,, power is work per unit time, or P = w/t where w = work in Joules (J) and t = time in seconds (s) thus the unit of power is Joules/second or J/s (A) hp = horsepower --> a unit of power,, (B) J = Joules --> unit of work (C) W = watts --> a unit of...
*October 29, 2010*

**math**

oh, i see you already have an answer,, right. the difference is 3/8 m/s. :)
*October 29, 2010*

**math**

nope,, 15 3/8 is greater than 15,, it's like you have 15 whole pizza plus 3 slices, while the other has only 15 whole pizzas, that's why, 15 3/8 > 15 then, "by how much" means you will get the difference: 15 3/8 - 15 = ?
*October 29, 2010*

**math**

yes, that's right~! :) now comparing the speed: Anna: 15 Julia: 15 3/8 which of the two is slower (or has smaller speed)? then, "by how much" means you will get the difference: 15 3/8 - 15 = ?
*October 29, 2010*

**math**

right~! :) now, we simplify 246/16,, since the numerator and denominator have a common factor 2, we can cancel it out: (2*123)/(2*8) = 123/8 123/8 is in simplest form,, now change this to mixed number.
*October 29, 2010*

**math**

you're on the right track,, now, what is 60/4 ?
*October 29, 2010*

**math**

nope, it's not 12,, remember that a whole number can be written to: 20 = 20/1 now, 20/1 * 3/4 = ? ..and we will not divide the answer by 246/16,, we will just compare them. first, let me see your answer.
*October 29, 2010*

**math**

when dividing a number by a fraction, first get the reciprocal of the fraction,, *to get reciprocal: you just interchange the numerator and denominator, thus: reciprocal of 4/3 = 3/4 now the operation becomes multiplication instead of division: 20 * (3/4) i think you know how ...
*October 29, 2010*

**math**

it's 20/(4/3),, first simplify this,,
*October 29, 2010*

**math**

recall that speed or rate is distance traveled over time, or: speed, v = d/t thus, you compare Anna's speed and Julia's speed: Anna: v = 20/(1 1/3) Julia: v = 246/(16) *note: first convert mixed number to improper fraction before dividing. hope this helps. :)
*October 29, 2010*

**College Algebra URGENT**

(fog)(x) is also f(g(x)) which means you substitute g(x) to the function of f(x),, (the x variables in f(x) will be g(x)), thus: (fog)(x) = 1/([g(x)]+4) (fog)(x) = 1/[(1/(6x+4) + 4] then simplify it.
*October 29, 2010*

**math correct or not correct**

Right. :)
*October 29, 2010*

**math correct or not correct**

right~! :)
*October 29, 2010*

**chemistry **

simplified energy balance: Q,absorbed + Q,lost = 0 , or Q,absorbed = -Q,lost where Q = m*c(Tf - Ti) in which Q=heat in J, m=mass in kg, c=specific heat capacity (which has a definite value for various substances) in J/(kg*C), T=temperature in Kelvin *Tf=final temp (the same ...
*October 29, 2010*

**math **

Right~! :) qt/day is fine. no need to write 1.
*October 29, 2010*

**math **

since 1440 is a whole number, you can rewrite it as 1440 = 1440/1 *any whole number divided by 1 is itself. then multiply fractions like normal multiplication,, numerator: number above the line, denominator: number below the line, numerator times numerator, and denominator ...
*October 29, 2010*

**math **

right, 24*60 = 1440 then 1440 * 5/8 = ?
*October 29, 2010*

**math **

recall these conversions: 1 qt = 32 fl oz 1 day = 24 hours = 24*60 minutes using dimensional analysis to cancel units: (20 oz)*(1 qt/32 oz) = 20/32 = 5/8 qt (1/1 min)*(24*60 min/1 day) = 24*60/day now multiply them (units in qt/day): (5/8)*(24*60) how do you multiply fractions...
*October 29, 2010*

**Math **

True. it's actually a theorem.
*October 29, 2010*

**Calculus**

is that ln (x^2) or (ln x)^2 ? anyway, in any case, it is not differentiable at x = 0 because if you get the derivative, for ln (x^2): ln (x^2) = 2*ln x derivative of 2*ln x = 2/x for (ln x)^2: derivative (ln x)^2 = 2*(ln x)/x if you substitute x=0 to the derivative, the ...
*October 29, 2010*

**physics**

acceleration is change in velocity over time, or: a = (v - v0)/t where v = final velocity in m/s v0 = initial velocity in m/s t = time in s assuming that it is initially at rest, v0 = 0,, the final velocity, v, is the speed of light, which is approximately 3.0 x 10^8 m/s ...
*October 29, 2010*

**physics**

first, recall formula for Force: F = ma where m = mass in kg, and a = acceleration in m/(s^2) then also recall the formula for acceleration,, acceleration is change in velocity over time, thus: a = (v - v0)/t where v = final velocity in m/s v0 = initial velocity in m/s t = ...
*October 28, 2010*

**physics**

acceleration is change in velocity over time, or: a = (v - v0)/t where v = final velocity in m/s v0 = initial velocity in m/s t = time in s assuming that it is initially at rest, v0 = 0,, the final velocity, v, is the speed of light, which is approximately 3.0 x 10^8 m/s ...
*October 28, 2010*

**physics**

first, recall formula for Force: F = ma where m = mass in kg, and a = acceleration in m/(s^2) then also recall the formula for acceleration,, acceleration is change in velocity over time, thus: a = (v - v0)/t where v = final velocity in m/s v0 = initial velocity in m/s t = ...
*October 28, 2010*

**math **

where is a and b? and is the "t" in the equations plus or another variable?
*October 28, 2010*

**algebra**

you're welcome, Jordyn! :)
*October 28, 2010*

**algebra**

(36x^2 - 49y^2)/(6x + 7y) notice that the numerator is a difference of two squares,, recall: a^2 - b^2 = (a+b)(a-b) thus the numerator can be factored into: (6x+7y)(6x-7y)/(6x+7y) then cancel the common factor and you get 6x - 7y hope this helps.
*October 28, 2010*

**math**

recall these conversions: 1 qt = 32 fl oz 1 day = 24 hours = 24*60 minutes using dimensional analysis to cancel units: (20 oz)*(1 qt/32 oz) = 20/32 = 5/8 qt (1/1 min)*(24*60 min/1 day) = 24*60/day now multiply them (units in qt/day): (5/8)*(24*60) = ? hope this helps.
*October 28, 2010*

**math**

no,, check again your multiplication.
*October 28, 2010*

**math**

recall these conversions: 1 qt = 32 fl oz 1 day = 24 hours = 24*60 minutes using dimensional analysis to cancel units: (20 oz)*(1 qt/32 oz) = 20/32 = 5/8 qt (1/1 min)*(24*60 min/1 day) = 24*60/day now multiply them (units in qt/day): (5/8)*(24*60) = ? hope this helps.
*October 28, 2010*

**math**

recall these conversions: 1 qt = 32 fl oz 1 day = 24 hours = 24*60 minutes using dimensional analysis to cancel units: (20 oz)*(1 qt/32 oz) = 20/32 = 5/8 qt (1/1 min)*(24*60 min/1 day) = 24*60/day now multiply them (units in qt/day): (5/8)*(24*60) = ? hope this helps.
*October 28, 2010*

**Calculus**

is that the derivative? if it is, ln(1/x) can be written as: ln (x^-1) = -ln(x) since the derivative of ln (x) is 1/x, then derivative of -ln(x) = ln(1/x)= -1/x hope this helps.
*October 28, 2010*

**Find the limit**

first, we observe what happens when t approaches 5: lim (t+2)/(t-5) as t->5 7/0 = infinity which can be (+) or (-) infinity since it's 5- or to the left of 5, some of the values can be 4.99, 4.999, 4.9999,, if we choose for instance, 4.999, 4.999 - 5 = -0.001 *negative...
*October 28, 2010*

**chemistry**

punctuation? ...or do you mean units? molar mass can be in g/mol or lb/lbmol... they can be found in periodic table of elements.
*October 28, 2010*

**maths **

alright then. if using L'hopital's Rule is not allowed, then recall the property: lim (sin x)/x = 1 as x->0 therefore, lim [sin(x-1)]/(x^2 + x - 2) we can factor the denominator: (x^2 + x - 2) = (x-1)(x+2) we can then re-write the limit as: lim [sin(x-1)]/[(x-1)(x+2...
*October 28, 2010*