Saturday

July 23, 2016
Total # Posts: 11,909

**Electronics**

Even if an amplifier circuit does not have band-pass filters, there is a limit on the band of frequencies that it can pass. The lowest frequency is determined by the value of the coupling capacitors. The highest frequency is limited by any capacitance in parallel with the ...
*March 5, 2016*

**maths**

VAT = 0.05*(52,500+84,000+262,000+672,000+157,000) =
*March 5, 2016*

**science**

L = V/F = 3*10^5/40*10^6 = 0.0075 m.
*March 5, 2016*

**algebra or algebra1**

(20)(x^3y^4)^3 = (20)(x^9y^12) = 20x^9y^12.
*March 5, 2016*

**algebra or algebra1**

F(a) = 2a + 9 = 7, 2a = -2, a = -1.
*March 5, 2016*

**algebra or algebra1**

L = Sqrt(21^2+16^2)
*March 5, 2016*

**physics**

C = pi*D = 3.14 * 67 = 211 cm. = 2.11 m. Speed = 11.2rev/s * 2.11 m/rev = 23.6 m/s.
*March 4, 2016*

**Calculus**

Show that f(x) = 2000x^4 and g(x) = 200x^4 grow at the same rate I know that they grow at the same rate because they are both raised to the same power, but i don't know how to show it.
*March 4, 2016*

**Math**

(5,6), (8,9). m = (9-6)/(8-5) = 1, Y = mx + b = 6, 1*5 + b = 6, b = 1, Y = x + 1. (0,5), (6,3). m = (3-5)/(6-0) = -1/3, Y = mx + b = 5, (-1/3)0 + b = 5, b = 5, Y = (-1/3)x + 5. x + 1 = (-1/3)x + 5, x+1 = -x/3 + 5, x + x/3 = 4, Multiply both sides by 3: 3x + x = 12, X = 3 Min.
*March 4, 2016*

**Math**

1. 1cents = 2^0 = 2^(d-1). 2. 2cents = 2^1 = 2^(d-1) 3. 4cents = 2^2 = 2^(d-1). 15. 2^(d-1) = 2^(15-1) = 2^14 = 16,384 Cents(pennies) = $163.84.
*March 4, 2016*

**math**

1. Take the chicken across. 2. Take the fox across and bring the chicken back. 3. Take the corn across. 4. Take the chicken across.
*March 4, 2016*

**Calculus**

Find the range of the function ∫sqrt(4-t^2) dt where a=0 =x [0, 4π] [0, 2π] [-4, 0] [0, 4]
*March 4, 2016*

**physics**

a. Impulse = 0.224 * 22 = b. V = Vo + a*t = -22, 18 + a*0.06 = -22, 0.06a = -40, a = 667 m/s^2. F = M*a = 0.224* (-667) =
*March 3, 2016*

**Physics**

h = Vo*t + 0.5g*t^2
*March 3, 2016*

**Physics**

Y = 5.07*sin60.2 = 4.40 m/s. d = V*T = 24.7, 4.4*T = 24.7, T = 5.61 s.
*March 3, 2016*

**physics**

a. V^2 = Vo^2 + 2g*h, Vo = 0, g = 9.8 m/s^2, h = 0.54 m., V = ?. b. k = Mg/d = (1.7*9.8)/0.088m =
*March 3, 2016*

**Algebra**

See previous post.
*March 2, 2016*

**Algebra**

See previous post.
*March 2, 2016*

**Algebra**

See previous post: Wed, 3-2-16, 10:20 PM.
*March 2, 2016*

**Algebra**

(-5,3), (4,-5). Y = mx + b, m = (-5-3)/(4-(-5)) = -8/9, Y = (-8/9)(-5) + b = 3, b = 3 - 40/9 = 27/9-40/9 = -13/9. Eq: Y = (-8/9)x - 13/9.
*March 2, 2016*

**Alegbra**

Incomplete.
*March 2, 2016*

**Algebra**

a. Y = a(x-h)^2 + k. h = -b/2a = -18/-6 = 3, k = -3*3^2 +18*3 + 53 = 80, Y = -3(x-3)^2 + 80. b. T max = k = 80o F.
*March 2, 2016*

**Algebra**

a. h(t) = 0.5g*t^2. b. h(1) = 16*1^2 = 16 Ft. c. h = 0.5g*t^2. h = 35 Ft., g = 32 Ft/s^2, t = ?.
*March 2, 2016*

**math**

son's age : (x+5) in 5 years. Parent's age: 2(x+5) in 5 years. 50 < ((x+5) + 2(x+5))< 100, 50 < (x+5 + 2x+10) < 100, 50 < 3x+15 < 100, 50-15 < 3x < 100-15, 35 < 3x < 85, 35/3 < x < 85/3. 11 2/3 < X < 28 1/3, 16 2/3 < x+5 <...
*March 2, 2016*

**Calculus**

Determine if the Mean Value Theorem for Integrals applies to the function f(x) = 5 - x^2 on the interval 0 to sqrt 5 . If so, find the x-coordinates of the point(s) guaranteed by the theorem.
*March 2, 2016*

**math 5th grade**

5.29 + (2/3)*3.59 + (4/3)*4.79 = $14.07, Yes. 28.50-(2*3.59)-1.34 = 19.98 = Cost of 4 pks. of glass beads. 19.98/4 = $5.00 = Cost of 1 pk. of glass beads.
*March 1, 2016*

**Maths**

1. W/100 = 8/5, 5W = 800, W = 160g of wheat. 160 + 100 = 260 Grams of muesli. 2. 84/R = 7/3, 7R = 252, R = 36g of raisins. 84 + 36 = 120 grams.
*March 1, 2016*

**Math**

Did you mean? 12a + 15p = 100.
*March 1, 2016*

**Math**

Suzanne: X min. Jim: (x+30)min. X = 1/3 * 60min = 20 min. x+30 = 20 + 30 = 50 min.
*March 1, 2016*

**Banking Finance**

Higher.
*March 1, 2016*

**Algebra**

P = Po(1+r)^n. Po = $3500, r = (6.75%/12)/100% = 0.005625 = Monthly % rate expressed as a decimal. n = 1Comp./mo. * 6mo = 6 Compounding periods. P = ?.
*February 29, 2016*

**Algebra**

P = Po(1+r)^n. Po = $500, r = (4%/4)/100% = 0.01 = Quarterly % rate expressed as a deci8mal. n = 4Comp./yr. * 6yrs = 24 Compounding periods. P = ?.
*February 29, 2016*

**Algebra**

P = Po(1+r)^n. n = 1Comp./yr. * 5yrs = 5 Compounding periods. P = 4000(1.06)^5 =
*February 29, 2016*

**Math**

P = Po(1+r)^n. Po = $850, r = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 10yrs. = 40 Compounding periods. P = 850(1+r)^40 = 1100, (1+r)^40 = 1100/850 = 1.294, Raise both sides to the 1/40 power: 1+r = 1.294^(1/40) = 1.00647, r = 1.00647 - 1 = 0.00647 = Quarterly...
*February 29, 2016*

**math**

P = Po(1+r)^n. r = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 2yrs = 8 Compounding periods. P = 3800*(1+r)^8 = 4300, (1+r)^8 = 4300/3800 = 1.132, 8*Log(1+r) = Log1.132, Log(1+r) = Log1.132/8 = 0.00673, 1+r = 10^(0.00673), r = 10^(0.00673) - 1 = 0.0156, APR = 4...
*February 29, 2016*

**math**

P = Po(1+r)^n. r = (2%/2)/100% = 0.01 = Semiannual % rate expressed as a decimal. n = 2Comp./yr. * 2yrs = 4 Compounding peri0ds. P = Po*(1.01)^4 = 12,500. Po = ?.
*February 29, 2016*

**math**

See previous post: Mon, 2-29-16, 2:12 AM.
*February 29, 2016*

**math**

P = Po(1+r)^n. r = (10%/2)/100% = 0.05 = Semiannual % rate expressed as a decimal. n = 2Comp./yr. * 10yrs = 20 Compounding periods. P = 100,000(1.05)^20 = $265,329.77. Repeat the above procedure for 15% and 20%.
*February 29, 2016*

**math**

Cost = 60 + 11.05*11 = $181.55 P = Po + Po*r*t = 181.55, 170 + 170*r*(11/12) = 181.55, 170 + 155.83r = 181.55, 155.83r = 11.55, r = 0.047 = 4.7%, APR.
*February 29, 2016*

**Algebra 2**

49^3x = 343^(x+1), 3x*Log49 = (x+1)*Log343, Divide both sides by Log49: 3x = (x+1)*Log343/Log49, 3x = 1.5*(x+1), 3x = 1.5x + 1.5, 3x-1.5x = 1.5, X = 1. So the 2x in your Eq should be x.
*February 23, 2016*

**Algebra 2**

49^3x = 343^(2x+1). 3x*Log49 = (2x+1)*Log343, Divide both sides by the Log of 49: 3x = (2x+1)*Log343/Log49, 3x = 1.5(2x+1), 3x = 3x+1.5, 3x-3x = 1.5. No solution? Please make sure the problem is copied correctly.
*February 23, 2016*

**Calculus**

The rate at which water flows into a tank, in gallons per hour, is given by a differentiable function R of time t. The table below gives the rate as measured at various times in an 8-hour time period. t---------0-----2------3-------7----8 (hours) R(t)--1.95---2.5---2.8----4.00...
*February 23, 2016*

**Math**

All angles are measured CCW from +x-axis. Vr = 55mi/h[55o] + 550mi/h[25o] = 31.5+45.1i + 498+232i = 530 + 277i = 598mi/h[27.6o]
*February 23, 2016*

**Calculus**

Use the graph of f(t) = 2t + 3 on the interval [-3, 6] to write the function F(x), where F(x)= ∫f(t) dt where a=3 b=x. F(x) = 2x^2 + 6x F(x) = 2x + 3 F(x) = x^2 + 3x + 54 F(x) = x^2 + 3x - 18 Honestly have no idea where to start. Do i take the derivative of that or what?
*February 23, 2016*

**MATH**

Both ordered pairs at D satisfy the Eq .
*February 23, 2016*

**Math**

9 min. = 0.15h, 22.5 min = 0.375h. d = (Va+Vs)*t = 1.5 km. (Va+Vs) * 0.15 = 1.5. Eq1: Va + Vs = 10. (Va-Vs)*0.375 = 1.5. Eq2: Va - Vs = 4. Add the two Eqs: Va + Vs = 10. Va - Vs = 4. Sum: 2Va = 14, Va = 7 km/h. In Eq1, replace Va with 7: 7 + Vs = 10 km/h, Vs = 3 km/h. Va = ...
*February 22, 2016*

**Science**

All angles are measured CCW from +x-axis. D = 118km[345o] + 118[125o] = 114-30.5i + -67.7+96.7i = 46.3 + 66.2i = 80.8km[55o].
*February 22, 2016*

**MAth**

P = Po + Po*r*t = $5,040. 4500 + 4500*0.06*t = 5040. t = ?.
*February 21, 2016*

**Calculus**

Yes and b are the lower and upper and I plugged in my value of 1 and got 2.59 but that's not one of my answers. My options are 12 6 4 1/9
*February 21, 2016*

**Calculus**

I don't know because thats what the question says. Thanks
*February 21, 2016*

**Calculus**

How would I set this up in my calculator? Let F(x)=∫ ln(t^2) dt where a= 1 and b=3x . Use your calculator to find F"(1). I set it up and I got way the wrong answer. I got 2ln(1)=0
*February 21, 2016*

**Calculus**

Pumping stations deliver gasoline at the rate modeled by the function D, given by D(t)= 6t/(1+2t) with t measure in hours and and R(t) measured in gallons per hour. How much oil will the pumping stations deliver during the 3-hour period from t = 0 to t = 3? Give 3 decimal ...
*February 21, 2016*

**Calculus**

A particle moves along the x-axis with velocity v(t) = sin(2t), with t measured in seconds and v(t) measured in feet per second. Find the total distance travelled by the particle from t = 0 to t = π seconds. Do I have to take the integral of the equation like ∫ sin(...
*February 21, 2016*

**Calculus**

f(x) and g(x) are a differentiable function for all reals and h(x) = g[f(2x)]. The table below gives selected values for f(x), g(x), f '(x), and g '(x). Find the value of h '(1). (4 points) x 1 2 3 4 5 6 f(x) 0 3 2 1 2 0 g(x) 1 3 2 6 5 0 f '(x) 3 2 1 4 0 2 g &#...
*February 21, 2016*

**Math Fractions**

Total = X pages. Monday: 1/6 * x = x/6 Pages read. x-x/6 = 6x/6 - x/6 = 5x/6 Remaining. Tuesday: 2/5 * 5x/6 = x/3 Pages read. 5x/6 - x/3 = 5x/6 - 2x/6 = 3x/6 Remaining. Wednesday: 1/3 * 3x/6 = x/6 Pages read. 3x/6 - x/6 = 2x/6 = x/3 Remaining. x/3 = 60, X = 180 Pages.
*February 21, 2016*

**physcis**

a. V = Vo + g*Tr = 0, Tr = -Vo/g = -20/-32 = 0.625 s. = Rise time. Tf = Tr = 0.625 s. = Fall time from max ht. to top of bldg. h = Vo*T + 0.5g*T^2. h = 60 Ft., Vo = 20 Ft/s, g = 32 Ft/s^2, T = ?. Tr+Tf+T = Time to reach gnd. b. V^2 = Vo^2 + 2g*h. Vo = 20 Ft/s, g = 32 Ft/s^2, h...
*February 21, 2016*

**Calculus**

Compare the rates of growth of f(x) = x + sinx and g(x) = x as x approaches infinity. f(x) grows faster than g(x) as x goes to infinity. g(x) grows faster than f(x) as x goes to infinity. f(x) and g(x) grow at the same rate as x goes to infinity. The rate of growth cannot be ...
*February 20, 2016*

**Calculus**

Which of the following functions grows the fastest as x goes to infinity? 3^x ln(x) e^4x x^10 I put e^4x but I thought that 3^x might have been it too. I know for sure that it is not ln(x) and x^10 because those grow much slower.
*February 20, 2016*

**Calculus**

Which of the following functions grows the slowest as x goes to infinity? x^e e^x ex they all grow the same rate. I think it is c because it does not have any exponents.
*February 20, 2016*

**Calculus**

The graph of f ′(x) is continuous and decreasing with an x-intercept at x = 0. Which of the following statements is false? (4 points) The graph of f has an inflection point at x = 0. The graph of f has a relative maximum at x = 0. The graph of f is always concave down. ...
*February 20, 2016*

**Physics**

Oops!! Please disregard my first post. First Student: Xo = Cos60.34 = 0.4949 Yo = sin60.34 = 0.8690 Y = Yo + g*Tr = 0, Tr = -Yo/g = -0.8690/-9.8 = 0.0887 s. = Rise time. Tf = Tr = 0.0887 s. T = Tr+Tf = 0.0887 + 0.0887 = 0.1774 s. = Time in air. Dx = Xo*T = 0.4949 * 0.1774 = 0....
*February 20, 2016*

**Physics**

Xo = Cos60.34 = 0.4949 Yo = sin60.34 = 0.8690
*February 20, 2016*

**physics**

M1*V1 + M2*V2 = M1V + M2*V. 3250*44 - 1500*17 = 3250V + 1500V. V = ? Direction: North.
*February 20, 2016*

**electronics**

Normally, the zener is connected in parallel with the load; it tends to maintain a constant voltage across the load. The zener is protected by a series resistor through which the zener and load current flows. If the load is removed, all of the current flows through the zener ...
*February 20, 2016*

**electronics**

1. The voltage dropped across the diodes might not be equal or the voltages from the center-tapped transformer might not be equal. Therefore, you could have a defective transformer or diode. 2.In cases where there are large variations in the input voltage and the load, a zener...
*February 20, 2016*

**Math**

The errors in your problem makes it difficult to understand.
*February 20, 2016*

**Algebra**

(T1+T2+T3)/3 = 19, T1+T2+T3 = 3*19 = 57. (57+T4)/4 = 21, T4 = 27 Degrees.
*February 20, 2016*

**Physical Science**

F = M*a = 100,000-82,000 = 18000, 30,000*a = 18000, a = 0.6 m/s^2.
*February 19, 2016*

**Math**

My answer is B.
*February 19, 2016*

**Physics**

Energy = 0.5C*V^2 = 0.5*14.1*45^2 = 14,276 uJ. = 0.01428 J. Energy = 0.5*14.1*V^2 = 0.001428, V^2 = 2.03*10^-4, Vc = 1.425 Volts when 90% of it's energy is lost. 45/e^x = 1.425, e^x = 31.6, X = 3.45 = t/RC = t/1.13, 1.13*3.45 = 3.90 mS. = 3.90*10^-3 s. = Time to loose 90% ...
*February 18, 2016*

**Physics**

T = R*C = 0.08k * 14.1uF = 1.13 Milliseconds. a. 45/e^x = 4.5, e^x = 45/4.5 = 10, X = 2.303 = t/T = t/1.13, t = 1.13 * 2.303 = 2.60 mS = 2.6*10^-3 s. b. i = v/R = 4.5/80 = 0.056 Amps.
*February 18, 2016*

**Physics**

T1 = 460.8N.[68.9o] N. of W. a. -T1*Cos68.9 = -T2*Cos33.8, -T2 = -T1*Cos68.9/Cos33.8, T2 = 0.433T1 = 0.433*460.8 = 199.6 N.[33.8o]. b. Y = 460*sin68.9 + 199.6*sin33.8 = 540.2 N. M*g = 540.2, M = 540.2/9.8 = 55.12 kg.
*February 18, 2016*

**Math/Finance**

Assuming simple interest. P = Po + Po*r*t = 4000. 2000 + 2000*r*2 = 4000. r = APR expressed as a decimal.
*February 18, 2016*

**Physics**

d = 27.8 * 20 = 556 m. Head start. 0.5a*t^2 = 556 + 27.8t. 1.5t^2 = 556 + 27.8t. 1.5t^2 - 27.8t - 556 = 0. t = Time required for B to catchup. 0.5a*t^2 = Distance at which B catches up.
*February 18, 2016*

**Physics**

a. db = 10*Log(I/Io) = 130. 10*Log(I/10^-12) = 130. Log(I/10^-12) = 13. I/10^-12 = 10^13. I = 10 W/m^2. b. db = 10*Log(20/10^-12) = 133. Doubling the sound intensity increases the sound level by only 3 db.
*February 17, 2016*

**physics**

Incomplete.
*February 17, 2016*

**SCIENCE**

Incomplete.
*February 16, 2016*

**Math**

I chose b also.
*February 16, 2016*

**Math**

1. Correct. 2. Correct.
*February 16, 2016*

**Basic electricity**

The given units are incorrect.
*February 16, 2016*

**science**

20 minutes per hour makes no sense. So let's assume: Vo = 20m/s[53o]. Xo = 20*Cos53 = 12.0 m/s. Yo = 20*sin53 = 16.0 m/s. a. Y = Yo + g*Tr = 0, 16 - 9.8*Tr = 0, -9.8Tr = -16, Tr = 1.63 s. = Rise time. Tf = Tr = 1.63 s. = Fall time. T = Tr+Tf = 1.63 + 1.63 = 3.27 s. = Time ...
*February 16, 2016*

**MATH HELP**

My answer is b.
*February 15, 2016*

**Math College Algebra (urgent before 2hours)**

The zero of a function is the value of X when Y or F(x) = 0. In other words it is the solution to the function. Example: Y = 2x + 4 = 0, 2x = -4, X = -2. So x = -2 when y = 0: (-2,0). 2. g(y) = y^2-3y+2 = 0, C = 2 = (-1)*(-2), Sum = B = -3. (y-1)(y-2) = 0, y-1 = 0, Y = 1, y-2...
*February 15, 2016*

**Science**

10o W. of N. = 100o CCW. 10o E. of N. = 80o CCW. Fr = 1.8*10^6[100o] + 1.8*10^6[80o]=-3.126*10^5+1.773*10^5i + 3.126^10^5+1.773*10^5i = 3.546*10^5i = 3.546*10^5[90o] = 3.546*10^5N., Due North. = Resultant force. Work = Fr*d = 3.546*10^5 * 500 =
*February 15, 2016*

**science**

F1 = 15N[0o], F2 = 20N[135o]. F1+F2 = 15 + -14.1+14.1i = 0.9 + 14.1i = 14.2 N.[86.4o] = 0.89 + 14.18i F3 must be equal to F1+F2 in magnitude and 180o out of phase: F3 = 14.2N[86.4+180] = 14.2[266.4o].= 14.2[86.4o] S. of W. = -0.89 - 14.18i
*February 14, 2016*

**Physics**

a. Work = Change in kinetic energy: Work = 0.5M*V^2-0.5M*Vo^2, Vo = 0, Work = 0.5M*V^2 = 0.5*845*25^2 = 264,063 J. Po = W/t = 264063/60 = 4401 J/s. = 4401 Watts = Power out. Pi = 4401/0.95 = 4633 Watts = Power in. Pi = 12*I = 4633, I = 4633/12 = 386 Amps.
*February 14, 2016*

**Maths**

r = 35/4 = 8 3/4% = 8.75% = 0.0875. I = Po*r*t = 3000*(0.0875/12)*14 = 90.0875*
*February 14, 2016*

**Physics**

1. V^2 = Vo^2 + 2g*h. Vo = 0, g = 9.8 m/s^2, h = 80 m, V = ?. 2. 0.5g*t^2 = 80. g = 9.8 m/s^2, t = ?.
*February 13, 2016*

**Physics**

Wc = M*g = 35*9.8 = 343 N. Fp = 343*sin26 = 150.4 N. = Force parallel to the incline. Fn = 343*Cos26 = 308.3 N. = Normal. Fp-Fk = M*a. 150.4-0.33*308.3 = 35*a. 35a = 48.66. a = 1.39 m/s^2. V = Vo + a*t = 0 + 1.39*2.5 = 3.48 m/s.
*February 13, 2016*

**physics**

V^2 = Vo^2 + 2g*h, V = 0, Vo = 5m/s, g = -10m/s^2, h = ?.
*February 13, 2016*

**physics**

177 + 0.00506(T-28.7)177 = 116. 177 + 0.8956(T-28.7) = 116. 177 + 0.8956T-25.7 = 116. 0.8956T + 151.3 = 116. 0.8956T = 116-151.3 = -35.3. T = -39.4oC.
*February 13, 2016*

**physics**

F = M*a, F = 37.5 N, a = 2.80 m/s^2, M = ?.
*February 13, 2016*

**Cal 2**

The region bounded by y=3/(1+x^2), y=0, x=0 and x=3 is rotated about the line x=3. Using cylindrical shells, set up an integral for the volume of the resulting solid. The limits of integration are:
*February 12, 2016*

**Biology**

How are the following terms related to the process of transcription and one another? Eukaryotes, Prokaryotes, membrane-bound nucleus, introns, exons, precursor RNA (pre-mRNA), mature RNA, heterochromatin, euchromatin, and structural gene.
*February 12, 2016*

**geometry**

Or 7.5/7 = x/18, X = ?.
*February 11, 2016*

**physics**

Vector V1: Vx = -6.5 units. Vy = 0. Vector V2: V = 8.3[60o] Vx = 8.3*Cos60 = Vy = 8.3in60 = V1 + V2 = -6.5 + 8.3[60] = -6.5 + 4.15+7.19i = -2.35 + 7.19i = 7.56[71.9o] N. of W. = 108o CCW
*February 11, 2016*

**physics**

Do you mean constant velocity? If so, d = V*t, t = d/V.
*February 11, 2016*

**physical science**

d = 0.5a*t^2. d = 10 m, t = 45 s, a = ?.
*February 10, 2016*

**mathematics**

David: X years old. John: x+4 years old. Joe: x-2 years old. x + x+4 + x-2 = 41. Solve for x and add 8 years to John's age.
*February 10, 2016*

**Pysics**

D = -400 + 200[135o] + 100i = -400 - 141.4+141.4i + 100i = -541.4 + 241.4i = 593 km[24o] N. of W.
*February 10, 2016*