Tuesday

September 30, 2014

September 30, 2014

Total # Posts: 9,176

**Physics**

Wb = m*g = 3kg * 9.8N/kg = 29.4 N. = Weight of block. Fp = 29.4*sin37 = 17.69 N. = Force parallel to the incline. Fn = 29.4*cos37 = 25.61 N. = Normal force = Force perpendicular to the incline. Fk = u*Fn = 0.1 * 25.61 = 2.56 N = Fap = 40/cos37 = 50.09 N. Parallel to incline. a...
*May 7, 2014*

**Math**

A = X Ft^2 B = (X+200) Ft^2 C = (X+200) +400 Ft^2 D = (X+200)+400 + 800 AREA = 4x + 600 + 800 + 800 = 4x + 2200 = 4A + 2200 Answer: She must measure Region A, multiply the results by 4, and add 2200 Ft^2.
*May 7, 2014*

**physics**

Mass = 150Lbs * 0.454kg/Lb = 68.1 kg. d = 75Ft * 1m/3.3Ft = 22.73 m. Work = F*d = F * 22.73 = 3813.75 Fn = 3813.75/22.73 = 167.8 N = Net force a = Fn/mass = 167.8/68.1 = 2.46 m/s^2 Vo = 1Ft/s * 1m/3.3Ft = 0.303 m/s = Initial velocity. V^2=Vo^2 + 2a*d=0.303^2 + 2*2.46*22.73 = ...
*May 7, 2014*

**Science**

Ct = 10uF/3 = 3.33 uF. Qt = Q1 = Q2 = Q3 = Ct*V = 3.33 * 100 = 333 Micro coulombs.
*May 7, 2014*

**science**

Wt = m * g. So the wt. decreases with distance.
*May 7, 2014*

**Physics**

See 10:24 PM post.
*May 6, 2014*

**Physics**

a = F/m = 65/0.075 = 867 m/s^2. V^2 = Vo^2 + 2a*d = 0 + 2*867*.9 = 1560 V = 39.5 m/s.
*May 6, 2014*

**Math!!**

-3(-9)+(3 + (2*5^2)) = 27 + (3 + (2*25)) = 27 + (3 + 50) = 27 + 53 = 80.
*May 6, 2014*

**algebra**

Glad I could help.
*May 6, 2014*

**algebra**

25 = (1/5)^-2 25 = 1/(1/5)^2 25 = 1/(1/25) 25 = 1 * 25/1 25 = 25
*May 6, 2014*

**math**

1. V = L*W*h = 3 1/2 * 1 1/2 * 2 = 7/2 * 3/2 * 2/1 = 42/4=10.5 cubic units. 2. 8 Cubes. 4. V = 1 * 1 * 1 = 1 Gubic units. 3.
*May 6, 2014*

**physics**

Work = F * d. Therefore,increasing the force or distance increases the amount of work done.
*May 5, 2014*

**Physics URGENT!!!!!!!!!!!!**

See previous post: 5-5-14, 11:42 AM.
*May 5, 2014*

**Physics URGENT!!!!!!!!!!!!**

Fr = ((Vs-Vr)/(Vs+Vb))*Fb Fr = ((343-0)/(343+Vb))*80 = 76 kHz (343/(343+Vb))*80 = 76 27,440/(343+Vb) = 76 26,068+76Vb = 27,440 76Vb = 27440 - 26,068 = 1372 Vb = 18 m/s. = Velocity of the bat. The bat is receding, because the freq. heard is lower than the freq. emitted by the ...
*May 5, 2014*

**physics**

Vt=120000m/h = 120000m/3600s = 33.33 m/s Fp = ((Vs+Vp)/(Vs-Vt))*Ft Fp = ((343+0)/(343-33.33))*600 Hz Fp = (343/309.7)*600 = 664.6 Hz = Freq. heard by the person. L = Vs/Fp = 343/664.6 = 0.516 m. = Wave- length.
*May 5, 2014*

**MATHS - FRACTION**

To add or subtract fractions, they must have the same denominator. The fraction that is being subtracted must be smaller than the other fraction. Given: 3 1/3 - 1 3/4 Step 1. Find a common denominator: 3 4/12 - 1 9/12 Step 2. Subtract 1(1=12/12) from 3 and add it to 4/12: 2 16...
*May 5, 2014*

**Physics question**

Yes.
*May 4, 2014*

**Physics**

a.KE = 0.5m*V^2 = 0.5*1.4*8.5^2=50.6 J. b. V^2 = Vo^2 + 2g*d V^2 = 8.5^2 + 19.6*37 = 725.2 V = 26.9 m/s. c. 0.5m*V^2 = 3600 J. .5*1.4*V^2 = 3600 0.7V^2 = 3600 V^2 = 5143 V = 71.7 m/s. When it hits the gnd. V^2 = Vo^2 + 2g*h Vo^2 = V^2-2g*h Vo^2 = (71.7)^2 - 19.6*37 = 4416 Vo...
*May 4, 2014*

**Physical science**

V = 25 * 10 * 1.5 = 375 m^3 375m^3 * 1000kg/m^3 = 375,000 kg.
*May 4, 2014*

**physics**

R1 = 9.0 ohms R2 = 53 ohms I1 = 1.41 Amps = current thru R1. V = I1 * R1 = 1.41 * 9 = 12.69 Volts. = voltage across battery.
*May 3, 2014*

**Math**

To find y-intercepts, let x = 0 and solve for Y. 1. 2x = 3y+4 2x-3y = 4 m = -A/B = -2/-3 = 2/3. 2*0-3y = 4 -3y = 4 Y = -4/3 = y-int. 2. 8x-2y-3 = 0 8x-2y = 3 Use same procedure as #1.
*May 3, 2014*

**math**

The following INFO is needed: h = ? W = ?
*May 3, 2014*

**math**

10-5c = 20c-40-18c-6 -5c-20c+18c = -40-6-10 -7c = -56 C = 8. 1.25y-.5y = -11.5+20.5 0.75y = 9 Y = 12 Divide both sides by 3: 7p-3q = 23.
*May 3, 2014*

**math**

NOTE: Disregard the last expression. The answer is 241i.
*May 3, 2014*

**math**

1. 5[19+(5^2-16)^2]^2 5[19+(9)^2]^2 5[100]^2 = 50,000 2. (7m^3-6m^2+10)-(5m^3-9+3m-2m^2) = 7m^3-6m^2+10-5m^3+9-3m+2m^2 = Combine like-terms: 2m^3-4m^2-3m+19 3. 3(a-2)(4a+1)-5(2a+3)(a-7) = 3(4a^2+1-8a-2)-5(2a^2-14a+3a-21) = 12a^2+3-24a-6-10a^2+70a-15a+105 = Combine like-terms: ...
*May 3, 2014*

**Science**

1b. 2c.
*May 3, 2014*

**MATH(markup and markdown )**

Po = $7,000 = Original price. P1 = 100% - 8% = 92% of Po P1 = 0.92 * 7000 = $6,440 = Resale price P2 = 100% + 18% = 118% 0f P1. P2 = 1.18 * 6440 = $7599.20=List price.
*May 2, 2014*

**MATH(markup and markdown )**

P1 = 100%-19% = 81% of original price. P1 = 0.81 * 15 = $12.15. = Sale price. P2 = 100%-5% = 95% of P1. P2 = .95 * P1 = .95 * 12.15 = $11.54 = Final sale price.
*May 2, 2014*

**Physics**

F1 = 512 - 20/4 = 507 Hz. F2 = 512 + 20/4 = 517 Hz.
*May 2, 2014*

**Physics (URGENT!!!)**

See previous post: Fri,5-2-14,2:37 AM.
*May 2, 2014*

**Calculus/Physics**

W = F*d = F * (5-2) = 1800 Joules. 3F = 1800 F = 600 N. k = 600N./3m = 200N/m
*May 2, 2014*

**Physics**

TYPO: Change Y = Yo*g*Tr = 0 to Y = Yo + g*Tr = 0
*May 2, 2014*

**Physics**

Vo = 120m/s[30o] Xo = 120*cos30 = 103.9 m/s. Yo = 120*sin30 = 60 m/s. a. Y = Yo * g*Tr = 0 Tr=-Yo/g = -60/-9.8 = 6.12 s. = Rise time. h = ho + (Y^2-Yo^2)/2g h = 35 + (0-(60^2))/-19.6 = 218.7 m. Above gnd. h = 0.5g*t^2 = 218.7 4.9t^2 = 218.7 t^2 = 44.63 Tf = 6.68 s. = Fall time...
*May 2, 2014*

**Science**

Work = 200*cos37 * 10 = 1597 Joules.
*May 1, 2014*

**math**

P = Po(1+r)^n Po = $3250. r = 6%/100% = 0.06 n = 1Comp./yr * 3.5yr. = 3.5 Compounding periods. Plug the above values into the given Eq and solve for P.
*May 1, 2014*

**physics**

Correction: R1 = R2 = R3 = 27/3 = 9 Ohms, each. When connected in parallel: Re = 9/3 = 3 Ohms.
*May 1, 2014*

**physics**

R = 27Ohm/3 = 9 Ohms. r =
*May 1, 2014*

**4th Grade Math**

6/8 = 3/4 (3/4) * 32 = 24 Teeth had cavities. 32 - 24 = 8 Healthy teeth.
*May 1, 2014*

**4th Grade Math**

2/8 = 1/4 (1/4)*64 = 16 Blue shirts. 64-16 = 48 Shirts not blue.
*May 1, 2014*

**Physics**

R1 = 16 Ohms R2 = 8 Ohms Re = R1*R2/(R1+R2)
*April 30, 2014*

**Math**

P = Po - Po*r*t P = 300 - 300*(0.17/12)*8 = $266.
*April 30, 2014*

**Math**

P = Po + Po*r*t = 500 Po + Po*(0.08/12)*9 = 500 Po + 0.06Po = 500 1.06Po = 500 Po = $471.70
*April 30, 2014*

**Geometry**

A(x,y), B(-24,15), C(-18,10). -18-x = 2(-24-x) -18-x = -48-2x 2x-x = -48+18 X = -30 10-y = 2(15-y) 10-y = 30-2y 2y-y = 30-10 Y = 20.
*April 30, 2014*

**Algebra**

15x^2 + 31x + 2 A*C = 15*2 = 30 = 1*30. Sum = 1+30=31=B. 15x^2 + (x+30x) + 2 Form 2 factorable binomials: (15x^2+x) + (30x+2) = x(15x+1) + 2(15x+1) = (15x+1)(x+2).
*April 30, 2014*

**Math**

The numerator: Are you sure that's a +2 ? Perhaps it should be -2. Please check.
*April 30, 2014*

**physics**

V = Vo + a*Tr = 0 @ max. ht. Tr = -Vo/a = -5/-10 = 0.5 s. = Rise time or time to reach max. ht. h = Vo*t + 0.5a*Tr^2 = 5*0.5 - 5*0.5^2 = 1.25 m.
*April 30, 2014*

**Science**

F = m*a
*April 30, 2014*

**Math**

V = (L*W) * h = (650)Ft^2 * 0.25Ft = 162.5 Ft^3. V = 162.5Ft^3 * 1yd^3/27Ft^3 = 6 yds^3
*April 30, 2014*

**Math**

V = L*W*h = 36 * 18 * 0.25 = 162 Ft^3 V = 162Ft^3 * 1yd^3/27Ft^3 = 6 Yds^3.
*April 30, 2014*

**Math**

V = pi*r^2 * L = pi * (0.5/12)^2 * 12 = 5.45*10^-3 Ft^3. = Vol. of rod. Wt.=490Lbs/Ft^3 * 5.45*10^-3Ft^3 = 2.67 Lbs.
*April 30, 2014*

**physics**

d = V*t = 343m/s * (1.6s/2) = 274.4 m.
*April 30, 2014*

**Science**

g on Jupiter is 2.5 times g on earth. 100/2.5 = 40 Lbs.
*April 30, 2014*

**physics**

What direction is the airplane flying?
*April 30, 2014*

**Science**

F = m*a = 5 * 7 = 35 N.
*April 29, 2014*

**Engineering**

Was the current given?
*April 29, 2014*

**Physics**

100 Cars: db = 10*Log(I/Io) db = 10*Log(I/10^-12) = 80 Log(I/10^-12) = 8 10^8 = I/10^-12 I = 10^-4 W/m^2. 5 Cars: I = (5/100) * 10^-4 = 5*10^-6 W/m^2. db = 10*Log(5*10^-6/10^-12) db = 10*Log(5*10^6) = 67.
*April 29, 2014*

**Govt college of technology**

Correction: Change 6 cm to 12 cm. The results does not change.
*April 29, 2014*

**Govt college of technology**

Circumference = pi*2r = pi * 6cm = 37.7 cm d = 300rev/min * 37.7cm/rev * 0.5min = 18.85 cm. Note: 0.5 min = 30 sec.
*April 29, 2014*

**Science**

F = m * a
*April 29, 2014*

**Math -Help**

X Crocus bulbs. Y Daffodil bulbs. Eq1: X + Y = 100 Eq2: 0.45x + 0.85y = $55.80 Multiply Eq1 by (-0.85) and add the Eqs: -0.85x - 0.85y = -85 +0.45x + 0.85y = 55.80 Sum: -0.40x = -29.2 X = 73 In Eq1, replace X with 73: 73 + Y = 100 Y = 27
*April 29, 2014*

**Math! Helppppp**

Two rt. triangles are formed with the ropes representing 7he hyp. of the triangles. The smaller Triangle: m = TanA = Y/X = 8/16 = 0.50 The Larger Triangle: m = TanA = Y/X = 16/16 = 1.00
*April 29, 2014*

**Physics**

Vo = 41.8m/s[30o] Xo = 41.8*cos30 = 36.2 m/s. Yo = 41.8*sin30 = 20.9 m/s. Y = Yo + g*Tr = 0 @ max. ht. Tr = -Yo/g == -20.9/-9.8 = 2.13 s. = Rise time. Tf = Tr = 2.13 s. = Fall time. Range = Xo*(Tr+Tf) = 36.2m/s * 4.26s = 154.4 m.
*April 29, 2014*

**Physics**

Correction: Change Tf = Yr to Tf = Tr.
*April 29, 2014*

**Physics**

Vo = 70m/s[15o] Xo = 70*cos15 = 67.61 m/s. Yo = 70*sin15 = 18.12 m/s. a. Y = Yo + g*Tr = 0 @ max ht. Tr=-Yo/g = -18.12/-1.63 = 11.12 s.=Rise time. Tf = Yr = 11.12 s. = Fall time. Tr+Tf = 11.12 + 11.12 = 22.24 s. = Time in flight. b. Range = Xo * (Tr+Tf) = 67.61 * 22.24 = 1504 m.
*April 29, 2014*

**physics**

Vc = Vo + a*(T-To)Vo Vc=548 + 12*10^-6*(10)*548 = 548.06576 cm^3 = Volume of container after 10oC increase in temperature. V = 548 + 7*10^-4*(10)*548 = 551.836 cm^3. = Volume of the oil after a 10oC increase in temperature. Vs = 551.836 - 548.06576 = 3.77 cm^3 = Volume spilled.
*April 28, 2014*

**Math Help**

Where is the Eq?
*April 28, 2014*

**physics**

Correction: Change V^@ to V^2.
*April 28, 2014*

**physics**

V^@=Vo^2 + 2g*h = 0 + 19.6*7.15 = 140.14 V = 11.84 m/s.
*April 28, 2014*

**Physics**

See Fri,5-2-14,2:17 AM post.
*April 28, 2014*

**Math 120**

T1 = Time for stone to hit bottom. T2 = Time for sound to reach top of well T1 + T2 = 17 s. T1 = 17-T2 0.5g*(17-T2)^2 = Vs*T2 4.9(289-34T2+T2^2) = 343T2 1416-167T2+4.9T2^2 = 343T2 4.9T2^2-510T2+1416 = 0 Use Quadratic formula and get: T2 = 2.85 s. T1 = 17-2.85 = 14.15 s. d = Vs...
*April 27, 2014*

**Physics**

Va = Ia*Ra = 2*10^-3 * 50 = 0.10 Volts = Voltage across ammeter @ full-scale. Rp=Va/I = 0.1/(40-2)*10^-3=0.1/38*10^-3= 2.632 Ohms. = Resistor connected in parallel with the ammeter to extend current range to 40 mA. Voltmeter: Rs = (V-Va)/If = (14-0.10)/2*10^-3=6,950 Ohms = The...
*April 27, 2014*

**science**

F = m*a
*April 25, 2014*

**physics**

No, the mass does not change. Yes, they weigh less on the moon; because g is 9.8 on earth but only 1.63 on the moon.
*April 25, 2014*

**physics**

Mass = 0.45kg/Lb * 160Lbs. = 72 kg. Wt. = m*g = 72kg * 9.8N./kg = 705.6 N. on Earth. Wt. = 705.6N/6 = 117.6 N. on the moon.
*April 25, 2014*

**finance**

Compounded Annually? P = Po(1+r)^25 = 45,000(1+0.07)^25 = $244,234.47 Simple Interest: P = Po + Po*r*t = 45,000 + 45000*0.07*25 = $123,750.
*April 24, 2014*

**science**

a = 3m/s^2 = (3m/s)/s.
*April 24, 2014*

**math**

P = Po(1+r)^n PO = $1,000 r = (8%/4)/100% = 0.02 n = 4comp./yr. * 1yr. = 4 Compounding periods. Plug the above values into the given Eq and solve for P. I = P-Po
*April 24, 2014*

**Physics ATTENTION HENRY!**

a.V^2 = X^2 + Y^2 = 0.8^2 + 1.2^2 = 2.08 Vs = 1.442 m/s. = Resultant velocity of the swimmer. Tan A = 0.8/1.2 = 0.66667 A = 33.7o E. of N.(N33.7E). d1 = 550m/cos33.7 = 661.1 m[N33.7E] = Dist. to other side. T1 = d1/Vs = 661.1/1.442 = 458.5 s. To reach other side. d2 = 550*Tan ...
*April 24, 2014*

**math**

P = Po(1+r)^n r = (14%/2)/100% = 0.07 = Semi-annual % rate expressed as a decimal. n = 2comp./yr. * 2.5yrs. = 5 Compounding periods. P = Po(1+0.07)^5 = $20,000 Po = 20000/1.07^5 = $14,259.72 I=P-Po = 20,000 - 14,259.72 = $5,740.28
*April 24, 2014*

**math**

See previous post: Thu,4-24-14,6:24 AM.
*April 24, 2014*

**math**

Same procedure as your 6:24 AM post.
*April 24, 2014*

**math**

P1 = Po(1+r)^n Po = $5,000 r = (6%/2)/100% = 0.03 = Semi-annual % rate expressed as a decimal. n = 2comp./yr * 2yrs. = 4 Compounding periods. P1 = 5000(1+0.03)^4 = $5627.54 after 2 years. P2 = P1(1+r)^n r = (8%/4)/100% = 0.02 = Quarterly % rate expressed as a decimal. n = ...
*April 24, 2014*

**math(compunded interest )**

a. P = Po(1+r)^n Po = $19,999 r = (4.5%/6)/100% = 0.0075 n = 6comp./yr. * 2yrs. = 12 Compounding periods. Solve for P. b. P = Po(1+r)^n Po = $120,000 r = (5.75%/12/100% = 0.00479 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 3.25yrs. = 39 Compounding periods. ...
*April 24, 2014*

**physics**

Re = 6*(6+6)/(6+6+6) = 6*12/18 = 72/18 = 4 Ohms.
*April 23, 2014*

**geometry**

h = Vm^3/pi*(dm/2)^2 = Vm^3/pi*dm^2/4 = Vm^3 * 4/pi*dm^2 = 4Vm/pi*d = 4Vm/3.14d = 1.27Vm/d = 1.27V/d Meters.
*April 23, 2014*

**Physcs**

Vp = 300km[135o]/0.75h = 400 km/h[135o] Without the wind. Vp + Vw = 400km/h[135] = -282.84+282.84i Vp - 80i = -282.84 + 282.84i Vp = -282.84 + 282.84i + 80i Vp = -282.84 + 362.8i=460.4km/h[128o] = 460.4km/h[38o] W. of N. With the wind blowing.
*April 23, 2014*

**physics**

Fb = m*g = 225kg * 9.8N/kg = 2205 N. = Force of box. = Normal force. Fk = u*Fn = 0.20 * 2205 = 441 N. = Force of kinetic friction. a=(Fap-Fk)/m = (2205-441)/225=7.84 m/s^2
*April 23, 2014*

**Physics**

FRICTION is the force that opposes motion.
*April 23, 2014*

**physics**

F1 + F2 + F3 = 0 1800N[75o] + 1800N[294o] + F3 = 0 1800*cos75+i1800*sin75 + 1800*cos294+i 1800*sin294+F3 = 0, 465.87+i1738.7 + 732.1+i(-1644)+F3 = 0 1198 + i94.7+F3 = 0 F3 = -1198 - i94.7 = -1202 N.[4.52o] Tan Ar = -94.7/-1198 = 0.07905 Ar = 4.52o = Reference angle. A = 4.52...
*April 23, 2014*

**finance**

P = Po(1+r)^n Po = $11,000 r = (3%/4)/100% = 0.0075 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 9yrs. = 36 Compounding periods. Plug the above values into the given Eq and solve for P(principal).
*April 23, 2014*

**math**

P = Po(1+r)^n Po = $7700 Compounded Quarterly? r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4 comp./yr. * 5yrs = 20 Compounding periods. Plug the above values into the given Eq and get P = $10,370.78. I = P-Po
*April 22, 2014*

**physics**

V^2 = Vo^2 + 2g*h = 0 + 19.6*2 = 39.2 V = 6.26 m/s.
*April 22, 2014*

**Physic**

a. Impulse = 0.135*(36+47) = 11.2 b. a = (V2-V1)/t a = (47-(-36))/7*10^-4 = 118,571 m/s^2. F = m*a = 0.135 * 118,571 = 16,007 N.
*April 22, 2014*

**Physics**

See previous post: Mon,4-21-14,2:27 PM.
*April 22, 2014*

**Physics**

d1 = d2 0.5a*t^2 = 25t 0.5a*t = 25 0.5*0.004t = 25 t = 12,500 s. = 3.5 h.
*April 22, 2014*

**Physics**

See previous post: Mon,4-21-14,2:27 PM.
*April 22, 2014*

**physics**

h = 0.5g*t^2 = 10,000 Ft. 16t^2 = 10,000 t^2 = 625 Tf = 25 s. = Fall time. V*Tf = 2.09 miles. V * 25s = 2.09 V = 0.0836 mi/s * 3600s/h = 301 mi/h.
*April 22, 2014*

**Inverse Trig**

Y = arcsin1 = The angle whose sine is 1= 90o.
*April 21, 2014*

**Physics**

V=d/t = 300/0.75=400 km/h[135o]. Without wind. V = 400[135] + 80[270o] X == 400*cos135 = -282.8 km/h. Y = 400*sin135 + 80*sin270 = 202.8 km/h. Tan Ar = Y/X = 202.8/-282.8 = -0.71727 Ar = -35.65o = Reference angle. A = -35.65 + 180 = 144.3o V = X/cosA = -282.8/cos144.3 = 348 km...
*April 21, 2014*

**Physics**

Vp + Vw = 200kn/h[90o] Vp + (-50) = 200i Vp = 50 + 200i = 206.2km/h[76o]
*April 21, 2014*

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