Friday

July 1, 2016
Total # Posts: 11,874

**trigonometric functions**

h = 100*sin14 =
*February 27, 2015*

**math**

3 thousands, and 3 hundredths.
*February 27, 2015*

**physics**

F-200 = M*a F-200 = 350 * 3 = 1050 F = 1250 N.
*February 27, 2015*

**3rd grade math**

1/3 * 36 = 12.
*February 27, 2015*

**math**

3 thousands, and 3 hundredths.
*February 26, 2015*

**science please help asap**

See Related questions: 2-26-15, 11:06 AM.
*February 26, 2015*

**Math**

2. x + 4 > 6 3. x => 3C 4. x => $15
*February 26, 2015*

**Physics**

F = 392 + 2 = 394 Hz
*February 26, 2015*

**Math**

RQ = 2-(-2) = 4 = Hor. line RP = (2-(-1) = 3 = Ver. line, downward. Tan A = RQ/RP = 4/3 = 1.33333 A = 53.1o
*February 26, 2015*

**maths**

Cos A = 2m/9m.
*February 26, 2015*

**math**

Plate cost $X. A cup cost $2X. A pot cost $2X + 3 x + 2x + 2x+3 = $10.20 Solve for x.
*February 26, 2015*

**physics**

Circumference = pi*2r = 3.14 * 4,180 = 13,132 m. d = V*t d = 13,132 m. V = 233 m/s. Solve for t.
*February 26, 2015*

**Physics mechanics**

d = 60^2/30^2 * 8 = 4 * 8 = 32 m
*February 26, 2015*

**science please help asap**

2. M*g = 490 * 9.8 = 4802 N. = Wt. of the body. Fn = Mg-Fap*sin A = 4802-1200*sin20 = 4392 N = Normal force. Fx-Fs = M*a 1200*Cos20 - Fs = M*0 1128 - Fk = 0 Fk = 1128 N. = Force of kinetic friction u = Fk/Fn = 1128/4392 = 0.257 3A. F = M*a F = 318.1 N. a = 3 n/s^2 M = mass in ...
*February 26, 2015*

**Physics**

Work = F*d = Mg * d. Their wt. and distance was the same; therefore, they did the same amount of work.
*February 26, 2015*

**science**

See previous post.
*February 25, 2015*

**physics**

The force must be in the same direction as the motion(hor.). Work = Fx*d = 0 * 10 = 0
*February 25, 2015*

**Physics**

Work = Fx*d = 200*Cos30 * 20 = Answer in Joules.
*February 25, 2015*

**Math**

(-4,3), (h,k), (6,-5). The center = 1/2 of the total distance: h - (-4) = (6 - (-4))/2 h + 4 = 10/2 = 5 h = 1 k-3 = (-5-3)/2 Solve for k.
*February 25, 2015*

**algebra**

Sarita: X muffins. Clara: X muffins. Joe: X muffins. Clara: x-1 = 14 X = 15 Total = 3x = 3*15 = 45 muffins.
*February 25, 2015*

**algebra**

3x^2 + 3x - 6 = 0 A*C = 3*(-6) = -18 = -3*6 Choose the pair of factors whose sum = B = +3: -3, and 6. 3x^2 + (-3x+6x) - 6 = 0 Form two factorable binomials: (3x^2-3x) + (6x-6) = 0 3x(x-1) + 6(x-1) = 0 (x-1)(3x+6) = 0 (x-1)*3(x+2) = 0 x-1 = 0 X = 1 3(x+2) = 0 Divide by 3: x+2...
*February 25, 2015*

**physics**

V^2 = Vo^2 + 2a*d a = V^2/2d = 87^2/170 = 44.5 m/s^2. M*g = 219,000 N. M = 219000/g = 219000/9.8 = 22,347 kg F = M*a = 22,347 * 44.5 =
*February 25, 2015*

**Physics**

Incomplete.
*February 25, 2015*

**Physics**

V^2 = Vo^2 + 2a*d V = 64.1 m/s Vo = 0 d = 29.2 m. Solve for a. F = M*a M = 35.5 kg Solve for F.
*February 25, 2015*

**physics**

a. V^2 = Vo^2 + 2g*h = 0 Vo^2 = -2g*h = -(-19.6)*1.29 = 25.284 Vo = 5.03 m/s b. 0.5g*t^2 = 1.29 m. 4.9t^2 = 1.29 t^2 = 0.263 Tf = 0.513 s. = Fall Time. Tr = Tf = 0.513 s. = Rise time. Hang time = Tr + Tf = 0.513 + 0.513 = 1.026 s.
*February 25, 2015*

**Algebra**

Y = 3x^2 + 19x - 72 = 0 A*C = 3*(-72) = -216 = -8*27. Sum = 19 (3x^2-8x) + (27x-72) = 0 x(3x-8) + 9(3x-8) = 0 (3x-8)(x+9) = 0 3x-8 = 0 3x = 8 X = 8/3 x+9 = 0 X = -9 Solution: X = -9, and 8/3.
*February 25, 2015*

**Physics**

V = Vo + a*t = Vo = 0 a = 3m/s^2 t = 10 s. Solve for V.
*February 25, 2015*

**physics**

F = M * 3g = 63.6kg * 3*9.8N/kg =
*February 25, 2015*

**Science**

a. PE max = Mg*h = 59*9.8*24 = 13,877 J. b. KE + PE = PE max = 13,877 J.
*February 25, 2015*

**math**

$X in account. x-30 = 3x/4 4x-120 = 3x X = $120
*February 25, 2015*

**physics**

V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d V = 0.63 m/s Vo = 0 d = 0.45 m. Solve for a. F = M*a M = 69 kg Solve for F.
*February 25, 2015*

**Math SO HARD :C**

T + 8 = -20 T = -20-8 = -28o C @ Midnight.
*February 25, 2015*

**physical science**

Correct.
*February 25, 2015*

**Physics**

I = V/R = 9/230 = 0.0391 Amps = 39.1 mA.
*February 25, 2015*

**Algebra 1**

Multiply Eq1 by -2 and add: -10x - 2y = -18 +10x - 7y = 18 Sum: 0 - 9y = 0 Y = 0 In Eq1, replace Y with 0 and solve for X -10x - 2*0 = -18 X = 1.8
*February 24, 2015*

**maths**

X pizzas 4X Drinks 12x + 0.5*4x = 112 Solve for X.
*February 24, 2015*

**physics**

Thank you Damon! I think I understand what you meant when I read your post My triangle was correct though, yes? I just referred to them wrong?
*February 24, 2015*

**physics**

Wait that's not how it's supposed to look. Ok
*February 24, 2015*

**physics**

How do I know which trig function to use? I made my second triangle like this _____ \ | \ | \ | \|
*February 24, 2015*

**physics**

Why did you swap Betas trig functions?
*February 24, 2015*

**physics**

What do you mean, I did indicate on the question that it was west of north?
*February 24, 2015*

**physics**

A golfer takes two putts to sink the ball, one is (81.6 ft, 31.7 degrees N of E) and the other is (3.20 ft, 53.4 degrees W of N). What is the displacement of the single putt that would sink the ball on the first try? Well, what I did was make a diagram of the two vectors, I ...
*February 24, 2015*

**Science**

M*g = 90 N. M*9.8 = 90 M = 9.18 kg Density = 9.18kg/45mL = 0.204 kg/mL Note: A 90-N. object has a mass of 9.18 kg or 9,180 grams.
*February 24, 2015*

**Finance**

V = Vo(1+r)^n r = 5%/365/100% = 0.00013699 = Daily % rate expressed as a decimal. n = 365Comp./yr * 11Yrs = 4015 Compounding periods. V = 10,000(1.00013699)^4015 = $17,332.13
*February 24, 2015*

**Physical science**

Fp = Mg*sin35 = 315 Mg = 315/sin35 = 549 N. = Force of gravity. Fn = Mg*Cos35 = 549*Cos35 = 450 N. = Normal force.
*February 24, 2015*

**Physics**

d = 42m1[135o] - 34mi[270o] X = 42*Cos135 = -29.7 mi Y = 42*sin135 - 34*sin270 = 63.7 mi. Tan A = Y/X = 63.7/-29.7 = -2.14473 A = -65o = 65o N. of W. = 115o, CCW. d = Y/sin A = 63.7/sin 115 = 70.3 mi. d = V*t = 70.3 V = 70.3/t = 70.3/0.5h = 140.6 mi/h
*February 24, 2015*

**Physics**

Vp = -250m/s + i25m/s, Q2. Tan A = Y/X = 25/-250 = -0.10000 A = -5.71o = 5.71o N. of W.= 174.3o,CCW Vp = X/Cos A = -250/Cos(174.3)=251 m/s
*February 23, 2015*

**Physics**

V = Vo + a*t = 31m/s[30o] Vo - 4*4 = 31*Cos 30 + i31*sin 30 Vo - 16 = 26.8 + 15.5i Vo = 42.8 + 15.5i Tan A = Y/X = 15.5/42.8 = 0.36215 A = 19.91o Vo = 42.8/Cos 19.91 = 45.5m/s[19.9o] = Initial velocity.
*February 23, 2015*

**physics**

d = V*t = 2*0.3 km = 0.6 km 216 * t = 0.6 t = (0.6/216) h. t = (0.6/216)h * 3600s./h = 100 s. Note: The sound travels 600m(0.6km).
*February 23, 2015*

**Physics**

1. M*g = Wt. of roller. Fp = Mg*sin 30 = 2500 Mg = 2500/sin 30 = 5000 N. M = 5000/g = 5000/9.8 = 510.2 kg 2. Fn = Mg*Cos 30 = 5000*Cos 30 = 4330 N = Normal force = Force exerted by the surface.
*February 23, 2015*

**Physics**

sin23.3 = h/0.7 h = 0.7*sin 23.3 = 0.277 m. h = 0.5g*t^2 h = 0.277 m. g = 9.8 m/s^2 Solve for t.
*February 23, 2015*

**physics**

Incomplete, and too many errors.
*February 23, 2015*

**Math Vectors**

Vr = 400km/h[200o] + 100km/h[225o] X = 400*Cos200 + 100*Cos225 = -447 km/h Y = 400*sin200 + 100*sin225 = -208 km/h Tan Ar = Y/X = -208/-447 = 0.46532 Ar = 25o = Reference angle. A = 25 + 180 = 205o (Q3). V = X/Cos A = -447/Cos205 = 493 km/h. = Resultant velocity.
*February 22, 2015*

**Math**

a. Range = Vo^2*sin(2A)/g Range = 1200 Ft. Vo = 500 Ft./s. g = 32 Ft/s^2 Solve for A. b. V^2 = Vo^2 + 2g*h h = -Vo^2/2g Vo = 500 Ft./s. g = -32 Ft./s^2 Solve for h
*February 22, 2015*

**math**

Isaiah: X cards. x-x/9 = 560/2 8x/9 = 280 8x = 2520 X = 315 560 - 315 = 245 More than Andy.
*February 22, 2015*

**math**

X = 5 km/h Y = -3 km/h i. Speed = Sqrt(X^2+Y^2) = sqrt(5^2+3^2)= 5.83 km/h = 1.62 m/s. b. Tan A = Y/X = -3/5 = -0.60 A = -31o = 31o S. of E. d = 30m/Cos(-31) = 35 m. = Distance to cross. d = V*t = 35 m. t = 35/V = 35/1.62 = 21.6 s.
*February 21, 2015*

**Physics**

E = 58.0 Volts 1/Ct = 1/C1 + 1/C2 + 1/C3 1/Ct = 1/3.83 + 1/5.89 + 1/12.9 = 0.5084 Ct = 1.97 uF. Qt = Q1 = Q2 = Q3. Qt = Ct*E = 1.97 * 58 = 114.1 uC Q1 = C1*V1 = 114.1 uC V1 = 114.1/3.83 = 29.8 Volts.
*February 20, 2015*

**physics**

Mc = 14 kg = Mass of cart Md = Mass of dog food. d = 0.5a*t^2 = 2.30 m. 0.5a*2.55^2 = 2.3 3.25a = 2.3 a = 0.707 m/s^2. F = M*a M = F/a (Mc+Md) = F/a F = 12 N. a = 0.707 m/s^2 Solve for Md.
*February 20, 2015*

**math**

a. A = 4.1m * 2.2m = 9.02 m^2. A max = (4.1+0.01) * (2.2+0.01) = A min. = (4.1-0.01) * (2.2-0.01) = 8.957 m^2.
*February 20, 2015*

**Math**

X+X = 2x = Total bought. Red Tulips: x-24 Yellow: 4(x-24) 2x-24 Tulips remaining. x-24 + 4(x-24) = 2x-24 x-24 + 4x-96 = 2x-24 3x = 120-24 = 96 X = 32 2x = 64
*February 20, 2015*

**Algebra 2**

W^2 + 5W = 36 W^2 + 5W - 36 = 0
*February 20, 2015*

**physics**

Bill, please clarify your problem by adding the missing words.
*February 19, 2015*

**Physics**

Circumference = pi*Dia = 3.14 * 32.6cm = 102.4 cm = 1.024 m. Vo = 247rev/60s. * 1.024m/rev=4.22 m/s. V = 378rev/60s * 1.024m/rev = 6.45 m/s. V = Vo + a*t V = 6.45 m/s Vo = 4.22 m/s t = 6.54 s. Solve for a. d = Vo*t + 0.5a*t^2
*February 19, 2015*

**physics**

See previous post: Thu, 2-19-15, 6:56 PM.
*February 19, 2015*

**Math**

See previous post: Thu, 10-23-14, 6:36 PM.
*February 19, 2015*

**physics**

A shorter method: R1 = 100 Ohms R2 = 449 Ohms Ri = Internal resistance. V1 = I1*R1 = 4 * 100 = 400 Volts. V2 = I2*R2 = 1.09 * 449 = 489.41 Volts. Ri = (V2-V1)/(I1-I2) = (489.41-400)/(4-1.09) = 30.73 Ohms. E = I1*R1 + I1*Ri = 400 + 122.9 = 522.9 Volts.
*February 19, 2015*

**physics**

E = Battery terminal voltage(e.m.f.). Ri = Internal resistance. R1 = 100 Ohms. R2 = 449 Ohms. I*R1 + I*Ri = E 4*100 + 4*Ri = E Eq1: -E + 4Ri = -400 I*R2 + I*Ri = E 1.09*449 + 1.09*Ri = E Eq2: -E + 1.09Ri = -489.41 Subtract Eq2 from Eq1: Eq1: -E + 4Ri = -400 Eq2: -E + 1.09Ri...
*February 19, 2015*

**physics**

V = 4.93revs/1.47s * 6.28rad/rev = 21.1 rad/s = Angular velocity. V = Vo + a*t V = 21.1 rad/s. Vo = 0 t = 1.47 s. a = rad/s^2 Solve for a.
*February 19, 2015*

**Math 222**

g^2 - 6g - 55 = 0 -55 = 5*(-11) g+5= 0 g+(-11) = 0 g-11 = 0 (g+5)(g-11)= 0
*February 19, 2015*

**physics**

Vo = 20m/s[40o] Xo = 20*Cos40 = 15.32 m/s. Yo = 20*sin40 = 12.86 m/s. a. Y^2 = Yo^2 + 2g*h Y = 0 Yo = 12.86 m/s. g = -9.8 m/s^2 Solve for h. b. Y = Yo + g*Tr Y = 0 Yo = 12.86 m/s. g = -9.8 m/s^2. Solve for Tr.(Rise time or time to reach max. ht.) c. V = Xo + Yi = Xo + 0 = Xo d...
*February 19, 2015*

**physics**

a. V = Vo + a*t V = 25.1 m/s Vo = 0 t = 0.48 s. Solve for a. b. F = M*a M = 910 kg a = Value calculated in part a.
*February 19, 2015*

**Chemistry**

Human bodies maintain their balance (homeostasis) through a series of equilibria. An important equilibrium involves calcium ion because Ca2+ is important for muscle contractions in the heart as well as for strong bones. Bone is a complex tissue consisting of living cells and ...
*February 19, 2015*

**Chemistry**

A 500.0 mL sample of saturated nickel(II) phosphate solution was analyzed spectrophotometrically and found to contain 1.88 × 10-5 g of nickel. (a) Determine the molarity of the nickel(II) phosphate solution. (b) Calculate the solubility product constant, Ksp for nickel(...
*February 19, 2015*

**Chemistry**

The solubility of insoluble substances changes depending on the nature of the solution. Below are two solutions in which Cu(OH)2 is dissolved; in each case, the solubility of Cu(OH)2 in those solutions is not the same as it is in pure water. (a) For each Cu(OH)2 solution below...
*February 19, 2015*

**Physics**

See previous post: 9-16-13, 8:40 PM.
*February 18, 2015*

**physics**

T^2 = 4pi^2*(L/g) L/g = T^2/4pi^2 = 4.17^2/39.5 = 0.440 0.75/g = 0.44 g = 0.75/0.44 = 1.70 m/s^2. It is on the moon!
*February 18, 2015*

**physics**

a. T = 2min/60cycles = 120s/60cycles = 2s/cycles b. F = 1/T = 1cycle/2s. = 0.50 cycles/s. = 0.50 Hz.
*February 18, 2015*

**physical science**

T = 50km * 1h/5km * 60min/h = 600 min.
*February 18, 2015*

**physics**

Incomplete.
*February 18, 2015*

**Physical Science**

a. h = 0.5g*t^2 h = 20 m g = +9,8 m/s^2 Solve for t. b. V^2 = Vo^2 + 2g*h Vo = 0 g = +9.8 m/s^2 h = 20 m. Solve for V.
*February 17, 2015*

**physics**

M*g = 25 * 9.8 = 235 N. = Wt. of signal. a. Given: A1 = A2=20o. Therefore,T1=T2. -235i + T1*sin(180-20) + T2*sin20 = 0. Replace T2 with T1: -235i + T1*sin(180-20) + T1*sin20 = 0. 0.342T1 + 0.342T1 = 235i. 0.684i*T1 = 235i. T1 = 344N. = T2. b. T1*Cos(180-20) + T2*Cos30 = 0. -0....
*February 17, 2015*

**Physics**

Please clarify your problem: Does V mean Voltage or velocity? Did you give all of the INFO? If: V = Supply voltage. V1 = Voltage across R1. V2 = Voltage across R2. R1 and R2 connected in series. Then, V = V1 + V2
*February 17, 2015*

**Physics**

I = 7.0 mA V = 14.7 Volts. v1 = 3.5 Volts. V2 = 1.4 Volts. a. V3 = V-V1-V2 b. R3 = V3/I I = 0.007 Amps
*February 17, 2015*

**Physics**

See previous post.
*February 17, 2015*

**physical**

Vo = 18.7m/s[51o] Xo = 18.7*Cos51 = 11.8 m/s. Yo = 18.7*sin51 = 14.5 m/s. Y^2 = Yo^2 + 2g*h = 0 h = -Yo^2/2g = -14.5^2/-19.6 = 10.8 m. Y^2 = Yo^2 + 2g*d = 0 + 19.6*(10.8-2.5)= 162.68 Y = 12.8 m/s = Ver. component. V^2 = Xo^2 + Y^2 = 11.8^2 + 12.8^2 = 303.08 V = 17.4 m/s. = ...
*February 17, 2015*

**science**

a = (V-Vo)/t = Acceleration in Ft./s^2 V = 20 Ft/s. Vo = 5 Ft/s.
*February 17, 2015*

**physics**

V = sgrt(X^2+Y^2)
*February 17, 2015*

**physics**

V = 5m/s[30o] Vy = 5*sin30 = 2.5 m/s
*February 17, 2015*

**Algebra**

Eq1: x + y = -8 Eq2: x - y = 4 Sum: 2x = -4 X = -2 In Eq1, replace x with -2: -2 + y = -8 Y = -6.
*February 16, 2015*

**physics**

M*g = 27 * 9.8 = 264.6 N. = Wt. of the lawnmower. Fn = 264.6 + Fap*sin36=264.6 + 0.588Fap Fk = u*Fn = 0.66*(264.6+0.588Fap) = 174.64 + 0.388Fap (Fx-Fk) = M*a (Fap*Cos36-(174.64+0.388Fap) = M*a (0.81Fap-174.64-0.388Fap = M*0 0.42Fap - 174.64 = 0 0.42Fap = 174.64 Fap = 416 N. = ...
*February 16, 2015*

**Physics**

W = Mg * d = 2.80*9.8 * (35-10) = 686 J.
*February 16, 2015*

**Physics**

a = (V-Vo)/t =(250-0)/12 =
*February 16, 2015*

**Physics**

a. T^2 = 4pi^2(L/g)=4*3.14^2(0.76/9.8) = 3.06 T = 1.75 s.
*February 15, 2015*

**physical science**

a. h = 0.5g*t^2 = 4.9*4^2 = 78.4 m b. h = 0.5g*t^2 h = 103 m. g = 9.8 m/s^2 Solve for t.
*February 15, 2015*

**Physics**

Incomplete.
*February 15, 2015*

**Business math**

Ordinary interest assumes a business year of 360 days. Exact interest uses 365 days per year. a. I = Po*r*T = 4400*(0.1025/360)*135 = $169.125 b. 4400 + 169.125 = $4569.13
*February 15, 2015*

**math**

d = 120km/h * 2.6667h=Distance traveled. L = d/4 = Liters of fuel used. Cost = $59 * L =
*February 15, 2015*

**science**

V^2 = Vo^2 + 2g*h Vo = 0 g = +9.8 m/s^2 h = 50 m. Solve for V.
*February 15, 2015*