Monday
January 23, 2017

Posts by Henry

Total # Posts: 13,051

Math
db = 10*Log(Po/75) = 12. Log(Po/75) = 1.2, Po/75 = 10^1.2, Po = 1189 W.
December 14, 2016

Physics
a. Vo = 20m/s[45o]. Xo = 20*Cos45 = 14.14 m/s. Yo = 20*sin45 = 14.14 m/s. Y = Yo + g*t = 0. 14.14 - 9.8t = 0, t = 1.44 s. b. Y^2 = Yo^2 + 2g*h = 0. (14.14)^2 - 19.6h = 0, h = ?. c. Range = Vo^2*sin(2A)/g. A = 45o. d. T = Tr+Tf. Tf = Tr, T = Tr+Tr = 1.44 + 1.44 = 2.88 s. d.
December 14, 2016

Math
Invested: Po @ 2%. (2Po+2300) @ 9%. t = 1 yr.? I = Po*r*t + (2Po+2300)*r*t = 647. Po*0.02*1 + (2Po+2300)*0.09*1 = 647, 0.02Po + 0.18Po + 207 = 647, 0.20Po = 440, Po = $2200. 2Po+2300 = 2*2200 + 2300 = $6700.
December 13, 2016

Mathematics
1. (8,11). y/x = 11/8, Y = 1.375x. 2. correct. 3. y/x = 232/4 = 58/1. 4. (2,5), (8,3). m = (3-5)/(8-2) = -2/6 = -1/3.
December 13, 2016

math
Correction: 360cm^3/2^3 = 45 Cubes.
December 13, 2016

physics
Work = KE2-KE1 = KE2-0 = KE2. KE2 = 0.5M*V^2 = 10,000 J. 500*V^2 = 10,000, V = ?.
December 12, 2016

Physics
a. M*g = 1.35 * 9.8 = 13.2 N. = Wt. of book. = Normal force(Fn). Fs = us*Fn = 0.45 * 13.2 = 5.95 N. F-Fs = M*a. F = Fs+M*a = 5.95+M*0 = 5.95 N. b. Fk = uk*Fn = 0.30 * 13.2 = 3.96 N. F-Fk = M*a. a = (F-Fk)/M. c. Fap-Fk = M*a. Fap = Fk+M*a = 3.96 + M*0 = 3.96 N. = Force applied...
December 12, 2016

Physics
e. Fnet = M*a. a = Fnet/M.
December 12, 2016

Physics
a. M*g = 475 * 9.8 = 4655 N. = Wt. of sleigh. = Normal force(Fn). b. Fs = u*Fn = 0.20 * 4655 = c. Fk = uk*Fn = 0.15 * 4655 = d. Fnet = Fh-Fk = 150,000-4655 =
December 12, 2016

Science
F = M*a. = 20. a = 20/M = 20/60 = 0.333 m/s^2.
December 11, 2016

physics
See previous post: Sun, 12-11-16, 7:32 PM.
December 11, 2016

Physics
M*g = 180 * 9.8 = 1764 N. = Wt. of trunk. Fn = 1764 - 400*sin15 = 1661 N. = Normal force. Fap*Cos A-Fk = M*a. Fk = Fap*Cos A-M*a = 400*Cos15-M*0 = 386.4 N. = Force of kinetic friction. Fk = u*Fn = 386.4. u = 386.4/Fn = 386.4/1661 = 0.233 = Coefficient of kinetic friction.
December 11, 2016

Physics
3. V = Vo + a*t = 0. 25 + a*8 = 0, a = -3.1025 m/s^2 Thrust = M*a = 958/9.8 * (-3.125) = -305.5 N. 5. M*g = 3.0 * 9.8 = 29.4 N. = Wt. of block = Normal(Fn). Fs = u*Fn = 0.4 * 29.4 = 11.8 N. 7. M*g = 50 * 9.8 = 490 N. = Wt. of box = Normal(Fn). Fk = u*Fn = 0.35*490 = 171.5 N. F...
December 11, 2016

Physics
Y^2 = Yo^2 + 2g*h = 0. Yo^2 - 64*20 = 0, Yo = 35.8 Ft/s. Vo*sin30 = 35.8, Vo = 71.6 Ft/s.
December 11, 2016

algebra
See previous post: Sun, 9-11-16, 2:24 PM.
December 11, 2016

algebra
Donuts: $X ea. Coffee: $Y ea. Eq1: 3x + 4y = 4.91 Eq2: 5x + 6y = 7.59 Multiply Eq1 by 5 and Eq2 by (-3): +15x + 20y = +24.55 -15x - 18y = -22.77 Sum: 2y = 1.78, Y = 0.89 In Eq1 replace Y with 0.89: 3x + 4*0.89 = 4.91. X = ?
December 11, 2016

algebra 1
Right!
December 11, 2016

algebra 1
(-3,-7), (-5,-7). m = (-7-(-7))/(-5-(-3)) = 0/-2 = 0. Y = mx + b = -7. 0*x + b = -7, b = -7, Eq: Y = -7 = A horizontal line.
December 11, 2016

algebra 1
X 2-pointers. (16-x) 3-pointers. 2x + 3(16-x) = 38, 2x + 48 - 3x = 38, X = 10. 16-x = 16-10 = 6.
December 11, 2016

algebra
X 2-pointers. (16-x) 3-pointers. 2x + 3(16-x) = 38, 2x + 48 - 3x = 38, X = 10. 16-x = 16-10 = 6.
December 11, 2016

math
post it.
December 11, 2016

Algebra
x^2 - 6x + 9 > 0. (x-3)^2 > 0, Take sqrt of both sides: x-3 > 0, X > 3.
December 10, 2016

Algebra
h(t) = 240 - 16tT^2 = 0. 16t^2 = 240, t = 3.87 s. 6
December 10, 2016

Math
a. Net Cash = 780,000 - 270,000 - 60,000 - 0.05(780,000-200,000) = $421,000.
December 10, 2016

Algebra
18a. F(x) = x - 5. 18b. F(x) = x - 0.25x = x(1-0.25) = 0.75x.
December 10, 2016

math
Randy: 28min.-11.0 s. Julie: 28min.-03 s. Pat: 28min.-2.9 s.
December 8, 2016

Science physics
See Related Questions: Feb 13, 2008, 11:12 PM.
December 8, 2016

Physics
%Eff. = Output/Input * 100% = 40/150 * 100% =
December 7, 2016

Trigonometry
correction: 2.5rev/10s * 6.28rad/rev = 1.57 rad/s.
December 6, 2016

Trigonometry
Va = 2.5rev/10s. * 6.28rad/rev = 15.7 rad/s.
December 6, 2016

math
d = V*t = 21*10^6 m. t = 21*10^6/3*10^8 = 7*10^-2 s. = 70 ms.
December 6, 2016

Algebra
2. (-2,-3), (1,1). m = (y2-y1)/(x2-x1) = (1-(-3))/(1-(-2)) = (1+3)/(1+2) = 4/3. 4. 24/8 = y/10, Y = 30. 5. Y = (2/3)x + 9. 6. (1,-3), (3,1). m = (1+3)/(3-1) = 2. Y = 2x + b = -3. 2*1 + b = -3, b = -5. Eq: Y = 2x - 5.
December 5, 2016

Mathematics
I = Po*r*t = 800*0.02*2 = $32.
December 5, 2016

Physics
M*g = 15 * 9.8 = 147 N. = Wt. of box. Fp = 147*sin30 = 73.5 N. = Force parallel to the incline. Fx = Fp*Cos30 = 73.5*Cos30 = 63.6 N.
December 4, 2016

Physics
M*g = 1.5, M = 1.5/g = 1.5/9.8 = 0.153 kg. PE = Mg*h = 1.5 * 4 = 6.0 J. V^2 = Vo^2 + 2g*h = 0 + 19.6*4 = 78.4 (m/s)^2. KE = 0.5M*V^2 = 0.5*0.153*78.4 = 6.0 Joules. Energy Lost = PE - KE = 6-6 = 0.
December 4, 2016

PreCalc
A = Po(1+r)^n. Po = $14,000. r = 0.052/12 = 0.0043/mo. n = 12comp./yr. * t yrs. = 12t compounding periods.
December 4, 2016

Maths
Bisi is X yrs. old. Musa is (x+12) yrs. old. Four yrs. later: Bisi is (x+4) yrs. old. Musa is 2(x+4) = 2x+8. 2x+8 = (x+4) + 12. 2x+8 = x+16, X = 8. x+12 = 8+12 = 20.
December 4, 2016

Physics
Vo = 5.6m/s[10o]. Xo = 5.6*Cos10 = 5.51 m/s. Yo = 5.6*sin10 = 0.97 m/s. Y^2 = Yo^2 + 2g*h = 0. 0.97^2 - 19.6h = 0, h = 0.048 m. Y = Yo + g*Tr = 0. 0.97 - 9.8Tr = 0, Tr = 0.099 s. = Rise time. 0.5g*Tf^2 = (0.048+3). 4.9Tf^2 = 3.048, Tf = 0,789 s. = Fall time. Dx = Xo*(Tr+Tf) = ...
December 4, 2016

MATH
11,450-10,000 = $1450 = profit on the remaining 2/3. 1450/10,000 * 100% = 14.5 % = Gain % on remaining 2/3.
December 4, 2016

MATH
15,000/3 = $5,000 = selling price to break even. 0.95 * 5000 = $4750 = selling price. Loss = 5000-4750 = $250. 10,000 + 250 = $10,250 = selling price to break even. 15,000 * 1.08 = $16,200 = total selling price for 8% profit. 16,200-4750 = $11,450 = Selling price of the ...
December 4, 2016

Math
M*g = 2 * 9.8 = 19.6 N. = Wt. of flowers. Fp = 19.6*sin A. = Force parallel with incline. Fn = 19.6*Cos A. = Normal force. Fs = u*Fn = 0.4*19.6*Cos A = 7.84*Cos A. = Force of static friction. Fp-Fs = M*a. 19.6*sin A-7.84*Cos A = M*0 = 0, 19.6*sin A = 7.84Cos A, 19.6*sin A/Cos ...
December 4, 2016

mathematics
A = L*W + 2W*h + 2L*h. A = 11*8 + 2(8*5) + 2(11*5) = 278 ft^2.
December 4, 2016

Math
(Vb-Vr) * T1 = 36 (Vb-Vr)3 = 36 Eq1: Vb - Vr = 12 (Vb+Vr) * T2 = 36 (Vb+Vr)2 = 36 Eq2: Vb + Vr = 18 Add Eq1 and Eq2: Vb - Vr = 12. Vb + Vr = 18. Sum: 2Vb = 30, Vb = 15 mi/h. In Eq1, replace Vb with 15: 15 - Vr = 12, Vr = 3 mi/h.
December 4, 2016

Math
Please proofread your problem; it doesn't make sense as written.
December 4, 2016

Propotion
When speed = 60km/h. time = T1. When speed = 80 km/h, time = (60/80)T1 = 0.75T1.
December 4, 2016

ALGEBRA PLZ HELP!1
L = 2in * 12ft/1n = 24 ft. W = 1.75in * 12ft/1n =
December 4, 2016

Math
10/35 = 8/W. W = ?.
December 4, 2016

Math
Length = 12 cm. Width = 1/1.414 * 12cm = 8.49 cm. Area = L * W.
December 4, 2016

math
65%/35% * 20Litres. = 37.1 Litres.
December 3, 2016

Physics
Va = 65mi/h * 1600m/mi * 1h/3600s = 28.9 m/s. F1 = (Vs+Vp)/(Vs-Va) * Fa. F1 = (330+0)/(330-28.9) * 500 = 548.0 Hz. F2 = (330-0)/(330+28.9) * 500 = 459.7 Hz. F1-F2 = 548 - 459.7 = 88.3 Hz. = Total shift in freq.
December 3, 2016

math
P = Po(1+r)^n. Po = 200 r = (9%/12)/100% = 0075/mo. n = 1comp./mo. * 24mo = 24 Compounding periods. P = 200(1.0075)^24 = $239.28
December 2, 2016

FINANICIAL
Po = 46,000/(1.0755)^12 = $19,205.82
December 2, 2016

FINANICIAL
P = Po(1+r)^n = 46,000. r = 7.55%/100% = 0.0755. n = 1comp./yr. * 12yrs. = 12 Compounding periods. Po = ?.
December 2, 2016

Physics
h = 0.5g*t^2 = 2.4-0.91. 4.9t^2 = 1.49. t1 = 0.551 s. d1 = Xo*t1 = 22.3 * 0.551 = 12.3 m. = Distance from back line to net. 0.5g*t2^2 = 2.4. 4.9t2^2 = 2.4, t2 = 0.70 s. to fall to gnd. d2 = Xo*t2 = 22.3 * 0.7 = 15.6 m. = Maximum distance travelled. a. Yes. b. d = 12.3 + 6.4 = ...
December 1, 2016

algerba
X pennies, and Y nickels. Eq1: 1x + 5y = 920 cents. Eq2: 5x + 1y = 2680 cents. -5x - 25y = -4600 +5x + 1y = 2680 Sum: -24y = -1920 Y = 80 nickels. In Eq1, replace Y with 80: x + 5*80 = 920, X = 520 Pennies.
December 1, 2016

MATH
Po = 46,000/(1.0755^12) = $19,205.82 = Amt. invested now.
December 1, 2016

math algebra
A = P*e^rt. P = $2,000 rt = 0.0475/yr. * 30yrs. = 1.425. A = ?.
December 1, 2016

Math
W = -(40*Cos30+60*Cos(theta)). -40*sin30 + 60*sin(theta) = 0. 60*sin(theta) = 40*sln30, sin(theta) = 2/3 * sin30 = 0.3333, theta = 19.5o W = -(40*Cos30+60*Cos19.5) = -91.2 N.
December 1, 2016

physics
6.28rad/rev * 2rev = 12.56 rad. 12.56rad/24h * 1h/3600s = 1.45*10^-4 rad/s.
December 1, 2016

physics
M*g = 30, g = 30/M.
December 1, 2016

physics
d = 0.5g*t^2.
December 1, 2016

Science
d = 0.5a*t^2 = 1500 m. 2.5*t^2 = 1500, t = 24.5 s.
December 1, 2016

physics
Range = Vo^2*sin(2A)/g.
November 30, 2016

Physics
See previous post.
November 30, 2016

Science Physics
See previous post: Wed, 11-30-16, 11:53 AM.
November 30, 2016

Science, physics
You have 2 vectors: one pointing north and one pointing west. Vr = -6 + 15i = 16.2km/h[-68.2o] = 16.2km/h[68.2o] N. of W.
November 30, 2016

Science
KE = 0.5M*V^2. KE = 0.5M*(V/2)^2 = 0.5M*V^2/4. So KE is reduced by a factor of 4(divided by 4).
November 30, 2016

physics
a. Vm - 2i = 4.2. Vm = 4.2 + 2i = 4.65m/s[25.6o] N. of E. = Velocity and Heading. b. Vm = 4.65m/s[25.6o]. c. d = Vm*t = 800. t = 800/Vm = 800/4.65 = 172 s.
November 30, 2016

Algebra
When B^2-4AC < 0, No real solutions. When B^2-4AC = 0, One real solution. When B^2-4AC > 0, Two real solutions.
November 30, 2016

Algebra
1. X = (-B +- Sqrt(B^2-4AC))/2A. X = (-0.8 +- sqrt(0.64+2.96))/-0.04 = -27.43, and 67.43. Solution: X = 67.43. 2. 0 = 5x^2+2x-12. B^2 - 4AC = 4 - (-240) = 244. Two solutions. 3. -8x^2 - 8x - 2 = 0. B^2-4AC = 64 - 64 = 0. One solution.
November 30, 2016

consumers math
Ar = Ab-I = Ab - Ab*r*t. Ar = 290 - 290*(0.16/360)*90, Ar = 290 - 11.60 = $278.40 = Amt. received(proceeds). I = $11.60.
November 30, 2016

precalculus
See previous post: Tue, 11-29-16, 3:33 PM.
November 29, 2016

Math
1. When X = 5, Y = 3*5 = 15. Since Y varies directly with X, Y will ALWAYS be 3 times X: Y = 3x. 2. Slope-Intercept Form: Y = (-2/3)x - 1. Multiply both sides by 3: 3y = -2x - 3, Add 2x to both sides: 2x + 3y = -3,
November 29, 2016

pre-calculus
A. 1rev/5.4min * 6.28rad/rev = 1.16 rad/min. B. Circumference = pi*2r = 3.14 * 78 = 245.0 feet. 5.6ft/s * 6.28rad/245ft. = 0.144 rad/s. C. 0.9rad/3s = 0.3rad/s.
November 29, 2016

math
See previous post: Tue, 11-29-16, 5:38 PM.
November 29, 2016

maths
a. 4.8kg/(0.25kg/pk.) = 19.2 or 19 packets. b. 250g/pk. * 0.2pk. = 50 g.
November 29, 2016

pre calculus
Eq2 was obtained by multiplying both sides of Eq1 by 2. Therefore, the two Eqs are identical. So we have an infinite number of solutions.
November 29, 2016

pre calculus
Eq2 was obtained by multiplying both sides of E
November 29, 2016

science
Circumference = pi*2r = 3.14 * 0.5 = 1.57 m. Vo = 72,000m/3600s * 6.28rad/1.57m = 80 rad/s. d = 20rev * 6.28rad/rev = 125.6 rad. V^2 = Vo^2 + 2a*d. V = 0, Vo = 80 rad/s, d = 125.6 rad, a = ?. "a" will be negative.
November 29, 2016

Science
Are you sure the time is only o.5 s.?
November 28, 2016

Math
Eq1: Vm - Vc = 15. Eq2: 0.5Vm + Vc = 12. Sum: 1.5Vm = 27, Vm = 18 mi/h. In Eq1, replace Vm with 18 and solve for Vc.
November 28, 2016

Math
d1 = d2. (Vp+Vw)*t1 = (Vp-Vw)t2. (150+Vw)*2 = (150-Vw)*3. Vw = ?.
November 28, 2016

physics
See Related Questions: Thu, 7-21-16, 1:58 AM.
November 28, 2016

History
The space is between the words the and act
November 27, 2016

History
The purpose of the act was to provide land to railroad companies so that a transcontinental railroad could be built.
November 27, 2016

History
Fill in the blank The purpose of the act was to provide land to railroad companies so that a transcontinental railroad could be built.
November 27, 2016

History
Yes
November 27, 2016

History
What are 2 things the railroad supplied from the west to other parts of the world ? What technology was used to show that the railway was complete ?
November 27, 2016

precalculus
Law of Sine: a/sin A = b/sin B. 9.4/sin150 = 4.8/sin B 9.4*sin B = 4.8*sin150, 9.4*sin B = 2.4, sin B = 0.25532, B = 14.8o. A+B+C = 180o. 150 + 14.8 + C = 180, C = 15.2o. a/sin A = c/sin C. c = ?.
November 27, 2016

physics
b. KE1 = 0.5M1*V1^2 + 0.5M2*V2^2, KE1 = 500*25^2 + (1000*15i^2), KE1 = 312,500 + 225,000 = 537,500 J. = KE before collision. KE2 = 0.5M1*V + 0.5M2*V. KE2 = 500*13^2 + 1000*13^2 = 253,500 J. = KE after collision. KE1-KE2 = KE lost after collision.
November 27, 2016

physics
a. M1V1 + M2V2 = M1V + M2V. 1000*25 + 2000*15i = 1000V + 2000V, 25,000 + 30,000i = 3000V, Divide by 1,000: 25 + 30i = 3V, V = 13m/s[50.2o] N. of E.
November 27, 2016

Physics
Correction: F = -1250 N.
November 27, 2016

Physics
V^2 = Vo^2 + 2a*d = 200^2. 300^2 + 2a*0.2 = 40,000, 0.4a = 40,000-90,000 = -50,000, a = -125,000 m/s^2. F = M*a = 0.01 * (-125000) = -11250 N. Resisting the bullet.
November 27, 2016

Physics , static fluids
Di/Dw = (920kg/m^3)/(1000kg/m^3) = 0.92 = 92% below the surface. 1.0-0.92 = 0.08 = 8% exposed.
November 26, 2016

Physics
F = 15 N.?. F = M*a, a = F/M = 15/14 = 1.07 m/s^2. V = Vo + a*t = 0 + 1,07*8 = 8.56 m/s.
November 25, 2016

Physics
Fr = 50N.[0o] + 30[30o]. X = 50 + 30*Cos30 = 76.0 N. Y = 30*sin50 = 15 N. Tan A = Y/X = 15/76 = 0.19737. A = 11.2o Fr = X/Cos A = 76/Cos11.2 = 77.5 N.]11.2o] N. of E.
November 25, 2016

physics
See previous post.
November 24, 2016

physics
M*g = 20 * 9.8 = 196 N. = Wt. of body. Fp = 196*sin30 = 98 N. = Force parallel to the incline. Fp-40 = M*a. 98-40 = M*a, a = 58/M = 58/20 = 2.9 m/s^2.
November 24, 2016

Physics
V = Vo + a*t = 2.0 rad/s. 0 + a*1.96 = 2.0, a = 1.02 rad/s^2. d = 0.5a*t^2 = 0.51*1.96*2 = 1.96 rad. (360deg./6.28rad) * 1.96rad = 112.4 deg. .
November 24, 2016

Maths Ratio and Proportion
Q1. (10/5)875 + (5/7)875 = 2375.
November 24, 2016

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