# Posts by Henry

Total # Posts: 13,538

Algebra
Correct.

Algebra.
To break even: Income = Expense. 5x + 1300 = 3x + 1800 + 1500. 5x - 3x = 1800 + 1500 - 1300. 2x = 2000. X = 1000 Tickets.

Algebra
P = 2L + 2W. W = L. P = 2L + 2L = 4L. 20< P < 94. 20< 4L < 94. Divide by 4: 5< L < 23.5 in. 5< W < 23.5 in.

Algebra 1
1. (-3,2).

Algebra 1
Correct.

Algebra 1
Eq1: 4x + 2y = 10. Eq2: Y = -3x + 6. In Eq1, replace y with -3x+6 and solve for x: 4x + 2(-3x+6) = 10. 4x - 6x + 12 = 10. -2x = -2. X = 1. In Eq2, replace x with 1 and solve for y: Y = -3*1 + 6 = 3. Solution: (1,3).

Algebra 1
None of the give answers satisfy BOTH of the given equations. Remember that each answer must satisfy BOTH equations. My answer: (-2/3,-77/3) satisfies BOTH equations.

Algebra 1
Eq1: 4x - y = 23. Eq2: 7x - y = 21. Multiply Eq2 by -1 and add: +4x - y = 23. -7x + y = -21. Sum: -3x = 2. X = -2/3. In Eq1, replace x with -2/3 and solve for y. 4(-2/3) - y = 23. Y = ? You should get: Y = -77/2 = -25 2/3.

Algebra 1
Eq2: y + 4 = -3x. Y = -3x - 4. Eq1 and Eq2 are identical. Therefore, there are an infinite number of solutions. The graph is a single line.

algebra 1
A. Correct. B. In Eq1, replace x with 30+y and solve for y: 30+y + y = 60. 2y = 30. Y = 15 Minutes on free hand exercises. C. Yes, but the time spent in the gym would be 55 minutes(15+40) instead of 60 minutes.

math
7256chickens * 3290feathers/chicken = 23,872,240 Feathers to be plucked. 23,872,240fe * 2.6s/83.6fe * 1h/3600s = 206.2 h.

Math
Unless otherwise indicated, all angles are measured CCW from +x-axis. Ship #1: d1 = 11.5km/h[52o] * 2h = 22km[52o]. Ship #2: d2 = 13km/h[ 317o] * 2h = 26km[317o]. d2-d1 = 26[317o] - 22[52o]. X = 26*Cos317 - 22*Cos52) = 5.47 km. Y = 26*sin317 - 22*sin52 = -35.1 km. d2-d1 = Sqrt...

physics
V = Vo + a*t = 0. a = -Vo/t = -3/5 = -0.6 m/s^2.

Calculus
Okay I didn't know you could do that haha

Calculus
Wait, but how can you let u=x^3 when there is not an x^3 in the equation

Calculus
Last one for me. Evaluate (3x^2)/sqrt(1-x^6) dx I changed sqrt (1-x^6) into 1^(1/2)- x^(3) and let u=1^(1/2)- x^(3) then I got du/dx=3x^2 and subbed dx=du/3x^2 into the equation and got x-(x^4/4) but its not right. Options 7x^3/(3sqrt(1-x^7) + C cos-1(3x) + C sin-1(x^3) + C ...

Calculus
Im think im going to go with B then

Calculus
Okay Thanks. That one confused me.

Calculus
Okay will do. So I'm presuming your saying the answer is B. I think D works.

Calculus
Wait so A is right or is it wrong?

Calculus
Which of the following integrals cannot be evaluated using a simple substitution? I think it is A because if you would substitute there would be nothing left in the equation? Is that right? Options ∫√(x-1) ∫1/√(1-x^2) ∫x/√(1-x^2) ∫&#...

Calculus
Oh shoot I misread my answer. Thanks

Calculus
∫(x^3-x^2)/x^2 I got (x^2)/(2)-x + C but that's not one of the answers Options x - 1 + C (x^2/2)-(x^3/3) + C (x^4-x^3)/4x^2 + C (x^2/2) -x + C

Calculus
Yes Thank you

Calculus
∫((cos^3(x)/(1-sin^(2)) What is the derivative of that integral? I have been trying to use trig identities but can't find one to simplify this equation. I can't find one for (cos^3(x) or (1-sin^(2)) My options -sin(x) + C sin(x) + C (1/4)cos^(4)(x) + C None of ...

Math
Yes, it is I, your humble servant(LOL).

Math
T = 2 h. Ta = 3 h. Tb = ? T = Ta*Tb/(Ta+Tb) = 2. 3*Tb/(3+Tb) = 2. Tb = ?.

Physics
F = M*a, M = F/a = 26.5/6.5.

English
I chose C

Maths
g Girls in the class. 4g + 3 Boys in class. Total = g + (4g+3). The total should have been given.

physics in kinematics
Vo = 18m/s[37o]. Xo = 18*Cos37 = m/s. Yo = 18*sin37 = m/s.

Physics
A. Vr = -104 - 398i = 411.4km/h[75.4o] S. of W. = 14.6o W. of S. B. 411.4km/h[14.6o] E. of S.

Science
V^2 = Vo^2 + 2a*d = 0 + 2*0.5*100 = 100. V = 10 m/s. V=10m/s * 1km/1000m * 3600s/h = 36 km/h.

physics
Fr = 10N.[0o] + 30N.[120o] + 50N.[240o] X = 10 + 30*Cos120 + 50*Cos240 = -30 N. Y = 30*sin120 + 50*sin240 = -17.3 N. Tan A = Y/X = -17.3/-30 = 0.57735. A=30o S. of W. = 210o CCW from +x-axis. Fr = -30/Cos210 = 34.64 N. @ 210o CCW.

PHYSICS
Fr = Sqrt(F1^2 + F2^2) = Resultant force

Calculus
I tried to use partial fractions to do it, but it didn't work.

Calculus
Find the integral of 2/((2-x)(x+2)^2)dx.

Physics
I = (5^2/20^2)*X = (1/16)X W/m^2.

Precalc
The "j" means there is a 90-degree phase difference between the two terms and they cannot be added directly. Another method of writing the polar form: 2.83[45o].

physics
Work = F*d = 1500*Cos60 * 30 =

Calculus
Solve the following problem by separation of variables. T^2y'-t=ty+y+1 Y(1)=0 Y is a function of t.

Calculus
Wait, why is it the integral from 3-5 instead of 0-2?

Calculus
Sorry I forgot the dx after the integral.

Calculus
Find the integral from 0 to 2 of xsqrt(5-sqrt4-x^2)). The hint said to use substitution of u=sqrt(4-x^2), and that I needed one more substitution, but I don't know how to do it.

Algebra 1
Since there are 2 variables and only 1 Eq, I have to solve for 1 variable in terms of the other.

Algebra 1
12AB + 7B = 5A. 12AB - 5A = -7B. A(12B - 5) = -7B. Divide by (12B-5): A = -(7B/(12B-5)).

physics
Glad I could help.

physics
By definition, acceleration means to increase speed. When speed is decreasing it is called Deceleration. So you can't do both at the same time. When an object is moving, it is either accelerating, decelerating or moving at a constant speed. In other words, there are 3 ...

physics
d = 75N * 1m/1500N = 0.05 m. PE=0.5F * d = 0.5*75 * 0.05 = 1.875 J.

physics 1
1a. V = Vo + a*T1 = 0. T1 = -Vo/a = -22.5/-3.95=5.70 s To stop. V = Vo + a*T2 = 22.5. T2 = (22.5-Vo)/a = (22.5-0)/4.91=4.58 s. To accelerate back up to speed. T1+45+T2 = 5.70 + 45 + 4.58 = 55.3 s. 2. Hare: r*t = 1000. 1.5t = 1000. t = 666.67 s., Non-stop. Tortoise: r*t = 1000...

physics
Assuming the 3.5 m/s is horizontal: h = 0.5g*t^2. g = 9.8 m/s^2. t = ? A3. h = Vo*t + 0.5g*t^2 h = 230 m. Vo = -7.9 m/s(plane moving upward). g = 9.8 m/s^2. t = ? K5. The problem doesn't say what the captain is trying to do.

physics
Ma*Va + Mb*Vb = Ma*V + Mb*V. 30.7*2.64 + 109*1.29i + 30.7V + 109V. 81.05 + 140.6i = 139.7V. 162.3m/s[60o] = 139.7V. V = 1.16m/s[60o] N. of E.

physics
M1*V1 + M2*V2 = M1*V + M2*V. 2864*V1 + 856*0 = 2864*7.5 + 856*7.5. V1 = ?

physics
M1*V1 + M2*V2 = M1*28.7 + M2*V. 0.192*44.4 + 0.459*0 = 0.192*28.7 + 0.459V. V = ?

physics
M1*V1 + M2*V2 = M1*(-0.43) + M2*V. 0.13*0.22+0.22*(-0.30)=-0.43*0.13 + 0.22V. V = ? Multiply your answer by 100 to convert to cm/s.

physics
M1*V1 + M2*V2 = M1*V + M2*25. 24.9*22 + 13.2*11.8 = 24.9V + 13.2*25. V = ?

physics
M1*V1 + M2*V2 = M1*V + M2*V. 13.2*6.8 + 3*(-3.5) = 13.2V + 3V. V = ?

physics
a. V = Vo + g*t = 0. Vo - 9.8*2 = 0. Vo = 19.6 m/s. b. h = Vo*t + 0.5g*t^2. g = -9.8 m/s^2. t = 2 s. h = ?. c. Tr+Tf = 2 + 2 = 4 s. To fall back to top of bldg. Tr = Rise time. Tf = Fall time. 8-4 = 4 s. To fall from top of bldg. to gnd. h = Vo*t + o.5g*t^2. Vo = 19.6 m/s. t...

Language Arts Project/Essay HELP!
Ugh, I am not really good at writing, sorry but I fell I'm useless here. I would better recommend you to contcat Supreme essay service. Those guys are real professionals in what they do. Best of luck!

MATH HELP
A = (3)^5/2 * (3)^5/2 = (3)^10/2 = 3^5 = 243 in^2.

College Algebra
1. P1 = 0.64 + 0.30*0.64 = P2 = 0.64 + 0.40*0.64 = P3 = 2. P = 0.64 + m*0.64 = 1.10 0.64m = 1.10 - 0.64 = 0.46. m = 0.719 = 71.9%.

Math
A = 2*(15*5) + 2(30*5) + 30*15=900 Ft^2. = Total area to be painted. 900Ft^2 * 1gal/250Ft^2 = 3.6 Gal. of paint needed. Buy 4-1gal. cans.

PHYSICS! Really Confused! Test Tmrw
V^2 = Vo^2 + 2g*h = 0. h = -Vo^2/2g + 10 = -(5^2)/-19.6 = 11.28 m. h = 0.5g*T^2 = 11.28 m. 4.9T^2 = 11.28. T^2 = 2.30. T = 1.52 s. d = Vt*T = 30 * 1.52 = 45.6 m.

Math
(Y+1)+4

physics
See previous post: Wed,8-12-15, 12:14 AM.

physics
Correction: r = (d1+d2)/(43.3+T) = 1.99. (170.2+1.13T)/(43.3+T) = 1.99. Solve for T.

physics
d1 = 3.93m/s * 43.3s = 170.2 m. d2 = 1.13*T. r = (d1+d2)/T = 1.99 m/s. (170.2+1.13T)/T = 1.99. Multiply by T: 170.2 + 1.13T = 1.99T. 1.99T - 1.13T = 170.2. 0.86T = 170.2. T = 198 s.

=
Diode Connected: Vd + (I2+Id)R1 = 6 Volts. 0.7 + (I2+1.0)R1 = 6. 0.7 + I2*R1 + R1 = 6. Eq1: I2R1 + R1 = 5.3. Diode disconnected: V2 + I2*R1 = 6 Volts. 2 + I2R1 = 6. Eq2: I2R1 = 4. In Eq1, replace I2H1 with 4: 4 + R1 = 5.3. R1 = 1.3k = 1300 Ohms. In Eq2, replace R1 with 1.3k: ...

Algebra
You show the Ht. of only 7 players and the Wt. of only 6 players.

Mathematics
Show that the root equation (x-a)(x-b)=k^2 are always real numbers

Mathematics
Factorice 16(a-2b)^2-(a+b)^2 leaving your answer in the simplest form

pre algebra
P = Po(1+r)^n. Po = \$2000. r = 0.051/2 = 0.0255 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * 7yrs. = 14 Compounding periods.

Algebra
1. x-1/5 = +-3. 5x - 1 = +-15. 5x = 16, and -14. X = 16/5, or -14/5. 2. D. decreasing nonlinear.

Math
0.64N. N = the number of boxes sold.

physics
Fr = 25N.[25o] + F2[-73o] Since the acceleration is parallel to the x-axis, the sum of Y components of velocity equals 0: 25*sin25 + F2*sin(-73) = 0. 10.57 -0.956F2 = 0. -0.956F2 = -10.57. F2 = 11.1N[-73o].

physics
Vo = 56m/s[35o]. Xo = 56*Cos35 = 45.9 m/s. Yo = 56*sin35 = 32.1 m/s. Y = Yo*t + 0.5g*t^2=32.1*2.9 -4.9*2.9^2 = 52 m. X = Xo*T = 45.9m/s * 2.9s = 133 m.

Physics
V^2 = Vo^2 + 2g*h. Vo = 0. V = ?

Math
1-3/4 = 4/4-3/4 = 1/4 Eaten.

Science
Eff. = 70/100 * 100%.

Math
a. d1 = 200/sin43 = 293 Ft. b. d2 = 200/tan43. c. d3 = d2/Cos16. d. h = 200 + d2*Tan16

P = Po + Po*r*t P = 1700 + 1700*(0.12/12)*18 = \$2,006.

Physics
V = 50,000m/3600s = 13.9 m/s. t = 20min ? = 1200 s. a = (V-Vo)/t = Vo = 0. a/g * 100% =

Math
The driver formed a rectangle with 10 km horizontal sides and 20 km vertical sides(northward).

Physics Help
Vo = 100m/s[60o]. Xo = 100*Cos60 = 50 m/s. Yo = 100*sin60 = 86.6 m/s. Y^2 = Yo^2 + 2g*h = 86.6^2 - 19.6*150 = 4560. Y = 67.5 m/s.

Physics (angle Vector)
Vb - 5.4i = 11.8. Vb = 11.8 + 5.4i = 13m/s[24.6o] N. of E. = Compass heading. 9-5.4i) =

math
Started with \$X. x/3 + x/2 = x - 9.00. Multiply by 6 and solve for x.

algebra
Sold X none student tickets. Sold Y student tickets. Eq1: x + y = 937. Eq2: 5x + 3y = 3943. Multiply Eq1 by -3 and use Elimination Method.

Algebra
Right!

physics
Incomplete.

physics
Oops! I misread the numbers. Total=2*3.33 + 1*2.11 + 1*1 = 9.77 Lbs. 9.77Lbs * 5days/10Lbs. = 4.9 Days or 5 days.

physics
Total = 23*33 + 12*11 + 1*1 = 892 Lbs. 892Lbs * 5days/10Lbs = 446 Days.

Mathematics
(x-6)*Log4 = 3x*Log2. Divide by Log4: x-6 = 3x*Log2/Log4. x-6 = 3x*0.5 = 1.5x. x-1.5x = 6. -0.5x = 6. X = -12.

Correction: In your case, 48 is the area of the base: V = B*h = 48m^2 * 7m = 336 m^3 or 336 cubic meters. Again, take half of the base only when it is the diameter.

V = pi*r^2*h = 3.14*24^2*7 = 12,660.5 cm^3(Not m^3). V = B*h, B=Area of the base, V=pi*r^2*h 48 is not the area of the base; it is the diameter of the base. Diameter*height = Square units. Diameter/2 = Radius. So you take 1/2 of the diameter to get the radius. I hope this helps.

Physics
-2.8 + Vb = -10.4i. Vb = 2.8 - 10.4i. = 10.8m/s[-74.9o] = 74.9o S. of E. = 15.1o E. of S.

algebra
1/4 + 1/3 + 1/2 = 3/12 + 4/12 + 6/12 = 13/12 = 1 1/12. Impossible, because 13/12 is more than a whole pizza.

Physics
101kpa = 101*10^3pa = 1.01*10^5 pa.

science
Increasing the voltage increases the current and power(P = E*I); therefore, the voltage should be increased.

Math
15/0.6 =

math
V1 = 75i mi/h. V2 = 60 mi/h Tan A = V1/V2=75/60 = 1.2500, A = 51.3o. d1 = 250*sin51.3 = 195 mi. V1*T = 195, 75 * T = 195, T = 2.60 h. = 156 min.

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