Monday

September 15, 2014

September 15, 2014

Total # Posts: 9,067

**physics**

a. F*cos23.2-48.5 = m*a = m*0 = 0 Fcos23.2 = 48.5 F = 48.5/cos23.2 = 52.8 N. b. Work = F*d = 52.8 * 34 = 1795 Joules. c. Work = Fk * d = 48.5 * 34 = 1649 J.
*July 8, 2013*

**math**

-16x^2 + 160t The max. point on the parabola is the vertex: t = Xv = -B/2A = -160/-32 5 s hmax. = Yv = -16*5^2 + 160*5 = 400 Ft. V(5,400).
*July 8, 2013*

**Geometry**

1. A = 400cm * 2cm = 800 cm^2. 2. A = (3.5^2) = 3. A = pi*r^2 = 3.14 * (9/2)^2 =
*July 8, 2013*

**algebra1 HELP PLEASE**

Let y = 0. x^2-7 = 0 x^2 = 7 X = =+-sqrt 7
*July 8, 2013*

**algebra1 HELP PLEASE**

h1(t) = 100 - 0.5*32*t^2. h1 = 100 - 16t^2 = 0 @ gnd. level. 16t^2 = 100 t^2 = 6.25 t = 2.50 s. h2(t) = 210 - 0.5*32*t^2 h2 = 210 - 16t^2 = 0 @ gnd. level. 16t^2 = 210 t^2 = 13.125 t = 3.62 s.
*July 8, 2013*

**physics**

See previous post,4:21 PM.
*July 7, 2013*

**Finance**

2. Increases with every payment and completely repays the loan with the last payment.
*July 7, 2013*

**physics**

Vo = 17m/s[25o] Xo = 17*cos25 = 15.4 m/s. Yo = 17*sin25 = 7.2 m/s. Y = Yo + g*t = 0 @ max. Ht. Tr = -Yo/ g = -7.2/-9.8 = 0.73 s. = Rise time. Tf = Tr = 0.73 s. = Fall time. D = Xo*(Tr+Tf) = 15.4 * 1.46 = 22.5 m. V=(D-12)/(Tr+Tf)=(22.5-12)/1.46=7.19m/s
*July 7, 2013*

**physics**

F = m*a V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = ((350)^2-0)/1.7 = 72,059 m/s^2 F = 0.004 * 72059 = 288 N.
*July 6, 2013*

**physics**

Please clarify your problem.
*July 6, 2013*

**phy**

1. Fn = m*a 40*cos37-Fk = 5 * 3 31.9-Fk = 15 Fk = 31.9-15 = 17 N. 3. a = Fn/m a = (250*cos37-8)/20 = 9.58 m/s^2.
*July 6, 2013*

**math**

The bar means the 2nd 89 REPEATS continuously.
*July 5, 2013*

**physics**

A = 5.0km[135o] B = 7.0km[315o] D = A+B D=(5.0*cos135+7.0*cos315)+i(5.0*sin135+ 7.0*sin315 D = (-3.54+4.95) + i(3.54-4.95) D = 1.41 - i1.41 = 2km[-45o]=2km[45o S of E]. NOTE: The cosine function was used to find the hor. components; the sine function was used to find the ver. ...
*July 4, 2013*

**physics**

A = 100m[0o] B = 200m[270o] C = 50m[3i5o] D = A+B+C D=(100+200*cos270+50*cos315+i(sin270+50*sin315) D = (100+0+35.4) + i(-200-35.4) D = 135.4 - i235.4 = 272m[-60o] = 272m [60o S. of E.].
*July 4, 2013*

**Physics**

A = 3m/s * 20s = 60m[180o]. B = 100m[270o]. C = 2m/s * 20s = 40 m[0o]. D = (A+B)-C A+B = (60*cos180+100*cos270)i(60*sin180+ 100*sin270) A+B = (-60+0) + i(0-100) A+B = -60 - i100 = -116.5[59o] A+B = 116.5[59+180] = 116.5m[239o]. D = (A+B)-C = 116.5[239] - 40 D = -60 - i100 - 40...
*July 4, 2013*

**math 2**

m1 = -A/B = 6/2 = 3. m2 = -12/-4 = 3. The Eqs have equal slopes. Therefore, they are parallel and do not intersect. So there are NO solutions.
*July 4, 2013*

**contemporary math**

P = Po(1+r)^n. P = $50,000 r = (8%/4)/100% = 0.02 = Quarterly % rate expressed as a decimal. n = 4comp./yr * 5.5yrs. = 22 Compounding periods. Plug the above values into the given Eq and solve for Po.
*July 4, 2013*

**Math**

Substitution.
*July 4, 2013*

**Math**

Substitution.
*July 4, 2013*

**math**

See previous post: Mon,7-1-13,10:49 PM.
*July 3, 2013*

**math**

Correction: A =(8/4)^2 * 18 = 72 Ft^2 = Area of the base. V = A*h = 72 * 8 = 576 Ft^3. OR V = (8/4)^3 * 72Ft^3 = 576 Ft^3.
*July 3, 2013*

**math**

18Ft^2*h1 = 72Ft^3 h1 = 72Ft^3/18Ft^2 = 4 Ft. A = (8Ft/4Ft) * 18Ft^2 = 36 Ft^2 = Area of the base. V = A*h = 36Ft^2 * 8Ft = 288 Ft^3.
*July 3, 2013*

**Gen. physics**

V^2 = Vo^2 + 2ad = 0 a = -Vo^2/2d = -(6.4)^2/29 = -1.41 m/s^2
*July 2, 2013*

**physics**

a. V = Vo + g*t = 17 m/s. Vo = 17-g*t = 17-(-9.8*2.2) = 38.56 m/s. b. V = 38.56 -9.8*4.4 = -4.56 m/s. The negative sign means the rock is on its' way down.
*July 2, 2013*

**gen physics**

See Related Questions: Thu,6-27-13,6:00am.
*July 2, 2013*

**gen physics**

A = 71[180o]. B = 71[270o]. a. A+B=(71*cos180+71*cos270)+i(71*sin180+71*sin270) A+B = (-71+0) + i(0-71) A+B = -71 - i71 = -100.4]45o] or 100.4[45o+180o] = 100.4[225o]. Since the resultant is in Q3, 45o is the reference angle. b. A-B=(71*cos180-71*cos270)-i(71sin180-71sin270) A...
*July 2, 2013*

**Algebra**

x(3y) = y(3x) = 3(xy) = 3*y*x.
*July 2, 2013*

**49PM.ath**

See Related Questions: Mon,7-1-13,10:
*July 1, 2013*

**math**

P = Po(1+r)^n. Po = $42,000 r = 11%/100% = 0.11 n = 1comp./yr. * 19yrs = 19 Compounding periods. Plug the above values into the given Eq and solve for P.
*July 1, 2013*

**algebra 1 NEED NOW!!! PLEASE HELPPP**

Since the parabola opens downward, the vertex is the max. point on the curve. Y = -12x^2 + 48x 1. h = Xv = -B/2A = -48/-24 = 2 Seconds. 2. k = Yv = -12*2^2 + 48*2 = 48 Ft. V(x,y)= (2,48). 3. Tr = Tf = 2 s. T = 2 + 2 = 4 s. Tr = Rise time. Tf = Fall time.
*July 1, 2013*

**business math**

See Mon,7-1-13,10:49PM post.
*July 1, 2013*

**Mathematics**

What is 72ten?
*July 1, 2013*

**finance**

D = 10000-0.15*10000 = $8500.
*June 30, 2013*

**Physics**

F = m*a a = V-Vo)/t = (34.4-0)/42 = 0.819 m/s^2. F = 3.6*0.819 = 2.95 N.
*June 30, 2013*

**MATH**

A(-1,-2),P(x,y),B(9,3). x-(-1) = 4(9-x) x+1 = 36-4x 5x = 35 X = 7. y-(-2) = 4(3-y) y+2 = 12-4y 5y = 10 Y = 2. P(7,2).
*June 30, 2013*

**Physics**

V = 6.48*cos9.54 = 6.39 m/s.
*June 30, 2013*

**Physics**

See previous post.
*June 30, 2013*

**Physics**

a=(V-Vo)/t = (26.5-0)/0.55 = 48.2 m/s^2. F = m*a = 929.4 * 48.2 = 44,780 N.
*June 30, 2013*

**Discrete Math**

CORRECTION:BCD should be BCDA
*June 30, 2013*

**Discrete Math**

8 different passwords were formed: ABCD BCD CDAB DABC. DCBA CBAD BADC ADCB
*June 30, 2013*

**math**

Move the decimal 8 places to the right. 7.5*10^8 = 750,000,000
*June 30, 2013*

**math**

1. P = Po(1+r)^n. Po = $500,000. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 5yrs. = 20 Compounding periods. Plug the above values into the given Eq. and solve for P. 2. P = Po(1+r)^n. r = APR = (8%/100% = 0.08 n = 1comp./yr. * 5yrs. = 5...
*June 29, 2013*

**trig**

X ^5 - 11 = 0 X^5 = 11 (X^5)^(1/5) = (11)^(1/5) X = 1.615.
*June 28, 2013*

**physics**

See Related Questions: Thu,6-27-13,6:ooAM.
*June 28, 2013*

**Business Math**

P = Po(1+r)^n. Po = 50000 r = (1.6%/2)/100% = 0.008 = Semi-APR. n = 2comp./yr. * 5yrs = 5yrs = 10 Compounding periods. Plug the above values into the given Eq and solve for P.
*June 27, 2013*

**Business Math**

P = Po(1+r)^n P = $27,500 Po = Initial investment. r = (6%/12)/100% = 0.005 = Monthly % rate expressed as a decimal. n = 12comp/yr. * 3yrs = 36 Compounding periods. P = Po(1.005)^36 = 27500 Po = 27500/(1.005)^36 = $22,980.
*June 27, 2013*

**Business Math**

APY = The interest for 1 year divided by the initial investment: APY = (I/Po)*100%.
*June 27, 2013*

**Business Math**

CORRECTION: n = 4Comp./yr. * 1yr. = 4 Compounding periods.
*June 27, 2013*

**Business Math**

P = Po(1+r)^n. Po = $1,000,000. r = (8%/4)/100% = 0.02 = Quarterly % .rate expressed as a decimal. n 4Comp./yr. * 8trs = 32 Compounding periods. Plug the above values into the given Eq and solve for P. I = P-Po.
*June 27, 2013*

**Business Math**

P = Po(1+r)^n. Po = $7700. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs = 20 Compounding periods. Plug the above values into the given Eq and get: P = $10,370.78
*June 27, 2013*

**physics**

Vo = 85m/s[45o]. Xo = 85*cos45 = 60.1 m/s. Yo = 85*sin45 = 60.1 m/s. Tr = (Y-Yo)/g = (o-60.1)/-9.8 = 6.1 s. = Rise time. h = Yo*t + 0.5g*t^2 h = 60.1*6.1 - 4.9*(6.1)^2 = 184.3 m. d = Yo*t + 0.5g*t^2=184.3 + 120=304.3m 0 + 4.9t^2 = 304.3 t^2 = 62.1 Tf = 7.9 s. = Fall time. d =...
*June 27, 2013*

**physics**

V*t = 17 m. 42.4 * t = 17 t = 0.40 s. d = 0.5g*t^2 g = 9.8m/s^2
*June 27, 2013*

**To Mara; Re: algebra**

L = 10-X. Your Eq is correct.
*June 27, 2013*

**physics**

V1*t = V2*t-37 m. 5.95t = 7.80t-37 7.8t-5.95t = 37 1.85t = 37 t = 20 s. d = 5.95 * 20 = 119 m
*June 27, 2013*

**Science**

Dw/Dl = 4/5 800/Dl = 4/5 4Dl = 4000 Dl = 1000 kg/m^3. = Density of the fluid.
*June 26, 2013*

**maths**

P1 = 1.08*65000 = 70200. (P1+P2)/2 = 66,300 (70,200+P2)/2 = 66300 70200+P2 = 132,600 P2 = 62400 Loss = 65000-62400 = 2600 %Loss = 2600/65000 = 0.04 = 4%. 2. 1kg/0.95kg = 1.0526 = 105.26 %. %Gain = 105.3% - 100% = 5.3%.
*June 26, 2013*

**math 4th grade**

See previous post.
*June 26, 2013*

**math 4th grade**

Population = 500,000km^2 * 20p/km^2 = 10,000,000 People.
*June 26, 2013*

**Physics**

Wp = m*g = 60kg * 9.8N/kg = 588 N. = Wt. of the person. Fp = 588*sin25 = 248.5 N. = Force parallel to plane. Fv = 588*cos25 = 533 N. = Force perpendicular to plane Fk = 0.450 * 533 = 240 N. = Force of kinetic friction. Fn = m*a a = Fn/m = (Fp-Fk)/m a = (248.5-240)/60 = 0.142 m...
*June 25, 2013*

**physics**

Fn = m*a = 0.1*10 = 1 N.
*June 24, 2013*

**physics**

F = m*a a = F/m = 80000/9.7 = 8247 m/s^2 V = Vo + a*t t = (V-Vo)/a = (6500-0)/ 8247 = 0.788 s.
*June 24, 2013*

**physics**

See previous post.
*June 24, 2013*

**physics**

Because the velocity at any instant depends on the time of the acceleration.
*June 24, 2013*

**Physics**

h = Vo*t + 0.5g*t^2 = 1.5 m. 0 + 4.9t^2 = 1.5 t^2 = 0.306 Tf = 0.553 s. = Fall time. D1 = V*Tf = 30m/s * 0.553s = 16.6 m. D2 = 35m/s * 0.553s = 19.4 m.
*June 24, 2013*

**MATH**

6 + 4*7/14 - 1 = 7 6 + 28/14 _ 1 = 7 6 + 2 - 1 = 7 7 = 7
*June 24, 2013*

**conceptual science**

a. V = Vo-g*t V = Vo-9.8m/s^2*1s V = Vo-9.8m/s. s. The speed decreases by 9.8 m each second. b. V = Vo + g*t V = Vo + 9.8m/s^2*1s V = Vo + 9.8m/s. The speed increases by 9.8 m each second. c. V = Vo + g*t = 0 @ max. ht. Vo + g*t = 0 Vo - 9.8t = 0 9.8t = Vo Tr = Vo/9.8 = Rise ...
*June 23, 2013*

**physics**

What is the question?
*June 23, 2013*

**physics**

V*t = 17 m. t = 17/V = 17/37.8 = 0.1852 s. d = 0.5g*t^2. g = 9.8 m/s^2.
*June 23, 2013*

**physics**

Vo = 26.5m/s[32.2o]. Xo = 26.5*cos32.2 = 22.4 m/s. Yo = 26.5*sin32.2 = 14.1 m/s Y = Yo + g*Tr = 0 @ max. ht. Tr = -Yo/g = -14.1/-9.8 = 1.44 s. = Rise time. D = Xo * Tr = 22.4m/s * 1.44s. = 32.3 m.
*June 23, 2013*

**physics**

Vo = 16.7m/s[33o]. Yo = 16.7*sin33 = 9.1 m/s. Y^2 = Yo^2 + 2g*h = 0 hmax= Yo^2/2g = -(9.1)^2/-19.6 = 4.23 m. V^2 = Vo^2 + 2g*d V^2 = 0 + 19.6*(4.23-2.6) V^2 = 19.6 * 1.625 = 31.85 V = 5.64 m/s.
*June 23, 2013*

**physics**

Correction: X = 4.15 m/s.
*June 23, 2013*

**physics**

X = Xo + a*t X = 3.2 + 1.9*0.5 = 4.15 m/s^2 Y = Yo + a*t Y = 8.1 - 6.2*0.5 = 5 m/s. a. V^2 = X^2 + Y^2 V^2 = (4.15)^2 + 5^2 = 42.2 V = 6.5 m/s. b. tan A = Y/X = 5/4.15 = 1.20482 A = 50.31o = Direction.
*June 23, 2013*

**physics**

See previous post.
*June 23, 2013*

**physics**

Vo = 12m/s[53.2o]. Xo = 12*cos 53.2 = 7.2 m/s. NOTE: The hor. component remains constant during the flight.
*June 23, 2013*

**physics**

a. V^2 = Vo^2 + 2a.d a = (V^2-Vo^2)/2d. a = (6.14-0)/26.8 = 0.229 m/s^2 b. a = 0.229*cos 32.6 = 0.193 m/s^2, c.
*June 23, 2013*

**physics**

tan A = Y/X = -558/925 = -0.60324 A = -31o D = 925/cos(-31) = 1080 m.
*June 23, 2013*

**physics**

See Related Questions: Tue,6-18-13,9:43PM.
*June 23, 2013*

**math**

translate the phrase into a mathematical expression and then evaluate it. sixtten squared divided by four cubed. The given expression in symbols is? (do not simplify. type exponential notation with positive exponents.) Evaluated, the expression is equal to? (simplify your answer)
*June 23, 2013*

**Physics**

x/0.017 = 22/1 X = 0.374 N. Work=F*d = 0.374 * 0.017=0.0064 Joules.
*June 23, 2013*

**science**

P = V*I = 2000 W. 220I = 2000 I = 9.09 Amps. The current too high for the circuit. If the circuit is properly protected, the fuse will blow or the circuit breaker will trip.
*June 23, 2013*

**Math**

I = Po*r*t = $23. 820*(r/360)*52 = 23 118.44444r = 23 r = 0.194 = 19.4 %.
*June 22, 2013*

**math**

P = Po(1+r)^n P = 8000+1261 = 9261. Po = 8000. n = 1comp./yr. * 3 yrs. = 3 Compounding periods. r = ? 8000(1+r)^3 = 9261. Divide both sides by 8000: (1+r)^3 = 1.157625. Take cube of both sides: 1+r = 1.05 r = 0.05 = 5% per yr.
*June 22, 2013*

**math**

P = Po + Po*r*t = 2600 2000 + 2000*(0.06/360)t = 2600 2000 + t/3 = 2600 t/3 = 2600-2000 = 600 t = 1800 Days. t = 1800Days / 360Days/yr. = 5 Yrs. Ordinary int. is based on 360 days/yr.
*June 22, 2013*

**business math**

C = 0.026*60000 + 0.034*(89400-60000) C = 1560 + 999.60 = $2559.60.
*June 22, 2013*

**physics**

tan A = Y/x = -4/2 = -2.0 A = -63.43o = 63.43o South of East. tan(-63.43) = d/10m d = 10*tan(-63.43) = -20 m = 20 m. South of starting point.
*June 22, 2013*

**physics**

V^2 = Vo^2 + 2g*d. Vo = 12 Ft/s. g = 32FT/s^2. d = 4.5 Ft. Plug the given values into the Eq and solve for V in Ft/s.
*June 21, 2013*

**physics**

V = Vo + a*t a = (V-Vo)/t a=(300-150)/(1/12)h=1800=1800 mi/h^2 V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a. d = (90000-22500)/3600 = 18.75 Miles.
*June 21, 2013*

**trig**

A + B = 90o A + 31 = 90 A = 59o. c*sin 59 = 3. c = 3/sin59 = 3.50 tan 59 = 3/b b = 3/tan 59 = 1.80
*June 21, 2013*

**Math 116**

See previous post.
*June 21, 2013*

**Math 116**

Multiply Eq1 by -6: -6x - 18y = -30 +6x - 6y = 14 Add the Eqs: -24y = -16 Y = 2/3. In Eq1, replace Y with 2/3: x + 3*2/3 = 5 x + 2 = 5 X = 3.
*June 21, 2013*

**Math 116**

Eq1:-6x - 2y = 12 Eq2:12x - 4y = -24 Multiply Eq1 by -4 and Eq2 by 2: 24x + 8y = -48 24x - 8y = -48 Add the Eqs: 48x = -96 X = -2. In Eq1, replace X with -2: -6*(-2) - 2y = 12 12 - 2y = 12 -2y = 12-12 = 0 Y = 0 (-2,0).
*June 21, 2013*

**Math Algebra1A**

Those are the only 2 that I know.
*June 20, 2013*

**grade 4 math**

10^x = 59,187 Take Log of both sides: x*Log 10 = Log 59187 X = Log59187/Log 10 = 4.77223. 10^4.77223 = 59187.
*June 20, 2013*

**math**

Monthly Salary = $X. Spends1/4 * $X = X/4. Bal. = X-X/4 = 3x/4. Spends1/5 * 3x/4 = 3x/20 Bal.=3x/4-3x/20 = 15x/20-3x/20=12x/20= 3x/5. Transportation: 1/10 * 3x/5 = 3x/50 Bal.=3x/5 - 3x/50 = 30x/50-3x/50=27x/50. 27x/50 = 630 27x = 31500 X = $1166.67.
*June 20, 2013*

**physics**

See previous post.
*June 20, 2013*

**physics**

See previous post.
*June 20, 2013*

**physics**

Vavg. = (30+45)/2 = 37.5 km/h.
*June 20, 2013*

**algebra**

Vb + Vc = 22 Vb - Vc = 8 Add the Eqs: 2Vb = 30 Vb = 15 mph. Replace Vb in Eq1 with 15: 15 + Vc = 22 Vc = 7 mph = Velocity of the current.
*June 19, 2013*

**Math**

787/9 = 87 Strawberries/carton. Bal. = 87 * 5 = 435 Strawberries 435strawberries/5strawberries/carton = 87 Cartons.
*June 19, 2013*

**physics**

h = 0.5g*t^2 = 81.6 m. 4.9t^2 = 81.6 t^2 = 16.65 t = 4.08 s. to hit ground. d = 9.13-4.30 = 4.83 m. = Distance the boat traveled in 4.08 s. Speed = d/t = 4.83/4.08 = 1.18 m/s.
*June 18, 2013*

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