Friday

February 27, 2015

February 27, 2015

Total # Posts: 10,144

**physics**

a. X = 181*Cos66.2 b. Y = 181*sin66.2
*December 14, 2014*

**physics**

V = Vo + a*t = 0 + 231*0.0442 = 10.21 m/s. a. V*Cos A = 10.21*Cos55 = 5.86 m/s. b. 10.21*sin55 = 8.36 m/s.
*December 14, 2014*

**math**

X = Footballs sold @ $22 ea. Y = Footballs sold @ $6 ea. Eq1: x + y = 6000 Eq2: 22x + 6y = $76,000 Multiply Eq1 by -6 and add the Eqs: -6x - 6y = -36000 22x + 6y = 76,000 Sum: 16x = 40,000 X = 2500 In Eq1, replace X with 2500: 2500 + y = 6000 Y = 6000-2500 = 3500
*December 14, 2014*

**7th grade math**

3. Correct. 9. Correct. 12. X = 305/18 = 16 17/18 13. Correct. 14. C < -12.8 21. Correct. 26. Correct.
*December 14, 2014*

**physics**

Fp = Mg*sin50 Fn = Mg*Cos50 Fk = u*Fn = u*Mg*Cos50 Mg*sin50-0.1Mg*cos50 = M*a Divide both sides by M: g*sin50-0.1g*Cos50 = a a = 9.8*sin50-0.98*Cos50 = 6.88 m/s^2.
*December 14, 2014*

**physics**

Answer: The object with the greatest momentum. Object A: M*V = 1.9 * 8 = 15.2 kg-m/s Object B: M*V = 2.0 * 5 = 10.0 kg-m/s
*December 13, 2014*

**Physics**

Conservation of momentum: (M1+M2)V1/8 = M1*V1-M2*0 Multiply both sides by 8/V1: M1 + M2 = 8M1 3.32 + M2 = 8*3.32 M2 = 8*3.32 - 3.32 = 23.24 kg.
*December 12, 2014*

**Physics**

Conservation of momentum: (M1+M2)V = M1*V1-M2*V2 M1 = 4.66 kg M2 = 3.00 kg V1 = 4.77 m/s. V2 = 3.33 m/s. Solve for V.
*December 12, 2014*

**physics**

KE2 = KE1 * (V2/V1)^2 KE1 = 5*10^5 J. V1 = 36 mi/h V2 = 115 mi/h Solve for KE2.
*December 12, 2014*

**Science**

Vo = 27.4m/s[48o] Xo = 27.4*Cos48 = 18.3 m/s. Yo = 27.4*sin48 = 20.4 m/s. h = 0.5g*t^2 = 860 m. 4.9*t^2 = 860 t^2 = 175.5 Tf = 13.2 s. = Fall time. Dx = Xo*Tf = 18.3m/s * 13.2s = 242.4 m. b. Y = Yo + g*t = 0 + 9.8*13.2 = 129.4 m/s. Tan A = Y/Xo = 129.4/18.3 = 7.07104 A = 82o.
*December 12, 2014*

**Math**

P = Po*e^(r*t) e^(r*t) = P/Po r*t = 0.03*10 = 0.30 e^0.3 = P/5 Solve for P. Answer in millions.
*December 12, 2014*

**physics**

V = Vo + a*t V = 6.4 m/s. Vo = 0 t = 0.27 s. Solve for a. F = m*a
*December 12, 2014*

**Chemistry**

But these are the numbers which have been provided in the question... If u could show me just the way to tackle it, it wud be very helpful,plz.
*December 12, 2014*

**Chemistry**

0.250 moles of HCL and 0.100 moles of acetic acid are mixed in 0.365 moles of water. Determine the following: [CH3COOH], [CH3COO^-], pH and pOH. Ka=1.8E-5. Calculate the pH of 0.05M CH3COO-Na+ . Plz show me step by step, really confused right now.
*December 12, 2014*

**physics**

V = Vo + a*t V = 20 m/s. Vo = 25.1 m/s. t = 5.7 s. Solve for a. (It should be negative.) F = M*a
*December 9, 2014*

**physics**

V^2 = Vo^2 + 2a*d Vo = 0 a = F/m = 196.3/0.39 = d = 1.28 m. Solve for V.
*December 9, 2014*

**physics**

Incomplete.
*December 9, 2014*

**math**

P = Po + Po*r*t P = 39,995 + 39,995*(0.0249/12)*60 =
*December 8, 2014*

**Physics**

a = (F1-F2)/m F1 = 1141 N. F2 = 947 N. M = 2300 kg Solve for a. V^2 = Vo^2 + 2a*d V = 3 m/s. Vo = 0 a: Calculated in step #1. Solve for d in meters. .
*December 8, 2014*

**AP physics**

KE = M*V^2/2 KE = 5400 J. M = 2840 kg Solve for V. Units: m/s.
*December 8, 2014*

**physics**

a. 30o/h *2h = 60o. b. 360o/h * 2h = 720o. c. 4320o/h * 2h = 8640o
*December 8, 2014*

**Physics**

a. d = 0.5a*t^2 = 1.92 m. 0.5a*1.9^2 = 1.92 m 1.81a = 1.92 a = 1.06 m/s^2 b. M*g = 2.84 * 9.8 = 27.8 N. = Wt. of block. Fp = 27.8*sin30 = 13.9 N. = Force parallel to the incline. Fn = 27.8*Cos30 = 24.1 N. = Normal force Fp-Fk = m*a 13.9-Fk = 2.84*1.06 = 3.01 -Fk = 3.01-13.9...
*December 8, 2014*

**Physics**

d = 0.5a*t^2 d = 0.79 m. t = 0.64 s. Solve for a. F = m*a
*December 8, 2014*

**physics**

See previous post: Sat, 12-6-14, 4:06 PM
*December 8, 2014*

**physics**

V^2 = Vo^2 + 2a*d V = 0 Vo = 30 m/s. d = 75 m. Solve for a.(It should be negative). F = m*a. The force will be negative, because it acts against the motion.
*December 8, 2014*

**physics**

X m.=Distance the heavier person moves 2x m.= Lighter person distance. x + 2x = 12 3x = 12 X = 4 m.
*December 8, 2014*

**Physics**

M*g = 63 * 9.8 = 617.4 N. = Wt. of block Fp = Fs @ critical angle. Mg*sinA = us*Mg*CosA Divide both sides by Mg: sin A = us*Cos A Divide both sides by Cos A: sin A/Cos A = us = 0.47 = Tan A A = 25.2o = The critical angle. Fp = 262.6
*December 7, 2014*

**physics**

M*g = 16 N. Solve for g.
*December 7, 2014*

**Physics**

PE = M*g*h
*December 7, 2014*

**Math**

22n^2 + n - 5 Use AC Method: A*C = 22*(-5) = -110 = -10*11. Select the pair of factors whose sum = B =1: -10, and 11. Form 2 factorable binomials: 22n^2 + (-10n+11n) - 5 (22n^2+11n) - (10n+5) 11n(2n+1) - 5(2n+1) (2n+1)(11n-5)
*December 7, 2014*

**math**

See previous post: Sat, 12-6-14, 2:02 PM
*December 7, 2014*

**Physics**

V = Vo + a*t V = 0 Vo = 24 m/s t = 0.16 s. Solve for a.(It will be negative) F = M*a
*December 7, 2014*

**ALG 1**

12a^4b^3 + 8a^3b^2 = 4a^3b^2(3ab+2). GCF = 4a^3b^2.
*December 7, 2014*

**physics**

Incomplete.
*December 7, 2014*

**Physics**

X = M1*V1 = 24*3.3 = 79.2 Y = M2*V2 = 33*2.4 = 79.2 1a. Tan A = Y/X = 79.2/79.2 = 1.00 A = 45o = Direction. 1b. Momentum = X/Cos A = 79.2/Cos45 = 112 (M1+M2)*V = 112[45o] (33+24)V = 112[45] V = 1.96 m/s.[45o]
*December 7, 2014*

**problem solving**

See previous post: Sun,12-7-14, 1:41 AM.
*December 7, 2014*

**problem solving**

Difference = 35 - 0.75*40 = 35 - 30 = 5.
*December 7, 2014*

**problem solving**

Cost = Po + 0.05Po = $315 1.05Po = 315 Po = $300 = Initial price. (315-300)/6blks = $2.50/blk 300/(2.50/blk) = 120 Blocks bought.
*December 7, 2014*

**problem solving**

400rev/min * 60min/h = 24,000 rev/h. Circumference(C) = 47,520m/24,000rev = 1.98 m/rev C = pi*2r = 1.98 m 6.28r = 1.98 r = 0.315 m = 31.5 cm = Radius of the wheels.
*December 7, 2014*

**problem solving**

see 1:52 AM post.
*December 7, 2014*

**Physics**

a. d = Xo*Tf = 150 m. 450 * Tf = 150 Tf = 0.333 s. d = 0.5g*Tf^2 = 4.9*0.333^2 = 0.544 m. Below the center.
*December 6, 2014*

**Physics**

F = 27in/39in * 29Lbs = 20.1 Lbs.
*December 6, 2014*

**Physics**

F1 = 400N[32o] F2 = 536N.[10o] a. X = 400*Cos32 + 536*Cos10 = Y = 400*sin32 + 536*sin10 = Tan A = Y/X A = Fr = X/Cos A = Resultant force @ Ao. b. a = Fr/m = Acceleration @ A Degrees.
*December 6, 2014*

**math**

Eq1: Vp + Vw = 570/3 = 190 Eq2: Vp - Vw = 570/5 = 114 Sum: 2Vp = 304 Vp = 152 mi/h In Eq1, replace Vp with 152: 152 + Vw = 190 Vw = 38 mi/h.
*December 6, 2014*

**Algebra 1**

(-10,3), m = -1/5. Y = mx + b Y = 3 m = -1/5 x = -10 Solve for b(y-intercept).
*December 6, 2014*

**physics**

Momentum = M*V
*December 6, 2014*

**science**

V^2 = Vo^2 + 2g*h V = 0 Vo = 10 m/s. g = -9.8 m/s^2 Solve for h.
*December 6, 2014*

**Science**

h = 4.6 m. V1 = 16 m/s. V2 = 26 m/s. g = 9.81 m/s^2 h = 0.5g*t^2 Solve for t = Fall time. d = (V2-V1)*t = Distance apart.
*December 6, 2014*

**physics**

Wc = M*g = 92kg * 9.8N/kg = 902 N. = wt. of the clock. Fap-Fs = M*a 656 - Fs = M*0 = 0 Fs = 656 N. = Force of static friction. us = Fap/Wc = 656/902 = 0.727 uk = 560/902 = 0.621
*December 5, 2014*

**physics**

V^2 = Vo^2 + 2a*d V = 0 Vo = 8.6 m/s. a = u*g = 0.050*(-9.8) = -0.49 m/s^2 Solve for d.
*December 5, 2014*

**Math**

(24x^18/6x^3xX^8)/30x^6 = 4x^6/30x^6 = 2/15.
*December 5, 2014*

**Physics**

V = Vo + a*t V = 0 Vo = 8.5 m/s t = 3 s. Solve for a.(It will be negative) F = m*a
*December 5, 2014*

**Physics**

M1*V1 = (M1+M2)*V M1 = 1600 kg V1 = 13.7 m/s. M2 = 4600 kg Solve for V.
*December 5, 2014*

**physics**

Dp = Ds Vp*T = Vs*(T+95.7) 8*T = 4.5*(T+95.7) 8T = 4.5T+430.65 8T-4.5T = 430.65 3.5T = 430.65 T = 123 s. D = Vp*T = 8 * 123 = 984 km.
*December 5, 2014*

**physics**

L = V/F V = L*F = 5.8 * 1.15 = 6.67 m/s. Note: The distance between crests is the wavelength(L).
*December 5, 2014*

**physics**

T = d/V = 1340/457 = 2.93 s.
*December 5, 2014*

**Quantitative Business Analysis**

See previous post.
*December 5, 2014*

**Quantitative Business Analysis**

I = Po*r*t I = $9800 r = 0.08 t = 1 yr. Solve Po, the amount borrowed.
*December 5, 2014*

**physics**

Eq1: F1 + F2 = 376 N. Eq2: F1 - F2 = 162 N. Sum: 2F1 = 538 F1 = 269 N. In Eq1, replace F1 with 269: 269 + F2 = 376 F2 = 376 - 269 = 107 N.
*December 4, 2014*

**physics help PLZ!!**

Fx = -23.3 N. Fy = 409.5 N. 2nd Quadrant. Tan Ar = Fy/Fx = 409.5/-23.3 = -17.57511 Ar = -86.7o = Reference angle(Q4). A = -86.7 + 180 = 93.3o, CCW(Q2) = Direction.
*December 4, 2014*

**Physics**

d = V*T d = 2 * 3.84*10^8 m. V = 3*10^8 m/s. = Speed of light. Solve for T.
*December 4, 2014*

**physics**

X = -116.8 + 93.5 = -23.3 N. Y = -248.6 + 658.1 = 409.5 N. Tan Ar = Y/X = 409.5/-23.3 = -17.57511 Ar = -86.7o = Reference angle. A = -86.7 + 180 = 93.3o, CCW. Fr = Y/sin A = 409.5/sin93.3 = 410 N. [93.3o]. = Resultant force. Fx = 410*Cos93.3 = -23.61 N = 23.61 N., Left(West).
*December 4, 2014*

**Math**

110 = 30*3 + 20 Y = mx + b Y = 30x + 20 (Intercept Form) m = 30 = Slope. b = 20 = Y-intercept. Y = 30x + 20 30x - y = -20 (Standard Form). m = -A/B = -30/-1 = 30 = Slope. Y-Intercept = C/B = -20/-1 = 20. I hope this is what you want.
*December 4, 2014*

**math**

Eq1: 8x - 4xy = 3 Eq2: -2x - 5y = 10 In Eq2, solve for X: -2x - 5y = 10 -2x = 5y + 10 X = -5y/2 - 5 In Eq1, replace X with -5y/2 - 5: 8(-5y/2 - 5) - 4y(-5y/2 - 5) = 3 -20y - 40 + 10y^2 + 20y = 3 10y^2 - 40 = 3 Divide both sides by 10: y^2 - 4 = 0.30 y^2 = 0.30 + 4 = 4.30 Y = -...
*December 4, 2014*

**Math Help!**

1. (60/75)*100% = 80 %. 80% - 100% = -20% = 20% Decrease. 2. (160/100)*100% = 160% 160% - 100% = 60% Increase. 3. %Cost = 100% - 10% = 90% Cost = 0.90 * 57.63 = $51.87 4. Same procedure as #3.
*December 4, 2014*

**math**

Scale: 1/2 in = 1Ft. = 12 in Ratio = (1/2)in/12in = 1/24 L = 24 * 1Ft = 24 Ft. W = 24 * (7.5/12)Ft = 15 Ft. Note: I assumed you mean 7 1/2 in wide.
*December 4, 2014*

**physics**

See previous post: Thu 12-4-14, 9:49 AM.
*December 4, 2014*

**physics**

M * g = 2970 N. M = 90 kg Solve for g.
*December 4, 2014*

**Economics calculation help**

Thanks!
*December 4, 2014*

**Can Ms.Sue Help?**

Please
*December 4, 2014*

**Economics calculation help**

Kelly total income last year was $24,000, but she could deduct $12,000 for various reasons. How can I calculate; If she had to pay 15% of her taxable income in federal income tax, what was her total tax payment? So I did 12,000 x .15 and got 1800, but I don't know if thats...
*December 4, 2014*

**Math**

Your original Eq is the Vertex form of a Y-Parabola that opens downward. I am assuming you want to solve for X. Standard form: Y = -20/27(x^2 + 3x + 2.25) Y = (-20/27)x^2 -(60/27)x - 5/3 Y = (-20/27)x^2 - (20/9)x - 5/3 Use Quadratic Formula. X = -1.5, and -1.5(Double solution...
*December 4, 2014*

**Economics help**

Thanks
*December 4, 2014*

**Economics help **

An elderly man receives free prescription drugs from a veterans' hospital. So what kind of a good is this, like is this a privately owned service or publicly own service?
*December 4, 2014*

**physics**

ho = 186 m. Vo = 64.8m/s[59o] Xo = 64.8*Cos59 = 33.37 m/s Yo = 64.8*sin59 = 55.54 m/s Tr = -Yo/g = -55.54/-9.8 = 5.67 s. = Rise time. h = ho + (-Yo^2)/2g h = 186 + -(55.54^2)/-19.6 = 343.4 m. Above gnd. h = 0.5g*t^2 = 343.4 m. 4.9t^2 = 343.4 t^2 = 70.1 Tf = 8.37 s. = Fall time...
*December 4, 2014*

**Geomatry**

Y = (x^2+x-2)/(x^2-x-6) Y = (x+2)(x-1)/(x+2)(x-3) = (x-1)/(x-3) a. Domain = All real values of X except 3. Note: 3 gives a denominator of zero which makes the fraction undefined. f. When Y = 0,(x-1) = 0 x-1 = 0, X = 1. X-Intercept = 1.
*December 4, 2014*

**physics**

See previous post: Wed, 12-3-14, 8:20 AM
*December 4, 2014*

**physics**

a. KE = M*V^2/2 M = 0.59 kg V = 1.5 m/s Solve for KE. b. KE = M*V^2/2 KE = 7.0 J M = 0.59 kg Solve for V.
*December 3, 2014*

**physics**

d = V*t 2*76.5 = 1500t Solve for t.
*December 3, 2014*

**Science**

V = 5m/2s = 2.5 m/s. KE = M*V^2/2 = 1539*2.5^2/2 = 4809 J.
*December 3, 2014*

**Algebra 1**

Y/X = 24/8 = 3 = K(Y/X is constant). Y/10 = 3 Y = 30.
*December 3, 2014*

**Physics**

a. h = 0.5g*T^2 h = 18 m. g = 9.8 m/s^2 T = Fall time in s. Solve for T. d = Xo*T d = 18 m. Xo = hor. speed in m/s. T = Time calculated in part a. Solve for Xo. b. Y^2 = Yo + 2g*h Y = Ver. component of Speed just before it hits the gnd. Yo = 0 = Ver. component of initial speed...
*December 3, 2014*

**physics**

a. Vo = 0 V = 12 m/s. t = 6 s. V = Vo + a*t Solve for a. b. V = a*t a = (Use value calculated in part a). t = 10 s. Solve for V.
*December 3, 2014*

**physics**

Vo = 30 m/s. V = 0 t = 3 s. V = Vo + a*t Solve for a.
*December 3, 2014*

**Math**

See previous post: Wed, 12-3-14, 12:26 AM.
*December 3, 2014*

**Math**

d1 = 5mi/h[350o] * 2h = 10mi[350o] d2 = 12mi/h[40o] * 2h = 24mi[40o] d3 = 10mi/h[180] * 5h = 50mi[180] X = 10*Cos350 + 24*Cos40 + 50*Cos180 = -21.8 Miles. Y = 10*sin350 + 24*sin40 + 50*sin180 = 13.7 Miles. d = d1+d2+d3 = X + Yi=-21.8 + 13.7i,Q2. Tan Ar = Y/X = 13.7/-21.8 = -0....
*December 3, 2014*

**science**

V^2 = Vo^2 + 2a*d = 20^2 13^2 + 2a*1250 = 400 2500a = 400-169 = 231 a = 0.0924 m/s^2 t = (V-Vo)/a = (20-13)/0.0924 = 75.8 s.
*December 2, 2014*

**Math**

Yes.
*December 2, 2014*

**Math**

Tr = -Vo/g = -40/-32 = 1.25 s. = Rise time or time to reach max ht. h = -16*1.25^2 + 40*1.25 + 70 = 95 Ft. h = 0.5g*t^2 = 95 16t^2 = 95 t^2 = 5.94 Tf = 2.44 s. = Fall time. Tr+Tf = 1.25 + 2.44 = 3.69 s. = Time to reach gnd.
*December 2, 2014*

**mathematics of investment**

P = Po + Po*r*t = $3,200 Po + Po*0.055*2.5 = 3200 Solve for Po, the initial principal or investment.
*December 2, 2014*

**Math**

x = (3y+1)/6 Multiply both sides by 6: 6x = 3y + 1 3y = 6x - 1 Divide both sides by 3: Y = (6x-1)/3 = 2x - 1/3
*December 2, 2014*

**Physics**

M*g = 10.9kg * 9.8N./kg = 106.82 N. = Wt of the box. Fp = 106.82*sin38 = 65.8 N. = Force parallel to the incline. Fn = 106.82*Cos38 = 84.2 N. = Normal force. Fk = u*Fn = 1 * 84.2 = 84.2 N. = Force of kinetic friction. Note: If the coefficient of kinetic friction is 1, the box ...
*December 2, 2014*

**Physics**

M*g = 284kg * 9.8N./kg = 2783.2 N. = Wt. of the crate = Normal force(Fn). Fk = u*Fn = 0.513 * 2783.2 = 1427.8 N. = Force of kinetic friction. Fap-Fk = M*a Fap-1427.8 = M*0 = 0 Fap = 1427.8 N. = Force applied. Power = Fap * V = 1427.8 * 7.2 = 10,280 J/s. = 10,280 Watts.
*December 2, 2014*

**physics-finding velocity**

V^2 = Vo^2 + 2g*h = 0 + 19.6*0.65 = 12.74 V = 3.57 m/s.
*December 1, 2014*

**Physics**

a. Correct b. h = g*t^2/2 = 4.5 4.9*t^2 = 4.5 t^2 = 0.9184 t = 0.958 s. c. V = Vo + g*t = 0 + 9.8*0.958 = 9.39 m/s. or V^2 = Vo^2 + 2g*d = 0 + 19.6*4.5 = 88.2 V = 9.39 m/s. or V^2 = 0 + (-19.6*(0-4.5) = 88.2 V = 9.39 m/.s.
*December 1, 2014*

**physics**

Fr = (Vs+Vr)/(Vs-Vp) * Fp Fr = (340+0)/(340-163) * 1730 Hz = 3323 Hz. = Freq. heard by the receiver or listener.
*December 1, 2014*

**Physics**

db = 10*Log(I1/I2) = 10*Log(110/330) = -4.77 I1 = 4.77 db below I2.
*December 1, 2014*

**physics**

Vo = 0 V = 41 m/s. t = 5.3 s. M = 87 kg a = (V-Vo)/t Fx = M*a Fy = M*g F = Sqrt(Fx^2+Fy^2) = Total force.
*November 30, 2014*

**physics**

a = (V-Vo)/t = (0.37-0)/12 = 0.0308 (Fx-Fk) = M*a (127*Cos40-Fk) = 35 * 0.0308 97.3 - Fk = 1.079 -Fk = 1.079 - 97.3 = -96.2 Fk = 96.2 N. = Force of kinetic friction.
*November 30, 2014*

**Math**

1. P = Po + Po*r*t P = 100,000 + 100,000*0.1*5 = 150,000
*November 30, 2014*

Pages: <<Prev | 1 | 2 | 3 | 4 | **5** | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>