Saturday

May 30, 2015

May 30, 2015

Total # Posts: 1,856

**algebra**

first we represent the unknowns using variables: let x = measure of angle 4 let 3x+4 = measure of angle 3 (from the second statement) then we set-up the equation. since the angles form a linear pair, their sum is equal to 180 degrees. therefore, x + 3x + 4 = 180 4x + 4 = 180 ...
*August 23, 2011*

**chemistry**

do you mean density of Na2CO3 of 1 dm^3 volume? if so, we first find its density. Since sodium carbonate only, assume that it is anhydrous (no water/hydrate). from density data found in some books, density of Na2CO3 is 2.54 g/cm^3. then we get the corresponding mass for a ...
*August 23, 2011*

**Math**

just substitute the value of radius to the equation: surface area = SA = 4*pi*r^2 SA = 4*3.14*(3960^2) SA = 1.97 * 10^8 miles^2 hope this helps~ :)
*August 23, 2011*

**algebra 2**

first, represent unknowns with variables: let x = width let x+5 = length (according to first statement) then set-up the equation. recall that the perimeter of a rectangle is given by P = 2L + 2W therefore, 58 = 2(x + 5) + 2x 58 = 2x + 10 + 2x 58 = 4x + 10 48 = 4x x = 12 cm (...
*August 23, 2011*

**science/math please help**

density = mass/volume density = 500 / 250 density = 2 g/mL
*August 23, 2011*

**algebra**

left and right sides of frame = 1 + 1 = 2 in top and bottom sides of frame = 1 + 1 = 2 in therefore the total length and width are: L = 8 + 2 = 10 in W = 8 + 2 = 10 in recall that area of rectangle is given by A = L*W A = 10*10 A = 100 in^2 hope this helps~ :)
*August 22, 2011*

**Math**

first we represent the unknowns using variables: let x = measure of angle 4 let 3x+4 = measure of angle 3 (from the second statement) then we set-up the equation. since the angles form a linear pair, their sum is equal to 180 degrees. therefore, x + 3x + 4 = 180 4x + 4 = 180 ...
*August 22, 2011*

**SCIENCE**

recall that the rate of energy being transferred is given by: q = -kA(dT/dx) where q = energy per unit time (in Watts) k = thermal conductivity (W/m-K) T = temperature (in Kelvin) x = distance (in meters) assuming steady-state heat transfer (meaning, at a particular location, ...
*August 18, 2011*

**PHYSICS**

recall that the rate of energy being transferred is given by: q = -kA(dT/dx) where q = energy per unit time (in Watts) k = thermal conductivity (W/m-K) T = temperature (in Kelvin) x = distance (in meters) assuming steady-state heat transfer (meaning, at a particular location, ...
*August 18, 2011*

**Mathematics**

both irregular and regular have 5 sides and 5 corners. also, both have the same TOTAL/SUM of the interior and exterior angles. regular pentagon has sides of equal lengths, while irregular pentagon has sides of not equal or varying lengths. hope this helps~ :)
*August 15, 2011*

**chemistry**

the heat released or absorbed is given by the formula, Q = mc(T2-T1) where m = mass of substance (units in g) c = specific heat capacity (units in J/g-K) T2 = final temperature T1 = initial temperature **note: if Q is (-), heat is released and if (+), heat is absorbed ...
*August 15, 2011*

**Math**

L^2*pi*a- 2L*pi*x + pi*x^2 = 0 first we can factor out pi from all terms and cancel it out: pi*[ L^2 * a - 2Lx + x^2 ] = 0 L^2 * a - 2Lx + x^2 = 0 a*L^2 - 2x*L + x^2 = 0 since it looks like a quadratic equation now (where L is the variable), we can use quadratic formula to ...
*July 23, 2011*

**mechanical**

recall that maximum range occurs at angle = 45 degrees. also, the max height in projectile motion is given by: y,max = (Vo)^2 * sin^2 (theta)/(2g) where Vo = initial velocity theta = angle of release g = acceleration due to gravity = 9.8 m/s^2 note that max height occurs at ...
*July 3, 2011*

**Algebra**

12i
*July 1, 2011*

**Algebra**

by just observing the given equations, since they have the same slope, they are parallel and thus the system has NO solution since parallel lines never meet or has no intersection. to prove this using substitution: first choose one equation. then choose one variable (for ...
*July 1, 2011*

**Algebra 1**

to do substitution: you choose one equation, then represent one of the variables in terms in terms of the other. and finally substitute it the the other equation. (1) x - 5y = 10 (2) 2x - 10y = 20 here, let's choose equation (1), and let's represent x in terms of ...
*June 26, 2011*

**math**

just type this in your calculator: 878 + 956 + 1039 + 1497 + 1463 + 1277 = ? for the second question, it is finite (or definite), since the total number of escapees is specific and can be measured. hope this helps~ :)
*June 18, 2011*

**College Physics**

momentum = mass * velocity thus we first get the mass by dividing the weight by g. m = W/g m = 9700/9.81 m = 988.8 kg thus, momentum = p = mv p = 988.8 * 36 p = 35596.8 kg*m/s hope this helps~ :)
*June 15, 2011*

**maths**

first we add all the fractions: 1/3 + 1/8 + 1/6 to add them, we need the 'least common denominator' (LCD) of the three fractions. LCD is the smallest number that is divisible by 3, 8 and 6. the LCD of 3, 8 and 6 is 24. then we change all the denominators by 24. to get ...
*June 15, 2011*

**derivative calculus**

the derivative you got is correct. by distributing, we can further simplify this into: 32t + 8t^(3/2) + 2t^(3/2) - (5/2)t^(-1/2) 10t^(3/2) + 32t - (5/2)t^(-1/2) hope this helps~ :)
*June 15, 2011*

**MATH**

linear pair means the sum of the angles equal 180 degrees. therefore, 3x - 12 + 7x + 2 = 180 10x - 10 = 180 10x = 190 x = 19 finally, substituting this back to angle 1 and 2: Angle 1: 3(19) - 12 = 45 degrees Angle 2: 7(19) + 2 = 135 degrees hope this helps~ :)
*June 15, 2011*

**Translate the following situation into an inequali**

first, we represent the unknowns using variables. let x = outfits that Jane packed let x-1 = outfits that Charlie packed let 2x-5 = outfits that Loretta packed since "limited to a total of 24 outfits", it means that the maximum number of outfits is 24: x + (x-1) + (...
*June 11, 2011*

**“Charlie would like to pack one less outfit than J**

*re-posted* first, we represent the unknowns using variables. let x = outfits that Jane packed let x-1 = outfits that Charlie packed let 2x-5 = outfits that Loretta packed since "limited to a total of 24 outfits", it means that the maximum number of outfits is 24: x...
*June 11, 2011*

**chemistry**

(a) x = 273.15 Kelvin (b) p = freezing (c) heat of freezing (d) Q = melting (e) heat of fusion
*June 11, 2011*

**Math**

supplement means the measure of angle in which when added to the other angle equals 180 degrees. therefore, we just subtract the given from 180: 180 - 58 = 122 degrees hope this helps~ :)
*June 7, 2011*

**Math**

y = -4x^2 - 16x - 11 there are many ways to determine the vertex, but the easiest (for me) i think is to use derivatives. first we get the derivative with respect to x: y = -4x^2 - 16x - 11 y' = -8x - 16 then we equate this to zero (because vertex is a maximum or a minimum...
*June 7, 2011*

**Math**

y = -2x^2 + 12x - 13 there are many ways to determine the vertex, but the easiest (for me) i think is to use derivatives. first we get the derivative with respect to x: y = -2x^2 + 12x - 13 y' = -4x + 12 then we equate this to zero (because vertex is a maximum or a minimum...
*June 7, 2011*

**math**

(x + 5) -2(4x -1) = 0 x + 5 - 8x + 2 = 0 -7x + 7 = 0 -7x = -7 x = 1 hope this helps~ :)
*June 7, 2011*

**math**

note that the sum of the interior angles of a triangle is always equal to 180. thus to get angle H, F + G + H = 180 32 + 100 + H = 180 132 + H = 180 H = 180 - 132 H = 48 degrees hope this helps~ :)
*June 5, 2011*

**Algebra**

e^9 = -x
*June 5, 2011*

** algebra**

(3x+6)/(4x+12) / (x^2 - 4)/(x-3) first, to divide, we get the reciprocal of the divisor (or the second term/ term at the right) and the operation will be multiplication. reciprocal is just interchanging the numerator and denominator terms. thus, (3x+6)/(4x+12) * (x-3)/(x^2 - 4...
*June 4, 2011*

**Math - Domain of Composite function**

f(x) = sqrt(x) g(x) = 2x + 12 thus, (fog)(x) = sqrt(2x + 12) note that to get the domain, you must get the intersection of the 3 function domains. for f(x) = sqrt(x), x cannot be less than zero thus the domain is [0 , +infinity) for g(x) = 2x + 12, x can be any real number ...
*June 3, 2011*

**math**

to multiply, just multiply the radicands (terms inside the radical sign): sqrt(3*3) - sqrt(3*21) sqrt(9) - sqrt((3^2)*7) 3 - 3*sqrt(7) hope this helps~ :)
*May 30, 2011*

**math**

note that you can combine them right away when the radicand (term inside radical sign) are not the same/equal. observe that 45 and 125 can be factored to: 45 = 3*3*5 = (3^2)*5 125 = 5*5*5 = (5^2)*5 thus, we can take 3 and 5 respectively from each term, and it becomes (4*3)*...
*May 30, 2011*

**math**

you just multiply the radicands (terms inside the radical sign): sqrt(2) * sqrt(6) = sqrt(12) but we can further simplify this to: sqrt(12) = 2*sqrt(3) hope this helps~ :)
*May 30, 2011*

**algebra**

1.042 x 10^3
*May 29, 2011*

**math**

2.24 x 10^(-5) note that since the exponent of 10 is negative (which is -5), we just move the decimal point 5 places to the LEFT, or: 0.0000224 hope this helps~ :)
*May 29, 2011*

**math**

hmm, i'm not sure with that "reduce to 5/8". i interpreted it in two ways: A.) 5/8 as a number: let n = number thus, n - 33 = 5/8 n = 33 5/8 B.) 5/8 of the original n - 33 = (5/8)n n - (5/8)n = 33 (3/8)n = 33 n = 33*8/3 n = 88 hope this helps~ :)
*May 27, 2011*

**Algebra**

(c^2 - 1)(c^2 + 1) (c - 1)(c + 1)(c^2 + 1)
*May 26, 2011*

**algebra**

there are many ways to solve for the vertex. i think the easiest is to first find the derivative and solve for x: f(x)=x^2-10x+21 f'(x) = 0 = 2x - 10 2x = 10 x = 5 now substitute this back to original: f(5) = 5^2 - 10*5 + 21 f(5) = 25 - 50 + 21 f(5) = -4 thus vertex is at...
*May 26, 2011*

**algebra**

5x^2 = 48x 5x^2 - 48x = 0 x(5x - 48) = 0 therefore, x = 0 and x = 48/5 there are two solutions, and they are both real numbers. hope this helps~ :)
*May 26, 2011*

**algebra**

how to do this: first, from the equation, we get b or the numerical coefficient of x. from the given, b = 2. then divide this by 2: 2/2 = 1 and square it: 1^2 = 1 thus, the number that we're looking for is 1: x^2 + 2x + 1 =(x + 1)^2 hope this helps~ :)
*May 26, 2011*

**algebra**

(1/7x^2 - 2/5)(1/2x + 1/2) to do this, first multiply the 1/7x by the two terms on the second parenthesis (that is, 1/2x and 1/2). then also multiply -2/5 by the terms on the second parenthesis. and add them all. (1/7x^2)*(1/2x + 1/2) = (1/14)x^3+(1/14)x^2 (-2/5)(1/2x + 1/2...
*May 26, 2011*

**math**

22 * 5/8 = 13.75
*May 26, 2011*

**Math**

(3/17)x = 12 to get x alone, you divide both sides by the numerical coefficient (number before the variable) of x. 3/17 divided by itself is 1 and thus thus x = 12 / (3/17) to divide by fraction, you get the reciprocal of the divisor (that is, the 3/17) and change the division...
*May 25, 2011*

**Geometry-Help PLZ**

if three cubes are stacked, the other three are stacked too, and they are put together, the figure i see is a rectangular prism of lengths 6, 4 and 2. getting the SA of a rectangular prism, SA = 2LW + 2LH + 2WH SA = 2(6*4) + 2(6*2) + 2(4*2) SA = 48 + 24 + 16 SA = 88 sq units. ...
*May 25, 2011*

**Geometry-Help PLZ**

recall surface area and volume of cube is given by SA = 6*s^2 V = s^3 where s = length of a side the volume becomes 1/8 of original so V' = 8 cubic units. thus, 8 = s^3 s = cuberoot(8) s = 2 (new length) the surface area of a cube of this length is SA = 6*(2^2) SA = 24 sq ...
*May 25, 2011*

**physica**

recall that the motion of the stone is uniformly accelerated motion (because it accelerated due to gravity). thus we can use the formula: h = vo*t - 1/2(g)(t^2) where h = height vo = initial velocity t = time g = acceleration due to gravity = 9.8 m/s^2 substituting, h = vo*(1....
*May 25, 2011*

**math**

true.
*May 25, 2011*

**math**

false. it's 1/[2*sqrt(x)]
*May 25, 2011*

**math**

because it is undefined at x = 3.
*May 25, 2011*

**Algebra**

do you mean these are the roots of the quadratic equation you want to find? if so, from its roots, 2 and -4, (x-2)(x+4) x^2 + 2x - 8 hope this helps~ :)
*May 25, 2011*

**algebra**

to find f(0), we just substitute x = 0: f(x) = [x^2 - 3x + 2] / x + 1 f(0) = [0^2 - 3(0) + 2] / (0 + 1) f(0) = 2/1 = 2 hope this helps~ :)
*May 25, 2011*

**Geometry-help**

it's D. because 27/3 = 9 -> which must be the product of the remaining two lengths that are not given.
*May 25, 2011*

**algebra**

2(a^2)b - 7a - 9b
*May 25, 2011*

**geometry**

recall that lateral area (area on the sides, not the top or the bottom) of a cylinder is given by, LA = 2πrh where r = radius h = height π = "pi" equal to 3.14 (constant) substituting, LA = 2*(3.14)*5*22 LA = 690.8 cm^2 recall that the surface area of ...
*May 24, 2011*

**algebra**

to get the slope, we first transform this into slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. x + 5y = 10 note that in slope-intercept form, y is the only term on the left side, and all other terms on the right side. thus, 5y = -x + 10 then ...
*May 24, 2011*

**algebra**

x-intercept occurs at y = 0. thus from the given equation, we set y = 0: -25x + y = 15 -25x = 15 x = -3/5 thus x-intercept is at (-3/5 , 0) y-intercept occurs at x = 0. thus from the given equation, we set x = 0: -25x + y = 15 y = 15 thus y-intercept is at (0 , 15) hope this ...
*May 24, 2011*

**Geometry -need help**

recall that the surface area of cylinder is given by SA = 2πr^2 + 2πrh where r = radius h = height π = "pi" equal to 3.14 (constant) substituting, SA = 2*(3.14)*3^2 + 2*(3.14)*3*9 SA = 226.08 in^2 then we divide this by his speed, 40 in^2/5 min: 226.08...
*May 24, 2011*

**math**

we need to divide both sides of the equation by 0.8 to get T alone: 0.8T = 24 0.8T / 0.8 = 24 / 0.8 T = 30
*May 24, 2011*

**algebra**

note that this equation is already in the slope-intercept from: y = mx + b , where m is the slope and b is the y-intercept. thus in the given, y = 2x + 6 the slope is 2. hope this helps~ :)
*May 23, 2011*

**algebra**

6y -6 < 5y - 3 6y - 5y < -3 + 6 y < 3 hope this helps~ :)
*May 23, 2011*

**algebra**

7+3x < 19 we just solve it like a normal equation (not an equality). 7 + 3x < 19 3x < 19 - 7 3x < 12 x < 4 hope this helps~ :)
*May 23, 2011*

**algebra**

5 - 9y - 2y < 27 we just solve it like a normal equation. 5 - 11y < 27 -11y < 27 - 5 -11y < 22 y > -2 note that when dividing both sides by a negative number, the inequality sign becomes its opposite. like here, both sides are divided by -11, and thus the sign ...
*May 23, 2011*

**maths**

first convert the time given in hours. 2 hours & 30 min = 2.5 hours then recall that speed is just distance traveled over time, or v = d/t substituting, v = 220/2.5 v = 88 km/hr hope this helps~ :)
*May 23, 2011*

**math**

x-intercept occurs at y=0. thus we substitute it to the given equation, y = x^2 + 4x - 12 0 = x^2 + 4x - 12 0 = (x-2)(x+6) x = 2 and x = -6 at these values of x, y is zero. thus the x-intercepts are (2,0) and (-6,0) hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

8(4s-7) < 6(2s+4) 32s - 56 < 12s + 24 20s < 80 s < 4 hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

-5(3e-2)<-2(6e+7) -15e + 10 < -12e - 14 -3e < -24 e > 8 *note that when dividing both sides of the equation by negative number, the sign changes to its opposite. like here, both sides were divided by -3 and the sign changes from < to >. hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

-3(2b+4)>4(b+7) -6b - 12 > 4b + 28 -10b > 40 b < -4 *note that when dividing both sides of the equation by negative number, the sign changes to its opposite. like here, both sides were divided by -10 and the sign changes from > to <. hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

48>3(w+7) 48 > 3w + 21 27 > 3w 9 > w or w < 9 hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

-12(c-6)<120 -12c + 72 < 120 -12c < 48 c > -4 *note that when dividing both sides of the equation by negative number, the sign changes to its opposite. like here, both sides were divided by -12 and the sign changes from < to >. hope this helps~ :)
*May 23, 2011*

**Pre-algebra**

7(v+5)>56 7v + 35 > 56 7v > 21 v > 3 hope this helps~ :)
*May 23, 2011*

**Math**

but we need the figure to solve for this.
*May 23, 2011*

**Math**

you can answer this in two ways~ systematic way (lol): let x = units digit let y = tens digit from the second statement, (1) xy = 14 from the first statement, (2) 10x + y = 3(10y + x) - 9 from equation (1), we can express y in terms of x, yielding y = 14/x substituting this to...
*May 23, 2011*

**Math**

2x^2 + 7x -15 =0 (2x - 3)(x + 5) = 0 therefore, x = 3/2 and x = -5 hope this helps~ :)
*May 22, 2011*

**physics**

just imagine when you dribble. you use force (directed downward) from your hand to "throw" it downwards.
*May 22, 2011*

**algebra**

numerical coefficients : 2, 4, 8
*May 22, 2011*

**algebra**

(-8x^2-2x+4)+(x^2-9x+7) to add, we just combine the numerical coefficients (or the numbers before the variable) of the same variables (meaning same letters and same exponents). thus, (-8x^2 - 2x + 4 ) + ( x^2 - 9x + 7 ) -7x^2 - 11x + 11 hope this helps~ :)
*May 22, 2011*

**chemistry**

(1) assuming the gas is ideal, the volume becomes 1/3 of the original. (2) recall that STP, pressure is at 1 atm. assuming the gas is ideal, P1*V1 = P2*V2 where P1 = initial pressure V1 = initial volume P2 = final pressure V2 = final volume substituting, 1*2000 = (P2)*15 P2 = ...
*May 21, 2011*

**math**

i think you mean 3k^2 + 6k = 6 thus, we can re write this as 3k^2 + 6k - 6 = 0 note that we can factor out 3 from each term and cancel it. thus we can re write this as k^2 + 2k - 2 = 0 using quadratic formula, k = [-b +- sqrt(b^2 - 4ac)]/(2a) substituting, k = [-2 +- sqrt(2^2...
*May 21, 2011*

**algebra2**

to do this, we just multiply the exponents. [x^9]^11/7 x^(9*11/7) x^(99/7) hope this helps~ :)
*May 17, 2011*

**Maths**

|| means they are parallel. since AB and CD are parallel, they will never meet.. thus i think the first statement is wrong that they meet at point E.
*May 17, 2011*

**Algebra**

(q-2)/4 * -2q/(q+5) to multiply, we just multiply numerator by numerator and denominator by denominator. thus, this becomes: (q-2)(-2q) / (4)(q+5) observe that we can factor 2 from numerator and denominator and cancel it, and this becomes: -q(q-2) / (2)(q+5) hope this helps~ :)
*May 17, 2011*

**science**

recall that current is voltage per resistance, or I = V/R *units of current in Amperes (A) *units of voltage in Volts (V) *units of resistance in ohms (Ω) substituting, 8 = 1.1/R R = 1.1/8 = 0.1375 Ω hope this helps~ :)
*May 17, 2011*

**chemistry **

first thing to do here is to balance the chemical equation. 2Na + Cl2 --> 2NaCl then we get the masses of Sodium and Chlorine from periodic table of elements in order to calculate the molar mass of NaCl. from periodic table, Na = 23 Cl = 35.5 thus, NaCl = 23+35.5 = 58.5 g/...
*May 17, 2011*

**math help please !!!**

*reposted -- because i think you haven't read my previous post in this problem* first, we solve for the initial velocity from the formula of the maximum height: h,max = [(vo)^2]/(2g) where vo = initial velocity g = acceleration due to gravity = 9.8 m/s^2 substituting, 30...
*May 17, 2011*

**geometry**

note that complement means the other angle in which their sum should be 90. thus to get the complement of each angle, we just subtract them from 90: 90 - 44 = 46 90 - 15 = 75 90 - 72 = 18 90 - 89 = 1 90 - 10 = 80 90 - 30 = 60 hope this helps~ :)
*May 16, 2011*

**math**

we'll solve this in two cases: Case I: absolute value is positive. |n+1| < 4 n+1 < 4 n < 3 Case II: absolute value is negative. |n+1| < 4 -(n+1) < 4 n+1 > -4 n > -5 getting the intersection (common between them) of the two answers, thus n must be ...
*May 15, 2011*

**Algebra**

the formula is wrong. it should be y = a(x-h)^2 + k where (h,k) is the center then to solve for a, you choose one of the points to substitute for the value of x and y. for instance you choose (-4,-1): y = a(x-h)^2 + k -1 = a(-4+3)^2 - 2 then solve for a. if you want to make ...
*May 15, 2011*

**Algebra**

yes~ :)
*May 15, 2011*

**Algebra**

yes, you're right. :)
*May 15, 2011*

**Algebra-right question for Jai**

the volume of a triangular prism is given by V = (1/2)*(B*H*L) where B = base H = height L = length thus the new volume becomes, V' = (1/2)*(2*B)(2*H)*L V' = 2*(1/2)*(B*H*L) or V' = 2*V thus the new volume is twice the original. note that first statement is tricky...
*May 15, 2011*

**Algebra- word problem**

sure~ :)
*May 15, 2011*

**Algebra- word problem**

original area: A = L*W A = 6*3 = 18 in^2 new area: A' = L'*W' A' = 8*5 = 40 in^2 the difference between these areas is the amount of wall space needed: 40-18 = 22 in^2 thus it's A. hope this helps~ :)
*May 15, 2011*

**algebra**

recall that the volume of a rectangular prism is given by V = L*W*H where L = lenght W = width H = height. if 4 is multiplied to both length and width, the new volume, V', is V' = (4L)*(4W)*(H) V' = 16*(L*W*H) or V' = 16*V thus the new volume is 16 times ...
*May 15, 2011*

**algebra**

oh, i see.. the choices are wrong. i guess you typed it wrong because "volume" is in the choices.. it must be "area" since it is the required. (and rectangles don't have volume)
*May 15, 2011*

**algebra**

original area: A = L*W new area: A' = (3L)*(3W) A' = 9*(L*W) or A' = 9*A thus there is no correct answer in the choices, since the new area is 9 times greater than the original. hope this helps~ :)
*May 15, 2011*

**algebra**

yes~ :) original area: A = L*W new area: A' = (3L)*(3W) A' = 9*(L*W) or A' = 9*A thus there is no correct answer in the choices, since the new area is 9 times greater than the original. hope this helps~ :)
*May 15, 2011*

**Math**

(a) to get this, we just use ratio and proportion: let x = weight of 150 books. 108 books : 30 kg = 150 books : x kg we can thus rewrite this as 108/30 = 150/x 3.6 = 150/x x = 150/3.6 x = 41.67 kg (b) we also use ratio and proportion here: let y = number of books that has ...
*May 15, 2011*

**physics**

recall that the volume of a sphere (geometry of the ball) is given by V = (4/3)πr^3 where r = radius π = 3.14 (constant) thus to get radius, we need to first get the volume from the given mass and density. recall that density is just mass per volume, or d = m/V ...
*May 15, 2011*