Monday
May 25, 2015

Posts by Henry


Total # Posts: 10,621

physics
a. h = 50 + 20 = 70 m Above gnd. V^2 = Vo^2 + g*h = 0 Vo^2 - 9.8*20 = 0 Vo^2 = 196 Vo = 14 m/s. = Initial velocity. V = Vo + g*Tr = 0 14 - 9.8Tr = 0 9.8Tr = 14 Tr = 1.43 s. = Rise time. h = 0.5g*t^2 = 70 m. 4.9t^2 = 70 t^2 = 14.3 Tf = 3.78 s. = Fall time. Tr+Tf = 1.43 + 3.78...
January 3, 2015

physics
a. P = 5m[150o] X = 5*Cos150 Y = 5*sin150 b. 120-90 = 30o Clockwise from positive x axis = 330o counter clockwise from positive x axis. Q = 3.6m[330o], CCW. X = 3.6*Cos330 Y = 3.6*sin330
January 3, 2015

physics
D = 5m[37o] + 10m[150o] X = 5*Cos37 + 10*Cos150 = -4.67 m. Y = 5*sin37 + 10*sin150 = 8.00 m. Tan Ar = Y/X = 8/-4.67 = -1.71501 Ar = -59.75o = Reference angle. A = -59.75 + 180 = 120.25o = Direction. D=Y/sin A = 8.00/sin120.25=9.26m[120.25] = Magnitude and direction.
January 3, 2015

physics
a. h = 0.5g*t^2 h = 43.4 m. g = 9.8 m/s^2 t = Fall time. Solve for t. b. Dx = Xo * t Dx = 57.3 m. = Hor. dist. Xo = Initial hor velocity. t = Fall time calculated in part a. Solve for Xo. c. X = Xo=Initial hor velocity(part b). Xo does not change. d. Y = Yo + g*t Yo = 0 g = 9....
January 2, 2015

physics
X^2 + Y^2 = r^2 X = 25 cm Y = Ver. Displacement r = 50 cm = Hypotenuse. Solve for Y.
January 2, 2015

physics
V = Vo + a*t V = -40 m/s Vo = 30 m/s t = 0.04 s. Solve for a(It is negative).
January 2, 2015

physics
11. Ws = 5000 N. = Normal force(Fn). Fk = u*Fn = 0.05 * 5000 = 250 N. = Eorce of kinetic friction. Fap-Fk = M*a Fap - 250 = M*0 = 0 Fap = 250 N. = Force applied. Work = Fap * d = 250 * 1000 = 250,000 J. = 2.5*10^5 J. 12. Same procedure as #11.13. 13. Ws = 6000 N. = Normal ...
December 31, 2014

Math- Max and Minimum
Consider the function f(x) = 3/4x^4 –x^3 -3x^2 + 6x , find the relative extrema for f(x), be sure to label each as a maximum or minimum. How do I find the x-values of what it is asking?
December 31, 2014

physics
E = 6 Volts r = 0.4 Ohms R = 2.6 Ohms. I = E/(r+R) = 6/(0.4+2.6) = 2 Amps. = Current flowing in the circuit. Vt = I*R = 2 * 2.6 = 5.2 Volts. = Potential difference between terminals of the battery. Vr = I * r = 2 * 0.4 = 0.8 Volts. = Voltage lost across the internal resistance...
December 31, 2014

physics
1 Amp = 6.242*10^18 Electrons/s 2.4 Amps = 2.4 * 6.242*10^18 = 1.5*10^19 Electrons/s.
December 31, 2014

physics
R2 = R1 + 0.00392(T2-T1)R1 = 257.6 Ohms. 200 + 0.00392(T2-0)200 = 257.6 200 + 0.784(T2-0) = 257.6 200 + 0.784T2 = 257.6 0.784T2 = 57.6 T2 = 73.5o C.
December 31, 2014

physics
V1=180rev/min * 6.28rad/rev * 1min/60s = 18.84 Rad/s. V2 = 140/180 * 18.84 = 14.65 Rad/s. a = (V2-V1)/t = (14.65-18.84)/20 = -0.209 Rad/s^2. b. V3 = V1 + a*t = 0 t = -V1/a = -18.84/-0.209 = 90 s. To stop. a. V3^2 = V1^2 + 2a*d = 0 d = -V1^2/2a = -(18.84^2)/-0.418 = 849.2 ...
December 31, 2014

Math
A = (0.44/6.28) * 360o = 25.2o sin A = h/L L = h/sin A = 202/sin25.2 = 474 Ft.
December 30, 2014

physics
g + a = 6.4 -9.8 + a = 6.4 a = 6.4 + 9.8 = 16.2 m/s^2 Thrust = M*a = 5 * 16.2 = 81 N.
December 30, 2014

Physics
Yes, I noticed that the initial velocity was unusually low; but I assumed that a change in velocity would change the answer but not the procedure.
December 29, 2014

Physics
1. Correct 3. Correct 5. Correct 6. Correct. 7. Correct 8. Correct 9. Correct.
December 29, 2014

physics
See Related Questions: Thu, 12-20-12, 6:03 PM.
December 29, 2014

physics
a = (V-Vo)/t = (25-20)/4 = 1.25 m/s^2.
December 28, 2014

physics
Wt. = M*g = 60kg * 10N/kg = 600 N.
December 28, 2014

math
A = 0.5*AB*AC*sin A=0.5 *5 * 5 * sin 60 = 10.8 cm^2.
December 26, 2014

physics
X = 8.70 m. Y = -6.04 m. a. D^2 = X^2 + Y^2 = 8.7^2 + (-6.04)^2 = 112.2 D = 10.6 m. b. Tan A = Y/X = -6.04/8.7 = -0.69425 A = -34.8o CW. A = 360 - 34.8 = 325.2o CCW.
December 25, 2014

Chemistry
What are the different ways to split a mixture of benzene and methanol into its constituents using a 2 phase system separation ?
December 25, 2014

Algebra 1
y = 4x + 3 Eq1: -4x + y = 3 Eq2: -8x + 2y = 3 m1 = -A/B = 4/1 = 4 m2 = 8/2 = 4 Eq1: y-int. = C/B = 3/1 = 3. Eq2: Y-int. = 3/2 = 1.5 No Solutions.
December 23, 2014

Algebra 1
x = -4y + 4 Eq1: x + 4y = 4 Eq2: 2x+8y = 8 Divide Eq2 by 2: x+4y = 4 The Eqs are identical and represent the same line. Therefore, we have an infinite number of solutions.
December 23, 2014

Algebra
$X To start with. 1st. Store: Bal. = X - ((X/2)+1) = X - X/2-1 = X/2-1 2nd Store: Bal=X/2-1 - (X/2-1)/2+1 = X/2-1 - X/4+1/2-1 = X/4 - 1/2. 3rd. Store: Bal = X/4-1/2 - (X/4-1/2)/2+1 = X/4-1/2 - X/8+1/4)-1 = X/8 - 1 1/4 = X/8 - 5/4. 4th Store: X/8-5/4 - (X/8-5/4)/2+1 = X/8-5/4...
December 22, 2014

Physics
a. h=ho + (-Vo^2/2g)=100 + (-98^2)/-19.6 = 590 m. b. V = Vo + g*Tr = 0 98 - 9.8*Tr = 0 -9.8Tr = -98 Tr = 10 s. = Rise time. h = 0.5g*t^2 = 590 4.9*t^2 = 590 t^2 = 120.4 Tf = 11 s. = Fall time. Tr+Tf = 10 + 11 = 21 s. = Time to reach gnd. c. V^2 = Vo^2 + 2g*h Vo = 0 g = 9.8 m/s...
December 22, 2014

Physics
Note: The Fall time is not required.
December 22, 2014

Physics
h = 0.5g*t^2 = 4 m. 4.9*t^2 = 4 t^2 = 0.816 Tf = 0.904 s. = Fall time. V1^2 = Vo^2 + 2g*h = 0 + 19.6*4 = 78.4 V1 = 8.85 m/s., Downward. V^2 = V2^2 + 2g*h = 0 V2^2 = -2g*h = -2*(-9.8)*3 = 58.8 V2 = 7.67 m/s, Upward. a = (V2-V1)/t = (7.67-8.85)/0.01 = -118 m/s^2, Upward.
December 22, 2014

physics
F = 200N[30o] Fx = 200*Cos30 = 173.2 N. Fy = 200*sin30 = 100 N. M*g = 30kg * 9.8N/kg = 294 N. = Wt. of the object. a. Fk = u*Fn = u*(Mg-Fy) = 0.2(294-100) = 38.8 N. = Force of kinetic friction. b. a = (Fx-Fk)/M c. V = Vo + a*t Vo = 0 a = Value from part b. t = 5 s. Solve for V.
December 21, 2014

physics
Vs = 50mi/h * 1600m/mi * 1h/3600s = 22.22 m/s. = Velocity of the speedster. a. Ds = Dp 22.2*t = 0.5a*t^2 Divide both sides by t: 0.5a*t = 22.2 0.5*0.450t = 22.2 0.225t = 22.2 t = 98.8 s. b. Ds = Dp = 22.2*t = 22.2 * 98.8 = 2193 m. c. V^2 = Vo^2 + 2a*d Vo = 0 a = 0.450 m/s^2 d...
December 21, 2014

Physics
A 10.0 kg barrel is lifted by pulling up on a rope. The barrel accelerates at 1.50 m/s2. Find the force of tension on the rope.
December 21, 2014

Calculas
V = Vo + g*t Vo = 0 g = 9.8 t = 2.75 s. Solve for V.
December 21, 2014

Science
V = 60km/h = 60,000m/3600s = 16.7 m/s. Work = The change in KE = 0.5*M*V^2 = 0.5*1500*16.7^2 = 209,168 J.
December 21, 2014

Science
V^2 = Vo^2 + 2g*h = 0 Vo^2 = -2g*h = -2*(-9.8)*1000 = 19,600 Vo = 140 m/s.
December 21, 2014

math
a. I = Po*r*t = 5000*(0.09/360)*80 = $100 = Interest. b. V = Po + I = 5000 + 100 = $5100 = Maturity value. c. July 1.
December 18, 2014

business math
Ar = Ab - Ad Ar = 20,000 - 20,000*(0.085/360)*90 = 20,000 - 425 = $19,575 = Amount received (proceeds). Ab = Amt. borrowed. Ad = Amt. discounted.
December 18, 2014

Physics
h = 3.1*sin30 = 1.55 m. a. V^2 = Vo^2 + 2g*h = 0 + 19.6*1.55 = 30.4 V = 5.51 m/s. b. V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d = (0-(5.51^2))/10 = -3.04 m/s^2. M*g = 7.5 * 9.8 = 73.5 N. = Wt. of suitcase. Fp = 73.5*Sin30 = 36.75 N. = Force parallel to the incline. Fn = 73.5*Cos30 = ...
December 18, 2014

physic
250+160+420+F4 = 220+340+180+560 Solve for F4.
December 18, 2014

math
d = r*t = 12 km 3 * t = 12 t = 4 h 1. d = r*t = 12 r * 3 = 12 r = 4 km/h Change = 4 - 3 = 1 km/h = 1 km/h increase. 2. d = r*t = 12 km r * 5 = 12 r = 2.4 km/h. Change = 2.4 - 3 = -0.6 km/h = 0.6 km/h decrease.
December 18, 2014

physics
Vo[0o] Xo = Vo*Cos0 = Vo Yo = Vo*sin0 = 0 Vo[30o] Xo = Vo*Cos30 = 0.87Vo Yo = Vo*sin30 = 0.5Vo Vo[60o] Xo = Vo*Cos60 = 0.5Vo Yo = Vo*sin60 = 0.87Vo
December 17, 2014

Phyiscs
V^2 = Vo^2 + 2g*h Vo = 0 g = 9.8 h = 0.5 m. Solve for V.
December 17, 2014

algebra
(3,63),(5,57), (17,y). m = (57-63)/(5-3) = -6/2 = -3. m = (y-57)/(17-5) = (y-57)/12 = -3/1 y-57 = -36 Y = 57-36 = 21 Inches after 17 days.
December 17, 2014

algebra
What tank?
December 17, 2014

physics
W = Fx*d = 54*Cos10 * 3.4
December 17, 2014

Algebra
Correction: The Eqs are identical(divide the 1st Eq by 4). So we have an infinite # of solutions.
December 17, 2014

Algebra
m1 = -A/B = -16/-8 = 2 m2 = -4/-2 = 2 m1 = m2. So the lines do not intersect. Therefore, there is no solution.
December 17, 2014

physic
V^2 = Vo^2 + 2g*d = 0 + 19.6*50 = 980 V = 31.3 m/s.
December 17, 2014

Algebra 1
2x/3 + y = 7 Multiply both sides by 3: 2x + 3y = 21
December 16, 2014

physics
X = -5.4 m/s. Y = 3.6 m/s. Tan Ar = Y/X = 3.6/-5.4 = -0.66666 Ar = -33.7o = Reference angle. A = -33.7 + 180 = 146.3o = Direction. V = X/Cos A = (-5.4)/Cos146.3 = 6.49 m/s[146.3o].
December 16, 2014

Algebra
1. (-7)(3)-(5)(-3) = -21 - (-15) = -21+15 = -6 2. (x^2+6) - (3x^2-2x-5)=x^2+6-3x^2-2x-5 = =2x^2 - 2x + 1
December 16, 2014

Algebra 2
a. m = -A/B = -2/-5 = 2/5 b. m = -3/2
December 16, 2014

Algebra
Answer = A.
December 16, 2014

Algebra 2
K = y/x = 1/-3 = -1/3. y/x = -1/3 4/x = -1/3 -x = 12 X = -12.
December 16, 2014

Algebra 2
a. Y = 2x - 3 Y = mx - b m = 2 = Slope. b. 3y - 7x = 1? -7x + 3y = 1 m = -A/B = 7/3
December 16, 2014

math
X = Tony's future age. 4x = Mr. Jacob's future age. 4x - x = 55-7 3x = 48 X = 16 4x = 4 * 16 = 64 16-7 = 9 years. 64-55 = 9 years. So Mr. Jacobs will be 4 times as old as Tony in 9 years.
December 16, 2014

Math
D. All real numbers.
December 16, 2014

geography
2+2\4[o]
December 16, 2014

Algebra 1
Y = mx + b Y = 6x - 4
December 15, 2014

Physics
V = Vo + g*t = 16 - 9.8*1.5 = 1.3 m/s. Your answers are correct.
December 15, 2014

physics
a. X = 181*Cos66.2 b. Y = 181*sin66.2
December 14, 2014

physics
V = Vo + a*t = 0 + 231*0.0442 = 10.21 m/s. a. V*Cos A = 10.21*Cos55 = 5.86 m/s. b. 10.21*sin55 = 8.36 m/s.
December 14, 2014

math
X = Footballs sold @ $22 ea. Y = Footballs sold @ $6 ea. Eq1: x + y = 6000 Eq2: 22x + 6y = $76,000 Multiply Eq1 by -6 and add the Eqs: -6x - 6y = -36000 22x + 6y = 76,000 Sum: 16x = 40,000 X = 2500 In Eq1, replace X with 2500: 2500 + y = 6000 Y = 6000-2500 = 3500
December 14, 2014

7th grade math
3. Correct. 9. Correct. 12. X = 305/18 = 16 17/18 13. Correct. 14. C < -12.8 21. Correct. 26. Correct.
December 14, 2014

physics
Fp = Mg*sin50 Fn = Mg*Cos50 Fk = u*Fn = u*Mg*Cos50 Mg*sin50-0.1Mg*cos50 = M*a Divide both sides by M: g*sin50-0.1g*Cos50 = a a = 9.8*sin50-0.98*Cos50 = 6.88 m/s^2.
December 14, 2014

physics
Answer: The object with the greatest momentum. Object A: M*V = 1.9 * 8 = 15.2 kg-m/s Object B: M*V = 2.0 * 5 = 10.0 kg-m/s
December 13, 2014

Physics
Conservation of momentum: (M1+M2)V1/8 = M1*V1-M2*0 Multiply both sides by 8/V1: M1 + M2 = 8M1 3.32 + M2 = 8*3.32 M2 = 8*3.32 - 3.32 = 23.24 kg.
December 12, 2014

Physics
Conservation of momentum: (M1+M2)V = M1*V1-M2*V2 M1 = 4.66 kg M2 = 3.00 kg V1 = 4.77 m/s. V2 = 3.33 m/s. Solve for V.
December 12, 2014

physics
KE2 = KE1 * (V2/V1)^2 KE1 = 5*10^5 J. V1 = 36 mi/h V2 = 115 mi/h Solve for KE2.
December 12, 2014

Science
Vo = 27.4m/s[48o] Xo = 27.4*Cos48 = 18.3 m/s. Yo = 27.4*sin48 = 20.4 m/s. h = 0.5g*t^2 = 860 m. 4.9*t^2 = 860 t^2 = 175.5 Tf = 13.2 s. = Fall time. Dx = Xo*Tf = 18.3m/s * 13.2s = 242.4 m. b. Y = Yo + g*t = 0 + 9.8*13.2 = 129.4 m/s. Tan A = Y/Xo = 129.4/18.3 = 7.07104 A = 82o.
December 12, 2014

Math
P = Po*e^(r*t) e^(r*t) = P/Po r*t = 0.03*10 = 0.30 e^0.3 = P/5 Solve for P. Answer in millions.
December 12, 2014

physics
V = Vo + a*t V = 6.4 m/s. Vo = 0 t = 0.27 s. Solve for a. F = m*a
December 12, 2014

Chemistry
But these are the numbers which have been provided in the question... If u could show me just the way to tackle it, it wud be very helpful,plz.
December 12, 2014

Chemistry
0.250 moles of HCL and 0.100 moles of acetic acid are mixed in 0.365 moles of water. Determine the following: [CH3COOH], [CH3COO^-], pH and pOH. Ka=1.8E-5. Calculate the pH of 0.05M CH3COO-Na+ . Plz show me step by step, really confused right now.
December 12, 2014

physics
V = Vo + a*t V = 20 m/s. Vo = 25.1 m/s. t = 5.7 s. Solve for a. (It should be negative.) F = M*a
December 9, 2014

physics
V^2 = Vo^2 + 2a*d Vo = 0 a = F/m = 196.3/0.39 = d = 1.28 m. Solve for V.
December 9, 2014

physics
Incomplete.
December 9, 2014

math
P = Po + Po*r*t P = 39,995 + 39,995*(0.0249/12)*60 =
December 8, 2014

Physics
a = (F1-F2)/m F1 = 1141 N. F2 = 947 N. M = 2300 kg Solve for a. V^2 = Vo^2 + 2a*d V = 3 m/s. Vo = 0 a: Calculated in step #1. Solve for d in meters. .
December 8, 2014

AP physics
KE = M*V^2/2 KE = 5400 J. M = 2840 kg Solve for V. Units: m/s.
December 8, 2014

physics
a. 30o/h *2h = 60o. b. 360o/h * 2h = 720o. c. 4320o/h * 2h = 8640o
December 8, 2014

Physics
a. d = 0.5a*t^2 = 1.92 m. 0.5a*1.9^2 = 1.92 m 1.81a = 1.92 a = 1.06 m/s^2 b. M*g = 2.84 * 9.8 = 27.8 N. = Wt. of block. Fp = 27.8*sin30 = 13.9 N. = Force parallel to the incline. Fn = 27.8*Cos30 = 24.1 N. = Normal force Fp-Fk = m*a 13.9-Fk = 2.84*1.06 = 3.01 -Fk = 3.01-13.9...
December 8, 2014

Physics
d = 0.5a*t^2 d = 0.79 m. t = 0.64 s. Solve for a. F = m*a
December 8, 2014

physics
See previous post: Sat, 12-6-14, 4:06 PM
December 8, 2014

physics
V^2 = Vo^2 + 2a*d V = 0 Vo = 30 m/s. d = 75 m. Solve for a.(It should be negative). F = m*a. The force will be negative, because it acts against the motion.
December 8, 2014

physics
X m.=Distance the heavier person moves 2x m.= Lighter person distance. x + 2x = 12 3x = 12 X = 4 m.
December 8, 2014

Physics
M*g = 63 * 9.8 = 617.4 N. = Wt. of block Fp = Fs @ critical angle. Mg*sinA = us*Mg*CosA Divide both sides by Mg: sin A = us*Cos A Divide both sides by Cos A: sin A/Cos A = us = 0.47 = Tan A A = 25.2o = The critical angle. Fp = 262.6
December 7, 2014

physics
M*g = 16 N. Solve for g.
December 7, 2014

Physics
PE = M*g*h
December 7, 2014

Math
22n^2 + n - 5 Use AC Method: A*C = 22*(-5) = -110 = -10*11. Select the pair of factors whose sum = B =1: -10, and 11. Form 2 factorable binomials: 22n^2 + (-10n+11n) - 5 (22n^2+11n) - (10n+5) 11n(2n+1) - 5(2n+1) (2n+1)(11n-5)
December 7, 2014

math
See previous post: Sat, 12-6-14, 2:02 PM
December 7, 2014

Physics
V = Vo + a*t V = 0 Vo = 24 m/s t = 0.16 s. Solve for a.(It will be negative) F = M*a
December 7, 2014

ALG 1
12a^4b^3 + 8a^3b^2 = 4a^3b^2(3ab+2). GCF = 4a^3b^2.
December 7, 2014

physics
Incomplete.
December 7, 2014

Physics
X = M1*V1 = 24*3.3 = 79.2 Y = M2*V2 = 33*2.4 = 79.2 1a. Tan A = Y/X = 79.2/79.2 = 1.00 A = 45o = Direction. 1b. Momentum = X/Cos A = 79.2/Cos45 = 112 (M1+M2)*V = 112[45o] (33+24)V = 112[45] V = 1.96 m/s.[45o]
December 7, 2014

problem solving
See previous post: Sun,12-7-14, 1:41 AM.
December 7, 2014

problem solving
Difference = 35 - 0.75*40 = 35 - 30 = 5.
December 7, 2014

problem solving
Cost = Po + 0.05Po = $315 1.05Po = 315 Po = $300 = Initial price. (315-300)/6blks = $2.50/blk 300/(2.50/blk) = 120 Blocks bought.
December 7, 2014

problem solving
400rev/min * 60min/h = 24,000 rev/h. Circumference(C) = 47,520m/24,000rev = 1.98 m/rev C = pi*2r = 1.98 m 6.28r = 1.98 r = 0.315 m = 31.5 cm = Radius of the wheels.
December 7, 2014

problem solving
see 1:52 AM post.
December 7, 2014

Physics
a. d = Xo*Tf = 150 m. 450 * Tf = 150 Tf = 0.333 s. d = 0.5g*Tf^2 = 4.9*0.333^2 = 0.544 m. Below the center.
December 6, 2014

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