Thursday

July 24, 2014

July 24, 2014

Total # Posts: 8,898

**Physics**

Correction: Fk = u*Fc-u*Fap*sin27.3 Fk = 0.442*218.54 - 0.442*Fap*sin27.3 Fk = 96.6 - 0.203Fap Fap*cos27.3-(96.6-0.203Fap) = m*a 0.889Fap - 96.6 + 0.203Fap = m*0 1.092Fap = 96.6 Fap = 88.5 N. = Force applied. W = Fap*cos27.3 * d W = 88.5*cos27.3 * 9.3 = 731.3 J.

**Physics**

Fc = m*g = 22.3kg * 9.8N/kg = 218.54 N = Wt. of cart. Fk = u*Fc = 0.442 * 218.54 = 96.6 N. = Force of kinetic friction. Fap*cos27.3-Fk = m*a Fap*cos27.3-96.6 = m*0 = 0 Fap*cos27.3 = 96.6 N. W=Fap*cos27.3 * d = 96.6 * 9.3=898.3 J. Fap = Force applied = Tension in rope.

**Math**

X Tickets @ $75 each. (3500-X) Tickets @ $110 each. 75x + 110(3500-x) = 245,000+0.25*245,000 75x + 385,000-110x = 306,250 -35x = 306,250-385,000 = -78,750 X = 2250 Seats @ $75 each. 3500-x=3500-2250 = 1250 seats @ @110each

**math**

9x^2 * x^3 = 32 x^5 = 32 x^5 = 2^5 x = 2

**Physict**

d = d1(V2/V1)^2 = 15(150/50)^2 = 135 m.

**math**

0.05 * 173,000,000

**math word problem**

See previous post: Mon, 4-7-14, 3:36 PM.

**math**

See previous post.

**geometry**

2. m AB = (5-2)/(2-0) = 3/2. m BC = (0-5)/(3-2) = -5/1 = -5. 3. A'(-4,4), B'(-2,7), C'(1,2). 4. m AB' = (7-4)/(-2+4) = 3/2. m BC' = (2-7)/(1+2) = -5/3

**Math word problems**

L = 15x + 15y L = 15(x + y) x = 5 3/8 Yards y = 3/4 Yard L = Total length x + y = 5 3/8 + 3/4 = 43/8 + 6/8 = 49/8 = 6 1/8 Yards. L=15 * 49/8 = 91.875 Yards = 91 7/8 Yds.

**physics**

KE = m*V^2/2 = 4 * 4^2/2 = 32 Joules.

**Math**

See previous post: Sat, 4-5-14, 10:04 PM.

**physics**

Freq. = 5*10^6rad/s * 1rev/6.28rad = 7.958*10^5 rev/s = 7.958*10^5 Hz. Xl = WL = (6.28*7.958*10^5)*100*10^-6 = 500 Ohms. Xc=1/WC = 1/(6.28*7.958*10^5)*100*10^-12 = 2000 Ohms. Z = R + j(Xl-Xc) = 30 + j(500-2000) = 30 - j1500 = 1500.3Ohms [-88.9o] I = V/Z = 1.0[0o]/1500.3[-88.9]...

**Math**

P(t) = 100(1-e^-0.12*3) P(3) = 100(1-0.6977) = 30.23% Fails. 100% - 30.23% = 69.7% Usable.

**Math**

The largest exponent of the variable is 2. Therefore, it is a 2nd degree polynomial.

**College Physics**

F1 = 8.2N[125o] F2 = 6.40N[233.4o] A. Fx = 8.2*cos125 + 6.40*cos233.4 = -8.519 N. B. Fy = 8.2*sin125 + 6.40*sin233.4 = 1.579 N. C. F^2 = -8.519^2 + 1.579^2 = 75.07 F = 8.66 N. D. Tan Ar=Fy/Fx = 1.579/-8.519=-0.18535 Ar = -10.5o = Reference angle. A = -10.5 + 180 = 169.5o = 10....

**Algebra**

C = (B/2)^2 = (9/2)^2 = 81/4.

**physical science**

Yes.

**Math, Geometry**

See previous post: Fri,4-4-14,1:14 AM.

**Algebra**

Use Quadratic Formula: X = (-0.8 +- sqrt(0.64+2.96))/-0.04 = -27.43, and 67.43 X = 67.43 m.

**math**

P = Po(1+r)^n Po = $10,000 r = 8%/100% = 0.08 = APR expressed as a decimal. n = 1comp/yr. * 18yrs. = 18 Compounding periods. Solve for P.

**Math**

Correction: c. % Grade = Slope expressed as a percentage.

**Math**

a. Y/X = Y/2.5 = 0.06 Y/2.5 = 0.06 Y = 0.15 Miles = 792 Ft. b. Y/X = Y/90 = 0.06 Y = 90 * 0.06 = 5.4 Miles = 28,512 Ft. c. % Grade = Slope expressed as a decimal.

**math**

P = Po(1+r)^n Po = $8500 r = (12%/4)/100% = 0.03 = Quarterly % rate expressed as a decimal. n = 1yr * 4comp/yr. = 4 compounding periods. Plug the above values into the given Eq and sole for P.

**Physics**

Va=63rev/min * 6.28rad/rev * 1min/60s= 6.594 rad/s. Angle=0.57 + 6.594rad/s*9.5s=63.21 rad. or 0.4132 rad.

**percentages/word problem**

(3456-1600)/1600

**percentages/word problem**

(30.60-18)/18 = 0.70 = 70%

**percentages/word problem**

C + 0.45C = 79.75 1.45C = 79.75 C = $55.00

**Physics**

Correction: Vo = 460.6 rad/s V = 45 rad/s a = -84.3 rad/s^2

**Physics**

Vo=4401rev/min * 6.28rad/rev * 1min/60s= 460.6 m/s V = 430 * 6.28/60 = 45 m/s. a=(V-Vo)/t = (45-460.6)/4.93=-84.3 m/s^2

**physics**

Depth = V*T = 1530 * 3.65/2 = 2792 m.

**PHYSICS**

V = Vo + g*Tr = 0 14 - 9.8Tr = 0 9.8Tr = 14 Tr = 1.43 s. = Rise time. h = ho + Vo*Tr + 0.5g*Tr^2 hmax = 70 + (14*1.43 -4.9*1.43^2)=80 m. Above gnd. hmax = 0.5g*t^2 = 80 4.9t^2 = 80 t^2 = 16.33 Tf = 4.04 s = Fall time. Tr+Tf = 1.43 + 4.04 = 5.47 s. = Time to strike gnd. V=Vo + ...

**physics**

Incomplete.

**physics.**

The liquid with the highest density will have the largest percentage of its' volume above the water. Find the density of each liquid and compare them.

**Pre Algebra**

(9+3+4+16+11+5+T)/7 = 6. Solve for T.

**Physics**

d = V*t = 1500m/s * 1.5/2 = 1125 m.

**PHYSICS!!!**

T = d/V = 200/7 = 28.57 s.

**physics**

P = F * d/t = mg * d/t P = 66*9.8 * 14/44 Joules/s.

**Physic**

The voltage across a battery is equal to the e m f of the battery only when there is no load on the battery. When a resistive load is connected across the terminals, a portion of the voltage is lost across the internal resistance of the battery.

**Physics Help**

L = V(1/F) + 0 Slope = V. V is a constant. y-intercept = 0

**physics**

All of the parameters change.

**physics**

PE = m*V^2 = 0.164 J. .0508*V^2 = 0.164 V^2 = 3.228 V = 1.80 m/s.

**Physics**

Va=219rev/20s * 6.28rad/rev=68.8 rad/s a=(V-Vo)/t = (68.8-0)/20=3.44 rad/s^2. Circumference=pi*2r = 6.28 * 68=427 cm= 4.27 m. d = 219revs * 4.27m/rev = 935.2 m.

**Physics -- check answers please**

1. My answer is zero, because the car did not move backwards. However, you should get a 2nd opinion. 2. KE = 0.5*m*V^2 = 40 Joules KE = 0.5*5*V^2 = 40 2.5V^2 = 40 V^2 = 16 V = 4 m/s. 3c. 4a. PE + KE = Constant 5. I don't know what you mean by 4 100 J If you mean 400 J. the...

**business mat**

I = Po*(r/360)*t = $15 740(r/360)*59 = 15 43,660r/360 = 15 121.28r = 15 r = 0.1237 = 12.37%/yr.

**business Math**

(115-100)/100 = 0.15 = 15%.

**Business Math**

I = Po*r*t = $1.307 45,000*(0.04/365)*t = 1307 Solve for t in days. NOTE: Exact interest is based on 365 days per year instead of 360 days.

**Algebra**

X = 3y^2 K = Yv = -B/2A = 0/6 = 0 h = Xv = 3 * 0^2 = 0 D(X1,K), V(h,K), F(X2,K). D(X1,0), V(0,0), F(X2,0) DV = 0-X1 = 1/4a = 1/12 0-X1 = 1/12 X1 = -1/12 VF = X2-0 = 1/4a = 1/12 X2 = 1/12

**physics**

a = (Fap-Fk)/m = (160-24)/20 = 6.8 m/s^2

**physics**

V = Vo + a*t = 30 m/s 0 + a*4 = 30 a = 30/4 = 7.5 m/s^2.

**Math**

Can you clarify your problem?

**Math**

(150-73)/150 = 0.51 = 51%

**science**

750W * 1hp/746W = 1.0 hp.

**math**

post it.

**phisecs**

Power = 19kW = 19000W = 19,000 Joules/s. Power = F*V = F * 29 = 19,000 J./s F = 19,000/29 = 655.2 N.

**phisecs**

a = (V^2-V0^2)/2d a = (0-17^2)/40 = - 7.23 m/s^2.

**algebra**

x-1 = x+5 x-x = 5+1 0 = 6. No Solution.

**Physics**

What is the mass of the crate?

**Physics**

V=90mi/h * 1600m/mi * 1h/3600s.= 40 m/s. a = (V-Vo)/t = (40-0)/0.5 = 80 m/s^2.

**Physics**

Work = F*h = mg * h = 6*9.8 * 4=235.2 J. Work = F*h = 12 * 5 = 60 J. Work = 5*8 = 40 J. PE = mg*h = 5 * 8 = 40 J.

**Physics**

L = V/F = 199 m. F = V/199 = 300*10^6/199=1.51*10^6 cy/s= 1.51*10^6 Hz. WL = 1/WC C = 1/W^2*L C=1/(6.28*1.51*10^6)^2*785*10^-6=0.0142 nanofarads.

**World History**

What role did the Jacobins play in the French Revolution? The Jacobins reached an agreement with moderate French leaders to end the revolution. The Jacobins opened French gov't to full participation by women. The Jacobins returned France to a monarchy by supporting Napoleo...

**History**

How was James I's rule of England similar to peter the great's rule of Russia? Both reduces the size of their empire. Both increased their own power without approval by other government entitles. Both relied heavily on the opinions of their subjects when making decisio...

**Electricity**

Q = C*V = 10*10^-9F * 5V = 50*10^-9 Coulombs.

**math**

Got it! thanks

**math **

for the line segment whose endpoints are r(1,2) and s(6,7), find the point located 3/4 the distance from r to s.

**math 2**

Thank you so much reiny : )

**math 2**

A segment with endpoints C (3,4) and D (11,3) is divided by a point E such that CE and DE form a 3:5 ratio. Find E.

**math**

So I continued working where you left off and got y=0.5x+2.5 is that correct? or is it y=0.5x-2.5? I am pretty sure that it is the first one but I just wanna make sure.

**math**

Write an equation of a line perpendicular to line AB below in slope-intercept form that passes through the point (7, 6). A (0,1) B (-2,5)

**Math**

Wow thanks! It is correct! :D

**Math**

Write an equation of a line perpendicular to y=1/2x-5 in slope-intercept form that passes through the point (2, -7).

**6th Grade Math**

Blue = 3/10 Red = 4/10 = 2/5 Green = 3/10

**Physics**

h = Vo*t + 0.5g*t^2 = 2 m. 0 + 4.9*t^2 = 2 t^2 = 0.4082 t = 0.639 s. = Fall time. V = Vo + g*t = g*t. g = 10 m/s^2 Use the following points for graphing. (t,v) = (0,0), (0.2,2), (0.3,3),(0.5,5), (0.6,6).

**math**

P = (Po*r*t)/(1-(1+r)^-t) Po = Initial principal = $199,000 r = (7.01%/12)/100% = 0.00584 = Monthly % rate expressed as a decimal. t = 25yrs * 12mo/yr. = 300 Months. Plug the above values into the given Eq. and get: P = $422,328.10 Int.(Tot.) = P-Po = $223,328.10 Monthly Payme...

**Physical science**

See Related Questions: Wed,9-25-13,3:20 PM.

**physics**

Ingrid: 2h, 21min, 06s = Blake-: 2h, 06min, 50s = 2h, 20min, 66s 2h, 06min, 50s Diff. = 14min, 16s. = = 14.267min = Blake's winning margin. Tb = 120 + 6 + 50/60 = 126.833min = Blake's time. Vb = d/Tb = 42,195m/126.833min = 332.681 m/min = Blake's speed. d = 332.681...

**physics**

See Related Questions: Fri,3-21-14,8:55 PM.

**Physics**

m*g = 115 * 9.8 = 1127 N. = Wt. of box. Fn = 1127*cos46 = 782.9 N. = Normal force.

**physics**

Circumference = pi*D = 3.14 * 0.7m = 2.20 m. b. Va = 2m/s * 6.28rad/2.20m=5.71 rad/s = Angular velocity.

**physics**

h = (V^2-Vo^2)/2g = (0-(8^2))/-19.6 = 3.27 m.

**physics**

d = 0.5g*t^2 = 20-12 = 8 m. 4.9t^2 = 8 t^2 = 1.63 t = 1.28 s. = Fall time. Range = V*t = 4m/s * 1.28s = 5.12 m. 5.12m > 5 m. Therefore, he will make it.

**math**

Eq1: 5x - y = 20 Eq2: 4x + 3y = 16 Multiply Eq1 by 3 and add the Eqs: 15x - 3y = 60 +4x + 3y = 16 Sum: 19x = 76 X = 4 In Eq1, replace x with 4 and solve for y: 5*4 - y = 20 20-y = 20 Y = 0. Solution: (x,y) = (4,0).

**physics**

See Related Questions:Fri,3-21-14,8:55PM

**Physics**

Vo = 50m/s[37o] Xo = 50*cos37 = 39.93 m/s. Yo = 50*sin37 = 30.09 m/s. Tr = (Y-Yo)/g = (0-30.09)/-9.8 = 3.07 s = Rise time. Tf = Tr = 3.07 s. = Fall time. T = Tr+Tf = 3.07 + 3.07 = 6.14 s. = Time in air. d = Xo*T = 39.93m/s * 6.14s = 245.2 m. = Total dist. traveled.

**trigonometry**

The ladder is the hyp. of a rt. triangle X = ? Y1 = 8 Ft. Y2 = 84-8 = 76 Ft. A = 60o Tan 60 = Y2/X = 76/X X = 76/Tan60 = 43.88 Ft. = Dist. from bldg.

**Physics**

h=(V^2-Vo^2)/2g = (0-(8^2))/-19.6=3.27 m

**physics**

V = d/t = (t^3-3t^2+2)/4=(4^3-3*4^2+2)/4 = 4.5 m/s.

**physics**

a. 1.5km * 1000m/km * 1*10^6um/m = 1.5*10^9 Microns. b. 1.5um * 1m/10^6um * 100cm/m = 1.5*10^-4 cm c. 1.5yds * 3Ft/yd * 1m/3.3Ft * 10^6um/m = 1.364*10^6 Microns.

**physics**

h=(V^2-Vo^2)/2g = (0-(-8^2)/-19.6 = 3.27 m.

**physics**

T = 3 25/60 + (7 35/60-3 25/60) T = 3.417 + (7.583-3.417) = 7.583 Min. = 455 s. t = (7.583-3.417)min * 60s/min = 250 s. d = V*t = 1.65m/s * 250s = 412.4 m. V = d/T = 412.4m/455s = 0.906 m/s.

**math**

Given: F(x) = 1 - 3x. g(x) = x^2 - 1. F(g(x)) = F(x^2-1) F(x^2-1) = 1 - 3(x^2-1) = 1 - 3x^2 + 3 = -3x^2 + 4 F(g(x)) = -3x^2 + 4

**physics**

m*g = 50 * 9.8 = 490 N. = Wt. of crate = Normal force (Fn). a. Fs = u*Fn + u*F*sin30 Fs = 0.75*490 + 0.375F = 367.5 + 0.375F F*cosA-Fs = m*a F*cos30-(367.5+0.375F) = m*0 = 0 0.866F-367.5-0.375F = 0 0.866F-0.375F = 367.5 0.491F = 367.5 F = 748.5 N b. Fs = 0.75*490 - 0.75*F*sin3...

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 20^2 - 19.6*15 = 106 V = 10.30 m/s.

**physics**

a = (V^2-Vo^2)/2d a = (0-(56)^2)/0.036 = -87,111 m/s^2 F = m*a = 850 * (-87,111)=-74,044,444 N.

**Physics**

V = 25 + 4 = 29 km/h.

**Math**

Vo = 200 Ft/s = Initial velocity. g = 2*(-16) = -32 Ft/s^2. hmax = (V^2-Vo^2)/2g = (0-(200)^2)/-64 = 625 Ft. Yes, because his max. ht. is greater than the ht. of the building.

**math**

C = pi*2r = (22/7) * 2(7n-21) C = (44/7) * (7n-21) = (308n - 924)/7 = 44n - 132

**physics**

m*g = 30 * 9.8 = 294 N. = Wt of cabinet. Fs = u*mg = 0.8 * 294 = 235.2 N.

**Math Help**

1. x^2 - 10x + 25 = 0 25 = -5 * -5 (x-5)(x-5) = 0 x-5 = 0 X = 5 x-5 = 0 X = 5 Solution set: X = 5, and 5. 2. 2x^2 + 9x -5 = 0 A*C = 2 * -5 = -10 = -1*10 2x^2 + (-x+10x) - 5 = 0 (2x^2-x) + (10x-5) = 0 x(2x-1) + 5(2x-1) = 0 (2x-1)(x+5) = 0 2x-1 = 0 2x = 1 X = 1/2 x+5 = 0 X = -5 ...

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