Monday
September 15, 2014

Posts by Henry


Total # Posts: 9,067

physics
a. F*cos23.2-48.5 = m*a = m*0 = 0 Fcos23.2 = 48.5 F = 48.5/cos23.2 = 52.8 N. b. Work = F*d = 52.8 * 34 = 1795 Joules. c. Work = Fk * d = 48.5 * 34 = 1649 J.
July 8, 2013

math
-16x^2 + 160t The max. point on the parabola is the vertex: t = Xv = -B/2A = -160/-32 5 s hmax. = Yv = -16*5^2 + 160*5 = 400 Ft. V(5,400).
July 8, 2013

Geometry
1. A = 400cm * 2cm = 800 cm^2. 2. A = (3.5^2) = 3. A = pi*r^2 = 3.14 * (9/2)^2 =
July 8, 2013

algebra1 HELP PLEASE
Let y = 0. x^2-7 = 0 x^2 = 7 X = =+-sqrt 7
July 8, 2013

algebra1 HELP PLEASE
h1(t) = 100 - 0.5*32*t^2. h1 = 100 - 16t^2 = 0 @ gnd. level. 16t^2 = 100 t^2 = 6.25 t = 2.50 s. h2(t) = 210 - 0.5*32*t^2 h2 = 210 - 16t^2 = 0 @ gnd. level. 16t^2 = 210 t^2 = 13.125 t = 3.62 s.
July 8, 2013

physics
See previous post,4:21 PM.
July 7, 2013

Finance
2. Increases with every payment and completely repays the loan with the last payment.
July 7, 2013

physics
Vo = 17m/s[25o] Xo = 17*cos25 = 15.4 m/s. Yo = 17*sin25 = 7.2 m/s. Y = Yo + g*t = 0 @ max. Ht. Tr = -Yo/ g = -7.2/-9.8 = 0.73 s. = Rise time. Tf = Tr = 0.73 s. = Fall time. D = Xo*(Tr+Tf) = 15.4 * 1.46 = 22.5 m. V=(D-12)/(Tr+Tf)=(22.5-12)/1.46=7.19m/s
July 7, 2013

physics
F = m*a V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = ((350)^2-0)/1.7 = 72,059 m/s^2 F = 0.004 * 72059 = 288 N.
July 6, 2013

physics
Please clarify your problem.
July 6, 2013

phy
1. Fn = m*a 40*cos37-Fk = 5 * 3 31.9-Fk = 15 Fk = 31.9-15 = 17 N. 3. a = Fn/m a = (250*cos37-8)/20 = 9.58 m/s^2.
July 6, 2013

math
The bar means the 2nd 89 REPEATS continuously.
July 5, 2013

physics
A = 5.0km[135o] B = 7.0km[315o] D = A+B D=(5.0*cos135+7.0*cos315)+i(5.0*sin135+ 7.0*sin315 D = (-3.54+4.95) + i(3.54-4.95) D = 1.41 - i1.41 = 2km[-45o]=2km[45o S of E]. NOTE: The cosine function was used to find the hor. components; the sine function was used to find the ver. ...
July 4, 2013

physics
A = 100m[0o] B = 200m[270o] C = 50m[3i5o] D = A+B+C D=(100+200*cos270+50*cos315+i(sin270+50*sin315) D = (100+0+35.4) + i(-200-35.4) D = 135.4 - i235.4 = 272m[-60o] = 272m [60o S. of E.].
July 4, 2013

Physics
A = 3m/s * 20s = 60m[180o]. B = 100m[270o]. C = 2m/s * 20s = 40 m[0o]. D = (A+B)-C A+B = (60*cos180+100*cos270)i(60*sin180+ 100*sin270) A+B = (-60+0) + i(0-100) A+B = -60 - i100 = -116.5[59o] A+B = 116.5[59+180] = 116.5m[239o]. D = (A+B)-C = 116.5[239] - 40 D = -60 - i100 - 40...
July 4, 2013

math 2
m1 = -A/B = 6/2 = 3. m2 = -12/-4 = 3. The Eqs have equal slopes. Therefore, they are parallel and do not intersect. So there are NO solutions.
July 4, 2013

contemporary math
P = Po(1+r)^n. P = $50,000 r = (8%/4)/100% = 0.02 = Quarterly % rate expressed as a decimal. n = 4comp./yr * 5.5yrs. = 22 Compounding periods. Plug the above values into the given Eq and solve for Po.
July 4, 2013

Math
Substitution.
July 4, 2013

Math
Substitution.
July 4, 2013

math
See previous post: Mon,7-1-13,10:49 PM.
July 3, 2013

math
Correction: A =(8/4)^2 * 18 = 72 Ft^2 = Area of the base. V = A*h = 72 * 8 = 576 Ft^3. OR V = (8/4)^3 * 72Ft^3 = 576 Ft^3.
July 3, 2013

math
18Ft^2*h1 = 72Ft^3 h1 = 72Ft^3/18Ft^2 = 4 Ft. A = (8Ft/4Ft) * 18Ft^2 = 36 Ft^2 = Area of the base. V = A*h = 36Ft^2 * 8Ft = 288 Ft^3.
July 3, 2013

Gen. physics
V^2 = Vo^2 + 2ad = 0 a = -Vo^2/2d = -(6.4)^2/29 = -1.41 m/s^2
July 2, 2013

physics
a. V = Vo + g*t = 17 m/s. Vo = 17-g*t = 17-(-9.8*2.2) = 38.56 m/s. b. V = 38.56 -9.8*4.4 = -4.56 m/s. The negative sign means the rock is on its' way down.
July 2, 2013

gen physics
See Related Questions: Thu,6-27-13,6:00am.
July 2, 2013

gen physics
A = 71[180o]. B = 71[270o]. a. A+B=(71*cos180+71*cos270)+i(71*sin180+71*sin270) A+B = (-71+0) + i(0-71) A+B = -71 - i71 = -100.4]45o] or 100.4[45o+180o] = 100.4[225o]. Since the resultant is in Q3, 45o is the reference angle. b. A-B=(71*cos180-71*cos270)-i(71sin180-71sin270) A...
July 2, 2013

Algebra
x(3y) = y(3x) = 3(xy) = 3*y*x.
July 2, 2013

49PM.ath
See Related Questions: Mon,7-1-13,10:
July 1, 2013

math
P = Po(1+r)^n. Po = $42,000 r = 11%/100% = 0.11 n = 1comp./yr. * 19yrs = 19 Compounding periods. Plug the above values into the given Eq and solve for P.
July 1, 2013

algebra 1 NEED NOW!!! PLEASE HELPPP
Since the parabola opens downward, the vertex is the max. point on the curve. Y = -12x^2 + 48x 1. h = Xv = -B/2A = -48/-24 = 2 Seconds. 2. k = Yv = -12*2^2 + 48*2 = 48 Ft. V(x,y)= (2,48). 3. Tr = Tf = 2 s. T = 2 + 2 = 4 s. Tr = Rise time. Tf = Fall time.
July 1, 2013

business math
See Mon,7-1-13,10:49PM post.
July 1, 2013

Mathematics
What is 72ten?
July 1, 2013

finance
D = 10000-0.15*10000 = $8500.
June 30, 2013

Physics
F = m*a a = V-Vo)/t = (34.4-0)/42 = 0.819 m/s^2. F = 3.6*0.819 = 2.95 N.
June 30, 2013

MATH
A(-1,-2),P(x,y),B(9,3). x-(-1) = 4(9-x) x+1 = 36-4x 5x = 35 X = 7. y-(-2) = 4(3-y) y+2 = 12-4y 5y = 10 Y = 2. P(7,2).
June 30, 2013

Physics
V = 6.48*cos9.54 = 6.39 m/s.
June 30, 2013

Physics
See previous post.
June 30, 2013

Physics
a=(V-Vo)/t = (26.5-0)/0.55 = 48.2 m/s^2. F = m*a = 929.4 * 48.2 = 44,780 N.
June 30, 2013

Discrete Math
CORRECTION:BCD should be BCDA
June 30, 2013

Discrete Math
8 different passwords were formed: ABCD BCD CDAB DABC. DCBA CBAD BADC ADCB
June 30, 2013

math
Move the decimal 8 places to the right. 7.5*10^8 = 750,000,000
June 30, 2013

math
1. P = Po(1+r)^n. Po = $500,000. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 5yrs. = 20 Compounding periods. Plug the above values into the given Eq. and solve for P. 2. P = Po(1+r)^n. r = APR = (8%/100% = 0.08 n = 1comp./yr. * 5yrs. = 5...
June 29, 2013

trig
X ^5 - 11 = 0 X^5 = 11 (X^5)^(1/5) = (11)^(1/5) X = 1.615.
June 28, 2013

physics
See Related Questions: Thu,6-27-13,6:ooAM.
June 28, 2013

Business Math
P = Po(1+r)^n. Po = 50000 r = (1.6%/2)/100% = 0.008 = Semi-APR. n = 2comp./yr. * 5yrs = 5yrs = 10 Compounding periods. Plug the above values into the given Eq and solve for P.
June 27, 2013

Business Math
P = Po(1+r)^n P = $27,500 Po = Initial investment. r = (6%/12)/100% = 0.005 = Monthly % rate expressed as a decimal. n = 12comp/yr. * 3yrs = 36 Compounding periods. P = Po(1.005)^36 = 27500 Po = 27500/(1.005)^36 = $22,980.
June 27, 2013

Business Math
APY = The interest for 1 year divided by the initial investment: APY = (I/Po)*100%.
June 27, 2013

Business Math
CORRECTION: n = 4Comp./yr. * 1yr. = 4 Compounding periods.
June 27, 2013

Business Math
P = Po(1+r)^n. Po = $1,000,000. r = (8%/4)/100% = 0.02 = Quarterly % .rate expressed as a decimal. n 4Comp./yr. * 8trs = 32 Compounding periods. Plug the above values into the given Eq and solve for P. I = P-Po.
June 27, 2013

Business Math
P = Po(1+r)^n. Po = $7700. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs = 20 Compounding periods. Plug the above values into the given Eq and get: P = $10,370.78
June 27, 2013

physics
Vo = 85m/s[45o]. Xo = 85*cos45 = 60.1 m/s. Yo = 85*sin45 = 60.1 m/s. Tr = (Y-Yo)/g = (o-60.1)/-9.8 = 6.1 s. = Rise time. h = Yo*t + 0.5g*t^2 h = 60.1*6.1 - 4.9*(6.1)^2 = 184.3 m. d = Yo*t + 0.5g*t^2=184.3 + 120=304.3m 0 + 4.9t^2 = 304.3 t^2 = 62.1 Tf = 7.9 s. = Fall time. d =...
June 27, 2013

physics
V*t = 17 m. 42.4 * t = 17 t = 0.40 s. d = 0.5g*t^2 g = 9.8m/s^2
June 27, 2013

To Mara; Re: algebra
L = 10-X. Your Eq is correct.
June 27, 2013

physics
V1*t = V2*t-37 m. 5.95t = 7.80t-37 7.8t-5.95t = 37 1.85t = 37 t = 20 s. d = 5.95 * 20 = 119 m
June 27, 2013

Science
Dw/Dl = 4/5 800/Dl = 4/5 4Dl = 4000 Dl = 1000 kg/m^3. = Density of the fluid.
June 26, 2013

maths
P1 = 1.08*65000 = 70200. (P1+P2)/2 = 66,300 (70,200+P2)/2 = 66300 70200+P2 = 132,600 P2 = 62400 Loss = 65000-62400 = 2600 %Loss = 2600/65000 = 0.04 = 4%. 2. 1kg/0.95kg = 1.0526 = 105.26 %. %Gain = 105.3% - 100% = 5.3%.
June 26, 2013

math 4th grade
See previous post.
June 26, 2013

math 4th grade
Population = 500,000km^2 * 20p/km^2 = 10,000,000 People.
June 26, 2013

Physics
Wp = m*g = 60kg * 9.8N/kg = 588 N. = Wt. of the person. Fp = 588*sin25 = 248.5 N. = Force parallel to plane. Fv = 588*cos25 = 533 N. = Force perpendicular to plane Fk = 0.450 * 533 = 240 N. = Force of kinetic friction. Fn = m*a a = Fn/m = (Fp-Fk)/m a = (248.5-240)/60 = 0.142 m...
June 25, 2013

physics
Fn = m*a = 0.1*10 = 1 N.
June 24, 2013

physics
F = m*a a = F/m = 80000/9.7 = 8247 m/s^2 V = Vo + a*t t = (V-Vo)/a = (6500-0)/ 8247 = 0.788 s.
June 24, 2013

physics
See previous post.
June 24, 2013

physics
Because the velocity at any instant depends on the time of the acceleration.
June 24, 2013

Physics
h = Vo*t + 0.5g*t^2 = 1.5 m. 0 + 4.9t^2 = 1.5 t^2 = 0.306 Tf = 0.553 s. = Fall time. D1 = V*Tf = 30m/s * 0.553s = 16.6 m. D2 = 35m/s * 0.553s = 19.4 m.
June 24, 2013

MATH
6 + 4*7/14 - 1 = 7 6 + 28/14 _ 1 = 7 6 + 2 - 1 = 7 7 = 7
June 24, 2013

conceptual science
a. V = Vo-g*t V = Vo-9.8m/s^2*1s V = Vo-9.8m/s. s. The speed decreases by 9.8 m each second. b. V = Vo + g*t V = Vo + 9.8m/s^2*1s V = Vo + 9.8m/s. The speed increases by 9.8 m each second. c. V = Vo + g*t = 0 @ max. ht. Vo + g*t = 0 Vo - 9.8t = 0 9.8t = Vo Tr = Vo/9.8 = Rise ...
June 23, 2013

physics
What is the question?
June 23, 2013

physics
V*t = 17 m. t = 17/V = 17/37.8 = 0.1852 s. d = 0.5g*t^2. g = 9.8 m/s^2.
June 23, 2013

physics
Vo = 26.5m/s[32.2o]. Xo = 26.5*cos32.2 = 22.4 m/s. Yo = 26.5*sin32.2 = 14.1 m/s Y = Yo + g*Tr = 0 @ max. ht. Tr = -Yo/g = -14.1/-9.8 = 1.44 s. = Rise time. D = Xo * Tr = 22.4m/s * 1.44s. = 32.3 m.
June 23, 2013

physics
Vo = 16.7m/s[33o]. Yo = 16.7*sin33 = 9.1 m/s. Y^2 = Yo^2 + 2g*h = 0 hmax= Yo^2/2g = -(9.1)^2/-19.6 = 4.23 m. V^2 = Vo^2 + 2g*d V^2 = 0 + 19.6*(4.23-2.6) V^2 = 19.6 * 1.625 = 31.85 V = 5.64 m/s.
June 23, 2013

physics
Correction: X = 4.15 m/s.
June 23, 2013

physics
X = Xo + a*t X = 3.2 + 1.9*0.5 = 4.15 m/s^2 Y = Yo + a*t Y = 8.1 - 6.2*0.5 = 5 m/s. a. V^2 = X^2 + Y^2 V^2 = (4.15)^2 + 5^2 = 42.2 V = 6.5 m/s. b. tan A = Y/X = 5/4.15 = 1.20482 A = 50.31o = Direction.
June 23, 2013

physics
See previous post.
June 23, 2013

physics
Vo = 12m/s[53.2o]. Xo = 12*cos 53.2 = 7.2 m/s. NOTE: The hor. component remains constant during the flight.
June 23, 2013

physics
a. V^2 = Vo^2 + 2a.d a = (V^2-Vo^2)/2d. a = (6.14-0)/26.8 = 0.229 m/s^2 b. a = 0.229*cos 32.6 = 0.193 m/s^2, c.
June 23, 2013

physics
tan A = Y/X = -558/925 = -0.60324 A = -31o D = 925/cos(-31) = 1080 m.
June 23, 2013

physics
See Related Questions: Tue,6-18-13,9:43PM.
June 23, 2013

math
translate the phrase into a mathematical expression and then evaluate it. sixtten squared divided by four cubed. The given expression in symbols is? (do not simplify. type exponential notation with positive exponents.) Evaluated, the expression is equal to? (simplify your answer)
June 23, 2013

Physics
x/0.017 = 22/1 X = 0.374 N. Work=F*d = 0.374 * 0.017=0.0064 Joules.
June 23, 2013

science
P = V*I = 2000 W. 220I = 2000 I = 9.09 Amps. The current too high for the circuit. If the circuit is properly protected, the fuse will blow or the circuit breaker will trip.
June 23, 2013

Math
I = Po*r*t = $23. 820*(r/360)*52 = 23 118.44444r = 23 r = 0.194 = 19.4 %.
June 22, 2013

math
P = Po(1+r)^n P = 8000+1261 = 9261. Po = 8000. n = 1comp./yr. * 3 yrs. = 3 Compounding periods. r = ? 8000(1+r)^3 = 9261. Divide both sides by 8000: (1+r)^3 = 1.157625. Take cube of both sides: 1+r = 1.05 r = 0.05 = 5% per yr.
June 22, 2013

math
P = Po + Po*r*t = 2600 2000 + 2000*(0.06/360)t = 2600 2000 + t/3 = 2600 t/3 = 2600-2000 = 600 t = 1800 Days. t = 1800Days / 360Days/yr. = 5 Yrs. Ordinary int. is based on 360 days/yr.
June 22, 2013

business math
C = 0.026*60000 + 0.034*(89400-60000) C = 1560 + 999.60 = $2559.60.
June 22, 2013

physics
tan A = Y/x = -4/2 = -2.0 A = -63.43o = 63.43o South of East. tan(-63.43) = d/10m d = 10*tan(-63.43) = -20 m = 20 m. South of starting point.
June 22, 2013

physics
V^2 = Vo^2 + 2g*d. Vo = 12 Ft/s. g = 32FT/s^2. d = 4.5 Ft. Plug the given values into the Eq and solve for V in Ft/s.
June 21, 2013

physics
V = Vo + a*t a = (V-Vo)/t a=(300-150)/(1/12)h=1800=1800 mi/h^2 V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a. d = (90000-22500)/3600 = 18.75 Miles.
June 21, 2013

trig
A + B = 90o A + 31 = 90 A = 59o. c*sin 59 = 3. c = 3/sin59 = 3.50 tan 59 = 3/b b = 3/tan 59 = 1.80
June 21, 2013

Math 116
See previous post.
June 21, 2013

Math 116
Multiply Eq1 by -6: -6x - 18y = -30 +6x - 6y = 14 Add the Eqs: -24y = -16 Y = 2/3. In Eq1, replace Y with 2/3: x + 3*2/3 = 5 x + 2 = 5 X = 3.
June 21, 2013

Math 116
Eq1:-6x - 2y = 12 Eq2:12x - 4y = -24 Multiply Eq1 by -4 and Eq2 by 2: 24x + 8y = -48 24x - 8y = -48 Add the Eqs: 48x = -96 X = -2. In Eq1, replace X with -2: -6*(-2) - 2y = 12 12 - 2y = 12 -2y = 12-12 = 0 Y = 0 (-2,0).
June 21, 2013

Math Algebra1A
Those are the only 2 that I know.
June 20, 2013

grade 4 math
10^x = 59,187 Take Log of both sides: x*Log 10 = Log 59187 X = Log59187/Log 10 = 4.77223. 10^4.77223 = 59187.
June 20, 2013

math
Monthly Salary = $X. Spends1/4 * $X = X/4. Bal. = X-X/4 = 3x/4. Spends1/5 * 3x/4 = 3x/20 Bal.=3x/4-3x/20 = 15x/20-3x/20=12x/20= 3x/5. Transportation: 1/10 * 3x/5 = 3x/50 Bal.=3x/5 - 3x/50 = 30x/50-3x/50=27x/50. 27x/50 = 630 27x = 31500 X = $1166.67.
June 20, 2013

physics
See previous post.
June 20, 2013

physics
See previous post.
June 20, 2013

physics
Vavg. = (30+45)/2 = 37.5 km/h.
June 20, 2013

algebra
Vb + Vc = 22 Vb - Vc = 8 Add the Eqs: 2Vb = 30 Vb = 15 mph. Replace Vb in Eq1 with 15: 15 + Vc = 22 Vc = 7 mph = Velocity of the current.
June 19, 2013

Math
787/9 = 87 Strawberries/carton. Bal. = 87 * 5 = 435 Strawberries 435strawberries/5strawberries/carton = 87 Cartons.
June 19, 2013

physics
h = 0.5g*t^2 = 81.6 m. 4.9t^2 = 81.6 t^2 = 16.65 t = 4.08 s. to hit ground. d = 9.13-4.30 = 4.83 m. = Distance the boat traveled in 4.08 s. Speed = d/t = 4.83/4.08 = 1.18 m/s.
June 18, 2013

Pages: <<Prev | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | 26 | 27 | 28 | Next>>

Search
Members