Saturday

October 10, 2015
Total # Posts: 11,267

**physics**

L = V/F V = L*F = 5.8 * 1.15 = 6.67 m/s. Note: The distance between crests is the wavelength(L).
*December 5, 2014*

**physics**

T = d/V = 1340/457 = 2.93 s.
*December 5, 2014*

**Quantitative Business Analysis**

See previous post.
*December 5, 2014*

**Quantitative Business Analysis**

I = Po*r*t I = $9800 r = 0.08 t = 1 yr. Solve Po, the amount borrowed.
*December 5, 2014*

**physics**

Eq1: F1 + F2 = 376 N. Eq2: F1 - F2 = 162 N. Sum: 2F1 = 538 F1 = 269 N. In Eq1, replace F1 with 269: 269 + F2 = 376 F2 = 376 - 269 = 107 N.
*December 4, 2014*

**physics help PLZ!!**

Fx = -23.3 N. Fy = 409.5 N. 2nd Quadrant. Tan Ar = Fy/Fx = 409.5/-23.3 = -17.57511 Ar = -86.7o = Reference angle(Q4). A = -86.7 + 180 = 93.3o, CCW(Q2) = Direction.
*December 4, 2014*

**Physics**

d = V*T d = 2 * 3.84*10^8 m. V = 3*10^8 m/s. = Speed of light. Solve for T.
*December 4, 2014*

**physics**

X = -116.8 + 93.5 = -23.3 N. Y = -248.6 + 658.1 = 409.5 N. Tan Ar = Y/X = 409.5/-23.3 = -17.57511 Ar = -86.7o = Reference angle. A = -86.7 + 180 = 93.3o, CCW. Fr = Y/sin A = 409.5/sin93.3 = 410 N. [93.3o]. = Resultant force. Fx = 410*Cos93.3 = -23.61 N = 23.61 N., Left(West).
*December 4, 2014*

**Math**

110 = 30*3 + 20 Y = mx + b Y = 30x + 20 (Intercept Form) m = 30 = Slope. b = 20 = Y-intercept. Y = 30x + 20 30x - y = -20 (Standard Form). m = -A/B = -30/-1 = 30 = Slope. Y-Intercept = C/B = -20/-1 = 20. I hope this is what you want.
*December 4, 2014*

**math**

Eq1: 8x - 4xy = 3 Eq2: -2x - 5y = 10 In Eq2, solve for X: -2x - 5y = 10 -2x = 5y + 10 X = -5y/2 - 5 In Eq1, replace X with -5y/2 - 5: 8(-5y/2 - 5) - 4y(-5y/2 - 5) = 3 -20y - 40 + 10y^2 + 20y = 3 10y^2 - 40 = 3 Divide both sides by 10: y^2 - 4 = 0.30 y^2 = 0.30 + 4 = 4.30 Y = -...
*December 4, 2014*

**Math Help!**

1. (60/75)*100% = 80 %. 80% - 100% = -20% = 20% Decrease. 2. (160/100)*100% = 160% 160% - 100% = 60% Increase. 3. %Cost = 100% - 10% = 90% Cost = 0.90 * 57.63 = $51.87 4. Same procedure as #3.
*December 4, 2014*

**math**

Scale: 1/2 in = 1Ft. = 12 in Ratio = (1/2)in/12in = 1/24 L = 24 * 1Ft = 24 Ft. W = 24 * (7.5/12)Ft = 15 Ft. Note: I assumed you mean 7 1/2 in wide.
*December 4, 2014*

**physics**

See previous post: Thu 12-4-14, 9:49 AM.
*December 4, 2014*

**physics**

M * g = 2970 N. M = 90 kg Solve for g.
*December 4, 2014*

**Economics calculation help**

Thanks!
*December 4, 2014*

**Can Ms.Sue Help?**

Please
*December 4, 2014*

**Economics calculation help**

Kelly total income last year was $24,000, but she could deduct $12,000 for various reasons. How can I calculate; If she had to pay 15% of her taxable income in federal income tax, what was her total tax payment? So I did 12,000 x .15 and got 1800, but I don't know if thats...
*December 4, 2014*

**Math**

Your original Eq is the Vertex form of a Y-Parabola that opens downward. I am assuming you want to solve for X. Standard form: Y = -20/27(x^2 + 3x + 2.25) Y = (-20/27)x^2 -(60/27)x - 5/3 Y = (-20/27)x^2 - (20/9)x - 5/3 Use Quadratic Formula. X = -1.5, and -1.5(Double solution...
*December 4, 2014*

**Economics help**

Thanks
*December 4, 2014*

**Economics help **

An elderly man receives free prescription drugs from a veterans' hospital. So what kind of a good is this, like is this a privately owned service or publicly own service?
*December 4, 2014*

**physics**

ho = 186 m. Vo = 64.8m/s[59o] Xo = 64.8*Cos59 = 33.37 m/s Yo = 64.8*sin59 = 55.54 m/s Tr = -Yo/g = -55.54/-9.8 = 5.67 s. = Rise time. h = ho + (-Yo^2)/2g h = 186 + -(55.54^2)/-19.6 = 343.4 m. Above gnd. h = 0.5g*t^2 = 343.4 m. 4.9t^2 = 343.4 t^2 = 70.1 Tf = 8.37 s. = Fall time...
*December 4, 2014*

**Geomatry**

Y = (x^2+x-2)/(x^2-x-6) Y = (x+2)(x-1)/(x+2)(x-3) = (x-1)/(x-3) a. Domain = All real values of X except 3. Note: 3 gives a denominator of zero which makes the fraction undefined. f. When Y = 0,(x-1) = 0 x-1 = 0, X = 1. X-Intercept = 1.
*December 4, 2014*

**physics**

See previous post: Wed, 12-3-14, 8:20 AM
*December 4, 2014*

**physics**

a. KE = M*V^2/2 M = 0.59 kg V = 1.5 m/s Solve for KE. b. KE = M*V^2/2 KE = 7.0 J M = 0.59 kg Solve for V.
*December 3, 2014*

**physics**

d = V*t 2*76.5 = 1500t Solve for t.
*December 3, 2014*

**Science**

V = 5m/2s = 2.5 m/s. KE = M*V^2/2 = 1539*2.5^2/2 = 4809 J.
*December 3, 2014*

**Algebra 1**

Y/X = 24/8 = 3 = K(Y/X is constant). Y/10 = 3 Y = 30.
*December 3, 2014*

**Physics**

a. h = 0.5g*T^2 h = 18 m. g = 9.8 m/s^2 T = Fall time in s. Solve for T. d = Xo*T d = 18 m. Xo = hor. speed in m/s. T = Time calculated in part a. Solve for Xo. b. Y^2 = Yo + 2g*h Y = Ver. component of Speed just before it hits the gnd. Yo = 0 = Ver. component of initial speed...
*December 3, 2014*

**physics**

a. Vo = 0 V = 12 m/s. t = 6 s. V = Vo + a*t Solve for a. b. V = a*t a = (Use value calculated in part a). t = 10 s. Solve for V.
*December 3, 2014*

**physics**

Vo = 30 m/s. V = 0 t = 3 s. V = Vo + a*t Solve for a.
*December 3, 2014*

**Math**

See previous post: Wed, 12-3-14, 12:26 AM.
*December 3, 2014*

**Math**

d1 = 5mi/h[350o] * 2h = 10mi[350o] d2 = 12mi/h[40o] * 2h = 24mi[40o] d3 = 10mi/h[180] * 5h = 50mi[180] X = 10*Cos350 + 24*Cos40 + 50*Cos180 = -21.8 Miles. Y = 10*sin350 + 24*sin40 + 50*sin180 = 13.7 Miles. d = d1+d2+d3 = X + Yi=-21.8 + 13.7i,Q2. Tan Ar = Y/X = 13.7/-21.8 = -0....
*December 3, 2014*

**science**

V^2 = Vo^2 + 2a*d = 20^2 13^2 + 2a*1250 = 400 2500a = 400-169 = 231 a = 0.0924 m/s^2 t = (V-Vo)/a = (20-13)/0.0924 = 75.8 s.
*December 2, 2014*

**Math**

Yes.
*December 2, 2014*

**Math**

Tr = -Vo/g = -40/-32 = 1.25 s. = Rise time or time to reach max ht. h = -16*1.25^2 + 40*1.25 + 70 = 95 Ft. h = 0.5g*t^2 = 95 16t^2 = 95 t^2 = 5.94 Tf = 2.44 s. = Fall time. Tr+Tf = 1.25 + 2.44 = 3.69 s. = Time to reach gnd.
*December 2, 2014*

**mathematics of investment**

P = Po + Po*r*t = $3,200 Po + Po*0.055*2.5 = 3200 Solve for Po, the initial principal or investment.
*December 2, 2014*

**Math**

x = (3y+1)/6 Multiply both sides by 6: 6x = 3y + 1 3y = 6x - 1 Divide both sides by 3: Y = (6x-1)/3 = 2x - 1/3
*December 2, 2014*

**Physics**

M*g = 10.9kg * 9.8N./kg = 106.82 N. = Wt of the box. Fp = 106.82*sin38 = 65.8 N. = Force parallel to the incline. Fn = 106.82*Cos38 = 84.2 N. = Normal force. Fk = u*Fn = 1 * 84.2 = 84.2 N. = Force of kinetic friction. Note: If the coefficient of kinetic friction is 1, the box ...
*December 2, 2014*

**Physics**

M*g = 284kg * 9.8N./kg = 2783.2 N. = Wt. of the crate = Normal force(Fn). Fk = u*Fn = 0.513 * 2783.2 = 1427.8 N. = Force of kinetic friction. Fap-Fk = M*a Fap-1427.8 = M*0 = 0 Fap = 1427.8 N. = Force applied. Power = Fap * V = 1427.8 * 7.2 = 10,280 J/s. = 10,280 Watts.
*December 2, 2014*

**physics-finding velocity**

V^2 = Vo^2 + 2g*h = 0 + 19.6*0.65 = 12.74 V = 3.57 m/s.
*December 1, 2014*

**Physics**

a. Correct b. h = g*t^2/2 = 4.5 4.9*t^2 = 4.5 t^2 = 0.9184 t = 0.958 s. c. V = Vo + g*t = 0 + 9.8*0.958 = 9.39 m/s. or V^2 = Vo^2 + 2g*d = 0 + 19.6*4.5 = 88.2 V = 9.39 m/s. or V^2 = 0 + (-19.6*(0-4.5) = 88.2 V = 9.39 m/.s.
*December 1, 2014*

**physics**

Fr = (Vs+Vr)/(Vs-Vp) * Fp Fr = (340+0)/(340-163) * 1730 Hz = 3323 Hz. = Freq. heard by the receiver or listener.
*December 1, 2014*

**Physics**

db = 10*Log(I1/I2) = 10*Log(110/330) = -4.77 I1 = 4.77 db below I2.
*December 1, 2014*

**physics**

Vo = 0 V = 41 m/s. t = 5.3 s. M = 87 kg a = (V-Vo)/t Fx = M*a Fy = M*g F = Sqrt(Fx^2+Fy^2) = Total force.
*November 30, 2014*

**physics**

a = (V-Vo)/t = (0.37-0)/12 = 0.0308 (Fx-Fk) = M*a (127*Cos40-Fk) = 35 * 0.0308 97.3 - Fk = 1.079 -Fk = 1.079 - 97.3 = -96.2 Fk = 96.2 N. = Force of kinetic friction.
*November 30, 2014*

**Math**

1. P = Po + Po*r*t P = 100,000 + 100,000*0.1*5 = 150,000
*November 30, 2014*

**math**

Vo = 90Ft/s[60o] Xo = 90*cos60 = 45 Ft/s Yo = 90*sin60 = 77.9 Ft/s ho = 5 Ft. g = -32 Ft/s^2 t = 3 s. h = ho + Yo*t + 0.5g*t^2
*November 30, 2014*

**physics**

X = 10 km/h Y = 2 km/h V^2 = X^2 + Y^2 = 10^2 + 2^2 = 104 V = 10.20 m/s.
*November 30, 2014*

**physics**

h max = R/2 = 150m/2 = 75 m. h max = 0.5g*t^2 = 75 4.9*t^2 = 75 t^2 = 15.31 Tf = 3.91 s. = Fall time. Tr = Tf = 3.91 s. = Rise time. V = Vo + g*t = 0 @ max ht. Vo = -g*t = -(-9.8*3.91) = 38.34 m/s. = Initial velocity. R = Vo^2*sin(2A)/g = 100 m. 38.34^2*sin(2A)/9.8 = 100 150*...
*November 30, 2014*

**math**

Incomplete.
*November 30, 2014*

**physics**

See previous post: Sat, 11-29-14, 11:06 PM.
*November 30, 2014*

**physics**

d = Vo*t + 0.5a*t^2 = 40*15 + 8*15^2/2 = 1500 m.
*November 30, 2014*

**physics**

Vo = 50mi/h * 1600m/mi * 1h/3600s. = 22.22 m/s. V = Vo + a*t = 0 When stopped. t = -Vo/a = -22.22/-7=3.17 s. To stop.
*November 30, 2014*

**trigonometry**

1. Va=(1/2)rev/2min * 6.28rad/rev= 1.57 rad/min. 2 thru 6. Same procedure as #1.
*November 30, 2014*

**physics**

a = V-V0)/t = (60-0)/7.2 = 8.33 m/s^2. F = M*a
*November 29, 2014*

**Math (Expectation)**

Robyn: M = 2mi/day * d days = 2*d = 2d.
*November 29, 2014*

**physics**

M*g = 20 * 9.8 = 196 N.=Wt. of suitcase. a. a = Fx/M = 50*cos30/20 = 2.17 m/s^2. b. Fn = 196 - 50*sin30 = 171 N.=Normal force = Force exerted on the bag by the floor.
*November 29, 2014*

**physics**

Output = 0.9333 * 75kW
*November 29, 2014*

**two step equation-fraction**

(4+m)/3 = 5/6 Multiply both sides by 6: 2(4+m) = 5 Multiply both terms inside the parenthesis by 2: 8 + 2m = 5 Subtract 8 from both sides: 8-8 + 2m = 5-8 0 + 2m = -3 2m = -3 Divide both sides by 2: m = -3/2 = -1 1/2.
*November 29, 2014*

**math**

See Related Questions: Tue,11-12-13, 9:28 AM.
*November 29, 2014*

**physics**

d = 44 Ft. g = 32 Ft/s^2 u = 0.50? Vo = ? a = u*g = 0.50 * (-32) = -16 Ft/s^2 V^2 = Vo^2 + 2a*d = 0 Vo^2 = -2a*d = -(-32*44) = 1408 Vo = 37.5 Ft/s.
*November 29, 2014*

**physics**

2m/s * 33s/3.5rev = 18.857 m/rev = Circumference(C). C = pi*2r = 18.857 m. 6.28r = 18.857 r = 3 m.
*November 29, 2014*

**maths**

Tan A = Y/X = (22-1.5)/20.5 = 20.5/20.5 = 1. A = 45o.
*November 29, 2014*

**math**

5/2 - 3/8 * Log3 = 2.321
*November 29, 2014*

**Pyhsics**

A. M*1.17g = 34.9 N. M*1.17*9.8 = 34.9 M*11.47 = 34.9 M = 3.04 kg B. 3.04 * a = 19.2 N. a = 6.31 m/s^2 on planet X. Note: It is the free-fall acceleration that changes; the mass remains constant.
*November 28, 2014*

**math**

Post it.
*November 28, 2014*

**Physics**

a. W = F*d = 453*Cos37 * d = 4820 J. d = 13.3 m. b. Fx-Fk = M*a 453*Cos37-Fk = M*0 = 0 Fk = 453*Cos37 = 361.8 N. = Force of kinetic friction. c. W = Fk*d = 361.8 * 13.3 = 4812 J. d. W = M*V^2/2 = 4820 J. M*7.82^2/2 = 4820 M*30.58 = 4820 M = 157.6 kg = Mass of the crate. M*g = ...
*November 26, 2014*

**AP Physics**

What is the question?
*November 25, 2014*

**business math**

I=Po*r*t = 3600*(0.088/365)*207=$179.66 = Penalty.
*November 25, 2014*

**MAT201 Basic Statistics**

Incomplete.
*November 24, 2014*

**Pre algebra**

X = Minutes used. Y = T0tal cost in Dollars. (X,Y), (20,48), (35,54), (40,56). m = (Y2-Y1)/(X2-X1)=(54-48)/(35-20) = 0.40 = Slope. (20,48) Y = mX + b = 48 0.4*20 + b = 48 b = 40 Eq: Y = 0.4X + 40
*November 24, 2014*

**Math with business apps**

P = Po * (1+r)^n r = (3%/12)/100% = 0.0025 = Monthly % rate expressed as a decimal. n = 12Comp./yr * 15 yrs. = 180 Compounding periods. Solve for P. I = P-Po
*November 24, 2014*

**Math with business apps**

See previous post: Mon,11-24-14, 6:31 PM
*November 24, 2014*

**MATH!!**

P = Po * (1+r)^n r = (4%/4)/100% = 0.01 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs. = 20 Compounding periods. Solve for P. 2nd investment = P + $500 @ 5% for 5 yrs.
*November 24, 2014*

**math**

Mr. Beach: X min. Ms. Johnson: 2x min. Mrs. Rodriguez: (X+10) min. x+10 = 35 min. X = 25 min. 2x = 50 min. Total = 35 + 25 + 50 = 110 Min.
*November 24, 2014*

**Math**

P = Po*(1+r)^n r = (3%/12)/100% = 0.0025 = Monthly % rate expressed as a decimal. n = 12Comp./yr. * 15yrs. = 180 Compounding periods. Solve for P. I = P-Po
*November 24, 2014*

**Math**

P = Po * (1+r)^n r = (6.5%/12)/100% = 0.00542 = Monthly % rate expressed as a decimal. n = 1Comp./mo * 18mo = 18 Compounding periods. Solve for P.
*November 24, 2014*

**math**

B: X min. A: (X+36) min. A/B = (x+36)/x = 6/5 5x + 180 = 6x 5x - 6x = -180 -X = -180 X = 180 min. X+36 = 180+36 = 216 min.
*November 24, 2014*

**physics**

See previous post.
*November 23, 2014*

**physics**

a = (V^2-Vo^2)/2d = (0-(22.9^2)/149.2 = -3.51 m/s^2. F = m*a =1949.1 * (-3.51) = -6851 N. Note: The negative sign means that the force opposes the motion.
*November 23, 2014*

**Physics**

See previous post: Sun,11-23-14, 12:08 AM.
*November 23, 2014*

**Physics**

False.
*November 23, 2014*

**Physics**

Vo = 9.2m/s[47o] Xo = 9.2*Cos47 = 6.27 m/s. Yo = 9.2*sin47 = 6.73 m/s. a. Y = Yo + g*Tr = 0 @ max ht. Tr = -Yo/g = -6.73/-9.8 = 0.687 s. = Rise time or time to reach max ht. b. h max = ho + Yo*Tr + 0.5g*Tr^2 = 6.6 + 6.73*0.687 - 4.9*0.687^2 = 8.91 m. Above gnd. c. h = 0.5g*Tf^...
*November 23, 2014*

**Physics**

Vo = 215km/h = 215,000m/3600s.=59.72 m/s V = Vo + a*t = 0. Vo + a*t = 0 Solve for a; it should be negative.
*November 23, 2014*

**Physics**

Range = Vo^2*sin(2A)/g = 16 m. Vo^2*sin(110)/9.8 = 16 0.09589Vo^2 = 16 Vo^2 = 166.863 Vo = 12.92 m/s.
*November 23, 2014*

**capacitors**

Not enough INFO.
*November 23, 2014*

**physics**

Tf = 4/2 = 2 s. = Fall time. h = 0.5g*Tf^2 = 4.9 * 2^2 = 19.6 m.
*November 23, 2014*

**Physics**

V1 = a*t1 = 0.6rad/s^2 * 10s. = 6 rad/s. d1 = 0.5a*t1^2 = 0.3*10^2 = 30 Radians. d2=V1*t2 = 6rad/s. * 20s. = 120 Rad1ans V2 = V1 + a*t3 = 0 6 + a*10 = 0 10a = -6 a = -0.60 m/s^2 V2^2 = V1^2 + 2a*d = 0 d2 = -(V1^2)/2a = -(6^2)/-1.2 = 30 Rad. V=(d1+d2)/(t1+t2+t3)=(120+30)/(10+20...
*November 23, 2014*

**physics**

See Related Questions: Tue, 9-2-14, 11:13 AM.
*November 22, 2014*

**physics**

See previous post.
*November 22, 2014*

**physics**

M*g = 70.4kg * 9.8N/kg = 689.9 N. = Wt. of skier. Fp = 689.9*sin36.8 = 413.3 N. = Force parallel to the incline. Fn = 689.9*Cos36.8 = 552.4 N. = Normal force = Force perpendicular to the incline. Fk = u*Fn = 0.14 * 552.4 = 77.34 N. = Force of kinetic friction. a = (Fp-Fk)/M...
*November 22, 2014*

**physics**

a = (V-Vo)/t = (66-0)/4.5 = 14.67 m/s^2. F = M*a
*November 22, 2014*

**Physics**

A. X = 1.5 m/s Y = 2 m/s. TanA = Y/X = 2/1.5 = 1.33333 A = 53o, CCW = 90-53 = 37o E. of N. or [N37E].
*November 22, 2014*

**Physics**

M*g = 4kg * 9.8 N./kg = 39.2 N. = Wt. of the bundle. KE = M*Vo^2/2 = 128 J. 4*Vo^2/2 = 128 Vo^2 = 64 Vo = 8 m/s = Initial velocity. a = u*g = 0.3 * (-9.8) = -2.94 m/s^2. V^2 = Vo^2 + 2a*d = 0 @ max ht. Vo^2 + 2a*d = 0. Solve for d.
*November 22, 2014*

**physics**

The position versus time for a certain object moving along the x-axis is shown. The object’s initial position is −2 m. Find the instantaneous velocity at 6 s. Answer in units of m/s
*November 21, 2014*

**Math**

P1 = Po*(1+r)^n. Compounded annually. r = 12%/100% = 0.12 = Annual % rate expressed as a decimal. n = 1Comp./yr. * 4yrs. = 4 Compounding periods. P1 = 6,000*(1.12)^4 = $9441.12 P2 = Po*(1+r)^n. Compounded quarterly. r = (12%/4)/100% = 0.03 = Quarterly % rate. n = 4Comp./yr. * ...
*November 21, 2014*

**physic**

Vo = 55m/s[30o] Xo = 55*Cos30 = 47.63 m/s Yo = 55*sin30 = 27.5 m/s. a. Y = Yo + g*Tr = 0 @ max ht. Tr=-Yo/g = -27.5/-9.8 = 2.806 s.=Rise time. Tf = Tr = 2.806 s. = Fall time. Tr+Tf = 2.806 + 2.806 = 5.61 = Time in air. b. Dx = Xo*(Tr+Tf) = 47.63m/s * 5.61s = 267.3 m. from base...
*November 21, 2014*

**physics**

a. Correct The last sentence in your problem is incomplete.
*November 21, 2014*

**MATH**

2AB + AB1 = 2AB + 1AB = 3AB.
*November 21, 2014*

**math**

Incomplete.
*November 21, 2014*