Solve equation for Y 2x + 8y = 6 8y = 6 - 2x y = 3/4 - x/4 Since this is a straight line, we can pick any value for X. Let's say X=2 Then y(2) = 3/4 - 2/4 = 1/4 Now, decrease x by 2, so x=0 y(0) = 3/4 - 0/4 = 3/4 The difference between Y(0) and Y(2) is 3/4 - 1/4 = 2/4 = 1/...
Change 1.9 hours into a form we can use. Let's break it into two parts. We know 1 hour is easy enough, and that will change the time to 4:05 PM (Subtract 1 hour from 5:05 PM). For the 0.9 hour part, let's change this to minutes. (0.9 hours)*(60 min / 1 hr) = 54 minutes...
Keep in mind it does not have to be in ratio of 3:4:5 to be a right triangle, it has to make the equation c^2=a^2+b^2 true. Another common right triangle is 5,12,13.
No...Use c^2=a^2+b^2. Use a= 24, b= 32 and c= 42 (the longest side). Take a^2 + b^2 and see if it eqauls c^2 If it does, it is a right angle. If it does not, it is not a right triange. In this case, it does not, so it is not a right triangle.
2X + 1 r 2/(x-3)
1. Multiply out z^2 + 6z + 14z^2 + 84z + 45 = 0 2. Combine like terms 15z^2 + 90z + 45 = 0 3. Use quadratic equation to get both answers for z.
A solution is prepared by mixing 50.7 mL of 0.28 M Pb(NO3)2 with 70.8 mL of 1.0 M KCl. Calculate the concentrations of Pb2+ and Cl - at equilibrium. Ksp for PbCl2(s) is 1.6 10-5.
Yes, you are correct. Key word is circular, so we are talking about a circle. pi = circumference of a circle / diameter --> pi = C / d Solve for C C = pi*d = (3.14) *(10 ft) = 31.4 ft, assuming the approximation of 3.14 for pi.
Think of a right triangle. The airport is the vertex of the right angle. Plane A is 70 miles north (Straight up). Plane B is 168 miles East (Straight right). From plane A to B would be side C of the right triange. C^2 = A^2 + B^2 C = sqrt (A^2 + B^2) C = sqrt (70^2 + 168^2) C ...
No, look at your answer... Your length is 4 times as long as your width... How did you come up with your answer?