January 30, 2015

Posts by Hina

Total # Posts: 16

Legal Research Studies
This is my first assignment in University and in a law course. I have learning disabilities and have trouble remembering and reading/writing. This is my first assignment. I read it but I don't understand a thing. Please help me out... "While researching a legal issue ...
January 20, 2015

Uranium benefits and uses
March 14, 2014

Uranium 235 problem that exits
March 14, 2014

Sulfur and chlorine can react together to form S2Cl2. When 1.00g of this sulfur chloride reacted with water, 0.36g of a yellow ppt of sulfur was formed together with a solution contianing a mixture of sulfurous acid, H2SO3, and HCl acid. Use the above data to deduce the ...
April 10, 2013

can anybody please tell me the source of this question , i mean the board from which the question is taken? thanks
March 14, 2013

pbo in gram/ 446.4 = ans *621.6 = final ans
January 11, 2013

(atomic percent/100*6.02*10^23)/ atomic volume of element
December 14, 2012

Math-please help!!!
how do you solve 2x^2+x^3=96?
October 24, 2011

i would say it is a compound sentence
October 24, 2011

Just to be precise, a complex sentence has an independent clause joined by one or more dependent clauses.It always has a subordinator such as because, since, after, although, or when or a relative pronoun such as that, who, or which. Since your sentence does not meet this ...
October 24, 2011

how do you solve 2x^2+x^3=96?
October 24, 2011

find an equation for the line tangent to y=2-6x^2 at (-5,-148)
September 7, 2011

May 31, 2011

give a description of the apartment that the Thorvald's live in.what can u infer about them from the description that is given?
January 8, 2010

General Chem
A weak acid has Ka= 1*10^-3. If [HA]= 1.00 M what must be [A-] for the pH to be pH 2.7? My work: pH= Pka + log(B/A) 2.7= 3 + log (B/A) Kw= Ka* Kb 1*10^-14= 1*10^-3 * Kb Kb= 1*10^-11 I don't know how to go about from here
August 9, 2009

my yest is on tuesday...i relly need hep. i wil hv questions similar to this...i need help!
June 16, 2006

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