Monday
September 1, 2014

Posts by Henry


Total # Posts: 8,966

Physics
Ap/Ae = pi*(8.25r)^2/pi*r^2=68.1r^2/r^2= 68.1/1 Ap = 68.1*Ae. Ap = Area of the planet. Ae = Area of the earth.
September 8, 2013

Physics
See previous post: Sun,11:33 AM.
September 8, 2013

Math
Vo = 100Ft/s[60o] X = 4*100*cos60 = 200 Ft. Y = 4*100*sin60 = 346.4 Ft. a. (X,Y) = (200,346.4). b. Yo = Vo*sin O = 100^sin60 = 86.6 Ft/s Y = Yo + g*t = 0 @ max. Ht. 86.6 + (-32)t = 0 -32t = -86.6 Tr = 2.71 s. = Rise time. Tf = Tr = 2.71 s. = Fall time. T = Tr + Tf = 2.71 + 2....
September 8, 2013

math
Int. = 200,000-166,000 = $34,000 %Int = (34000/200000)*100% = 17%/13yrs. APR = 17%/13yrs. = 1.31%/yr.
September 8, 2013

business math
Gross Pay = 735 + 0.035(45,900-15,500)
September 8, 2013

Physics
CAR: V1 = 45mi/h * 1600m/mi * 1h/3600s=20 m/s a=8.5mi/h/s*1600m/mi*1h/3600s=3.78m/s^2 a*t = 20 m/s 3.78t = 20 t = 5.29 s. to reach max velocity. d1 = 0.5a*t^2 d1 = 0.5*3.78*5.29^2 = 52.9 m = Dist.@ which max. velocity is reached. BIKE: V2 = (15/45)*20 m/s = 6.67 m/s = max. ...
September 7, 2013

college essay
something beautiful
September 7, 2013

algebra 2
A=A1+A2=(150*65) + (150*225)=43,500 Ft^2 43,500Ft^2 * 1bag/5000Ft^2=8.7 or 9 Bags to cover both yards. (150*225)Ft^2 * 1bag/5000Ft^2 = 6.75 or 7 Bags to cover back yard.
September 6, 2013

PHYSICS
a. I=E/(Ri+Rb) = (12.6/(0.05+5.60)=2.23A V = I*Rb = 2.23 * 5.60 = 12.49 Volts. b. Vb=E-I*Ri=12.6 - (35+2.23)0.05=10.74 Volts.
September 6, 2013

Physics
D, and F.
September 6, 2013

physics
Vo = 120km/h = 120000m/3600s=33.33 m/s. d1 = Vo*t + 0.5a*t^2 d1 = 33.33*2 + (-3)*2^2 = 54.66 m Traveled by policeman in 2 s. d2 = Vo * t = 33.33 * 2 = 66.66 m/s. = Distance traveled by me in 2 s. d3 = Do - (d2-d1) d3=25 - (66.66-54.66)=13 m = Separation between me and the ...
September 5, 2013

physics
Vo = 74km/h = 74000m/3600s = 20.56 m/s. V = Vo + a*t t1 = (V-Vo)/a = (0-20.56)/-1.3 = 15.8 s. t2 = 3 min = 180 s. t3 = 20.56-0)/0.7 = 29.37 s T=t1 + t2 + t3=15.8 + 180 + 29.37=225.2s = 3.75 min. = Time lost.
September 5, 2013

physics
a. See previous post: 9-5-13,12:33 AM. b. 1784 Watts = 1784 J/s. Energy=1784J/s * 2.9h*3600s/h=18,625 J. c. (1.784*2.9)kWh*0.160/kWh = $0.83
September 5, 2013

physics
See 11:25 Am post.
September 5, 2013

physics
Vo = 10.8m/s[24.9o] Xo = 10,8*cos24.9 = 9.8 m/s Yo = 10.8*sin24.9 = 4.55 m/s a. Y = Yo + g*t Y = 4.55 + (-9.8)*0.310 = 1.51 m/s. V^2 = Xo^2 + Y^2 V^2 = 9.8^2 + 1.51^2 = 98.3 V = 9.9 m/s. b. = tan A = Y/Xo = 1.51/9.8 = 0.15408 A = 8.76o = The direction. c. Y = Yo + g*t Y = 4.55...
September 5, 2013

physics
Po = 2.20hp * 746w./hp = 1641.2 Watts Pi = Po/0.92 = 1641.2/0.92 = 1784 Watts Pi = 120*I = 1784 W. I = 1784/120 = 14.9A.
September 5, 2013

Physics
P=(Vrms)^2/R = (0.707*169)^2/506=28.2 Watts.
September 4, 2013

physics
V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a d = (7^2-0)/2.4
September 4, 2013

physics
d1 = 0.5a*t^2 = 0.6*5.3^2 = 16.85 m. V1 = a*t = 1.2m/s^2 * 5.3s = 6.36 m/s. a. V = Vo + a.t V = 6.36m/s - 2.3m/s^2*1.60s = 2.68 m/s. b. V^2 = V0^2 + 2a*d d2 = V^2-Vo^2)/2a d2 = (2.68^2-6.36^2)/-4.6 = 7.23 m. D = d1 + d2 = 16.85 + 7.23 = 24.1 m.
September 4, 2013

Math
(150,80), (50,30). m =(30-80)/(50-150) = -50/-100 = 0.5 Y = mx + b Y = 0.5*150 + b = 80 b = 80-75 = 5 Eq: Y = 0.5x + 5 Error: The student interchanged the slope and Y-intercept.
September 4, 2013

jru-physics
PE = mg*h = 50*9.8*2m = 980 Joules
September 4, 2013

Math
Another Approach: %Decrease = ((15%-10%)/15%)*100% = (5/15)*100% = 33.33%
September 3, 2013

Math
(10%/15%)*100%=(10/15)*100%= 66.67%. 66.67% - 100%=-33.33% or 33.33% Decrease
September 3, 2013

Physics
See your 5:59 pm post.
September 3, 2013

Physics
a. Fa = ((V-Va)/(V+Vb))*Fb Fa = ((343-0)/(343+68.6))*960 = 800 Hz b. Fc=((343+114.33)/(343-0))*480=640 Hz. c. Fb = ((343+68.6)/(343-114.33))*1550 Fb = 2790 Hz.
September 3, 2013

Physics
Fr = ((Vs+Vr)/(Vs-Vo))*Fo = 205 Hz ((336+0)/(336-Vo))*200 = 205 ((336)/(336-Vo))*200 = 205 67,200)/(336-Vo) = 205 205(336-Vo) = 67200 68,880-205Vo = 67200 -205Vo = 67200-68880 = -1680 Vo = 8.2 m/s. = Speed of the train.
September 3, 2013

Physics
CORRECTION: b. Fr = 638.33 Hz.
September 3, 2013

Physics
Vo=120km/h = 120,000m/3600s = 33.33 m/s. a. Fr = ((Vs+Vr)/(Vs-Vo))*Fo Fr=(345+0)/(345-33.33)*700Hz = 774.9 Hz b. Fr = ((345-0)/(345+33.33))*700=356 Hz = Freq. heard by the receiver(person).
September 3, 2013

Physical Science
Yes, the answer is C, because KE + PE = A constant.
September 3, 2013

Physics
a. d = 115-160 = -45 miles. The negative sign means the number decreased. b A decreasing marker number means you are traveling South or West. Therefore, John is 45 miles South or West of town.
September 2, 2013

Math
((-3)^2+(-3)*(-2))/4*(-2) = (9+6)/-8 = 15/-8 = -15/8 = -1 7/8.
September 2, 2013

science
d1 = 0.5*3.5*5.9^2 = 60.9 m V1=a*t = 3.5*5.9 = 20.65 m/s. = Velocity after 3.5 s. d2 = Vo*t + 0.5a*t^2 d2 = 20.65*5.98 + 2.98*5.98^2 = 176.8 m. V2 = a*t = 2.98*5.98 = 17.82 m/s. = Velocity @ 176.8 m. d3 = (V^2-Vo^2)/2g d3 = (0-17.82^2)/-19.6 = 16.2 m. = Free fall distance up. ...
September 2, 2013

optical circuits
Total loss = -5 + -5 + -1 = -11 db 10*Log(Po/Pi) = -11 db. 10*Log(Po/2) = -11 Log(Po/2) = -1.1 Po = 2*10^-1.1 = 0.159 mW.
August 31, 2013

Physics
d1 + d2 = 5.3+4.2 = 9.5 km = Distance between the runners. 8.8t + 7.9t = 9.5 16.7t = 9.5 t = 0.569 h. to cross paths. d1 = 5.3 - 8.8*0.569 = 0.293 km West of flagpole. d2 = 4.2 - 7.9*0.569 = -0.295 km West of Flagpole. So they meet at approximately 0.294 km west of flagpole.
August 31, 2013

Algebra
Steve, that was an excellent explanation.
August 31, 2013

math
a. V = Vo + g*t Tr = (V-Vo)/g = (0-15)/-32 = 0.469 s. To reach max. Ht. = Rise time. b. h = ho + Vo*t + 0.5g*t^2 h = 4 + 15*0.469 - 16*(0.469)^2=7.52Ft. Above Gnd. c. h = Vo*t + 0.5g*t^2 = 7.52 Ft. 0 + 16*T^2 = 7.52 T^2 = 0.469 Tf = 0.685 s. = Fall time. T = Tr + Tf = 0.469 + ...
August 31, 2013

US History
True or False Check. 1. During the Starving Time of 1609-10, some of the colonists turned to cannibalism as a means of survival. True 2. Early settlers of Jamestown spent many of their waking hours bowling. True 3. The location of Jamestown was selected partially out of fear ...
August 28, 2013

phiycics
t = 144km * 1h/48km = 3 h.
August 28, 2013

Physic
Correction: The speed of the car does not have to be reduced to zero, because the truck is moving forward. It must be reduced to 50 km/h(13.9m/s). a = (V^2-Vo^2)/2d a = (13.9^2-27.8^2)/400 = -1.45 m/s^2.
August 28, 2013

Physic
Car Speed=100km/h=100000m/3600s=27.8m/s Truck Speed =(50/100) * 27.8=13.9 m/s. V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = (0-(27.8-13.9)^2)/400 = -0.483 m/s^2 NOTE: The effective speed of the car is less than the actual speed, because the truck is moving forward.
August 28, 2013

Science
d=109km/day * 1mi/1.6km*7days/wk = 476.875 mi/wk 1.1euros/L*$1.26/euro*3.8L/gal=$5.27/gal Cost = 476.875m1*1gal/39mi*5.27/gal = $64.44
August 28, 2013

Science , physics
Change = 35.4 - 99.9 = -64.5oC The negative sign means the change was a decrease.
August 27, 2013

m= ath
4 Liters(L) = 4000 Milliliters(mL). 4000/150 = 26.7 or 26 Beakers can be filled.
August 27, 2013

SAT Math
2. a is greater because it has the smaller reciprocal. 3. P/4<q/12 Multiply both sides by 12: 3P<q or q>3P. (P-1)/4 Let P = 3 (3-1)/4 = 2/4 = 1/2. (q-9)/12 Let q = 10 which greater than 3P. (10-9)/12 = 1/12. Therefore, (P-1)/4>(q-9)/12. This is true for values of q...
August 27, 2013

Math
(KR)^2 = (-5-2)^2 + (3-9)^2 = 85 KR = 9.22 (RN)^2 = (-5-0)^2 + (3+7)^2 = 125 RN = 11.18 (KN)^2 = (0-2)^2 + (-7-9)^2 = 260 KN = 16.12 P = 9.22 + 11.18 + 16.12 = 36.5
August 27, 2013

Algebra 2
See previous post.
August 27, 2013

Algebra 2
5681mg = 5681*10^-3g 5681*10*-3g * 10^-3 = 5681*10^-6 kg OR 5681mg * 10^-6=5681*10^-6 kg =0.005681 kg.
August 27, 2013

AP Physics
D = 10m[90o] + 7m[120o]. X = 10*cos90 + 7*cos120 = -3.50 m. Y = 10*sin90 + 7*sin120 = 16.1 m. tanAr = Y/X = 16.1/-3.5 = -4.58857 Ar = -77.7o = Reference angle. A = -77.7 + 180 = 102.3o D = X/cosA = -3.50/cos102.3 = 16.43 m.[102.3o]
August 27, 2013

algebra
a. 50/10^9. 15/10^9. b. 50*10^-9 15*10^-9.
August 26, 2013

Science Physics
I'm assuming R and C are in series. R = 10k ohms RC = 34us = 34*10^-6 s. Vr = E/e^(t/RC) = 11 Volts. 27/e^(t/RC) = 11 e^(t/RC) = 27/11 = 2.45455 Take Ln 0f both sides: (t/RC)*Ln e = Ln 2.45455 (t/RC)*1 = 0.89794 Multiply both sides by RC: t = 0.89794RC t=0.89794*(34*10^-6...
August 26, 2013

Physics !!
1a. d1 = 0.5g*t^2 = 4.9*2^2 = 19.6 m. = Distance fallen by the 1st stone after 2 s. V1^2 = Vo1^2 + 2g*d V1^2 = 0 + 19.6*19.6 = 384.16 V1 = 19.6 m/s = Velocity of 1st stone after 2 s. d1 = d2-19.6 m. Vo1*t + 0.5g*t^2 = Vo2*t+0.5t^2-19.6 Vo1*t-Vo2*t+4.9t^2-4.9t^2 = -19.6 19.6t-...
August 26, 2013

physics
V=(4.15*10^-2m)^3 = 7.15*10^-5m^3 Density=1.2kg/7.15*10^-5m^3=16,783kg/m^3
August 25, 2013

physics
R1 = 2 Megohms? R2 = 3 megohms? R3 = 15 Megohms? I = 3 Microamps? Please clarify your problem.
August 25, 2013

physics
X = 30m/30s = 1 m/s. Y = 1 m/s . tanA = Y/X = 1/1 = 1. A = 45o = Direction. V = 1/cos45 = 1.414 m/s[45o].
August 25, 2013

Physics
X = ? Y = -2.9 km. R = 4.25 km = Resultant. X^2 + Y^2 = R^2 X^2 + (-2.9)^2 = (4.25)^2 X^2 = (4.25)^2 - (-2.9)^2 = 9.653 X = 3.1 km tanA = -2.9/3.1 = -0.93548 A = -43.1 o A = -43.1 + 360 = 316.9o CCW. A = 316.9 - 270 = 46.9o East of South.
August 25, 2013

physics
V^2 = Vo^2 + 2a*h V^2 = 79^2 + 7.8*980 = 13,885 V = 117.83 m/s. @ 980 m a. V = Vo + a*t = 117.83 79 + 3.9t = 117.83 3.9t = 117.83-79 = 38.83 Tr1 = 9.96 s. to rise to 980 m. V = Vo + g*t 117.83 - 9.8t = 0 9.8t = 117.83 Tr2 = 12.02 s to reach max. ht. hmax = ho + (V^2-Vo^2)/2g ...
August 25, 2013

physics
V^2 = Vo + 2g*d V^2 = 0 + 19.6*(12-6) = 117.6 V = 10.84 m/s. V^2 = 0 + 19.6*12 = 235.2 V = 15.34 m/s
August 24, 2013

Math ASAP
As = 2*22 + 308 = 352 Sq. In. Same as previous results.
August 24, 2013

Math ASAP
SORRY! The calculated surface area was for a rectangular prism NOT a hexagonal prism.
August 24, 2013

Math ASAP
As=2*Ab + Al = 2*22 + 308 = 352 Sq. In.
August 24, 2013

Mathematics
A. P = Po + Po*(r/360)*t = $10,000 Po + Po*(0.043/360)*96 = 10,000 Po + 0.01146667Po = 10000 1.01146667Po = 10000 Po = $9886.63. = Amt. paid. B. %Yield=((10000-9886.63)/9886.63 *365/96 = 4.36
August 23, 2013

business math
P = Po + Po(0.04/360)*45 20000 + 20000(0.04/360)*45 = $20,100 after 45 days. Bal. = 20100-8000 = $12,100
August 23, 2013

MaTh
Ag + As = At As = At - Ag As = 3.14*6^2 - 3.14*5^2 = Area of strip. At = Total area. Ag = Area of garden.
August 22, 2013

science
h = Vo*t + 0.5g*t^2 = 160 m. 0 + 4.9t^2 = 160 t^2 = 32.65 t = 5.7 s. = Time to strike ground.
August 22, 2013

Math
3x^5 - 12x^4 + 18x^3. 1. Locate the smallest constant which is 3. If 3 will divide into the other constants with no remainder, factor out 3. 2. Factor out the variable with the smallest exponent which is x^3. We have factored out 3x^3. 3. To determine what goes inside of the ...
August 22, 2013

Physics
L=V*T = V/F=300*10^6 / 5.35*10^5=561 m.
August 22, 2013

algebra
30-13 means 30 decreased by 13 or 30 less(minus) 13.
August 22, 2013

algebra
13<30.
August 22, 2013

algebra
Where is the "question above"?
August 22, 2013

Math
A. (11-1)games/team * 11teams = 110 games played. Team 1. 10 Games 2. 10 Games 3. 10 4. 10 5. 10 6. 10 7. 10 8. 10 9. 10 10 10 11.10 Games. Total: 110 Games. B. (12-1)games/team * 12teams = 132 Games played.
August 21, 2013

MATH
a. A = -100 + 360 = 260o.
August 19, 2013

math
2(x-3/4)+3(x+2/3)+4(x-1/5) = 9x+17 2x-6/4+3x+6/3+4x-4/5 = 9x+17 9x-3/10 = 9x+17 9x-9x = 17+3/10 0 = 17 3/10 = 173/10. No Solution! Check and make sure the prob. is copied correctly.
August 19, 2013

Math (Finance)
See previous post: Mon,6:41pm.
August 19, 2013

Finance
5.17 Ci=49,000=The # of copies sold 1st year. C3 = C1*(1+r)^3) C3 = 49000(1.21)^3 = 86,806 Copies sold after 3 years. C4 = 86,806*(1.13) = 98,091 Copies sold in 4th year. 5.21a P = Po(1+r)^n r = (8.9%/12)/100% = 0.0074167 = Monthly % rate expressed as a decimal. n = 12Comp/yr...
August 19, 2013

physics
Circumference = pi*2r = 3.14*100 = 314 m V=1rev/4min*314m/1rev1*1min/60s=1.31m/s
August 19, 2013

8th grade algebra
5x = The # of bikes rented. 2x = The # of scooters renteb 15.50*1.12*5x + 160*1.12*2x = 1600. 86.8x + 358.4x = 1600 445.2x = 1600 X = 3.59 Bikes = 5 * 3.59 = 18 Scooters = 2 * 3.59 = 7.
August 18, 2013

Physics
The current entering a point is equal to the current leaving the point. Therefore, the current leaving the positive terminal of a battery is equal to the current entering the negative terminal. This is true for the light bulb or any load.
August 18, 2013

math
P = (Po*r*t)/(1-(1+r)^-t) Po = 1598 * 1.05 = $1677.90 r = (15%/12)/100% = 0.0125 = Monthly % rate expressed as a decimal. t = 3yrs * 12mo./yr = 36 Months. Plug the above values into the given Eq and get: P = 2093.94 Monthly Payment = P/t
August 18, 2013

Physics
The brightness increases.
August 18, 2013

Science
Wb = m*g = 17.25kg * 9.8N/kg = 169 N. = Wt of body. Fv = m*g = 169 N. = Force perpendicular to the table. Fs = u*Fv = 0.34*169 = 57.5 N. = Force of static friction.
August 17, 2013

physics
P = F * d/t = F * V = mg * V P=400*9.8 * 0.03m/s = 118 J/s.=118 Watts
August 17, 2013

Math
63miles/22gal. = 2.86 Miles/gal. D = 66gal * 2.86mi/gal = 189 Miles.
August 16, 2013

physics
Rmax = V/I = (500000*.97)/1000=485 Ohms=Max. conductor resistance. Dmax = 485 Ohms / 0.026Ohms/km=18,654 km.
August 15, 2013

Physic
Fp = mg*sin23 = 597.8*2in23=233.6 N.= Force parallel to the hill. Fv = mg*cos23 = 597.8*cos23=550.3 N.= Force perpendicular to the hill. Fk = 72 N. a = (Fp-Fk)/m = (233.6-72)/61=2.65 m/s^2 V^2 = Vo^2 + 2a*d V^2 = (3.5)^2 + 2*2.65*62 = 340.85 V = 18.5 m/s.
August 14, 2013

Pre- Algebra
1. Y = -2x - 4. (1,3). Parallel lines have equal slopes: m1 = m2 = -2. Y = mx + b = 3 -2*1 + b = 3 b = 3+2 = 5 Eq: Y = -2x + 5 2. Y = 3x+3. (1,1). The slope of the line is equal to the negat1ive reciprocal of the slope of the given line. m1 = 3 m2 = -1/3. Y = mx + b = 1 (-1/3...
August 14, 2013

hydromechanic
Fap-Ff = m*a 124-Ff = m*0 = 0 Ff = 124 N. = Force of friction. u = Ff/Fl = 124/1026 = 0.121 = Coefficient of friction. Fap = Force applied.
August 13, 2013

basic math
The DIGIT in the units(ones) position is 2. TENS Position: 1. HUNDREDS position: 5. THOUSANDS position: 5. TENS of THOUSANDS position: 5.
August 12, 2013

math
The hypotenuse is greater than either of the other 2 sides but less than the sum. Therefore the answer is d. c^2 = 5^2 + 12^2 = 25 + 144 = 169 c = 13.
August 12, 2013

Physics
V^2 = Vo^2 + 2g*h Vo^2 = V^2 - 2g*h. Vo^2 = 0 + 19.6*23 = 450.8 Vo = 21.2 m. h = (0.5Vo)^2-Vo^2)/2g h = ((10.62)^2-(21.2^2))/-19.6=17.2 m.
August 11, 2013

MaThS
A. Y = -2x+1, and Y = -2x+3. m1 = m2 = -2. The lines are parallel, because their slopes are equal. B. x+y/3+5 = 0, and 2y+6x = 1 x+y/3=-5, and 6x+2y = 1. 3x+y = -15, and 6x+2y = 1 m1 = -A/B = -3/1 = -3 m2 = -6/2 = -3 The slopes are equal; therefore, the lines are parallel.
August 11, 2013

algebra
10. 16-9+25 = 32 11. 32/(-7+5)^3 = 32/-8 = -4. 12. 4^3-(2-5)^3 = 64 - (-27) = 91
August 10, 2013

math
Gregg: p + q Coins. Brother: 8p + 4q Coins. Sum = 8p+p + q+4q = 9p + 5q
August 10, 2013

math
1. 0x+6y-5x = 5x+6y. 2. 9x^2+10+4x^2+7 = 13x^2+17.
August 10, 2013

algebra
P1(1,-3),P2(2,4). D^2 = (2-1)^2 + (4+3)^2 = 50 D = 7.07
August 10, 2013

Maths
tan 60o = (Y1+Y2)/X1 = 3000/X1 X1*tan 60 = 3000 X1 = 3000/tan60 = 1732 m. tan 30o = (Y1+Y2)/(X1+X2)=3000/(1732+X2) (1732+X2)*tan30 = 3000 1732+X2 = 3000/tan30 = 5196 X2 = 5196-1732 = 3464 m tan30 = Y2/X2 = Y2/3464 Y2 = 3464*tan30 = 2,000 m. Y1 = 3000-2000 = 1,000 m. = Distance...
August 9, 2013

introduction to finance-16
1. P = Po*(1+r)^n Po = $4,000. r = (4%/100%) = 0.04 n = 1Comp./yr * 5yrs = 5 Compounding periods. Plug the above values into the given Eq and get: P = $4,866.61. 2. P = Po(1+(y-1))*(1+r)^n Y = Length of loan = 5 years. P = 4000(1+4)*(1.04)^5 = $24,333.06
August 9, 2013

math
Eq1: x*y = -84 Eq2: x+y = 5 x+y = 5 y = 5-x In Eq1, replace y with 5-x: x*(5-x) = -84 5x-x^2 = -84 -x^2+5x+84 = 0 Use Quadratic Formula and get: X = -7, and 12.
August 8, 2013

Math
The angles are assumed to be complimentary(sum=90o). DCE + ECF = 90o 4x+15 + 6x-5 = 90 10x + 10 = 90 10x = 80 X = 8 DCE = 4*8 + 15 = 47o
August 8, 2013

Mechanics, Waves and Optics
Wt. of crate=m*g=18kg * 9.8N/kg=176.4 N. Fv = 176.4*cos0 = 176.4 N. = Force perpendicular to the surface. Fk = u*Fv = 0.5 * 176.4 = 88.2 N. = Force of kinetic friction. Fap*cos20-Fk = m*a Fap*0.94-88.2 = 18*0 = 0 0.94Fap = 88.2 Fap = 93.9 N. = Force applied b. Tension = Fap = ...
August 7, 2013

physical science
V = Vo + a*t = 10 m/s. 6 + a*2 = 10 2a = 4 a = 2 m/s^2.
August 7, 2013

Pages: <<Prev | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | Next>>

Search
Members