Sunday

April 19, 2015

April 19, 2015

Total # Posts: 10,448

**geometry**

2. m AB = (5-2)/(2-0) = 3/2. m BC = (0-5)/(3-2) = -5/1 = -5. 3. A'(-4,4), B'(-2,7), C'(1,2). 4. m AB' = (7-4)/(-2+4) = 3/2. m BC' = (2-7)/(1+2) = -5/3
*April 7, 2014*

**Math word problems**

L = 15x + 15y L = 15(x + y) x = 5 3/8 Yards y = 3/4 Yard L = Total length x + y = 5 3/8 + 3/4 = 43/8 + 6/8 = 49/8 = 6 1/8 Yards. L=15 * 49/8 = 91.875 Yards = 91 7/8 Yds.
*April 7, 2014*

**physics**

KE = m*V^2/2 = 4 * 4^2/2 = 32 Joules.
*April 7, 2014*

**Math**

See previous post: Sat, 4-5-14, 10:04 PM.
*April 6, 2014*

**physics**

Freq. = 5*10^6rad/s * 1rev/6.28rad = 7.958*10^5 rev/s = 7.958*10^5 Hz. Xl = WL = (6.28*7.958*10^5)*100*10^-6 = 500 Ohms. Xc=1/WC = 1/(6.28*7.958*10^5)*100*10^-12 = 2000 Ohms. Z = R + j(Xl-Xc) = 30 + j(500-2000) = 30 - j1500 = 1500.3Ohms [-88.9o] I = V/Z = 1.0[0o]/1500.3[-88.9...
*April 6, 2014*

**Math**

P(t) = 100(1-e^-0.12*3) P(3) = 100(1-0.6977) = 30.23% Fails. 100% - 30.23% = 69.7% Usable.
*April 5, 2014*

**Math**

The largest exponent of the variable is 2. Therefore, it is a 2nd degree polynomial.
*April 5, 2014*

**College Physics**

F1 = 8.2N[125o] F2 = 6.40N[233.4o] A. Fx = 8.2*cos125 + 6.40*cos233.4 = -8.519 N. B. Fy = 8.2*sin125 + 6.40*sin233.4 = 1.579 N. C. F^2 = -8.519^2 + 1.579^2 = 75.07 F = 8.66 N. D. Tan Ar=Fy/Fx = 1.579/-8.519=-0.18535 Ar = -10.5o = Reference angle. A = -10.5 + 180 = 169.5o = 10....
*April 5, 2014*

**Algebra**

C = (B/2)^2 = (9/2)^2 = 81/4.
*April 4, 2014*

**physical science**

Yes.
*April 4, 2014*

**Math, Geometry**

See previous post: Fri,4-4-14,1:14 AM.
*April 4, 2014*

**Algebra**

Use Quadratic Formula: X = (-0.8 +- sqrt(0.64+2.96))/-0.04 = -27.43, and 67.43 X = 67.43 m.
*April 4, 2014*

**math**

P = Po(1+r)^n Po = $10,000 r = 8%/100% = 0.08 = APR expressed as a decimal. n = 1comp/yr. * 18yrs. = 18 Compounding periods. Solve for P.
*April 4, 2014*

**Math**

Correction: c. % Grade = Slope expressed as a percentage.
*April 4, 2014*

**Math**

a. Y/X = Y/2.5 = 0.06 Y/2.5 = 0.06 Y = 0.15 Miles = 792 Ft. b. Y/X = Y/90 = 0.06 Y = 90 * 0.06 = 5.4 Miles = 28,512 Ft. c. % Grade = Slope expressed as a decimal.
*April 4, 2014*

**math**

P = Po(1+r)^n Po = $8500 r = (12%/4)/100% = 0.03 = Quarterly % rate expressed as a decimal. n = 1yr * 4comp/yr. = 4 compounding periods. Plug the above values into the given Eq and sole for P.
*April 4, 2014*

**Physics**

Va=63rev/min * 6.28rad/rev * 1min/60s= 6.594 rad/s. Angle=0.57 + 6.594rad/s*9.5s=63.21 rad. or 0.4132 rad.
*April 3, 2014*

**percentages/word problem**

(3456-1600)/1600
*April 3, 2014*

**percentages/word problem**

(30.60-18)/18 = 0.70 = 70%
*April 3, 2014*

**percentages/word problem**

C + 0.45C = 79.75 1.45C = 79.75 C = $55.00
*April 3, 2014*

**Physics**

Correction: Vo = 460.6 rad/s V = 45 rad/s a = -84.3 rad/s^2
*April 3, 2014*

**Physics**

Vo=4401rev/min * 6.28rad/rev * 1min/60s= 460.6 m/s V = 430 * 6.28/60 = 45 m/s. a=(V-Vo)/t = (45-460.6)/4.93=-84.3 m/s^2
*April 3, 2014*

**physics**

Depth = V*T = 1530 * 3.65/2 = 2792 m.
*April 3, 2014*

**PHYSICS**

V = Vo + g*Tr = 0 14 - 9.8Tr = 0 9.8Tr = 14 Tr = 1.43 s. = Rise time. h = ho + Vo*Tr + 0.5g*Tr^2 hmax = 70 + (14*1.43 -4.9*1.43^2)=80 m. Above gnd. hmax = 0.5g*t^2 = 80 4.9t^2 = 80 t^2 = 16.33 Tf = 4.04 s = Fall time. Tr+Tf = 1.43 + 4.04 = 5.47 s. = Time to strike gnd. V=Vo + ...
*April 3, 2014*

**physics**

Incomplete.
*April 3, 2014*

**physics.**

The liquid with the highest density will have the largest percentage of its' volume above the water. Find the density of each liquid and compare them.
*April 3, 2014*

**Pre Algebra**

(9+3+4+16+11+5+T)/7 = 6. Solve for T.
*April 3, 2014*

**Physics**

d = V*t = 1500m/s * 1.5/2 = 1125 m.
*April 3, 2014*

**PHYSICS!!!**

T = d/V = 200/7 = 28.57 s.
*April 3, 2014*

**physics**

P = F * d/t = mg * d/t P = 66*9.8 * 14/44 Joules/s.
*April 3, 2014*

**Physic**

The voltage across a battery is equal to the e m f of the battery only when there is no load on the battery. When a resistive load is connected across the terminals, a portion of the voltage is lost across the internal resistance of the battery.
*April 3, 2014*

**Physics Help**

L = V(1/F) + 0 Slope = V. V is a constant. y-intercept = 0
*April 3, 2014*

**physics**

All of the parameters change.
*April 3, 2014*

**physics**

PE = m*V^2 = 0.164 J. .0508*V^2 = 0.164 V^2 = 3.228 V = 1.80 m/s.
*April 2, 2014*

**Physics**

Va=219rev/20s * 6.28rad/rev=68.8 rad/s a=(V-Vo)/t = (68.8-0)/20=3.44 rad/s^2. Circumference=pi*2r = 6.28 * 68=427 cm= 4.27 m. d = 219revs * 4.27m/rev = 935.2 m.
*April 2, 2014*

**Physics -- check answers please**

1. My answer is zero, because the car did not move backwards. However, you should get a 2nd opinion. 2. KE = 0.5*m*V^2 = 40 Joules KE = 0.5*5*V^2 = 40 2.5V^2 = 40 V^2 = 16 V = 4 m/s. 3c. 4a. PE + KE = Constant 5. I don't know what you mean by 4 100 J If you mean 400 J. the...
*April 2, 2014*

**business mat**

I = Po*(r/360)*t = $15 740(r/360)*59 = 15 43,660r/360 = 15 121.28r = 15 r = 0.1237 = 12.37%/yr.
*April 2, 2014*

**business Math**

(115-100)/100 = 0.15 = 15%.
*April 2, 2014*

**Business Math**

I = Po*r*t = $1.307 45,000*(0.04/365)*t = 1307 Solve for t in days. NOTE: Exact interest is based on 365 days per year instead of 360 days.
*April 2, 2014*

**Algebra**

X = 3y^2 K = Yv = -B/2A = 0/6 = 0 h = Xv = 3 * 0^2 = 0 D(X1,K), V(h,K), F(X2,K). D(X1,0), V(0,0), F(X2,0) DV = 0-X1 = 1/4a = 1/12 0-X1 = 1/12 X1 = -1/12 VF = X2-0 = 1/4a = 1/12 X2 = 1/12
*April 2, 2014*

**physics**

a = (Fap-Fk)/m = (160-24)/20 = 6.8 m/s^2
*April 1, 2014*

**physics**

V = Vo + a*t = 30 m/s 0 + a*4 = 30 a = 30/4 = 7.5 m/s^2.
*April 1, 2014*

**Math**

Can you clarify your problem?
*April 1, 2014*

**Math**

(150-73)/150 = 0.51 = 51%
*April 1, 2014*

**science**

750W * 1hp/746W = 1.0 hp.
*March 31, 2014*

**math**

post it.
*March 31, 2014*

**phisecs**

Power = 19kW = 19000W = 19,000 Joules/s. Power = F*V = F * 29 = 19,000 J./s F = 19,000/29 = 655.2 N.
*March 31, 2014*

**phisecs**

a = (V^2-V0^2)/2d a = (0-17^2)/40 = - 7.23 m/s^2.
*March 31, 2014*

**algebra**

x-1 = x+5 x-x = 5+1 0 = 6. No Solution.
*March 30, 2014*

**Physics**

What is the mass of the crate?
*March 30, 2014*

**Physics**

V=90mi/h * 1600m/mi * 1h/3600s.= 40 m/s. a = (V-Vo)/t = (40-0)/0.5 = 80 m/s^2.
*March 29, 2014*

**Physics**

Work = F*h = mg * h = 6*9.8 * 4=235.2 J. Work = F*h = 12 * 5 = 60 J. Work = 5*8 = 40 J. PE = mg*h = 5 * 8 = 40 J.
*March 28, 2014*

**Physics**

L = V/F = 199 m. F = V/199 = 300*10^6/199=1.51*10^6 cy/s= 1.51*10^6 Hz. WL = 1/WC C = 1/W^2*L C=1/(6.28*1.51*10^6)^2*785*10^-6=0.0142 nanofarads.
*March 28, 2014*

**World History**

What role did the Jacobins play in the French Revolution? The Jacobins reached an agreement with moderate French leaders to end the revolution. The Jacobins opened French gov't to full participation by women. The Jacobins returned France to a monarchy by supporting ...
*March 27, 2014*

**History**

How was James I's rule of England similar to peter the great's rule of Russia? Both reduces the size of their empire. Both increased their own power without approval by other government entitles. Both relied heavily on the opinions of their subjects when making ...
*March 27, 2014*

**Electricity**

Q = C*V = 10*10^-9F * 5V = 50*10^-9 Coulombs.
*March 27, 2014*

**math**

Got it! thanks
*March 26, 2014*

**math **

for the line segment whose endpoints are r(1,2) and s(6,7), find the point located 3/4 the distance from r to s.
*March 26, 2014*

**math 2**

Thank you so much reiny : )
*March 26, 2014*

**math 2**

A segment with endpoints C (3,4) and D (11,3) is divided by a point E such that CE and DE form a 3:5 ratio. Find E.
*March 26, 2014*

**math**

So I continued working where you left off and got y=0.5x+2.5 is that correct? or is it y=0.5x-2.5? I am pretty sure that it is the first one but I just wanna make sure.
*March 26, 2014*

**math**

Write an equation of a line perpendicular to line AB below in slope-intercept form that passes through the point (7, 6). A (0,1) B (-2,5)
*March 26, 2014*

**Math**

Wow thanks! It is correct! :D
*March 26, 2014*

**Math**

Write an equation of a line perpendicular to y=1/2x-5 in slope-intercept form that passes through the point (2, -7).
*March 26, 2014*

**6th Grade Math**

Blue = 3/10 Red = 4/10 = 2/5 Green = 3/10
*March 26, 2014*

**Physics**

h = Vo*t + 0.5g*t^2 = 2 m. 0 + 4.9*t^2 = 2 t^2 = 0.4082 t = 0.639 s. = Fall time. V = Vo + g*t = g*t. g = 10 m/s^2 Use the following points for graphing. (t,v) = (0,0), (0.2,2), (0.3,3),(0.5,5), (0.6,6).
*March 26, 2014*

**math**

P = (Po*r*t)/(1-(1+r)^-t) Po = Initial principal = $199,000 r = (7.01%/12)/100% = 0.00584 = Monthly % rate expressed as a decimal. t = 25yrs * 12mo/yr. = 300 Months. Plug the above values into the given Eq. and get: P = $422,328.10 Int.(Tot.) = P-Po = $223,328.10 Monthly ...
*March 26, 2014*

**Physical science**

See Related Questions: Wed,9-25-13,3:20 PM.
*March 26, 2014*

**physics**

Ingrid: 2h, 21min, 06s = Blake-: 2h, 06min, 50s = 2h, 20min, 66s 2h, 06min, 50s Diff. = 14min, 16s. = = 14.267min = Blake's winning margin. Tb = 120 + 6 + 50/60 = 126.833min = Blake's time. Vb = d/Tb = 42,195m/126.833min = 332.681 m/min = Blake's speed. d = 332....
*March 25, 2014*

**physics**

See Related Questions: Fri,3-21-14,8:55 PM.
*March 24, 2014*

**Physics**

m*g = 115 * 9.8 = 1127 N. = Wt. of box. Fn = 1127*cos46 = 782.9 N. = Normal force.
*March 24, 2014*

**physics**

Circumference = pi*D = 3.14 * 0.7m = 2.20 m. b. Va = 2m/s * 6.28rad/2.20m=5.71 rad/s = Angular velocity.
*March 24, 2014*

**physics**

h = (V^2-Vo^2)/2g = (0-(8^2))/-19.6 = 3.27 m.
*March 24, 2014*

**physics**

d = 0.5g*t^2 = 20-12 = 8 m. 4.9t^2 = 8 t^2 = 1.63 t = 1.28 s. = Fall time. Range = V*t = 4m/s * 1.28s = 5.12 m. 5.12m > 5 m. Therefore, he will make it.
*March 23, 2014*

**math**

Eq1: 5x - y = 20 Eq2: 4x + 3y = 16 Multiply Eq1 by 3 and add the Eqs: 15x - 3y = 60 +4x + 3y = 16 Sum: 19x = 76 X = 4 In Eq1, replace x with 4 and solve for y: 5*4 - y = 20 20-y = 20 Y = 0. Solution: (x,y) = (4,0).
*March 23, 2014*

**physics**

See Related Questions:Fri,3-21-14,8:55PM
*March 23, 2014*

**Physics**

Vo = 50m/s[37o] Xo = 50*cos37 = 39.93 m/s. Yo = 50*sin37 = 30.09 m/s. Tr = (Y-Yo)/g = (0-30.09)/-9.8 = 3.07 s = Rise time. Tf = Tr = 3.07 s. = Fall time. T = Tr+Tf = 3.07 + 3.07 = 6.14 s. = Time in air. d = Xo*T = 39.93m/s * 6.14s = 245.2 m. = Total dist. traveled.
*March 23, 2014*

**trigonometry**

The ladder is the hyp. of a rt. triangle X = ? Y1 = 8 Ft. Y2 = 84-8 = 76 Ft. A = 60o Tan 60 = Y2/X = 76/X X = 76/Tan60 = 43.88 Ft. = Dist. from bldg.
*March 23, 2014*

**Physics**

h=(V^2-Vo^2)/2g = (0-(8^2))/-19.6=3.27 m
*March 23, 2014*

**physics**

V = d/t = (t^3-3t^2+2)/4=(4^3-3*4^2+2)/4 = 4.5 m/s.
*March 23, 2014*

**physics**

a. 1.5km * 1000m/km * 1*10^6um/m = 1.5*10^9 Microns. b. 1.5um * 1m/10^6um * 100cm/m = 1.5*10^-4 cm c. 1.5yds * 3Ft/yd * 1m/3.3Ft * 10^6um/m = 1.364*10^6 Microns.
*March 23, 2014*

**physics**

h=(V^2-Vo^2)/2g = (0-(-8^2)/-19.6 = 3.27 m.
*March 23, 2014*

**physics**

T = 3 25/60 + (7 35/60-3 25/60) T = 3.417 + (7.583-3.417) = 7.583 Min. = 455 s. t = (7.583-3.417)min * 60s/min = 250 s. d = V*t = 1.65m/s * 250s = 412.4 m. V = d/T = 412.4m/455s = 0.906 m/s.
*March 23, 2014*

**math**

Given: F(x) = 1 - 3x. g(x) = x^2 - 1. F(g(x)) = F(x^2-1) F(x^2-1) = 1 - 3(x^2-1) = 1 - 3x^2 + 3 = -3x^2 + 4 F(g(x)) = -3x^2 + 4
*March 22, 2014*

**physics**

m*g = 50 * 9.8 = 490 N. = Wt. of crate = Normal force (Fn). a. Fs = u*Fn + u*F*sin30 Fs = 0.75*490 + 0.375F = 367.5 + 0.375F F*cosA-Fs = m*a F*cos30-(367.5+0.375F) = m*0 = 0 0.866F-367.5-0.375F = 0 0.866F-0.375F = 367.5 0.491F = 367.5 F = 748.5 N b. Fs = 0.75*490 - 0.75*F*...
*March 21, 2014*

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 20^2 - 19.6*15 = 106 V = 10.30 m/s.
*March 21, 2014*

**physics**

a = (V^2-Vo^2)/2d a = (0-(56)^2)/0.036 = -87,111 m/s^2 F = m*a = 850 * (-87,111)=-74,044,444 N.
*March 21, 2014*

**Physics**

V = 25 + 4 = 29 km/h.
*March 21, 2014*

**Math**

Vo = 200 Ft/s = Initial velocity. g = 2*(-16) = -32 Ft/s^2. hmax = (V^2-Vo^2)/2g = (0-(200)^2)/-64 = 625 Ft. Yes, because his max. ht. is greater than the ht. of the building.
*March 20, 2014*

**math**

C = pi*2r = (22/7) * 2(7n-21) C = (44/7) * (7n-21) = (308n - 924)/7 = 44n - 132
*March 20, 2014*

**physics**

m*g = 30 * 9.8 = 294 N. = Wt of cabinet. Fs = u*mg = 0.8 * 294 = 235.2 N.
*March 20, 2014*

**Math Help**

1. x^2 - 10x + 25 = 0 25 = -5 * -5 (x-5)(x-5) = 0 x-5 = 0 X = 5 x-5 = 0 X = 5 Solution set: X = 5, and 5. 2. 2x^2 + 9x -5 = 0 A*C = 2 * -5 = -10 = -1*10 2x^2 + (-x+10x) - 5 = 0 (2x^2-x) + (10x-5) = 0 x(2x-1) + 5(2x-1) = 0 (2x-1)(x+5) = 0 2x-1 = 0 2x = 1 X = 1/2 x+5 = 0 X = -5 ...
*March 20, 2014*

**Quick math help**

1. (3p^5*5p^2) + (7p^3*2p^4) = 15p^7 + 14p^7 = 29p^7 2. (6x^2-2xy+3y^2)-(4x^2-xy-y^2) = 6x^2-2xy+3y^2 -4x^2+xy+y^2 = 2x^2 - xy + 4y^2
*March 20, 2014*

**physics**

See previous post.
*March 20, 2014*

**physics**

When resistors are connected across a voltage source, the voltage will remain constant if the internal resistance of the source is much smaller than the total resistance connected across the source.
*March 20, 2014*

**Physics**

Correction: F*cosA-Fp = m*a F*cos46-810.7 = m*0 = 0 F*cos46 = 810.7 F = 1167 N.
*March 20, 2014*

**Physics**

m*g = 115 * 9.8 = 1127 N. = Wt of box. Fp = 1127*sin46 = 810.7 N. = Force parallel to the ramp. F-Fp = m*a F - 810.7 = m*0 = 0 F = 810.7 N. Fn = 1127*cos46 = 782.9 N. = Normal force.
*March 20, 2014*

**Physics**

30days * 24h/day = 720 Hours kW * h = (60/1000)kW * 720h = 43.2 kWh Cost = 43.2kWh * 0.10/kWh = $4.32
*March 20, 2014*

**physics**

A + B = 220[0o] + 220[120o] R = 220 + 220*cos120 + (220*sin120)I = 220-110 + 190.5i = 110 + 190.5i = 220[60o].
*March 20, 2014*

**Physics**

Fo = ((Vs+Vo)/(Vs-Vt))*Ft = 122 Hz ((340+0)/(340-Vt))*118 = 122 (340/(340-Vt))*118 = 122 40,120/(340-Vt) = 122 41,480-122Vt = 40,120 -122Vt = 40,120 - 41,480 = -1360 Vt = 11.15 m/s. = Velocity of the train.
*March 20, 2014*