Sunday

March 29, 2015

March 29, 2015

Total # Posts: 10,338

**Science**

P = Mg*h/t = Mg * 30/24 = 15,000 Mg = 12,000 N. = Total Wt.
*March 10, 2015*

**science past year**

5. E1 = 60 V. E2 = 30 V. R1 = 0.5 Ohms. R2 = 10-Ohm Load. R3 = 0.6 Ohms. R2*I2 + R1*I1 = 60 V. I1 = I2 + I3 R2*I2 + R1*(I2+I3) = 60 10I2 + 0.5I2 + 0.5I3 = 60 Eq1: 10.5I2 + 0.5I3 = 60 R2I2 - R3I3 = 30 V. Eq2: 10I2 - 0.6I3 = 30 Multiply Eq1 by 0.6 and Eq2 by 0.5. Then add the ...
*March 10, 2015*

**science past year**

1. E = 10 Volts. R1 = 1.5 Ohms. R2 = 3 Ohms. R = ? 1.1.1 R1//R2 = R1*R2/(R1+R2) = (1.5*3)/(1.5+3) = 1 Ohm. Rt = E/I = 10/2 = 5 Ohms = Total resistance. R = 5-1 = 4 Ohms. 1.1.2 Pd = E*I = 10 * 2 = 20 Watts. 1.2 0.004/C*(35-10)C * 100 = 10 Ohm Increase. 6. Rt = (R1*R2/(R1+R2) + ...
*March 10, 2015*

**Physics**

Fp = ((Vs+Vp)/(Vs-Vh))*Fh Fp = ((343+0)/(343-23)*378 = 405.2 Hz. Fp = Freq. heard by the person. Vp = Velocity of the person. Vs = Velocity of sound in air. Vh = Velocity of the horn. Fh = Freq. of the horn.
*March 10, 2015*

**physics**

Range = Vo^2*sin(2A)/g = 18 A = 60o g = 9.8 m/s^2 Vo = Initial velocity in m/s. Solve for Vo.
*March 10, 2015*

**physics**

a. V^2 = Vo^2 + 2g*h Vo = 0 g = 9.8 m/s^2 h = 50 m. Solve for V.
*March 10, 2015*

**physics**

a. V = Vo + a*t Vo = 30 m/s V = 10 m/s t = 5s. Solve for a. It will be negative. b. d = Vo*t + 0.5a*t^2
*March 10, 2015*

**physics**

M*g = 92 * 9.8 = 901.6 N. = Wt. of crate = Normal force, Fn. Fk = u*Fn = 0.357 * 901.6 = 321.9 N. = Force of kinetic friction. a. Fex-Fk = 289 - 321.9 = -32.9 N. The Force of friction is greater than the exerted force.
*March 9, 2015*

**Math**

2h[135o] + 3h[55o] X = 2*Cos135 + 3*Cos55 = 0.307 h. Y = 2*sin135 + 3*sin55 = 3.87 h. Tan A = Y/X = 3.87/0.307 = 12.61 A = 85.5o = The direction. T = Y/sin85.5 = 3.88 h.
*March 9, 2015*

**physics**

d = Vo^2*sin(2A)/g = 300^2*sin(60)/9.8 =
*March 9, 2015*

**physics for physical science**

See Related Questions: Sun, 2-3-13, 1:05 PM.
*March 9, 2015*

**Math**

r = 14 Ft. X = 10.7 Ft. CosA = X/r
*March 8, 2015*

**Math**

X = 13 Ft. Y = Ht. = 10 Ft. TanA = Y/X
*March 8, 2015*

**math**

See your previous post.
*March 8, 2015*

**physics**

M*g = 20 * 9.8 = 196 N. = Wt. of block. Fp = 196*sin30 = 98 N. = Force parallel t0 the incline. Fn = 196*Cos30 = 169.7 N. = Normal force Fk = u*Fn = 0.2 * 169.7 = 33.95 N. = Force of kinetic friction. a. Fap-Fp-Fk = M*a a = 0 Fap = Force applied. Solve for Fap. Work = Fap * d ...
*March 8, 2015*

**math**

See your previous post.
*March 8, 2015*

**Math**

b. T = Tr + Tf = 1.94 + 1.94 = 3.88 s. Tr = Rise time. Tf = Fall time.
*March 8, 2015*

**Math**

t = -B/2A = -62/-32 = 1.94 h = -16*1.94^2 + 62*1.94 + 2 = 62.1 Ft.
*March 8, 2015*

**Chemistry**

What is the method used to separate water from bleached wood pulp?
*March 8, 2015*

**Math**

X1=Mike's distance from bottom of tower. X1+21.2 = Lani's distance from bottom of tower. Tan40 = h/X1 h = X1*Tan40 Tan38.5 = h/(X1+21.2) h = (X1+21.2)*Tan38.5 h = X1*Tan40 = (X1+21.2)*Tan38.5 0.839X1 = 0.795X1 + 16.86 0.044X1 = 16.86 X1 = 383 m. h = 383 * Tan40 = 322 m.
*March 8, 2015*

**math**

V = Vo - Vo*r*t = 5000 - 5000*0.05*5 = 5000 - 1250 = $3750 = Value after 5 yrs.
*March 7, 2015*

**physics**

See Related Questions: Wed, 5-28-14, 8:01 PM.
*March 7, 2015*

**Physics**

M1*V1 + M2*V2 = M1*V3 + M2*V4 0.02*0.25 - 0.04*0.15 = 0.02*(-0.16) + 0.04*V4 0.005-0.006 = - 0.0032 + 0.04*V4 -0.001 + 0.0032 = 0.04*V4 0.04*V4 = 0.0022 V4 = 0.055 m/s.
*March 7, 2015*

**Physics**

Impulse = M*V
*March 7, 2015*

**Physics**

Range = Vo^2*sin(2A)/g = 7^2*sin(80)/9.8 = 4.92 m.
*March 7, 2015*

**Physics**

Vo = 5m/s[35o] Yo = 5*sin35 = 2.87 m/s. Y^2 = Yo^2 + 2g*h = 0 h = -Yo^2/2g = -(2.87)^2/-19.6 = 0.42 m
*March 7, 2015*

**Physics**

See previous post: Fri, 3-6-15, 4:28 AM.
*March 7, 2015*

**Geometry**

Horizon: C = 0.30x + 28 X = Minutes used. Sprint: C = 0.029x + 30
*March 7, 2015*

**math word problem**

r = 66Ft./6s = 11 Ft/s
*March 7, 2015*

**Dynamics of machinery**

See Related Questions: Wed, 12-31-14, 5:48 AM.
*March 7, 2015*

**physics**

M1*V1 + M2*V2 + M3*V3 = M1*V + M2*2[60o] + M3*3[30o] M1 = M2 = M3? M1*V1 + M1*V2 + M1*V3 = M1*V + M1*2[60o] + M1*3[30o] M1*4 + M1*0 + M1*0 = M1*V + M1*2[60] + M1*3[30] Divide both sides by M1: 4 = V + 2[60] + 3[30] 4 = V + 2*Cos60 + 2*sin60 + 3*Cos30 + 3*sin30 4 = V + 1 + 1....
*March 7, 2015*

**physics**

V^2 = Vo^2 + 2a*d = 0 + 2*2*9 = 36 V = 6 m/s
*March 7, 2015*

**Physics**

h = 19.5 - 1.6 = 17.9 m. Dx = 58 m. 1. h = 0.5g*T^2 = 17.9 4.9T^2 = 17.9 T^2 = 3.65 T = 1.91 s. = Fall time. Dx = Vo*T = 58 Vo * 1.91 = 58 Vo = 58/1.91 = 30.3 m/s 2. V^2 = Vo^2 + 2g.h = 0 + 19.6*17.9 = 350.84 V = 18.7 m/s
*March 7, 2015*

**math**

What is the area of the largest rectangle with lower base on the x-axis and upper vertices on the curve y equals 27 minus x^2?
*March 6, 2015*

**Science**

Total momentum before the collision = Total momentum after the collision. C. 100kg m/s.
*March 6, 2015*

**Physics**

Fo = ((Vs+Vo)/(Vs-Vg))*Fg = 1185 Hz ((343+Vo)/(343-0))*1099 = 1185 ((343+Vo)/343)*1099 = 1185 Multiply both sides by 343/1099: 343 + Vo = 1185 * 343/1099 = 369.8 Vo = 369.8 - 343 = 26.84 m/s = Velocity of the observer.
*March 6, 2015*

**Physics**

M*V1 + M*V2 = 30,000 V1 = 20 m/s V2 = 5 m/s Solve for M.
*March 6, 2015*

**Physics**

d = Xo*t = 15 m. 12t = 15 t = 1.25 s. = Fall time.
*March 6, 2015*

**Physics**

d = Vx*Tf = 3 m. 0.5m/s * Tf = 3 Tf = 6 s. = Fall time. h = 0.5g*Tf^2 = 4.9 * 6^2 = 176.4 m.
*March 6, 2015*

**Physics**

h = 0.5g*t^2 = 7.5 4.9t^2 = 7.5 t^2 = 1.53 t = 1.24 s. = Fall time. d = Vx*t = 15m/s * 1.24s = 18.6 m.
*March 6, 2015*

**physics**

T = M*g + M*a
*March 6, 2015*

**physics**

Vo=1.65 rev/s * 6.28rad/rev=10.362 rad/s V=0.485rev/s * 6.28rad/rev = 3.05 rad/s a. a = (V-Vo)/t
*March 6, 2015*

**Physics**

d = V*t = 4800 m t = 4800/343 = 14 s.
*March 5, 2015*

**Calculus, HELP!!**

1) A rectangular page is to contain 24 square inches of print. The page has to have a 6-inch margin on top and at the bottom and a 1-inch margin on each side. Find the dimensions of the page that minimize the amount of paper used. 2) A cable runs along a wall from C to P at a ...
*March 5, 2015*

**physics**

d1 = V*t = 42m/s * 0.8s = 33.6 m. Head start for the speeder. d2 = d1 + 33.6 m. 20*t + 0.5*a*t^2 = 42*t + 33.6 20t+ 0.5*5*t^2 = 42t + 33.6 2.5t^2 -22t = 33.6 2.5t^2 - 22t - 33.6 = 0 Use Quadratic Formula. t = 10.13 s.
*March 5, 2015*

**Physics**

You gave your answer in miph/s. The problem says "give your answer in mph/s". Which one is correct? 1. a = (V-Vo)/t = (70-0)/3=23.3 miph/s. a = (99.2-0)/4 = 24.8 kmph/s. 2. a = 23.3miph/s * 1.6km/mi = 37.3 kmph/s. = acceleration of the cheetah. a = 24.8 kmph/s = ...
*March 5, 2015*

**Physics**

Eff. = (Output/Input)*100% =(230/420)*100 = 54.8%
*March 4, 2015*

**Physics**

Tension = M*g + M*a
*March 4, 2015*

**physics**

F = 97N - 107N[71.4] Fx = 97 - 107*Cos71.4 = 62.87 N. Fy = 0 - 107*sin71.4 = -101.4 N. a. F^2 = Fx^2 + Fy^2=62.87^2 + (-101.4^2) = 119.3 N. F = N. b. Tan A = Fy/Fx = -101.4/62.87 = -1.61285 A = -58.2o S of E = 301.8o CCW c. 107N[71.4o] - 97
*March 4, 2015*

**Physics**

Fg = M*g = 4 * 9.8 = 39.2 N. = Force of gravity. Fp = 39.2*sin30 = 19.6 N. = Force parallel to the incline. Fn = 39.2*Cos30 = 33.9 N. = Normal force a. W = Fg*d = 39.2 * 10 = 392 J. b. W = Fn*d = 33.9 * 10 = 339 J. c. d. h = d*sin30 = 10*sin30 = 5 m. KE = PE = Mg * h = 39.2 * ...
*March 4, 2015*

**Physics**

M*g = 70*10 = 700 N. = Wt. = Force of gravity(Fg). h = 31steps * 15m/step = 465 m. Work = F*h = Mg * h Joules.
*March 4, 2015*

**Physics**

M*g = 2.2 * 9.8 = 21.56 N. = Wt. of block. Fp = 21.56*sin27.7 = 10.02 N. = Force parallel to incline. Fn = 21.56*Cos27.7 = 19.09 N. = Normal force. Fk = u*Fn = 0.41 * 19.09 = 7.83 N. = Force of kinetic friction. a. a = (Fp-Fk)/M = (10.02-7.83)/2.2 = 0.995 m/s^2 b. L = h/sin27....
*March 3, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*V 5*3 + 5*0 = 5*V + 5*V Solve for v.
*March 3, 2015*

**physics**

V^2 = Vo^2 + 2g*h Vo = 24 m/s g = -9.8 m/s^2 h = 13 m. Solve for V.
*March 3, 2015*

**math**

P = Po(1+r)^n Po = $3,000 r = 1.8%/12/100% = 0.0015. n = 12Comp./yr. * 3yrs. = 36 Compounding periods. Solve for P.
*March 3, 2015*

**physical science**

V^2 = Vo^2 + 2g*d Vo = 0 g = +9.8 m/s^2 d = 80 m. Solve for V.
*March 3, 2015*

**Physics**

M1*V1 + M2*V2 = M1*V3 + M2*V4 M1 = M2? M1*4 + M1*0 = M1*3.46[30o] + M1*V4 Divide both sides by M1: M1*4 = M1*3.46[30] + M1*V4 4 = 3.46[30] + V4 V4 = 4 - 3.46[30] = 4 - 3 - 1.73i = 1-1.73i = 2.0m/s[300o] = Velocity of target ball.
*March 3, 2015*

**physics**

If an object weighs 480 N. on the earth, it's weight on the moon will be 480/6 = 80 N. How did you get 120 N.? The mass on the moon is the same as on earth.
*March 3, 2015*

**trigonometric functions**

h = 100*sin14 =
*February 27, 2015*

**math**

3 thousands, and 3 hundredths.
*February 27, 2015*

**physics**

F-200 = M*a F-200 = 350 * 3 = 1050 F = 1250 N.
*February 27, 2015*

**3rd grade math**

1/3 * 36 = 12.
*February 27, 2015*

**math**

3 thousands, and 3 hundredths.
*February 26, 2015*

**science please help asap**

See Related questions: 2-26-15, 11:06 AM.
*February 26, 2015*

**Math**

2. x + 4 > 6 3. x => 3C 4. x => $15
*February 26, 2015*

**Physics**

F = 392 + 2 = 394 Hz
*February 26, 2015*

**Math**

RQ = 2-(-2) = 4 = Hor. line RP = (2-(-1) = 3 = Ver. line, downward. Tan A = RQ/RP = 4/3 = 1.33333 A = 53.1o
*February 26, 2015*

**maths**

Cos A = 2m/9m.
*February 26, 2015*

**math**

Plate cost $X. A cup cost $2X. A pot cost $2X + 3 x + 2x + 2x+3 = $10.20 Solve for x.
*February 26, 2015*

**physics**

Circumference = pi*2r = 3.14 * 4,180 = 13,132 m. d = V*t d = 13,132 m. V = 233 m/s. Solve for t.
*February 26, 2015*

**Physics mechanics**

d = 60^2/30^2 * 8 = 4 * 8 = 32 m
*February 26, 2015*

**science please help asap**

2. M*g = 490 * 9.8 = 4802 N. = Wt. of the body. Fn = Mg-Fap*sin A = 4802-1200*sin20 = 4392 N = Normal force. Fx-Fs = M*a 1200*Cos20 - Fs = M*0 1128 - Fk = 0 Fk = 1128 N. = Force of kinetic friction u = Fk/Fn = 1128/4392 = 0.257 3A. F = M*a F = 318.1 N. a = 3 n/s^2 M = mass in ...
*February 26, 2015*

**Physics**

Work = F*d = Mg * d. Their wt. and distance was the same; therefore, they did the same amount of work.
*February 26, 2015*

**science**

See previous post.
*February 25, 2015*

**physics**

The force must be in the same direction as the motion(hor.). Work = Fx*d = 0 * 10 = 0
*February 25, 2015*

**Physics**

Work = Fx*d = 200*Cos30 * 20 = Answer in Joules.
*February 25, 2015*

**Math**

(-4,3), (h,k), (6,-5). The center = 1/2 of the total distance: h - (-4) = (6 - (-4))/2 h + 4 = 10/2 = 5 h = 1 k-3 = (-5-3)/2 Solve for k.
*February 25, 2015*

**algebra**

Sarita: X muffins. Clara: X muffins. Joe: X muffins. Clara: x-1 = 14 X = 15 Total = 3x = 3*15 = 45 muffins.
*February 25, 2015*

**algebra**

3x^2 + 3x - 6 = 0 A*C = 3*(-6) = -18 = -3*6 Choose the pair of factors whose sum = B = +3: -3, and 6. 3x^2 + (-3x+6x) - 6 = 0 Form two factorable binomials: (3x^2-3x) + (6x-6) = 0 3x(x-1) + 6(x-1) = 0 (x-1)(3x+6) = 0 (x-1)*3(x+2) = 0 x-1 = 0 X = 1 3(x+2) = 0 Divide by 3: x+2...
*February 25, 2015*

**physics**

V^2 = Vo^2 + 2a*d a = V^2/2d = 87^2/170 = 44.5 m/s^2. M*g = 219,000 N. M = 219000/g = 219000/9.8 = 22,347 kg F = M*a = 22,347 * 44.5 =
*February 25, 2015*

**Physics**

Incomplete.
*February 25, 2015*

**Physics**

V^2 = Vo^2 + 2a*d V = 64.1 m/s Vo = 0 d = 29.2 m. Solve for a. F = M*a M = 35.5 kg Solve for F.
*February 25, 2015*

**physics**

a. V^2 = Vo^2 + 2g*h = 0 Vo^2 = -2g*h = -(-19.6)*1.29 = 25.284 Vo = 5.03 m/s b. 0.5g*t^2 = 1.29 m. 4.9t^2 = 1.29 t^2 = 0.263 Tf = 0.513 s. = Fall Time. Tr = Tf = 0.513 s. = Rise time. Hang time = Tr + Tf = 0.513 + 0.513 = 1.026 s.
*February 25, 2015*

**Algebra**

Y = 3x^2 + 19x - 72 = 0 A*C = 3*(-72) = -216 = -8*27. Sum = 19 (3x^2-8x) + (27x-72) = 0 x(3x-8) + 9(3x-8) = 0 (3x-8)(x+9) = 0 3x-8 = 0 3x = 8 X = 8/3 x+9 = 0 X = -9 Solution: X = -9, and 8/3.
*February 25, 2015*

**Physics**

V = Vo + a*t = Vo = 0 a = 3m/s^2 t = 10 s. Solve for V.
*February 25, 2015*

**physics**

F = M * 3g = 63.6kg * 3*9.8N/kg =
*February 25, 2015*

**Science**

a. PE max = Mg*h = 59*9.8*24 = 13,877 J. b. KE + PE = PE max = 13,877 J.
*February 25, 2015*

**math**

$X in account. x-30 = 3x/4 4x-120 = 3x X = $120
*February 25, 2015*

**physics**

V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d V = 0.63 m/s Vo = 0 d = 0.45 m. Solve for a. F = M*a M = 69 kg Solve for F.
*February 25, 2015*

**Math SO HARD :C**

T + 8 = -20 T = -20-8 = -28o C @ Midnight.
*February 25, 2015*

**physical science**

Correct.
*February 25, 2015*

**Physics**

I = V/R = 9/230 = 0.0391 Amps = 39.1 mA.
*February 25, 2015*

**Algebra 1**

Multiply Eq1 by -2 and add: -10x - 2y = -18 +10x - 7y = 18 Sum: 0 - 9y = 0 Y = 0 In Eq1, replace Y with 0 and solve for X -10x - 2*0 = -18 X = 1.8
*February 24, 2015*

**maths**

X pizzas 4X Drinks 12x + 0.5*4x = 112 Solve for X.
*February 24, 2015*

**physics**

Thank you Damon! I think I understand what you meant when I read your post My triangle was correct though, yes? I just referred to them wrong?
*February 24, 2015*

**physics**

Wait that's not how it's supposed to look. Ok
*February 24, 2015*

**physics**

How do I know which trig function to use? I made my second triangle like this _____ \ | \ | \ | \|
*February 24, 2015*

**physics**

Why did you swap Betas trig functions?
*February 24, 2015*

**physics**

What do you mean, I did indicate on the question that it was west of north?
*February 24, 2015*

**physics**

A golfer takes two putts to sink the ball, one is (81.6 ft, 31.7 degrees N of E) and the other is (3.20 ft, 53.4 degrees W of N). What is the displacement of the single putt that would sink the ball on the first try? Well, what I did was make a diagram of the two vectors, I ...
*February 24, 2015*

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