Wednesday

April 16, 2014

April 16, 2014

Total # Posts: 8,508

**math**

-16x^2 + 160t The max. point on the parabola is the vertex: t = Xv = -B/2A = -160/-32 5 s hmax. = Yv = -16*5^2 + 160*5 = 400 Ft. V(5,400).

**Geometry**

1. A = 400cm * 2cm = 800 cm^2. 2. A = (3.5^2) = 3. A = pi*r^2 = 3.14 * (9/2)^2 =

**algebra1 HELP PLEASE**

Let y = 0. x^2-7 = 0 x^2 = 7 X = =+-sqrt 7

**algebra1 HELP PLEASE**

h1(t) = 100 - 0.5*32*t^2. h1 = 100 - 16t^2 = 0 @ gnd. level. 16t^2 = 100 t^2 = 6.25 t = 2.50 s. h2(t) = 210 - 0.5*32*t^2 h2 = 210 - 16t^2 = 0 @ gnd. level. 16t^2 = 210 t^2 = 13.125 t = 3.62 s.

**physics**

See previous post,4:21 PM.

**Finance**

2. Increases with every payment and completely repays the loan with the last payment.

**physics**

Vo = 17m/s[25o] Xo = 17*cos25 = 15.4 m/s. Yo = 17*sin25 = 7.2 m/s. Y = Yo + g*t = 0 @ max. Ht. Tr = -Yo/ g = -7.2/-9.8 = 0.73 s. = Rise time. Tf = Tr = 0.73 s. = Fall time. D = Xo*(Tr+Tf) = 15.4 * 1.46 = 22.5 m. V=(D-12)/(Tr+Tf)=(22.5-12)/1.46=7.19m/s

**physics**

F = m*a V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d a = ((350)^2-0)/1.7 = 72,059 m/s^2 F = 0.004 * 72059 = 288 N.

**physics**

Please clarify your problem.

**phy**

1. Fn = m*a 40*cos37-Fk = 5 * 3 31.9-Fk = 15 Fk = 31.9-15 = 17 N. 3. a = Fn/m a = (250*cos37-8)/20 = 9.58 m/s^2.

**math**

The bar means the 2nd 89 REPEATS continuously.

**physics**

A = 5.0km[135o] B = 7.0km[315o] D = A+B D=(5.0*cos135+7.0*cos315)+i(5.0*sin135+ 7.0*sin315 D = (-3.54+4.95) + i(3.54-4.95) D = 1.41 - i1.41 = 2km[-45o]=2km[45o S of E]. NOTE: The cosine function was used to find the hor. components; the sine function was used to find the ver. ...

**physics**

A = 100m[0o] B = 200m[270o] C = 50m[3i5o] D = A+B+C D=(100+200*cos270+50*cos315+i(sin270+50*sin315) D = (100+0+35.4) + i(-200-35.4) D = 135.4 - i235.4 = 272m[-60o] = 272m [60o S. of E.].

**Physics**

A = 3m/s * 20s = 60m[180o]. B = 100m[270o]. C = 2m/s * 20s = 40 m[0o]. D = (A+B)-C A+B = (60*cos180+100*cos270)i(60*sin180+ 100*sin270) A+B = (-60+0) + i(0-100) A+B = -60 - i100 = -116.5[59o] A+B = 116.5[59+180] = 116.5m[239o]. D = (A+B)-C = 116.5[239] - 40 D = -60 - i100 - 40...

**math 2**

m1 = -A/B = 6/2 = 3. m2 = -12/-4 = 3. The Eqs have equal slopes. Therefore, they are parallel and do not intersect. So there are NO solutions.

**contemporary math**

P = Po(1+r)^n. P = $50,000 r = (8%/4)/100% = 0.02 = Quarterly % rate expressed as a decimal. n = 4comp./yr * 5.5yrs. = 22 Compounding periods. Plug the above values into the given Eq and solve for Po.

**Math**

Substitution.

**Math**

Substitution.

**math**

See previous post: Mon,7-1-13,10:49 PM.

**math**

Correction: A =(8/4)^2 * 18 = 72 Ft^2 = Area of the base. V = A*h = 72 * 8 = 576 Ft^3. OR V = (8/4)^3 * 72Ft^3 = 576 Ft^3.

**math**

18Ft^2*h1 = 72Ft^3 h1 = 72Ft^3/18Ft^2 = 4 Ft. A = (8Ft/4Ft) * 18Ft^2 = 36 Ft^2 = Area of the base. V = A*h = 36Ft^2 * 8Ft = 288 Ft^3.

**Gen. physics**

V^2 = Vo^2 + 2ad = 0 a = -Vo^2/2d = -(6.4)^2/29 = -1.41 m/s^2

**physics**

a. V = Vo + g*t = 17 m/s. Vo = 17-g*t = 17-(-9.8*2.2) = 38.56 m/s. b. V = 38.56 -9.8*4.4 = -4.56 m/s. The negative sign means the rock is on its' way down.

**gen physics**

See Related Questions: Thu,6-27-13,6:00am.

**gen physics**

A = 71[180o]. B = 71[270o]. a. A+B=(71*cos180+71*cos270)+i(71*sin180+71*sin270) A+B = (-71+0) + i(0-71) A+B = -71 - i71 = -100.4]45o] or 100.4[45o+180o] = 100.4[225o]. Since the resultant is in Q3, 45o is the reference angle. b. A-B=(71*cos180-71*cos270)-i(71sin180-71sin270) A...

**Algebra**

x(3y) = y(3x) = 3(xy) = 3*y*x.

**49PM.ath**

See Related Questions: Mon,7-1-13,10:

**math**

P = Po(1+r)^n. Po = $42,000 r = 11%/100% = 0.11 n = 1comp./yr. * 19yrs = 19 Compounding periods. Plug the above values into the given Eq and solve for P.

**algebra 1 NEED NOW!!! PLEASE HELPPP**

Since the parabola opens downward, the vertex is the max. point on the curve. Y = -12x^2 + 48x 1. h = Xv = -B/2A = -48/-24 = 2 Seconds. 2. k = Yv = -12*2^2 + 48*2 = 48 Ft. V(x,y)= (2,48). 3. Tr = Tf = 2 s. T = 2 + 2 = 4 s. Tr = Rise time. Tf = Fall time.

**business math**

See Mon,7-1-13,10:49PM post.

**Mathematics**

What is 72ten?

**finance**

D = 10000-0.15*10000 = $8500.

**Physics**

F = m*a a = V-Vo)/t = (34.4-0)/42 = 0.819 m/s^2. F = 3.6*0.819 = 2.95 N.

**MATH**

A(-1,-2),P(x,y),B(9,3). x-(-1) = 4(9-x) x+1 = 36-4x 5x = 35 X = 7. y-(-2) = 4(3-y) y+2 = 12-4y 5y = 10 Y = 2. P(7,2).

**Physics**

V = 6.48*cos9.54 = 6.39 m/s.

**Physics**

See previous post.

**Physics**

a=(V-Vo)/t = (26.5-0)/0.55 = 48.2 m/s^2. F = m*a = 929.4 * 48.2 = 44,780 N.

**Discrete Math**

CORRECTION:BCD should be BCDA

**Discrete Math**

8 different passwords were formed: ABCD BCD CDAB DABC. DCBA CBAD BADC ADCB

**math**

Move the decimal 8 places to the right. 7.5*10^8 = 750,000,000

**math**

1. P = Po(1+r)^n. Po = $500,000. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4comp./yr. * 5yrs. = 20 Compounding periods. Plug the above values into the given Eq. and solve for P. 2. P = Po(1+r)^n. r = APR = (8%/100% = 0.08 n = 1comp./yr. * 5yrs. = 5...

**trig**

X ^5 - 11 = 0 X^5 = 11 (X^5)^(1/5) = (11)^(1/5) X = 1.615.

**physics**

See Related Questions: Thu,6-27-13,6:ooAM.

**Business Math**

P = Po(1+r)^n. Po = 50000 r = (1.6%/2)/100% = 0.008 = Semi-APR. n = 2comp./yr. * 5yrs = 5yrs = 10 Compounding periods. Plug the above values into the given Eq and solve for P.

**Business Math**

P = Po(1+r)^n P = $27,500 Po = Initial investment. r = (6%/12)/100% = 0.005 = Monthly % rate expressed as a decimal. n = 12comp/yr. * 3yrs = 36 Compounding periods. P = Po(1.005)^36 = 27500 Po = 27500/(1.005)^36 = $22,980.

**Business Math**

APY = The interest for 1 year divided by the initial investment: APY = (I/Po)*100%.

**Business Math**

CORRECTION: n = 4Comp./yr. * 1yr. = 4 Compounding periods.

**Business Math**

P = Po(1+r)^n. Po = $1,000,000. r = (8%/4)/100% = 0.02 = Quarterly % .rate expressed as a decimal. n 4Comp./yr. * 8trs = 32 Compounding periods. Plug the above values into the given Eq and solve for P. I = P-Po.

**Business Math**

P = Po(1+r)^n. Po = $7700. r = (6%/4)/100% = 0.015 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs = 20 Compounding periods. Plug the above values into the given Eq and get: P = $10,370.78

**physics**

Vo = 85m/s[45o]. Xo = 85*cos45 = 60.1 m/s. Yo = 85*sin45 = 60.1 m/s. Tr = (Y-Yo)/g = (o-60.1)/-9.8 = 6.1 s. = Rise time. h = Yo*t + 0.5g*t^2 h = 60.1*6.1 - 4.9*(6.1)^2 = 184.3 m. d = Yo*t + 0.5g*t^2=184.3 + 120=304.3m 0 + 4.9t^2 = 304.3 t^2 = 62.1 Tf = 7.9 s. = Fall time. d =X...

**physics**

V*t = 17 m. 42.4 * t = 17 t = 0.40 s. d = 0.5g*t^2 g = 9.8m/s^2

**To Mara; Re: algebra**

L = 10-X. Your Eq is correct.

**physics**

V1*t = V2*t-37 m. 5.95t = 7.80t-37 7.8t-5.95t = 37 1.85t = 37 t = 20 s. d = 5.95 * 20 = 119 m

**Science**

Dw/Dl = 4/5 800/Dl = 4/5 4Dl = 4000 Dl = 1000 kg/m^3. = Density of the fluid.

**maths**

P1 = 1.08*65000 = 70200. (P1+P2)/2 = 66,300 (70,200+P2)/2 = 66300 70200+P2 = 132,600 P2 = 62400 Loss = 65000-62400 = 2600 %Loss = 2600/65000 = 0.04 = 4%. 2. 1kg/0.95kg = 1.0526 = 105.26 %. %Gain = 105.3% - 100% = 5.3%.

**math 4th grade**

See previous post.

**math 4th grade**

Population = 500,000km^2 * 20p/km^2 = 10,000,000 People.

**Physics**

Wp = m*g = 60kg * 9.8N/kg = 588 N. = Wt. of the person. Fp = 588*sin25 = 248.5 N. = Force parallel to plane. Fv = 588*cos25 = 533 N. = Force perpendicular to plane Fk = 0.450 * 533 = 240 N. = Force of kinetic friction. Fn = m*a a = Fn/m = (Fp-Fk)/m a = (248.5-240)/60 = 0.142 m...

**physics**

Fn = m*a = 0.1*10 = 1 N.

**physics**

F = m*a a = F/m = 80000/9.7 = 8247 m/s^2 V = Vo + a*t t = (V-Vo)/a = (6500-0)/ 8247 = 0.788 s.

**physics**

See previous post.

**physics**

Because the velocity at any instant depends on the time of the acceleration.

**Physics**

h = Vo*t + 0.5g*t^2 = 1.5 m. 0 + 4.9t^2 = 1.5 t^2 = 0.306 Tf = 0.553 s. = Fall time. D1 = V*Tf = 30m/s * 0.553s = 16.6 m. D2 = 35m/s * 0.553s = 19.4 m.

**MATH**

6 + 4*7/14 - 1 = 7 6 + 28/14 _ 1 = 7 6 + 2 - 1 = 7 7 = 7

**conceptual science**

a. V = Vo-g*t V = Vo-9.8m/s^2*1s V = Vo-9.8m/s. s. The speed decreases by 9.8 m each second. b. V = Vo + g*t V = Vo + 9.8m/s^2*1s V = Vo + 9.8m/s. The speed increases by 9.8 m each second. c. V = Vo + g*t = 0 @ max. ht. Vo + g*t = 0 Vo - 9.8t = 0 9.8t = Vo Tr = Vo/9.8 = Rise t...

**physics**

What is the question?

**physics**

V*t = 17 m. t = 17/V = 17/37.8 = 0.1852 s. d = 0.5g*t^2. g = 9.8 m/s^2.

**physics**

Vo = 26.5m/s[32.2o]. Xo = 26.5*cos32.2 = 22.4 m/s. Yo = 26.5*sin32.2 = 14.1 m/s Y = Yo + g*Tr = 0 @ max. ht. Tr = -Yo/g = -14.1/-9.8 = 1.44 s. = Rise time. D = Xo * Tr = 22.4m/s * 1.44s. = 32.3 m.

**physics**

Vo = 16.7m/s[33o]. Yo = 16.7*sin33 = 9.1 m/s. Y^2 = Yo^2 + 2g*h = 0 hmax= Yo^2/2g = -(9.1)^2/-19.6 = 4.23 m. V^2 = Vo^2 + 2g*d V^2 = 0 + 19.6*(4.23-2.6) V^2 = 19.6 * 1.625 = 31.85 V = 5.64 m/s.

**physics**

Correction: X = 4.15 m/s.

**physics**

X = Xo + a*t X = 3.2 + 1.9*0.5 = 4.15 m/s^2 Y = Yo + a*t Y = 8.1 - 6.2*0.5 = 5 m/s. a. V^2 = X^2 + Y^2 V^2 = (4.15)^2 + 5^2 = 42.2 V = 6.5 m/s. b. tan A = Y/X = 5/4.15 = 1.20482 A = 50.31o = Direction.

**physics**

See previous post.

**physics**

Vo = 12m/s[53.2o]. Xo = 12*cos 53.2 = 7.2 m/s. NOTE: The hor. component remains constant during the flight.

**physics**

a. V^2 = Vo^2 + 2a.d a = (V^2-Vo^2)/2d. a = (6.14-0)/26.8 = 0.229 m/s^2 b. a = 0.229*cos 32.6 = 0.193 m/s^2, c.

**physics**

tan A = Y/X = -558/925 = -0.60324 A = -31o D = 925/cos(-31) = 1080 m.

**physics**

See Related Questions: Tue,6-18-13,9:43PM.

**math**

translate the phrase into a mathematical expression and then evaluate it. sixtten squared divided by four cubed. The given expression in symbols is? (do not simplify. type exponential notation with positive exponents.) Evaluated, the expression is equal to? (simplify your answer)

**Physics**

x/0.017 = 22/1 X = 0.374 N. Work=F*d = 0.374 * 0.017=0.0064 Joules.

**science**

P = V*I = 2000 W. 220I = 2000 I = 9.09 Amps. The current too high for the circuit. If the circuit is properly protected, the fuse will blow or the circuit breaker will trip.

**Math**

I = Po*r*t = $23. 820*(r/360)*52 = 23 118.44444r = 23 r = 0.194 = 19.4 %.

**math**

P = Po(1+r)^n P = 8000+1261 = 9261. Po = 8000. n = 1comp./yr. * 3 yrs. = 3 Compounding periods. r = ? 8000(1+r)^3 = 9261. Divide both sides by 8000: (1+r)^3 = 1.157625. Take cube of both sides: 1+r = 1.05 r = 0.05 = 5% per yr.

**math**

P = Po + Po*r*t = 2600 2000 + 2000*(0.06/360)t = 2600 2000 + t/3 = 2600 t/3 = 2600-2000 = 600 t = 1800 Days. t = 1800Days / 360Days/yr. = 5 Yrs. Ordinary int. is based on 360 days/yr.

**business math**

C = 0.026*60000 + 0.034*(89400-60000) C = 1560 + 999.60 = $2559.60.

**physics**

tan A = Y/x = -4/2 = -2.0 A = -63.43o = 63.43o South of East. tan(-63.43) = d/10m d = 10*tan(-63.43) = -20 m = 20 m. South of starting point.

**physics**

V^2 = Vo^2 + 2g*d. Vo = 12 Ft/s. g = 32FT/s^2. d = 4.5 Ft. Plug the given values into the Eq and solve for V in Ft/s.

**physics**

V = Vo + a*t a = (V-Vo)/t a=(300-150)/(1/12)h=1800=1800 mi/h^2 V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a. d = (90000-22500)/3600 = 18.75 Miles.

**trig**

A + B = 90o A + 31 = 90 A = 59o. c*sin 59 = 3. c = 3/sin59 = 3.50 tan 59 = 3/b b = 3/tan 59 = 1.80

**Math 116**

See previous post.

**Math 116**

Multiply Eq1 by -6: -6x - 18y = -30 +6x - 6y = 14 Add the Eqs: -24y = -16 Y = 2/3. In Eq1, replace Y with 2/3: x + 3*2/3 = 5 x + 2 = 5 X = 3.

**Math 116**

Eq1:-6x - 2y = 12 Eq2:12x - 4y = -24 Multiply Eq1 by -4 and Eq2 by 2: 24x + 8y = -48 24x - 8y = -48 Add the Eqs: 48x = -96 X = -2. In Eq1, replace X with -2: -6*(-2) - 2y = 12 12 - 2y = 12 -2y = 12-12 = 0 Y = 0 (-2,0).

**Math Algebra1A**

Those are the only 2 that I know.

**grade 4 math**

10^x = 59,187 Take Log of both sides: x*Log 10 = Log 59187 X = Log59187/Log 10 = 4.77223. 10^4.77223 = 59187.

**math**

Monthly Salary = $X. Spends1/4 * $X = X/4. Bal. = X-X/4 = 3x/4. Spends1/5 * 3x/4 = 3x/20 Bal.=3x/4-3x/20 = 15x/20-3x/20=12x/20= 3x/5. Transportation: 1/10 * 3x/5 = 3x/50 Bal.=3x/5 - 3x/50 = 30x/50-3x/50=27x/50. 27x/50 = 630 27x = 31500 X = $1166.67.

**physics**

See previous post.

**physics**

See previous post.

**physics**

Vavg. = (30+45)/2 = 37.5 km/h.

**algebra**

Vb + Vc = 22 Vb - Vc = 8 Add the Eqs: 2Vb = 30 Vb = 15 mph. Replace Vb in Eq1 with 15: 15 + Vc = 22 Vc = 7 mph = Velocity of the current.

**Math**

787/9 = 87 Strawberries/carton. Bal. = 87 * 5 = 435 Strawberries 435strawberries/5strawberries/carton = 87 Cartons.

**physics**

h = 0.5g*t^2 = 81.6 m. 4.9t^2 = 81.6 t^2 = 16.65 t = 4.08 s. to hit ground. d = 9.13-4.30 = 4.83 m. = Distance the boat traveled in 4.08 s. Speed = d/t = 4.83/4.08 = 1.18 m/s.

**Physics**

Vo=a*t = 4i7 * 0.0475 = 19.8 m/s[59.70]. a. Xo = 19.8cos59.7 = 10 m/s. b. Yo = 19.8sin59.7 = 17 m/s.

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