Saturday
April 19, 2014

Posts by Henry


Total # Posts: 8,520

algebra
Multiply both sides by 4: a. 32--7x-3 -24+8x = 0 x + 32-27 = 0 X = -5.

math
Octagon = 360o/8angles = 45o/angle, Hexagon = 360o/6angles = 60o/angle. 60 - 45 = 15o Increase.

slope help
Given:Slope = 3. P(2,4)? Y = mx + b = 4 3*2 + b = 4 b = -2 Eq: Y = 3x - 2 Use the same procedure for the remaining problems.

precalculus
See previous post.

Science
1. Density = 8g/4cm^3 = 2g/cm^3.

precalculus
9x^2 + 36y^2 = 64 When Y = 0, 9x^2 = 64 x^2 = 64/9 X = +- 8/3 = x-intercepts. When X = 0, 36y^2 = 64 y^2 = 64/36 Y = +- 8/6 = +-4/3 = y-intercepts. Major Axis = 8/3 - (-8/3)=8/3+8/3= 16/3 Minor Axis = 4/3 - (-4/3) = 8/3. NOTE: The major axis has the largest intercept.

Math
See previous post.

Math
a. Se previous post. b. 850(1.02)^t = 1700. Solve for t.

Math
P = Po(1+r)^t = 1000. 850(1.02)^t = 1000 (1.02)^t = 1000/850 = 1.17647 Take Log of both sides: t*Log 1.02 = Log 1.17647 0.0086t = 0.07058 t = 8.2 Years

physics
Range = Vo^2*2sinA*cosA/g = Vo*cosA*T (550)^2*2sinA*cosA/9.8=550cosA*49.2 Divide both sides by 550cosA: 550*2sinA/9.8 = 49.2 56.12*2sinA = 49.2 112.24*sin A = 49.2 sinA = 0.43833 A = 26o. Range = Vo*cos A * T Range = 550*cos26 * 49.2 = 24321 m.

physics
Yo = 250km/h = Ver. component? Vo = 250/sin30 = 500 km/h.

physics
h = 5*sin43 = 3.41 m. m*g = 88 N m = 88/g = 88/9.8 = 8.98 kg 0.5m*V^2 = mg*h - Fk. 0.5*8.98*V^2 = 88*3.41-19 = 281.1 4.49V^2 = 281.1 V^2 = 62.6 V = 7.9 m/s.

Physics (MOMENTUM)
Ball B. Momentum = m*V. Ek = 0.5m*V^2. Ball A: Momentum = (m/2)*2V = m*V. Ek = 0.5m*V^2 a. Their momentum is equal. b. Their kinetic energy is equal.

Math
Incomplete.

physics
h = ho + (V^2-Vo^2)/2g h = 14.7 + (0-(7.53)^2)/-19.6 = 17.6 m. Above gnd. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*17.6 = 345 V = 18.6 m/s. V = Vo + g*t Tr = (V-Vo)/g = (0-7.53)/-9.8=0.768 s.= Rise time. h = Vo*t + 0.5g*t^2 = 17.6 m. 0 + 4.9t^2 = 17.6 t^2 = 3.59 Tf = 1.89 s. = Fall ti...

science
How are the resistors connected?

pre algebra
P = Po(1+r)^n P = 100(1+0.05)^5 P = 100(1.05)^5 = $127.63.

physics
V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*3 = 58.8 V = 7.67 m/s.

mathematics
See previous post.

mathematics
See previous post.

mathematics
X Nickels. 2x Dimes. (2X-4) Quarters. 5x + 10*2x + 25(2x-4) = 575 Cents. Solve for x.

physics
V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*1 = 19.6 V = 4.43 m/s.

science
See previous post.

Physics
a. Wo^2=1/LC=1/(0.015*5*10^-6)=1.33*10^7 Wo = 3651 Rad/s. b. Xl=0.25Wo*L=0.25*3651*0.015=13.7 Ohm Xc=1/(0.25*3651*5*10^-6) = 219 Ohms. Z^2 = R^2 + (Xl-Xc)^2 Z^2 = (80)^2 + (13.7-219)^2 = 48,548.1 Z = 220.3 Ohms. Im = V/Z = 40/220.3 = 0.182A. Xl = W*L = 3651*0.015 = 54.77 Ohms ...

physics
h = Vo*t + 0.5g*t^2 = 0.35 m 0 + 4.9t^2 = 0.35 t^2 = 0.0714 t = 0.257 s.

science
See previous.

science
Increase in velocity.

science
My answer is C. The force must act in the same direction as the motion.

business math
See previous post.

Business Math
X Banana splits @ $4.25 each. 4x Sundaes @ $3.60 each. 4.25*x + 3.60*4x = 3730 X = 200.

Math
[(3-5)+3*8]/4[8-4/2(7+1)] = ]-2+24]/4[-8] = (22/4) * (-8) = -44.

acollege algebra
Correction: (2,-7) should be (2,-3).

acollege algebra
Correction: F(x) = Y = 2(x-3)^2-5 Use the following points for graphing: (X,Y) (1,3) (2,-7) V(3,-5) (4,-3) (5,3)

acollege algebra
F(x) = Y = 2(x-3)^22(-5 Y = 2(x^2--6x+9)-5 Y = 2x^2-12x+18-5 Y = 2x^2-12x+13 h = -B/2A = 12/4 = 3 k = 2(3-3)^2-5 = -5 V(h,k) = (3,-5) Use Quad. Formula and get: X = 4.5,and 1.5. = X- Intercepts To find Y-int.,replace x in given Eq with 0 and solve for y. Y-int = 4.

math
I = Po*r*t = 5000*0.06*1 = $300.

physics
V = 3.42L * (309k/215k) = 4.92 L.

math
9/2 - 1/2 = 8/2 = 4.

Math
L = h/sinA = 32/sin39 = 51 m.

Physics Need help plz
Accuracy = (+-0.22/22)*100% = +- 1.0 %.

um reviewing old subjects .. Linear Equations
A = X Degrees. B = (x+24) Degrees. The sum of 2 complimentary angles = 90o: A + B = 90o X + (x+24) = 90 2x + 24 = 90 2x = 90-24 = 66 X = 33o X+24 = 57o

physics
Please leave space between words.

physics
Please clarify your problem.

algebra
X 10-point questions. Y 5-point questions. Eq1: X + Y = 21 Questions Eq2: 10x + 5y = 200 Points. Multiply Eq1 by -5 and add Eq1 and Eq2: -5x - 5y = -105 10x + 5y = 200 Solution set: (X,Y) = (19,2). 5x = 95 X = 19 In Eq1, replace x with 19: 19 + y = 21 Y = 2.

algebra
10 - 0.5y = 1.5x -1.5x - 0.5y = -10 Multiply both sides by -2: Eq1: 3x + y = 20 y = 0.5(6x+40) y = 3x + 20 Eq2: -3x + y = 20 Add Eq1 and Eq2: 2y = 40 Y = 20 In Eq1. replace y with 20: 3x + 20 = 20 3x = 20-20 = 0 X = 0. Solution Set: (x,Y) = (0,20).

Physics
V=pi*r^2 * h=3.14*0.35^2 * 2.1=0.8o8 m^3 Mass = 0.808 m^3 * 2200kg/m*3=1777.1 kg. Wt. = 1777.1kg * 1Lb/0.454kg = 3914 Lbs.

math
The slope of the perpendicular line is the negative reciprocal of the give slope. m = -(-1/8)= 1/8.

Algebra
y = -3x/2 + 3 Multiply both sides by -2: -2y = 3x - 6 2y = -3x + 6 2y = 6 - 3x Answer = A.

algebra word problem
X Students sold. X+100 Adult tickets sold. 2000-(x+x+100) = 1900-2x Children tickets sold. 10x + 12(x+100) + 5(1900-2x) = $19,700. 10x + 12x+1200 + 9500-10x = 19700 12x = 19700-10700 = 9000 X = 750 X+100 = 850 1900-2x = 400.

Maths
Use the law of cosines. cosA = (-a^2+b^2+c^2)/2bc. cosA=(-(8.6)^2+(9.1)^2+(9.7)^2)/176.54 = 0.58310. A = 54.33o. Area = 0.5*bc*sinA. Area=0.5*9.1*9.7*sin(54.33) = 35.9 cm^2

physics
See previous post.

physics
a. a = (V-Vo)/t = (11-0)/4.8=2.29 m/s^2. d = 0.5a*t^2 = 0.5*2.29*(4.8)^2=26.4 m. Work = F*d = mg*d = (79*9.8) * 26.4 = 20,439 J. b. P = F*d/t = 20439/4.8 = 4258 J/s = 4258 W.

axia
I'm assuming the account is compounded annually. A = Po(1+r)^n n = 1comp/yr. * 2yrs. = 2 Compounding periods. A = 4000(1.1)^2 = $4840.

maths
1. d = 16*t^2. 1 s. 16 Ft. 2 s. 64 Ft. 3 s. 144 Ft. d = 4.9*6^2 = 176.4 Ft in 6v s. 3. T = 75(1+0.10)^3 = 99.8o.

Physics
Incomplete.

physics
ho = 0.5*a*t^2 = 0.5*20*60^2 = 36,000 m. Vo = a*t = 20*60 1200 m/s. a. h. = ho + (V^2-Vo^2)2g h=36000 + (0-(1200)^2)/-19.6=109,469 m. b. V = Vo + g*t Tr = To + (V-Vo)/g=60 + (0-1200)/-9.8 = 182.4 s. h = Vo*t + 0.5g*t^2 = 109,469 m. 0 + 4.9t^2 = 109469 t^2 = 22,341 s Tf = 150 s...

math
s + 0.2s = 4200 1.2s = 4200 S = $3500 = Wayne's salary. Barry's Salary. s - 0.4s = 3500 0.6s = 3500 S = $5833.33 = Barry's salary.

science
V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = (0-20^2)/100 = -4 m/s^2.

math
23000-0.07*t*23000 = 3000 23000 - 1610t = 3000 -1610t = 3000-23000 = -20000 t = 12.42 Years.

physics
Fn = 193 - 0.39*193 = 117.73 = Net force. Power = Fn * d/t Power = 117.73 * 4.9/12 = 48.1 J/s = 48.1 Watts.

physics 1
h = Vo*t + 4.9t^2 = 1000 m. 0 + 4.9t^2 = 1000 t^2 = 204.08 t = 14.3 s. = Fall time. D = 50m/s * 14.3s = 714.3 m.

physic
Vo = 350Ft/s[60o]. Xo = 350*cos60 = 175 Ft/s Yo = 350*sin60 = 303 Ft/s. b. Y^2 = Yo^2 + 2g*h h = (Y^2-Yo^2)/2g h = (0-(303)^2)/-64 = 1435 Ft. c. Dx = Vo^2*sin(2A)/g Dx = (350)^2*sin(120)/32 = 3315 Ft. d. 350 Ft/s[60o]. Same as initial velocity.

algebra
2. h = Vo*t + 0.5g*t^2 = 84 Ft. 10t + 16t^2 = 84 16t^2 + 10t - 84 = 0 Use Quadratic Formula. t = 2 s.

calculus
See Wed, 1:58AM post.

algebra
X min. = Joe's time. 2x/3 = Frank's time. 1/x + 3/2x = 1/40 Multiply both sides by 2x: 2 + 3 = x/20 x/20 = 5 X = 100 min. = Joe's time. 2x/3=200/3 = 66.67 min. = Frank's time.

math
a. F(x) = x/(x+6).

algebra
Y = -16t^2 + 400 h = Xv = -B/2A - 0/-32 = 0. k = Yv = -16*0^2 + 400 = 400. V(0,400).

Math
d1 = d2 V*(4+1) = 50*4 = 200 5V = 200 V = 40 Mi/h = Adam's speed.

math algebra
(15+Vc)t = 20 Eq1: 15t + Vc*t = 20 (15-Vc)t = 10 Eq2: 15t - Vct = 10 Add Eq1 and Eq2: 15t + Vct = 20 15t _ Vct = 10 30t = 30 t = 1 h. 15*1 + Vc*1 = 20 Vc = 20-15 = 5 mi/h. = Velocity of current.

math
P = Po(1+r)^n r = (6%/2)/100% = 0.03 = Semi-annual % rate expressed as a decimal. n = 2Comp,/yr. * 25yrs. = 50 Compounding periods. Po(1.03)^50 = $600,000 Po*4.38391 = 600000 Po = $136,864.25 = Present value. Plug the above values into the given Eq. and get $

Physics
Power = F*d/t = mg*d/t =(60*10)*1.2/1.5 = 480 J/s = 480 Watts.

math
P = Po*e^rt 1000*e^0.079t = 100,000 e^0.079t = 100000/1000 = 100 Take Ln of both sides: 0.079t*Ln e = Ln 100 0.079t*1 = 4.61 t = 58.3 yrs. 1-1-2008 + 58.3yrs. = 4-19-2066.

math
Slope = -2, P(0,-3). Slope-intercept Form. Y = mx + b -2*0 + b = -3 b = -3. Eq.: Y = -2x - 3. Point-slope Form. (0,-3), (x,y). Slope = (y+3)/(x-0) = -2 Cross multiply: Eq.:y+3 =-2(x-0).

mechanics
F = m*a = 18 * 36 = 648 N.

Physics
I have no idea what your circuit looks like.

algebra1
T=(T1*T2)/(T1+T2)=(20*30)/(20+30)=12 min.

Math
P = Po*e^rt r*t = (3%/100%) * 2yrs. = 0.06 P = 2000*e^0.06 = $2123.67

Algebra
V = Vo + g*t t = (V-Vo)/g = (0-45)/-32 = 1.41 s. ht. = 6 + 45*1.41 - 0.5*32*(1.41)^2 = 37.64 Ft.

math
d = Vo*t + 0.5a*t^2 d = 4.5*7 + 0.5*2.5*7^2 = 92.75 m.

algebra
10/3x + 4/3 = (7+x)/2x Multiply both sides by 6x: 2*10 + 8x = 3(7+x) 20 + 8x = 21+3x 8x-3x = 21-20 = 1 5x = 1 X = 1/5.

Algebra
NOTE: B^2 = (-3)^2 = 9.

Algebra
Y = x^2 - 3x + 6. B^2 = (-3) = 9. 4*A*C = 4*1*6 = 24. B^2 - 4AC = 9 - 24 = -15 = The value under the radical. Since the value under the radical is negative, there are 2 imaginary solutions. Therefore, the graph does not touch or cross the x-axis. So there are no x-intercepts. ...

algebra-word problem
X+11 = 121 h.

algebra-word problem
X = The # of hours before the increase. (X+11) = The # of hours after the increase. (x+11)/x = 1.1 1.1x = x+11 1.1x - x = 11 0.1x = 11 X = 110 h.

college physics
Power = 7.0hp * 746W/hp = 5222 Watts = 5222 Joules/s. Mass = 475Lbs * 0.454kg/Lb = 215.65 kg.= Mass of boiler. d = 38Ft./3.3Ft/m = 11.52 m. Work=F*d = mg * d=215.65*9.8 *11.52= 24,346 Joules. t = 24346J * 1s/5222J = 4.66 s.

applied physics
Fp = 35*cos40 = 26.8 N. = Force parallel to yard. Work = Fp*d = 26.8 * 900 = 24,130 Joules

applied physics
Work = 11*94Lbs * d == 4340Ft-Lbs. 1034d = 4340 d = 4.2 Ft.

applied physics
V^2 = Vo^2 + 2g*d V^2 = 0 + 64*(5000-1000) = 256,000 V = 506 Ft/s

physics
a. V^2 = 0 + 19.8*6.4 = 126.72 V = 11.26 m/s.

Science
W1/W2=(F/2 *4d)/(F*d)=(2F*d)/(F*d)=2. W1 = Joe's work. W2 = Mary's work. Joe does twice as much work as Mary.

physics
V = Vo + g*t = 0 t = (V-Vo)/g = (0-2.6)/-9.8 = 0.265 s.

nyoike
producea java program which when given 3 sides of a triangle determines whether the traingle is an equilateral an issosceles or a scaline

Physics
mg*h = 0.5m*V^2 Divide both sides by m: g*h = 0.5V^2 V^2 = 2gh V = sqrt(2g*h.

physics
a = (V-Vo)/t = (10-0)/2 = 5 m/s^2.

physics
Speed = 30m/2s = 15 m/s.

Physics
See previous post.

physics
Fn = m*a = 40-24 = Net force. 8a = 16 a = 2 m/s^2.

Solving an Equation in one variale
Incomplete.

geometry
V=L*W*h=0.4m * 0.2m * 0.2m 0.016 m^3 Wt. = 0.016m^3 * 1700kg/m^3 = 27 kg.

For the given functions f and g
a. (F*g)(x) = sqrt(x)(5x-9) Domain: X => 0. Domain: All real values of X that are equal to or greater than zero. The value under the radical cannot be less than zero. b. F/g(x) = sqrt(x)/(5x-9)

Math
Use the following points for graphing: (X,Y) (-3,-15) (-2,-5) (-1,1) V(0,3) (1,1) (2,-5) (3,-15).

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