Friday

May 6, 2016
Total # Posts: 1,989

**Pre-algebra**

-5(3e-2)<-2(6e+7) -15e + 10 < -12e - 14 -3e < -24 e > 8 *note that when dividing both sides of the equation by negative number, the sign changes to its opposite. like here, both sides were divided by -3 and the sign changes from < to >. hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

-3(2b+4)>4(b+7) -6b - 12 > 4b + 28 -10b > 40 b < -4 *note that when dividing both sides of the equation by negative number, the sign changes to its opposite. like here, both sides were divided by -10 and the sign changes from > to <. hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

48>3(w+7) 48 > 3w + 21 27 > 3w 9 > w or w < 9 hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

-12(c-6)<120 -12c + 72 < 120 -12c < 48 c > -4 *note that when dividing both sides of the equation by negative number, the sign changes to its opposite. like here, both sides were divided by -12 and the sign changes from < to >. hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

7(v+5)>56 7v + 35 > 56 7v > 21 v > 3 hope this helps~ :)
*May 23, 2011*

**Math**

but we need the figure to solve for this.
*May 23, 2011*

**Math**

you can answer this in two ways~ systematic way (lol): let x = units digit let y = tens digit from the second statement, (1) xy = 14 from the first statement, (2) 10x + y = 3(10y + x) - 9 from equation (1), we can express y in terms of x, yielding y = 14/x substituting this to...
*May 23, 2011*

**Math**

2x^2 + 7x -15 =0 (2x - 3)(x + 5) = 0 therefore, x = 3/2 and x = -5 hope this helps~ :)
*May 22, 2011*

**physics**

just imagine when you dribble. you use force (directed downward) from your hand to "throw" it downwards.
*May 22, 2011*

**algebra**

numerical coefficients : 2, 4, 8
*May 22, 2011*

**algebra**

(-8x^2-2x+4)+(x^2-9x+7) to add, we just combine the numerical coefficients (or the numbers before the variable) of the same variables (meaning same letters and same exponents). thus, (-8x^2 - 2x + 4 ) + ( x^2 - 9x + 7 ) -7x^2 - 11x + 11 hope this helps~ :)
*May 22, 2011*

**chemistry**

(1) assuming the gas is ideal, the volume becomes 1/3 of the original. (2) recall that STP, pressure is at 1 atm. assuming the gas is ideal, P1*V1 = P2*V2 where P1 = initial pressure V1 = initial volume P2 = final pressure V2 = final volume substituting, 1*2000 = (P2)*15 P2 = ...
*May 21, 2011*

**math**

i think you mean 3k^2 + 6k = 6 thus, we can re write this as 3k^2 + 6k - 6 = 0 note that we can factor out 3 from each term and cancel it. thus we can re write this as k^2 + 2k - 2 = 0 using quadratic formula, k = [-b +- sqrt(b^2 - 4ac)]/(2a) substituting, k = [-2 +- sqrt(2^2...
*May 21, 2011*

**algebra2**

to do this, we just multiply the exponents. [x^9]^11/7 x^(9*11/7) x^(99/7) hope this helps~ :)
*May 17, 2011*

**Maths**

|| means they are parallel. since AB and CD are parallel, they will never meet.. thus i think the first statement is wrong that they meet at point E.
*May 17, 2011*

**Algebra**

(q-2)/4 * -2q/(q+5) to multiply, we just multiply numerator by numerator and denominator by denominator. thus, this becomes: (q-2)(-2q) / (4)(q+5) observe that we can factor 2 from numerator and denominator and cancel it, and this becomes: -q(q-2) / (2)(q+5) hope this helps~ :)
*May 17, 2011*

**science**

recall that current is voltage per resistance, or I = V/R *units of current in Amperes (A) *units of voltage in Volts (V) *units of resistance in ohms (Ω) substituting, 8 = 1.1/R R = 1.1/8 = 0.1375 Ω hope this helps~ :)
*May 17, 2011*

**chemistry **

first thing to do here is to balance the chemical equation. 2Na + Cl2 --> 2NaCl then we get the masses of Sodium and Chlorine from periodic table of elements in order to calculate the molar mass of NaCl. from periodic table, Na = 23 Cl = 35.5 thus, NaCl = 23+35.5 = 58.5 g/...
*May 17, 2011*

**math help please !!!**

*reposted -- because i think you haven't read my previous post in this problem* first, we solve for the initial velocity from the formula of the maximum height: h,max = [(vo)^2]/(2g) where vo = initial velocity g = acceleration due to gravity = 9.8 m/s^2 substituting, 30...
*May 17, 2011*

**geometry**

note that complement means the other angle in which their sum should be 90. thus to get the complement of each angle, we just subtract them from 90: 90 - 44 = 46 90 - 15 = 75 90 - 72 = 18 90 - 89 = 1 90 - 10 = 80 90 - 30 = 60 hope this helps~ :)
*May 16, 2011*

**math**

we'll solve this in two cases: Case I: absolute value is positive. |n+1| < 4 n+1 < 4 n < 3 Case II: absolute value is negative. |n+1| < 4 -(n+1) < 4 n+1 > -4 n > -5 getting the intersection (common between them) of the two answers, thus n must be ...
*May 15, 2011*

**Algebra**

the formula is wrong. it should be y = a(x-h)^2 + k where (h,k) is the center then to solve for a, you choose one of the points to substitute for the value of x and y. for instance you choose (-4,-1): y = a(x-h)^2 + k -1 = a(-4+3)^2 - 2 then solve for a. if you want to make ...
*May 15, 2011*

**Algebra**

yes~ :)
*May 15, 2011*

**Algebra**

yes, you're right. :)
*May 15, 2011*

**Algebra-right question for Jai**

the volume of a triangular prism is given by V = (1/2)*(B*H*L) where B = base H = height L = length thus the new volume becomes, V' = (1/2)*(2*B)(2*H)*L V' = 2*(1/2)*(B*H*L) or V' = 2*V thus the new volume is twice the original. note that first statement is tricky...
*May 15, 2011*

**Algebra- word problem**

sure~ :)
*May 15, 2011*

**Algebra- word problem**

original area: A = L*W A = 6*3 = 18 in^2 new area: A' = L'*W' A' = 8*5 = 40 in^2 the difference between these areas is the amount of wall space needed: 40-18 = 22 in^2 thus it's A. hope this helps~ :)
*May 15, 2011*

**algebra**

recall that the volume of a rectangular prism is given by V = L*W*H where L = lenght W = width H = height. if 4 is multiplied to both length and width, the new volume, V', is V' = (4L)*(4W)*(H) V' = 16*(L*W*H) or V' = 16*V thus the new volume is 16 times ...
*May 15, 2011*

**algebra**

oh, i see.. the choices are wrong. i guess you typed it wrong because "volume" is in the choices.. it must be "area" since it is the required. (and rectangles don't have volume)
*May 15, 2011*

**algebra**

original area: A = L*W new area: A' = (3L)*(3W) A' = 9*(L*W) or A' = 9*A thus there is no correct answer in the choices, since the new area is 9 times greater than the original. hope this helps~ :)
*May 15, 2011*

**algebra**

yes~ :) original area: A = L*W new area: A' = (3L)*(3W) A' = 9*(L*W) or A' = 9*A thus there is no correct answer in the choices, since the new area is 9 times greater than the original. hope this helps~ :)
*May 15, 2011*

**Math**

(a) to get this, we just use ratio and proportion: let x = weight of 150 books. 108 books : 30 kg = 150 books : x kg we can thus rewrite this as 108/30 = 150/x 3.6 = 150/x x = 150/3.6 x = 41.67 kg (b) we also use ratio and proportion here: let y = number of books that has ...
*May 15, 2011*

**physics**

recall that the volume of a sphere (geometry of the ball) is given by V = (4/3)πr^3 where r = radius π = 3.14 (constant) thus to get radius, we need to first get the volume from the given mass and density. recall that density is just mass per volume, or d = m/V ...
*May 15, 2011*

**Math**

#1 to get this, we just use ratio and proportion. let x = weight of 1000 cm^3 liquid. 250 cm^3 : 125 g = 1000 cm^3 : x g thus we can rewrite this as, 250/125 = 1000/x solving for x, 2 = 1000/x 2x = 1000 x = 500 grams #2 here, we also use ratio and proportion. first we convert ...
*May 15, 2011*

**algebra**

to get this, you just substitute t=6 to the given equation: v = (-1/2)t + 3 v = (-1/2)*6 + 3 v = -3 + 3 v = 0 plot: h t t p : / / w w w 4 c . w o l f r a m a l p h a . c o m / Calculate/MSP/MSP412219fd25cdf0efbh880000587daeb9i9ea74bg?MSPStoreType=image/gif&s=11&w=424&h=166&cdf...
*May 15, 2011*

**math**

first, we solve for the initial velocity from the formula of the maximum height: h,max = [(vo)^2]/(2g) where vo = initial velocity g = acceleration due to gravity = 9.8 m/s^2 substituting, 30 = [(vo)^2]/(2*9.8) vo = sqrt(588) vo = 24.25 m/s (a) note that the motion of the ...
*May 15, 2011*

**algebra**

*reposted* 9t^4 + 7t - 45 t^3 + 10t note that when combining terms with variables, we just add the numerical coefficient of the same variable (and exponent). here, we can only combine 7t and 10t. thus 9t^4 + 7t - 45 t^3 + 10t 9t^4 + 17t - 45 t^3 rearranging, 9t^4 - 45 t^3 + ...
*May 14, 2011*

**algebra**

*reposted* 9t^4 + 7t - 45 t^3 + 10t note that when combining terms with variables, we just add the numerical coefficient of the same variable (and exponent). here, we can only combine 7t and 10t. thus 9t^4 + 7t - 45 t^3 + 10t 9t^4 + 17t - 45 t^3 rearranging, 9t^4 - 45 t^3 + ...
*May 14, 2011*

**math**

sin 90 = 1 hope this helps~ :)
*May 14, 2011*

**math**

sin 90 = 1 hope this helps~ :)
*May 14, 2011*

**algebra**

9t^4 + 7t - 45 t^3 + 10t note that when combining terms with variables, we just add the numerical coefficient of the same variable (and exponent). here, we can only combine 7t and 10t. thus 9t^4 + 7t - 45 t^3 + 10t 9t^4 + 17t - 45 t^3 rearranging, 9t^4 - 45 t^3 + 17t hope this...
*May 14, 2011*

**Math**

first observe that you are 24 years older than your son. also, since we are required of the ages, we represent these unknown ages using variables: let x = your son's age let x+24 = your age note that when your son's age is x years, you are three times as old. therefore...
*May 14, 2011*

**Applied Physics**

equilibrium means that all forces acting on the object are balanced / cancel each other out. it can also mean that the object is not accelerating. thus, an object can be in equilibrium whether it is motion or not, as long as forces are balanced. since it's said that it ...
*May 14, 2011*

**Chemistry**

to get the heat released or absorbed, Q = mc(T2-T1) where m = mass of substance (units in g) c = specific heat capacity (units in J/g-K) T2 = final temperature T1 = initial temperature **note: if Q is (-), heat is released and if (+), heat is absorbed now we can only apply ...
*May 14, 2011*

**Chemistry**

to get the heat released or absorbed, Q = mc(T2-T1) where m = mass of substance (units in g) c = specific heat capacity (units in J/g-K) T2 = final temperature T1 = initial temperature **note: if Q is (-), heat is released and if (+), heat is absorbed for water c = 4.184 J/g-K...
*May 14, 2011*

**Math**

X(bar) = 10,000 M = 1,000 D = 500 C = 100 L = 50 X = 10 I = 1 thus XMMDCLXII is equal to 12,662 hope this helps~ :)
*May 14, 2011*

**mensuration**

recall that the area of rectangle is given by A = L*W where L is length and W is width. substituting, A = 20*12 = 240 m^2 (we'll use this later) since there is 2 m wide path, (and thus there is total of 4 m on both sides), 20 - 4 = 16 m 12 - 4 = 8 m getting the area of ...
*May 14, 2011*

**physics**

hello~ you can find answers on google. just type "why candle flame up" , there are links discussing this topic. i can't post links here that's why~ ^^;
*May 13, 2011*

**Math- college**

to get this, we just use ratio and proportion: let x = miles travelled with 24 gallons 22 miles : 1 gallon = x miles : 24 gallons therefore, 22/1 = x/24 x = 22*24 x = 528 miles hope this helps~ :)
*May 13, 2011*

**Math- college**

(a) to get this, we just divide 1148 by 13. type this in you calculator: 1148 / 13 the answer must be 88.308. since the number of bags can not be decimal, we only take the whole number, which 88 sand bags. (b) to get this, we multiply the number of bags used (which is 88) by ...
*May 13, 2011*

**Math**

first let's represent their weights using variables: let C = weight of one piece of cake let A = weight of one apple let H = weight of one cherry from the first statement, (1) 2C = A + H for the second statement, (2) A = 5H + C now we need to find how mach does cherries ...
*May 13, 2011*

**Algebra 8th**

do you mean "square root" for the "radical"? if so, 2[sqrt(8) + sqrt(5)] note that we cannot combine the radical terms since their radicands (term inside the radical sign) are not equal. but we can rewrite this as 2[2*sqrt(2) + sqrt(5)] 4*sqrt(2) + 2*sqrt(5...
*May 13, 2011*

**Calculus**

recall that the derivative of cos^-1 (x) or arccos (x) is -1/[sqrt(1-x^2)] * dx thus the derivative of cos^-1 (x^2) -(2x)/[sqrt(1 - x^4)] note that the 2x is the dx that came from the derivatice of the term inside the cos^-1, which is x^2. hope this helps~ :)
*May 13, 2011*

**Math**

to convert PERCENT to DECIMAL, we move 2 decimal places to the LEFT. thus for 0.06%, we move 2 decimal places, and it becomes: 0.0006 now we know the decimal, we can convert this to fraction. first we count the places to the right of decimal point. there are 4 decimal places (...
*May 11, 2011*

**Geometry**

recall that length of arc is given by s = r*theta where r = radius theta = angle in radians first we convert the given angle to radians: 20 * pi/180 = pi/9 = 0.349 rad substituting, s = 1*0.349 s = 0.349 s = 0.35 (nearest hundredth) hope this helps~ :)
*May 11, 2011*

**physics **

(a) the motion of the book is projectile, and uniformly accelerated motion. thus we use the formula, h = ho + vo*t - (1/2)*g*t^2 where h = final height ho = initial height vo,y = initial vertical velocity = vo*sin(theta) t = time g = acceleration due to gravity (9.8 m/s^2) ...
*May 11, 2011*

**physics **

..what do you want to solve?
*May 11, 2011*

**math**

note that 36/9 is also equal to 4. thus we look for fractions that is also equal to 4. the denominator of 4 is 1 (any number divided by 1 is itself). thus we only multiply the numerator and denominator by the same number to get an equivalent fraction. for instance, let's ...
*May 11, 2011*

**math**

do you mean x^(2-n) ? if so at x = 8, 8^(2-n) = 0 , we can rewrite this as (8^2)/(8^n) = 0 64/8^n = 0 note that this equation has no solution and only at n-> infinity, it will approach zero. also at x=-8, it has no solution. hope this helps~ :)
*May 11, 2011*

**science**

in physics, note that mass is different from weight. mass has units in kilograms, grams, etc., while weight has units of Newton. (Newton = kg*m/s^2) to determine weight, we use the formula W = m*g where m = mass (in kg) g = acceleration due to gravity = 9.8 m/s^2 substituting...
*May 11, 2011*

**Physics(Please Help!!)**

* means multiply or times / means divided by to solve, input this on your calculator: 77.18 x 9.81 x 5.83 / 4.37
*May 9, 2011*

**geometry: volume of cone**

recall that volume of cone is given by V = pi*(r^2)*h/3 where pi = 3.14 (constant) r = radius h = height if r becomes (1/2)r, V,new = pi*[(1/2)r]^2*h/3 V,new = 1/4[pi*(r^2)*h/3] V,new = (1/4)V thus multiplied by 1/4. hope this helps~ :)
*May 9, 2011*

**math!!!!**

you use the distance formula: d = sqrt[ (x2 - x1)^2 + (y2 - y1)^2 ] where (x1,y1) = first point (x2,y2) = second point hope this helps~ :)
*May 9, 2011*

**math**

for the first question, we just use ratio and proportion. let x = time it takes to travel 3 miles. 0.75 mi : 0.25 min = 3 mi : x min therefore, writing in fraction, 0.75/0.25 = 3/x cross-multiplying, 0.75x = 0.25*3 0.75x = 0.75 x = 1 minute for the second, we also use ratio ...
*May 5, 2011*

**math**

it's positive~ example for (+) answer: 7 - 3 = 4 **3 (the lesser integer) is being subtracted from 7 (greater integer) other examples, -3 - (-8) = 5 0 - (-2) = 2 2 - (-1) = 3 hope this helps~ :)
*May 5, 2011*

**math**

note that the next term has a numerator 3 greater than the previous and has denominator 4 greater than the previous. thus, if 4/3 is the first term, (4 + 3(n-1))/(3 + 4(n-1)) where n = nth term (if 1st, n=1, if 2nd, n=2, etc.) or simplifying, (3n + 1)/(4n - 1) hope this helps~ :)
*May 5, 2011*

**Math**

x = -1/4 - 5/8 first, we convert 1/4 to a fraction whose denominator is 8, so that we can combine the fractions. we can do this by multiplying both numerator and denominator by 2: 1*2 / 4*2 = 2/8 therefore, x = -(2/8) - 5/8 then we simply add the numerator and copy the ...
*May 5, 2011*

**trig**

(1/m)= (m-34)/(2m^2) we cross-multiply: 2m^2 = m(m-34) 2m^2 = m^2 - 34m m^2 + 34m = 0 m(m+34) = 0 m = 0 and m = -34 but note that m = 0 is extraneous since when substituted back to original, 1/0 = (0-34)/(2*0^2) and any number divided by zero is undefined. thus x = -34 only. ...
*May 5, 2011*

**math**

(1) -4 + 7log(x) = 10 7log(x) = 14 log(x) = 2 x = 10^2 = 100 (2) log(x+3) + log(x-2) = log 14 recall some laws of exponents. when we add two log terms with same base, we can combine them by multiplying the terms inside the log. thus, we can rewrite this as, log[(x+3)(x-2)] = ...
*May 5, 2011*

**Algebra**

yes, you got the right answer for simplifying it. 2/(x^2-16) + 3/(x^2 -2x-8) = 5x+16/(x-4)(x+4)(x+2) but the question says that if numerator is equal to 6, what is x? thus we equate the numerator to 6: 5x + 16 = 6 5x = 6-16 5x = -10 x = -2 hope this helps~ :)
*May 5, 2011*

**math**

yes~ :)
*May 5, 2011*

**Quick Question**

25s + 25 = -15s first, we transpose all terms containing the variable s to one side of the equation (in this problem, let's transpose them to the left side), and all other terms to the other side. thus, we transpose -15s to the left side. to transpose, we change its sign ...
*May 4, 2011*

**Math**

it's (x^11)*sqrt(x), because sqrt(x^23) sqrt(x*x^22) sqrt( x * (x^11)^2 ) then sqrt of (x^11)^2 is x^11, so we can take it out: x^11 * sqrt(x) hope this helps~ :)
*May 4, 2011*

**precalc**

domain = set of all possible values of x range = set of all possible values of y therefore, (1) y = sqrt(x-3) note that the term inside the sqrt can be zero but cannot be negative, for it will become imaginary. thus, Domain: x must be greater than or equal to 3. also, y can be...
*May 4, 2011*

**physics**

the energy needed to increase or decrease the temperature of a given substance is given by Q = mc(T2-T1) where Q = heat (in J or cal) m = mass (in g) c = specific heat capacity (in J/g*K or cal/g*K) T = temperature (in Kelvin) **change in temperature can have unit degree ...
*May 4, 2011*

**Math**

first, we factor the radicand (the term inside the radical sign or the squreroot): sqrt(27*b^11) sqrt[ (3*3*3) (b*b^10) ] then we separate the perfect squares: sqrt[ 3*(3^2) b*((b^5)^2) ] and we take the squarerrot of the perfect squres. the squareroot of 3^2 is 3, while (b^5...
*May 4, 2011*

**MAth**

they are the reciprocal of each other. *reciprocal = when you interchange the value of numerator and denominator hope this helps~ :)
*May 4, 2011*

**algebra**

substituting, A = (1/2)bh A = (1/2)(30)(30) A = 450 m^2 hope this helps~ :)
*May 3, 2011*

**IPC**

there was a typo. from the first paragraph, ...this only means that when two objects are in thermal equilibrium (or their temperature is the same/equal), NO heat is being transferred... and the rest is ok. :)
*May 3, 2011*

**IPC**

Zeroth Law of Thermodynamics = two objects in thermal equilibruim will have no net heat flow between them. **this only means that when two objects are in thermal equilibrium (or their temperature is the same/equal), heat is being transferred. this is a consequence of the ...
*May 3, 2011*

**geometry**

recall that the general equation of a circle is given by (x - h)^2 + (y - k)^2 = r^2 where the point (h,k) is the center of the circle, and r is the radius. thus in the given equation, (x + 4)^2 + (y – 9)^2 = 18 18 = r^2 therefore, r = sqrt(18) = 3*sqrt(2) and so the ...
*May 3, 2011*

**IPC**

the energy needed to increase or decrease the temperature of a given substance is given by Q = mc(T2-T1) where Q = heat (in J or cal) m = mass (in g) c = specific heat capacity (in J/g*K or cal/g*K) T = temperature (in Kelvin) **change in temperature can have unit degree ...
*May 3, 2011*

**math**

thousands
*May 3, 2011*

**math**

to round off, first you need to know the place of the digit you want to round off,, in the problem it's "to the nearest ten". then we look at the number to the right of tens digit if the number to the right of tens digit is: *greater than or equal to 5, you add 1...
*May 3, 2011*

**algebra1**

..then?
*May 2, 2011*

**Chem5**

recall that density is mass over volume, or d = m/V substituting, 1 = m / 4200 m = 4200 g H2O to get the mass of dioxin, we just multiply its percent mass: 4200 * 0.00052 = 2.184 g dioxin hope this helps~ :)
*May 2, 2011*

**physical science**

assuming the gas is ideal, we can use Charles' Law: V1/T1 = V2/T2 where V1 = initial volume V2 = final volume T1 = initial temperature (in Kelvin) T2 = final temperature (in Kelvin) we first convert the given temp to Kelvin: T1 = 30 + 273.15 = 303.15 K substituting, V1/T1...
*May 2, 2011*

**calculus**

yes. the substitution is correct: let u = x^(1/2) thus du = 1/[2(x^(1/2))] dx, or dx = 2(x^(1/2)) du, or dx = 2u du substituting these to original integral, integral of [e^x^(1/2) / x^(1/2)] dx integral of [(e^u) / u] * (2u) du the u's will cancel out: integral of [2*e^u] ...
*May 2, 2011*

**algebra 1**

3(2x-5) > x+15 6x - 15 > x + 15 combining similar terms, 6x - x > 15 + 15 5x > 30 x > 6 hope this helps~ :)
*May 2, 2011*

**physics**

assuming the air is ideal, we can use the formula, P1/T1 = P2/T2 where P1 = initial pressure P2 = final pressure T1 = initial temperature (in Kelvin) T2 = final temperature (in Kelvin) we first convert the given temp to Kelvin: T1 = 20 + 273.15 = 293.15 K T2 = 250 + 273.15 = ...
*May 2, 2011*

**Math**

(2/3)y = (-1/5)x to get the slope, we first transform this equation into slope-intercept form, y = mx + b where m = slope and b = y-intercept. note that the numerical coefficient of y (number before the variable y) in slope-intercept form is 1, thus to change the given ...
*May 2, 2011*

**math**

note that in elimination method, we first simplify/modify one (or both) the given equation until if we add the two given equation, one of the variables will cancel out. in the problem, we can obviously see that the 2y in the first equation will be cancelled out by the -2y of ...
*May 2, 2011*

**math**

..it's difficult to show long division here,, but the answer is 4 - 4x.
*May 2, 2011*

**math**

(3x + 3)(-4x^2 + 4x - 2) -12x^3 + 12x^2 - 6x - 12x^2 + 12x - 6 note that the 12x^2 and -12x^2 will cancel out, and we combine -6x and 12x: -12x^3 + 6x - 6 hope this helps~ :)
*May 2, 2011*

**math**

f(x) = x^2 – 18x + 81 f(x) = 16 substituting the value of f(x) to the quadratic equation, 16 = x^2 - 18x + 81 0 = x^2 - 18x + 81 - 16 0 = x^2 - 18x + 65 0 = (x-13)(x-5) thus, x = 13 and x = 5 hope this helps~ :)
*May 2, 2011*

**math**

*reposted* ..it's difficult to show long division here,, but the answer must be 4 - 4x.
*May 2, 2011*

**Physical Science**

i'll try my best to explain them as simple as possible. (i) distance - how far an object has moved. it is in units of length (meters, kilometers, etc) (ii) speed - distance traveled over certain time, or in formula, v = d/t where v = speed d = distance t = time it has ...
*May 2, 2011*

**Calculus**

x^2 / ln 3x getting the derivative, [(2x)(ln 3x) + (x^2)(1/(3x))(3)] / [(ln 3x)^2] simplifying, [ (2x)ln 3x + x ]/[(ln 3x)^2] hope this helps~ :)
*April 30, 2011*

**Algebra**

note that you cannot simplify the right side equation log3 (4) + log3 (y+8) , by 4 + y + 8 ... they should be multiplied. recall some laws of exponents; if we are add terms of the same base, for example log 3 + log 5 this simplifies to log(3*5) or log 15 going back to the ...
*April 30, 2011*

**Algebra Unit Analysis**

for #1, 1 mi = 1609.344 m since we need units in cubic meters, we raise both sides by 3: (1 mi)^3 = (1609.344 m)^3 1 mi^3 = 4168181825.44 m^3 for #2, we first convert the 58 ft into miles. we use ration and proportion (let n = unknown): 1 mi : 5280 ft = n mi : 58 ft thus 1/...
*April 30, 2011*