Monday

October 20, 2014

October 20, 2014

Total # Posts: 9,302

**physics**

(Fr)^2 = 9.93^2 + 1.23^2 = 100.1 Fr = 10.0 N. = Resultant force. a = Fr/m = 10/3.02 = 3.31 m/s^2.
*October 8, 2013*

**physics**

V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g = (0-16^20/3.24=79 m.
*October 7, 2013*

**Business Math**

I = Po*(r/360)*d = 15 740*(r/360)*59days = 15 121.3r = 15 r = 0,1237 = 12.37%.
*October 7, 2013*

**physics**

See previous post:7:33 PM
*October 7, 2013*

**physics**

Range = Vo^2*sin(2A)/g = 63 m. Vo^2*sin(76)/9.8 = 63 0.0990Vo^2 = 63 Vo^2 = 636.3 Vo = 25.23 m/s[38o]
*October 7, 2013*

**Physics**

F = m * g = 2.5kg * 9.8N/kg = 24.5 N. d = (24.5N/50N) * 1m = 0.49m. = 49 cm. End of spring = 21 + 49 = 70 cm.
*October 7, 2013*

**physics**

V=Vo + g*t = -0.60 + 9.81*2.8=26.87 m/s d = Vo*t + 0.5g*t^2 d = -0.60*2.8 + 4.9*2.8^2 = 36.74 m below the pelican.
*October 7, 2013*

**Science**

F2 = F1 = m * g = 1kg * 9.8N/kg = 9.8 N. F1 = Force of the book. F2 = Force of ihe table. The 2 forces are equal and opposite.
*October 7, 2013*

**math**

P = 5*((3x) + (2x+2) + (5x-3) + (2x+2)) P=5*(3x+2x+2+5x-3+2x+2)=5*(12x+1)=60x+5
*October 7, 2013*

**Business Math**

I = Po*(r/360)*d I = 2500*(0.1175/360)*136days = $110.97 AMT. = 2500 + 110.97 = $2610.97
*October 7, 2013*

**physics**

X = 30 km/h Y = 5 km/h V^2 = 30^2 + 5^2 = 925 V = 30.4 km/h
*October 7, 2013*

**chemistry**

An aqueous solution of glucose is made by disolving 8.75 g of glucose in 100 mL of water. Calculate molarity, molality and the mole fraction
*October 7, 2013*

**Algebra**

Eq1: 3x-2y+2z = 30 Eq2: -x+3y-4z = -33 Eq3: 2x-4y+3z = 42 Multiply Eq1 by 2 and add Eq1 and Eq2: 6x-4y+4z = 60 -x+3y-4z = -33 Eq4:5x-y = 27 = Sum. Multiply Eq2 by 3 and Eq3 by 4 and add Eq2 and Eq3: -3x+9y-12z = -99 8x-16y+12z = 168 Eq5: 5x-7y = 69 Multiply Eq4 by -1 and add ...
*October 7, 2013*

**science physics**

a = (V-Vo)/t a = (12-4)/4 = 2 m/s^2.
*October 7, 2013*

**physics**

d = 26.2/cos25 = 28.91 m. = Distance the boat must travel to reach shore. T = d/r = 28.91m./4.5m/s = 6.42 s.
*October 7, 2013*

**physics**

T = d/r = 93Ft/2Ft/s = 46.5 s. To ride 93 Ft. V = d/T = 12Ft/46.5s. = 0.258 Ft./s.
*October 6, 2013*

**Physics**

Vo = 12m/s[20o] Xo = 12*cos20 = 11.28 m/s. Yo = 12*sin20 = 4.10 m/s. Y = Yo + g*Tr = 0 @ max. ht. 4.10 - 9.8Tr = 0 -9.8Tr = -4.10 Tr = 0.419 s. = Rise time. Tf = Tr = 0.419 s. T = Tr + Tf = 0.419 + 0.419 = 0.838 s.= Time in air.
*October 6, 2013*

**physics**

Vo = 26.9m/s[63.2o] Xo = 26.9*cos63.2 = 12.13 m/s. Yo = 26.9*sin63.2 = 24.01 m/s. Y^2 = Yo^2 + 2g*h h = (Y^2-Yo^2)/2g = (0-24.01^2)/-19.6 = 29.41 m.
*October 6, 2013*

**Physics**

h = Vo*t + 0.5g*t%2 = 45 m. h = 4.9t^2 = 45 t^2 = 9.18 Tf = 3.03 s. = Fall time. Dist. = Xo * Tf = 35 m. Xo * 3.03 = 35 Xo = 11.55 m/s = Hor. component of initial velocity. Yo = 0.
*October 6, 2013*

**Physics**

a. h1 = V1*t + 0.5g*t^2 h1 = 11*1 - 5*1^2 = 6 m. Head start. V^2 = V1^2 + 2g*h V^2 = 11^2 - 20*6 = 1 V = 1.0 m/s. h2=V2*t + 0.5g*t^2 = 6 + V*t + 0.5g*t^2 16*t - 5*t^2 = 6 + 1*t - 0.5g*t^2 The 0.5g*t^2 terms cancel: 16t - t = 6 15t = 6.0 t = 0.4 s. to catch up.
*October 6, 2013*

**physics**

V = 22m/s[-40.3o] Xo = 22*cos(-40.3) = 16.78 m/s. = Hor. component of initial velocity. Y = 22*sin(-40.3) = -14.23 m/s. Xo * Tf = 62.3 m. 16.78 * Tf = 62.3 Tf = 3.71 s. = Fall time. Y = Yo + g*Tf = -14.23 m/s. a. Yo + 9.8*3.71 = -14.23 Yo + 36.38 = -14.23 Yo = -14.23 - 36.38...
*October 5, 2013*

**Physics**

You didn't give all of the INFO. Density = m/V = 50kg/1m^3 = 50kg/m^3
*October 5, 2013*

**physics**

1. V = a*t = 1.8m/s^2 * 4.5s. = 8.1 m/s. X = 6.1 m/s. Y = 8.1 m/s. tan A = Y/X = 8.1/6.1 = 1.32787 A = 53o = Direction. 2. V = Y/sinA = 8.1/sin53 = 10.14 m/s.
*October 5, 2013*

**physics**

Vo = 20m/s[35o] Xo = 20*cos35 = 16.38 m/s. Yo = 20*sin35 = 11.47 m/s. a. Tr = (Y-Yo)/g = 0-11.47/-10=1.147 s = Rise time. h = Yo*t + 0.5g*t^2 = hmax = 11.47*1.147 - 5*1.147^2 = 6.58 m h = 0.5g*t^2 = 6.58-6 = 0.58 m. 5t^2 = 0.58 t^2 = 0.116 Tf = 0.341 s. = Fall time. Range=Xo*(...
*October 5, 2013*

**Physics**

a. Wr = m * g = 500kg * 9.8N/kg = 4900 N. b. a=Fn/m = (13500-4900)/500=17.2 m/s^2
*October 5, 2013*

**physics**

V^2 = Vo^2 + 2g*h Vo^2 = -2g*h = -2*-9.8*107 = 2097.2 Vo = 45.8 m/s. V = Vo + gt = 0 @ max. ht. Tr = (V-Vo0/g = (0-45.8)/-9.8 = 4.67 s. = Rise time. Tf = Tr = 4.67 s. = Fall time. T = Tr + Tf = 4.67 + 4.67 = 9.35 s. = Time in air.
*October 5, 2013*

**physics**

Wb = m * g = 74kg * 9.8N/kg = 725.2 N. = Weight of box. Fs = u * Wb = 1.1 * 725.2 = 797.7 N. = Force of static friction.
*October 4, 2013*

**Physics**

a=F/m = (4*415)/140,000=0.011857 m/s^2
*October 4, 2013*

**math**

Cost = $2375 * 0.85 * 0.80 * 0.80=$1292 Discount = 2375 - 1292 = $1083.
*October 4, 2013*

**science**

V2 = 1000 * 380/760 * 25/50 e. None of these.
*October 4, 2013*

**PHYSICS**

Wc = m * g = 200 N. m * 9.8 = 200 m = 20.41 kg. = Mass of crate. F = 55N.[35o.] 55*cos35 - Fk = m*a 45.05 - Fk = m*0 = 0 Fk = 45.05 = Force of kinetic friction. u = Fk/Wc = 45.05/200 = 0.225
*October 3, 2013*

**PHYSICS**

Wb = m * g = 100kg * 9.8N/kg = 980 N. F1 = 980*sin15 = 253.6 N. = Force parallel to the ramp. F2 = 980*cosi5 = 946.6 N. = Force perpendicular to the ramp. Fs = F1 = 253.6 N. @ 15o u = Fs/F2 = 253.6/946.6 = 0.268
*October 3, 2013*

**PHYSICS**

Ws = m*g = 150 N. = Weight of sled. m = 150/g = 150/9.8 = 15.31 kg. F1 = 150*sin28 = 70.42 N. = Force parallel to the slope. F2 = 150*cos28 = 132.4 N. = Force perpendicular to the slope. a = F1/m = 70.42/15.31 = 4.60 m/s^2.
*October 3, 2013*

**physics**

W1 = m * g = 10kg * 9.8N/kg = 98 N. = Wt. 0f m1. Fs = u * mg = 0.69 * 98 = 67.62 N. = Force of static friction. m2 * g = Fs = 67.62 N. m2 * 9.8 = 67.62 m2 = 6.9 kg.
*October 3, 2013*

**physics**

Vo = 15.4m/s[38.7o] Xo = 15.4*cos38.7 = 12 m/s. Yo = 15.4*sin38.7 = 9.63 m/s. Range = Vo^2*sin(2A)/g Range = 15.4^2*sin(77.4)/9.8 = 23.62 m. Range = Xo * T = 23.62 m. Range = 12 * T = 23.62 T = 1.97 s. in air. d=Vr * T = 23.62-17.7 = 5.92 m. to run. Vr * 1.97 = 5.92 Vr = 3.0 m...
*October 3, 2013*

**Physics**

See 11:48 PM post.
*October 2, 2013*

**Physics**

A. h = 0.5g*t^2 = 0.809 m. 4.9t^2 = 0.809 t^2 = 0.1651 t = 0.4063 s. Xo * t = 18.3 m. Xo * 0.4063 = 18.3 Xo = 45 m/s. = Velocity of the pitch. B. h = 0.5g*t^2 = 5.4 m 4.9*t^2 = 5.4 t^2 = 1.1 Tf = = 1.05 = Fall time of each vessel. Ds = Xo * Tf = 15m/s * 1.05s. = 15.75m. = Dist...
*October 2, 2013*

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*26.8 = 525.28 V = 22.92 m/s.
*October 2, 2013*

**Physics**

V^2 = Vo^2 + 2g*h V^2 = 0 + 20*500 = 10,000 V = 100 m/s.
*October 2, 2013*

**physics**

You did not give the angle for F2.
*October 2, 2013*

**Physics**

u * F = 7.01 N. 0.44 * F = 7.01 F = 15.93 N.
*October 2, 2013*

**Intermediate Algebra**

4x^2 + x - 1. Use Quadratic formula. X = (-B +-Sqrt(B^2-4AC))/2A X = (-1 +-Sqrt(1+16))/8 X = (-1 +-Sqrt(17))/8 X = (-1 +- 4.12)/8 = 0.39, and -0.64
*October 2, 2013*

**Intermediate Algebra**

11 1/2 * 11^3 = 23/2 * 11^3 = 23/2 * 1331 = 15,306.5
*October 2, 2013*

**Physics**

a. Wr = m * g = 56kg * 9.8N/kg = 549. N = Weight of refrigerator. Fs = u*Wr = 0.7 * 549 = 384 N. = Force of static friction which points in the +x direction. b. F = -384 N.
*October 2, 2013*

**Math**

X = The # of $10 bills. 3X = the # of $5. bills. 3x+30 = The # of $1 bills. 10x + 5*3x + 1*(3x+30) = 170 10x + 15x + 3x + 30 = 170 28x = 140 X = 5-$10 bills. 3x = 3*5 = 15-$5 bills. 3x+30 = 3*5 + 30 = 45-$1 bills.
*October 1, 2013*

**physics**

a. Wt. = m * g 25kg * 9.8N/kg = 245 N. F1 = Force parallel to the incline. F2 = Force perpendicular to the incline. Q1. F1 = 245*sinA = u*F2 245*sinA = 0.45*245*cosA Divide both sides by 245*cosA: sinA/cosA = 0.45 Replace SinA/cosA with tanA: tanA = 0.45 A = 24.2o = Angle of ...
*October 1, 2013*

**physics**

V^2 = X^2 + Y^2 V^2 = 3.8^2 + 1,6^2 = 17 V = 4.12 m/s
*October 1, 2013*

**math**

I = Po*r*t = 17,000*0.025*5 = $2125
*October 1, 2013*

**Physics**

Correction: h = (0-20^2)/-19.6 = 20.4 m.
*October 1, 2013*

**Physics**

1. KE = 0.5m*V^2 = 5*20^2 = 2000 Joules 2. V^2 = Vo^2 + 2g*h = h = (V^2-Vo^2)/2g h = (0-20^20/-19.6 = 20.4 m.
*October 1, 2013*

**interest**

I = Po*r*t = 400 Po*(8.5/360)*30days = 400 0.70833*Po = 400 Po = $564.71 4564.71.
*September 30, 2013*

**Physics**

a. T=290km/81km/h + 210km/80km/h + 25/60 = 6.62 h. b. V = d/T = (290+210)/6.62 = 75.5 km/h.
*September 30, 2013*

**MATH**

P = Po + Po*r*t P = 675 + 675*0.1925*1 = $804.94
*September 30, 2013*

**Geometry**

Incomplete.
*September 29, 2013*

**math**

b. Amt. = 600*3 + 3200 = $5000 To start with. c. $3200/$ = 600 = 5.3 Months
*September 29, 2013*

**Physics**

h = 1.94*sin27.5 = 0.896 m. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*0.896 = 17.56 V = 4.19 m/s.
*September 29, 2013*

**physics**

See previous post: Sun,9-29-13,4:54 PM.
*September 29, 2013*

**physics**

a. V = Vo + g*t = 19 m/s. 39 - 9.8*t = 19 -9.8t = 19-39 = -20 t = 2.04 s. b. V = Vo + g*t = -19 m/s. 39 - 9.8t = -19 -9.8t = -58 t = 5.92 s.
*September 29, 2013*

**physics**

a. V^2 = Vo^2 + 2a*d a=(V^2-Vo^2)/2d = (15^2-0)/250=0.9 m/s^2 b. V = Vo + a*t t = (V-Vo)/a = (15-0)/0.9 = 16.67 s.
*September 29, 2013*

**physics**

Tr = 0.5 * 4.84 = 2.42 s. = Rise time. V = Vo + g.t = 0 @ max ht. Vo - 9.8*(2.42) = 0 Vo = 23.72 m/s. = Initial velocity. h = Vo*t + 0.5g*t^2 h = 23.72*2.42 - 4.9*2.42^2 = 28.7 m.
*September 29, 2013*

**physics**

See previous post.
*September 29, 2013*

**physics**

a. F = 7 + 10 = 17 N. b. F = 10-7 = 3 N. c. F1 = 7N[45o]. F2 = 10N[105o]. X = 7*cos45 + 10*cos105 = 2.36 N. Y = 7*sin45 + 10*sin105 = 14.6 N. tanA = Y/X = 14.6/2.36 = 6.18644 A = 80.8o Fr=Y/sinA = 14.6/sin80.8=14.8 N.[80.8o] = Resultant force. d. Fr = 7[160o] + 10[160o] = 17N[...
*September 29, 2013*

**Grade 12 physics**

F1 = 15N[66o],CCW. F2 = Pull South. F3 = Pull West. a. X = 15*cos66 + F3 = 0 F3 = -15*cos66 = -6.10 N. Y = 15*sin66 + F2 = 0 F2 = -15*sin66 = -13.7 N. b. X = 15*cos66-6.10 = 0 Y = 15*sin66 = 13.7 N.=13.7N Fn = X + Yi = 0 + Yi = 13.7i=13.7N[90o]
*September 29, 2013*

**physics**

Fa + Fb + Fc = 2.33N[S12.2W]
*September 29, 2013*

**physics**

Fa = 2.3N[235o],CCW. Fb = 3.6N[104o],CCW. Fc = 4.2N[294o],CCW. X=2.3*cos235+3.6*cos104+4.2*cos294 = -0.482 N. Y=2.3*sin235+3.6*sin104+4.2*sin294= -2.28 N. tan Ar = Y/X = -2.28/-0.482 = 4.62215 Ar = 77.8o = Reference angle. A = 77.8 + 180 = 257.8o CCW = 12.2o W of S. Fr = Y/...
*September 29, 2013*

**maths**

P = Po(1+r)^n n = 4Comp./yr * 5yrs. = 20 Compounding periods. P = 10,000(1+r)^20 = $20,000 Divide both sides by 10,000: (1+r)^20 = 2 Take Log of both sides: 20*Log(1+r) = Log 2 Divide both sides by 20: Log(1+r) = 0.015051 1+r = 10^0.015051 = 1.035265 r = 1.035265-1 = 0.035265...
*September 29, 2013*

**Physics**

a. 8.1[52o] + 8[180o] X = 8.1*cos52 + 8*cos180 = 4.99 Units Y = 8.1*sin52 + 8*sin180 = 6.38 Units. Mag. = Sqrt(4.99^2+6.38^2 = 8.1 Units tanA = Y/X = 6.38/4.99 = 1.27856 A = 51.97o = Direction. b. 8.1[52o] - 8[180o] Subtract and use same procedure as "a".
*September 29, 2013*

**physics**

Vf = 3.2m/s + 0.68*8 = 8.64 m/s.
*September 28, 2013*

**physics**

Incomplete.
*September 28, 2013*

**physics**

h = 168 - 0.5g*t^2 h = 168 - 4.9*2.24^2 = 143.4 m
*September 28, 2013*

**math**

(x+y+3y)/2 = 3x 6x = x+4y 4y = 5x Y = 5x/4
*September 28, 2013*

**physics**

F = m*a = 13 N. 36*a = 13 a = 0.361 m/s^2 d = 0.5a*t^2 = 0.5*0.361*4.5^2 = 3.66 m.
*September 28, 2013*

**physics**

Vo = 29m/s[36.9o] Xo = 29*cos36.9 = 23.2 m/s. Yo = 29*sin36.9 = 17.4 m/s. a. h = Yo*t + 0.5g*t^2 = 10 m 17.4*t - 4.9t^2 = 10 -4.9t^2 + 17.4t - 10 = 0. Use Quad. Formula. t = 0.72, and 2.83 s. b. X = Xo = 23.2 m/s. = Hor. component of velocity , and does not change. c. Y = Yo...
*September 28, 2013*

**Physics**

When t = 0, x = 0.
*September 27, 2013*

**dma040**

Do you mean V = (1/3)*ah? If so, V = ah/3 Multiply both sides by 3/a: h = 3V/a
*September 27, 2013*

**Physics**

L = (V^2-Vo^2)/2g a. L = (15^2-4.7^2)/19.6 = 10.4 m. b. h = L*sin10 h = 10.4*sin10 = 1.8 m. h = Vo*t + 0.5g*t^2 = 1.8 4.7t + 4.9t^2 = 1.8 4.9t^2 + 4.7t - 1.8 = 0 t = 0.293 s. Use Quadratic Formula.
*September 27, 2013*

**Crossing a River in min time**

TanA = (1km/h)/15km/h = 0.066666 A = 3.8o E. of N. d = 1.17/cos3.8 = 1.173km. = Distance boat must travel. Vb = 15/cos3.8 = 15.033 km/h d = V*t = 1.173 km 15.033t = 1.173 t = 0.078028 h = 4.68 Min.
*September 27, 2013*

**physics**

a. OA = 0.5a*t^2 = 25 m. 0.5a*7^2 = 25 0.5a*49 = 25 a = 1.02 m/s^2 b. V = a*t = 1.02 * 7 = 7.14 m/s. c. AB = (V^2-Vo^2)/2a AB = (15^2-7.14^2)/2.04 = 85.3 m.
*September 24, 2013*

**physics**

a. V = Vi + g*t b. d = Vi*t + 0.5g*t^2 c. V = -Vi + g*t. d = -Vi*t + g*t
*September 24, 2013*

**Phsyics**

Vo = 30m/s[80o] Yo = 30*sin80 = 29.54 m/s. hmax = (V^2-Vo^2)/2g hmax = (0-29.54^2)/-19.6 = 44.52 m Tr = -Vo/g = -29.54/-9.8 = 3.0 s = Rise time, Tf = 5-3 = 2 s. = Fall time. h = ho - 0.5g*t^2 h=44.52 - 4.9*2^2 = 24.92 m. after 5 s. 4.9*2^2 = 19.6
*September 24, 2013*

**physic**

V^2 = 30^2 + 5^2 = 925 V = 30.4 km/h.
*September 24, 2013*

**Physics**

Vo = 36km/h = 36000m/3600s = 10 m/s. V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g h = (0-10^2)/-19.6 = 5.0 m.
*September 23, 2013*

**Physics**

See previous post: Tue,1-18-11,6:56 PM.
*September 23, 2013*

**physics**

Correction: F2 = mg*cosA.
*September 23, 2013*

**physics**

mg = 667.5 N. F1 = mg*sinA = 667.5*sin38 = 411 N = Force parallel to the hill. F2 = mg*sinA= 667.5*cos38 = 526 N = Force perpendicular to the hill. Fs = u*F2 = 0.4 * 526 = 210.4 N = Force of static friction. Yes, because F1 is greater than the forceof s tatic friction, Fs.
*September 23, 2013*

**Physics**

a. V2 = T2/T1 * P1/P2 * V1.
*September 23, 2013*

**physics**

Vo = 18.9m/s[47o] Xo = 18.9*cos47 = 12.9 m/s. Range = Vo^2*sin(2A)/g Range = 18.9^2*sin94/9.8 = 36.4 m. Range = Xo * t = 36.4 m. 12.9 * t = 36.4 t = 2.82 s. in flight. d = 54.4-36.4 = 18 m To run in 2.82 s. Speed = d/t = 18m/2.82s = 6.38 m/s.
*September 23, 2013*

**Physics**

Vo = 15m/s[75o] Xo = 15*cos75 = 3.88 m/s. Range = Vo^2*sin(2A)/g Range = 15^2*sin(150)/9.81 = 11.47 m. d = 0.5a*t^2 = 11.47 m. 0.5a*1.03^2 = 11.47 0.53a = 11.47 a = 21.6 m/s^2.
*September 22, 2013*

**Physics**

0.4.9*t^2 = h t^2 = h/4.9 t = sqrt (h)/2.21 = Fall time. S = Vx * t
*September 22, 2013*

**Physics**

P = mg*d/t = 600 * 1.2/1.5 = 480 J/s = 480 Watts.
*September 22, 2013*

**physics**

See previous post: Sun,9-22-13,8:57 PM.
*September 22, 2013*

**physics**

a = (V-Vo)/t = (34-10)/10 = 2.4 m/s^2. Fn = m*a = 1570 * 2.4 = 3768 N.
*September 22, 2013*

**physics**

See previous post: Tue,1-18-11,6:56 PM.
*September 22, 2013*

**Physics**

a = (V-Vo)/t = (10-(-50))/15 = 4 m/s^2.
*September 22, 2013*

**Physics**

A. h = 0.5g*t^2 = 4.9*15^2 = 1103 m. B. d = 290m/s * 15s = 4350 m. C. Over the island.
*September 22, 2013*

**physics**

See previous post: Sat,9-21-13,11:52 PM.
*September 22, 2013*

**physics**

Da = 204 + Db Da = 22.9t = 204 + 18.6t 22.9t-18.6t = 204 4.3t = 204 t = 47.44 s. To catch up.
*September 22, 2013*

**physics**

d = 0.5a*t^2 = 0.725 * 63.7^2 = 2942 Rad
*September 22, 2013*

**physics**

d1 + d2 = 5.16 m. (Vo*t+0.5g*t^2 ) + (Vo*t+0.5g*t^2=5.16 (8.67t-4.9t^2) + (8.67*t+4.9*t^2 = 5.16 8.67t + 8.67t = 5.16 17.34t = 5.16 t = 0.298 s. Note: 4.9t^2-4.9t^2 = 0 d1 = 8.67*0.298 - 4.9*0.298^2 = 2.14 m Above gnd. = The point where they meet.
*September 21, 2013*

**Physics**

Incomplete and unclear.
*September 21, 2013*

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