Saturday

April 19, 2014

April 19, 2014

Total # Posts: 8,521

**physics**

Vo = 28m/s[30o]. Yo = Vo*sin30 = 28*sin30 = 14 m/s. Y^2 = Yo^2 + 2g*h

**UOG**

P = Po(1+r)^n. Po = $12,000 r = (4%/4)/100% = 0.01 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 2yrs. = 8 Compounding periods. Plug the above values into the given Eq. and get $12,994.28.

**Math**

(140-120)/10 * 500Lbs/yr. * 5yrs=5000 Lbs.

**physics**

Incomplete.

**physics**

Wb = 314 N. m*g = 314 m = 314/g = 314/9.8=32 kg.=mass of box. Fb = 314N[0o]. Fp = 314*sin(0) = 0 = Force parallel to floor. Fv = 314*cos(0)+475*sin35 = 586 N. = Force perpendicular to floor. Fk = u*Fv = 0.53 * 586 = 310.6 N. = Force of kinetic friction. a. Fap*cos35-Fp-Fk = m*...

**Calculus**

Implicit Differentiation. (x-3)^2+(y+2)^2=25

**engineering**

F = 9C/5 + 32 = 80 9c/5 = 80-32 = 48 9c = 240 C = 26.67o Celsius.

**Precalculus Test**

A = -7pi/5rad * 180o/pi = -2520 -252o + 360 = 108o = Co-terminal angle.

**physics**

See previous post.

**physics**

P = E^2/R = 58 Watts. (127)^2/R = 58 58R = (127)^2 R = (127)^2/58 = 278 Ohms.

**Physics**

F = Fr*sqrt(Xl/Xc) F = 1470*sqrt(29/5) = 3540.23 Hz a. WL = 29 L = 29/W = 29/22244 = 1.3*10^-3 H=1.3mH b. 1/WC = 5 WC = 1/5 = 0.2 C = 0.2/22244 = 9*10^-6F = 9 uF. NOTES 1. Sqrt = Square root 2. Fr = Resonant Freq. 3. W = 2PI*F.

**Science**

Series Circuit. V1 = 4Volts. V2 = 6-4 = 2Volts. R1 = 2R3. Parallel Circuit. R2 = V/I = 6/0.45 = 13.33 Ohms. R1 = 2R2 = 2*13.33 = 26.66 Ohms.

**Physics**

Work = F * d = 25 * 0.5 = 12.5 Joules.

**physics**

C = PI * D = 3.14 * 75cm = 235.62 cm. = Circumference. d = 3000rev * 235.62cm/rev = 706,858 cm = 7069 m.

**physics**

Energy = 9 * 10A-h = 90 Watt-hours.

**physics**

V1 = 4 * 1.852km/h = 7.408 km/h.[65o]. d1 = 3h * 7.408km/h = 22.224 km/h[65o]. V2 = 5 * 1.852km/h = 9.26 km/h.[270o]. d2 = 9.26km/h * 2h = 18.52 km[270o]. R = d1 + d2. R = 22.224km[65o] + 18.52 km[270o] X = 22.224*cos65 = 9.39 km. Y = 22,224*sin65 + 18.52*sin270=1.62 km tanA =...

**Alg 1**

3b/2 * b = 24 In^2 Multiply both sides by 2: 3b * b = 48 3b^2 = 48 b^2 = 16. b = +-4 In.

**College math**

W = KXY^2/Z^3 = 3 K4*2^2/4^3 = 3 16K/64 = 3 K/4 = 3 K = 12. W = KXY^2/z^3 = 12*8*9^2/6^3 = 36.

**math**

NOTE: 2 rt. triangles were formed with a common vert. side and a shared hor. side(X1 and X2).

**math**

tan20o = Y/X1 Y = X1*tan20. tan10o = Y/(X1+X2). Y = (X1+X2)*tan10 X1*tan20 = (X1+X2)*tan10 X2 = 189 Ft. X1*tan20 = (X1+189)*tan10 X1*tan20 = X1*tan10+189*tan10 X1*tan20-X1*tan10 = 189*tan10 0.364X1-0.176X1 = 33.33 0.188X1 = 33.33 X1 = 177.3 Ft. Y = h = X1*tan20 = 177.3*tan20=6...

**physics**

See Sat. post.

**Please Help!!!! Maths**

x^2-6x+1 = (3x+5)/2. Multiply both sides by 2: 2x^2-12x+2 = 3x+5 2x^2-15x-3 = 0 Use Quad. Formula and get: X = 7.695, and -0.195

**Physics - Electricity**

I=E/(R1+R2+R3)=13/(15+20+25)=0,217 Amps. V = I*R2 = 0.217 * 20 = 4.33 Volts.

**Physics**

a 2.0 kg block moving at 8 m/s on a frictionless surface collides elastically with a block at rest. The first block moves in the same direction at 2 m/s. What is the second block's mass?

**math**

Ratio = 2:5? P = 42 cm. X cm = Long side. 2x/5 cm = Short side. 2x + 2*2x/5 = 42 cm. 10x + 4x = 210 14x = 210 X = 15 cm. 2x/5 = 2*15/5 = 6 cm.

**math**

(6p+4q)(-2p+9q). -12p^2+54pq + -8pq+36q^2 -12p^2 + 36q^2 + 46pq 2(-6p^2+18q^2+23pq)

**math**

1. Remove the 1st parenthesis without changing any of the terms. 2. Since there is a negative sign in front of the 2nd parenthesis, remove it by changing the sign of each term. 3. Combine like-terms.

**Please Help!!!! Maths**

Po = $4500. I = $1620 I = Po*r*t = 1620 4500*r*3 = 1620 13500r = 1620 r = 0.12 = 12%.

**Please Help!!!! Maths**

I = Po*r*t = $1000. Po*0.04*2 = 1000 0.08Po = 1000 Po = $12,500

**science**

tanA = Y/X = 20/12 = 1.6666 A = 59o.

**Physics**

Mass = 5.8kg.? Radius = 5 cm.? Ht. = 15 cm. V = pi*r^2*h = 3.14*5^2*15 = 1178.1 cm^3 Density = 5800g/1178.1cm^3 = 4.92g/cm^3.

**college physics**

a. V = Vo + gt t = -Vo/g = -22.5/-9.8 = 2.3 s. b. b. V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g h = (0-(22,5)^2)/-19.6 = 25.83 m. c. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*25.83 = 506.27 V = 22.5 m/s. d. T = Tr + Tf = 2.3 + 2.3 = 4.6 s.

**physics**

Incomplete.

**math**

1/8 + 5/8 = 6/8 = 3/4 of the paint used.

**math**

a. F(t) = -4t + 20.

**Math**

$PO @ 5%. Po+3000) @ 6%. I = Po*r*t + (Po+3000)*r*t = $730 Po*0.05*1 + (Po+3000)*0.06*1 = 730 0.05Po + 0.06Po+180 = 730 0.11Po = 730-180 = 550 Po = $5,000 @ 5%. Po+3000 = $8,000 @ 6%.

**math**

Multiply both sides of the 1st Eq by -2, and multiply both sides of the 2nd Eq by 3. Then add the Eqs. -8u -6v = 2 +9u +6v = 3 U = 5.

**Math - Please Answer ASAP**

Correction: D = d2 + d3 = 546 + 182 = 728 cm.

**Math - Please Answer ASAP**

d1 = 182cm above gnd. d2 = 3*182 = 546 cm below gnd. d3 = 182 cm from head to bottom of hole. D=d1 + d2 + d3=182 + 546 + 182=910 cm = Depth of the hole.

**math**

Multiply both sides of the 1st Eq by -3, and multiply the 2nd Eq by 2. Then add the Eqs. -6s + 9t = 3 +6s - 8t = 0 t = 3.

**math**

Answer = D. m = Y/X = Y/0 = Infinite = Undefined.

**math**

Eq1: 4x + 6y = 12. m1 = -A/B = -4/6 = -2/3. Y-int. = C/B = 12/6 = 2. Eq2: 2x + 3y = 6. m2 = -2/3. Y-int. = 6/3 = 2. Since the slopes and Y-intercepts are both equal, the Eqs represent the same line. Therefore, we have an infinite number of solutions. Multiply both sides of Eq2...

**math**

1. Value = 7500 + 7500*0.09*20 = $21,000

**Math**

I = Po*r*t = 50,000*0.05*15 = $37,500.

**Physics**

V = 8km/h = 8000m/3600s = 2.22m/s. 0.5a = (V-Vo)/t = (2.22-0)/5 = 0.444 m/s^2 d = 0.5a*t^2 = 20 m. 0.222*t^2 = 20 t^2 = 90.1 t = 9.49 s.

**Algebra 8th grade**

Multiply both sides of the 1st Eq by -6. Multiply both sides of the 2nd Eq by 3. Then add the Eqs. -18a - 30b = -420 +18a + 27b = 405 -3b = -15 b = 5. in the 1st Eq, replace b by 5: 3a + 5*5 = 70 3a = 70-25 = 45 a = 15

**Algebraic**

See previous post.

**Algebraic**

$Po @ 4%. $2Po @ 5%. Po*0.04*1 + 2Po*0.05*1 = $378. .04Po + .10Po = 378 0.14Po = 378 Po = $2700. @ 4%. Int. = 0.04*2700 = $108. 2Po = $5400 @ 5%. Int. = 0.05*5400 = $270.

**Math**

P = Po(1+r)^n. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp/yr * t = 4t. P = 100(1.015)^4t = 200 (1.015)^4t = 200/100 = 2.00 4t*Log1.015 = Log2 4t = Log2/Log1.015 = 46.556 t = 11.64 Yrs.

**Algebra**

Correction: Eq1 = -630.

**Algebra**

Multiply Eq1 by -9, and multiply Eq2 by 5: -27a - 45b = 630 +30a + 45b = 675 3a = 45 a = 15.

**math**

V mi/h = Speed of B. (V-14) = Speed of A. Eq1: V*T = 260 = Dist. of B. T = 260/V. Eq2: (V-14)T = 190 = Dist. of A. In Eq2, replace T with 260/V: (V-14)260/V = 190. Multiply both sides by V: (V-14)260 = 190V 260V - 3640 = 190V 260V-190V = 3640 70V = 3640 V = 52 mi/h (V-14) = 38...

**math**

T=(T1*T2)/(T1+T2) = (55*60)/(55+60)=28.7 min.

**Calculus**

Right, but I am unsure what to put for intervals of concave up :/

**Calculus**

THANK YOU TUTORS SO MUCH FOR YOUR HELP Determine the intervals on which the function is concave up or concave down. I finally understand that when f'' is greater than 0 it means concave up. f(X) = 18x^2 + x^4 so I differentiate that to be 36x + 4x^3 that is f' if I...

**Calculus **

Determine the intervals on which the function is concave up and concave down f(x) = 17x^2 = x^4 by differentiating I get f'(x) = 34x+4x^3 and then I get lost. Can someone finish this up?

**Calculus**

Determine the intervals on which the function is concave up and concave down f(theta) = 21theta + 21Sin^2(theta), [0,pi] I have tried to implicitly differentiate but I am getting nowhere,... can anyone please help?

**Math**

A and D are correct.

**physics**

V = 72000m/3600s. = 20 m/s. d = V*t = 418+108 = 526 m. t = 526/V = 526/20 = 26.3 s.

**math help**

(f+g)(x) = F(x) + g(x) = -6x-1 + 4x^2.

**algebra**

1. 6(2a-3)(a+7)+3(3a+2)0 6(2a-3)(a+7+9a+6) 6(2a-3)(8a-1)

**algebra**

See prev. post.

**algebra**

Use Simple Int. P = Po +Po*r*t P = 3100 + 3100*0.15*21.6666 = $13,175.00

**Math**

Min. = 40 - 0,015*40 = 39.4. Max. = 40 + 0.015*40 = 40.6

**math**

X Fiction Books. (x-240) Non-fiction Books (x-240)-190 Picture Books. x + (x-240) + (x-240)-190 = 2630 Books. x + x-240 + x-240-190 = 2630 3x -480 - 190 = 2630 3x = 2630+670 = 3300 X = 1100 (X-240) = 860 (X-240)-190 = 670

**college physics**

h = Vo*t + 0.5g*t^2. = 3.6 0 * 4.9t^2 = 3.6 t^2 = 0.735 . Tf = 0.857 s. = Fall time. d = Xo * Tf = 13.4m/s * 0.857s. = 11 m.

**college physics**

a. d = 0.5a*t^2. d = 0.5*3*30^2 = 1350 m. b. V = a*t = 3 * 30 = 90 m/s.

**college physics**

V^2 = Vo^2 + 2a*d. a = (V^2-Vo^2)/2d a = (0-(23)^2)/420 = 1.26 m/s^2.

**math**

2L * 2W = 125 cm. 2L + 2*21.4 = 125 2L + 42.8 = 125 2L = 125-42.8 = 82.2 L = 41.1 cm.

**physics**

Incomplete.

**Algebra**

V1 = = X- mi/h V2 = (x+5) mi/h. d = 4*X + 4*(X+5) = 420 4x + 4x+20 = 420 8x = 420-20 = 400 X = 50 mi/h. X+5 = 55 mi/h.

**Algebra**

Please check your problem for errors.

**algebra 1**

3x+1 + 3-x + 2x+4 = 4x+8.

**Math**

4/3 * 3/4 = 5k 5k = 1 K = 1/5 = 0.2

**science**

F = u*Fv u = Coefficient of friction Fv = Normal or vertical component of object being set in motion.

**math**

4x+28 = 4(x+3)+16. 4x+28 = 4x+12+16 4x-4x = 28-28 0 = 0. No Solution.

**Math**

3. 9x^2-6x+1 + 5-15x + 3x(9x^2-6x+1) 9x^2-6x+1 + 5-15x + 27x^3-18x^2+3x 27x^3-9x^2-18x+6 3(9x^3-3x^2-6x+2)

**Math**

Commutative means you can add in any order: 3 + 7 +9 + 6 = 9+6+3+7 = 25. The Associative Property means that the order of grouping does not matter: (3+7) + (9+6) = (3+9) + (7+6) = 25. You are correct on the Commutative Property.

**Pre calculus**

-3 -6(3*sqrtx^2) = -8. 1. Isolate the term with the radical by adding 3 to both sides. 2. Divide both sides by -6 and get: 3x = 5/6. 3. Divide both sides by 3 and get: X = 5/18. 3.

**geometry**

Ap = 5/4 * 150in^2 = 187.5 in^2.

**physics**

Incomplete.

**PHYSICS**

is called Acceleration.

**Algebra**

P = Po*e^rt. a. rt = 0.08t P = 1700*e^0.08t = $2000 e^0.08t = 2000/1700 = 1.176 0.08t*Lne = Ln1.176 0.08t*1 = 0.1625 t = 2.03 Years. b. P = 1700*e^0.08t = 3400 Solve for t.

**physics**

Xc =< 0.1(Rs+Rl). = The capacitor's Reactance. Rs = The source resistance. Rl = The load resistance. Cc = 1/(W*Xc) = 1/(W*0.1(Rs+Rl)) = Coupling capacitor in Farads. W = 2pi*F. F = Frequency in Hertz. Rs and Rl in ohms.

**Pre-calculus**

1. 3.14rad/180o * 64.4o = 2.71 rad. 1. 180o/3.14rad * 2rad = 114.59o.

**algebra 1**

P = Po(1+r)^n. Po = $200.00 r = (5%/100%) = 0.05 = Annual % rate expressed as a decimal. n = 1Comp/yr * 8yrs = 8 Compounding periods. Plug the above values into the given Eq and get: P = $295.49.

**physics**

The diameter cannot be in cubic units. Volume is measured in cubic units.

**Algebra**

I don't understand your problem. Can you show it in a different format?

**college physics**

Correction: V^2 = 102.9.

**college physics**

V^2 = Vo^2 + 2g*d V^2 = 0 + 19.8*(10.5-5.25) V^2 = 1102.9 V = 10.1 m/s.

**math**

Y = -2x^2 h = Xv = -B/2A = 0/-4 = 0. k = -2*0^2 = 0. V(0,0). Use the following points for graphing: Y = -2x^2. (x,y) (-2,-8) (-1,-2) V(0,0) (1,-2) (2,-8) Y = -2x^2 + 4. h = Xv = -B/2A = 0/-4 = 0. k = Yv = -2*0^2 + 4 = 4. V(0,4). (-2,-4) (-1,2) V(0,4) (1,2) (2,-4)

**science**

a=(V2-V1)/(T2-T1)=(3.8-3)/(40-30)=0.08m/s^2.

**PHYsics......**

V = 100m/5s = 20 m/s.. a = (V-Vo)/t = (20-0)/5 = 4 m/s^2.

**math**

P = Po*r*t/(1-(1+r)^-t). Po = $100,000.00 r = (1%/12)/100% = 0.0008333 = Monthly % rate expressed as a decimal. t = 12mo/yr * 5yrs = 60 Mo. P=(10^5*0.0008333*60)/(1-(1.0008333^-t) P = $102,566.07 Monthly = 102,566.07/60mo = $1709.43/mo.

**College Gen. Math**

X Qtrs. 6X Dimes. (X+6) Nickels. 25*x + 10*6X + 5*(X+6) = 570. 25x + 60x + 5x+30 = 570 90x = 570-30 = 540 X = 6 Quarters. Amount = 6 * $.25 = $1.50.

**Physics**

Wc = m*g = 22kg * 9.8N/kg = 215.6 = Wt. of crate. Fc = 215.6N.[0o] = Force of crate. Fp = 215.6*sin(0) = 0 = Force parallel to floor. Fv = 215.6*cos(0) = 215.6 N. = Force perpendicular to floor. Fs = u*Fv = Force of static friction. Fap-Fp-u*Fv = m*a 76-0-u*215.6 = m*0 = 0. u*...

**Physics**

a. Wb = m*g = 8kg * 9.8N/kg = 78.4 N. = Wt of block. Epmax = mg*h-Fk*d Epmax = 78.4*1.6*sin30 - Fk*1.6 Epmax = 62.72 - Fk*1.6 Ek = 62.72 - Ff*1.6 0.5m*V^2 = 62.72 - Ff*1.6 4*5^2 = 62.72 - Fk*1.6 100 = 62.72 - Ff*1.6 Ff*1.6 = 62.72-100 = -37.28 Ff = -23.3 N. = Force of friction...

**physics**

Direction = 35o South of West. t = d/V = 53/(12+8.1) = 2.64 s.

**urgent urgent algebra / precalculas**

e^(0.03k) = 1.4 0.03k*Lne = Ln1.4 0.03k*1 = 0.33647 k = 11.22

**Math**

1/4 + 1/6 = 3/12 + 2/12 = 5/12. Note: 4*6 = 24. Therefore,24 can be used as a common denominator; but it is not the LEAST. So I used 1/2 of 24 or 12. If I use 24, my answer would be 10/24 = 5/12. Try the other one.

Pages: <<Prev | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | **21** | 22 | 23 | 24 | 25 | 26 | 27 | Next>>