Please help on geometry - analytic geometry
It helps if you plot the points first, then you can find the length of the sides of the triangle. area of a triangle is 1/2 base times height.
That isn't the answer. That was just an example of what consecutive even numbers mean to show why we are using n, n+2 and n+4. My equation is the same as yours.
Even numbers have a differnce of two. 2, 6, and 8 are consecutive even numbers. Let n = 1st Let n + 2 = 2nd Let n + 4 = 3rd 3(n) - 2(2n+2) = 1/3(n+4) Here is the equation. Can you solve it?
l + 2w = perimeter l + 2w = 24 l = 24-2w Area = l times w (24-2w)w = Area. 24w -2w^2 = Area. If you are doing this using calculus, you would take the derivative of the area and set it equal to zero to find w.
Guidance and Discipline
What are the choices?
x = the number you start with after round 1: you have x/2 1/3 of those are eliminated which means 2/3 remain Multiply x/2 times 2/3 = x/3 Next round 1/4 are eliminated which means that 3/4 remain. 3/4 times x/3 = x/4 Can you finish from here with rounds 5 and 6 it should end w...
x = 1st number and y = second number 2x + y = 24 2x - y = 12 Can you finish from here? Add the two equations to eliminate y and solve for x. Then find y. Be sure to check both x and y in both equations to be sure you are correct.
There are 100 students... and 40 boys. What is the probability of getting a boy? Student wears eye glasses. It looks like 40 wear eye glasses so 40/100 again. I am not sure if the question is two separate problems or they are trying to say .. if you picked a boy and that he we...
I put the numbers in using the stat function of the TI-83. I hit STAT and edit to put in the numbers in L1 and L2. Then I did Stat -Calc and I chose Quadreg and L1 L2 from keyboard and enter.
I am taking a chance at this one. See if you agree or not. (0,0) is the initial starting point (55, 0) is the ending point 24.8 is the max height which occurs 1/2 between 0 and 55 so that gives us another point (27.5, 24.8) I used the quadratic regression on the graphing calcu...
For Further Reading