Wednesday

October 1, 2014

October 1, 2014

Total # Posts: 9,180

**History**

How was James I's rule of England similar to peter the great's rule of Russia? Both reduces the size of their empire. Both increased their own power without approval by other government entitles. Both relied heavily on the opinions of their subjects when making ...
*March 27, 2014*

**Electricity**

Q = C*V = 10*10^-9F * 5V = 50*10^-9 Coulombs.
*March 27, 2014*

**math**

Got it! thanks
*March 26, 2014*

**math **

for the line segment whose endpoints are r(1,2) and s(6,7), find the point located 3/4 the distance from r to s.
*March 26, 2014*

**math 2**

Thank you so much reiny : )
*March 26, 2014*

**math 2**

A segment with endpoints C (3,4) and D (11,3) is divided by a point E such that CE and DE form a 3:5 ratio. Find E.
*March 26, 2014*

**math**

So I continued working where you left off and got y=0.5x+2.5 is that correct? or is it y=0.5x-2.5? I am pretty sure that it is the first one but I just wanna make sure.
*March 26, 2014*

**math**

Write an equation of a line perpendicular to line AB below in slope-intercept form that passes through the point (7, 6). A (0,1) B (-2,5)
*March 26, 2014*

**Math**

Wow thanks! It is correct! :D
*March 26, 2014*

**Math**

Write an equation of a line perpendicular to y=1/2x-5 in slope-intercept form that passes through the point (2, -7).
*March 26, 2014*

**6th Grade Math**

Blue = 3/10 Red = 4/10 = 2/5 Green = 3/10
*March 26, 2014*

**Physics**

h = Vo*t + 0.5g*t^2 = 2 m. 0 + 4.9*t^2 = 2 t^2 = 0.4082 t = 0.639 s. = Fall time. V = Vo + g*t = g*t. g = 10 m/s^2 Use the following points for graphing. (t,v) = (0,0), (0.2,2), (0.3,3),(0.5,5), (0.6,6).
*March 26, 2014*

**math**

P = (Po*r*t)/(1-(1+r)^-t) Po = Initial principal = $199,000 r = (7.01%/12)/100% = 0.00584 = Monthly % rate expressed as a decimal. t = 25yrs * 12mo/yr. = 300 Months. Plug the above values into the given Eq. and get: P = $422,328.10 Int.(Tot.) = P-Po = $223,328.10 Monthly ...
*March 26, 2014*

**Physical science**

See Related Questions: Wed,9-25-13,3:20 PM.
*March 26, 2014*

**physics**

Ingrid: 2h, 21min, 06s = Blake-: 2h, 06min, 50s = 2h, 20min, 66s 2h, 06min, 50s Diff. = 14min, 16s. = = 14.267min = Blake's winning margin. Tb = 120 + 6 + 50/60 = 126.833min = Blake's time. Vb = d/Tb = 42,195m/126.833min = 332.681 m/min = Blake's speed. d = 332....
*March 25, 2014*

**physics**

See Related Questions: Fri,3-21-14,8:55 PM.
*March 24, 2014*

**Physics**

m*g = 115 * 9.8 = 1127 N. = Wt. of box. Fn = 1127*cos46 = 782.9 N. = Normal force.
*March 24, 2014*

**physics**

Circumference = pi*D = 3.14 * 0.7m = 2.20 m. b. Va = 2m/s * 6.28rad/2.20m=5.71 rad/s = Angular velocity.
*March 24, 2014*

**physics**

h = (V^2-Vo^2)/2g = (0-(8^2))/-19.6 = 3.27 m.
*March 24, 2014*

**physics**

d = 0.5g*t^2 = 20-12 = 8 m. 4.9t^2 = 8 t^2 = 1.63 t = 1.28 s. = Fall time. Range = V*t = 4m/s * 1.28s = 5.12 m. 5.12m > 5 m. Therefore, he will make it.
*March 23, 2014*

**math**

Eq1: 5x - y = 20 Eq2: 4x + 3y = 16 Multiply Eq1 by 3 and add the Eqs: 15x - 3y = 60 +4x + 3y = 16 Sum: 19x = 76 X = 4 In Eq1, replace x with 4 and solve for y: 5*4 - y = 20 20-y = 20 Y = 0. Solution: (x,y) = (4,0).
*March 23, 2014*

**physics**

See Related Questions:Fri,3-21-14,8:55PM
*March 23, 2014*

**Physics**

Vo = 50m/s[37o] Xo = 50*cos37 = 39.93 m/s. Yo = 50*sin37 = 30.09 m/s. Tr = (Y-Yo)/g = (0-30.09)/-9.8 = 3.07 s = Rise time. Tf = Tr = 3.07 s. = Fall time. T = Tr+Tf = 3.07 + 3.07 = 6.14 s. = Time in air. d = Xo*T = 39.93m/s * 6.14s = 245.2 m. = Total dist. traveled.
*March 23, 2014*

**trigonometry**

The ladder is the hyp. of a rt. triangle X = ? Y1 = 8 Ft. Y2 = 84-8 = 76 Ft. A = 60o Tan 60 = Y2/X = 76/X X = 76/Tan60 = 43.88 Ft. = Dist. from bldg.
*March 23, 2014*

**Physics**

h=(V^2-Vo^2)/2g = (0-(8^2))/-19.6=3.27 m
*March 23, 2014*

**physics**

V = d/t = (t^3-3t^2+2)/4=(4^3-3*4^2+2)/4 = 4.5 m/s.
*March 23, 2014*

**physics**

a. 1.5km * 1000m/km * 1*10^6um/m = 1.5*10^9 Microns. b. 1.5um * 1m/10^6um * 100cm/m = 1.5*10^-4 cm c. 1.5yds * 3Ft/yd * 1m/3.3Ft * 10^6um/m = 1.364*10^6 Microns.
*March 23, 2014*

**physics**

h=(V^2-Vo^2)/2g = (0-(-8^2)/-19.6 = 3.27 m.
*March 23, 2014*

**physics**

T = 3 25/60 + (7 35/60-3 25/60) T = 3.417 + (7.583-3.417) = 7.583 Min. = 455 s. t = (7.583-3.417)min * 60s/min = 250 s. d = V*t = 1.65m/s * 250s = 412.4 m. V = d/T = 412.4m/455s = 0.906 m/s.
*March 23, 2014*

**math**

Given: F(x) = 1 - 3x. g(x) = x^2 - 1. F(g(x)) = F(x^2-1) F(x^2-1) = 1 - 3(x^2-1) = 1 - 3x^2 + 3 = -3x^2 + 4 F(g(x)) = -3x^2 + 4
*March 22, 2014*

**physics**

m*g = 50 * 9.8 = 490 N. = Wt. of crate = Normal force (Fn). a. Fs = u*Fn + u*F*sin30 Fs = 0.75*490 + 0.375F = 367.5 + 0.375F F*cosA-Fs = m*a F*cos30-(367.5+0.375F) = m*0 = 0 0.866F-367.5-0.375F = 0 0.866F-0.375F = 367.5 0.491F = 367.5 F = 748.5 N b. Fs = 0.75*490 - 0.75*F*...
*March 21, 2014*

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 20^2 - 19.6*15 = 106 V = 10.30 m/s.
*March 21, 2014*

**physics**

a = (V^2-Vo^2)/2d a = (0-(56)^2)/0.036 = -87,111 m/s^2 F = m*a = 850 * (-87,111)=-74,044,444 N.
*March 21, 2014*

**Physics**

V = 25 + 4 = 29 km/h.
*March 21, 2014*

**Math**

Vo = 200 Ft/s = Initial velocity. g = 2*(-16) = -32 Ft/s^2. hmax = (V^2-Vo^2)/2g = (0-(200)^2)/-64 = 625 Ft. Yes, because his max. ht. is greater than the ht. of the building.
*March 20, 2014*

**math**

C = pi*2r = (22/7) * 2(7n-21) C = (44/7) * (7n-21) = (308n - 924)/7 = 44n - 132
*March 20, 2014*

**physics**

m*g = 30 * 9.8 = 294 N. = Wt of cabinet. Fs = u*mg = 0.8 * 294 = 235.2 N.
*March 20, 2014*

**Math Help**

1. x^2 - 10x + 25 = 0 25 = -5 * -5 (x-5)(x-5) = 0 x-5 = 0 X = 5 x-5 = 0 X = 5 Solution set: X = 5, and 5. 2. 2x^2 + 9x -5 = 0 A*C = 2 * -5 = -10 = -1*10 2x^2 + (-x+10x) - 5 = 0 (2x^2-x) + (10x-5) = 0 x(2x-1) + 5(2x-1) = 0 (2x-1)(x+5) = 0 2x-1 = 0 2x = 1 X = 1/2 x+5 = 0 X = -5 ...
*March 20, 2014*

**Quick math help**

1. (3p^5*5p^2) + (7p^3*2p^4) = 15p^7 + 14p^7 = 29p^7 2. (6x^2-2xy+3y^2)-(4x^2-xy-y^2) = 6x^2-2xy+3y^2 -4x^2+xy+y^2 = 2x^2 - xy + 4y^2
*March 20, 2014*

**physics**

See previous post.
*March 20, 2014*

**physics**

When resistors are connected across a voltage source, the voltage will remain constant if the internal resistance of the source is much smaller than the total resistance connected across the source.
*March 20, 2014*

**Physics**

Correction: F*cosA-Fp = m*a F*cos46-810.7 = m*0 = 0 F*cos46 = 810.7 F = 1167 N.
*March 20, 2014*

**Physics**

m*g = 115 * 9.8 = 1127 N. = Wt of box. Fp = 1127*sin46 = 810.7 N. = Force parallel to the ramp. F-Fp = m*a F - 810.7 = m*0 = 0 F = 810.7 N. Fn = 1127*cos46 = 782.9 N. = Normal force.
*March 20, 2014*

**Physics**

30days * 24h/day = 720 Hours kW * h = (60/1000)kW * 720h = 43.2 kWh Cost = 43.2kWh * 0.10/kWh = $4.32
*March 20, 2014*

**physics**

A + B = 220[0o] + 220[120o] R = 220 + 220*cos120 + (220*sin120)I = 220-110 + 190.5i = 110 + 190.5i = 220[60o].
*March 20, 2014*

**Physics**

Fo = ((Vs+Vo)/(Vs-Vt))*Ft = 122 Hz ((340+0)/(340-Vt))*118 = 122 (340/(340-Vt))*118 = 122 40,120/(340-Vt) = 122 41,480-122Vt = 40,120 -122Vt = 40,120 - 41,480 = -1360 Vt = 11.15 m/s. = Velocity of the train.
*March 20, 2014*

**physics**

Speed = 1/0.005 = 200 On-States/s.
*March 20, 2014*

**Science**

d = V*T = 7.83*10^10 m. 3*10^8m/s * T = 7.83*10^10 T = 2.61*10^2 = 261 s. = 4.35 min.
*March 20, 2014*

**Algebra**

See previous post.
*March 19, 2014*

**Algebra**

F(-5,1), V(-2,1) VF = -5-(-2) = -3 = 1/4a 1/4a = -3 4a = -1/3 a = -1/12 = p. X = a(y-k)^2 + h X = (-1/12)(y-1)^2 - 2. Vertex Form.
*March 19, 2014*

**Physics**

X = -69 km/h Y = 215 km/h Tan Ar = Y/X = 215/-69 = -3.11594 Ar = -72.21o = Reference angle. A = -72.21 + 180 = 107.8o V=Y/sinA = 215/sin107.8=225.8km/h[107.8]
*March 19, 2014*

**phsyics**

Coefficient of Linear Exp.=(3.6*10^-5)/3 = 1.2*10^-5/C. L = Lo + a*(T-To)Lo L = 17 + 1.2*10^-5*(5-100)17 = 17 - 0.0194 = 16.981 m.
*March 19, 2014*

**Dont I need more info for this Math problem??**

Since the compounding frequency was not given, you'll have to use simple interest. P = Po + Po*r*t P=2,000 + 2000*0.03*4=2000 + 240 = 2240. Always show the Eq before plugging-in the values.
*March 19, 2014*

**phsyics**

a. Circumference = pi*2r = 3.14*2r = 6.28r V = C/t = 2pi*r/t b. V = 6.28*100m/14s = 45 m/s.
*March 19, 2014*

**phsyics**

a. V = Vp+Vw = 60 + (-40) = 20 km/h. b. V = 60 + 40 = 100 km/h.
*March 19, 2014*

**physics**

Vb = (Dc/Dw)*Vc = (100/1000)*Vc = 3 m^3 0.1Vc = 3 Vc = 30 m^3. = Vol. of cylinder.
*March 19, 2014*

**Physical Science**

P = V*I = 110 * 15
*March 19, 2014*

**physics**

Vo = 6.93 m/s[45.6o] Xo = 6.93*cos45.6 = 4.85 m/s Yo = 6,93*sin45.6 = 4.95 m/s. h = (Y^2-Yo^2)/2g = (0-4.95^2)/-19.6 = 1.25 m.
*March 19, 2014*

**physic**

a. KE = 0.5m*V^2 = 0.5m*0 = 0 J. The velocity is zero at the max. ht. b. V^2 = Vo^2 + 2g*h V^2 = 41.8^2 - 19.6*(34.5-8.88) V^2 = 1245.09 V = 35.29 m/s.
*March 19, 2014*

**Physics**

V^2 = Vo^2 + 2g*h = 0 at peak. Vo^2 - 19.6*16.6 = 0 Vo^2 = 325.4 Vo = 18.04 m/s = Speed at which ball was kicked.
*March 18, 2014*

**PHysiscs**

Fn = m*g = (83.5+68+62+55) * 9.8
*March 18, 2014*

**Maths**

10km[0o].
*March 18, 2014*

**Physics**

Circumference = pi * 2r = 3.14 * 0.20 = 0.6283 m/rev. Va = 24m/s * 6.28rad/0.6283m = 240 rad/s = Angular velocity. V = 24m/s * 1rev/0.6283m * 60s/min = 2292 RPM.
*March 17, 2014*

**Physics**

Circumference = pi * 2r = 3.14 * 0.620 = 1.95 m/rev. 8.5*10^7m * 1rev/1.95m = 4.36*10^7 Revs = 43.6 Million Revs.
*March 17, 2014*

**Physics**

a. Y^2 = Yo^2 + 2g*h = 0 m/s @ max. ht. Yo^2 - 19.6*0.750 = 0 Yo^2 = 14.7 Yo = 3.83 m/s. = Initial ver. velocity. b. Y = Yo + g*Tr = 0 m/s @ max. ht. Y = 3.83 - 9.8Tr = 0 9.8Tr = 3.83 Tr = 0.3908 s. = Rise time. Dx=Xo * Tr = 5m/s * 0.3908s. = 1.95 m. From basket.
*March 17, 2014*

**Physics**

Range = Vo^2*sin(2A)/g = 78 m. 34^2*sin(2A)/9.8 = 78 Solve for A.
*March 17, 2014*

**PHYSICS**

See previous post: Mon,3-17-14,8:03 PM.
*March 17, 2014*

**Physics**

m*g = 20 N. m = 20/g = 20/9.8 = 2.041 kg A. Work = 0.5m*Vo^2 - 0.5m*V^2 = mg*h 1.02*Vo^2 - 1.02*25^2 = 20*14.8 1.02Vo^2 - 637.5 = 290 1.02Vo^2 = 290 + 637.5 = 927.5 Vo^2 = 909.31 Vo = 30.15 m/s. B. h = (V^2-Vo^2)/2g = (0-30.15^2)/-19.6 = 46.38 m.
*March 17, 2014*

**physics**

Ratio = (331+0.6T1)/(331+0.6T2) = (331+0)/(331+60) = 0.847
*March 17, 2014*

**math**

-16t^2 + 120t = 0 Use Quadratic Formula and get: Tr = 3.75 s. = Rise time or time to reach max ht. Tf = Tr = 3.75 s. = Fall time. T = Tr + Tf = 3.75 + 3.75 = 7.50 s. To strike gnd.
*March 17, 2014*

**physics**

1. 15 - 6 = 9 N. = Net force. 2. a = Fn/m = 9/3 = 3 m/s^2.
*March 16, 2014*

**physics**

F = m*a = 60 * 2.5 = 150 N. V = Vo + a*t = 0 + 2.5*4 = 10 m/s.
*March 14, 2014*

**physics**

a=(V^2-Vo)/2d = (0-20^2)/1000=-0.4 m/s^2 F = m*a = 10000 * -0.4 = -4,000 N.
*March 14, 2014*

**Physics**

V = Vo + a*t = 0 + 0.3*30 = 9 m/s. d = (V^2-Vo^2)/2a = (9^2-0)/0.6 = 135 m.
*March 14, 2014*

**math**

F(x) = 5x^2 + 8x + 5 = 0 Quadratic Formula: X = (-B +- sqrt(B^2-4AC))/2a X = (-8 +- sqrt(64-100))/10 = (-8 +- sqrt(36*(-1))/10 = (-8 +- 6i)/10 = -0.8 +- 0.6i = -0.8 + 0.6i, and -0.8 - 0.6i. So we have 2 imaginary solutions.
*March 14, 2014*

**math**

x^2 + 5x - 2 < 0 Solve and graph: x^2 + 5x - 2 = 0 Use Quadratic Formula an get: X = -5.37, and 0.372 Solution to inequality:-5.37 < X < 0.372
*March 14, 2014*

**physics**

m*g = 15.7 * 9.8 = 153.9 N. = Wt. of block. Fn = 153.9*cos12.1 = 150.4 N.
*March 14, 2014*

**Physics**

PEmax=mg*hmax = 28*9.8 * 159=43,630 J. = KEmax @ bottom of hill with no friction. KE = 14*31.3^2 = 13,716 J. Energy lost = 43,630 - 13,716=29,914 J.
*March 14, 2014*

**physics-impulse**

Impulse = 2*m*V*cos45
*March 14, 2014*

**Physics**

Energy = m*g*h.
*March 14, 2014*

**math**

0.002N = 76 N = 38,000
*March 14, 2014*

**math**

GP = 22/day*6days + 0.18*2766.50 =
*March 14, 2014*

**Physics**

m*g = 295 * 9.8 = 2891 N. = Wt. of box. = Fn = Normal force. Fs = u*Fn = 0.2 * 2891 = 578.2 N. = Force of static friction. Fe-Fs = m*a Fe - 578.2 = m*0 = 0 Fe = 578.2 N. = Force of engine. Energy=Work = Fe*d = 578.2 * 2.8=1619 J.
*March 14, 2014*

**Algebra**

1. 18 = 1*18 = 1*2*9 = 1*2*3*3. Factors: N = {1,2,3,9,18}. 3a. 5.25x => 252 4a. Inequality: 88 < (78+93+x)/3 < 90 264 < 171 + x < 270 93 < X < 99 The inequality says: (78+93+x)/3 is greater than 88 but less than 90.
*March 13, 2014*

**physics**

V = Vo + g*t = 0 + 9.8*3 = 29.4 m/s
*March 13, 2014*

**phys**

m*g = 12kg * 9.8N/kg = 117.6 N. = Wt. of the crate. Fs = u*mg = 0.4 * 117.6 = 47.04 N. = Force of static friction. F*cos(-30) - Fs = m*a 0.8669F - 47.04 = m*0 = 0 0.866F = 47.04 F = 54.32 N.
*March 12, 2014*

**Science... plz help~!**

F = m*a = 40 * 10 = 400 N.
*March 12, 2014*

**finance**

P = Po*r*t/(1-(1+r)^-t) Po = $13,000 = Loan amount. r = (6%/12)/100% = 0.005 = Monthly % rate expressed as a decimal. t = 12mo/yr * 10yrs = 120 Months. P = (13000*0.005*120)/(1-(1.005)^-120) = $17,319.20 = Amt. to be paid. Monthly Payment = P/t = 17319.20/120 = $144.33 Payment...
*March 12, 2014*

**Gr 11 - math linear systems**

(10-2)x - 2000 = $16,000 8x - 2000 = 16000 8x = 18000 X = 2,250 Tickets.
*March 11, 2014*

**math**

2. Shifted 5units down. 5. -7x^2 + 6x + 3 = 0 Use Quadratic formula and get 2 solutions : -0.354, and 1.211. 6. Y = 3x^2 + 18x + 27 = 0 x^2 * 6x + 9 = 0 (x+3)(x+3) = 0 x+3 = 0, x = -3. x+3 = 0, X = -3. 2 solutions : -3, and -3. 11. Use Quad. Formula and get 3.54 s. 12. V = Vo...
*March 11, 2014*

**physics**

V = Vo + g*t = 0 + 10*1=10 m/s. T = 1s. d = Vo*t + 0.5g*t^2 d = 10*1 + 5*1^2 = 15 m.
*March 11, 2014*

**physics**

My answer is B also.
*March 11, 2014*

**Physics**

P = 16/12 = 1.333 s.
*March 11, 2014*

**Physics**

d = V*t = 305 m. V*(1.85/2) = 305 V = 329.7 m/s.
*March 11, 2014*

**physics**

a = (V-Vo)/t = (-8-16)/0.04 = -600 m/s^2 F = m*a = 0.2 * (-600) = -120 N.
*March 11, 2014*

**physics**

Xo = 0.9 m/s? D = Xo*t = 0.9m/s * 0.4s = 0.36 m.
*March 11, 2014*

**physics**

B. 10 m/s, North.
*March 11, 2014*

**physics**

PEmax = mg*hmax = mg*4.07 J. Change = 0-mg*4.07 = -3900 mg = 958.2 N. = Wt. of the vaulter.
*March 11, 2014*

**math**

Fp = 1.5*sin18 = Parallel Force(Wt.) Fn=1.5*cos18 = Normal or perpendicular force(Wt.).
*March 11, 2014*

**physics**

Fh = 151 Hz Vr = 28.7 m/s Vs = 343 m/s Fr = ((Vs+Vr)/(Vs-Vh)) * Fh Fr = ((343+28.7)/(343-0)) * 151 Hz = (371.7/343) * 151 = 163.6 Hz = Freq. heard by the receiver(Passenger).
*March 11, 2014*

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