Friday

March 27, 2015

March 27, 2015

Total # Posts: 10,327

**algebra**

10in./30in. =
*January 21, 2015*

**Math (Greatest common factor)**

12 = (1*12), (2*6), (3*4). 18 = (1*18), (2*9), (3*6). 24 = (1*24), (2*12), (3*8), (4*6). CF = 1,2,3,6. GCF = 6. So we factor out 6 and the variables with the lowest exponents: 6m^2n^3(2m^3 + 3m - 4) I, normally, find the GCF by knowing that the GCF =< 12 (the smallest ...
*January 21, 2015*

**Math**

1. 6.4in * 2.54cm/in = 2. 4qts * 32oz./qt * 0.03L/oz. = 3. 10kg * 1Lb/0.454kg =
*January 21, 2015*

**physics**

A train whistle is heard at 280Hz as the train approaches town. The train cuts its speed in half as it nears the station, and the sound of the whistle is then 270 Hz. What is the speed of the train before slowing down? What is the speed of the train after slowing down?
*January 21, 2015*

**physics**

M1*V1 + M2*V2 = M1*V3 + M2*V3 V3 = V4. 60*0 + 15*12 = 60*V3 + 15*V3 180 = 75V3 V3 = 2.4 m/s = Velocity after impact.
*January 21, 2015*

**physics**

a. Y = Yo + g*t = 0 + 9.8*1 = 9.8 m/s = Ver Component. X-component = 0 b. D = 0.5*g*t^2. Solve for D. Y = D, X = 0.
*January 21, 2015*

**physic**

a. V = a*t = 0.5m/s^2 * 4s. = 2 m/s. b. d = 0.5a*t^2 = 0.5*0.5*4^2 = 4 m.
*January 21, 2015*

**Physics**

T = 12s./10rev = 1.2 s/rev.=1.2 s/cycle
*January 20, 2015*

**Math**

sqrt(450) = sqrt(2*225) = 15*sqrt(2).
*January 20, 2015*

**ascience**

X = 20 mi/h Y = 10 mi/h Tan A = Y/X = 10/20 = 0.50 A = 26.56o V = X/Cos A = 20/Cos26.56 = 22.4mi/h[26.56o]
*January 20, 2015*

**Physics**

Do you mean (5,7)? If so, (x,y) = 5,7).
*January 20, 2015*

**physics**

V = Vo + g*t V = 0 Vo = Initial velocity. g = -9.8 m/s^2 t = 2.2 s. Solve for Vo.
*January 20, 2015*

**Math**

Yes.
*January 20, 2015*

**math**

Bearing of Q = 90-50 = 40o East of North
*January 20, 2015*

**Math**

8/25 + 1/5 + x = 4/5 X = 4/5 - 8/25 - 1/5=20/25 - 8/25 - 5/25 = 20/25 - 13/25 = 7/25 of the grid for Nate.
*January 19, 2015*

**physics**

Dx = 1710*Cos5.08 =
*January 19, 2015*

**physics**

196m[-18o] X = 196*Cos(-18) = Y = 196*sin(-18) =
*January 19, 2015*

**grade 7 math**

1. -450 km/h(South). 2. 675 km/h(North). 675T - (-450T) = 3600 km. Solve for T.
*January 19, 2015*

**grade 7 math**

A = -80 km/h(West). B = 110 km/h(East). 110T - (-80T) = 760 km 110T + 80T = 760 190T = 760 T = 4 h.
*January 19, 2015*

**grade 7 math**

d1 + d2 = 210 km 60*2 + r2*2 = 210 Solve for r2.
*January 19, 2015*

**grade 7 math**

9:15 - 8:00 = 1h and 15 min. = 1.25h head-start. d = r1*t = 45km/h * 1.25h = 56.25 km Head-start. r2*t = r1*t + 56.25 t = 9:15AM to 1PM = 3h and 45min = 3.75h r2 * 3.75 = 45*3.75 + 56.25 r2*3.75 = 225 r2 = 60km/h = Michael's speed. r1*t + 56.25 = 45*3.75 + 56.25 = 225 km...
*January 19, 2015*

**grade 7 math**

d1 = r1*t1 = 60km/h * 0.5h = 30 km after 0.5 h. r2*t = r1*t + 30 65 * t = 60*t + 30 65t - 60t = 30 5t = 30 t = 6 hours.
*January 19, 2015*

**Physics/Math**

a. Eo/Ei = 1.0 100/Ei = 1 Solve for Ei. b. Eo/Ei = 0.30 Eo/100 = 0.30 Solve for Eo. c. Same procedure as a and b.
*January 19, 2015*

**physics**

A = 13.2[0o] B = 6.1[110o] R = 13.2+6.1*Cos110 + i6.1*sin110 = 11.11 + 5.73i R^2 = 11.11^2 + 5.73^2 = 156.3 R = 12.50
*January 19, 2015*

**physics**

1. D = Vo*t + 0.5a*t^2 = 6.1*6.8 * 0.5*0.49[35o]*6.8^2 = 41.48 + 11.33[35o] = 41.48 + 9.28+6.5.0i = 50.76 + 6.5i D^2 = 50.76^2 + 6.5^2 = 2618.3 D = 51 m. 2. Tan A = Y/X = 6.5/50.76 = 0.12805 A = 7.3o = Direction.
*January 18, 2015*

**physics**

M*g = 10kg * 9.8N/kg = 98 N. = Wt. of block. Fn = M*g - Fap*sinA = 98 - 75*sin37 = 52.9 N. Fk = u*Fn = 0.4 * 52.9 = 21.15 N. = Force of kinetic friction. a = (Fap*Cos37-Fk)/M = (75*Cos37-21.15)/10 =
*January 18, 2015*

**Math**

Rono: Cost = 4000 + 6*3000 = $22,000 Sam: Cost = 22000 - 5000 =
*January 17, 2015*

**Math**

Dan: Cost = 0.90 * 6245 = $5620.50 Dave: Cost = 3000 + 12*500 = $9,000 9000 - 5620.50 =
*January 17, 2015*

**Math**

Hali: Cost = 0.95 * 15000 = $14,250 John: Cost = 6000 + 3*3200 = $15,600 15,600 - 14,250 = $1,350 More than Hali.
*January 17, 2015*

**Physics**

V = 3km/h[90o] + 40km/h[20o] Y = 3 + 40*sin20 = 16.7km/h = Vertical or Northerly component. d = r*t = 16.7km/h * 6h = 100.1 km.
*January 17, 2015*

**physics**

See previous post: Sat,1-17-15, 6:18 PM.
*January 17, 2015*

**physics**

Power=Fx * d/t = 70.9*Cos48 * 19.9/4.3 = Note: J/s = Watts.
*January 17, 2015*

**physical science**

When they are acting in the same direction. Fmax = 5 + 7 = 12 N.
*January 17, 2015*

**Physics Class**

0.450 ms = 0.000450 s. V = Vo + a*t = -36.7 36.7 + a*0.000450 = -36.7 0.00045a = -36.7-36.7 = -73.4 a = -163,111 m/s^2 F = M*a = 0.140 * (-163111) = 22,836 N.
*January 16, 2015*

**Physics**

X = 1.84 m/s = Velocity of the current. Y = 1.1 m/s = Velocity of the boat. A. Vb^2 = X^2 + Y^2 = 1.84^2 + 1.1^2 = 4.60 Vb = 2.14 m/s. B. Tan A = Y/X = 1.1/1.84 = 0.59783 A = 30.9o, CCW = 59.1o E. of N. Tan59.1 = d/115 d = 115*Tan59.1 = 192 m. Downstream.
*January 16, 2015*

**Algebra**

a. Month 1: Profit = (4.31-1.50)/cup * 1283cups = $3605.23 Profit = (0.83-0.76)/donut * 216Donuts = $15.12 Month 2: Profit = (4.31-1.50)/cup * 4210cups = $11,830.10 Profit = (0.83-0.76)/donut * 317Donuts = $22.19
*January 15, 2015*

**physics**

V^2 = Vo^2 + 2g*h V = 0 g = -9.8 m/s^2 h = 6.57 m. Solve for Vo.
*January 15, 2015*

**Math**

(32 + 56) 32 = (1,32), (2,16), (4,8). 56 = (1,56), (2,28), (4,14), (7,8). CF = 1,2,4,and 8. GCF = 8. 8(4 + 7)
*January 15, 2015*

**physical science**

F(net) = F1 + F2 = 3.5 + (-4.5) = -1 N. = 1 N. Towards the Left.
*January 15, 2015*

**PHYSICS**

V^2 = Vo^2 + 2a*d = 0 d = -Vo^2/2a = -(25^2)/-5 = 125 m. Circumference = pi * 2r = 3.14 * 0.54 = 1.70 m. 125m * 1rev/1.70m = 73.5 Revolutions.
*January 15, 2015*

**physics**

See Related Questions: Tue, 9-10-13, 1:08 PM.
*January 15, 2015*

**math(5th grade)**

2.8pages/3.5min * 31.5min = 25.2 Pages.
*January 15, 2015*

**General/Academics**

Glad I could help.
*January 14, 2015*

**General/Academics**

0.75*85 + 0.25*F = 89 63.75 + 0.25F = 89 0.25F = 89-63.75 = 25.25 F = 101 = Finals score. Cannot be done! 0.75*85 + 0.25*100 = 88.75% = Max. possible score.
*January 14, 2015*

**physics**

Eq1:0.5M*V^2 = 198 J. Eq2: M*V = 13 M = 13/V In Eq1, replace M with 13/V: 0.5*(13/V)*V^2 = 198 6.5*V = 198 V = 30.5 m/s.
*January 13, 2015*

**Physics**

Vo = 1860m/s[67.4o] Xo = 1860*Cos67.4 = 714.8 m/s. Yo = 1860*sin67.4 = 1717.2 m/s. Y = Yo-g*Tr = 0 1717.2 - 9.8Tr = 0 9.8Tr = 1717.2 Tr = 175 s. = Rise time. Tf = Tr = 175 s. = Fall time Tr+Tf = 175 + 175 = 350 s. = 5.83 Min. in flight.
*January 13, 2015*

**Math**

Social studies: X Hours. 2 3/4 + 1 1/2 + x = 5 3/4 Hours. Solve for X.
*January 13, 2015*

**algebra**

-2(2+3)-2k = -2-4(2+2) -2(5)-2k = -2-4(4) -10-2k = -2-16 -10-2k = -18 -2k = -18+10 -2k = -8 Divide both sides by (-2): K = 4. 9(
*January 13, 2015*

**algebra**

Y = 16/20 * 38 = 30.4 in. = Length of short side. Cost = 6*Area = 6 * (38*30.4) = 20/16 = 38/30.4 = 1.25
*January 13, 2015*

**math**

Your Eq is correct. Length = X Ft. (2/5)x + 600 = 2000. Multiply both sides by 5/2: x + 1500 = 5000 X = 3500 Ft.
*January 12, 2015*

**physics**

F = 1500beats/30s = 50 Beats/s = 50cycles/s = 50 Hz. P = 1/F = 1/50 = 0.02 s.
*January 12, 2015*

**Physics**

Incomplete.
*January 12, 2015*

**physics**

Conservation of Linear Momentum: M1V1 + M2V2 = M1*V3 + M2*V3 M1 = 160,000 kg V1 = 0.30 m/s M2 = 115,000 kg V2 = -0.120 m/s Solve for V3, the final velocity.
*January 12, 2015*

**physics**

h = Vy*t + 0.5g*t^2 = 840 m. 0*t + 4.9t^2 = 840 Solve for t.
*January 12, 2015*

**physics**

Conservation of Linear Momentum: M1V1 + M2*V2 = M1V3 + M2*V4 77.5V1 + 21*0 = 77.5*2.18 + 21*2.18 77.5V1 + 0 = 214.73 V1 = 2.77 m/s.
*January 12, 2015*

**physics**

M1V1+M2V2 = 85*2 + 55*2.7[22o] = 170 + 148.5[22o] = 170 + 148.5*Cos22 + 148.5*sin22 = 170+137.7 + 55.63i = 307.7 + 55.63i = 313[10.25o] kg-m/s.
*January 12, 2015*

**Physics**

F = M*g = 0.55kg * 9.8N/kg = 5.39 N. K = 5.39N./0.36m = 14.97 N/m
*January 12, 2015*

**algebra--1 question**

Slope = (Y2-Y1)/(X2-X1)=(1+3)/(1+2)=4/3.
*January 12, 2015*

**Physic- help on direction (Not that good at Englis**

Use the slope that was calculated from your lab data to calculate g using the given equation.
*January 12, 2015*

**physics**

M*g = 89.7kg * 9.8N/kg = 879.1 N. = Wt. of box = Normal force(Fn). Fs = u*Fn = 0.5 * 879.1 = 439.5 N. = Force of static friction. Fap-Fs = M*a Fap-439.5 = M*0 = 0 Fap = 439.5 N. = Force applied.
*January 12, 2015*

**physics**

1. Draw a hor. line. 2. Draw a ver. line to the right-end of the hor. line and label it h for height. 3. From the left-end of the hor. line, draw a hypotenuse to the top of the ver. line. The angle it makes with the hor. is 12o. 4. Draw a 2nd hyp. to the right of the first and...
*January 12, 2015*

**physics**

E = 43 Volts. R1 = 13 Ohms R2 = 24 Ohms R3 = 41 Ohms I = I1 + I2 + I3 = E/R1 + E/R2 + E/R3 = 43/13 + 43/24 + 43/41 = 3.31 + 1.79 + 1.05 = 6.15 Amps. = Total current drawn from the 43-volt source. P = E*I = 43 * 6.15 = 264.5 Watts = Total power taken from the 43-volt source. P1...
*January 12, 2015*

**Physics-Check**

d1 = V1*T = 5m/s * 10min*60s/min=3000 m. d2 = V2*T = 4.5 * 10min*60s/min = 2700 m d1-d2 = 3000 - 2700=300 m. Between them. Or d=(5-4.5)m/s * 10min*60s./min=300 m. Between them.
*January 12, 2015*

**Mechanics**

Open circuit.
*January 11, 2015*

**math**

1 - 1/x = 2 - 2/x -1/x + 2/x = 1 1/x = 1 X = 1 3 - 3/x = 3 - 3/1 = 3 - 3 = 0
*January 11, 2015*

**physics**

V = Vo + a*t Vo = 2.5 m/s. a = 1.5 m/s^2 t = 4 s. Solve for V(m/s).
*January 11, 2015*

**Math**

P = Po*(1+r)^n Po = $4000 = Initial principal. r = (13.8%/12)/100% = 0.0115 = Monthly % rate expressed as a decimal. n = 12Comp/yr. * 4yrs. = 48 Compounding periods. Solve for Principal(P).
*January 11, 2015*

**Physics**

a. d = Circumference = pi*2r = 3.14 * 18.54 = 58.25 m. b. T = 1min/861rev = 60s/861rev = 0.0697 s./rev c. V=861rev/min * 58.25m/rev * 1min/60s =
*January 11, 2015*

**physic**

V = 160km/2h = 80 km/h
*January 11, 2015*

**physics**

M*g = 550 N. = Normal force(Fn). Fs = u*Fn = 0.16 * 550 = 88 N. = Force of static friction. Fap-Fs = M*a Fap - 88 = M*0 = 0 Fap = 88 N. = Force applied.
*January 11, 2015*

**trigonometry**

X = 36 m. Tan60 = Y/X Solve for Y. h = Y + 2.3
*January 11, 2015*

**trigonometry**

Y = 5 m. = ht. A = 20.67o L = Length of rope. sin A = Y/L Solve for L.
*January 11, 2015*

**trigonometry**

The wire and the post form a rt. triangle with the gnd. L = Hyp. = Length of wire. X = 7 m. A = 56.67o L = X/Cos A
*January 11, 2015*

**physics**

M = 1970 kg V = 102km/h = 102,000m/3600s. = 28.33 m/s. KE = 0.5*M*V^2
*January 11, 2015*

**physics**

d = 1.7km * 1000m/km = 1700 m. T = 10.7min * 60s./min = 642 s. V = d/T = 1700m/642s. = 2.65 m/s. KE = 0.5*M*V^2
*January 11, 2015*

**Math**

1. F(x) = -3(x^2+4x+4)=-3x^2 - 12x - 12 2. (x-2)(x+1)/(3x+1)(x+1) = (x-2)/(3x+1) F(x)=(x+1)(x-2)/(x+1)(3x+1)=(x-2)/(3x+1)
*January 10, 2015*

**Math**

1. F(x) = (x+1)(x-2)/(x+1) = x-2 = g(x) 2. F(x) = (x+3)(x-4)/x+3 = x-4. g(x) = (x-2)(x-4)/(x-2) = x-4 = F(x).
*January 10, 2015*

**Math**

(3x+1)/2(x^2-1) + 2(x+1)/2(x^2-4x+3) = (3x+1)/2(x+1)(x-1) + 2(x+1)/2(x-1)(x-3) = (3x+1)/2(x+1)(x-1) + (x+1)/(x-1)(x-3) LCD = 2(x+1)(x-1)(x-3) (3x+1)(x-3)/2(x+1)(x-1)(x-3) + (x+1)(x+1)/2(x+1)(x-1)(x-3) (3x^2-9x+x-3)/LCD + (x^2+2x+1)/LCD Add the Numerators: (4x^2-6x-2)/LCD = 2(...
*January 9, 2015*

**Physics**

See Related Questions: Thu, 10-2-14, 2:52 AM.
*January 9, 2015*

**physics**

1. 38Lbs/95Lbs * 882N. = 352.8 N. on Mars. 2. 95Lbs/38Lbs * 333N = 832.5 N. on Earth.
*January 9, 2015*

**Physics**

A. d = V*T = 57.5 m V*15.3 = 57.5 V = 3.76 m/s B. V = Va + Vp = 3.76 1.75 + Vp = 3.76 Vp = 2.0 m/s
*January 8, 2015*

**physics**

Range = Vo^2*sin(2A)/g = 12 m. Vo^2*sin(28.4)/9.8 = 12 Vo^2*sin(28.4) = 117.6 Vo^2 = 117.6/sin(28.4) = 247.3 Vo = 15.72 m/s.
*January 8, 2015*

**Algebra 1**

x + y = 9 x - y = 1 Sum: 2x + 0 = 10 X = 5 In Eq1, replace x with 5: 5 + y = 9 Y = 4 Solution set: (x,y) = (5,4).
*January 8, 2015*

**physics**

Wt. = M*g = 40kg * 9.8N/kg = 392 N. L = 6 + (1m/50N * 392N) = 13.84 m.
*January 8, 2015*

**6TH GRADE MATH**

Platypus: 10 min. Whale: 7(10+x) = 112
*January 8, 2015*

**Math**

a. X = 2. F(x) = -3(2+-2)^2 - (2+1) = -51 g(x) = -3*2^2 - 13*2 - 13 = -51 The student should finish the assignment.
*January 8, 2015*

**Math**

5/(x-1) + 2/(x+1) = -6 LCD = (x-1)(x+1) 5(x+1)/(x-1)(x+1)+2(x-1)/(x+1)(x-1) =-6 (5x+5)/(x-1(x+1) + (2x-2)/(x+1)(x-1)=-6 Add the numerators: (7x+3)/(x+1)(x-1) = -6 7x+3 = -6(x+1)(x-1) 7x+3 = -6(x^2-1) 7x+3 = -6x^2 + 6 6x^2 + 7x = 6 - 3 = 3 6x^2 + 7x - 3 = 0 Use AC method of ...
*January 8, 2015*

**Math 1 please help**

1. Shirts: A = (12-3)x = 9x x = The number of shirts bought. Jeans: A = (19-3)x = 16x
*January 8, 2015*

**science**

See Related Questions: Tue, 7-17-12, 8:08 AM.
*January 7, 2015*

**Physical Science**

Correct!
*January 7, 2015*

**Physical Science**

(M1+M2)V = M2*V2 80.16V = 0.16*20 Solve for V.
*January 7, 2015*

**Physics**

M*g = 100 N. Fn = 100*Cos0 - Fap*sin45 = Normal force Fn = 100 - 0.707Fap Fk=u*Fn = 0.75(100-0.707Fap)=75-0.53Fap Fap-Fk = M*a Fap-75 + 0.53Fap = M*0 = 0 1.53Fap = 75 Fap = 49 N. = Force applied. Fn = 100-0.707Fap = 100 - 0.707*49 = 65.4 N. = Normal force.
*January 7, 2015*

**math**

Eq1: Do mean Y = (3/2)x - 1? If so, then Y = 3x/2 - 1 Multiply both sides by 2: 2y = 3x - 2 Eq1:-3x + 2y = -2 Eq2: +x + y = 4 Multiply Eq2 by 3 and add the Eqs: -3x + 2y = -2 +3x + 3y = 12 Sum: 5y = 10 Y = 2. In Eq2, replace y with 2 and solve for x: x + 2 = 4 X = 2. Solution ...
*January 7, 2015*

**physics**

Wt. = M*g M = 23.5 kg g = 9.8m/s^2 Solve for Wt.
*January 7, 2015*

**physics**

Mass = 4.6g/1000 = 0.0046 kg a. KE1 = 0.5*M*V1^2 = 3.13 J. b. KE@ = 0.0023*74.8^2 = 12.87 J.
*January 7, 2015*

**Physics**

M*g = 500 N. = Normal force(Fn). Fk = u*Fn = 0.3 * 500 = 150 N. = Force of kinetic friction. Fap-Fk = M*a Fap-150 = M*0 = 0 Fap = 150 N. = Force applied.
*January 7, 2015*

**Math**

In a rt. triangle, the sum of the square of the two shorter sides is equal to the square of the 3rd side. X = 959 Miles Y = 1,011 Miles Z = 1,033 Miles X^2 + Y^2 = Z^2 959^2 + 1011^2 = 1033^2 1,941,802 > 1,067,089 It is not a rt. triangle.
*January 7, 2015*

**physics**

Circumference = pi * 2r = 3.14 * 2*399 = 2507 m. V = 40.5m/s * 6.28rad/2507m = 0.1015 rad/s.
*January 7, 2015*

Pages: <<Prev | 1 | 2 | 3 | 4 | **5** | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | Next>>