Sunday
January 22, 2017

Posts by Henry

Total # Posts: 13,047

Math
A = X Degrees. B = (4x+20) Degrees. x + (4x+20) = 90o. X = ?
November 14, 2015

Math
Correction: Math-99Henry. should be Math Henry.
November 13, 2015

High school /physic
Vf = Vo + g*t. Vf^2 = Vo^2 + 2g*h.
November 13, 2015

Math
See previous post: Thu, 11-12-15, 11:06 PM.
November 13, 2015

Math
P = Income-Expense=20x-((20x/2)+18)=200. 20x - (10x+18) = 200. 20x - 10x - 18 = 200. 10x = 218. X = 21.8 or 22 Copies.
November 13, 2015

University of North Dakota
Correction: Change 49.5 to 495.
November 13, 2015

University of North Dakota
Acc. #1: Po1 = $X @ 9.5%. Acc. #2: Po2 = $(33,000-X) @ 1.5%. Po1*r1*t = Po2*r2*t. X*0.095*1 = (33,000-X)*0.015*1. 0.095x = 49.5 - 0.015x. 0.11x = 495. X = $4500. 33000-X = 33000-4500 == $28,500.
November 13, 2015

Math
d = 16t^2 = 1551 Ft. t^2 = 96.9375. t = 9.8 s. V = 64h?? 62
November 12, 2015

math
V = 0.3125 * 18 * 15 = in^3. Wt. = V*D = V * 0.698 = The surface area(As) is the area of the 6 sides: As = 2*W*h + 2*L*h + 2*L*W. L = 18 1n. W = 15 in. h = 0.3125 in.
November 12, 2015

Math homework
6/6-1/6 = 5/6 = Remainder. 5/6-2/5 = 25/30-12/30 = 13/30 Left.
November 12, 2015

algebra
Y = x^2+5x-36 = 0 -36 = -4*9, -4+9 = 5 = B. (x-4)(x+9) = 0.
November 12, 2015

PHYSICS
D = 350rev/60s * 0.64s * 6.28rad/rev =
November 12, 2015

PHYSICS
Do you think we might need to know the angles?
November 12, 2015

Physics
V^2 = Vo^2 + 2a*d = 0. a = -(Vo^2)/2d. It will be negative.
November 11, 2015

Physics
C = pi*2r = 3.14 * 2*0.98 = 6.15 m. 0.44rev/s. * 6.15m/rev = 2.71 m/s. = Tangential speed.
November 11, 2015

physics
Wo = M*g = 2 * 9.8 = 19.6 N. Fn = 19.6-20*sin20 = Normal force. Fk = u*Fn = Force of kinetic friction. Net force = 20*Cos20 - Fk.
November 11, 2015

Pre-Alegebra
3. Irrational. 4. D^2 = 15^2 + 8^2, D = 17. 5. You can test each choice by taking the cube root or raising it to the 1/3 power: 100^(1/3) = 4.64 125^(1/3) = 5 = A perfect cube. 6. Whole number/Integer. 7. 9/10. 8. Sqrt(35) = 5.92 In. Cut the 6-in. piece. 10. Riley: Sqrt(36) = ...
November 11, 2015

Physics
V^2 = Vo^2 + 2g*h. Vo = 0. g = 9.8 m/s^2. h = 2.1 m. V = ?
November 11, 2015

physics
Vf^2 = Vo^2 + 2g*h = 0. h = -Vo^2/2g + 1.5 = Meters above gnd. Vo = 20 m/s. g = -9.8 m/s^2.
November 11, 2015

nwfsc
V = I * R = 20 * 7 = 140 Volts. R = V/I = 140/14 = 10 Ohms.
November 10, 2015

Math
Libby: $60. Jess: 3/4 * 60 = $45. Stephanie: 1/3 * 45 = $15. Total:
November 10, 2015

Math
P(1, 2). Slope = 3. (1, 2), (x, y). m = (y-2)/(x-1) = 3. (y-2) = 3(x-1).
November 9, 2015

math
I've solved several of your problems. Where is the end?
November 9, 2015

math
Same procedure as your previous post.
November 9, 2015

math
I = Po*r*t = $1200. r = (18%/12)/100% = 0.015 = Monthly % rate expressed as a decimal. t = 1 Mo. Po*0.015*1 = 1200. Po = $80,000.
November 9, 2015

math
P = Po + Po*r*t = 2Po. Po + Po*0.1*t = 2Po Divide by Po: 1 + 0.1t = 2. 0.1t = 1. t = 10 Years.
November 9, 2015

math
I = Po*r*t. I = $3600. Po = $20,000. r = 0.12. t = ?.
November 9, 2015

math
P = Po + Po*r*t.
November 9, 2015

Physics
a. Vo = 60000m/3600s. = 16.7 m/s. Vf = 40000m./3600s. = 11.1 m/s. b. a = (Vf-Vo)/t = (11.1-16.7)/8 = -0.699 m/s^2.
November 9, 2015

AP Physics
Wb = M*g = 55 * 9.8 = 539 N. Fp = 539*sin40 = 347 N. = Force parallel to the ramp. Fn = 539*Cos40 = 413 N. = Normal force. Fp-Fk = M*a. 347-Fk = M*0 = 0. Fk = 347 N. = Force of kinetic friction. u = Fk/Fn.
November 8, 2015

physics
180N[W60oN] + [140N[90o] + 180N[E60oN]+ Ws = 0. Ws=-(-180*Cos60+180*sin60+140i+180*Cos60 +180*sin60) = -(155.9i+140i+155.9i) = -452i = -452 = 452 N. Downward. = Wt. of the sign. The horizontal components cancelled: 180*Cos60 - 180*Cos60 = 0.
November 8, 2015

physics
a = M1/M2 * a1 = 2.9/6.2 * 2.7 = 1.26 m/s^2.
November 8, 2015

Science
Mass = 200Lbs * 0.454kg/Lb = 90.8 kg. Wb = M*g = 90.8 * 9.8 = 889.84 N. = Normal force(Fn). a = 10Ft/s^2 * 1m/3.3Ft = 3.03 m/s^2. Fk = u*Fn = 0.25 * 889.84 = 222.5 N. = Force of kinetic friction. Fap-Fk = M*a. Fap = Applied or required force. Fap = ?.
November 8, 2015

physics
See previous pose: Sat, 11-7 15, 6:23 PM.
November 8, 2015

physics
F1 + F2 + F3 = 0. F3 = -(F1+F2) F3 = -(18[E60oN]+6.5[E45oS]) = -(18*Cos60+18*sin60 +6.5*Cos45+6.5*sin45 = -(9+15.6i + 4.6-4.6i) = -(13.6+11i) = -13.6 - 11i = 21.6N.[39o] Below the negative X-axis. f4
November 8, 2015

ap physics
Incomplete.
November 8, 2015

physics
Vf^2 = Vo^2 + 2a*d.
November 7, 2015

physics
V = Vo + a*t = 41.1m/s[26.5o]. 3.87[40.3o] + a*8.35 = 41.1[26.5]. 2.95+2.50i + a*8.35 = 36.8 + 18.3i. a*8.35 = 36.8 + 18.3i - 2.95 - 2.50i. a*8.35 = 33.9 + 15.8i = 37.4m/s[25o]. a = 4.48m/s^2[25o], CCW from +X-axis.
November 7, 2015

physics
Vf = Vo + a*t = 59.1m/s[43o]. Vo + 2.1[31.7o]*7.75 = 59.1[43]. Vo + 16.3[31.7o = 59.1*Cos43+59.1*sin43. Vo+16.3*Cos31.7+16.3*sin31.7=43.2+40.3i. Vo + 13.9 + 8.6i = 43.2 + 40.3i. Vo=43.2 + 40.3i - 13.9 - 8.6i=29.3+31.7i Vo = 43.2m/s[47.3o], CCW from +X-axis.
November 7, 2015

physics
P = E*I = 1.0 W. 1.58I = 1.0 I = 0.633A. A*h = 1. 0.633*h = 1. h = 1.58 Hours.
November 7, 2015

Calculus
Find the Absolute Maximum and Absolute Minimum of f on (0,3]. f(x)=(x^3-4x^2+7x)/x Multiple choice question I know the minimum is (2,3) but the maximum is either nothing or (0,7) but I can't tell which one
November 7, 2015

science
Velocity in kg/h???.
November 7, 2015

physics
Wc = M*g = 330 * 9.8 = 3234 N. = Normal force, Fn. Fap = 410 + 240 = 650 N. = Force applied. Fap-Fk = M*a. Fap-Fk = M*0 = 0. Fk = Fap = 650 N. = Force of kinetic friction. u = Fk/Fn.
November 6, 2015

Physics
V = Vo + g*T. Vo = 0. g = 10 m/s^2. h = ho - 0.5g*Tf^2 = 0. 5Tf^2 = 80. Tf^2 = 16. Tf = 4 s. = Fall time. Use T in the range of 0 to 4 seconds. (T,V,h). (0,0,80). (1,10,75). (2,20,60). (3,30,35). (4,40,0).
November 6, 2015

math
1. 6x4 in., P = 2*6 + 2*4 = 20 in. 2. 6*2 in., P = 2*6 + 2*2 = 16 in. 3. 4x2 in., P = 2*4 + 2*2 = 12 in. =
November 5, 2015

Physics
Units of time are seconds, minutes, and hours. Vf = Vo + a*t = 0. t = -Vo/a = -22/-6.1 = 3.61 s.
November 5, 2015

Precalc
a. P = Po(1+r)^n Po = $60,000. r = (4%/4)/100% = 0.01 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 10yrs. = 40 Compounding periods. P = ? c. Same procedure as a.
November 5, 2015

physics
Vf = Vo + a*t = 3 + 1*5 = 8 m/s. d = Vo*t + 0.5a*t^2.
November 5, 2015

universitu
See Related Questions: Sun, 2-17-13, 5:09 AM.
November 5, 2015

Calculus
use tangent line approximation (linear approximation) to estimate The cube root of 1234 to 3 decimal places. Hint: the equation should be y=f'(x0)(x-x0)+f(x0) 11^3=1331 can be easily computed using binomial theorem. I used linear approximation and got 10.733, but it is not...
November 4, 2015

Physics
a. 0.5g*t^2 = 4780. 4.9t^2 = 4780. t^2 = 975.5 t = 31.2 s. Dx = 175m/s * 31.2s = 5465.8 m.
November 3, 2015

math
2. X = -30 km/h = velocity of the wind. Y = -295 km/h.=velocity of the aircraft. Q3. tan A = y/x = -295/-30 = 9.83333. A = 84.2o S. of W. = direction. Vr = y/sin A=-295/-sin84.2 = 296.5 km/h.
November 3, 2015

physics
Vf^2 = Vo^2 + 2g*h. g = 9.8 m/s^2.
November 3, 2015

Science
10cm3 * 10.5g/cm^3 = wt. in grams. mass = g/1000 = kilograms.
November 2, 2015

physics
140rev/60s * 20s =
November 2, 2015

science
T1*Cos26.5 - T2*Cos49.5 = 0 T1*Cos26.5 = T2*co49.5. T1 = 0.73T2. T1*sin26.5 + T2*sin49.5 = 155. Replace T1 with 0.73T2: 0.73T2*sin26.5 + T2*sin49.5 = 155. 0.324T2 + 0.760T2 = 155. 1.084T2 = 155. T2 = 143 N. T1 = 0.73*143 = 104 N.
November 1, 2015

Physics
Work = F*d = 23*Cos39 * 8 =
November 1, 2015

physics
Fs = M*g = 14 * 9.8 = 137 N. Fp = 137*sin 0 = 0 = Force parallel to the gnd. Fn = 137*Cos 0 - 25*sin30 = 124.5 N. = Normal Force. Fk = u*Fn = Force of kinetic friction. a = (25*Cos30-Fp-Fk)/M. Vf^2 = Vo^2 + 2a*d Vo = 1 m/s. d = 18 m. Vf = ?
November 1, 2015

Physics
See Relate Questions: Tue, 2-7-12, 1:11 AM.
November 1, 2015

science
Vf = Vo + g*Tr = 0. 24.5 + (-9.8)Tr = 0. -9.8Tr = 24.5 Tr = 2.5 s. = Rise time. Tf1 = Tr = 2.5 s = Time to fall back to roof. h = Vo*t + 4.9*t^2 = 24 m. 24.5*t + 4.9t*2 = 24. 4.9t^2 + 24.5t -24 = 0. Use Quad. Formula. t = 0.839 s. = Time to fall from top of roof to gnd. T = Tr...
November 1, 2015

physics
Fb = M*g = 13 * 9.8 = 127.4 N. Fp = 127.4*sin 0 = 0. = Force parallel to the floor. Fn = 127.4 - 86.4*sin64. = Normal force. Fk = u*Fn = Force of kinetic friction. a = (F*Cos64-Fp-Fk)/M.
November 1, 2015

physics
F1 = 2123 N. F2 = 1930 N. M = 1245 kg. a = (F1-F2)/M.
November 1, 2015

Physics
Vo = 90,000m/3600s = 25 m/s. d1 = Vo*t = 25m/s * 0.75s. = 18.75 m. d2 = 40 - 18.75 = 21.25 m. = Required stopping distance. Vf^2 = Vo^2 + 2a*d. Vf = 0. Vo = 25 m/s. a = -10 m/s^2. If d is => 21.25 m, the car will hit the barrier.
October 31, 2015

physics
4. Incomplete. Vo = 35m/s[33o]. Xo = 35*Cos33 = 29.4 m/s. Yo = 35*sin33 = 19.1 m/s. 5A. Yf^2 = Yo^2 + 2g*h. Yf = 0. g = -9.8 m/s^2. h = ? B. Dx = Vo^2*sin(2A)/g. A = 33o. g = +9.8 m/s^2. Dx = ?
October 31, 2015

SPR,PHYSICS
Vs = Db/Dw * Vb = 2/3 * Vb = 2Vb/3. Db/Dw * Vb = 2Vb/3. Db/Dw = 2/3 = 0.667. Db=0.667Dw = 0.667 * 0.998=0.665 g/cm^3. = Density of the block. Notes: Vs = Volume submerged. Db = Density of the block. Dw = Density of water. Vb = Volume of the block.
October 30, 2015

force
Wb = M*g = 10*9.8 = 98 N. Fp = 98*sin 0 = 0 = Force parallel to the surface. Fn = 98*Cos 0 - 40*sin30 = 78 N. = Normal force. Fk = u*Fn = 0.3 * 78 = 23.4 N. = Force of kinetic friction. a=(Fap*Cos30-Fp-Fk)/M=(34.6-0-23.4)/10 = 1.12 m/s^2.
October 30, 2015

Physics
I had this same problem... θ > arctan(μs) is the answer, you're welcome fam.
October 29, 2015

math
d1 = 10km/h * (20/60)h = 3.33 km., N. d2 = 5km/h * (35/60)h=2.92 km, NE.(45o)= 2.06 + 2.06i. Disp.=2.06 + 2.06i + 3.33i=2.06 + 5.39i = sqrt(2.06^2 + 5.39^2)
October 29, 2015

physics
Disp. = 7m[90o] + 9m[E45oN] + 7m[W14oS] X = 9*Cos45 + (-7*Cos14) = -0.428 m. Y = 7 + 9*sin45 + (-7*sin14) = 11.7 m. Q2. Tan A = Y/X = 11.7/-0.428 = -27.26754. A = -87.9o = 87.9o N. of W. = Direction. Disp. = Y/sin A = 11.7/sin87.9 = 11.71 m
October 29, 2015

physics
Disp. = 7m[90o] + 9m[E45oN] + 7m[S76oW]. X = 9*Cos45 - 7*Cos76 = 1.84 m. Y = 7 + 9*sin45 - 7*sin76 = 6.57 m. Q1. Tan A = Y/X = 6.57/1.84 = 3.57168. A = 74.4o N. of E. = Direction. Disp. = Y/sin A = 6.57/sin74.4 = 6.82 m
October 29, 2015

physics
A quantity that shows magnitude AND direction.
October 29, 2015

geometry
x^2 + 3x = 180o. x^2 + 3x-180 = 0. Factor it. -180 = -12*15. -12 + 15 = 3 = B. (x-12)(x+15) = 0. X = 12. X = -15. Use positive value of X: X = 12. X^2 = 144o. 3x = 36o.
October 29, 2015

physics
See Related Questions: Fri, 3-7-14, 4:52 PM.
October 29, 2015

Chemistry
Methanol, a major industrial feedstock, is made by several catalyzed reactions, such as CO(g) + 2H2(g) ----> CH3OH (l) One concern about using CH3OH as an auto fuel is its oxidation in air to yield formaldehyde, CH2OH(g) which poses a health hazard. Calculate ÄG o at ...
October 29, 2015

physics math science
Vo = 200m/s[37o]. Xo = 200*Cos37 = 160 m/s. Yo = 200*sin37 = 120 m/s. A. Y = Yo + g*t = 120 + (-9.8)*2 = 100 m/s. = Ver. component of velocity @ 2 s. Tan A = Y/Xo = 100/160 = 0.625. A = 32o. V = Xo/Cos A = 160/Cos32 = 189 m/s[32o]. B. Yf = Yo + g*Tr Yf = 0, g = -9.8m/s^2, Tr...
October 29, 2015

Calculus
i did. Dv=128pi. But the answer is 8pi/25
October 28, 2015

Calculus
Use differentials to estimate the amount of paint needed to apply a coat of paint 0.02 cm thick to a sphere with diameter 40 meters. (Recall that the volume of a sphere of radius r is V=(4/3)πr^3. Notice that you are given that dr=0.02.)
October 28, 2015

math
2 Years ago: Pam: X yrs. old. Sam: 2x/3 yrs. old. 3 yrs. later: Pam: x+3 yrs. old. Sam: 2x/3 + 3 yrs. old 2x/3 + 3 = 3/4(x+3). 2x/3 + 3 = 3x/4+9/4 8x + 36 = 9x + 27. X = 9. So Pam is 3 yrs. older than Sam. In 20 yrs.: x + (x+3) = 69. 2x = 66. X = 33. X+3 = 36. Today: Sam: 33...
October 28, 2015

Physics
F = 0.119m * 110N./m =
October 28, 2015

Physics
Wc = M*g = 1400 * 9.8 = 13,720 N. = Normal force, Fn. Fp = mg*sin 0 = 0. = Force parallel to the road. Fk = u*Fn = 0.0889 * 13,720 = 1220 N. a = (Fp-Fk)/M = (0-1220)/1400 = -0.871 m/s^2. Vf^2 = Vo^2 + 2a*d. Vf = 0. a = -0.871 m/s^2. Vo = 21.4 m/s. d = ?.
October 28, 2015

physics
Wt. = 450cm^3 * 0.998g/cm^3 = 449.1 g. = 0.449 kg of water displaced. M*g = 0.449kg * 9.8N/kg = 4.40 N.
October 28, 2015

SCIENCE\PHYSICS
Disp. = 0. d = 5 + 5 = 10 m.
October 28, 2015

PHYSICS
d = 5 + 5 = 10 m.
October 28, 2015

PHYSICS
Displacement = 0, because it ended at the starting point.
October 28, 2015

PHYSICS
a. Yf^2 = Yo^2 + 2g*h = 0. Yo^2 = -2g*h = -2*(-9.8)27.5 = 539. Yo = 23.2 m/s. = Vertical component of initial velocity. sin A = Yo/Vo = 23.2/47.5 = 0.48877. A = 29.3o. Xo = Vo*Cos A = 47.5*Cos29.3 = 41.4 m/s = Horizontal component of initial velocity = Total velocity at max ht...
October 28, 2015

physics
The velocity of the truck must be equal to the hor. component of the airplane's velocity: V = 180*Cos47.
October 28, 2015

Calculus
Let f(x)=x^4. If a=1 and dx=Δx=1/2, what are Δy and dy?
October 28, 2015

Physics
Wb = M*g = 200 N., M = 200/g = 200/9.8 = 20.4 kg. sin A = 3/10 = 0.30, A = 17.5o. Fp = 200*sin17.5 = 60 N. Fn = 200*Cos17.5 = 191 N. a. Work = F*d = 120 * 10 = 1200 J. b. Mg*h-0 = Mg*h = 200 * 3 = 600 J. c. Conservation Energy : Change in KE = Change in PE = 600 J. d. Fap-Fp-...
October 27, 2015

maths
P = Po(1+r)^n. r = (6%/2)/100% = 0.03 = Semi-annual % rate expressed as a decimal. n = 2comp./yr. * 1yr. = 2 Compounding periods. P = Po(1+0.03)^2 = Po*1.03^2 = 1.0609Po. I = P-Po = 1.0609Po-Po = 0.0609Po. I/Po * 100% = 0.0609Po/Po = 6.09% = Effective APR.
October 27, 2015

Physic
V = Vo^2 + 2g*h. Vo = 0, h = 20 m, V = ?
October 27, 2015

physicsn
Notes: 1. Fp = Force parallel with the hill. 2. Fn = Normal force. 3. Fk = Force of kinetic friction. 4. Ws = Wt. of skier.
October 27, 2015

physicsn
Ws = M*g = 9.8M. Fp = 9.8M*sin30 = 4.9M. Fn = 9.8M*Cos30 = 8.49M. Fk = u*Fn = u*8.49M. Fp-Fk = M*a. 4.9M-u8.49M = M*(-1.4) Divide by M: 4.9-8.49u = -1.4 -8.49u = -1.4-4.9 = -6.3 u = 0.74.
October 27, 2015

Physics
a. a=(Vf-Vo)/t = (5-0)/20 = 0.25 m/s^2. d1 = Vo*t + 0.5a*t^2 = 0 + 0.5*0.25*20^2 = 50 m.
October 27, 2015

math
a scooter is priced between $1000 and $2000. its price is a multiple of 10. All the digits in the price, except for the thousands digit, are even numbers. The value of the hundreds digit is 30 times the value of the tens digit. what is the price of the scooter?
October 26, 2015

science
Wb = M*g = 10 * 9.8 = 98 N. Fn = 98-40*sin30 = Normal force. Fk = u*Fn = Force of kinetic friction. a = (Fap*Cos30-Fk)/M.
October 26, 2015

Physics
a = F/m = 5/0.3 = 16.7 m/s^2. V = Vo + a*t. Vo = 20 m/s. t = 0.03 s. V = ?
October 26, 2015

Physics
Correction: Yf = 36.6 m/s.
October 26, 2015

Physics
h = 0.5g*t^2 = 68.2 m. 4.9t^2 = 68.2 t^2 = 13.92. t = 3.73 s. Dx = Xo*t = 4.2m/s * 3.73s. = 15.7 m. Yf^2 = Yo^2 + 2g*h. Yf^2 = 0 + 19.6*68.2 = 1336.72. Yf = 36.6 m. Vf = sqrt(Xo^2 + Yf^2) = Final velocity.
October 26, 2015

math 1350
Bob: X baseball cards. Ted: 2x " " Reggie: 2x-5 " " 2x-5 + x = 82. X = ?. 2x = ?
October 26, 2015

science
h = 0.5g*t^2.
October 26, 2015

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