Sunday

February 7, 2016
Total # Posts: 1,926

**math**

let x = initial number of stickers then set up the equation: x-26 = 2(x-38) x - 26 = 2x - 76 -x = -76 + 26 -x = -50 x = 50 stickers hope this helps~ :)
*October 21, 2011*

**Math**

the equation is not given..
*October 21, 2011*

**chemistry**

recall that the amount of heat absorbed or released is given by: Q = mc(T2-T1) where m = mass (in g) c = specific heat capacity (in J/g-K) T = temperature (in C or K) *note: Q = (+) when heat is absorbed and (-) when heat is released to get the final temp, we note that Q,...
*October 20, 2011*

**Math**

to do this, we substitute h = 3 to the equation and solve for x: h = -0.005x^2 + x + 3 3 = -0.005x^2 + x + 3 0 = -0.005x^2 + x 0 = x(-0.005x + 1) x = 0 (this is extraneous) x = 1/0.005 = 200 ft hope this helps~ :)
*October 20, 2011*

**Algebra 2**

#1 -16 + 17(5-y²)-(5-y²)² let X = (5-y²) -16 + 17X - X² -(16 - 17X + X²) -(X² - 17X + 16) -(X - 16)(X - 1) substituting back X, -((5-y²) - 16)((5-y²) - 1) or (11 - y²)(4 - y²) #2 [x + y + 1][x² - x(y + 1)+(y + 1)²...
*October 20, 2011*

**chemistry**

recall that the amount of heat absorbed or released is given by: Q = mc(T2-T1) where m = mass (in g) c = specific heat capacity (in J/g-K) T = temperature (in C or K) *note: Q = (+) when heat is absorbed and (-) when heat is released to get the final temp, we note that Q,...
*October 20, 2011*

**Algebra 2**

you can factor (y-1)² from both, resulting to: (y-1)² [(y-1)² -1] since both terms inside the bracket are perfect squares, we can still factor them, resulting to: (y-1)² [(y-1)-1][(y-1)+1] or (y-1)² [y-2][y] rewriting, y(y-2)(y-1)(y-1) hope this helps~ :)
*October 20, 2011*

**Math**

first represent the unknowns using variables: let 2x = shortest piece let 7x = 2nd longest piece let 11x = longest piece from the second statement, the longest piece is 72 longer than the shortest: 11x = 72 + 2x solving for x, 11x - 2x = 72 9x = 72 x = 8 the length of the ...
*October 15, 2011*

**Algebra**

(a) represent the unknowns using variables: let x = be the smaller odd integer (b) since the difference between any odd integers is always 2, we must add 2 to the smaller odd integer to get the next odd integer. (c) let x + 2 = be the greater odd integer (d) since it is stated...
*October 14, 2011*

**pre-algebra**

just follow PEMDAS: Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction. this is the order in which operation must be performed first. thus, #1. 12^2 + 2[(13+3)] / 2^2] 144 + 2[(16)/4] 144 + 2[4] 144 + 8 152 #2. -4(3)+5[7-6(-4)^2] -12 + 5[7 - 6*(16)] -12 + ...
*October 14, 2011*

**algebra 2**

*i think you mean the ZEROS / ROOTS are 5, 2i and -2i. if so, you can get them by multiplying and expanding, (x-5)(x-2i)(x+2i) note that 1 = sqrt(-1) but an easier method would be, to start with the roots 2i and -2i. recall that q quadratic equation follows the formula, x^2...
*October 14, 2011*

**Math**

(1/8)b = 6 b = 6*8 = 48
*October 13, 2011*

**Algebra**

recall that area of triangle is given by: A = (1/2)*bh where A = area, b = base, and h = height. substituting, 2x^2 + 5x + 3 = (1/2)*(4x+6)*b we do factoring: 2x^2 + 5x + 3 = (1/2)*2*(2x+3)*b (2x+3)*(x+1) = (2x+3)*b then we divide both side by 2x+3. therefore, b = x+1 hope ...
*October 13, 2011*

**algebra**

-18 + |-12| *absolute value: distance from the origin (which is zero). to get this, just take the positive value of the number inside: -18 + 12 -6 hope this helps~ :)
*October 12, 2011*

**Math**

let x = the other number then we set-up the equation. 4*(x-14) = (1/2)*(x+14) 4x - 56 = (1/2)x + 7 4x - 0.5x = 56 + 7 3.5x = 63 x = 18 hope this helps~ :)
*October 9, 2011*

**math**

distributive property
*October 9, 2011*

**Math**

p less than 5: 5 - p p greater than 10: 10 + p 9 times sum of p and 6: 9*(p+6)
*October 8, 2011*

**Math - fractions**

to multiply fractions, just multiply the numerator by numerator, and denominator by denominator. (note: numerator = the number above the fraction bar, while denominator = the number below the fraction bar). thus: 9/16 * 14/15 (9*14) / (16*15) 126 / 240 or 21/40 yd^2 hope this ...
*October 8, 2011*

**Algebra**

for the first problem: -a = 5 to get a, you divide both sides of equation by the numerical coefficient (number before the variable) of a. the numerical coefficient of a is -1, thus: -a/(-1) = 5/(-1) a = -5 for problem 2, 3 and 4: do the same procedure as what we did to problem...
*October 8, 2011*

**Algebra 2**

3y + 6 > 21 3y > 21 - 6 3y > 15 y > 5 graph: h t t p : / / w w w . w o l f r a m a l p h a . com/input/?i=3y+%2B+6+%3E+21
*September 17, 2011*

**Pre-Calc**

you're right. you can do log144/log6 the sign will not be switched.
*September 10, 2011*

**Algebra**

first you represent the unknown with variable: let x = number of hours you rent the canoe then we set-up the equation. since the rate is $10 per hour, we multiply the number of hours (which is x) by 10 and add the usage fee to get the total amount. thus, 10x + 5 = 45 hope this...
*September 10, 2011*

**geometry**

i'm not actually sure about this, but what do you mean "x is the measurement outside the square"? is it the length of the square? because if you have a circle inside a square, you can find right away the area of the whole square using the given radius r. the side...
*September 10, 2011*

**algebra**

if K is between JL, then we can say that the sum of the lengths of JK and KL is equal to JL, or JK + KL = JL 6x + 3x = 27 9x = 27 x = 3 KL = 3x = 9 hope this helps~ :)
*September 10, 2011*

**Chem**

amount of energy absorbed or released is given by Q = mc*(T2 - T1) where Q = heat (in Joules) m = mass (in grams) c = specific heat capacity (J/g-K) T = temperature (in Celsius or Kelvin) *note that Q is (+) if the object absorbed heat, and (-) if it released heat. for water, ...
*September 10, 2011*

**physics 180**

recall that for a projectile motion, the maximum height that the object can reach is given by the formula, h,max = [(vo)^2 * sin^2 (θ)]/(2g) where vo = initial velocity θ = angle of release g = acceleration due to gravity = 9.8 m/s^2 the unknown in the problem is vo...
*September 10, 2011*

**Math**

3(x-2)(x+6) since we want to expand this, we can use the FOIL method: multiply the FIRST terms of each expression inside the parenthesis (x and x), OUTER terms (x and 6), INNER terms (-2 and x) and LAST terms (-2 and 6), and we add the products. therefore, 3*(x*x + x*6 + (-2)*...
*September 10, 2011*

**Algebra 2**

you can rewrite -27 as -26 16/16 (since 16/16 is just equal to 1). thus, -26 16/16 + 1/16 -26 + (16-1)/16 -26 15/16
*September 10, 2011*

**Algebra 2**

x^3 + y^(-2) to evaluate means you substitute the value of x and y which are given in the problem. first, recall some laws of exponents. if a term is raised by a negative number, it is also equal to its reciprocal raised to the that number but positive in sign. for example, 5...
*September 10, 2011*

**maths**

first we represent unknowns using variables. let x = number of girls in the hall since the the total number of children is 335, let 335 - x = number of boys in the hall then we set-up the equation. since 1/4 of the girls and 2/5 of the boys are swimmers and their total is 110...
*September 10, 2011*

**Algebra 2**

recall some laws of exponents. a term which is raised by a negative number is also equal to its reciprocal raised to that number with positive sign. for example, 3^(-2) = (1/3)^2 thus, we can rewrite it as, (1/x)^4 substituting x = 2, (1/2)^4 (1/2)*(1/2)*(1/2)*(1/2) 1/16 hope ...
*September 10, 2011*

**Algebra II**

S = (-1/2)gt^2 + vt S + (1/2)gt^2 = vt vt = S + (1/2)gt^2 v = [S + (1/2)gt^2]/t , or v = S/t + (1/2)gt hope this helps~ :)
*September 9, 2011*

**Algebra II**

first represent the unknowns using variables. let x = first multiple of 10 since consecutive multiples of ten has difference of 10 (example 40 and 30 has a difference of 10), let x + 10 = second multiple of 10 let x + 20 = third multiple of 10 then we set-up the equation. from...
*September 9, 2011*

**math**

6*e^(-4t) = 2 e^(-4t) = 1/3 take the ln of both sides: ln [ e^(-4t) ] = ln (1/3) -4t = ln (1/3) t = -(1/4)*(ln (1/3)) or t = (1/4)*(ln 3) hope this helps~ :)
*September 4, 2011*

**math**

note that you can combine exponents if they have the same base. thus, we change the 4 (first term) to 2^2 since the base on the second term is equal to 2: 3 x 4^(1/4) - 12 x 2^(-3/2) 3 x (2^2)^(1/4) - 12 x 2^(-3/2) also, since 12 = 2*2*3 = (2^2)*3, 3 x (2^2)^(1/4) - (3*2^2) x ...
*September 4, 2011*

**algebra**

(5x-4)/3 = 12 5x - 4 = 36 5x = 36 + 4 5x = 40 x = 8 hope this helps~ :)
*September 4, 2011*

**college meth**

i interpreted this as: -128 / 4^2 + 6 - 1 recall PEMDAS: Parenthesis, Exponents, Multiplication, Division, Addition, Subtraction. this is the order in which operation must be done first. therefore, -128 / 8 + 6 - 1 -16 + 6 - 1 -11 hope this helps~ :)
*September 4, 2011*

**geometry**

since AD bisects BC, point D is therefore the midpoint of B and C. recall that the formula for midpoint is given by MP = ( (x1 + x2)/2 , (y1 + y2)/2 ) where (x1,y1) and (x2,y2) = coordinates of B and C substituting, D = ( (5+3)/2 , (-1+5)/2 ) D = ( 8/2 , 4/2 ) D = (4, 2) hope ...
*September 4, 2011*

**maths**

we can rewrite 2:40 as 14:40 then we subtract, 14:40 - 9:50 since 40 is less than 50, we add an hour to it or 60 minutes, while we subtract 1 from 14: 13:100 - 9:50 4 : 50 = 4 hours and 50 minutes hope this helps~ :)
*September 4, 2011*

**algebra**

in the second line of your solution, 2*(-3x^2) = -6x^2 not 6y^2. thus, -3x^2 + 4xy + 7y^2 - 6x^2 + 10xy + 22y^2 -9x^2 + 14xy + 29y^2 ..for the second problem, i think there are typos. please check the problem again. also, 100^2 is not equal to 200.
*September 3, 2011*

**algebra**

-4^6 = -(4*4*4*4*4*4) = -4096
*September 3, 2011*

**chemistry**

recall that density is mass per unit volume, or d = m/V substituting, 8600 kg/m3 = 2 kg / V V = 2/8600 V = 0.00023256 m^3, or in mL, V = 232.56 mL hope this helps~ :)
*September 3, 2011*

**math/algebra**

to do this you can either just factor it out (if it is factorable) or use quadratic formula. since it's factorable, (x + 4)(x - 3) = 0, thus x = -4 and x = 3 using quadratic formula: x = [-b +- sqrt(b^2 - 4ac)]/(2a) where a = numerical coefficient of x^2 b = numerical ...
*September 3, 2011*

**algebra**

11 + 12^2 - (-11)*12 11 + 144 + 132 155 + 132 287 you should perform multiplication operation (the -11*12) first, not subtraction (not the 144-11). -(8m) - (-7m + 2) -8m + 7m - 2 -m - 2 you should distribute the negative sign to the terms inside the parenthesis. thus their ...
*September 3, 2011*

**algebra**

A. (x-6)(2x+3) B. (2x-9)(7x+4) C. (x-1)(x+1)(x+3)
*September 3, 2011*

**math**

(x+3)(x-3)(x-2) (x^2 - 9)(x - 2) x^3 - 9x - 2x^2 + 18 x^3 - 2x^2 - 9x + 18 hope this helps~ :)
*September 3, 2011*

**maths**

1000^1000 = (10^3)^1000 = 10^3000 ..it's like, 3000 zeros written on the right of 1. hope this helps~ :)
*September 3, 2011*

**science**

recall that acceleration is the change in velocity over time, or a = Δv / t substituting, 2 = Δv / 6 Δv = 12 m/s hope this helps~ :)
*September 3, 2011*

**PreCal**

first recall that the form of polar coordinate is (r, θ) to convert polar coordinate to rectangular coordinate, we do this: (r*cos θ , r*sin θ) in the problem, r = 40 and θ = 62. thus, (r*cos θ , r*sin θ) (40*cos 62 , 40*sin 62) (18.78 , 35.32) ...
*September 3, 2011*

**math**

since the amount of money the theater makes is a function of the number of people, it is dependent on the number of people. let n = number of people let m = amount of money since a ticket costs 2 dollars, the amount of money would be m = 2n, or in function form, m(n) = 2n ...
*September 3, 2011*

**Math**

on the fourth line of your solution, 2(4) = 8, not 16. thus, = 15 - 8 - 4/2 = 15 - 8 - 2 = 5 hope this helps~ :)
*September 2, 2011*

**math**

x = 6 + y y = -z/3 substituting, x = 6 - z / 3 thus letter (c).
*September 2, 2011*

**Chem**

neutral Nitrogen has an atomic number of 7 (from periodic table) thus it has 7 protons and 7 electrons (equal +p and -e). Since it is an ion with charge -3, it means that it gained 3 electrons. therefore, N^-3 has 7 protons and 10 electrons. hope this helps~ :)
*August 29, 2011*

**geometry**

since it's already factored, you can equate each factor to zero and solve for x. 2x - 3 = 0 2x = 3 x = 3/2 x - 5 = 0 x = 5 4x + 7 = 0 4x = -7 x = -7/4 note that there are three values of x. hope this helps~ :)
*August 29, 2011*

**Math**

first represent unknowns with variables. let x = games that they tied let x+1 = games that they lost let (x+1)+2 = games that they won then we set-up the equation. since the total games is 12, x + x+1 + (x+1)+2 = 12 x + x + 1 + x + 3 = 12 3x + 4 = 12 3x = 8 x = 8/3 = 2.67 ...
*August 29, 2011*

**science**

recall that speed is distance travelled over time. thus we calculate the speed of each. let's also make sure that the units of speed for both are the same. Car: (convert first the units) 240 km * (1000 m /1 km) = 240000 m 2 hr * (3600 s / 1 hr) = 7200 s v = d/t v = 240000/...
*August 29, 2011*

**science**

i think you forgot to include here the time given. because speed is distance travelled over time, but the only given here is the distance.
*August 29, 2011*

**Geometry**

...but we need to see the figure.
*August 29, 2011*

**geometry**

recall the form, y - y1 = m(x - x1) where m = slope (x1 , y1) = point on the line substituting, y - (-2) = (2/3)*(x - 5) y + 2 = (2/3)x - 10/3 y = (2/3)x - 10/3 - 2 y = (2/3)x - 10/3 - 6/3 y = (2/3)x - 16/3 *the slope-intercept form is in the form y = mx + b. hope this helps~ :)
*August 29, 2011*

**Chemistry**

(a) to get the weight/volume percent, we just divide the mass of the compound to the volume, and multiply by 100: 25 g / 1000 mL * 100 = 2.5 % w/v (b) recall that molarity is moles of solute per liter of solution. thus first get the number of moles of the compound by dividing ...
*August 29, 2011*

**Maths**

cos (theta) = -0.25 theta = cos^-1 (-0.25) there are two answers: theta = 104.48 degrees = 3.65 radians and, theta = -104.48 degrees = -3.65 radians hope this helps~ :)
*August 29, 2011*

**Trig**

0 - 5(-1) 0 + 5 5
*August 29, 2011*

**Trig**

we only to find the angle formed between 2 and 3 (represents where the longer hand points when 15 minutes). notice that, as the longer hand of clock moves, the shorter hand also moves. the maximum angle that it can move in an hour is 360/12 = 30 degrees (occurs if the longer ...
*August 29, 2011*

**geometry**

(9m+2)(m-3) to multiply this, use FOIL method: F = multiply first terms (9m & m) O = multiply outer terms (9m & -3) I = multiply inner terms (2 & m) L = multiply last terms (2 & -3) then add all the products. therefore, 9m * m = 9m^2 9m * -3 = -27m 2 * m = 2m 2 * -3 = -6 9m^2...
*August 28, 2011*

**algebra**

y = (-7/4)x - 1 since the points given will satisfy the given equation, we just substitute the value of x-coordinate to variable x in the equation to get y: for x = -4, y = (-7/4)*(-4) - 1 y = 7 - 1 = 6 thus the first point is (-4,6) for x = 0, y = (-7/4)*0 - 1 y = -1 thus the...
*August 28, 2011*

**math**

first, represent unknowns with variables. let x = measure of angle 2 let 4x-5 = measure of angle 1 (according to the first statement of problem) then set-up the equation. since the angles form a linear pair, their sum must be equal to 180. thus, x + 4x - 5 = 180 5x = 180 + 5 ...
*August 28, 2011*

**Math**

just follow MDAS: Multiplication, Division, Addition Subtraction. this is the sequence that should be followed when there are multiple operations. however, for operations involving only Multiplication and Division, you can solve them left to right. for example, 6 / 3 * 4 2 * 4...
*August 24, 2011*

**math**

first we represent unknowns with variables. let x = number of $3-tickets since the total number of tickets ($3 and $5) is equal to 272, let 272-x = number of $5-tickets then we set-up the equation. to get the total cost, we multiply each price of the ticket with their number. ...
*August 24, 2011*

** science**

recall that speed is distance traveled over a certain time, or v = d/t substituting, v = 400/90 v = 4.44 m/s hope this helps~ :)
*August 23, 2011*

**chemistry**

first we write the balanced chemical reaction: C + 2 H2 -> CH4 *note that Hydrogen is diatomic in nature (that's why it's H2, not H) then to get how much H2 reacted (in grams), we use the data of Carbon. 1 g of Carbon reacted, thus to get the number of moles of C, ...
*August 23, 2011*

**algebra**

first we represent the unknowns using variables: let x = measure of angle 4 let 3x+4 = measure of angle 3 (from the second statement) then we set-up the equation. since the angles form a linear pair, their sum is equal to 180 degrees. therefore, x + 3x + 4 = 180 4x + 4 = 180 ...
*August 23, 2011*

**chemistry**

do you mean density of Na2CO3 of 1 dm^3 volume? if so, we first find its density. Since sodium carbonate only, assume that it is anhydrous (no water/hydrate). from density data found in some books, density of Na2CO3 is 2.54 g/cm^3. then we get the corresponding mass for a ...
*August 23, 2011*

**Math**

just substitute the value of radius to the equation: surface area = SA = 4*pi*r^2 SA = 4*3.14*(3960^2) SA = 1.97 * 10^8 miles^2 hope this helps~ :)
*August 23, 2011*

**algebra 2**

first, represent unknowns with variables: let x = width let x+5 = length (according to first statement) then set-up the equation. recall that the perimeter of a rectangle is given by P = 2L + 2W therefore, 58 = 2(x + 5) + 2x 58 = 2x + 10 + 2x 58 = 4x + 10 48 = 4x x = 12 cm (...
*August 23, 2011*

**science/math please help**

density = mass/volume density = 500 / 250 density = 2 g/mL
*August 23, 2011*

**algebra**

left and right sides of frame = 1 + 1 = 2 in top and bottom sides of frame = 1 + 1 = 2 in therefore the total length and width are: L = 8 + 2 = 10 in W = 8 + 2 = 10 in recall that area of rectangle is given by A = L*W A = 10*10 A = 100 in^2 hope this helps~ :)
*August 22, 2011*

**Math**

first we represent the unknowns using variables: let x = measure of angle 4 let 3x+4 = measure of angle 3 (from the second statement) then we set-up the equation. since the angles form a linear pair, their sum is equal to 180 degrees. therefore, x + 3x + 4 = 180 4x + 4 = 180 ...
*August 22, 2011*

**SCIENCE**

recall that the rate of energy being transferred is given by: q = -kA(dT/dx) where q = energy per unit time (in Watts) k = thermal conductivity (W/m-K) T = temperature (in Kelvin) x = distance (in meters) assuming steady-state heat transfer (meaning, at a particular location, ...
*August 18, 2011*

**PHYSICS**

recall that the rate of energy being transferred is given by: q = -kA(dT/dx) where q = energy per unit time (in Watts) k = thermal conductivity (W/m-K) T = temperature (in Kelvin) x = distance (in meters) assuming steady-state heat transfer (meaning, at a particular location, ...
*August 18, 2011*

**Mathematics**

both irregular and regular have 5 sides and 5 corners. also, both have the same TOTAL/SUM of the interior and exterior angles. regular pentagon has sides of equal lengths, while irregular pentagon has sides of not equal or varying lengths. hope this helps~ :)
*August 15, 2011*

**chemistry**

the heat released or absorbed is given by the formula, Q = mc(T2-T1) where m = mass of substance (units in g) c = specific heat capacity (units in J/g-K) T2 = final temperature T1 = initial temperature **note: if Q is (-), heat is released and if (+), heat is absorbed ...
*August 15, 2011*

**Math**

L^2*pi*a- 2L*pi*x + pi*x^2 = 0 first we can factor out pi from all terms and cancel it out: pi*[ L^2 * a - 2Lx + x^2 ] = 0 L^2 * a - 2Lx + x^2 = 0 a*L^2 - 2x*L + x^2 = 0 since it looks like a quadratic equation now (where L is the variable), we can use quadratic formula to ...
*July 23, 2011*

**mechanical**

recall that maximum range occurs at angle = 45 degrees. also, the max height in projectile motion is given by: y,max = (Vo)^2 * sin^2 (theta)/(2g) where Vo = initial velocity theta = angle of release g = acceleration due to gravity = 9.8 m/s^2 note that max height occurs at ...
*July 3, 2011*

**Algebra**

12i
*July 1, 2011*

**Algebra**

by just observing the given equations, since they have the same slope, they are parallel and thus the system has NO solution since parallel lines never meet or has no intersection. to prove this using substitution: first choose one equation. then choose one variable (for ...
*July 1, 2011*

**Algebra 1**

to do substitution: you choose one equation, then represent one of the variables in terms in terms of the other. and finally substitute it the the other equation. (1) x - 5y = 10 (2) 2x - 10y = 20 here, let's choose equation (1), and let's represent x in terms of ...
*June 26, 2011*

**math**

just type this in your calculator: 878 + 956 + 1039 + 1497 + 1463 + 1277 = ? for the second question, it is finite (or definite), since the total number of escapees is specific and can be measured. hope this helps~ :)
*June 18, 2011*

**College Physics**

momentum = mass * velocity thus we first get the mass by dividing the weight by g. m = W/g m = 9700/9.81 m = 988.8 kg thus, momentum = p = mv p = 988.8 * 36 p = 35596.8 kg*m/s hope this helps~ :)
*June 15, 2011*

**maths**

first we add all the fractions: 1/3 + 1/8 + 1/6 to add them, we need the 'least common denominator' (LCD) of the three fractions. LCD is the smallest number that is divisible by 3, 8 and 6. the LCD of 3, 8 and 6 is 24. then we change all the denominators by 24. to get ...
*June 15, 2011*

**derivative calculus**

the derivative you got is correct. by distributing, we can further simplify this into: 32t + 8t^(3/2) + 2t^(3/2) - (5/2)t^(-1/2) 10t^(3/2) + 32t - (5/2)t^(-1/2) hope this helps~ :)
*June 15, 2011*

**MATH**

linear pair means the sum of the angles equal 180 degrees. therefore, 3x - 12 + 7x + 2 = 180 10x - 10 = 180 10x = 190 x = 19 finally, substituting this back to angle 1 and 2: Angle 1: 3(19) - 12 = 45 degrees Angle 2: 7(19) + 2 = 135 degrees hope this helps~ :)
*June 15, 2011*

**Translate the following situation into an inequali**

first, we represent the unknowns using variables. let x = outfits that Jane packed let x-1 = outfits that Charlie packed let 2x-5 = outfits that Loretta packed since "limited to a total of 24 outfits", it means that the maximum number of outfits is 24: x + (x-1) + (...
*June 11, 2011*

**“Charlie would like to pack one less outfit than J**

*re-posted* first, we represent the unknowns using variables. let x = outfits that Jane packed let x-1 = outfits that Charlie packed let 2x-5 = outfits that Loretta packed since "limited to a total of 24 outfits", it means that the maximum number of outfits is 24: x...
*June 11, 2011*

**chemistry**

(a) x = 273.15 Kelvin (b) p = freezing (c) heat of freezing (d) Q = melting (e) heat of fusion
*June 11, 2011*

**Math**

supplement means the measure of angle in which when added to the other angle equals 180 degrees. therefore, we just subtract the given from 180: 180 - 58 = 122 degrees hope this helps~ :)
*June 7, 2011*

**Math**

y = -4x^2 - 16x - 11 there are many ways to determine the vertex, but the easiest (for me) i think is to use derivatives. first we get the derivative with respect to x: y = -4x^2 - 16x - 11 y' = -8x - 16 then we equate this to zero (because vertex is a maximum or a minimum...
*June 7, 2011*

**Math**

y = -2x^2 + 12x - 13 there are many ways to determine the vertex, but the easiest (for me) i think is to use derivatives. first we get the derivative with respect to x: y = -2x^2 + 12x - 13 y' = -4x + 12 then we equate this to zero (because vertex is a maximum or a minimum...
*June 7, 2011*

**math**

(x + 5) -2(4x -1) = 0 x + 5 - 8x + 2 = 0 -7x + 7 = 0 -7x = -7 x = 1 hope this helps~ :)
*June 7, 2011*

**math**

note that the sum of the interior angles of a triangle is always equal to 180. thus to get angle H, F + G + H = 180 32 + 100 + H = 180 132 + H = 180 H = 180 - 132 H = 48 degrees hope this helps~ :)
*June 5, 2011*

**Algebra**

e^9 = -x
*June 5, 2011*