Wednesday

September 2, 2015
Total # Posts: 10,940

**physics**

Vo = 50km/h = 50,000m/3600s = 13.89 m/s. a = (V-Vo)/t = (0-13.89)/5 = -2.78 m/s^2 F = m*a = 1000 * (-2.78) = -2780 N. The negative sign means the force is against the motion.
*October 25, 2014*

**Calculus/pre-trig**

D = B^2 - 4AC 1. If B^2 is less than 4AC(B^2 < 4AC), the Determinant is negative and we have 2 imaginary solutions and no real solutions. 2. If B^2 = 4AC, we have one real solution and no imaginary solutions. 3.If B^2 > 4AC, we have 2 real solutions and no imaginary ...
*October 25, 2014*

**Physics**

Fb = m*g = 11.2kg * 9.8N/kg = 109.8 N. = Force of block. Fp = 109.8*sin24 = 44.64 N. = Force parallel to the incline. d = (1m/31,300N) * Fp d = (1m/31,300N) * 44.64N = 0.0014262 m. = 0.143 cm.
*October 25, 2014*

**physics**

Xo = 13 m/s. Dx = 60 m. h = ? Dx = Xo * Tf = 60 Tf = 60/Xo = 60/13 = 4.62 s. = Fall time. h = 0.5g*Tf^2 = 4.9*4.62^2 = 105 m.
*October 25, 2014*

**intermidiate algebra**

Eq1: 3x + 300y = 111 Eq2: 5x + 600y = 198 Multiply Eq1 by -5 and Eq2 by 3 : -15x - 1500y = -555 +15x + 1800y = +594 Sum: 300y = 39 Y = $0.13 per mile. In Eq1, replace Y with 0.13 and solve for X: 3x + 300*0.13 = 111 3x = 111 - 39 = 72 X = $24 per day.
*October 25, 2014*

**physis**

W = 750N/6 = 125 N. on the moon.
*October 24, 2014*

**Math, Trig/Pre Calc**

See previous post: Fri, 10-24-14, 5:38 PM.
*October 24, 2014*

**Pre-Calc/Trig...**

Y = x^2 - 2x - 3 Vertex Form: Y = a(x-h)^2 + k h = -b/2a = 2/2 = 1 K = 1^2 - 2*1 - 3 = -4 Vertex Form: Y = 1(x-1)^2 - 4 Y = x^2 - 2x - 3 = 0 -3 = 1*(-3). Sum = 1 + (-3) = -2 = b. Factored or Intercept form:(x+1)(x-3) = 0
*October 24, 2014*

**math**

Tan13 = h/200 h = 200*Tan13 = 46 Ft. Cos13 = 200/r r = 200/Cos13 = 205 Ft = hypotenuse.
*October 24, 2014*

**Math 222**

1. g^2 - 6g - 55 = 0 -55 = 1*(-55) = 5*(-11) Choose the pair of factors whose sum = B : 5, and -11. (g+5)(g-11) = 0 g+5 = 0 g = -5. g-11 = 0 g = 11. Solution: g = -5, and 11. 2. k^3 + k = 0 k(k^2+1) = 0 k = 0 k^2 + 1 = 0 k^2 = -1 k = sqrt(-1) = I Solution: k = 0, and i. 3. k^2...
*October 23, 2014*

**Algebra**

Cannot be factored. Use Quadratic Formula and get: X1 = -737.1. X2 = 122.1.
*October 23, 2014*

**Physics**

Vo = 1560 m/s @ 67.4o Range = Vo^2*sin(2A)/g = 1560^2*sin(134.8)/9.8 = 176,205 m. Range = Vo*cos67.4*T = 176,205 T = 176,205/1560*cos67.4 = 294 s. in flight.
*October 23, 2014*

**math**

d = 110 - 30t = 40. Solve for t.
*October 23, 2014*

**physics**

Vo = 12.8 m/s @ 33.5o Yo = 12.8*sin33.5 = 7.06 m/s. Tr = -(Yo)/g = -7.06/-9.8 = 0.721 s. = Rise time. Tf1 = Tr = 0.721 s. = Fall time from max ht. to top of building. Tr+Tf1+Tf2 = 3.4 s. 0.721 + 0.721 + Tf2 = 3.4 Tf2 = 3.4 - 1.44 = 1.96 s. = Fall time from top of building to ...
*October 23, 2014*

**physics**

West = 340*Cos20 = 319.5 km. North = 340*sin20 = 116.3 km.
*October 23, 2014*

**accounting**

Po = $9800, r = 0.02, t = 15yrs. I = Po*r*t
*October 23, 2014*

**Physics**

h = ho + -(Vo^2)/2g h = 744 + -(15.5^2)/-19.6 = 756.3 m
*October 23, 2014*

**physics**

a. F1 = 6N @ 0o, F2 = 6N @ 60o. X = 6 + 6*Cos60 = 9.0 N. Y = 0 + 4*sin60 = 3.46 N. F1+F2 = X+Yi = 9 + 3.46i Fr = 9 + 3.46i + 4 = 13 + 3.46i = 13.5 N @ 14.9o
*October 23, 2014*

**Physics Mechanics**

F(x) = 30 - 10x = 0 10x = 30 X = 3 Meters.
*October 23, 2014*

**Physics**

Work = F*d = 6.7 J. F * 0.044 = 6.7 F = 152.3 N F/(0.038+0.044) = 152.3/0.044 F/0.082 = 3461.36 F = 283.83 N. Work = F*d = 283.83 * 0.082 = 23.3 J. 23.3 - 6.7 = 16.6 J.
*October 23, 2014*

**Physics**

u = a/g a = u*g = 0.53*(-9.8) = -5.194 m/s^2 V^2 = Vo^2 + 2a*d = 0 Vo^2 = 2*5.194*11 = 114.3 Vo = 10.7 m/s.
*October 22, 2014*

**physic**

Vo = 25m/s @ 35o Xo = 25*cos35 = 20.48 m/s. Dx = Xo*t = 38 m. t = 38/Xo = 38/20.48 = 1.86 s.
*October 22, 2014*

**Business Math**

P = Po + Po*r*t P = 8,500 + 8500*(0.06/360)*40 - 2000 = $8556.67 - 2000 = $6556.67 After 40 days. P = 6556.67 + 6556.67*(0.06/360)*70 - 2000 = 6633.16 - 2000 = 4633.16 After 70 days. P = 4633.16 + 4633.16*(.0/360)*(180-110)= $4687.21 After 180 days.
*October 22, 2014*

**Finance**

C = Co + Co*r*t = 1400 Gigabytes. Co + Co*0.15*5 = 1400 Co + 0.75Co = 1400 1.75Co = 1400 Co = 800 Gigabytes = Today's capacity.
*October 22, 2014*

**Math**

5 - 2x - 1 = x+2 4-2x = x + 2 -2x-x = 2 - 4 -3x = -2 X = -2/-3 = 2/3 Your method: Multiply each term on both sides by 12: 12(5-2x-1) = 12(x+2) 60 - 24x - 12 = 12x + 24 48-24x = 12x + 24 -24x - 12x = 24 - 48 -36x = -24 X = -24/-36 = 24/36 = 2/3. Note: I don't know why you ...
*October 22, 2014*

**physics**

Vo = 110km/h = 110000m/3600s = 30.56 m/s V^2 = Vo^2 + 2a*d = 0 a = -(Vo^2)/2d = -(30.56^2)/200 = -4.67 m/s^2. F = m*a = 3.6*10^5 * (-4.67) = -1.68*10^6 N. Note: The negative sign means that the force opposes the motion.
*October 22, 2014*

**Physics**

X = 810 m/s^2 Y = 910 m/s^2 m = 0.32 kg F = ? a^2 = X^2 + Y^2 = 810^2 + 910^2 = 1,484,200 a = 1218 m/s2. F = m*a = 0.32 * 1218 = 390 N
*October 22, 2014*

**physics**

Vo = 0 V = 33.9 m/s. t = 6.02 s. m = 1640 kg F = ? a = (V-Vo)/t = (33.9-0)/6.02 = 5.63 m/s^2. F = m*a = 1640 * 5.63 = 9235 N.
*October 22, 2014*

**Physics**

Vo = 29.2m/s @ 46.9o Xo = 29.2*Cos46.9 = 20.0 m/s. Yo = 29.2*sin46.9 = 21.32 m/s. V = Xo + Yi = 20 + 0i = 20 m/s @ h max. KE = 0.5m*V^2 = 0.5*19.4*20^2 = 3880 J.
*October 21, 2014*

**physics... PLEASE HELP**

L = V/F = Wavelength in meters.
*October 21, 2014*

**physics**

Vo = 75.2m/s @ 47o Xo = 75.2*cos47 = 51.3 m/s. Yo = 75.2*sin47 = 55.0 m/s. h = 520 m a. Yo*t + 0.5g*t^2 = 520 m. -55*t + 4.9*t^2 = 520 4.9t^2 - 55t -520 = 0 Use Quadratic formula. Tf = 17.34 s. = Fall time. Dx = Xo*Tf = 51.3m/s * 17.34s = 890 m b. Y = Yo + g*t = -55 + 9.8*17....
*October 21, 2014*

**physics... PLEASE HELP**

L = V/F
*October 21, 2014*

**Physics**

Vo = 4.35 m/s. g = -1.62 m/s^2 V^2 = Vo^2 + 2g*h. = 0 @ h max. h = -(Vo^2)/2g
*October 21, 2014*

**physics**

Xo = 35 m/s. h = 1.5 m. h = 0.5g*t^2 = 1.5 m. 4.9t^2 = 1.5 t^2 = 0.306 Tf = 0.553 s. = Fall time. Dx = Xo*Tf = 35m/s * 0.553s = 19.4 m.
*October 21, 2014*

**Physics**

1. V^2 = Vo^2 + 2g*h = 0 + 19.6*10 = 196 V = 14 m/s. KE = 0.5m*V^2 = 980 J. 0.5M*196 = 980 M = 980/(0.5*196) = 10 kg. 2. PE = mg*h = 9.8*1 = 9.8 J. At top of inclined plane. KE = 0.5m*V^2 = 0.5 * 1 * 4^2 = 8.0 J. At bottom of inclined plane. 9.8 - 8.0 = 1.8 J. Lost to heat ...
*October 21, 2014*

**physics**

a. Tan A = 4.24/9.47 = 0.44773 A = 24.1o From straight.
*October 21, 2014*

**math**

Eq1: x + 2y = 7 Eq2: 3x - 6y = 3 Multiply Eq1 by -3 and add the Eqs: -3x - 6y = -21 +3x - 6y = 3 Sum: -12y = -18 Y = -18/-12 = 3/2 In Eq1, replace Y with 3/2 and solve for X: x + 2*3/2 = 7 X = 7-3 = 4. Solution: (4, 3/2).
*October 21, 2014*

**math**

a. X Gal. of premium. (x+420) Gal. of regular 2.55x + 2.30(x+420) = $10,957 Solve for X.
*October 20, 2014*

**physics**

Fc = m*g = 80kg * 9.8N/kg = 784 N. = Force of crate. Fn = Fc = 784 N. = Normal. Fk = u*Fn = 0.25 * 784 = 196 N. = Force of kinetic friction. Work = (Fap-Fk))* d = (500-196) * 35 = 10,640 J.
*October 20, 2014*

**Physics**

T = d1/V1 + d2/V2 T = 443/(5.8+5.04) + 348/(5.8-5.04) = 40.87 + 457.9 = 498.8 s. = 8.3 Min.
*October 20, 2014*

**Physics**

X = 4N. Y = 3N. X + Yi + F3 = 0 4 + 3i + F3 = 0 F3 = -4 - 3i Tan Ar = Y/X = -3/-4 = 0.75000 r = 36.87o(Q1). = Reference angle. A = 36.87 + 180 = 216.87o(Q3). F3 = X/Cos A = -4/Cos216.87 = 5.0 N. @ 216.87o. Note: F3 is = to and opposite of the sum of the two given forces.
*October 20, 2014*

**Physics**

Fb = m*g = 4.58kg * 9.8N/kg = 44.9 N. = Force of the block. Fn = 44.9 - 10.5*sin25.5 = 40.4 N. = Normal = Force perpendicular to the floor. Fk = u*Fn = 0.09 * 40.4 = 3.63 N. = Force of kinetic friction. a = (Fx-Fk)/m = (10.5*cos25.5-3.63)/4.58 = 5.85 m/s^2. V = a*t = 5.85 * 5....
*October 20, 2014*

**int.science**

1.8*10^-2/9*10^2 = 0.2*10^-4 = 2.0*10^-5
*October 20, 2014*

**physics**

u = a/g. For a detailed explanation, see Related Questions: Sat, 11-17-12, 5:33 PM.
*October 20, 2014*

**business**

P = Po + Po*r*t = 5000 + 5000*0.058*36 = $15,440
*October 20, 2014*

**Physics 12**

F1+F2 = 50N[60o] + 60N[330o] X = 50*Cos60 + 60*Cos330 = 73.3 N. Y = 50*sin60 + 60*sin330 = 8.30 N. (F1 + F2) +F3 = 0 73.3 + 8.3i + F3 = 0 F3 = -73.3 - 8.3i Tan Ar = Y/X = -8.3/-73.3 = 0.11326 Ar = 6.46o N of E = Reference angle(Q1). A = 6.46 + 180 = 186.46o(Q4) = 6.46o S of W ...
*October 19, 2014*

**algebra**

F(x) = 2 - 1/4x Y = -(1/4)x + 2 Use the following points for graphing. (x, y) (0, 2) (1, 1.75) (2, 1.5) (3, 1.25) (4, 1) (5, 0.75)
*October 19, 2014*

**algebra**

See previous post.
*October 19, 2014*

**algebra**

F(x) = 2x^2 + x - 21 Y = 2x^2 + x + 1 = 0 A*C Method: A*C = 2 * (-21 = -42 = -3*14 = -6*7 Choose the pair of factors whose sum = B -6+7 = 1 = B. 2x^2 + (-6x+7x) - 21 = 0 (2x^2-6x) + (7x-21) = 0 Factor each binomial: 2x(x-3) + 7(x-3) = 0 Factor out (x-3): (x-3)(2x+7) = 0 x-3 = ...
*October 19, 2014*

**Geometry**

1. Scale: 2in = 6Ft 2. Scale: 1in = 3Ft. 3. Scale: 1/2 in = 1.5 Ft.
*October 19, 2014*

**Geometry**

See previous post.
*October 19, 2014*

**geometry**

L = 120Ft * 1unit/5Ft = 24 Units. W = 75Ft. * 1unit/5Ft = 15 Units.
*October 19, 2014*

**science**

Work = F*d = 250 J. F = 250/d = 250/19 = 13,16 N.
*October 19, 2014*

**algebra**

V = 80,000 - 6000t. t years.
*October 19, 2014*

**physics**

Fy = = 750*Cos22 = 695.4 N.
*October 19, 2014*

**algebra**

V(t) = 80,000 - 6000t
*October 18, 2014*

**Physics**

Vo = 200km/h = 200,000m/3600s=55.56 m/s a. Vavg. = (V+Vo)/2 = (0+55.56)/2 = 27.8 m/s. b. V = Vo + a*t = 0 55.56 + a*21 = 0 21a = -55.56 a = -2.65 m/s^2 b.V^2 = Vo^2 + 2a*d d = (V^2-Vo^2)/2a = (0-(55.56^2))/-5.3 = 582 m.
*October 18, 2014*

**algebra**

A(w) = sqrt(W^2+13) A(r+1) = sqrt((r+1)^2+13) A(r+1) = sqrt(r^2+2r+1+13) A(r+1) = sqrt(r^2+2r+14)
*October 18, 2014*

**algebra**

A(w) =sqrt(W^2 + 13) A(4) = sqrt(4^2 + 13) = 5.385.
*October 18, 2014*

**Physics**

a. h = 0.5g*t^2 = 2.5 m. 4.9t^2 = 2.5 m. t^2 = 0.51 Tf = 0.714 s. b. Dx = Xo*Tf = 1450m/s * 0.714s=1026 m.
*October 17, 2014*

**Physics**

h = 0.5g*t^2 = 0.031 m 4.9t^2 = 0.031 t^2 = 0.00633 Tf = 0.0795 s. = Fall time. Dx = Xo*Tf = 720 m/s * 0.0795s = 57.3 m.
*October 17, 2014*

**Physics**

h = 0.5g*t^2 = 0.93 m. 4.9t^2 = 0.92 t^2 = 0.1878 Tf = 0.433 s. Dx = Xo*Tf = 1.66m/s * 0.433s = 0.719 m.
*October 17, 2014*

**Physics**

Vo = 19.4m/s @ 33o Xo = 19.4*Cos33 = 16.27 m/s Yo = 19.4*sin33 = 10.57 m/s. Y^2 = Yo^2 + 2g*h = 0 @ max ht. h = -(Yo^2)/2g = -(10.57^2)/-19.6 = 5.7m Above gnd. Y^2 = Yo^2 + 2g*d Y^2 = 0 + 19.6*(5.7-3.1) = 50.96 Y = 7.14 m/s. = Ver. component of velocity. V^2 = Xo^2 + Y^2 = 16....
*October 17, 2014*

**Trigonometry**

mg*sin A = u*mg*Cos A Divide both sides by mg*Cos A: sin A/Cos A = u sin A/Cos A = Tan A Tan A = u = 0.17 A = 9.65o
*October 17, 2014*

**Math**

See previous post: Tue, 10-14-14, 2:39 PM.
*October 17, 2014*

**Math**

a. d = 13 + 18 +13 = 44 km b. 45 + 45 + 90 = 180o
*October 17, 2014*

**direct variation**

Y = 6x = 11 X = 11/6 = 1 5/6. Less than 2.
*October 17, 2014*

**Physics**

h = 0.5g*t^2 = 48m. Solve for t.
*October 17, 2014*

**algebra**

d1 = r*t = 6mi/h * (12/60)h = 1.2 Miles head start. d2 = d1 + 1.2 mi. 9t = 6t 1.2. Solve for t in hours.
*October 17, 2014*

**Physics**

h = 0.5g*t^2 = 100 m. 4.9t^2 = 100 t^2 = 20.40 Tf = 4.52 s. = Fall time. Dx = Xo*Tf = 40m/s * 4.52s = 180.7 m.
*October 17, 2014*

**physics**

1. True 2. True 3. False. 4. False 5. False 6. True
*October 16, 2014*

**physics**

a. F = m*g = 63.8 * 9.8 = 625.2 N. b. Work = F*d = 625.2 * 0.366 = 228.8 J.
*October 16, 2014*

**Physics Help Please!!!! Urgent!!**

1. Fb = m*g = 10 *9.8 = 98 N. = ForceFb of brick. Fap-Fk = m*a 46 - Fk = m*0 = 0 Fk = 46 N. = Force of kinetic friction. u = Fk/Fb = 46/98 = 0.469.
*October 16, 2014*

**Physics**

Vo = 5.71m/s[49.8o] Yo = 5.71*sin49.8 = 4.36 m/s. Y^2 = Yo^2 + 2g*h = 0 @ max. ht. h = (Y^2-(Yo^2))/2g h = (0-(4.36^2))/-19.6 = 0.970 m.
*October 16, 2014*

**physics**

Vo = 240km/h = 240,000m/3600s = 66.7 m/s V^2 = Vo^2 + 2a*d a = (V^2-Vo^2)/2d = (0-(66.7^2))190 = 23.42 m/s^2.
*October 16, 2014*

**Algebra**

d1 = 3km/h * 2h = 6 km Head start. d2 = d1 + 6km 40t = 3t + 6 37t = 6 t = 0.162 h = 9.73 min. to catchup. 2 + 0.162 = 2.162 h = Hours travelled by the first stagecoach. Note: Please check the speed of the 2nd coach; because forty doesn't look right.
*October 16, 2014*

**physics**

Vo = 57.1km/h = 57100m/3600s = 15.9 m/s. Fc = m*g = Force of the crate. Fs = u*mg = 0.394mg Fap-Fs = m*a Fap-0.394mg = m*0 = 0 Fap = 0.394mg = Force applied. a=Fap/m = 0.394mg/m=0.394g=0.394*(-9.8) = -3.86 m/s^2. V^2 = Vo + 2a*d d = (V^2-Vo^2)/2a = 0-(15.9^2)/-7.72 = 32.7 m.
*October 16, 2014*

**7th grade math**

P = 0.5*20x - 18 = 200 10x - 18 = 200 10x = 218 X = 21.8 or 22 Copies.
*October 16, 2014*

**Pre-Calc/Trig...**

Eq1: Y = x^2 + 5x - 2 h = -B/2A = -5/2 k = (-5/2)^2 + 5*(-5/2) - 2 = 25/4 - 25/2 - 2 = 25/4 - 50/4 - 8/4 = -33/4 V(-5/2, -33/4) Y = (x-3)^2 + 5(x-3) - 2 Eq2: Y = x^2 - x - 8 h = -B/2A = 1/2 k = (1/2)^2 - 1/2 - 8 = -8 1/4 = -33/4 V(1/2, -33/4). D. Shifted 3 units to the right.
*October 15, 2014*

**Physics/science**

See previous post: Wed,10-15-14, 6:23 AM
*October 15, 2014*

**Science**

Xo = 70mi/h * 1600m/mi + 1h/3600s = 31.1 m/s. h = 350 - 82 = 268 m Above the ledge. h = 0.5g*t^2 = 268 m. 4.9t^2 = 268 t^2 = 54.69 Tf = 7.4 s. = Fall time. Dx = Xo*Tf = 31.1m/s * 7.4s = 230 m. = Hor. distance.
*October 15, 2014*

**Physics**

a. Vpa = Vpg + Va = -228 km/h Vpg - 50i = -228 Vpg = -228 + 50i Tan Ar = Y/X = 50/-228 = -0.21930 Ar = -12.4o = Reference angle. A = -12.4 + 180 = 167.63oC CCW = 12.4o N. of W. = Heading. b. Vpg = X/CosA = -228/Cos167.63 = 233.4 km/h. = Plane's speed relative to gnd.
*October 15, 2014*

**Physics**

Vo = 31m/s[52o] Yo = 31*sin52 = 34.4 m/s. h = Yo*t + 0.5g*t^2 = 10 m. 34.4*t - 4.9t^2 = 10 -4.9t^2 + 34.4t - 10 = 0 Use Quadratic formula and get: t1 = 0.304 s. t2 = 6.71 s.
*October 14, 2014*

**physics**

h = L*sin A = 7.06*sin29 = 3.42 m. V^2 = Vo^2 + 2g*h = 4.03^2 + 19.6*3.42 = 83.3 V = 9.13 m/s.
*October 14, 2014*

**PHYSICS**

Fr = 10N[45o] + 10N[330] X = 10*Cos45 + 10*Cos330 = 15.73 m/s. Y = 10*sin45 + 10*sin330 = 2.071 m/s. Tan A = Y/X = 2.071/15.73 = 0.13166 A = 7.50o. Fr = X/Cos A = 15.73/Cos7.50 = 15.9 N. @ 7.50o.
*October 14, 2014*

**Physics**

Xo = 60 m/s. Yo = 20 m/s. Vo = ? m/s. Tan A = Yo/Xo = 20/60 = 0.33333 A = 18.43o = Direction. Vo = Xo/Cos A = 60/Cos18.43 = 63.2 m/s @ 18.43o
*October 14, 2014*

**Pre-Calc/Trig...**

Axis = h = Xv = -B/2A = 4/4 = 1. k = Y = 2*1^2 - 4*1 + 2 = 0 V(h,k) = V(1, 0).
*October 14, 2014*

**Physics**

h = 0.5g*t^2 = 6.14 m. 4.9t^2 = 6.14 t^2 = 1.253 Tf = 1.12 s. = Fall time.
*October 14, 2014*

**physics**

Incomplete.
*October 13, 2014*

**Algebra 2 Answer Check**

1. |3x-4|/(-5) = 6 (3x-4)/(-5) = 6 3x-4 = -30 3x = -26 X = -26/3 Does not satisfy Eq. (-3x+4)/(-5) = 6 -3x+4 = -30 -3x = -34 X = -34/-3 = 34/3 Does not satisfy Eq.
*October 13, 2014*

**Algebra 2 Answer Check**

1. |3x-4}/( 2. |2x-5| = x + 3 2x-5 = x+3 X = 8. -2x+5 = x+3 -3x = -2 X = 2/3 3. |5x+15| > 20 5x+15 > 20 5x > 20-15 X > 1 -5x-15 = > 20 -5x > 20 + 15 X < -7 Or 1 < X < -7 4. |x-2|/4 => 5 (x-2)/4 => 5 x-2 => 20 X => 22. (-x+2)/4 => 5 -x...
*October 13, 2014*

**Business Math**

P = Po*r*t = 1000*(0.06/365)*192 = 31.56 = Penalty.
*October 13, 2014*

**Finance kennedy king**

See previous post: Sun, 10-12-14, 11:49 PM.
*October 13, 2014*

**physics**

a. ho + (V-Vo^2)/2g=13 + (0-(8^2)/-19.6 = 16.3 m. Above gnd. b. V^2 = Vo^2 + 2g*h Vo = 0 m/s, 2g = 19.6 m/s^2, h = 16.3 m. Calculate V. c. V = Vo + g*Tr = 0. Tr = -Vo/g = -8/-9.8 = 0.82 s=Rise time. h = 0.5g*t^2 = 16.3 m. 4.9t^2 = 16.3 t^2 = 3.33 Tf = 1.82 s. = Fall time. Tr+...
*October 13, 2014*

**8**

a. P = Po + Po*r*t = $9,500 2,000 + 2000*r*1 = 9,500 Solve for r. b. 9500 - 9500*r*t = 2000 9500 - 9500*r*1 = 2000 -9500r = 2000-9500 = -7500 r = 0.7895 = 78.95%
*October 12, 2014*

**5**

P = Po + Po*r*t = 5000 + 5000*0.08*4 = 5000 + 1600 = $6600 = Amt. paid. Int. = $1600
*October 12, 2014*

**F**

Growth rate = 5%/5yrs. = 1%/yr. A = Po + Po*r*t = 3 Million. 1.5 + 1.5*0.01*t = 3 1.5 + 0.015t = 3 0.015t = 1.5 t = 100 Years.
*October 12, 2014*

**physics**

h = ho + (V^2-(Vo^2))/2g h = 50 + (0-(20^2))/-19.6 = 70.4 m. Above gnd. V^2 = Vo^2 + 2g*h = 0 + 19.6*70.4 = 1380 V = 37.1 m/s.
*October 12, 2014*

**physics**

V^2 = Vo^2 + 2g*h Vo = 0 = Vertical component of initial velocity. g = 9.8 m/s^2 h = 0.70 m. Solve for V in m/s. Note: The mass of the ball does not matter.
*October 12, 2014*

**electrical**

Incomplete.
*October 12, 2014*