Yes, it is D.
This isn't as bad as you think 28 minimum and 34 max. Your numbers have to be between 28 and 34 with a median of 30 28 30 34 You need an equal number of entries above and below 30 with 29 being a mode.. it means you can have multiple entries 28 29 29 29 29 30 30 31 32 33 3...
You need to get common denominators so that you can relate each fraction to the other ones. Another way would be to write each as a decimal. The first 3/5 = .6
Let x = 0 You have 5(0) - 2y = 10 so -2y = 10 divide both sides by -2 to find y. Your ordered pair is (0, y) Do the same for y = 0 5 x - 2(0) = 10 5x = 10 solve for x and your ordered pair is (x, 0)
You are looking for a number that both 8 and 12 will go into which is 24.
Try some examples. + 8 - (-8) Remember when you subtract, you add the opposite in algebra +8 + (+8) = 16 + 10 - (-4) = " Look for a pattern.
please help with geometry - dilation
A square with an area of 4 has to have all sides equal to 2. Right? If I increase by a factor of k that means multiply 2 times k My area is 2k times 2k = 4k^2 I would set this equal to 9 I am getting 3/2 for the value of k -3/2 is another possibility, but we have to discount i...
Checking with what I think you have in your problem 7^3 times 7^2 times 8^5 in the numerator? If so you can simplify to 7^5 times 8^5 in the numerator The denominator: 8^4 times 7 times 8^-7 if so you can simplify the denominator to 8^-3 times 7 7^5 times 8^5 divided by 8^-3 t...
I am having trouble understanding what you mean for part a. Is the x a variable or are you writing it as a times sign to indicate multiplication? for b I am a little confused too. a raised to the -2 b raised to the 4 c raised to the 3 should everything in the ( ) be squared? i...
Math plz fast i really need it
For the first part, you really need to make a table to show all of the possible sums I suggest making a table with 1 -6 across the top and 1-6 down the side.. Then fill in the table by adding the die. 1,1 = 2 1, 2 = 3 You may be able to find a table like this in your book or b...
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