Sunday
April 26, 2015

# Posts by Henry

Total # Posts: 10,489

math
1. P1 = Po(1+r)^n Po = \$2,000 r = 0.06 n = 35yrs * 1comp./yr. = 35 Compounding periods. P1 = 2000(1.06)^35 = \$15,372.17 2. Use same Eq as above with a 25-yr. investment(60-35). P2 = Po(1+r)^n Difference = P1-P2. 3. Use your table and compare with calculated values below. P = 1...
June 26, 2014

physics
d = pi*2r/2 = pi*r = 3.14 * 70 = 219.9 m = Total distance covered. = Total Dis- placement.
June 26, 2014

physics
144km/h = 144,000m/3600s = 40 m/s. V = (60+40)/2 = 50 m/s.
June 25, 2014

physics
a = F/m = 18.1/2.92 = 6.20 m/s^2. V = Vo + a*t = 0 + 6.20*4.48 = 27.77 m/s P=F*(d/t) = F*V = 18.1 * 27.77=502.6 J/s = 502.6 Watts.
June 25, 2014

math
P = (Po*r*t)/(1-(1+r)^-t) Po = %73,700 r = (10%/12)/100% = 0.008333 = Monthly % rate expressed as a decimal. t = 25yrs. * 12mo./yr. = 300 Months. Plug the above values into the given Eq and get: P = \$200,913.71 P/t = 200913.71/300mo = \$669.71/mo.
June 24, 2014

math
Po = 800 - 0.05*800 = \$760 P = 65.41/mo. * 12mo. = \$784.92 I = P-Po = 784.92 - 760 = \$24.92 %I = (I/Po)*100% = (24.92/760)*100% = 3.3 = APR.
June 24, 2014

pre cal
1. F(x) = 2/(x^2-2x-3) C = -3 = 1*(-3). 1+(-3) = -2 = B. F(x) = 2/(x+1)(x-3) x+1 = 0 X = -1, Denominator = 0. x-3 = 0 X = 3, Denominator = 0. Domain = All real values of x except -1, and 3. Y-int. = 2/(0+1)(0-3) = 2/-3 = -2/3 No x-intercept, because the numerator is constant ...
June 23, 2014

pre cal
(1/sqrt2,-1/sqrt2). sqrt = Square root of 2.
June 23, 2014

pre cal
Cos(-45) = 1/sqrt2 = X/r x^2 + y^2 = r^2 1^2 + y^2 = ((2)^1/2)2 1 + y^2 = 2 y^2 = 2-1 = 1 Y = sqrt1 = +-1. Y = -1(Q4). P(x,y) = (1,-1).
June 23, 2014

1. X = 40*cos25 = 36.21 m/s^2. Y = 40*sin25 = 16.90 m/s^2. 2. d2-d1 = 25 m. d2 = 25 + d1 d2=25 + 35[230o]=25+35*cos230+i35*sin230 = 25 - 22.50-26.81i = 2.50 - 26.81i = 27m[-84.7o] = 27m[275.3o] = 27m[5.3o E. of S.] 3. Correct.
June 23, 2014

math
F(x) = 5x-1 F(-6) = 5*(-6) - 1 = -31. g(x) = -4x^2 - 3 g(5)=-4*5^2 - 3 = -100 - 3=-100 + (-3) = -103.
June 22, 2014

math
Eq1: D + C = 24kg Eq2: D + R = 20kg Eq3: C + R = 10kg Subtract Eq2 from Eq1: D + C = 24 D + R = 20 Diff: C-R = 4 R = C-4 In Eq3, replace R with C-4: C + C-4 = 10 2C = 14 C = 7 kg In Eq1, replace C with 7: D + 7 = 24 D = 17 kg R = C-4 = 7-4 = 3 kg C + D + R = 7 + 17 + 3 = 27 kg.
June 22, 2014

Survey of Mathematics
Jan. 5th thru Dec. 9th = 338 Days. a. I = Po*r*t = 6500*(0.085/360)*338 = \$518.74 b. P=(6500 + 6500*(0.085/360)*118)-1500 = \$6681.10 - 1500 = \$5181.10 After May 3. P = 5181.10 + 5181.10*(0.085/360)*128 - 2500 = 5337.68 - 2500 = \$2837.68 After Sept. 11 P = 2837.68 + 2837.68*(0....
June 22, 2014

Physics
Work = Fap*cosA * d=74.1*cos32.3 * 72.4 = 4535 J.
June 22, 2014

physics
V = Vo + a*t. Vo = Initial velocity.
June 21, 2014

ap physics
See previous post: Fri,6-20-14,11:33PM.
June 21, 2014

ap physics
d = d2-d1 = 120m[105o]-60m[15o] X = 120*cos105 - 60*cos15 = -89.0 m. Y = 120*sin105 - 60*sin15 = 100.4 m. Tan Ar = Y/X = 100.4/-89.0 = -1.12789 Ar = -48.44o = Reference angle. A = -48.44 + 180 = 131.6o = Direction. d = Y/sinA = 100.4/sin131.6 = 134.3 m. [131.6].
June 20, 2014

math
a ball is thrown down ward from a 320 ft building at a initial velocity of 32 ft per sec. How long would the ball take to reach a height of 48 feet?' 16t^2+32+320
June 20, 2014

Po =(1-0.08) * 8500 = \$7820. P = 243.07/mo. * 36mo. = \$8750.52 P = Po + Po*r*t = 8750.52 7820 + 7820*r*3 = 8750.52 7820 + 23,460r = 8750.52 23,460r = 8750.52-7820 = 930.52 r = 3.97% or 4.0% = APR.
June 20, 2014

Survey of mathematics
Solved under a later post.
June 20, 2014

Survey of Mathematics
Correction: 100%-5% = 95% borrowed.
June 20, 2014

Survey of Mathematics
100% - 5% = 95% Down payment. Po = 0.95 * \$289,000 = \$274,550.=Amount of loan. P = (Po*r*t)/(1-(1+r)^-t) r = (6%/12)/100% = 0.005=Monthly % rate. t = 25yrs. * 12mo./yr. = 300 months. Plug the above values into the given Eq and get: P = \$530,678.85 = Total cost of the house. 2 ...
June 20, 2014

Survey of mathematics
Po = P - 0.08P = 8500-(0.08*8500)= \$7820 243.07/mo. * 36mo. = \$8750.52 Paid back. I = Po*r*t = 8750.52-7820.00 = 930.52 7820*r*3yrs. = 930.52 23460r = 930.52 r = 0.0397 = 3.97% = APR.
June 20, 2014

physics
Vp+Vw = 275km[45o] Vp + 55km[90o] = 275[45o] Vp + 55i = 275*cos45 + i275sin45 Vp + 55i = 194.45 + 194.45i Vp = 194.45 + 194.45i - 55i Vp = 194.45 + 139.45i = 239.3km[35.6o] = Velocity and heading of plane. Check: 194.45+139.45i + 55i = 194.45 + 194.45i = 275[45o]
June 19, 2014

trig
V(0,0), T(-12,5) X = -12 - 0 = -12. Y = 5- 0 = 5. r = Sqrt(X^2+Y^2) = Sqrt(144+25) = 13 Sin A = Y/r = 5/13. Cos A = X/r = Tan A = Y/X CSC A = r/Y Sec A = Cot A = NOTES: V = Vertex. T = Terminal side. Sqrt = Square root.
June 19, 2014

Algebra
(2b-2)/(2b^2-8) 2b^2-8 = 0 2b^2 = 8 b^2 = 4 b=+-2 Gives a denominator of zero which makes the expression Undefined. Domain: All real values of b except +2 and -2. Mathematically: -2 > b > 2.
June 19, 2014

Physics
1. See previous post:Tue,6-17-14,9:52 PM 2. Xo = 4.0 m/s. h = 0.5g*t^2 = 6.5 m. 4.9*t^2 = 6.5 t^2 = 1.327 Tf = 1.15 s. = Fall time. d = Xo * Tf = 4.0m/s * 1.15s = 4.60 m.
June 18, 2014

Physics
June 18, 2014

Physics
1. r1=d/t = 30m/5s = 6 m/s.=Speed of rabbit r2=30m/120s = 0.25 m/s.=Speed of turtle T1 = d/r1 = 96/6 = 16 s.=Rabbit's time. T2 = d/r2 = 96/0.25 = 384 s. = Turtle's time. T2 - T1 = 384 - 16 = 368 s. 2. T2 = d/r2 = 500/10 = 50 s. = Time of red bicycle. d = r1 * T1 = 500 ...
June 18, 2014

math
Incomplete.
June 18, 2014

Physics
T1 = d1/r1 = 800/6 = 133.3 s. T2 = d2/r2 = 800/8 = 100 s. a. T1+T2 = 133.3 + 100 = 233.3 s.=Total time of travel. b. r = d/T = 1600m/233.3s = 6.86 m/s.
June 17, 2014

Physics
Direction = 25.0o West of north? a. D = 290m[25.0o] t = D/V = 290[25.0]/2[25o] = 145 s. b. r = D/t = 290m/145s = 2m/s.
June 17, 2014

physics
d1 + d2 = 4-1 = 3 m. (0.5g*t^2) + (Vo*t+0.5g*t^2) = 3 m. 4.9t^2 + 6t+(-4.9t^2) = 3 6t = 3 t = 0.5 s. d1 = ho - 0.5g*t^2 d1 = 4 - 4.9*0.5^2 = 4 - 1.225=2.775 m. Above gnd. d2 = 1 + (6*0.5 + (-4.9)*0.5^2 d2 = 1 + (3 + (-1.225) = 1 + 1.775=2.775 m. Above gnd. Therefore, the ball ...
June 17, 2014

Angles,Lines and Triangles
A1 = A2 Eq: A1 + A2 + A3 = 180o A1 + A2 + (A1+18) = 180 Replace A2 with A1: A1 + A1 + (A1+18) = 180 3A1 + 18 = 180 3A1 = 180-18 = 162 A1 = A2 = 54o A3 = A1 + 18 = 54 + 18 = 72o.
June 17, 2014

math apr
See previous post: Tue,6-10-14, 10:55AM.
June 17, 2014

math
Jerry's number = n. Mike's number = n+2000 Barry's number = n+400. Larry's number = 443+1500 = 1943. Sam'2 number = 443. Barry's number = 443+60 = 503. n+400 = 503 n = 103 n+2000 = 103+2000 = 2103
June 17, 2014

Physics
Fg=m*g = (66.2kg+5.3kg)*9.8N/kg=700.7 N. = Force of gravity = Combined wt. of person and sled. Ff = u*Fg = 0.12 * 700.7 = 84.1 N. = Force of friction. Fx-Ff = m*a Fx-84.1 = m*0 = 0 Fx = 84.1 N.
June 16, 2014

math
Y = 1.5x X = The # of bottles of water purchased. Y = Total cost in dollars. (x,y) (1,1.5) (2,3) (3,4.5) (4,6).
June 16, 2014

Physics
r = 225km/h = 225000/3600s = 62.5 m/s. = Average speed for full length. r1 = 205km/h = 205000m/3600s = 56.94 m/s.= Average speed for 1st half(700m). (r1+r2)/2 = r (56.94+r2)/2 = 62.5 m/s. 56.94 + r2 = 125 r2 = 125-56.94 = 68.06 m/s = Average speed for 2nd half of race.
June 15, 2014

Physics
Johnny: T1 = 4 min,57s = 240+57 = 297 s. Martha: T2 = 4 min,38s = 240+38 = 278 s. r2 = 400m/278s. = 1.439 m/s. d = r2*(T1-T2) = 1.439(297-278)=27.3 m.
June 15, 2014

algebra
Sum = 8 = 7+1 = 6+2 = 5+3 = 4+4 Select 5, and 3: Original #: 53. Reversed: 35. Difference = 53-35 = 18.
June 15, 2014

algebra
X Nickels. (16-X) Qtrs. 5x + 25(16-X) = 220 Cents. Solve for X.
June 15, 2014

Algebra 2
S1+S2+S3 = 5 Ft. S1 = S2 = S3 S1+S1+S1 = 5 3S1 = 5 S1 = 5/3 Ft. = 20 In. = S2 = S3. (s/2)^2 + h^2 = S^2 (20/2)^2 + h^2 = 20^2. Solve for h.
June 15, 2014

Algebra 2
N Large packages. (12-N) Small packages. Cost = 7n + 4.5(12-n) Cost = 7n + 54-4.5n = 2.5n + 54.
June 15, 2014

physics
h = 0.5g*t^2 = 1 m. 4.9t^2 = 1 t^2 = 0.204 t = o.452 s. = Fall time. d = Vo*t = 1.32 m. Vo*0.452 = 1.32 Vo = 2.92 m/s.
June 14, 2014

physics
V = 42.3mi/40min * 1600m/mi * 1min/60s = 28.2 m/s. V = 42.3mi/40min * 1.6km/mi * 60min/h = 101.5 km/h.
June 13, 2014

physics
V = 22.7[32o] Momentum=m*V = 537 * 22.7=12,190 kg-m/s.
June 13, 2014

Physics
Wt. = 1.8 Tonne. Vo = 3 m/s. d = 45 m. Fk = 80 N. Mass = 1.8 * 1000kg = 1800 kg. Fg = m*g = 1800 * 9.8 = 17,640 N. KE + PE = mg*h-Fk*d KE + PE = mg*h-80*45 0.5m*Vo^2 + 0 = mg*h-3600 900*9 + 3600 = 17640h 17,640h = 11,700 h = 0.6633 m. sinA = h/d = 0.6633/45 = 0.01474 A = 0.84o...
June 11, 2014

physics
99. If you drop an object: Vo = 0 = Initial velocity. a = g = 10 m/s^2. If you throw it down: Vo > 0 a = g = 10 m/s^2. So in both cases, the acceleration remains constant at 10 m/s^2.
June 11, 2014

Algebra
6x-72 = 0 6x = 72 X = 12
June 11, 2014

Math
y-6=> 12 Y =>12+6 Y => 18 This is the Eq of a hor. line in which Y => 18 for all values of X.
June 11, 2014

calculus
V = Vo + a*t = 2000 + (-3000)*0.03 = 1910 m/s.
June 11, 2014

physics
Momentum = m*V = 5 * 3 = 15 kg-rad/s.
June 10, 2014

Algebra 1
1.(15-5x)/(x^2-9x+18). -5(x-3)/(x-3)(x-6) = -5/(x-6). 2. T=T1*T2/(T1+T2) T = 40*60/(40+60)=24 min. 3. A*C = 2*(-20)-40 = 4*(-10) = 5*(-8) B = The sum of the pair of factors that are divisible by 2: B = 2+(-20) = -18 B = 4+(-10) = -6 Eq1: 2x^2-18x-20 = 0 Divide by 2: x^2-9x-10...
June 10, 2014

Physics
a. V=110km/h = 110000m/3600s.=30.56 m/s V^2 = Vo^2 + 2g*h h = (V^2-Vo^2)/2g = (0-(30.56)^2/-19.6 = 47.6 m.
June 10, 2014

Physics
d = (24.5N./2500N.)*1M = = 0.0098 M.
June 10, 2014

math - APR
a. (42,650-5100)/60 = %625.83/mo. b. P = (Po*r*t)/(1-(1+r)^-t) Po = 42,650-5100 = 37550 r = (2.5%/12)/100% = 0.00208 t = 60 Months. Plug the above values into the given Eq and get: P = \$39,984.81 39984.81/60mo = \$666.41/mo. = Monthly payments. c. I = (39984.81-37550)/5yrs = \$...
June 10, 2014

math
Use synthetic(long-hand) division: (2x^3-5x^2+x+2)/(x-2) = 2x^2-x-1 a = 2, and b = -1.
June 10, 2014

physics
Green = 0.99*200 = 198 White = 0.01*200 = 2 X green marbles removed. (200-x) Marbles remaining. 0.98(200-x) + 2 = 200-x 196-.98x + 2 = 200-x 0.02x = 200-198 = 2 X = 100 Green marbles removed. 198-100 = 98 Green marbles remaining. 200-100 = 100 total Marbles remaining. Check: ...
June 10, 2014

Physics
a. Fb = m*g = 76 * 9.8 = 744.8 N. = Force of barbell. Po = 20 * 744.8 * 2.6/90s = 430.3 J/s = 430.3 W. b. hp = 430.3/746 = 0.577
June 9, 2014

physics
See previous post.
June 9, 2014

physics
V^2 = Vo^2 + 2g*h = 0 + 20*10 = 200 V = 14.14 m/s. 0.5g*t^2 = 10 m. 5t^2 = 10 t^2 = 2 t = 1.414 s.
June 9, 2014

physics
Vo = 136km/h = 136,000m/3600s=37.78 m/s V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a d = (0-(37.78^2))/-500 = 2.85 m.
June 8, 2014

Math Personal Finance
See previous post.
June 8, 2014

Math Personal Finance
P = Po(1+r)^n = 2000 r = (6%/12)/100% = 0.005 n = 12comp/yr. * 5yrs. = 60 compounding periods. Po(1.005)^60 = 2000 Po = 2000/(1.005^60) = \$1482.74=Initial deposit or present value.
June 8, 2014

Math Personal Finance
P=Po(1+r)^n. Calculate int. for 1 year. r = (5%/12)/100% = 0.00417 = Monthly % rate expressed as a decimal. n = 12comp./yr. * 1yr. = 12 Compounding periods. P = 7000(1.00417)^12 = \$7358.13 I = P-Po = 7358.13 - 7000 = \$358.13 APY = (I/Po)*100% = (358.13/7000)*100% = 5.116%
June 8, 2014

Engg Mechanics
Block A: 200*sin30 = 100 N. = Force parallel to the plane. Fn = 200*cos30 = 173.2 N. = Normal force Block B: 100*sin30 = 50 N. = Force parallel to the plane. Fn = 100*cos30 = 86.6 N. = Normal force. P = Wa+Wb = 200 + 100 = 300 N.
June 8, 2014

electronics
Given: i = 6 mA. t = ? 1. Locate 6 mA on the y-axis. 2. Draw a hor. line from 6 mA to the curve. 3. Draw a ver. line from the intersection of the hor. line and curve to the x-axis. 4.Read the time, t , at the intersection of the ver. line and x-axis. Note: When t is given, ...
June 8, 2014

physics
a. The force of static friction decreases. b. The force of friction increases. The max. possible value of the force of friction increases. The max. angle at which block will slide decreases.
June 8, 2014

Physics
Upward: a = g = -9.8 m/s^2(slowing down) Highest point: a = g = -9.8 m/s^2. Downward: a = g = 9.8 m/s^2. The data shows that the acceleration due to gravity is present during the entire flight of the object. If g goes to zero, the object would not come down.
June 8, 2014

Physics
a. V^2 = Vo^2 + 2g*d V^2 = 4.9^2 + 19.6*21 = 435.61 V = 20.87 m/s. b. V = Vo + g*t t = (V-Vo)/g = (20.87-4.9)/9.8 = 1.63 s.
June 7, 2014

physics
a. False.
June 7, 2014

Science
2. Slower object: KE = 0.5m*V^2. Faster object: KE = 0.5m*(2V)^2 = 0.5m*4*V^2. 0.5m*4V^2/0.5m*V^2 = 4 Times. 3. KE = 0.5m*V^2 9. MA = 20/100 10. W = F*d. d = 0.
June 7, 2014

Physics
a. Vo=36mi/h * 1600m/mi * 1h/3600s=16 m/s. V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a d = (0-256)/-10 = 25.6 m. b. d = 0-1024)/-10 = 102.4 m.
June 7, 2014

MULTIPLY. WRITE EACH PRODUCT IN SCIENTIFIC NOTATIO
24. (3*10^6)(2*10^12) = 6*10^(6+12)=6*10^18 26. (6*10^9)(5*10^4) = 30*10^(9+4) = 30*10^13 = 3*10^14
June 6, 2014

MULTIPLY. WRITE EACH PRODUCT IN SCIENTIFIC NOTATIO
34. 5^10/5^7 = 5^(10-7) = 5^3 36. 76^11/76^5 = 76^(11-5) = 76^6
June 6, 2014

electronics
Rt = R2*R3/R1 = 2.11k R2*8.2k/2.2k = 2.11k 3.727R2 = 2.11k R2 = 0.566k = 566 ohms. NOTE: I'm assuming that Rt = 2.11k at 0oC.
June 6, 2014

physics
Yes, when an object is DROPPED, the initial velocity is 0. When an object is THROWN up or down, the initial velocity is not 0. V^2 = Vo^2 + 2g*h V^2 = 0 + 19.6*7 = 137.2 V = 11.71 m/s.
June 5, 2014

Math
1. ) = 30 + 0.1(x-200) F(x) = 30 + 0.1x - 20 The above Eq is valid for all real values of X that are equal to or greater than 200: X => 200. When x = 200 minutes, the cost would be \$30. None of the given choices meets this requirement. 2. Cost = 30 + 0.1x - 20 = \$100 0.1x...
June 5, 2014

math
See previous post: Fri,5-23-14,12:35 PM.
June 5, 2014

electrical circuit instrumentation
R1 = 6 ohms. R2 = 8 ohms. Re=R1*R2/(R1+R2) = 6*8/(6+8)=3.429 ohms = Equivalent resistor. I1 = E/R1 = 36/6 = 6 Amps. I2 = E/R2 = 36/8 = 4.5 Amps. I = I1+I2 = 6 + 4.5 = 10.5 Amps. P1 = E^2/R1 = 36^2/6 = 216 Watts. P2 = E^2/8 = 36^2/8 = 162 Watts. P = P1+P2 = 216 + 162 = 378 ...
June 5, 2014

mechanical physics
Incomplete.
June 5, 2014

Physics
1. h = 0.5g*t^2 = 6 m. 4.9t^2 = 6 t^2 = 1.224 Tf = 1.107 s. = Fall time. d = Xo * Tf = 24 m. Xo * 1.107 = 24 Xo = 21.7 m/s = Initial velocity. 2. Fg = m*g = Force of gravity = Wt. of car. Fk = u*Fg = Force of kinetic friction. Fn = Fap-Fk = Net force. Fap = Force applied.
June 5, 2014

science
1. V = Vo + g*t = 30 - 10*2 = 10 m/s. 2. hmax = (V^2-Vo^2)/2g hmax = (0-(30)^2)/-20 = 3. V = Vo + g*Tr = 0 @ hmax. Tr = -Vo/g = -30/-10 = 3 s. = Rise time.
June 3, 2014

math
I=2.37*10^-5 watts/cm^2=Sound Intensity level. Io =10^-16 W/cm^2 = Reference sound Intensity level. db = 10*Log(I/Io) db = 10*Log(2.37*10^-5/10^-16) = 114
June 3, 2014

physics
Fx = 100*Cos37 = 79.86 N. Wb = m*g = 10kg * 9.8N/kg = 98 N. = Weight of buggy. a=(Fx-Fk)/m = (79.86-60)/10=1.99 m/s^2
June 3, 2014

physics
d1 = d2 25t = 0.5a*t^2 25 = 0.5a*t 0.002t = 25 t = 12,500 s. = 3.5 h.
June 3, 2014

physics
d = 300km[135o] V1 = 300km[135o]/0.75h = 400 km/h[135o] without wind. Vp + Vw = 400o[135] Vp + 80[-90o] = 400[135] Vp = 400[135] - 80[-90] Vp=400*cos135+i400*sin135 - (80*Cos(-90)+i80*sin(-90)) Vp = -282.84+i282.84 - (0-i80) Vp = -282.84 + i362.84 = 460km[128o] = Velocity and ...
June 3, 2014

Algebra 1 (Reiny)
1. T = T1*T2/(T1+T2) = 2*3/(2+3)=1.2 h. 2. H = 0.4 * 300 = 120 mL in current solution. W = 0.6 * 300 = 180 mL of water in current solution. W/(W+H) = 0.7 W/(W+120) = 0.7 W = 0.7W + 84 0.3W = 84 W = 280 mL of water in new solution. 280-180 = 100 mL of water added to new solution.
June 3, 2014

geometry
A1 = 150o = Minor Arc. A2 = 360-150 = 210o = Major Arc. X = (A2-A1)/2 = (210-150)/2 = 30o=Angle formed by 2 tangents. a
June 3, 2014

College Algebra
Length = L units. Width = (2L-2) units. A = L(2L-2) = 82cm^2 2L^2 - 2L - 82 = 0 L^2 - L - 41 = 0 Use Quadratic formula: L = 6.92 cm. Width = 2L - 2 = 2*6.92 - 2 = 11.84 cm. The diagonal divides the rectangle into 2 congruent rt. triangles. D^2 = L^2 + W^2 = 6.92^2 + 11.84^2=...
June 2, 2014

1. Width = W ft. Length = (W+20) ft. A = W*(W+20) = 8,000 Ft^2 W^2 + 20W - 8000 = 0 C=-8,000 = -80*100. Sum = -80+100=20=B. (w+100)(w-80) = 0 w+100 = 0, W = -100 w-80 = 0, W = 80 Ft = Width. w+20 = 80+20 = 100 Ft = Length. 2. A = L*W = 16, L = 16/W. Eq2: L^2 + W^2 = 68 In Eq2...
June 2, 2014

LOOK AT THE GIVEN TRIANGLES??
a. P1 = (4x+2) + (7x+7) + (5x-4)=16x + 5 P2 = (x+3) + (x+7) + (2x-5) = 4x+5 b. P1-P2 = (16x+5) - (4x+5) = 16x+5 - 4x-5 = 12x.
June 2, 2014

physics
d = 3.6 + 0.5 = 4.1 miles. T1 = 3.6/9 + 12/60 = 0.6 hr. To travel 4.1 miles from starting point. V1 = d/T1 = 4.1/0.6 = 6.83 mi/h. V2=9.0 mi/h. when returning to starting point. V = (V1+V2)/2 = (6.83+9.0)/2 = 7.92 mi/h = Average velocity for entire trip.
June 2, 2014

physics
T^2 = 4pi^2(L/g) = 3.4^2 39.48(2.87/g) = 11.56 113.3/g = 11.56 11.56g = 113.3 g = 9.80 m/s^2
June 2, 2014

Kirr
P = Po(1+r)^n = \$25,000 r = (1.825%/365)/100% = 5*10^-5 = Daily % rate expressed as a decimal. n = 365Comp./yr. * 4yrs. = 1460 Compounding periods. Po(1.00005)^1460 = 25000 Po = 25,000/1.00005^1460 = \$23,240.
June 2, 2014

algebra math!
9pts/6wks = 1.5 Points/week.
June 1, 2014

physics
Wb = m*g = 40kg * 9.8N/kg = 392 N. = Weight of box. Fk=u*(Wb-F*sin31)=0.45(392-173*sin31) = 136.3 N.= Force of kinetic friction. Fn=F*CosA-Fk = 173*cos31 - 136.3 = 12 N. = Net force. a = Fn/m = 12/40 = 0.30 m/s^2.
June 1, 2014

Physics
hmax = L*sin A = 5*sin40 = 3.21 m. At top of incline: KE + PE = mg*hmax-Fk*L 0 + PE = mg*3.21-10*5 PE = mg*3.21-50. At bottom of incline: KE + PE = mg*3.21-50 KE + 0 = mg*3.21-50 KE = mg*3.21-50 = 35 J. m*9.8*3.21-50 = 35 31.5m-50 = 35 31.5m = 85 m = 2.7 kg. = Mass of box.
May 30, 2014

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