Friday

February 24, 2017
Total # Posts: 13,209

**castor financial math**

Ar = Ab-I = 380 - 11.40 = $368.60 = Amt. received or proceeds.

*October 26, 2016*

**castor financial math**

I = Ab*r*t = 380*(0.18/360)*60 = $11.40

*October 26, 2016*

**physics**

Fn = M*g-F*sin30 = Normal force. Fk = uk * Fn = uk*(M*g-F*sin30).

*October 26, 2016*

**science**

Density = 50g/20cm^3 = 2.5 g/cm^3. The substance will sink, because its' density is greater than the density of water.

*October 26, 2016*

**value**

See Related Questions: Mon, 12-21-15, 10:38 AM.

*October 25, 2016*

**bus math**

Ar = Ab - I. Ar = Ab - Ab*r*t. Ar = 2900 - 2900*(0.0625/360)*180 = Amt. received. Ab = Amt. borrowed.

*October 25, 2016*

**Physics**

See previous post: Sat., 10-22-16, 11:54 AM.

*October 24, 2016*

**Physics**

V^2 = 19.6, V = 4.43 m/s.

*October 24, 2016*

**Physics**

V^2 = Vo^2 + 2g*h. V^2 = 0 + 19.6*1 =

*October 24, 2016*

**physics projectile**

See previous post: Mon, 10-24-16, 5:42 PM.

*October 24, 2016*

**physics Projectiles**

1. See Previous post: Mon, 10-24-16, 5:42 PM. 2. Vo = 50m/s a. A = 45o for max. range. b. R = Vo^2*sin(2A)/g.

*October 24, 2016*

**Math**

Z = k * xy. 2.4 = k * 3*2, k = 0.4. Z = 0.4xy.

*October 24, 2016*

**physics projectiles**

Vo = 20m/s[30o]. Xo = 20*Cos30 = 17.32 m/s. Yo = 20*sin30 = 10 m/s. a. Y = Yo + g*Tr. 0 = 10 -9.8Tr, Tr = 1.02 s. = Rise time. Tf = Tr = 1.02 s. Tr+Tf = 1.02 + 1.02 = 2.04 s. = Time in flight. b. h = Yo*Tr + 0.5g*Tr^2. h = 10*1.02 - 4.9*1.02^2 = c. Range = Xo*(Tr+Tf)= 17.32*2....

*October 24, 2016*

**Physics**

Vo = 44rev/min. * 6.28rad/rev * 1min/60s. = 4.61 rad/s. V^2 = Vo^2 + 2a*D. 0 = 4.61^2 - 2.6D, D = ?.

*October 24, 2016*

**Science**

P = V*I = 120 * 6 = R = V/I = 120/6 =

*October 24, 2016*

**physics**

See Related Questions: Fri, 2-7-14, 2:59 AM.

*October 24, 2016*

**physics**

See Related Questions: Thu, 1-22-15, 6:20 PM.

*October 23, 2016*

**Math**

400mg = 0.400g = 4.00*10^-4 kg. 1 tonne = 1000kg. 1000/4*10^-4 = 2.5*10^6 = 2.5 Million buttons.

*October 23, 2016*

**Science**

Density = 85g/100cm^3 = 0.85g/cm^3.

*October 23, 2016*

**math**

Gordon: 4*t = 50, t = 12.5 s. Maria: d = 1m/s * 12.5s = 12.5 m. Difference = 50-12.5 = 37.5 m. Gordon beats her by 37.5 m.

*October 23, 2016*

**Physics**

Vo = 17rev/min. * 6.28rad/rev * 1min/60s = 1.78 rad/s. V = Vo + a*t. 0 = 1.78 - 2.2*t, t = ?.

*October 22, 2016*

**science**

a. Va = 120rev/min. * 6.28rad/rev * 1min./60s = 12.56 rad/s. b. C = pi*2r = 3.14 * 20cm = 62.8 cm = 0.628 m.= Circumference. V = 120rev/min * 0.628m/rev * 1min/60s = 1.256 m/s.

*October 22, 2016*

**Physical**

V = Vo + a*t = 14 - 7*1 = 7 m/s. V^2 = Vo^2 + 2a*d. 7^2 = 14^2 - 14*d, d = ?.

*October 22, 2016*

**PHYSIC**

a. Dx = Xo*t. t = Dx/Xo = 20/300 = 0.067 s. Dy = 0.5g*t^2 = 4.9*0.067^2 = 0.022 m. b. t = d/Vo = 40/300 = 0.133 s. Dy = 4.9*0.133^2 = 0.087 m. c. t = Dx/Vo = 80/300 = 0.267 s. Dy = 4.9*0.267^2 = 0.348 m. d. Dy = 4.9*1^2 = 4.9 m.

*October 22, 2016*

**Physics**

Yes. In fact, the resultant can be zero.

*October 22, 2016*

**Physics**

F1 = 100[30o] N. of E. = [30o]CCW. F1 + F2 = 0. 100[30] + F2 = 0. 100*Cos30 + (100*sin30)i + F2 =0. 86.6 + 50i + F2 = 0. F2 = -86.6-50i(Q3) = 100[30o] S. of W. = 100[210o] CCW from +x-axis. 210o - 30o = 180o. So the two vectors are 180o out of phase. Therefore, point in ...

*October 22, 2016*

**Physics**

See previous post: Fri, 10-21-16, 11:02 PM.

*October 22, 2016*

**Physics**

If F1 + F2 = 0, They must be equal in magnitude and opposite in direction. They cannot have different magnitudes(lengths). If F1 and F2 are unequal, a third force may be added to give a sum of zero. However, the third force must be equal to the sum of the first two and ...

*October 21, 2016*

**Math**

P = Po(1+r)^n. n = 1comp./yr * 3yrs = 3 Compounding periods. P = 2000(1+.03)^3 = $2,185.45.

*October 21, 2016*

**math**

a. Y = kx 72 = k*6, k = 12. Eq: Y = 12x. b. Y = 12 * 10 = 120.

*October 21, 2016*

**Physics**

F2 = (Vs_Vr)/(Vs+Vg) * F1. F2 = (340-0)/340+2.3) * 74 = 73.5 Hz. Fb = F1-F2 = 74 - 73.5 = 0.5 Hz.

*October 21, 2016*

**Physics**

V = 100km/h = 100,000m/3600s = 27.78 m/s. KE = 0.5M*V^2 = 500 * 27.78^2 = 385,802 J. = KE of the auto. 0.5M*V^2 = 385,802. 25*V^2 = 385,802, V = ?.

*October 20, 2016*

**Math**

P = Po*r*t/(1-(1+r)^-t). Po = 07 * 49,500 = $34,650 Financed. r = 0.12/12 = 0.01/mo. t = 2.5yrs * 12mo/yr. = 30 mo. P = (34,650*0.01*30)/(1-(1.01)^-30) = 10,395/0.25807708 = $40,278.66 = Total amt. paid. 40,278.66/30mo. = $1342.62 /mo. 0

*October 20, 2016*

**math**

Correction: The plane is not a free-fall object. a. d = Yo*t. 10,000 = 140*t, t = ?. b. 16,000 = 140*t, t = ?.

*October 20, 2016*

**math**

Vo = 345Ft/s[24o]. Xo = 345*Cos24 = 315 Ft/s. Yo = 345*sin24 = 140 Ft/s. Y^2 = Yo^2 + 2g*h. 0 = 140^2 - 64*h. h = 306.25 Ft., max. Based on the information given, the plane can reach a maximum ht. of only 306 Ft.

*October 20, 2016*

**science**

Efficiency = Output/Input. High friction lowers the output and causes mechanical efficiency to be lowered.

*October 20, 2016*

**physics**

Vo = 80m/s[30o]. Xo = 80*Cos30 = 69.3 m/s. Yo = 80*sin30 = 40 m/s. a. Y = Yo + g*Tr. 0 = 40 - 9.8Tr, Tr = 4.08 s. = Rise time. h = Yo*Tr + 0.5g*Tr^2. h = 40*4.08 -4.9*4.08^2 = 81.6 m. b. Tf = Tr = 4.08 m/s. = Fall time. Tr+Tf = 4.08 + 4.08 = 8.16 s. = Time in air. c. Range = ...

*October 20, 2016*

**Math**

Sign: W = 22/36 * 52 = 32. Ab/As = (36*52)/(22*32) = 2.68. Or Ab/As = (36/22)^2 = 2.68.

*October 20, 2016*

**Physics**

See previous post: Tue, 10-18-16, 8:27 AM.

*October 20, 2016*

**Physics**

M*g = 12*9.8 = 117.6 N. = Wt. of the object. Fp = 117.6*sin56 = 97.5 N. = Force parallel to the slope. a. Work = Fp*d = 97.5 * 34 = 3315 J.

*October 20, 2016*

**Physics**

1. M1*V1 + M2*V2 = M1*V + M2*V. 600*30 + 900*0 = 600V * 900V, 18000 = 1500V, V = 12 m/s. 2. V = Vo + a*t. 12 = 30 + a*0.15, a = -120 m/s^2. F = M*a = (M1+M2)*a = 1500 * (-120) = -180,000 N. The negative sign means the force opposed the motion. 3. a = -120 m/s^2.

*October 20, 2016*

**Maths**

X = Smaller number. x+4x = 5x = Larger number. 5x-x = 24. X = 6, 5x = 30.

*October 19, 2016*

**physic**

Density = (80-25)g/500mL = 0.11g/mL.

*October 19, 2016*

**math**

X adults. 4x children. x + 4x = 300. X = 60 Adult seats. 4x = 4*60 = 240 Children seats.

*October 19, 2016*

**Math**

Cathy had $X. x - x/5 - x/4 - 120 = 540. x - 4x/20 - 5x/20 - 120 = 540, 20x - 4x - 5x - 2400 = 10,800, 11x = 13,200, X = $1200.

*October 18, 2016*

**Math**

The opposite angles are equal: A = C = 2x+25, B = D = 3x-5. 2(2x+25) + 2(3x-5) = 360. 4x+50 + 6x-10 = 360, X = 32. A = C = 64+25 = 89o, B = D = 96-5 = 91.

*October 18, 2016*

**physics**

a. M*g = 50 * 9.8 = 490 N. = Wt. of sled = Normal force(Fn). Fs = us*Fn = 0.3 * 490 = 147 N. Fap-Fs = M*a. Fap = M*0 + 147 = 147 N. b. Fk = uk*Fn = 0.10 * 490 = 49 N. Fap = M*0 + 49 = 49N.

*October 18, 2016*

**Physics**

V = Vo + a*t. 78 = 0 + a*0.04, a = 1950 m/s^2, F = M*a = 0.145 * 1950 = 283 N.

*October 18, 2016*

**Physics**

See previous post: Tue, 10-18-16, 4:43 AM.

*October 18, 2016*

**Physics**

M1V1 + M2V2 = M1V + M2V. 14866*5-14866*5 = 14866V+14866V, V = 0.

*October 18, 2016*

**Math**

a. L = 120yds * 3ft./yd = 360 Ft. W = 53 1/3yd * 3ft/yd = 160 Ft. b. Length = 2L + 2W = 2*360 + 2*160 = 1040 Ft. = Perimeter. c. 5,280Ft/mi * 1Lap/1040Ft = 5.1 Laps/m1. or 5.1 Laps = 1 mile.

*October 18, 2016*

**physics**

M1*V1 = M2*V2. 84*V1 = 28000*1, V1 = 333.3 mi/h.

*October 18, 2016*

**physics**

Fr = 25[120o] + 18[0o]. Fr = (25*Cos120+18) + (25*sin120)i. Fr = 5.5 + 21.65i = 22.3N[75.7o] = The resultant force. Fr is 75.7o N. of the 18N. force.

*October 18, 2016*

**physics**

PE = M*g * h = 63*9.8 * 7.6 = 4692 J. KE = 0.5M*V^2 = 0.5 * 63 * 3.2^2 = 323 J. 4692 - 323 = 4369 J. loss.

*October 17, 2016*

**physics**

Correction: Fap-Fs = M*a. Fap = M*0 + 150 = 150 N. = Force applied. Work = Fap*d = 150 * 7 = 1050 J.

*October 17, 2016*

**physics**

Fap-Fc-Fs = M*a. Fap-550-150 = M*0 = 0, Fap = 700 N. = Force applied. W0rk = Fap*d = 700 * 7.0 = 4900 J.

*October 17, 2016*

**8th pre algebra**

solve for x 2x-7=13 subtract 7 to both sides divide by 2 both sides x=10..am i right?

*October 17, 2016*

**MATH (Celcius/Fahrenheit)**

F = 1.8C + 32 = 1.8*15 + 32 =

*October 17, 2016*

**Physics**

A. = PE = Mg*h = 1.8*9.8 * 1.95 = B. PE = 1.8*9.8 * 1.55 =

*October 16, 2016*

**Physics**

h = 0.5g*t2 = 4.9*1.3^2 =

*October 16, 2016*

**Physics**

28o W. of N. = 118o CCW from +x-axis. 16o E. of N. = 74o CCW from +x-axis. T1*Cos118 = -T2*Cos74. T1 = -T2*Cos74/Cos118 = 0.587T2. T1*sin118 + T2*sin74 = -(-46), 0.883T1 + 0.961T2 = 46, 0.883(0.587T2) + 0.961T2 = 46, 0.518T2 + 0.961T2 = 46, T2 = 31.1 N. T1 = 0.587*T2 = 0.587*...

*October 16, 2016*

**maths fraction**

X pupils in class. X/2 girls in class. X/2 boys in class. 3/8 * X/2 = 3x/16 Girls wear glasses. 1/4 * X/2 = x/8 Boys wear glasses. 3x/16 + x/8 = 3x/16 + 2x/16 = 5x/16 Pupils wear glasses. (5x/16)/X = 5/16 of the pupils wear glasses. .

*October 16, 2016*

**Phyics**

V = 1.7m/s[41o]. d = 1.7m/s * 437s *sin41 = 487.4 m.

*October 15, 2016*

**Physics**

Disp. = 21 + 34m[32o]. Disp. = (21+34*Cos32) + (34*sin32)i = 49.8 + 18.0i. Disp. = sqrt(49.8^2+18^2)

*October 15, 2016*

**math**

Tan A = 5m/12m, A = 22.6o. Cos22.6 = 3.4/V, V = 3.68 m/min.

*October 15, 2016*

**science**

R. Density = 750/1000 = 0.75.

*October 15, 2016*

**math**

20-6(2+1) = 2.

*October 14, 2016*

**Physics**

M*g = 100 * 9.8 = 980 N. = Wt. of crate = Normal force(Fn). Fs = us*Fn = 0.4 * 980 = 392 N. = Force of static friction. The crate does not move, because the applied force is less than the fore of static friction(Fs).

*October 14, 2016*

**physics**

M*g = 93 * 9.8 = 911.4 N. = Wt. of firefighter. Mg-Fk = M*a. 911.4 - 710 = 98*a, a = ?. V = Vo^2 + 2a*d. 3.2 = 0 + 2a*d, d = ?.

*October 14, 2016*

**Physics**

See previous post: Fri, 10-14-16, 10:33 AM.

*October 14, 2016*

**Physics**

Given: Vx = 30 m/s., Vy = 53 m/s. 2A. Vx = 30 m/s. Vy = 53 + g*t = 53 - 9.8*4 = 13.8 m/s. 2B. Dx = Vx*t = 30 * 4 = 120 m. Dy = 13.8 * 4 = 55.2 m. 3A. h = 0.5g*t^2 = 4.9*6^2 = 176.4 m.

*October 14, 2016*

**Physics**

Vo = 12m/s[47]. Xo = 12*Cos47 = 8.18 m/s. Yo = 12*sin47 = 8.78 m/s. Xo*T = 40. 8.18*T = 40, T = 4.89 s. = Time in air. Y = Yo + g*Tr_. 0 = 8.78 - 9.8Tr, Tr = 0.896 s. = Rise time. Tr+Tf = 4.89. 0.896 + Tf = 4.89, Tf = 3.99 s. = Fall time. ha = Yo*Tr + 0.5g*Tr^2. ha = 8.78*0....

*October 13, 2016*

**Physics**

a. M*g = 20 * 9.8 = 196 N. = Wt. of crate = Normal(Fn). Fap-Fs = M*a. 75-Fs = 20*0 = 0, Fs = 75 N. = Force of static friction. us = Fs/Fn = 75/196 = 0.383. b. 60-Fk = M*a. 60-Fk = M*0 = 0, Fk = 60 N. uk = 60/196 = 0.306.

*October 13, 2016*

**Physics**

52o S. of E. = 308o CCW. Disp. = 77[21o] + 124[308o]. Disp. = (77*Cos21+124*Cos308) + (77*sin21+124*sin308)I = 148.2 - 70.11i = 164m1[-25.3o] = 25.3o S. of E. = Direction. The crew must fly 164 miles in a direction 25.3o S. of E.

*October 13, 2016*

**Physics**

0.5g*t^2 = 25. 0.83*t^2 = 25, t = 5.49 s. to reach gnd. h = 0.5g*t^2 =4.9*5.49^2 = 148 m.

*October 13, 2016*

**physics**

V^2 = Vo^2 + 2g*h = 23^2 - 19.6*14 =

*October 13, 2016*

**Physics 11**

Vp + 50i = 500[0o]. Vp = 500 - 50i = 503 km/h[-5.71o] = 5.71o S. of E. = Direction.

*October 13, 2016*

**Physics**

D1 = 88 * 2 = 176km, S. D2 = 55 * 1.5 = 82.5km[70o] N. of E. X = 82.5*Cos70 = 28.22 km. Y = -176 + 82.5*sin70 = -98.5 km. D = sqrt(X^2+Y^2) = sqrt(28.22^2+98.5^2) = 102.5 km. Tan A = Y/X = (-98.5)/28.22 = -3.49043, A = -74o = 74o S. of E. = Direction.

*October 13, 2016*

**physics grade 11**

Post the problem.

*October 13, 2016*

**Physics**

V = Vo + a*t = 0 + 2*6 = 12 m/s. V = Vo + a*t. 0 = 12 + a*4, a = -3 m/s^2.

*October 13, 2016*

**Physics**

Ek = 0.5M*V^2 = 500*490 = 245,000 J.

*October 13, 2016*

**Physics**

a. V^2 = Vo^2 + 2g*h = 0 + 19.6*5 = 98, V = 9.90 m/s. Ek = 0.5M*V^2 = 500*98 = 49,000 J. b. V^2 = Vo^2 + 2g*h. 0 = Vo^2 - 19.6*25, Vo = 22.1 m/s. Ek =

*October 13, 2016*

**Java Programming Algorithm Help**

I just realized that my example provided is not clear and wrong. How about "51.283" and "1.982" We know 51 - 1 = 50 and 0.982 - 0.283 = 0.699 BUT, 51.283 - 1.982 = 49.301 Thank you

*October 12, 2016*

**Java Programming Algorithm Help**

Ok so for my assignment, I have to have two String inputs. For example, "1.021" and "2.51" And I need to calculate the difference between these strings (biggest number minus smaller). I can only use the data types: short, char, boolen and String. I cannot ...

*October 12, 2016*

**Physics**

V = Vo + a*t(i) = 4.8 + 3.4i*4.4 = 4.8 + 14.96i = sqrt(4.8^2 + 14.960^2) = 15.71 m/s.

*October 11, 2016*

**physics**

V = Vo + a*t. 21 = 0 + a*7, a = 3 m/s^2. V = 0 + 3*2 = 6 m/s.

*October 11, 2016*

**math**

727.7cm^3 * 19.3g/cm^3 = 14,045 g. Wt. = 14,045g * 1Lb/454g = 30.9 Lbs.

*October 11, 2016*

**Physics**

a. 0.5g*t^2 = 100. 4.9t^2 = 100, t = 4.52 s. b. V = Vo + g*t = 0 + 9.8*4.52 = 44.3 m/s. = Velocity after falling 100 m. Vo*t + 0.5g*t^2 = 100. 44.3*t + 0.5g*t^2 = 100, 4.9t^2 + 44.3t - 100 = 0, Use Quadratic formula: t = (-B+-sqrt(B^2-4AC)/2A. t =(-44.3+-sqrt(44.3^2+1960)/9.8...

*October 11, 2016*

**Science**

X = t^2-4t+7. X = 4^2 - 4*4 + 7 =

*October 11, 2016*

**Physics**

Y^2 = Yo^2 + 2g*h. Yo = sqrt(Y^2-2g*h). So if each object has the same value of Y and h, their initial Y component of velocity would be equal. We have 3 variables: 1. Y = 0 = Vertical component of final velocity. 2. Yo = Vertical component of initial velocity. 3.The max height...

*October 11, 2016*

**physics**

M1*d1 = M2*d2. M1*1.2 = M2*1.5, M1 = 1.25M2. (M1+14)*1.8 = M2*3. (1.25M2+14)1.8 = 3M2, 2.25M2 + 25.2 = 3M2, M2 = 33.6 kg, F2 = M2*g = 33.6*9.8 = 329.3 N. = Wt. of the girl. M1 = 1.25M2 = 1.25*33.6 = 42 kg, F1 = 42*9.8 = 411.6 N. = Wt. of the boy.

*October 11, 2016*

**AP Physics**

M*g = 5*9.8 = 49 N. = Wt. of the box. Fp = 49*sin30 = 24.5 N. = Force parallel t0 the incline. T = Fp = 24.5 N.

*October 10, 2016*

**math**

sin A = a/c = 26/65.2 = 0.39877, A = 23.5o. A + B + C = 180. 23.5 + B + 90 = 180, B = 66.5o.

*October 10, 2016*

**algebra 1**

Incomplete.

*October 10, 2016*

**physics**

V1*t = V2*t + d1. V1*t-V2*t = d1, t(V1-V2) = d1, t = d1/(V1-V2).

*October 10, 2016*

**Geometry**

86o + Xo + Yo = 180o. Yo = 180-86-X = 94-X.

*October 10, 2016*

**pre-calc**

r = 6-4 = 2mi/h.

*October 10, 2016*

**Science**

Vb = 12i + 20 = Sqrt(12^2+20^2) =

*October 10, 2016*

**physics**

M*g = 85 * 9.8 = 833 N. = Wt. of block. Fn = Mg-F*sin38 = 833 - 0.616F = Normal force. F*Cos38-u*Fn = M*a. 0.788F - 0.42(833-0.616F) = M*0 = 0, 0.788F - 349.9+0.259F = 0, 1.047F = 349.9, F = 334.3 N.

*October 9, 2016*

**physics**

1. Vr = Vc + Vb = 4. -3i + Vb = = 4, Vb = 4 + 3i = 5km/h[36.9o]. Direction = 36.9o N. of E. 2. Vr = 4 km/h. = Resultant velocity. 3. 5km/h[36.9o].

*October 9, 2016*