Thursday

April 17, 2014

April 17, 2014

Total # Posts: 8,512

**Math**

Ad = pi*r^2 = 3.14 * 4^2 = 50.3 cm^2 = Area of the disc. Ar = 170 * 90 = 15,300 cm^2. = Area of the rectangle. Ar/Ac=15,300/50.3=3o4.175 or 304 ciscs. A = 0.175 * 50.3 = 8.80 cm^2 Left.

**math**

r = (6%/360)/100% =0.000166666 = Daily % rate expressed as a decimal. I = Po*r*t = 11,900 Po*0.000166666*50 = 11,900 0.0083333Po = 11900 Po = $1,428,000.57 = Initial investment.

**algebra**

Total=$3.6*10^5 * 7.7*10^7=$2.772*10^13

**circuits**

R1 = %k Ohms. R2 = 25k Ohms Pt = P1 + P2 = E^2/R1 + E^2/R2. Pt = 10^2/5k + 10^2/25k = 20 + 4 = 24mW. = 24*10^-3 Watts. mW = Milliwatts.

**DES**

No, because the force of static friction is greater than the applied force.

**college physics**

Ep = mg*h = 230*9.8*125 = 281,750 Joules Ek = Ep = 281,750 Joules. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*125 = 2450 V = 49.5 m/s.

**Ưndustrial Engineering**

a. h = Yo*t + 4.9g*t^2 = 17.02 m Yo*2.94 - 4.9*(2.94)^2 = 17.02 2.94Yo - 42.35 = 17.02 2.94Yo = 17.02 + 42.35 = 59.37 Yo = 20.2 m/s = Ver. component of initial velocity. Dx = Xo*2.94 = 41 Xo = 13.95 m/s = Hor. component of initial velocity. tanA = Yo/Xo = 20.2/13.95 = 1.44803 ...

**physx!!!!**

See 12:20am post

**physics**

F = m*a m = F/a = 40/100 = 0.40 kg.

**Physics**

Draw a vector from the origin pointing due north. Then draw a vector from the origin pointing due west. Since the 2 vectors are equal, the resultant vector will fall midway between them(135o or North West). Mathematically: tanAr = Y/X = 20/-20 = -1.0 Ar = -45o = Reference angl...

**physics**

a. T^2 = 4*pi^2(L/g). L in meters. g in m/s^2. b. F = 1/T.

**math**

I = Po*r*t = 2500-1800. 1800*0.04*t = 700 72t = 700 t = 9.7 years.

**Physics**

Correction: Change 0.025 to 0.026 and get 530.4 N.

**Physics**

a = (V-Vo)/t a=(8.2-19.6)/5.6*10^-4 =-2.04*10^4m/s^2 Fe = m*a=0.025 * (-2.04*10^4=-510 N.= Force exerted.

**Managerial Finance**

A firm has an issue of preferred stock outstanding that has a par value of $100 and a 4% dividend. If the current market price of the preferred stock is $50, the yield on the preferred stock is

**Algebra**

1. sqrt75 + sqrt3 sqrt(25*3) + sqrt3 5*sqrt3 + sqrt3. = 6*sqrt3. 2. sqrt7(sqrt14+sqrt3) sqrt7(sqrt(7*2)+sqrt3) sqrt7(sqrt7*sqrt2+sqrt3) 7*sqrt2 + sqrt7*sqrt3 7*sqrt2 + sqrt21.

**math**

As = 2(W*h + L*h + L*W) As = 2(21 + 105 + 45) = 2(171)=342 in^2= Surface area.

**physics**

b. Dx = Vo^2*sin(2A)/g = 10 m Vo^2*sin80/9.8 = 10 0.1Vo^2 = 10 Vo^2 = 100 Vo = 10 m/s[40o].

**College algebra**

Y = -x^2 - 6x. a. h = Xv = -b/2a = 6/-2 = -3 k = -(-3)^2 - 6*-3 = 9 V(h,k)=(-3,9). b. Axis = h = Xv = -3. c. Y = -x^2 - 6x = 0. x(-x-6) = 0 X = 0 = x-Intercept. -x-6 = 0 X = -6. = X-Intercept. d. Domain = All real values of X. e. f. X = -6 to -3. g. X = -3 to 0. h. Use the fol...

**math ALG 2!scientific notations helpp**

1. 23,000,000 = 2.3*10^7. Moving the decimal 7 places to the right returns the number to standard form. 3. 0.00000021 = 2.1*10^-7. Moving the decimal 7 places to the left returns the number to standard form. 5. Write all of the numbers in standard form and compare. Remember th...

**physics**

Incomplete.

**consumers math**

assume $2.50 was earned from each account. I = Po*r*t = $2.50 1000*r*1 = 2.50 1000r = 2.50 r = 0.0025 = 0.25% For each acc.

**Math**

V = 300mph[35o] + 30mph[0o] X = 300*cos35+30 = 275.7 mph. Y = 300*sin35 = 172.1 mph. tanA = 172.1/275.7 = 0.62413 A = 32o V = X/cosA = 275.7/cos32=325.1 mph[32o]

**math**

Incomplete.

**algebra**

P = -0.025x + 80.35. P = -0.025*2010 + 60.35 = 10.1. So,10.1 % of the population is expected to be in the 18 t0 24- year range in year 2010. The student should finish the table. -0.025t + 60.35 = 9.4 Solve for t.

**Physics**

Please show the graph or data representing the graph.

**Electronics**

1. R=(15*5)/(15+5) + 10=3.75 + 10=13.75 Ohms. = Resistance of the circuit. 2. I = E/R = 40/13.75 = 2.91 Amps. 3. V = I*R = 2.91 * 10 = 29.1 Volts. 4. V = I*R = 2.91 * 3.75 = 10.91 Volts. 5. I = V/R = 10.91/15 = 0.727 Amps. 6. I = V/R = 29.1/10 = 2.91 Amps.

**math**

Length = 120 m. Area = 960 m^2. Width = ?. A = L*W = 960 120W = 960 W = 8 m. = Width.

**physical science**

See previous post

**physical science**

T = Time in seconds. h = Ht above gnd. in meters. (T,h). (0,97.5) (0.51,98.8) (1.01,97.5) (5,0).

**physical science**

V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g h = (0-25)/-19.6 = 1.28 m. = Max. ht. above bldg. V = Vo + g*t Tr = (V-Vo)/g = (0-5)/-9.8 = 0.51 s. = Rise time. Tf1 = Tr = 0.51 s. = Time to fall back to edge of bldg. Tf2 = 5 = - Tr - Tf1=5-0.51 - 0.51=3.98 s. Hb = Vo*t + 0.5a*t^2 Hb = 5*3...

**Physics**

Momentum = 1.5*10^3 * 32 = 4.8*10^4.

**physics**

k = 720N/15cm = 48N/cm F = m*g = 60kg * 9.8N/kg = 588 N. d = 588N/48N * 1cm = 12.25 cm.

**Physics**

W = F*d = 8*0.5 = 4.0 Joules.

**algebra**

x/4 + 5 <= 20 Multiply both sides by 4: x + 20 <= 80 x <= 80-20 X<= 60 X = 60,max.

**maths**

tan51 = Y1/X = 66/X. X = 66/tan51 = 53.4 m. = Distance between buildings. tan34 = Y2/X = Y2/53.4 Y2 = 53.4*tan34 = 36.0 m. h = Y1 + Y2 = 66 + 36 = 102.0 m. = Ht. of taller Bldg.

**physical science**

When forward velocity is 40 m/s, the downward velocity is zero.

**math**

P = 0.02 * 5270.00

**Physics**

240 mm/10 = 24 cm. 240 mm/1000 = 0.240 m.

**physics**

V^2 = Vo^2 + 2a*d. a = (V^2-Vo^2)/2d a = (0-(40)^2)/200 = -8 m/s^2.

**Math**

L = Length of 1st piece. 2(L-2) = Length of 2nd piece. L + 2(L-2) = 8 Ft. 3L - 4 = 8 3L = 12 L = 4 Ft. 2(L-2) = 2(4-2) = 4 Ft.

**Physics**

d = 1560m/s * (3.88s/2) = 3026.4 m. NOTE: 3.88 s = Time to travel to bottom of ocean and return.

**Physics**

d = = (1/240)*334.7 = 1.395 m.

**precalc**

V = (12/5)*40 = 96 rpm.

**precalc**

V = (12/5)*40 = 96 rpm.

**math**

Please read and clarify your problem.

**physics**

When the car catches up, it would have traveled 190 m. farther than the truck: 41.6t = 19.4t + 190 Solve for t.

**Trig**

tan34 = Y/X = Y/37. Y = 37*tan34 = 25 Ft. Ht. = Y + 5.3 = 25 + 5.3 = 30.3 Ft.

**Math**

F(x) = -2x^2 + 6x. F(1) = -2*1^2 + 6*1 = -2 + 6 = 4. F(3) = -2*3^2 + 6*3 = -18 + 18 = 0. F(3)-F(1) = 0 - 4 = -4 = Average rate of change.

**physics**

R = 42 Ohms. Xc = 1/W*C = 1/(140*175*10^-6)=40.8 Ohms Xl = W*L = 140*100*10^-3 = 14 Ohms. Z^2 = R^2 + (Xl-Xc)^2 = 2482.24 Z = 49.82 Ohms. tanA = (Xl-Xc)/R = (14-40.8)/42=-0.63810 A = -32.54o = Phase angle. Z = 49.82 Ohms @ -32.54o.

**Physics**

X = 22*cos61 + 46 = 56.67 km. Y = 22*sin61 + 29 = 48.24 km. a. D^2 = X^2 + Y^2 = 5538.74 D = 74.4 km. b. tanA = Y/X = 48.74/56.67 = 0.85124 A = 40.4o.

**Physical science**

Incomplete,

**Maths**

tan57.67 = Y/X = Y/35. Solve for Y.

**maths**

tan36.25 = Y/x = 8000/X. Solve for X.

**maths**

We draw and solve a rt. triangle: Y = 180 m. = Ht. X = 850 m = Hor..Distance of ferry. Z = Hyp. = Line of sight. tanA = Y/X = 180/850 = 0.21176. A = 12o = Angle of depression.

**Physics**

X = 0.8 m/s. Y = 1.4 m/s. tanA = Y/X = 1.4/0.8 = 1.75 A = 60.3o. tan60.3 = Y/X = 2km/X. X = 2km/tan60.3 = 1.14 km East of North.

**physics**

W = F*d = 46.3*cos28.7 * 3.09 = 125.5 J.

**Physics**

W = 5750[180o] * 360[210o]=2.07*10^6 J. @ 390o = 2.07*10^6 J. @ 30o.

**Physics**

Va=5.5rev/3.0s * 6.28rad/rev=11.5 rad/s

**Algebra 1**

Please check your Eq for errors. The -49 should be -4.9.

**Physics/math**

Ek=0.5*m*V^2=0.5*16.1*(3.35)^2=90.34 J. = Kinetic energy. Ep = m*g*h = 90.34 h = 90.34/m*g = 90.34/157.78 = 0.57 m

**Physics**

F = m*a

**algebra one**

x/4 - 3 >= 2.

**algebra one**

-3x + 4 <= x-8.

**algebra one**

4(x+2) + 3 >= 27 .

**algebra one**

5x/6 + 7 > -3

**algebra one**

5x-8 <= 2x+10.

**algebra one**

x + 14 <= 3x x - 3x <= -14 -2x <= -14 X >= 7.

**MONGU COLLEGE**

Is the inductive reactance of the coil 1200 ohms? If so: a. Xl = 2pi*F*L = 1200 Ohms. F=Xl/(2pi*L)=1200/(6.28*0.07)=2728.4 Hz. b. Xc = 1/(2pi*F*C) Xc=1/(6.28*2728.4*0.001*10^-6)=58333 Ohms Z = Xl+ Xc=1200 + (-58333)=-57133 Ohms, Capacitive. = 57133@(-90) Deg. I = V/Z = 120/571...

**MONGU COLLEGE**

I cannot calculate the freq. unless the reactance of the inductor or capacitor is given. I will assume a 230v.- 60 Hz supply. a 60 Hz. b. Xl = 2pi*F*L = 6.28*60*4 = 1508 Ohms. Xc = 1/(2p*F*C) = 1/(6.28*60*25*10^-6= 106 Ohms. Z = R + j(Xl-Xc) Z = 15 + j(1508-106) Z = 15 + j1402...

**Math**

% Financed = 100%-10% = 90%. Po = 0.9 * 185000=$166500=Amt. Financed P = Po(1+r)^n. r = (4.5%/12)/100% = 0.00375 = Monthly % rate expressed as a decimal. n = 12Comp./yr * 25Yrs = 300 Compounding periods. Plug the above values into the given Eq and get: P = $511,778.13. I = P-Po

**math**

b. Time = (100/45) * t = 2.22t. c. (45/6min) * 8min = 60 Containers. Amt.=(950grams/25cont. * 60=2280 Grams

**Math**

V =( Ab*h)/2 = (2.3 * 1.2)/2=1.38 m^3.

**Algebra**

Correction: Chuck's rate = (r+3)mi/h.

**Algebra**

r mi/h = Dana's rate. r * t = 224 miles. t = 224/r. 3)224r+3) mi/h = Chuck's rate. (r+3)t = 236 Replace t with 224/r: (r+3)224/r = 236 Multiply both sides by r: (r+3)224 = 236r 224r + 672 = 236r 236r - 224r = 672 12r = 672 r = 56 mi/h = Dana's speed. r+3 = 59 mi/h ...

**science physice**

Incomplete.

**College math**

See previous.

**College math**

See previous.

**College math**

10 + 10 + s = 180 S = 180-20 = 160 a = 10c. 5*10c + 3c + 2*160 = 500 50c + 3c + 320 = 500 53c = 500-320 = 180 C = 3.396 a = 10c = 10*3.396 = 33.96

**Math**

Assuming simple Interest: I = Po*r*t = 2719.50*0.061*20 = $3317.79 P = Po + I = 2719.50 + 3317.79=$6037.29. P = Po + Po*r*t = $3742.50. 3000 + 3000*r*3.75 = 3742.50 3000 + 11250r = 3742.50 11250r = 3742.50-3000 = 742.50 r = 0.066 = 6.6%/yr.

**Algebra**

N = 0.03x - 59.02 = 1.1 Million. 0.03x - 59.02 = 1.1 . 0.03x = 1.1 + 59.02 = 60.12 X = 2004.

**Algebra**

What is the ht. 0f the cliff?

**Physics III**

The “average” driver drives ~15,000 miles per year. Let’s assume ~10,000 miles of that is interstate driving. Using your models from parts (b) and (c) again, how much does the average driver spend per year if their average speed is 55 mph, 65 mph, and 75 mph? 15...

**Physics II**

It is ~ 100 miles of mostly interstate driving to camp. Using your model from parts (b) and (c), how much does it cost me to drive to camp if I drive 55 mph, 65 mph, and 75 mph? (don’t forget the return trip) the current price of gas for part c is 3.89/gal I have tried to...

**Physics**

Develop a model for the effective gas mileage (call it E) as a function of speed (S) for a ¡°typical¡± car (you should be able to find the necessary information to develop this model for your own car). This model should be valid for 55 ¡Ü S &i...

**Physics**

Wb = m*g = 40kg * 9.8N/kg = 392 N, = Wt. of the box. P1 = F*d/t = 392 * 1.3/0.7 = 728 J/s = 728 Watts. Wb = 48kg * 9.8N/kg = 470.4 N. P2=470.4 * 0.9/0.6=706. J/s=706Watts. The 1st boy is more powerful.

**geometry**

h = 36*sin70 = 33.83 Ft.

**Math**

As = 1 * 1 = 1 sq. unit. = Area of the sq. The 2 diagonals divide the sq. into 4 congruent triangles. The area of each triangle = 1/4 of total area: A = As/4 = 1/4 sq. units = BPC and BPD.

**Physics**

Vo = 100/e^(t/RC). t = 0 t/(RC) = 0/(RC) = 0 Vo = 100/e^0 = 100/1 = 100 Volts.= Initial voltage across capacitor and resistor.

**algebra**

See previous post.

**algebra**

d = Vo * t. Vo = Initial velocity.

**algebra**

d = 0.5*a*t^2.

**maths**

Lighthouse = 9.6nmi@156o. X = 9.6*cos156 = -8.8 n. miles = 8.8 n. miles West of ship. Ship = 8.8 Nautical miles East of light- h0use.

**physics**

Vo = 35.5m/s @ 60o. Xo = 35.5*cos60 = 17.75 m/s. Yo = 35.5*sin60 = 30.74 m/s. Y = Yo + g*t Y = 30.74 - 9.8*1.5 = 16.04 m/s. tanA = Y/Xo = 16.04/17.75 = 0.90366 A = 42.1o V=Xo/cosA=17.75/cos42.1=23.9 m/s.@42.1o.

**Physics**

1. Work = mg*h Work = 343 * 2 = 686 J. 3. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*2 = 39.2 V = 6.26 m/s.

**Physics**

Power = 500J/s = 500 Watts. V*I = 500 V = 500/I = 500/4 = 125 Volts.

**science**

Vo = 9.8mL * 1cm^3/mL = 9.8 cm^3 = Vol.of the object. Do = 12.5g/9.8cm^3=1.28 g/cm^3.=Density of the object. Density of water = 1 g/cm^3. Therefore, the object will sink; because its' density is greater than the density of water.

**physics**

Incomplete.

**Math**

Compute the following -7/2 x 9^-3/2 + 3/2 x 9^-5/2 + 14 7/2 is a negative fraction. the entire fractions are multiplied by 9 raised to their respective exponents. I can't figure this out. Please help?

**physics**

Wt. = m*g = m*9.8 = Wt. in Newtons. Fp = 9.8m*sin(0) = 0 = Force parallel to the field. Fv=9.8m*cos(0) - 750*sin47 = 9.8m-548.5= Force perpendicular to the field. Fk = u*Fv=0.21(9.8m-548.5)=2.06m-115.19 = Force of kinetic energy. 750*cos47-Fp-Fk = m*a 511.5-0-(2.06m-115.19) = ...

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