Thursday

April 24, 2014

April 24, 2014

Total # Posts: 8,535

**physics**

The diameter cannot be in cubic units. Volume is measured in cubic units.

**Algebra**

I don't understand your problem. Can you show it in a different format?

**college physics**

Correction: V^2 = 102.9.

**college physics**

V^2 = Vo^2 + 2g*d V^2 = 0 + 19.8*(10.5-5.25) V^2 = 1102.9 V = 10.1 m/s.

**math**

Y = -2x^2 h = Xv = -B/2A = 0/-4 = 0. k = -2*0^2 = 0. V(0,0). Use the following points for graphing: Y = -2x^2. (x,y) (-2,-8) (-1,-2) V(0,0) (1,-2) (2,-8) Y = -2x^2 + 4. h = Xv = -B/2A = 0/-4 = 0. k = Yv = -2*0^2 + 4 = 4. V(0,4). (-2,-4) (-1,2) V(0,4) (1,2) (2,-4)

**science**

a=(V2-V1)/(T2-T1)=(3.8-3)/(40-30)=0.08m/s^2.

**PHYsics......**

V = 100m/5s = 20 m/s.. a = (V-Vo)/t = (20-0)/5 = 4 m/s^2.

**math**

P = Po*r*t/(1-(1+r)^-t). Po = $100,000.00 r = (1%/12)/100% = 0.0008333 = Monthly % rate expressed as a decimal. t = 12mo/yr * 5yrs = 60 Mo. P=(10^5*0.0008333*60)/(1-(1.0008333^-t) P = $102,566.07 Monthly = 102,566.07/60mo = $1709.43/mo.

**College Gen. Math**

X Qtrs. 6X Dimes. (X+6) Nickels. 25*x + 10*6X + 5*(X+6) = 570. 25x + 60x + 5x+30 = 570 90x = 570-30 = 540 X = 6 Quarters. Amount = 6 * $.25 = $1.50.

**Physics**

Wc = m*g = 22kg * 9.8N/kg = 215.6 = Wt. of crate. Fc = 215.6N.[0o] = Force of crate. Fp = 215.6*sin(0) = 0 = Force parallel to floor. Fv = 215.6*cos(0) = 215.6 N. = Force perpendicular to floor. Fs = u*Fv = Force of static friction. Fap-Fp-u*Fv = m*a 76-0-u*215.6 = m*0 = 0. u*...

**Physics**

a. Wb = m*g = 8kg * 9.8N/kg = 78.4 N. = Wt of block. Epmax = mg*h-Fk*d Epmax = 78.4*1.6*sin30 - Fk*1.6 Epmax = 62.72 - Fk*1.6 Ek = 62.72 - Ff*1.6 0.5m*V^2 = 62.72 - Ff*1.6 4*5^2 = 62.72 - Fk*1.6 100 = 62.72 - Ff*1.6 Ff*1.6 = 62.72-100 = -37.28 Ff = -23.3 N. = Force of friction...

**physics**

Direction = 35o South of West. t = d/V = 53/(12+8.1) = 2.64 s.

**urgent urgent algebra / precalculas**

e^(0.03k) = 1.4 0.03k*Lne = Ln1.4 0.03k*1 = 0.33647 k = 11.22

**Math**

1/4 + 1/6 = 3/12 + 2/12 = 5/12. Note: 4*6 = 24. Therefore,24 can be used as a common denominator; but it is not the LEAST. So I used 1/2 of 24 or 12. If I use 24, my answer would be 10/24 = 5/12. Try the other one.

**physics**

V = 2m/s[270o] + 4.2m/s[0o] X = 4.2 m/s. Y = -2 m/s. tanA = -2/4.2 = -0.47619. A =-25.46o = 25.46o South of East. V = x/cosA = 4.2/cos(-25.46) = 4.65 m/s.

**maths**

R = 20K Ohms. C = 100uF. R*C = 20*10^3 * 100*10^-6 = 2000*10^-3= 2 s. E/e^(t/RC) = E-Vc. 40/e^(t/2) = 40-18 = 22 e^(t/2) = 40/22 = 1.8182. t/2*lne = ln1.8182 (t/2)*1 = 0.59785 t = 1.2 s.

**science**

X = -50 km/h, Y = 2000 km/h. tanAr = Y/X = 2000/-50 -40.0 Ar = -88.6o = Reference angle. A = -88.6 + 180 = 91.4o = Direction.. V = -50/cos91.4 = 2000.62 km.

**physics**

V^2 = (2.3)^2 + 19.6*114 = 2239.69 V = 47.3 m/s. = Final velocity. Ek=0.5m*V^2=0.5*42.8*(47.3)^2=47,929 J.

**physics**

NOTE: The force of the cart(Fc) is not needed.

**physics**

Fc = m*g = 220kg * 9.8N/kg = 2156 N. = Force of the cart. Work = Fc * D = 300*cos37 * 20=4792 J.

**Math**

C = pi*D = 3.14 * 0.88m = 2.76 m.= Circumference. Va=50000m/h * 1rev/2.76m=18,182 rev/min

**Math**

C = pi * D = 3.14 * 0.24m = 0.754 m.= Circumference. V=2800rev/min * 0.754m/rev * 1min/60s = 35.2 m/s.

**Math**

Please disregard previous solution. My theory is incorrect.

**Math**

Ad = pi*r^2 = 3.14 * 4^2 = 50.3 cm^2 = Area of the disc. Ar = 170 * 90 = 15,300 cm^2. = Area of the rectangle. Ar/Ac=15,300/50.3=3o4.175 or 304 ciscs. A = 0.175 * 50.3 = 8.80 cm^2 Left.

**math**

r = (6%/360)/100% =0.000166666 = Daily % rate expressed as a decimal. I = Po*r*t = 11,900 Po*0.000166666*50 = 11,900 0.0083333Po = 11900 Po = $1,428,000.57 = Initial investment.

**algebra**

Total=$3.6*10^5 * 7.7*10^7=$2.772*10^13

**circuits**

R1 = %k Ohms. R2 = 25k Ohms Pt = P1 + P2 = E^2/R1 + E^2/R2. Pt = 10^2/5k + 10^2/25k = 20 + 4 = 24mW. = 24*10^-3 Watts. mW = Milliwatts.

**DES**

No, because the force of static friction is greater than the applied force.

**college physics**

Ep = mg*h = 230*9.8*125 = 281,750 Joules Ek = Ep = 281,750 Joules. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*125 = 2450 V = 49.5 m/s.

**Ưndustrial Engineering**

a. h = Yo*t + 4.9g*t^2 = 17.02 m Yo*2.94 - 4.9*(2.94)^2 = 17.02 2.94Yo - 42.35 = 17.02 2.94Yo = 17.02 + 42.35 = 59.37 Yo = 20.2 m/s = Ver. component of initial velocity. Dx = Xo*2.94 = 41 Xo = 13.95 m/s = Hor. component of initial velocity. tanA = Yo/Xo = 20.2/13.95 = 1.44803 ...

**physx!!!!**

See 12:20am post

**physics**

F = m*a m = F/a = 40/100 = 0.40 kg.

**Physics**

Draw a vector from the origin pointing due north. Then draw a vector from the origin pointing due west. Since the 2 vectors are equal, the resultant vector will fall midway between them(135o or North West). Mathematically: tanAr = Y/X = 20/-20 = -1.0 Ar = -45o = Reference angl...

**physics**

a. T^2 = 4*pi^2(L/g). L in meters. g in m/s^2. b. F = 1/T.

**math**

I = Po*r*t = 2500-1800. 1800*0.04*t = 700 72t = 700 t = 9.7 years.

**Physics**

Correction: Change 0.025 to 0.026 and get 530.4 N.

**Physics**

a = (V-Vo)/t a=(8.2-19.6)/5.6*10^-4 =-2.04*10^4m/s^2 Fe = m*a=0.025 * (-2.04*10^4=-510 N.= Force exerted.

**Managerial Finance**

A firm has an issue of preferred stock outstanding that has a par value of $100 and a 4% dividend. If the current market price of the preferred stock is $50, the yield on the preferred stock is

**Algebra**

1. sqrt75 + sqrt3 sqrt(25*3) + sqrt3 5*sqrt3 + sqrt3. = 6*sqrt3. 2. sqrt7(sqrt14+sqrt3) sqrt7(sqrt(7*2)+sqrt3) sqrt7(sqrt7*sqrt2+sqrt3) 7*sqrt2 + sqrt7*sqrt3 7*sqrt2 + sqrt21.

**math**

As = 2(W*h + L*h + L*W) As = 2(21 + 105 + 45) = 2(171)=342 in^2= Surface area.

**physics**

b. Dx = Vo^2*sin(2A)/g = 10 m Vo^2*sin80/9.8 = 10 0.1Vo^2 = 10 Vo^2 = 100 Vo = 10 m/s[40o].

**College algebra**

Y = -x^2 - 6x. a. h = Xv = -b/2a = 6/-2 = -3 k = -(-3)^2 - 6*-3 = 9 V(h,k)=(-3,9). b. Axis = h = Xv = -3. c. Y = -x^2 - 6x = 0. x(-x-6) = 0 X = 0 = x-Intercept. -x-6 = 0 X = -6. = X-Intercept. d. Domain = All real values of X. e. f. X = -6 to -3. g. X = -3 to 0. h. Use the fol...

**math ALG 2!scientific notations helpp**

1. 23,000,000 = 2.3*10^7. Moving the decimal 7 places to the right returns the number to standard form. 3. 0.00000021 = 2.1*10^-7. Moving the decimal 7 places to the left returns the number to standard form. 5. Write all of the numbers in standard form and compare. Remember th...

**physics**

Incomplete.

**consumers math**

assume $2.50 was earned from each account. I = Po*r*t = $2.50 1000*r*1 = 2.50 1000r = 2.50 r = 0.0025 = 0.25% For each acc.

**Math**

V = 300mph[35o] + 30mph[0o] X = 300*cos35+30 = 275.7 mph. Y = 300*sin35 = 172.1 mph. tanA = 172.1/275.7 = 0.62413 A = 32o V = X/cosA = 275.7/cos32=325.1 mph[32o]

**math**

Incomplete.

**algebra**

P = -0.025x + 80.35. P = -0.025*2010 + 60.35 = 10.1. So,10.1 % of the population is expected to be in the 18 t0 24- year range in year 2010. The student should finish the table. -0.025t + 60.35 = 9.4 Solve for t.

**Physics**

Please show the graph or data representing the graph.

**Electronics**

1. R=(15*5)/(15+5) + 10=3.75 + 10=13.75 Ohms. = Resistance of the circuit. 2. I = E/R = 40/13.75 = 2.91 Amps. 3. V = I*R = 2.91 * 10 = 29.1 Volts. 4. V = I*R = 2.91 * 3.75 = 10.91 Volts. 5. I = V/R = 10.91/15 = 0.727 Amps. 6. I = V/R = 29.1/10 = 2.91 Amps.

**math**

Length = 120 m. Area = 960 m^2. Width = ?. A = L*W = 960 120W = 960 W = 8 m. = Width.

**physical science**

See previous post

**physical science**

T = Time in seconds. h = Ht above gnd. in meters. (T,h). (0,97.5) (0.51,98.8) (1.01,97.5) (5,0).

**physical science**

V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g h = (0-25)/-19.6 = 1.28 m. = Max. ht. above bldg. V = Vo + g*t Tr = (V-Vo)/g = (0-5)/-9.8 = 0.51 s. = Rise time. Tf1 = Tr = 0.51 s. = Time to fall back to edge of bldg. Tf2 = 5 = - Tr - Tf1=5-0.51 - 0.51=3.98 s. Hb = Vo*t + 0.5a*t^2 Hb = 5*3...

**Physics**

Momentum = 1.5*10^3 * 32 = 4.8*10^4.

**physics**

k = 720N/15cm = 48N/cm F = m*g = 60kg * 9.8N/kg = 588 N. d = 588N/48N * 1cm = 12.25 cm.

**Physics**

W = F*d = 8*0.5 = 4.0 Joules.

**algebra**

x/4 + 5 <= 20 Multiply both sides by 4: x + 20 <= 80 x <= 80-20 X<= 60 X = 60,max.

**maths**

tan51 = Y1/X = 66/X. X = 66/tan51 = 53.4 m. = Distance between buildings. tan34 = Y2/X = Y2/53.4 Y2 = 53.4*tan34 = 36.0 m. h = Y1 + Y2 = 66 + 36 = 102.0 m. = Ht. of taller Bldg.

**physical science**

When forward velocity is 40 m/s, the downward velocity is zero.

**math**

P = 0.02 * 5270.00

**Physics**

240 mm/10 = 24 cm. 240 mm/1000 = 0.240 m.

**physics**

V^2 = Vo^2 + 2a*d. a = (V^2-Vo^2)/2d a = (0-(40)^2)/200 = -8 m/s^2.

**Math**

L = Length of 1st piece. 2(L-2) = Length of 2nd piece. L + 2(L-2) = 8 Ft. 3L - 4 = 8 3L = 12 L = 4 Ft. 2(L-2) = 2(4-2) = 4 Ft.

**Physics**

d = 1560m/s * (3.88s/2) = 3026.4 m. NOTE: 3.88 s = Time to travel to bottom of ocean and return.

**Physics**

d = = (1/240)*334.7 = 1.395 m.

**precalc**

V = (12/5)*40 = 96 rpm.

**precalc**

V = (12/5)*40 = 96 rpm.

**math**

Please read and clarify your problem.

**physics**

When the car catches up, it would have traveled 190 m. farther than the truck: 41.6t = 19.4t + 190 Solve for t.

**Trig**

tan34 = Y/X = Y/37. Y = 37*tan34 = 25 Ft. Ht. = Y + 5.3 = 25 + 5.3 = 30.3 Ft.

**Math**

F(x) = -2x^2 + 6x. F(1) = -2*1^2 + 6*1 = -2 + 6 = 4. F(3) = -2*3^2 + 6*3 = -18 + 18 = 0. F(3)-F(1) = 0 - 4 = -4 = Average rate of change.

**physics**

R = 42 Ohms. Xc = 1/W*C = 1/(140*175*10^-6)=40.8 Ohms Xl = W*L = 140*100*10^-3 = 14 Ohms. Z^2 = R^2 + (Xl-Xc)^2 = 2482.24 Z = 49.82 Ohms. tanA = (Xl-Xc)/R = (14-40.8)/42=-0.63810 A = -32.54o = Phase angle. Z = 49.82 Ohms @ -32.54o.

**Physics**

X = 22*cos61 + 46 = 56.67 km. Y = 22*sin61 + 29 = 48.24 km. a. D^2 = X^2 + Y^2 = 5538.74 D = 74.4 km. b. tanA = Y/X = 48.74/56.67 = 0.85124 A = 40.4o.

**Physical science**

Incomplete,

**Maths**

tan57.67 = Y/X = Y/35. Solve for Y.

**maths**

tan36.25 = Y/x = 8000/X. Solve for X.

**maths**

We draw and solve a rt. triangle: Y = 180 m. = Ht. X = 850 m = Hor..Distance of ferry. Z = Hyp. = Line of sight. tanA = Y/X = 180/850 = 0.21176. A = 12o = Angle of depression.

**Physics**

X = 0.8 m/s. Y = 1.4 m/s. tanA = Y/X = 1.4/0.8 = 1.75 A = 60.3o. tan60.3 = Y/X = 2km/X. X = 2km/tan60.3 = 1.14 km East of North.

**physics**

W = F*d = 46.3*cos28.7 * 3.09 = 125.5 J.

**Physics**

W = 5750[180o] * 360[210o]=2.07*10^6 J. @ 390o = 2.07*10^6 J. @ 30o.

**Physics**

Va=5.5rev/3.0s * 6.28rad/rev=11.5 rad/s

**Algebra 1**

Please check your Eq for errors. The -49 should be -4.9.

**Physics/math**

Ek=0.5*m*V^2=0.5*16.1*(3.35)^2=90.34 J. = Kinetic energy. Ep = m*g*h = 90.34 h = 90.34/m*g = 90.34/157.78 = 0.57 m

**Physics**

F = m*a

**algebra one**

x/4 - 3 >= 2.

**algebra one**

-3x + 4 <= x-8.

**algebra one**

4(x+2) + 3 >= 27 .

**algebra one**

5x/6 + 7 > -3

**algebra one**

5x-8 <= 2x+10.

**algebra one**

x + 14 <= 3x x - 3x <= -14 -2x <= -14 X >= 7.

**MONGU COLLEGE**

Is the inductive reactance of the coil 1200 ohms? If so: a. Xl = 2pi*F*L = 1200 Ohms. F=Xl/(2pi*L)=1200/(6.28*0.07)=2728.4 Hz. b. Xc = 1/(2pi*F*C) Xc=1/(6.28*2728.4*0.001*10^-6)=58333 Ohms Z = Xl+ Xc=1200 + (-58333)=-57133 Ohms, Capacitive. = 57133@(-90) Deg. I = V/Z = 120/571...

**MONGU COLLEGE**

I cannot calculate the freq. unless the reactance of the inductor or capacitor is given. I will assume a 230v.- 60 Hz supply. a 60 Hz. b. Xl = 2pi*F*L = 6.28*60*4 = 1508 Ohms. Xc = 1/(2p*F*C) = 1/(6.28*60*25*10^-6= 106 Ohms. Z = R + j(Xl-Xc) Z = 15 + j(1508-106) Z = 15 + j1402...

**Math**

% Financed = 100%-10% = 90%. Po = 0.9 * 185000=$166500=Amt. Financed P = Po(1+r)^n. r = (4.5%/12)/100% = 0.00375 = Monthly % rate expressed as a decimal. n = 12Comp./yr * 25Yrs = 300 Compounding periods. Plug the above values into the given Eq and get: P = $511,778.13. I = P-Po

**math**

b. Time = (100/45) * t = 2.22t. c. (45/6min) * 8min = 60 Containers. Amt.=(950grams/25cont. * 60=2280 Grams

**Math**

V =( Ab*h)/2 = (2.3 * 1.2)/2=1.38 m^3.

**Algebra**

Correction: Chuck's rate = (r+3)mi/h.

**Algebra**

r mi/h = Dana's rate. r * t = 224 miles. t = 224/r. 3)224r+3) mi/h = Chuck's rate. (r+3)t = 236 Replace t with 224/r: (r+3)224/r = 236 Multiply both sides by r: (r+3)224 = 236r 224r + 672 = 236r 236r - 224r = 672 12r = 672 r = 56 mi/h = Dana's speed. r+3 = 59 mi/h ...

**science physice**

Incomplete.

**College math**

See previous.

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