Tuesday
June 30, 2015

Posts by Henry


Total # Posts: 10,677

Physics
See Related Questions: Thu, 10-2-14, 2:52 AM.
January 9, 2015

physics
1. 38Lbs/95Lbs * 882N. = 352.8 N. on Mars. 2. 95Lbs/38Lbs * 333N = 832.5 N. on Earth.
January 9, 2015

Physics
A. d = V*T = 57.5 m V*15.3 = 57.5 V = 3.76 m/s B. V = Va + Vp = 3.76 1.75 + Vp = 3.76 Vp = 2.0 m/s
January 8, 2015

physics
Range = Vo^2*sin(2A)/g = 12 m. Vo^2*sin(28.4)/9.8 = 12 Vo^2*sin(28.4) = 117.6 Vo^2 = 117.6/sin(28.4) = 247.3 Vo = 15.72 m/s.
January 8, 2015

Algebra 1
x + y = 9 x - y = 1 Sum: 2x + 0 = 10 X = 5 In Eq1, replace x with 5: 5 + y = 9 Y = 4 Solution set: (x,y) = (5,4).
January 8, 2015

physics
Wt. = M*g = 40kg * 9.8N/kg = 392 N. L = 6 + (1m/50N * 392N) = 13.84 m.
January 8, 2015

6TH GRADE MATH
Platypus: 10 min. Whale: 7(10+x) = 112
January 8, 2015

Math
a. X = 2. F(x) = -3(2+-2)^2 - (2+1) = -51 g(x) = -3*2^2 - 13*2 - 13 = -51 The student should finish the assignment.
January 8, 2015

Math
5/(x-1) + 2/(x+1) = -6 LCD = (x-1)(x+1) 5(x+1)/(x-1)(x+1)+2(x-1)/(x+1)(x-1) =-6 (5x+5)/(x-1(x+1) + (2x-2)/(x+1)(x-1)=-6 Add the numerators: (7x+3)/(x+1)(x-1) = -6 7x+3 = -6(x+1)(x-1) 7x+3 = -6(x^2-1) 7x+3 = -6x^2 + 6 6x^2 + 7x = 6 - 3 = 3 6x^2 + 7x - 3 = 0 Use AC method of ...
January 8, 2015

Math 1 please help
1. Shirts: A = (12-3)x = 9x x = The number of shirts bought. Jeans: A = (19-3)x = 16x
January 8, 2015

science
See Related Questions: Tue, 7-17-12, 8:08 AM.
January 7, 2015

Physical Science
Correct!
January 7, 2015

Physical Science
(M1+M2)V = M2*V2 80.16V = 0.16*20 Solve for V.
January 7, 2015

Physics
M*g = 100 N. Fn = 100*Cos0 - Fap*sin45 = Normal force Fn = 100 - 0.707Fap Fk=u*Fn = 0.75(100-0.707Fap)=75-0.53Fap Fap-Fk = M*a Fap-75 + 0.53Fap = M*0 = 0 1.53Fap = 75 Fap = 49 N. = Force applied. Fn = 100-0.707Fap = 100 - 0.707*49 = 65.4 N. = Normal force.
January 7, 2015

math
Eq1: Do mean Y = (3/2)x - 1? If so, then Y = 3x/2 - 1 Multiply both sides by 2: 2y = 3x - 2 Eq1:-3x + 2y = -2 Eq2: +x + y = 4 Multiply Eq2 by 3 and add the Eqs: -3x + 2y = -2 +3x + 3y = 12 Sum: 5y = 10 Y = 2. In Eq2, replace y with 2 and solve for x: x + 2 = 4 X = 2. Solution ...
January 7, 2015

physics
Wt. = M*g M = 23.5 kg g = 9.8m/s^2 Solve for Wt.
January 7, 2015

physics
Mass = 4.6g/1000 = 0.0046 kg a. KE1 = 0.5*M*V1^2 = 3.13 J. b. KE@ = 0.0023*74.8^2 = 12.87 J.
January 7, 2015

Physics
M*g = 500 N. = Normal force(Fn). Fk = u*Fn = 0.3 * 500 = 150 N. = Force of kinetic friction. Fap-Fk = M*a Fap-150 = M*0 = 0 Fap = 150 N. = Force applied.
January 7, 2015

Math
In a rt. triangle, the sum of the square of the two shorter sides is equal to the square of the 3rd side. X = 959 Miles Y = 1,011 Miles Z = 1,033 Miles X^2 + Y^2 = Z^2 959^2 + 1011^2 = 1033^2 1,941,802 > 1,067,089 It is not a rt. triangle.
January 7, 2015

physics
Circumference = pi * 2r = 3.14 * 2*399 = 2507 m. V = 40.5m/s * 6.28rad/2507m = 0.1015 rad/s.
January 7, 2015

physics
M*g = 300 N T = 100N[30o] Fn = M*g - T*sin A = 300 - 100*sin30
January 7, 2015

algebra
Oops! Posted pre-maturely. 2. Mark: 3y Linda: 3y - 6 In the end: Mark: 3y + 2y = 5y Linda: (3y-6) + 2y = 5y - 6
January 7, 2015

algebra
1. Sheila: 7y Craft sticks. Mark: 7y-4y = 3y Linda: 3y-y = 2y In the end: Sheila: 7y-2y-2y = 3y Mark: 3y + 2y = 5y Linda: 2y + 2y = 4y 2. Mark: 3y Linda: 3y - 6
January 7, 2015

Math
X = 8 Mi Y = -10 Mi a. Tan A = Y/X = -10/8 = -1.25 A = -51.3o = 51.3o S. of E. b. d^2 = X^2 + Y^2 = 8^2 + (-10)^2 = 164 d = 12.81 Miles. c. d = V*t Solve for t. d. A = -51.3 + 180 = 128.7o, CCW = 51.3o N. of W.
January 6, 2015

physics please help
See previous post: Tue, 1-6-15, 3:44 PM.
January 6, 2015

Physics
Ww = Vo*Dw = 4m^3 * 1000kg/m^3 = 4,000 kg. = Wt. of water displaced. = Wt. of the object in water.
January 6, 2015

Physics
Vb = L*W*h = 5 * 1 * 0.5 = 2.5 m^3 = Vol. of the box=Vol. of water displaced. Mass = Vb*Dw = 2.5m^3 * 1000kg/m^3 = 2500 kg.
January 6, 2015

physics
Vo = 157km/h = 157000m/3600s = 43.61 m/s V = 75.0km/h = 75000m/3600s = 20.83 m/s. a = -7.0 m/s^2 A. V = Vo + a*t Solve for t. B. V^2 = Vo^2 + 2a*d Solve for d.
January 6, 2015

physics please help
Tr = Tf = 4s./2 = 2 s. = Rise & fall time. h = Vo*Tf + 0.5g*Tf^2 = 0 + 4-9*2^2 = 19.6 m.
January 6, 2015

Algebra
2nd number = X 1st number = 3x/20 x + 3x/20 = 46 Multiply both sides by 20 and solve for x.
January 5, 2015

Math
I = Po*r*t = 10,000*(0.0225/52)*13 = 56.25 = Int. for 13 weeks. (56.25/13) * 52 = $225 = Int./yr. %I = (225/10,000)*100% = 2.25%
January 5, 2015

Physics
At 100 m. above gnd. PE max = Mg*h max = 80*100 = 8000 J. KE + PE = 8000 0 + 8000 = 8000 At 60 m. above gnd. PE = Mg*h = 80*60 = 4800 J. KE + PE = 8000 KE + 4800 = 8000 KE = 8000-4800 = 3200 J. The total energy, KE+PE, is constant at 8000 J.
January 5, 2015

physics
h = 4*sin37 = 2.41 m. V^2 = Vo^2 + 2g*h Vo = 0 g = 9.8 m/s^2 h = 2.41 m Solve for V.
January 4, 2015

physics
V^2 = Vo^2 + 2g*h V = 0 Vo = Initial velocity. g = -9.8 m/s^2 h = 1.28 m. Solve for Vo.
January 4, 2015

Physics
Tx = 20*Cos53 = 12 N. = Hor. component of tension. Tx-Fk = M*a 12-Fk = M*0 = 0 Fk = 12 N.
January 4, 2015

physics
h = 0.5g*t^2 h = 2 m. g = 9.8 m/s^2 t = Fall time. Solve for t. Dx = Xo * t Dx = Hor. distance from table. Xo = 10m/s = Initial hor. velocity. Solve for Dx.
January 4, 2015

Math
9(a^2+a+4) Answer: Neither. Difference of 2 squares = (a+b)(a-b) = a^2 - b^2
January 4, 2015

Pre-calc/trig
Log3(x^2+18) = 5 x^2 + 18 = 3^5 x^2 + 18 = 243 x^2 = 243 - 18 = 225 X = 15
January 4, 2015

Algebra 1
Use Long-hand division. (6x^3 - 3x^2 + x - 40)/(x-2)=6x^2+9x+19, Remainder 2.
January 4, 2015

mathe
Use your calculator.
January 4, 2015

physics
V^2 = Vo^2 + 2g*h Vo = 0 g = 9.8 m/s^2 h = 2 m. Solve for V. Note: The 10 m/s velocity is in the hor. direction.
January 4, 2015

Physics
V^2 = Vo^2 + 2a*d V = 17 m/s Vo = 0 d = 45 m Solve for a. F = m*a
January 3, 2015

Physics
a = (Fap-Ff)/M = (56-12)/25 = 1.76 m/s^2
January 3, 2015

physics
A = 5m[45o], CCW. B = 7m[330o], CCW C = 4m[240o], CCW. X=5*Cos45 + 7*Cos330 + 4*Cos240 = 7.60 m Y=5*sin45 + 7*sin330 + 4*sin240=-3.43 m Tan A = Y/X = -3.43/7.60 = -0.45113 A = -24.28o = 24.28o S of E = 335.7o, CCW. Resultant = X/CosA = 7.60/Cos335.7 = 8.34m[335.7]
January 3, 2015

physics
See previous post: Sat, 1-3-15, 4:01 AM.
January 3, 2015

physics
a. h = 50 + 20 = 70 m Above gnd. V^2 = Vo^2 + g*h = 0 Vo^2 - 9.8*20 = 0 Vo^2 = 196 Vo = 14 m/s. = Initial velocity. V = Vo + g*Tr = 0 14 - 9.8Tr = 0 9.8Tr = 14 Tr = 1.43 s. = Rise time. h = 0.5g*t^2 = 70 m. 4.9t^2 = 70 t^2 = 14.3 Tf = 3.78 s. = Fall time. Tr+Tf = 1.43 + 3.78...
January 3, 2015

physics
a. P = 5m[150o] X = 5*Cos150 Y = 5*sin150 b. 120-90 = 30o Clockwise from positive x axis = 330o counter clockwise from positive x axis. Q = 3.6m[330o], CCW. X = 3.6*Cos330 Y = 3.6*sin330
January 3, 2015

physics
D = 5m[37o] + 10m[150o] X = 5*Cos37 + 10*Cos150 = -4.67 m. Y = 5*sin37 + 10*sin150 = 8.00 m. Tan Ar = Y/X = 8/-4.67 = -1.71501 Ar = -59.75o = Reference angle. A = -59.75 + 180 = 120.25o = Direction. D=Y/sin A = 8.00/sin120.25=9.26m[120.25] = Magnitude and direction.
January 3, 2015

physics
a. h = 0.5g*t^2 h = 43.4 m. g = 9.8 m/s^2 t = Fall time. Solve for t. b. Dx = Xo * t Dx = 57.3 m. = Hor. dist. Xo = Initial hor velocity. t = Fall time calculated in part a. Solve for Xo. c. X = Xo=Initial hor velocity(part b). Xo does not change. d. Y = Yo + g*t Yo = 0 g = 9....
January 2, 2015

physics
X^2 + Y^2 = r^2 X = 25 cm Y = Ver. Displacement r = 50 cm = Hypotenuse. Solve for Y.
January 2, 2015

physics
V = Vo + a*t V = -40 m/s Vo = 30 m/s t = 0.04 s. Solve for a(It is negative).
January 2, 2015

physics
11. Ws = 5000 N. = Normal force(Fn). Fk = u*Fn = 0.05 * 5000 = 250 N. = Eorce of kinetic friction. Fap-Fk = M*a Fap - 250 = M*0 = 0 Fap = 250 N. = Force applied. Work = Fap * d = 250 * 1000 = 250,000 J. = 2.5*10^5 J. 12. Same procedure as #11.13. 13. Ws = 6000 N. = Normal ...
December 31, 2014

Math- Max and Minimum
Consider the function f(x) = 3/4x^4 –x^3 -3x^2 + 6x , find the relative extrema for f(x), be sure to label each as a maximum or minimum. How do I find the x-values of what it is asking?
December 31, 2014

physics
E = 6 Volts r = 0.4 Ohms R = 2.6 Ohms. I = E/(r+R) = 6/(0.4+2.6) = 2 Amps. = Current flowing in the circuit. Vt = I*R = 2 * 2.6 = 5.2 Volts. = Potential difference between terminals of the battery. Vr = I * r = 2 * 0.4 = 0.8 Volts. = Voltage lost across the internal resistance...
December 31, 2014

physics
1 Amp = 6.242*10^18 Electrons/s 2.4 Amps = 2.4 * 6.242*10^18 = 1.5*10^19 Electrons/s.
December 31, 2014

physics
R2 = R1 + 0.00392(T2-T1)R1 = 257.6 Ohms. 200 + 0.00392(T2-0)200 = 257.6 200 + 0.784(T2-0) = 257.6 200 + 0.784T2 = 257.6 0.784T2 = 57.6 T2 = 73.5o C.
December 31, 2014

physics
V1=180rev/min * 6.28rad/rev * 1min/60s = 18.84 Rad/s. V2 = 140/180 * 18.84 = 14.65 Rad/s. a = (V2-V1)/t = (14.65-18.84)/20 = -0.209 Rad/s^2. b. V3 = V1 + a*t = 0 t = -V1/a = -18.84/-0.209 = 90 s. To stop. a. V3^2 = V1^2 + 2a*d = 0 d = -V1^2/2a = -(18.84^2)/-0.418 = 849.2 ...
December 31, 2014

Math
A = (0.44/6.28) * 360o = 25.2o sin A = h/L L = h/sin A = 202/sin25.2 = 474 Ft.
December 30, 2014

physics
g + a = 6.4 -9.8 + a = 6.4 a = 6.4 + 9.8 = 16.2 m/s^2 Thrust = M*a = 5 * 16.2 = 81 N.
December 30, 2014

Physics
Yes, I noticed that the initial velocity was unusually low; but I assumed that a change in velocity would change the answer but not the procedure.
December 29, 2014

Physics
1. Correct 3. Correct 5. Correct 6. Correct. 7. Correct 8. Correct 9. Correct.
December 29, 2014

physics
See Related Questions: Thu, 12-20-12, 6:03 PM.
December 29, 2014

physics
a = (V-Vo)/t = (25-20)/4 = 1.25 m/s^2.
December 28, 2014

physics
Wt. = M*g = 60kg * 10N/kg = 600 N.
December 28, 2014

math
A = 0.5*AB*AC*sin A=0.5 *5 * 5 * sin 60 = 10.8 cm^2.
December 26, 2014

physics
X = 8.70 m. Y = -6.04 m. a. D^2 = X^2 + Y^2 = 8.7^2 + (-6.04)^2 = 112.2 D = 10.6 m. b. Tan A = Y/X = -6.04/8.7 = -0.69425 A = -34.8o CW. A = 360 - 34.8 = 325.2o CCW.
December 25, 2014

Chemistry
What are the different ways to split a mixture of benzene and methanol into its constituents using a 2 phase system separation ?
December 25, 2014

Algebra 1
y = 4x + 3 Eq1: -4x + y = 3 Eq2: -8x + 2y = 3 m1 = -A/B = 4/1 = 4 m2 = 8/2 = 4 Eq1: y-int. = C/B = 3/1 = 3. Eq2: Y-int. = 3/2 = 1.5 No Solutions.
December 23, 2014

Algebra 1
x = -4y + 4 Eq1: x + 4y = 4 Eq2: 2x+8y = 8 Divide Eq2 by 2: x+4y = 4 The Eqs are identical and represent the same line. Therefore, we have an infinite number of solutions.
December 23, 2014

Algebra
$X To start with. 1st. Store: Bal. = X - ((X/2)+1) = X - X/2-1 = X/2-1 2nd Store: Bal=X/2-1 - (X/2-1)/2+1 = X/2-1 - X/4+1/2-1 = X/4 - 1/2. 3rd. Store: Bal = X/4-1/2 - (X/4-1/2)/2+1 = X/4-1/2 - X/8+1/4)-1 = X/8 - 1 1/4 = X/8 - 5/4. 4th Store: X/8-5/4 - (X/8-5/4)/2+1 = X/8-5/4...
December 22, 2014

Physics
a. h=ho + (-Vo^2/2g)=100 + (-98^2)/-19.6 = 590 m. b. V = Vo + g*Tr = 0 98 - 9.8*Tr = 0 -9.8Tr = -98 Tr = 10 s. = Rise time. h = 0.5g*t^2 = 590 4.9*t^2 = 590 t^2 = 120.4 Tf = 11 s. = Fall time. Tr+Tf = 10 + 11 = 21 s. = Time to reach gnd. c. V^2 = Vo^2 + 2g*h Vo = 0 g = 9.8 m/s...
December 22, 2014

Physics
Note: The Fall time is not required.
December 22, 2014

Physics
h = 0.5g*t^2 = 4 m. 4.9*t^2 = 4 t^2 = 0.816 Tf = 0.904 s. = Fall time. V1^2 = Vo^2 + 2g*h = 0 + 19.6*4 = 78.4 V1 = 8.85 m/s., Downward. V^2 = V2^2 + 2g*h = 0 V2^2 = -2g*h = -2*(-9.8)*3 = 58.8 V2 = 7.67 m/s, Upward. a = (V2-V1)/t = (7.67-8.85)/0.01 = -118 m/s^2, Upward.
December 22, 2014

physics
F = 200N[30o] Fx = 200*Cos30 = 173.2 N. Fy = 200*sin30 = 100 N. M*g = 30kg * 9.8N/kg = 294 N. = Wt. of the object. a. Fk = u*Fn = u*(Mg-Fy) = 0.2(294-100) = 38.8 N. = Force of kinetic friction. b. a = (Fx-Fk)/M c. V = Vo + a*t Vo = 0 a = Value from part b. t = 5 s. Solve for V.
December 21, 2014

physics
Vs = 50mi/h * 1600m/mi * 1h/3600s = 22.22 m/s. = Velocity of the speedster. a. Ds = Dp 22.2*t = 0.5a*t^2 Divide both sides by t: 0.5a*t = 22.2 0.5*0.450t = 22.2 0.225t = 22.2 t = 98.8 s. b. Ds = Dp = 22.2*t = 22.2 * 98.8 = 2193 m. c. V^2 = Vo^2 + 2a*d Vo = 0 a = 0.450 m/s^2 d...
December 21, 2014

Physics
A 10.0 kg barrel is lifted by pulling up on a rope. The barrel accelerates at 1.50 m/s2. Find the force of tension on the rope.
December 21, 2014

Calculas
V = Vo + g*t Vo = 0 g = 9.8 t = 2.75 s. Solve for V.
December 21, 2014

Science
V = 60km/h = 60,000m/3600s = 16.7 m/s. Work = The change in KE = 0.5*M*V^2 = 0.5*1500*16.7^2 = 209,168 J.
December 21, 2014

Science
V^2 = Vo^2 + 2g*h = 0 Vo^2 = -2g*h = -2*(-9.8)*1000 = 19,600 Vo = 140 m/s.
December 21, 2014

math
a. I = Po*r*t = 5000*(0.09/360)*80 = $100 = Interest. b. V = Po + I = 5000 + 100 = $5100 = Maturity value. c. July 1.
December 18, 2014

business math
Ar = Ab - Ad Ar = 20,000 - 20,000*(0.085/360)*90 = 20,000 - 425 = $19,575 = Amount received (proceeds). Ab = Amt. borrowed. Ad = Amt. discounted.
December 18, 2014

Physics
h = 3.1*sin30 = 1.55 m. a. V^2 = Vo^2 + 2g*h = 0 + 19.6*1.55 = 30.4 V = 5.51 m/s. b. V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d = (0-(5.51^2))/10 = -3.04 m/s^2. M*g = 7.5 * 9.8 = 73.5 N. = Wt. of suitcase. Fp = 73.5*Sin30 = 36.75 N. = Force parallel to the incline. Fn = 73.5*Cos30 = ...
December 18, 2014

physic
250+160+420+F4 = 220+340+180+560 Solve for F4.
December 18, 2014

math
d = r*t = 12 km 3 * t = 12 t = 4 h 1. d = r*t = 12 r * 3 = 12 r = 4 km/h Change = 4 - 3 = 1 km/h = 1 km/h increase. 2. d = r*t = 12 km r * 5 = 12 r = 2.4 km/h. Change = 2.4 - 3 = -0.6 km/h = 0.6 km/h decrease.
December 18, 2014

physics
Vo[0o] Xo = Vo*Cos0 = Vo Yo = Vo*sin0 = 0 Vo[30o] Xo = Vo*Cos30 = 0.87Vo Yo = Vo*sin30 = 0.5Vo Vo[60o] Xo = Vo*Cos60 = 0.5Vo Yo = Vo*sin60 = 0.87Vo
December 17, 2014

Phyiscs
V^2 = Vo^2 + 2g*h Vo = 0 g = 9.8 h = 0.5 m. Solve for V.
December 17, 2014

algebra
(3,63),(5,57), (17,y). m = (57-63)/(5-3) = -6/2 = -3. m = (y-57)/(17-5) = (y-57)/12 = -3/1 y-57 = -36 Y = 57-36 = 21 Inches after 17 days.
December 17, 2014

algebra
What tank?
December 17, 2014

physics
W = Fx*d = 54*Cos10 * 3.4
December 17, 2014

Algebra
Correction: The Eqs are identical(divide the 1st Eq by 4). So we have an infinite # of solutions.
December 17, 2014

Algebra
m1 = -A/B = -16/-8 = 2 m2 = -4/-2 = 2 m1 = m2. So the lines do not intersect. Therefore, there is no solution.
December 17, 2014

physic
V^2 = Vo^2 + 2g*d = 0 + 19.6*50 = 980 V = 31.3 m/s.
December 17, 2014

Algebra 1
2x/3 + y = 7 Multiply both sides by 3: 2x + 3y = 21
December 16, 2014

physics
X = -5.4 m/s. Y = 3.6 m/s. Tan Ar = Y/X = 3.6/-5.4 = -0.66666 Ar = -33.7o = Reference angle. A = -33.7 + 180 = 146.3o = Direction. V = X/Cos A = (-5.4)/Cos146.3 = 6.49 m/s[146.3o].
December 16, 2014

Algebra
1. (-7)(3)-(5)(-3) = -21 - (-15) = -21+15 = -6 2. (x^2+6) - (3x^2-2x-5)=x^2+6-3x^2-2x-5 = =2x^2 - 2x + 1
December 16, 2014

Algebra 2
a. m = -A/B = -2/-5 = 2/5 b. m = -3/2
December 16, 2014

Algebra
Answer = A.
December 16, 2014

Algebra 2
K = y/x = 1/-3 = -1/3. y/x = -1/3 4/x = -1/3 -x = 12 X = -12.
December 16, 2014

Algebra 2
a. Y = 2x - 3 Y = mx - b m = 2 = Slope. b. 3y - 7x = 1? -7x + 3y = 1 m = -A/B = 7/3
December 16, 2014

math
X = Tony's future age. 4x = Mr. Jacob's future age. 4x - x = 55-7 3x = 48 X = 16 4x = 4 * 16 = 64 16-7 = 9 years. 64-55 = 9 years. So Mr. Jacobs will be 4 times as old as Tony in 9 years.
December 16, 2014

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