# Posts by Henry

Total # Posts: 13,538

ap physics
Incomplete.

physics
Vf^2 = Vo^2 + 2a*d.

physics
V = Vo + a*t = 41.1m/s[26.5o]. 3.87[40.3o] + a*8.35 = 41.1[26.5]. 2.95+2.50i + a*8.35 = 36.8 + 18.3i. a*8.35 = 36.8 + 18.3i - 2.95 - 2.50i. a*8.35 = 33.9 + 15.8i = 37.4m/s[25o]. a = 4.48m/s^2[25o], CCW from +X-axis.

physics
Vf = Vo + a*t = 59.1m/s[43o]. Vo + 2.1[31.7o]*7.75 = 59.1[43]. Vo + 16.3[31.7o = 59.1*Cos43+59.1*sin43. Vo+16.3*Cos31.7+16.3*sin31.7=43.2+40.3i. Vo + 13.9 + 8.6i = 43.2 + 40.3i. Vo=43.2 + 40.3i - 13.9 - 8.6i=29.3+31.7i Vo = 43.2m/s[47.3o], CCW from +X-axis.

physics
P = E*I = 1.0 W. 1.58I = 1.0 I = 0.633A. A*h = 1. 0.633*h = 1. h = 1.58 Hours.

Calculus
Find the Absolute Maximum and Absolute Minimum of f on (0,3]. f(x)=(x^3-4x^2+7x)/x Multiple choice question I know the minimum is (2,3) but the maximum is either nothing or (0,7) but I can't tell which one

science
Velocity in kg/h???.

physics
Wc = M*g = 330 * 9.8 = 3234 N. = Normal force, Fn. Fap = 410 + 240 = 650 N. = Force applied. Fap-Fk = M*a. Fap-Fk = M*0 = 0. Fk = Fap = 650 N. = Force of kinetic friction. u = Fk/Fn.

Physics
V = Vo + g*T. Vo = 0. g = 10 m/s^2. h = ho - 0.5g*Tf^2 = 0. 5Tf^2 = 80. Tf^2 = 16. Tf = 4 s. = Fall time. Use T in the range of 0 to 4 seconds. (T,V,h). (0,0,80). (1,10,75). (2,20,60). (3,30,35). (4,40,0).

math
1. 6x4 in., P = 2*6 + 2*4 = 20 in. 2. 6*2 in., P = 2*6 + 2*2 = 16 in. 3. 4x2 in., P = 2*4 + 2*2 = 12 in. =

Physics
Units of time are seconds, minutes, and hours. Vf = Vo + a*t = 0. t = -Vo/a = -22/-6.1 = 3.61 s.

Precalc
a. P = Po(1+r)^n Po = \$60,000. r = (4%/4)/100% = 0.01 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 10yrs. = 40 Compounding periods. P = ? c. Same procedure as a.

physics
Vf = Vo + a*t = 3 + 1*5 = 8 m/s. d = Vo*t + 0.5a*t^2.

universitu
See Related Questions: Sun, 2-17-13, 5:09 AM.

Calculus
use tangent line approximation (linear approximation) to estimate The cube root of 1234 to 3 decimal places. Hint: the equation should be y=f'(x0)(x-x0)+f(x0) 11^3=1331 can be easily computed using binomial theorem. I used linear approximation and got 10.733, but it is not...

Physics
a. 0.5g*t^2 = 4780. 4.9t^2 = 4780. t^2 = 975.5 t = 31.2 s. Dx = 175m/s * 31.2s = 5465.8 m.

math
2. X = -30 km/h = velocity of the wind. Y = -295 km/h.=velocity of the aircraft. Q3. tan A = y/x = -295/-30 = 9.83333. A = 84.2o S. of W. = direction. Vr = y/sin A=-295/-sin84.2 = 296.5 km/h.

physics
Vf^2 = Vo^2 + 2g*h. g = 9.8 m/s^2.

Science
10cm3 * 10.5g/cm^3 = wt. in grams. mass = g/1000 = kilograms.

physics
140rev/60s * 20s =

science
T1*Cos26.5 - T2*Cos49.5 = 0 T1*Cos26.5 = T2*co49.5. T1 = 0.73T2. T1*sin26.5 + T2*sin49.5 = 155. Replace T1 with 0.73T2: 0.73T2*sin26.5 + T2*sin49.5 = 155. 0.324T2 + 0.760T2 = 155. 1.084T2 = 155. T2 = 143 N. T1 = 0.73*143 = 104 N.

Physics
Work = F*d = 23*Cos39 * 8 =

physics
Fs = M*g = 14 * 9.8 = 137 N. Fp = 137*sin 0 = 0 = Force parallel to the gnd. Fn = 137*Cos 0 - 25*sin30 = 124.5 N. = Normal Force. Fk = u*Fn = Force of kinetic friction. a = (25*Cos30-Fp-Fk)/M. Vf^2 = Vo^2 + 2a*d Vo = 1 m/s. d = 18 m. Vf = ?

Physics
See Relate Questions: Tue, 2-7-12, 1:11 AM.

science
Vf = Vo + g*Tr = 0. 24.5 + (-9.8)Tr = 0. -9.8Tr = 24.5 Tr = 2.5 s. = Rise time. Tf1 = Tr = 2.5 s = Time to fall back to roof. h = Vo*t + 4.9*t^2 = 24 m. 24.5*t + 4.9t*2 = 24. 4.9t^2 + 24.5t -24 = 0. Use Quad. Formula. t = 0.839 s. = Time to fall from top of roof to gnd. T = Tr...

physics
Fb = M*g = 13 * 9.8 = 127.4 N. Fp = 127.4*sin 0 = 0. = Force parallel to the floor. Fn = 127.4 - 86.4*sin64. = Normal force. Fk = u*Fn = Force of kinetic friction. a = (F*Cos64-Fp-Fk)/M.

physics
F1 = 2123 N. F2 = 1930 N. M = 1245 kg. a = (F1-F2)/M.

Physics
Vo = 90,000m/3600s = 25 m/s. d1 = Vo*t = 25m/s * 0.75s. = 18.75 m. d2 = 40 - 18.75 = 21.25 m. = Required stopping distance. Vf^2 = Vo^2 + 2a*d. Vf = 0. Vo = 25 m/s. a = -10 m/s^2. If d is => 21.25 m, the car will hit the barrier.

physics
4. Incomplete. Vo = 35m/s[33o]. Xo = 35*Cos33 = 29.4 m/s. Yo = 35*sin33 = 19.1 m/s. 5A. Yf^2 = Yo^2 + 2g*h. Yf = 0. g = -9.8 m/s^2. h = ? B. Dx = Vo^2*sin(2A)/g. A = 33o. g = +9.8 m/s^2. Dx = ?

SPR,PHYSICS
Vs = Db/Dw * Vb = 2/3 * Vb = 2Vb/3. Db/Dw * Vb = 2Vb/3. Db/Dw = 2/3 = 0.667. Db=0.667Dw = 0.667 * 0.998=0.665 g/cm^3. = Density of the block. Notes: Vs = Volume submerged. Db = Density of the block. Dw = Density of water. Vb = Volume of the block.

force
Wb = M*g = 10*9.8 = 98 N. Fp = 98*sin 0 = 0 = Force parallel to the surface. Fn = 98*Cos 0 - 40*sin30 = 78 N. = Normal force. Fk = u*Fn = 0.3 * 78 = 23.4 N. = Force of kinetic friction. a=(Fap*Cos30-Fp-Fk)/M=(34.6-0-23.4)/10 = 1.12 m/s^2.

Physics
I had this same problem... θ > arctan(μs) is the answer, you're welcome fam.

math
d1 = 10km/h * (20/60)h = 3.33 km., N. d2 = 5km/h * (35/60)h=2.92 km, NE.(45o)= 2.06 + 2.06i. Disp.=2.06 + 2.06i + 3.33i=2.06 + 5.39i = sqrt(2.06^2 + 5.39^2)

physics
Disp. = 7m[90o] + 9m[E45oN] + 7m[W14oS] X = 9*Cos45 + (-7*Cos14) = -0.428 m. Y = 7 + 9*sin45 + (-7*sin14) = 11.7 m. Q2. Tan A = Y/X = 11.7/-0.428 = -27.26754. A = -87.9o = 87.9o N. of W. = Direction. Disp. = Y/sin A = 11.7/sin87.9 = 11.71 m

physics
Disp. = 7m[90o] + 9m[E45oN] + 7m[S76oW]. X = 9*Cos45 - 7*Cos76 = 1.84 m. Y = 7 + 9*sin45 - 7*sin76 = 6.57 m. Q1. Tan A = Y/X = 6.57/1.84 = 3.57168. A = 74.4o N. of E. = Direction. Disp. = Y/sin A = 6.57/sin74.4 = 6.82 m

physics
A quantity that shows magnitude AND direction.

geometry
x^2 + 3x = 180o. x^2 + 3x-180 = 0. Factor it. -180 = -12*15. -12 + 15 = 3 = B. (x-12)(x+15) = 0. X = 12. X = -15. Use positive value of X: X = 12. X^2 = 144o. 3x = 36o.

physics
See Related Questions: Fri, 3-7-14, 4:52 PM.

Chemistry
Methanol, a major industrial feedstock, is made by several catalyzed reactions, such as CO(g) + 2H2(g) ----> CH3OH (l) One concern about using CH3OH as an auto fuel is its oxidation in air to yield formaldehyde, CH2OH(g) which poses a health hazard. Calculate ÄG o at ...

physics math science
Vo = 200m/s[37o]. Xo = 200*Cos37 = 160 m/s. Yo = 200*sin37 = 120 m/s. A. Y = Yo + g*t = 120 + (-9.8)*2 = 100 m/s. = Ver. component of velocity @ 2 s. Tan A = Y/Xo = 100/160 = 0.625. A = 32o. V = Xo/Cos A = 160/Cos32 = 189 m/s[32o]. B. Yf = Yo + g*Tr Yf = 0, g = -9.8m/s^2, Tr...

Calculus
i did. Dv=128pi. But the answer is 8pi/25

Calculus
Use differentials to estimate the amount of paint needed to apply a coat of paint 0.02 cm thick to a sphere with diameter 40 meters. (Recall that the volume of a sphere of radius r is V=(4/3)πr^3. Notice that you are given that dr=0.02.)

math
2 Years ago: Pam: X yrs. old. Sam: 2x/3 yrs. old. 3 yrs. later: Pam: x+3 yrs. old. Sam: 2x/3 + 3 yrs. old 2x/3 + 3 = 3/4(x+3). 2x/3 + 3 = 3x/4+9/4 8x + 36 = 9x + 27. X = 9. So Pam is 3 yrs. older than Sam. In 20 yrs.: x + (x+3) = 69. 2x = 66. X = 33. X+3 = 36. Today: Sam: 33...

Physics
F = 0.119m * 110N./m =

Physics
Wc = M*g = 1400 * 9.8 = 13,720 N. = Normal force, Fn. Fp = mg*sin 0 = 0. = Force parallel to the road. Fk = u*Fn = 0.0889 * 13,720 = 1220 N. a = (Fp-Fk)/M = (0-1220)/1400 = -0.871 m/s^2. Vf^2 = Vo^2 + 2a*d. Vf = 0. a = -0.871 m/s^2. Vo = 21.4 m/s. d = ?.

physics
Wt. = 450cm^3 * 0.998g/cm^3 = 449.1 g. = 0.449 kg of water displaced. M*g = 0.449kg * 9.8N/kg = 4.40 N.

SCIENCE\PHYSICS
Disp. = 0. d = 5 + 5 = 10 m.

PHYSICS
d = 5 + 5 = 10 m.

PHYSICS
Displacement = 0, because it ended at the starting point.

PHYSICS
a. Yf^2 = Yo^2 + 2g*h = 0. Yo^2 = -2g*h = -2*(-9.8)27.5 = 539. Yo = 23.2 m/s. = Vertical component of initial velocity. sin A = Yo/Vo = 23.2/47.5 = 0.48877. A = 29.3o. Xo = Vo*Cos A = 47.5*Cos29.3 = 41.4 m/s = Horizontal component of initial velocity = Total velocity at max ht...

physics
The velocity of the truck must be equal to the hor. component of the airplane's velocity: V = 180*Cos47.

Calculus
Let f(x)=x^4. If a=1 and dx=Δx=1/2, what are Δy and dy?

Physics
Wb = M*g = 200 N., M = 200/g = 200/9.8 = 20.4 kg. sin A = 3/10 = 0.30, A = 17.5o. Fp = 200*sin17.5 = 60 N. Fn = 200*Cos17.5 = 191 N. a. Work = F*d = 120 * 10 = 1200 J. b. Mg*h-0 = Mg*h = 200 * 3 = 600 J. c. Conservation Energy : Change in KE = Change in PE = 600 J. d. Fap-Fp-...

maths
P = Po(1+r)^n. r = (6%/2)/100% = 0.03 = Semi-annual % rate expressed as a decimal. n = 2comp./yr. * 1yr. = 2 Compounding periods. P = Po(1+0.03)^2 = Po*1.03^2 = 1.0609Po. I = P-Po = 1.0609Po-Po = 0.0609Po. I/Po * 100% = 0.0609Po/Po = 6.09% = Effective APR.

Physic
V = Vo^2 + 2g*h. Vo = 0, h = 20 m, V = ?

physicsn
Notes: 1. Fp = Force parallel with the hill. 2. Fn = Normal force. 3. Fk = Force of kinetic friction. 4. Ws = Wt. of skier.

physicsn
Ws = M*g = 9.8M. Fp = 9.8M*sin30 = 4.9M. Fn = 9.8M*Cos30 = 8.49M. Fk = u*Fn = u*8.49M. Fp-Fk = M*a. 4.9M-u8.49M = M*(-1.4) Divide by M: 4.9-8.49u = -1.4 -8.49u = -1.4-4.9 = -6.3 u = 0.74.

Physics
a. a=(Vf-Vo)/t = (5-0)/20 = 0.25 m/s^2. d1 = Vo*t + 0.5a*t^2 = 0 + 0.5*0.25*20^2 = 50 m.

math
a scooter is priced between \$1000 and \$2000. its price is a multiple of 10. All the digits in the price, except for the thousands digit, are even numbers. The value of the hundreds digit is 30 times the value of the tens digit. what is the price of the scooter?

science
Wb = M*g = 10 * 9.8 = 98 N. Fn = 98-40*sin30 = Normal force. Fk = u*Fn = Force of kinetic friction. a = (Fap*Cos30-Fk)/M.

Physics
a = F/m = 5/0.3 = 16.7 m/s^2. V = Vo + a*t. Vo = 20 m/s. t = 0.03 s. V = ?

Physics
Correction: Yf = 36.6 m/s.

Physics
h = 0.5g*t^2 = 68.2 m. 4.9t^2 = 68.2 t^2 = 13.92. t = 3.73 s. Dx = Xo*t = 4.2m/s * 3.73s. = 15.7 m. Yf^2 = Yo^2 + 2g*h. Yf^2 = 0 + 19.6*68.2 = 1336.72. Yf = 36.6 m. Vf = sqrt(Xo^2 + Yf^2) = Final velocity.

math 1350
Bob: X baseball cards. Ted: 2x " " Reggie: 2x-5 " " 2x-5 + x = 82. X = ?. 2x = ?

science
h = 0.5g*t^2.

science
d = 0.5*g*t^2.

science/physics
F = 9C/5 + 32.

Physics
Wc = M*g = 1300 * 9.8 = 12,740 N. = Normal force, Fn. Fp = Mg*sin A = Mg*sin 0 = 0. = Force parallel to the plane. Fk = u*Fn = 0.8 * 12,740 = 10,192 N. a = (Fp-Fk)/m = (0-10,192)/1300 = -7.84 m/s^2. d = (Vf^2-Vo^2)/2a = (0-(28^2))/-15.68 = 50 m.

1. M = 70 kg. Slope = 35o? L = 60 m. h = 60*sin35 = 34.4 m. Work = F*h = Mg*h = 70*9.8 * 34.4 = 23,608 J. 3. 19kW = 19kJ/s. = 19,000 J/s 6.8*10^7J * 1s./ 1.9*10^4J = 3580 s. = 0.994 h. or 1 h. 4. d = 0.5g*t^2 5. 24h/day * 365days/yr. * 3600s./h = 6. 200km[60o] N. of E. Dx = ...

Urgent physics help
A. D = 230mi/h * 2.5h = 575 mi. B. Dx = 575*Cos60 = C. Dy = 575*sin60 = D. Vr = 575mi[60o]/2.5h = Resultant velocity. Vx = Vr*Cos60 =

Quick Physics check
How did you arrive at your answer? See previous post: Wed, 10-21-15, 5:38 PM.

physics
Effective Intensity = 0.12 * 250W/m^2 = 30W/m^2. Area=(1200W * 1m^2/30W) = 40 m^2.

physics
Ws = M*g = 18 * 9.8 = 176.4 N. Fn = 176.4 - 45*sin30 = Normal force. Fk = u*Fn = Force of kinetic friction. F(net) = 45*Cos30-Fk

physics
See previous post: Fri, 10-23-15, 10:39 PM.

physics
Ws = M*g = 18 * 9.8 = 176.4 N. a. Fn = 176.4 - 45*sin30 = 153.9 N. = Normal force = Force perpendicular to the plane.

Physics
a = Fap/M = -250/50,000 = -0.005 m/s^2. Vf = Vo + a*t = 0. t = -Vo/a = 0.30/-0.005 = 60 s.

Physics
a. Wo = M*g = 4 * 9.8 = 39.2 N. d = 39.2N. * 1m/150N. = 0.261 m.

MAth
2^4 = 16. 2^-4 = 1/2^4 = 1/2^2*2^2 = 1/4*4 = 1/16.

Physics
h = 9.4*sin8.0 = 1.31 m. h = 0.5g*t^2 = 1.31 m. g = 9.8 m/s^2. t = ?

Physics
Vf = Vo + a*t = 20 + 2*4 = 28 m/s. Dc = 20*4 + 0.5*2*4^2 = 96 m. in 4 sec. Dc = 28m/s * 6s = 168 m. in 6 sec. Dc = 96 + 168 = 264 m. in 10 sec. Dt = 18m/s * 10s. = 180 m. in 10 sec. (264-8) - 180 = Distance in front of the truck.

physics
d = 2.06*sin28.8 = 0.992km, Due North.

Science
Vf = 100,000m/3600s. = 27.8 m/s. a = (Vf-Vo)/t = (27.8-0)/10 = 2.78 m/s^2

Algebra
Sun: X tickets were sold. Sat: 3x " " " Fri: 2x " " " \$2(x + 3x + 2x) = \$2160. X = ?

math
Assume 5 cm is measured on the drawing. d = 5cm * 3m/1cm = 15 m. = Actual distance.

math
(2/3)/6 = 2/3 * 1/6 = 2/18 = 1/9 cup.

physics
M*g = 1000 * 9.8 = 9800 N. Fp = 9800*sin33 = 5337 N. = Force parallel to the incline. a = Fp/M = 5337/1000 = 5.34 m/s^2.

sri krishna
3-4-5 triangle with each side multiplied by 4: hyp. = 20 = 5*4. 3*4 = 12. 4*4 = 16. So X = 4. so

Math
3/4 * M = 48. M = 4/3 * 48 = \$64.

Physics
a. Vf = Vo + g*Tr = 0. Tr = -Vo/g = -15/-9.8 = 1.53 s. = Rise time. b. h1 = Vo*Tr + 0.5g*Tr^2 = Ht. above the roof. g = -9.8 m/s^2. h = h1 + 20. c. h = 0.5g*Tf^2. h = h1 + 20. g = 9.8 m/s^2. Tf = Fall time. Tf = ? Tr + Tf = Total flight time. d. Vf^2 = Vo^2 + 2g*h. Vo = 0. g...

Physics

math
d = 5days * 2(13/2)mi/day = 65 Miles. 65mi/4gal. = 16.25 mi/gal.

math
144/32 = 4 R16 = 4 Thirty-two inch pieces with 16 inches left.

math
(3 2/3)/2/3 = (11/3)/2/3 = 11/3 * 3/2 = 33/6 = 5 3/6 = 5 1/2 or 5 pieces.

physics
Yf^2 = Yo + 2g*h = 0. Yo = -2g*h = -2*(-9.8)*0.449 = 8.8 m/s. Yo = Vo*sin3.40 = 8.8 m/s. Vo = 8.8/sin3.4 = 148 m/s.

math
Sole X necklaces. Sold 3x watches. 4*x + 7*3x = \$300. X = ?.

maths
1 - (2/5 + 1/3) = 15/15 -(6/15 + 5/15)= 15/15 - 11/15 = 4/15 Left.

physics
D = 26km[90o] + 62km[60o]. X = 62*Cos60 = 31km. Y = 26 + 62*sin60 = 79.7 km. Q1. Tan A = Y/X = 79.7/31 = 2.57076. A = 68.7o = Direction. D = Y/sin A = 79.7/sin68.7 = 85.5 km[68.7o].

Quick physics check
Fr = 60[135o]CCW + 5[330o]CCW. X = 60*Cos135 + 5*Cos330 = -38.1 N. Y = 60*sin135 + 5*sin330 = 39.9 N. Q2. Tan A = Y/X = 39.9/-38.1 = -1.04794. A = -46.3o = 46.3o N. of W. = Direction. Fr=Sqrt(X^2 + Y^2)=Sqrt(38.1^2 + 39.9^2) = 55.2 N. = Resultant force.

Physics
M*g = 9990 N., M = 9990/9.8 = 1019 kg. V = 64.87 mi/h * 1600m/mi * 1h/3600s. = 28.83 m/s. KE = 0.5M*V^2 = 0.5*1019*(28.83)^2 = 423,481 J. PE = Mg*h = KE. 9990*h = 423,481. h = ?

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