Tuesday
May 31, 2016

Posts by Henry

Total # Posts: 11,831

physics
X = 10 km/h Y = 2 km/h V^2 = X^2 + Y^2 = 10^2 + 2^2 = 104 V = 10.20 m/s.
November 30, 2014

physics
h max = R/2 = 150m/2 = 75 m. h max = 0.5g*t^2 = 75 4.9*t^2 = 75 t^2 = 15.31 Tf = 3.91 s. = Fall time. Tr = Tf = 3.91 s. = Rise time. V = Vo + g*t = 0 @ max ht. Vo = -g*t = -(-9.8*3.91) = 38.34 m/s. = Initial velocity. R = Vo^2*sin(2A)/g = 100 m. 38.34^2*sin(2A)/9.8 = 100 150*...
November 30, 2014

math
Incomplete.
November 30, 2014

physics
See previous post: Sat, 11-29-14, 11:06 PM.
November 30, 2014

physics
d = Vo*t + 0.5a*t^2 = 40*15 + 8*15^2/2 = 1500 m.
November 30, 2014

physics
Vo = 50mi/h * 1600m/mi * 1h/3600s. = 22.22 m/s. V = Vo + a*t = 0 When stopped. t = -Vo/a = -22.22/-7=3.17 s. To stop.
November 30, 2014

trigonometry
1. Va=(1/2)rev/2min * 6.28rad/rev= 1.57 rad/min. 2 thru 6. Same procedure as #1.
November 30, 2014

physics
a = V-V0)/t = (60-0)/7.2 = 8.33 m/s^2. F = M*a
November 29, 2014

Math (Expectation)
Robyn: M = 2mi/day * d days = 2*d = 2d.
November 29, 2014

physics
M*g = 20 * 9.8 = 196 N.=Wt. of suitcase. a. a = Fx/M = 50*cos30/20 = 2.17 m/s^2. b. Fn = 196 - 50*sin30 = 171 N.=Normal force = Force exerted on the bag by the floor.
November 29, 2014

physics
Output = 0.9333 * 75kW
November 29, 2014

two step equation-fraction
(4+m)/3 = 5/6 Multiply both sides by 6: 2(4+m) = 5 Multiply both terms inside the parenthesis by 2: 8 + 2m = 5 Subtract 8 from both sides: 8-8 + 2m = 5-8 0 + 2m = -3 2m = -3 Divide both sides by 2: m = -3/2 = -1 1/2.
November 29, 2014

math
See Related Questions: Tue,11-12-13, 9:28 AM.
November 29, 2014

physics
d = 44 Ft. g = 32 Ft/s^2 u = 0.50? Vo = ? a = u*g = 0.50 * (-32) = -16 Ft/s^2 V^2 = Vo^2 + 2a*d = 0 Vo^2 = -2a*d = -(-32*44) = 1408 Vo = 37.5 Ft/s.
November 29, 2014

physics
2m/s * 33s/3.5rev = 18.857 m/rev = Circumference(C). C = pi*2r = 18.857 m. 6.28r = 18.857 r = 3 m.
November 29, 2014

maths
Tan A = Y/X = (22-1.5)/20.5 = 20.5/20.5 = 1. A = 45o.
November 29, 2014

math
5/2 - 3/8 * Log3 = 2.321
November 29, 2014

Pyhsics
A. M*1.17g = 34.9 N. M*1.17*9.8 = 34.9 M*11.47 = 34.9 M = 3.04 kg B. 3.04 * a = 19.2 N. a = 6.31 m/s^2 on planet X. Note: It is the free-fall acceleration that changes; the mass remains constant.
November 28, 2014

math
Post it.
November 28, 2014

Physics
a. W = F*d = 453*Cos37 * d = 4820 J. d = 13.3 m. b. Fx-Fk = M*a 453*Cos37-Fk = M*0 = 0 Fk = 453*Cos37 = 361.8 N. = Force of kinetic friction. c. W = Fk*d = 361.8 * 13.3 = 4812 J. d. W = M*V^2/2 = 4820 J. M*7.82^2/2 = 4820 M*30.58 = 4820 M = 157.6 kg = Mass of the crate. M*g = ...
November 26, 2014

AP Physics
What is the question?
November 25, 2014

business math
I=Po*r*t = 3600*(0.088/365)*207=$179.66 = Penalty.
November 25, 2014

MAT201 Basic Statistics
Incomplete.
November 24, 2014

Pre algebra
X = Minutes used. Y = T0tal cost in Dollars. (X,Y), (20,48), (35,54), (40,56). m = (Y2-Y1)/(X2-X1)=(54-48)/(35-20) = 0.40 = Slope. (20,48) Y = mX + b = 48 0.4*20 + b = 48 b = 40 Eq: Y = 0.4X + 40
November 24, 2014

Math with business apps
P = Po * (1+r)^n r = (3%/12)/100% = 0.0025 = Monthly % rate expressed as a decimal. n = 12Comp./yr * 15 yrs. = 180 Compounding periods. Solve for P. I = P-Po
November 24, 2014

Math with business apps
See previous post: Mon,11-24-14, 6:31 PM
November 24, 2014

MATH!!
P = Po * (1+r)^n r = (4%/4)/100% = 0.01 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs. = 20 Compounding periods. Solve for P. 2nd investment = P + $500 @ 5% for 5 yrs.
November 24, 2014

math
Mr. Beach: X min. Ms. Johnson: 2x min. Mrs. Rodriguez: (X+10) min. x+10 = 35 min. X = 25 min. 2x = 50 min. Total = 35 + 25 + 50 = 110 Min.
November 24, 2014

Math
P = Po*(1+r)^n r = (3%/12)/100% = 0.0025 = Monthly % rate expressed as a decimal. n = 12Comp./yr. * 15yrs. = 180 Compounding periods. Solve for P. I = P-Po
November 24, 2014

Math
P = Po * (1+r)^n r = (6.5%/12)/100% = 0.00542 = Monthly % rate expressed as a decimal. n = 1Comp./mo * 18mo = 18 Compounding periods. Solve for P.
November 24, 2014

math
B: X min. A: (X+36) min. A/B = (x+36)/x = 6/5 5x + 180 = 6x 5x - 6x = -180 -X = -180 X = 180 min. X+36 = 180+36 = 216 min.
November 24, 2014

physics
See previous post.
November 23, 2014

physics
a = (V^2-Vo^2)/2d = (0-(22.9^2)/149.2 = -3.51 m/s^2. F = m*a =1949.1 * (-3.51) = -6851 N. Note: The negative sign means that the force opposes the motion.
November 23, 2014

Physics
See previous post: Sun,11-23-14, 12:08 AM.
November 23, 2014

Physics
False.
November 23, 2014

Physics
Vo = 9.2m/s[47o] Xo = 9.2*Cos47 = 6.27 m/s. Yo = 9.2*sin47 = 6.73 m/s. a. Y = Yo + g*Tr = 0 @ max ht. Tr = -Yo/g = -6.73/-9.8 = 0.687 s. = Rise time or time to reach max ht. b. h max = ho + Yo*Tr + 0.5g*Tr^2 = 6.6 + 6.73*0.687 - 4.9*0.687^2 = 8.91 m. Above gnd. c. h = 0.5g*Tf^...
November 23, 2014

Physics
Vo = 215km/h = 215,000m/3600s.=59.72 m/s V = Vo + a*t = 0. Vo + a*t = 0 Solve for a; it should be negative.
November 23, 2014

Physics
Range = Vo^2*sin(2A)/g = 16 m. Vo^2*sin(110)/9.8 = 16 0.09589Vo^2 = 16 Vo^2 = 166.863 Vo = 12.92 m/s.
November 23, 2014

capacitors
Not enough INFO.
November 23, 2014

physics
Tf = 4/2 = 2 s. = Fall time. h = 0.5g*Tf^2 = 4.9 * 2^2 = 19.6 m.
November 23, 2014

Physics
V1 = a*t1 = 0.6rad/s^2 * 10s. = 6 rad/s. d1 = 0.5a*t1^2 = 0.3*10^2 = 30 Radians. d2=V1*t2 = 6rad/s. * 20s. = 120 Rad1ans V2 = V1 + a*t3 = 0 6 + a*10 = 0 10a = -6 a = -0.60 m/s^2 V2^2 = V1^2 + 2a*d = 0 d2 = -(V1^2)/2a = -(6^2)/-1.2 = 30 Rad. V=(d1+d2)/(t1+t2+t3)=(120+30)/(10+20...
November 23, 2014

physics
See Related Questions: Tue, 9-2-14, 11:13 AM.
November 22, 2014

physics
See previous post.
November 22, 2014

physics
M*g = 70.4kg * 9.8N/kg = 689.9 N. = Wt. of skier. Fp = 689.9*sin36.8 = 413.3 N. = Force parallel to the incline. Fn = 689.9*Cos36.8 = 552.4 N. = Normal force = Force perpendicular to the incline. Fk = u*Fn = 0.14 * 552.4 = 77.34 N. = Force of kinetic friction. a = (Fp-Fk)/M...
November 22, 2014

physics
a = (V-Vo)/t = (66-0)/4.5 = 14.67 m/s^2. F = M*a
November 22, 2014

Physics
A. X = 1.5 m/s Y = 2 m/s. TanA = Y/X = 2/1.5 = 1.33333 A = 53o, CCW = 90-53 = 37o E. of N. or [N37E].
November 22, 2014

Physics
M*g = 4kg * 9.8 N./kg = 39.2 N. = Wt. of the bundle. KE = M*Vo^2/2 = 128 J. 4*Vo^2/2 = 128 Vo^2 = 64 Vo = 8 m/s = Initial velocity. a = u*g = 0.3 * (-9.8) = -2.94 m/s^2. V^2 = Vo^2 + 2a*d = 0 @ max ht. Vo^2 + 2a*d = 0. Solve for d.
November 22, 2014

physics
The position versus time for a certain object moving along the x-axis is shown. The object’s initial position is −2 m. Find the instantaneous velocity at 6 s. Answer in units of m/s
November 21, 2014

Math
P1 = Po*(1+r)^n. Compounded annually. r = 12%/100% = 0.12 = Annual % rate expressed as a decimal. n = 1Comp./yr. * 4yrs. = 4 Compounding periods. P1 = 6,000*(1.12)^4 = $9441.12 P2 = Po*(1+r)^n. Compounded quarterly. r = (12%/4)/100% = 0.03 = Quarterly % rate. n = 4Comp./yr. * ...
November 21, 2014

physic
Vo = 55m/s[30o] Xo = 55*Cos30 = 47.63 m/s Yo = 55*sin30 = 27.5 m/s. a. Y = Yo + g*Tr = 0 @ max ht. Tr=-Yo/g = -27.5/-9.8 = 2.806 s.=Rise time. Tf = Tr = 2.806 s. = Fall time. Tr+Tf = 2.806 + 2.806 = 5.61 = Time in air. b. Dx = Xo*(Tr+Tf) = 47.63m/s * 5.61s = 267.3 m. from base...
November 21, 2014

physics
a. Correct The last sentence in your problem is incomplete.
November 21, 2014

MATH
2AB + AB1 = 2AB + 1AB = 3AB.
November 21, 2014

math
Incomplete.
November 21, 2014

physics
Mass = 200kg? Vo = 15 m/s. V = 25 m/s. t = 10 s. a = (V-Vo)/t = (25-15)/10 = 1 m/s^2. F = m*a = 200 * 1 = 200 N. d = Vo*t + 0.5g*t^2=15*10 + 4.9*10^2 = 640 m. W = F*d = 200 * 640 = 128,000 Joules.
November 21, 2014

math
Correction: T = 10/3-6/5 = 50/15 - 18/15 = 32/15 = 2.1333 h Vp+Vw = 900/2.1333 = 421.875 mi/h Vp = (270+421.875)/2 = 346 mi/h = Velocity of the plane without wind.
November 21, 2014

math
Vp-Vw=900/(10/3) = 900 * 3/10 = 270 mi/h Vp+Vw=900/(50/60)=900 * 60/50=1080 mi/h Vp - Vw = 270 Vp + Vw = 1080 Sum: 2Vp = 1350 Vp = 675 mi/h. = Velocity of plane without the wind.
November 21, 2014

Physics
M*g = 310kg * 9.8N/kg = 3,038 N. = Wt. of the crate = Normal force(Fn). Fap-Fk = M*a (440+230)-Fk = M*0 = 0 670 - Fk = 0 Fk = 670 N. = Force of kinetic friction uk = Fk/Fn = 670/3038 = 0.221
November 21, 2014

physics
d = 0.5a*t^2 = 200 m. 0.5a*19.5^2 = 200 190.125a = 200 a = 1.052 m/s^2. V = a*t = 1.052m/s^2 * 1.7s = 1.788 m/s.
November 20, 2014

physics
Vo = 1000m/s[24o] Xo = 1000*Cos24 = 913.5 m/s. Yo = 1000*sin24 = 406.7 m/s. h1=Yo*t + 0.5a*t^2=406.7*2 + 7.5*2^2 = 843.4 m Y1 = Yo + a*t = 406.7 + 15*2=436.7 m/s. Y2 = Y1 + g*t = 0 @ max ht. t = -Y1/g = -436.7/-9.8 = 44.56 s. Tr = t+2 = 44.56 + 2 = 46.56 s. = Rise time or time...
November 20, 2014

ap physics
See Related Questions: Sun, 9-2-14, 11:13 AM.
November 20, 2014

physics
Range = Vo^2*sin(2A)/g = 10.1 m. Vo^2*sin(90.8)/9.8 = 10.1 0.102Vo^2 = 10.1 Vo^2 = 98.99 Vo = 9.95 m/s.
November 20, 2014

Math
A different Method: X Grams per apple. Y Grams = Wt. of basket. Eq1: 12x + Y = 3105 Eq2: 7x + Y = 1980 Diff: 5x = 1125 X = 225 In Eq1, replace X with 225: 12*225 + Y = 3105 Y = 3105 - 2700 = 405.
November 20, 2014

Math
Correction: After removing 5 apples, we took the reduction in Wt.(1125grams) and divided by the # of apples removed(5). That gave us the wt. per apple.
November 20, 2014

Math
(3105-1980)/(12-7) = 225 grams/apple 3105 - (12*225) = 405 grams = Wt. of the basket. 1980 - (7*225) = 405 grams = Wt. of basket. Note: After removing 7 apples, we took the remaining wt(1125grams) and divided by the remaining # of apples(5). That gave us the Wt. per apple.
November 20, 2014

physics
M*g = 13 * 9.8 = 127.4 N. = Wt. of box = Normal force(Fn). Fap-Fs = M*a 47 - Fs = M*0 = 0 Fs = 47 N. = Force of static friction. us = Fs/Fn = 47/127.4 = 0.369
November 20, 2014

physics
V8y^2=X^2 + Y^2 = 3.98^2 + (-3.16)^2=25.83 V = 5.08 m/s. Momentum = M*V = 4.53 * 5.08 = 23 kg.m/s
November 20, 2014

Physics
KE = M*V^2/2 = 3.54*596^2/2 = 628,732 J
November 20, 2014

Science
M*g = 32kg * 9.8m/kg = 313.6 N. = Wt. of crate. = Normal force(Fn). Fk = u*Fn = 0.57 * 313.6 = 178.8 N. = Force of kinetic friction. F-Fk = M*a F-178.8 = 32 * 1.8 = 57.6 F = 57.6 + 178.8 = 236.4 N.
November 20, 2014

physics
h = 0.5g*t^2 = 40 m 4.9t^2 = 40 t^2 = 8.16 Tf = 2.86 s. = Fall time. Dx = V*Tf = 1.2m/s * 2.86s = 3.43 m.
November 20, 2014

physics
a = u*g = 0.8 * (-9.8) = -7.84 m/s^2 V = Vo + a*t = 0 27 - 7.84*t = 0 -7.84t = -27 t = 3.44 s.
November 20, 2014

physics
Incomplete.
November 20, 2014

Physics
F = m*g = 1*10^4kg * 9.8N/kg = 9.8*10^4N P = F*d/t = 9.8*10^4 * 20/5 = 3.92*10^5 J/s = 3.92*10^5 Watts. = 3.92e5 Watts. Note: Your Eq should have been m*g * d/t You omitted g(9.8m/s^2).
November 19, 2014

physics
V^2 = Vo^2 + 2a*d V = 561 m/s Vo = 0 d = 0.976 m. a = ?
November 19, 2014

physics
V = Vo + a*t
November 19, 2014

physics
Y^2 = Yo^2 + 2g*h = 0 @ max ht. Yo^2 = - 2(-9.8)*45 = 882 Yo = 29.7 m/s = Vertical component of initial velocity. Vo*sin50 = Yo = 29.7 Vo = 38.8 m/s.
November 19, 2014

Math
P = Po*(1+r)^n r = (7%/4)/100% = 0.0175 = Quarterly % rate expressed as a decimal. n = 4 Comp./yr. * 7yrs. = 28 Compounding periods. P = Po*(1.0175)^28 = 30,000 Po = 30,000/(1.0175)^28 = $18,456.85 = Initial deposit.
November 19, 2014

Math
Find the value of b, if any, that will make the function differentiable at x = 0 g(x)= { x+b, x<0 cos(x), x≥0 can you help, I got 0 but I don't know if that will make the function differential at x=0.
November 18, 2014

Math
Find the value of b, if any, that will make the function differentiable at x = 0 g(x)= { x+b, x<0 cos(x), x≥0 can you help, I got 0 but I don't know if that will make the function differential at x=0.
November 18, 2014

5th grade math
X = Total # of flowers. Pink = X/4 Flowers. Bal. = X - X/4 = 3x/4 Red = 2/5 * 3x/4 = 6x/20=3x/10 Flower. Yellow = 18 X/4 + 3x/10 + 18 = X Multiply both sides by 20: 5x + 6x + 360 = 20x 11x - 20x = -360 -9x = -360 X = 40
November 18, 2014

physics
Momentum = M*(V-Vo) = 2*(8-0) = 16 J/s.
November 18, 2014

Physics
M1*V1 + M2*V2[90o] = 2.59m/s[23.9o] 8.34*2.4 + 0.170*V2[90o] = 2.59[23.9o] 20.02 + 0.170*V2[90] = 2.37 + 1.05i 0.170V2[90] = 2.37-20.02 + 1.05i 0.170V2[90] = -19 + 1.05i 0.170V2{90] = 19.03[176.8o] V2 = 112m/s[86.8o] = Velocity of the puck.
November 18, 2014

math
Compounded Int. P1 = Po(1+r)^n r = 4.8%/100 = 0.048 = Annual % rate expressed as a decimal. n = 1Comp./yr. * 10Yrs. = 10 Compounding periods. P1 = 850(1.048)^10 = $1358.41 Simple Int. P2 = Po + Po*r*t = 850 + 850*0.048*10 = $1258.00 P1-P2 = 1358.41 - 1258 = $100.41
November 17, 2014

science
M*g = 2000kg * 9.8N./kg = 19,600 N. = Wt of car. = Normal Force(Fn). a = u*g = 0.2 * (-9.8) = -1.96 m/s^2. d = -Vo^2/2a = -(27^2)/-3.92 = 186 m. = Stopping distance.
November 17, 2014

math
See previous post
November 17, 2014

math
See previous post.
November 17, 2014

algebra
L(x) = 100*e^-1.5 = 100*0.22313=22.313 %
November 17, 2014

algebra
I(30) = 81,000 - 45,000e^-0.005t = 81,000 - 45,000*e^(-0.15) = $42,268.14 I(130) = 81,000 - 45,000*e^(-0.65) = b. I(approach): 81,000 - 0 = $81,000
November 17, 2014

MATH
X = # heads to begin the day. (X-24) = Bal. after morning sale. (2/7)*(X-24) sold during afternoon. Bal. = (5/7)*(X-24) = X/2 (10/7)(X-24) = X (10x-240)/7 = X 10x - 240 = 7x 10x - 7x = 240 3x = 240 X = 80
November 17, 2014

physical
Fk = u*Fn = 40. Solve for Fn
November 17, 2014

physics
I agree with your answer.
November 17, 2014

physics
M = 70.3 kg = Mass of the person. Dj = Density of the jacket. Vj = 0.0307 m^3 = Vol. of the jacket. Dp = Density of the person. Vp = 0.0649 m^3 = Vol. of the person. Dw = 1000kg/m^3 = Density of water. Mj+Mp = (Vj+Vp) * Dw Mj+Mp = 0.0956m^3 * 1000kg/m^3=95.6 kg Mj = 95.6 - Mp...
November 16, 2014

Physics
M*g = 25kg * 9.8N./kg = 245 N. = Wt. of the box = Normal force. Fk = u*Fn = 0.55 * 245 = 134.75 N. = Force of kinetic friction. a. Fp-Fk = M*a Fp - 134.75 = M*0 = 0 Fp = 134.75 N. = Pulling force. b. F(net) = Fp-Fk = 350 - 134.75 = 215.3 N. c. a = (Fp-Fk)/M = 215.3/25 = 8.61 m...
November 16, 2014

physics grade 11
See previous post.
November 16, 2014

physical education
KE = M*Vo^2/2 = 196 J. 1*Vo^2/2 = 196 Solve for Vo. V^2 = Vo^2 + 2g*h = 0 @ max ht. h = -Vo^2/2g. g = -9.8 m/s^2 Solve for h.
November 16, 2014

physics
They are asking for the PE at A only: PE = m*g*h1
November 16, 2014

physics
See previous post: Sat,11-15-14, 5:29 PM.
November 16, 2014

physics
V^2 = V1^2 + 2g*h = 0 @ max ht. Vo^2 = -2g*h = 19.6*24.2 = 474.32 Vo = 21.8 m/s = Initial velocity. h = (V^2-Vo^2)/2g = (0-(21.8^2)/-3.2 = 148.3 m.
November 15, 2014

physics
See previous post: 5:29 PM.
November 15, 2014

physics
See previous post: 5:29 PM.
November 15, 2014

physics
1. V = (85,000/500,000) * 54,540,000 m^3 2. Dw = 1g/cm^3 = 1,000kg/m^3 = Density of water. Mass(kg) = V * 1000 3. h1 = 74 m, h2 = 221, h3 = 55 h = (h2-h1) + h3. 4. PE(gained) = mg*h - Mg*h1 PE/Mass = PE gained per kg of water.
November 15, 2014

  1. Pages:
  2. <<Prev
  3. 14
  4. 15
  5. 16
  6. 17
  7. 18
  8. 19
  9. 20
  10. 21
  11. 22
  12. 23
  13. 24
  14. 25
  15. 26
  16. 27
  17. 28
  18. Next>>