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Posts by Henry

Total # Posts: 13,497

Vectors
50o W. of N. = 140o CCW. Vr = Vb + Vc. 20[140] = Vb + (-8i), Vb = 20[140] + 8i, Vb = 20*Cos140+20*sin140 + 8i. Vb = -15.3 + 12.9i + 8i = -15.3 + 20.9i Tan A = Y/X = 20.9/(-15.3) = -1.36601. A = -53.8o = 53.8o N. of W. = 126.2o CCW = 36.2O W of N.

Vectors
B. sin50 = 1.7/d. d = 2.22 km.

Vectors
Your last question doesn't make sense.

Vectors
A. Vr = Vb + Vc. 20[50o] = Vb - 8i, Vb = 20[50]+8i, Vb = 20*Cos50+20*sin50 + 8i, Vb = 12.9 + 15.3i + 8i = 12.9 + 23.3i. Tan A = Y/X =23.3/12.9 = 1.80620, A = 61o.

Math
3n = 5n-14. n = ?.

math
The opposite angles of a parallelogram are equal: A = C = 35 + 25 = 60o. 360-120 = 240o. B = D = 240/2 = 120o.

Maths
$5400 * 1m/$13.50 = 400 m. Cost = 400m * 28.50/m =

Algebra
Po1*r1*t + Po2*r2*t = 2730. Po1*0.06*1 + Po2*0.09*1 = 2730, 0.06Po1 + 0.09Po2 = 2730. Eq1: 6Po1 + 9Po2 = 273,000, Eq2: Po1 + Po2 = 39000. Multiply Eq2 by -6 and Add: +6Po1 + 9Po2 = 273000. -6Po1 - 6Po2 = -234,000. Sum: 3Po2 = 39,000, Po2 = $13,000 Invested in acc. #2. Po1 = 39...

Physics
post it.

Physics
V = 80m/s[-20O]. Vx = 80*Cos(-20) = 75.2 m/s. Vy = 80*sin(-20) = -27.4 m/s. A. Range = V^2*sin(2A)/g. Range = 80^2*sin(2*20)/9.8 = 420 m. B. Tan20 = h/420, h = 153 m. h = Vy*t + 0.5g*t^2. 153 = -27.4*t + 4.9t^2, 4.9t^2 - 27.4t - 153 = 0, Using the Quadratic Formula: t = 9.04 s...

Math
L = 23.5 ft. W = 11 ft. h = 2/3 ft. 1 yd^3. = 27 ft^3. V = L*W*h. Yards = V/27.

physics
Incomplete.

electronic
Incomplete.

physical science
R = pL/A. p = 110*10^-8 Ohm.m = 110*10^-6 ohm.cm. L = 220 cm. r = 0.056 cm. A = pi*r^2 = 3.14*0.056^2 = 9.85*10^-3 cm^2. R = (110*10^-6*220)/(9.85*10^-3) = 2.46 Ohms.

pyhsical science
R = pL/A A = pi*r^2 = pi*(2r)^2 = pi*4r^2. R2 = 2pL/(pi*4r^2) = pL/Pi*2r^2.

Maths
Wt. of box = 20 N. Fp1 = 4*Cos20 = 3.76 N. = Force acting Parallel to ramp(upward). Fp2 = 20*sin A = Force acting parallel to ramp(downward). Fp2-Fs-Fp1 = 0. 20*sin A-5-3.76 = 0. Equilibrium. A = ?. 9 20*sin A-5-3.76 = 0. 20*sin A = 8.76, A = 10.8o. = Angle of elevation.

algebra
1. a^2 + b^2 = c^2. 15^2 + b^2 = 20^2, 225 + b^2 = 400. b^2 = 400-225 = 175, b = sqrt(25*7) = 5*sqrt7. 2. 9^2 + 12^2 = c^2. c^2 = 81 + 144 = 225, c = sqrt(225) = 15.

Algebra
Eq1: A = x * y = 48ft^2. Eq2: P = 2x + 2y = 28 Ft.

Scienc
2. Acceleration. 3. A. 6. D. Friction opposes motion. 7. A. Velocity includes magnitude and direction. 8. A. 10. C. 11. F = M*a = 3 * 7 = 21 N.

Math
A. V(t) = Vo - 899t. Vo = Initial value. B. V(t) = Vo + 899t.

Science
M*g = 50 * 9.8 = 490 N. = Wt. of box. Fp = 490*sin30 = 245 N. = Force parallel with incline. Fn = 490*Cos30 = 424 N. = Normal force. Fs = u*Fn = = 424u. = Force of static friction. Fp-424u = M*a. 245-424u = M*0 = 0, U = ?.

Physics
1 gal. = 8 Lbs. = 3.63 kg. M = 10,000gal * 3.63kg/gal. = 36,320 kg. PE = M*g*h = 36,320*9.8*61.5 Joules.

physics
V*a*(T2-T1) = 136. 1.53*a*(15.1-92.2) = 136, a = ?.

physics
a = 13*10^-6/oC = Temp. coeff. h*a*(T2-T1) = 0.197. h*13*10^-6(40-(-9)) = 0.197, h*0.000637 = 0.197, h = 309.3 m.

physics
a = 13*10^-6/deg.C = Temp. coeff. 358*a*(T2-T1) = 358*13*10^-6*(22-1.99) = 0.093 m. = 9.3 cm.

Math 115
C = 0.79P, P>100.

physics
d = 0.5a*t^2. 8 = 0.5a*4^2, a = 1 m/s^2. V = Vo + a*t.= 0 + 1*4 = 4 m/s.

physics
(14*10^-6/19*10^-6) * 3600cm = 2653 cm.

physics
M*g = 532 * 9.6 = 5214 N. = Wt. of piano. Work = F*d = 372 * 14 = 5208 J. PE = Mg*h = 5208. 5214h = 5208, h = 1.0 m.

Physics
M = 28.44 kg. F1 = 3964N[63.74o]. F2 = 130N[180o]. Fx = 3964*Cos63.74 - 130*Cos180 = 1624 N. Fx = M*a. a = Fx/M = 1624/28.44 = 57 m/s^2.

Physics
Fr = 5.9[28o] + 5[90o]. X = 5.9*Cos28 = 5.2Units. Y = 5*sin28 + 5*sin90 = 7.35 Units. Fr = sqrt(x^2+y^2) = Tan A = Y/X = 7.35/5.2 = 1.41346, A = 54.7o = The direction.

Math
1. x + y = 9. 2xy = 40, xy = 20, X = 20/y. x + y = 9. 20/y + y = 9, Multiply by Y: 20 + y^2 = 9y, y^2 - 9y + 20 = 0, (x-4)(x-5) = 0, Y = 4, and 5. x + y = 9. Solution set: (x,y)=(4,5),(5,4). So the numbers are 4, and 5. 2. 1st number = X. 2nd number = x+4. x^2 + (x+4)^2 = 208...

Physics
Vo = 5m/s[60o]. Xo = 5*cos60 = 2.5 m/s. Yo = 5*sin60 = 4.33 m/s. 1. Y = Yo + g*t. 0 = 4.33 - 9.8t, t = ?. 2. Y^2 = Yo^2 + 2g*h. 0 = 4.33^2 - 19.6h, h = ?. 3. Range = Vo^2*sin(2A)/g. Range = 5^2*sin(120)/9.8 =

science
The Elasticity of the balloon. The balloon can be stretched beyond its' normal size and can return to normal if the elastic limit is not exceeded.

physics
a. (185+182+183+182+182+184+183)/7 =

Physics
I drew out image of the situation but still need help. Can someone help with this problem about swinging on wrecking ball when at 1st: wrecking ball is in line with birdbath when at a peak in its trajectory, and in line with front door at the lowest point in the trajectory. ...

math
M*g = 35 * 9.8 = 343 N. = wt. of carton. Fp = 343*sin40 = 220.5 N. = Force parallel to the incline. Fn = 343*cos40 = 262.8 N. = Normal force. Fp-Fs = M*a. 220.5 - Fs = 35*0, Fs = 220.5 N. = Force of static friction.

math
Correction: 326 = 0.816T2, T2 = 400 N.

math
60o W. of N. = 150o CCW from +x-axis. 45o E. of N. = 45o CCW from +x-axis. The system is in equilibrium: 326*cos150 = -T2*cos45. 326 = 0.742T2, T2 = 400 N. Fb = -(T1*sin150+T2*sin45). Fb = -(326*sin150+400*sin45) = -446 N. = 446 N. Downward. M*g = 446. M = 446/g = 446/9.8 = 46...

Physics
While swinging on the wrecking ball, a student notices that, at first, the wrecking ball is in line with her birdbath when it is at a peak in its trajectory, and in line with her front door at the lowest point in the trajectory. However, since drag is acting against the ...

Physics
I was able to figure out mass of ball = to 720kg and velocity of ball and her is 1.90m/s

Physics
While swinging on the wrecking ball, a student notices that, at first, the wrecking ball is in line with her birdbath when it is at a peak in its trajectory, and in line with her front door at the lowest point in the trajectory. However, since drag is acting against the ...

Slopes
m = (7-4)/(-5-0) = -0.6 Y = mx + b. 4 = -0.6*(6) + b, b = 7.6. Eq: Y = -0.6x + 7.6

Math
r = 226mi/2h = 113 mi/h. d = r*t =

Math
csc A = 4/3. sin A = 3/4, x^2 + 9 = 16, X = sqrt7 = 7^(1/2). Cot A = sqrt7/3. sin A + sin A * cot^2 A = 3/4 + 3/4*(7^(1/2))^2 = 3/4+3/4*7 = 24/4 = 6.

Finance
My answer is unsecured debt.

math
Income/wk. = $12/wash * XWASHES = $12X. Cost/wk. = ($12/h*40h)2 + $450/wk. = $1410. Profit/wk. = 12x - 1410 = $3.25/wash * xwashes. = $3.25x. Profit/wk. = 12x - 1410 = 3.25x, X = 161.14 or 162 Washes.

algebra
Vp*t = 1600. Vp*5 = 1600, Vp = 320 mi/h. in still air. (Vp-Vw)*5.5 = 1600. 5.5Vp - 5.5Vw = 1600. 5.5*320 - 5.5Vw = 1600, Vw = ?.

Physics
8 - 5 = 3 N. M*g = 3, M = 3/9.8 = 0.306 kg = Mass of water displaced. V*D = 306 grams. V*1 = 306, V = 306 cm^3. volume of water displaced = volume of candle holder. M*g = 8 N. M = 8/g = 8/9.8 = 0.816 kg = Mass of candle holder. D = 816g/306cm^3 = 2.67 g/cm^3.

Science
F = M*G = 500 * 10 = 5000 N. P = F*d/(t*0.4) = 5000*80/(10*0.4) = 100,000 Watts.

Science
F = M*a. a = F/M. = 15,000/500.

Physics
2. F4 =-(F1*sin90+F2*sin170+F3*sin34.8)F4 = -(70 + 8.68 + 34.2) = -113 N. = 113 N. Downward.

Physics
F1 = 70N[90o]. F2 = 50N[170o], CCW from +x-axis. F3 = 60N[Xo]. 1. The hor. component of F2 and F3 must be equal and opposite: F3*Cos X = -F2*Cos170. 60*Cos X = -50*Cos170, Cos X = 0.82067, X = 34.8o. 2.

Physics
F1 = 70N[90o]. F2 = 50N[170o], CCW from +x-axis. F3 = 60N[Xo]. F3*Cos X = -F2*Cos170. 60*Cos X = -50*Cos170, Cos X = 0.82067, X = 34.8o.

Physics
V = 1000mi/2wks * 1wk./7days * 1day/24h = 2.98 mi/h.

Physics
a. V = Vo + a*t. -45 = 36 + a*0.002, a = ? F = M*a. b. V = Vo + a*t. 45[30o] = 36 + a*0.002, 39 + 22.5i = 36 + a*0.002, 3 + 22.5i = a*0.002, a = 1500 + 11,250i = 11,350 m/s^2[82.4o]. F = M*a = 0.15 * 11,350[82.4o] = 1,702N[82.4o]. Magnitude = 1,702 N.

math
I don't see the scale.

Physics
Range = Vo^2*sin(2A)/g. Range = 65^2*sin(2*37)/9.8 = 414.4 m.

Physics
V = Vo + a*t. 55 = 70 + a*25, a = ?.

Physics
V = 68mi/72min * 60min/h =

Physics
V^2 = Vo^2 + 2g*h. 0 = 69^2 - 19.6h, h = ?. V = Vo + g*t. 0 = 69 - 9.8t, t = ?.

physics
V^2 = vo^2 + 2g*h. V^2 = 0 + 19.6*27, V = 23 m/s.

Math
(x-2)/x > 1/2. 2x-4 > x, X > 4. Let x = 5. (5-2)/5 = 3/5.

math
A diagram of the problem: 1. Draw a rectangle with the longest sides hor. 2. Draw a hor. line through the ver. sides to form two rectangles. 3. Label the ver. sides of the lower rectangle h1(15m) and the ver. sides of the top rectangle h2. 4. Draw a diagonal from the upper ...

math
Tan 17 = h1/d. Tan 17 = 15/d, d = 49.1 m. = Distance between the buildings. Tan32 = h2/d. Tan32 = h2/49.1, h2 = 30.7 m. = ht. from window of 1st bldg. to top of 2nd bldg. h = h1+h2 = 15 + 30.7 = 45.7 m. = ht. of 2nd bldg.

Math
Yes! -9(x-63) = x + (-49) = x-49.

PHYSICS
A window washer pulls herself upward using the bucket-pulley apparatus.. Part A) How hard must she pull downward to raise herself slowly at constant speed? The mass of the person plus the bucket is 80 kg . Part B) If she increases this force by 16 %, what will her acceleration...

physics
The cable supporting a 2150-kg elevator has a maximum strength of 2.2×104 N . What maximum upward acceleration can it give the elevator without breaking?

Physics
1. V^2 = Vo^2 + 2a*d. (3*10^6)^2 = 0 + 2a*0.15, a = ?. 2. F = M*a, a = F/M = 4.9/0.5 =

maths
(75+82+90+X)/4 = 85. X = ?.

physics
See previous post.

physics
V = pi*r^2*(h2-h1). V = 3.14*6^2*(135-120) = 1696 cm^3.

Algebra
1. (3,2), (1,-4) m = (y2-y1)/(x2-x1) = (-4-2)/(1-3) = -6/-2 = 3. 2. (-2,4), (-4,6). m = (6-4)/(-4-(-2)) = 2/-2 = -1. 3. (7,4), (-5,-2). m = (-2-4)/(-5-7) = -6/-12 = 1/2. Y = mx + b 4 = (1/2)7 + b, b = 1/2. Y = (1/2)x + 1/2. 4. (1,4), (2,-8). m = (-8-4)/(2-1) = -12, Y = mx + b...

Math
3pizzas/4bro. = 3/4 Pizza/bro.

Physics
V1 = a1*t1 = 1.76 * 20 = 35.2 m/s. d1 = 0.5a1*t1^2 = 0.88*20^2 = V2 = V1 + a*t = 35.2 - 5.93*5 = 5.55 m/s. The 5-second deceleration is not enough to bring the car to a full stop. d2 = V1*t + 0.5a*t^2. d2 = 35.2*5 - 0.5*5.93*5^2 = d = d1+d2 =

algebra
14x -3 y to the negative 4 / 2x5 y to the negative 2 how do you do this

math
1. I = Po*r*t = 1200*(0.105/12)*3. 2. P = Po + Po*r*t. P = 1200 + 1200*0.0775*2 = 3. 100%-20% = 80% financed. Po = 0.80 * 69,500 =

Math
4. 30/80 = 6/16. Not 6/18.

Math
1. 4/20 = 1/5. Not 1/6.

math
a. 1957 total CDs. X pop CDs. x-256 hip-hop CDs. (x-256)/3 country CDs. x + (x-256) + (x-256)/3 = 1957. Multiply both sides by 3 and solve for x. c. Country CDs/3.

Physics
V2 = V1 + a*t. 60 = 0 + a*4, a = 15 m/s^2. d = V1*t + 0.5a*t^2. V1 = 0, t = 4 s., a = 15 m/s^2, d = ?.

physics
Mb*V1 + Ma*V2 = Mb*V3 + Ma*V4. 5*3 - 10*3 = 5*V3 + 10*2, -15 = 5V3 + 20, V3 = -7 m/s = 7 m/s to the left.

Science
Incomplete.

Science
A. d = Vo*t + 0.5a*t^2. d = 0 + 1*30^2 = B. V = a*t.

physics
Tan A = (-3.50)/116.5 = -0.030043, A = -1.72o = 1.72o S. of E. Tan1.72 = d/153, d = 4.59 m.

Physics
Range = Vo^2*sin(2A)/g. 2.4 = 7^2*sin(2A)/9.8. A = 14.7o. = Minimum launching angle. Max. range occurs at 45o: Range = 7^2*sin(2*45)/9.8 = 5 m., max. Range of launch angles = 14.7 t0 45o.

algebra
t = 4/8 * 32h =

physics
2. Continued. d = V*t, V = 3*10^5 km/s, t = ?.

physics
1. 10^56/10^35 = 2. d = 3.3AU * 1.499*10^8km/AU =

Pre Cal
A ) B + C = 180. A + 62 + 48 = 180, A = 70o. sinB/b = sinA/a. b = ?.

biology
1)Can you suggest reasons why a phylogeny based on molecular evidence and a phylogeny based on morphology and other evidence might not be exactly the same? 2) Zoologist worldwide are sequencing a mitochondrial gene CO1 (cyctochrome c oxidase subunit), which is found in all ...

Physics
M*g = 300 * 9.8 = 2940 N. = Wt. of furniture. Fk = Force of kinetic friction. F1 = 45 N. F2 = 80*Cos25 = 72.5 N. F1+F2 - Fk = M*a. Fk = ?.

Physics
a. V = Vo + a*t. V = 0, Vo = 15 m/s, t = 0.3 s., a = ?. a will be negative. b. F = M*a. F will be negative.

physics
F = 2N/0.2cm * 2cm = 20 H. Work = F*d.

math
X tickets sold. x/6 children's tickets. 40 seniors tickets. X/2 adult tickets. x/6 + 40 + x/2 = X. x/6 + 40 + 3x/6 = x, 4x/6 - x = -40, -2x/6 = -40, X = 120. x/6 = 120/6 = 20. x/2 = 120/2 = 60 2*20 + 3*40 + 6*60 = $520 Collected.

math
Correction: Ignore the "10".

math
10 100ft^2/2 = 50 ft^2/sq. s^2 = 50, s = 7.071 ft. 7.071ft/side * 8sides = 56.57 ft = total required. But we have only 56 ft.

math
At = Ag + Arg. At = 6 + Arg, We need to know the dimensions of the area surrounding the rose garden. Then we could calculate At, the total area which leaves only one unknown(Arg), the area of the rose garden.

Science
d = V*t.

Math
Flour/Milk = Y/X = 5/4. a. Yes. b. Y/X = 5/4, Y/14 = 5/4, Y = ?.

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