Wednesday

February 22, 2017
Total # Posts: 13,198

**Calculus**

I tried to use partial fractions to do it, but it didn't work.

*December 27, 2015*

**Calculus**

Find the integral of 2/((2-x)(x+2)^2)dx.

*December 27, 2015*

**Physics**

I = (5^2/20^2)*X = (1/16)X W/m^2.

*December 26, 2015*

**Precalc**

The "j" means there is a 90-degree phase difference between the two terms and they cannot be added directly. Another method of writing the polar form: 2.83[45o].

*December 26, 2015*

**physics**

Work = F*d = 1500*Cos60 * 30 =

*December 26, 2015*

**Calculus**

Solve the following problem by separation of variables. T^2y'-t=ty+y+1 Y(1)=0 Y is a function of t.

*December 25, 2015*

**Calculus**

Wait, why is it the integral from 3-5 instead of 0-2?

*December 23, 2015*

**Calculus**

Sorry I forgot the dx after the integral.

*December 23, 2015*

**Calculus**

Find the integral from 0 to 2 of xsqrt(5-sqrt4-x^2)). The hint said to use substitution of u=sqrt(4-x^2), and that I needed one more substitution, but I don't know how to do it.

*December 23, 2015*

**Algebra 1**

Since there are 2 variables and only 1 Eq, I have to solve for 1 variable in terms of the other.

*December 23, 2015*

**Algebra 1**

12AB + 7B = 5A. 12AB - 5A = -7B. A(12B - 5) = -7B. Divide by (12B-5): A = -(7B/(12B-5)).

*December 23, 2015*

**physics**

Glad I could help.

*December 23, 2015*

**physics**

By definition, acceleration means to increase speed. When speed is decreasing it is called Deceleration. So you can't do both at the same time. When an object is moving, it is either accelerating, decelerating or moving at a constant speed. In other words, there are 3 ...

*December 23, 2015*

**physics**

d = 75N * 1m/1500N = 0.05 m. PE=0.5F * d = 0.5*75 * 0.05 = 1.875 J.

*December 21, 2015*

**physics 1**

1a. V = Vo + a*T1 = 0. T1 = -Vo/a = -22.5/-3.95=5.70 s To stop. V = Vo + a*T2 = 22.5. T2 = (22.5-Vo)/a = (22.5-0)/4.91=4.58 s. To accelerate back up to speed. T1+45+T2 = 5.70 + 45 + 4.58 = 55.3 s. 2. Hare: r*t = 1000. 1.5t = 1000. t = 666.67 s., Non-stop. Tortoise: r*t = 1000...

*December 20, 2015*

**physics**

Assuming the 3.5 m/s is horizontal: h = 0.5g*t^2. g = 9.8 m/s^2. t = ? A3. h = Vo*t + 0.5g*t^2 h = 230 m. Vo = -7.9 m/s(plane moving upward). g = 9.8 m/s^2. t = ? K5. The problem doesn't say what the captain is trying to do.

*December 20, 2015*

**physics**

Ma*Va + Mb*Vb = Ma*V + Mb*V. 30.7*2.64 + 109*1.29i + 30.7V + 109V. 81.05 + 140.6i = 139.7V. 162.3m/s[60o] = 139.7V. V = 1.16m/s[60o] N. of E.

*December 20, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*V. 2864*V1 + 856*0 = 2864*7.5 + 856*7.5. V1 = ?

*December 20, 2015*

**physics**

M1*V1 + M2*V2 = M1*28.7 + M2*V. 0.192*44.4 + 0.459*0 = 0.192*28.7 + 0.459V. V = ?

*December 19, 2015*

**physics**

M1*V1 + M2*V2 = M1*(-0.43) + M2*V. 0.13*0.22+0.22*(-0.30)=-0.43*0.13 + 0.22V. V = ? Multiply your answer by 100 to convert to cm/s.

*December 19, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*25. 24.9*22 + 13.2*11.8 = 24.9V + 13.2*25. V = ?

*December 19, 2015*

**physics**

M1*V1 + M2*V2 = M1*V + M2*V. 13.2*6.8 + 3*(-3.5) = 13.2V + 3V. V = ?

*December 19, 2015*

**physics**

a. V = Vo + g*t = 0. Vo - 9.8*2 = 0. Vo = 19.6 m/s. b. h = Vo*t + 0.5g*t^2. g = -9.8 m/s^2. t = 2 s. h = ?. c. Tr+Tf = 2 + 2 = 4 s. To fall back to top of bldg. Tr = Rise time. Tf = Fall time. 8-4 = 4 s. To fall from top of bldg. to gnd. h = Vo*t + o.5g*t^2. Vo = 19.6 m/s. t...

*December 18, 2015*

**Language Arts Project/Essay HELP!**

Ugh, I am not really good at writing, sorry but I fell I'm useless here. I would better recommend you to contcat Supreme essay service. Those guys are real professionals in what they do. Best of luck!

*December 18, 2015*

**MATH HELP**

A = (3)^5/2 * (3)^5/2 = (3)^10/2 = 3^5 = 243 in^2.

*December 17, 2015*

**College Algebra**

1. P1 = 0.64 + 0.30*0.64 = P2 = 0.64 + 0.40*0.64 = P3 = 2. P = 0.64 + m*0.64 = 1.10 0.64m = 1.10 - 0.64 = 0.46. m = 0.719 = 71.9%.

*December 17, 2015*

**Math**

A = 2*(15*5) + 2(30*5) + 30*15=900 Ft^2. = Total area to be painted. 900Ft^2 * 1gal/250Ft^2 = 3.6 Gal. of paint needed. Buy 4-1gal. cans.

*December 17, 2015*

**PHYSICS! Really Confused! Test Tmrw**

V^2 = Vo^2 + 2g*h = 0. h = -Vo^2/2g + 10 = -(5^2)/-19.6 = 11.28 m. h = 0.5g*T^2 = 11.28 m. 4.9T^2 = 11.28. T^2 = 2.30. T = 1.52 s. d = Vt*T = 30 * 1.52 = 45.6 m.

*December 17, 2015*

**Math**

(Y+1)+4

*December 16, 2015*

**physics**

See previous post: Wed,8-12-15, 12:14 AM.

*December 16, 2015*

**physics**

Correction: r = (d1+d2)/(43.3+T) = 1.99. (170.2+1.13T)/(43.3+T) = 1.99. Solve for T.

*December 16, 2015*

**physics**

d1 = 3.93m/s * 43.3s = 170.2 m. d2 = 1.13*T. r = (d1+d2)/T = 1.99 m/s. (170.2+1.13T)/T = 1.99. Multiply by T: 170.2 + 1.13T = 1.99T. 1.99T - 1.13T = 170.2. 0.86T = 170.2. T = 198 s.

*December 16, 2015*

**=**

Diode Connected: Vd + (I2+Id)R1 = 6 Volts. 0.7 + (I2+1.0)R1 = 6. 0.7 + I2*R1 + R1 = 6. Eq1: I2R1 + R1 = 5.3. Diode disconnected: V2 + I2*R1 = 6 Volts. 2 + I2R1 = 6. Eq2: I2R1 = 4. In Eq1, replace I2H1 with 4: 4 + R1 = 5.3. R1 = 1.3k = 1300 Ohms. In Eq2, replace R1 with 1.3k: ...

*December 16, 2015*

**Algebra**

You show the Ht. of only 7 players and the Wt. of only 6 players.

*December 16, 2015*

**Mathematics**

Show that the root equation (x-a)(x-b)=k^2 are always real numbers

*December 16, 2015*

**Mathematics**

Factorice 16(a-2b)^2-(a+b)^2 leaving your answer in the simplest form

*December 16, 2015*

**pre algebra**

P = Po(1+r)^n. Po = $2000. r = 0.051/2 = 0.0255 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * 7yrs. = 14 Compounding periods.

*December 15, 2015*

**Algebra**

1. x-1/5 = +-3. 5x - 1 = +-15. 5x = 16, and -14. X = 16/5, or -14/5. 2. D. decreasing nonlinear.

*December 15, 2015*

**Math**

0.64N. N = the number of boxes sold.

*December 15, 2015*

**physics**

Fr = 25N.[25o] + F2[-73o] Since the acceleration is parallel to the x-axis, the sum of Y components of velocity equals 0: 25*sin25 + F2*sin(-73) = 0. 10.57 -0.956F2 = 0. -0.956F2 = -10.57. F2 = 11.1N[-73o].

*December 15, 2015*

**physics**

Vo = 56m/s[35o]. Xo = 56*Cos35 = 45.9 m/s. Yo = 56*sin35 = 32.1 m/s. Y = Yo*t + 0.5g*t^2=32.1*2.9 -4.9*2.9^2 = 52 m. X = Xo*T = 45.9m/s * 2.9s = 133 m.

*December 15, 2015*

**Physics**

V^2 = Vo^2 + 2g*h. Vo = 0. V = ?

*December 14, 2015*

**Math**

1-3/4 = 4/4-3/4 = 1/4 Eaten.

*December 14, 2015*

**Science**

Eff. = 70/100 * 100%.

*December 14, 2015*

**Math**

a. d1 = 200/sin43 = 293 Ft. b. d2 = 200/tan43. c. d3 = d2/Cos16. d. h = 200 + d2*Tan16

*December 14, 2015*

**Business Math**

P = Po + Po*r*t P = 1700 + 1700*(0.12/12)*18 = $2,006.

*December 14, 2015*

**Physics**

V = 50,000m/3600s = 13.9 m/s. t = 20min ? = 1200 s. a = (V-Vo)/t = Vo = 0. a/g * 100% =

*December 14, 2015*

**Math**

The driver formed a rectangle with 10 km horizontal sides and 20 km vertical sides(northward).

*December 14, 2015*

**Physics Help**

Vo = 100m/s[60o]. Xo = 100*Cos60 = 50 m/s. Yo = 100*sin60 = 86.6 m/s. Y^2 = Yo^2 + 2g*h = 86.6^2 - 19.6*150 = 4560. Y = 67.5 m/s.

*December 13, 2015*

**Physics (angle Vector)**

Vb - 5.4i = 11.8. Vb = 11.8 + 5.4i = 13m/s[24.6o] N. of E. = Compass heading. 9-5.4i) =

*December 13, 2015*

**math**

Started with $X. x/3 + x/2 = x - 9.00. Multiply by 6 and solve for x.

*December 13, 2015*

**algebra**

Sold X none student tickets. Sold Y student tickets. Eq1: x + y = 937. Eq2: 5x + 3y = 3943. Multiply Eq1 by -3 and use Elimination Method.

*December 13, 2015*

**Algebra**

Right!

*December 13, 2015*

**physics**

Incomplete.

*December 13, 2015*

**physics**

Oops! I misread the numbers. Total=2*3.33 + 1*2.11 + 1*1 = 9.77 Lbs. 9.77Lbs * 5days/10Lbs. = 4.9 Days or 5 days.

*December 13, 2015*

**physics**

Total = 23*33 + 12*11 + 1*1 = 892 Lbs. 892Lbs * 5days/10Lbs = 446 Days.

*December 13, 2015*

**Mathematics**

(x-6)*Log4 = 3x*Log2. Divide by Log4: x-6 = 3x*Log2/Log4. x-6 = 3x*0.5 = 1.5x. x-1.5x = 6. -0.5x = 6. X = -12.

*December 13, 2015*

**8th grade algebra**

Correction: In your case, 48 is the area of the base: V = B*h = 48m^2 * 7m = 336 m^3 or 336 cubic meters. Again, take half of the base only when it is the diameter.

*December 12, 2015*

**8th grade algebra**

V = pi*r^2*h = 3.14*24^2*7 = 12,660.5 cm^3(Not m^3). V = B*h, B=Area of the base, V=pi*r^2*h 48 is not the area of the base; it is the diameter of the base. Diameter*height = Square units. Diameter/2 = Radius. So you take 1/2 of the diameter to get the radius. I hope this helps.

*December 12, 2015*

**Physics**

-2.8 + Vb = -10.4i. Vb = 2.8 - 10.4i. = 10.8m/s[-74.9o] = 74.9o S. of E. = 15.1o E. of S.

*December 11, 2015*

**algebra**

1/4 + 1/3 + 1/2 = 3/12 + 4/12 + 6/12 = 13/12 = 1 1/12. Impossible, because 13/12 is more than a whole pizza.

*December 11, 2015*

**Physics**

101kpa = 101*10^3pa = 1.01*10^5 pa.

*December 11, 2015*

**science**

Increasing the voltage increases the current and power(P = E*I); therefore, the voltage should be increased.

*December 11, 2015*

**Math**

15/0.6 =

*December 11, 2015*

**math**

V1 = 75i mi/h. V2 = 60 mi/h Tan A = V1/V2=75/60 = 1.2500, A = 51.3o. d1 = 250*sin51.3 = 195 mi. V1*T = 195, 75 * T = 195, T = 2.60 h. = 156 min.

*December 10, 2015*

**Marh**

Tan 32 = h/(X1+X2), (X1+X2) = h/Tan 32 = 918/Tan32 = 1469 Ft. Tan 58 = h/X1, X1 = h/Tan 58 = 918/Tan58 = 574 Ft. X1 + X2 = 1469. 574 + X2 = 1469. X2 = Distance between the 2 people.

*December 10, 2015*

**science**

Incomplete.

*December 10, 2015*

**algebra**

Sold X cakes. Sold Y pies. Eq1: x + y = 9. Eq2: 13x + 6y = 75. Multiply Eq1 by -6 and add the Eqs.

*December 10, 2015*

**physics**

Incomplete.

*December 9, 2015*

**physics**

k = 66N/8.3cm = 7.95 N/cm. F = 11cm * 7.95N/cm =

*December 9, 2015*

**phy 105**

A student's Blood pressure reading 120/70 millimeters of mercury.

*December 9, 2015*

**physics**

Ws = M*g = 81.2 * 9.8 = 796 N. = Wt. of sled = Normal force, Fn. Fk = u*Fn = 0.172 * 796 = 137 N. = Force of kinetic friction. Fap-Fk = M*a. Fap-137 = M*0 = 0. Fap = 137 N. = Force applied. Work = Fap*d = 137 * 3.12 = 427 J. = 0.427 kJ.

*December 9, 2015*

**Math**

(2,1), (4,5). Slope = (y2-y1)/(x2-x1) = (5-1)/(4-2) =

*December 9, 2015*

**geometry**

Correction: A = 4.83*5^2.

*December 9, 2015*

**geometry**

A = 4.83*s^2 = 3.83*5^2 = 120.75 m^2.

*December 9, 2015*

**Math**

An ordered pair is a single point and not a line; Therefore, it has no slope.

*December 9, 2015*

**Math**

A. Plug your calculated value of T(2 s.) into the given Eq and solve for S, the ht. B. Tr = 2 s. = Rise time(part A). h = 0.5g*Tf^2 = 264 Ft. g = 32Ft/s^2. Tf = Fall time. Tf = ? Tr + Tf = Time to reach gnd. C. S(o) = ht. when t = 0. In the given Eq, replace t with zero and ...

*December 9, 2015*

**Algebra**

(1 3/4)sugar/(2/3)milk = (7/4)/(2/3) = 7/4 * 3/2 = 21/8 = (2 5/8)/1

*December 8, 2015*

**Math**

r^2 = X^2 + Y^2 (-12)^2 + 5^2 = 169. r = 13. sin A = Y/r = 5/13 = 0.3846.

*December 8, 2015*

**Math**

a. X = Sheldon's distance. x+4 = Leonard's distance. c. x + x+4 = 26. d. 2x = 26-4 = 22. X = 11.

*December 8, 2015*

**math**

Let X = 3: 3x/2 + 7/2 = 2^x. 3*3/2 + 7/2 = 2^3. 9/2 + 7/2 = 8. 16/2 = 8. 8 = 8. So X = 3 satisfies the Eq.

*December 8, 2015*

**Math: Geometry**

New Line = EF/(1/2) = 2EF.

*December 8, 2015*

**contemporary mathematics**

392mi/t = 322/t + 20. 392 = 322 + 20t. 20t = 392 - 322 = 70. t = 3.5 h. r = 392mi/3.5h = 112 mi/h = Speed of the P. train. r = 322mi/3.5h = 92 mi/h = Speed of the F. train.

*December 8, 2015*

**Physics**

X = 5m/s. = Vw. Y = 4 m/s = Vd. a. Tan A = Y/X = 4/5 = 0.8, A = 38.7o. N. of E. = 51.3o E. of N. Vr = X/Cos A=5/Cos38.7=6.4 m/s[38.7o] = Resultant drone velocity. b. d = 120/sin38.7 = 192 m. To cross the field. V*t = 192, 4*t = 192, t = 48 s.

*December 7, 2015*

**physics**

M(g+a)= 478. a = ?

*December 7, 2015*

**physics**

See previous post: Fri, 11-28-14, 9:52 PM.

*December 7, 2015*

**math**

A = b*h = 300yds^2. 15h = 300. h = 20 yds.

*December 7, 2015*

**math**

Scale = 16in/5ft = 3.2 in/ft. Width = 15Ft * 3.2in/ft. = 48 in. Height = 10ft * 3.2in/ft. = 32 in. Area = 48 * 32 = Square inches.

*December 7, 2015*

**AC circuits**

Note: If the voltage across the resistor is incorrect, all voltages will be wrong.

*December 6, 2015*

**AC circuits**

I = VR/R = 10/4 = 2.5A. = Current through all components(R,L, and C). VL = I*XL = 2.5 * 6 = j15.0 Volts. Vc = I*Xc = 2.5 * 8 = -j20.0 Volts. Z = R + j(XL-Xc)) = 4 + j(6-8) = 4 - j2 = 4.47 Ohms[-26.6o]. Es = I*Z = 2.5 * 4.47 = 11.2 Volts. Pf = Cos(-26.6) = 0.894 = Power factor...

*December 6, 2015*

**Physics**

There are errors in your problem that makes it difficult to understand. X = 3 km/h. Y = 10 km/h. Tan A = Y/X = 10/3 = 3.33333. A = 73.3o N. of E. = 16.7o E. of N. d1 = 5/Tan73.3 = 1.50 km downstream. d2 = Sqrt(1.5^2 + 5^2) = 5.22 km to cross. 2. Direction to offset affect of ...

*December 6, 2015*

**Physics**

L = 40 + 12*10^-6/Co(T-20) = 40.01. 40 + 12*10^-6T - 240*10^-6 = 40.01. 40 - 0.00024 + 12*10^-6T = 40.01. 39.99976 + 12*10^-6 = 40.01. 12*10^-6T = 40.01 - 39.99976 = 0.01024. T = 853.333 Degrees C.

*December 6, 2015*

**math**

post it.

*December 6, 2015*

**Physics**

Ws = M*g = 150*9.8 = 1470 N. Fp = 1470*sin40 = 945 N.=Force parallel to the ramp. Fn = 1470*Cos40 = 1126 N. = Normal force Fk = u*Fn = 0.54 * 1126 = 608 N. = Force of kinetic friction. Fp-Fc-Fk = M*a. 945-Fc-608 = M*0 = 0. 337-Fc = 0. Fc = 337 N. = Force of the curator. a. ...

*December 5, 2015*

**Math**

3x - 5x = 18. 2x = 18. X = 9. 3x = 3*9 = 27 = 1st number. 5x = 5*9 = 45 = 2nd number.

*December 5, 2015*

**MATH**

7.48*10^5.

*December 5, 2015*

**math**

I = 280/40 * 4 = 28 Amps. or E = I*R = 4*280 = 1120 v. I = E/R = 1120/40 = 28 Amps.

*December 3, 2015*

**PreCalculas**

2. D(3/4,-3), V(h,-3), F(5/4,-3). 1/2a = 5/4-3/4 = 2/4 = 1/2. 2a = 2, a = 1. 1/4a = 1/(4*1) = 1/4. h = 3/4 + 1/4a = 3/4 + 1/4 = 4/4 = 1. X = a(y-k)^2 + h. X = (y+3)^2 + 1, Vertex form. X = y^2 + 6y + 10, Standard form.

*December 3, 2015*

**PreCalculas**

1. V(2,5), F(2,-3). 1/4a = -3-5 = -8. 4a = -1/8. a = -1/32. Y = a(x-h)^2 + k. Y = (-1/32)(x-2)^2 + 5, Vertex Form

*December 3, 2015*

**physics**

See previous post: Tue, 12-1-15, 12:30 PM.

*December 3, 2015*