Wednesday
September 28, 2016

# Posts by Henry

Total # Posts: 12,062

Mathematics
Let x = speed of car X y = speed of car Y L = distance of AB "meet 80minutes later" L = 80x + 80y (distance = velocity * time) The time for car X to reach town B is: tx = ty + 36 But, tx = L/x and ty = L/y Substitute, tx = ty + 36 [80(x+y)]/x = [80(x+y)]/y + 36 ...
July 9, 2015

Mathematics
A car X left town A for town B at the same time that another car Y left town B for town A, each travelling at constant speed. They met 80 minutes later and car X arrived at town B 36 minutes after car Y reached town A. How long did it take car X to reach town B?
July 9, 2015

Physics
Work = The change in kinetic energy: Work = KE2-KE1 = 0.5*M*V2^2 - 0.5*M*V1^2 = 31*5^2 - 31*2^2 = 651 J. Work = (Fe-30)*d = 651. (Fe-30)*25 = 651. 25Fe - 750 = 651. 25Fe = 1401. Fe = 56 N. = Force exerted.
July 9, 2015

physics
M*g = 95 * 9.8 = 931 N. = Wt. of load. Fp = 931*sin50 = 713.2 N. = Force parallel to the incline. Fn = 931*Cos50 = 598.4 N. = Normal = Force perpendicular to the incline. Fk = u*Fn = 0.10 * 598.4 = 59.84 N. = Force of kinetic friction. a. Work = Fk*d = 59.84 * 30 = 1795 N. b. ...
July 9, 2015

Physics
Correction: b. D1 + D2 = 30+300 = 330 m. 0.5*1.17*t^2 + 0.5*1.1*t^2 = 330. 0.585t^2 + 0.55t^2 = 330. 1.135t^2 = 330. t^2 = 290.75. t = 17.1 s.
July 9, 2015

Physics
D1 = Distance traveled by train on left. D2 = Distance traveled by train on right a. D1 + D2 = 30 m. 0.5a1*t^2 + 0.5a2*t^2 = 30 0.5*1.17*t^2 + 0.5*1.1*t^2 = 30 0.585t^2 + 0.55t^2 = 30. 1.135t^2 = 30. t^2 = 26.43 t = 5.14s. D1 = 0.5*a1*t^2. a1 = 1.17 m/s^2. t = 5.14 s. Solve ...
July 9, 2015

Algebra
F(x) = Y = -8x^2 +3x +7 = 0 Use Quadratic Formula: X = (-B +/- sqrt(B^2-4AC))/2A X = (-3 +/- sqrt(9+224))/-16 X = (-3 +- sqrt233)/-16. X = (-3 +- 15.26)/-16 = -0.767 and 1.14.
July 8, 2015

Calculus
Can someone provide a function that satisfies all of the following: • p(−1) = 3 and lim x→−1 p(x) = 2 • p(0) = 1 and p'(0) = 0 • lim x→1 p(x) = p(1) and p'(1) does not exist Thanks!
July 8, 2015

ITT
PE = 20J. at top of incline. PE = 10J. halfway down the incline. KE + PE = 20 KE + 10 = 20 KE = 10J. KE = 0.5M*V^2 = 10 M = 1kg. Solve for V.
July 8, 2015

Math
Diagram: Draw a rectangle with the vert. sides representing the ht. of the Metro Bldg.(h1).and hor. sides are the distance between bldgs.(45m). Draw a diagonal from lower left to upper right and notice that the alternate interior angles are equal(56o).Extend the vert. side on ...
July 7, 2015

Physics
M*g = 60 * 9.8 = 588 N. = Wt. of the person. Eq1: T1*Cos9.4 + T2*Cos35.3 = 0. T1*Cos9.4 = -T2*Cos35.3. T1 = -0.827T2. Eq2: T1*sin9.4 + T2*sin35.3 =-588[270o]. 0.1633T1 + 0.578T2 = 0 + 588 Replace T1 with -0.827T2: 0.1633*(-0.827T2) + 0.578T2 = 588 -0.135T2 + 0.578T2 = 588 0....
July 7, 2015

physics 20
See Related Questions: Tue, 2-7-12, 11:59 AM.
July 6, 2015

Physics
Yo = 15*sin30 = 7.5 m/s. = Ver. component of initial velocity. Y^2 = Yo^2 + 2g*h = 0. h = -Yo^2/2g = -(7.5)^2/-19.6 = 2.87 m. above the roof. V^2 = Vo^2 + 2g*(h+40) = 0 +19.6*42.87 = 840.25 V = 29 m/s.
July 4, 2015

physics
July 3, 2015

physics
1. Work = 0.5M*V^2 = 0.5*1500*20^2 = 300,000 J. 2. hp * 746W/hp = 1492 Watts=1492J/s. P = F*V = Mg * V = 1492 J/s. 200*9.8 * V = 1492 1960V = 1492 V = 0.76 m/s.
July 3, 2015

Math
There is no difference between the number of males or females who go to their primary care physician for an annual exam.
July 3, 2015

Math
2. P = Po*r*t/(1-(1+r)^-t) Po = 9500 - 800 = \$8700. r = (9%/12)/100% = 0.0075 = Monthly % rate expressed as a decimal. P = (8700*0.0075*48)/(1-1.0075)^-48 = \$10,392. P/t = 10,392/48 = \$216.50/mo. 3. P = Po + I = Po + Po*r*t. P = 2419 + 2419*0.052*36 = \$2796.36. P/t = 2796.36/...
July 2, 2015

physics
See Related Questions: Tue, 11-23-2010, 5:05 AM.
June 29, 2015

Physics
d1 = Vo*t1 + 0.5g*t1^2 = 59.7 m. 0 + 4.9t1^2 = 59.7. t1^2 = 12.18. t1 = 3.49 s. V1 = Vo + g*t1 = 0 + 9.8*3.49 = 34.2 m/s. V2^2 = V1^2 + 2a*d2 = 3.41^2 = 11.63. 34.2^2 - 3.2d2 = 11.63. -3.2d2 = 11.63-1169.64 = -1158. d2 = 362 m. d2 = V1*t2 + 0.5a*t2^2 = 362. 34.2*t2 - 0.80*t2^2...
June 29, 2015

Amplifiers
Beta = Ic/Ib = 10ma/1ma = 10.
June 23, 2015

physics
M*g = 45 * 9.8 = 441 N. = Wt. of trunk. Fn = 441 + F*sin33. Fs = u*Fn = 0.55(441+F*sin33) = 242.6 + 0.3F. (F-Fs) = M*a. (F-(242.6+0.3F) = M*0. F - 242.6 - 0.3 = 0 0.7F = 242.6. F = 347 N.
June 23, 2015

physics
M1*V1 + M2*V2 = M1*V3 + M2*V4 1100*22 + 2300*0 = 1100*(-11) + 2300*V4 24,200 = -12,100 + 2300V4 2300V4 = 36,300 V4 = +15.8 m/s = Velocity of the truck.
June 19, 2015

physics
June 19, 2015

physics
496/1127 = 0.44 = 44% sin A = 0.85/2.1. A = 23.9o. Fp = 1127*sin23.9 = 457 N. = Force parallel to the ramp. Fn = 1127*Cos23.9 = 1,030 N. = Force perpendicular to the ramp = Normal force. Eff. = Fp/Fap = 457/496 = 0.92 = 92%
June 19, 2015

physics
T1[26.5o] and T2[131.5o], CCW. T1*Cos26.5 + T2*Cos131.5 = 0 T1*Cos26.5 = -T2*Cos131.5 T1 = 0.74T2 T1*sin26.5 + T2*sin131.5 + 115*sin270 = 0. Replace T1 with 0.74T2: 0.74T2*sin26.5 + T2*sin131.5 + 115*sin270 = 0. 0.33T2 + 0.749T2 - 115 = 0 1.079T2 = 115. T2 = 106.6 N. T1 = ....
June 17, 2015

Physics
a. V^2 = Vo^2 + 2g*h = 0 h = -Vo^2/2g = -225/-19.6 = 11.5 m. b. V = Vo + g*Tr = 0. Tr = -Vo/g = -15/-9.8 = 1.53 s. = Rise time. 0.5g*Tf^2 = 11.5-5 = 6.5 m. 4.9Tf^2 = 6.5 Tf^2 = 1.33 Tf = 1.15 s. = Fall time. Tr+Tf = 1.53 + 1.15 = 2.68 s. To catch the ball.
June 17, 2015

Physics
d1 = 0.5a*T1^2 = 45 m. Solve for T1. 0.5*0.88*T1^2 = 45. T1^2 = 102.3 T1 = 10.11 s. to run the 1st 45 m. V = a*T1 = 0.88*10.11 = 8.9 m/s. d2 = V*T2 = 8.9 * T2 = 100-45 = 55 m. T2 = 55/8.9 = 6.18 s. To run the last 55 m. T = T1+T2 = 10.11 + 6.18 = 16.29 s. to run the race.
June 17, 2015

Physics
a = (Fap-Fk)/M = (25-10)/5 3 m/s^2. d = 0.5a*t^2.
June 17, 2015

Po = 575-25 = \$550 = Amount of loan. I = Po*r*t = 550*0.15*2yrs = \$165. P = Po + I = 550 + 165 = \$715 = Total cost. P/t = 715/24mo. = \$29.79/mo.
June 17, 2015

science
F = ma. a = F/m = -2500/1125 = -2.22 m/s^2.
June 17, 2015

physics
V^2 = Vo^2 + 2a*d = 0 10^2 + 2a*0.04 = 0 2a*0.04 = -100 a = -1250 m/s. Note: The negative sign means that the acceleration opposes the motion.
June 17, 2015

secondary
Do you mean: y+2x/4 = x/3 or (y+2x)/4 = x/3 y + 2x/4 = x/3 Multiply both sides by 12: 12y + 6x = 4x. 2x + 12y = 0. m = -A/B = -2/12 = -1/6. (y+2x)/4 = x/3. Multiply both sides by 12: 3y + 6x = 4x. 2x + 3y = 0 m = -A/B = -2/3.
June 16, 2015

furthe math
Parallel lines have equal slopes(gradients): m1 = m2 = -3.
June 16, 2015

further mathematic
Parallel lines have equal gradients(slopes); m1 = m2 = -3.
June 16, 2015

Science
M*g = 9.5 N. M*9.8 = 9.5 M = 0.969 kg. Wt. = M*g = 0.969 * 1.64 = 1.58 N.
June 16, 2015

Maths
Area = 364/16 = 22.75 m^2 Width = W meters. Length = W+3 meters. Area = (W+3) * W = 22.75 W^2 + 3W - 22.75 = 0 Use Quadratic Formula: W = 3.5 meters = Width.
June 15, 2015

basic electronics
R3 = R Ohms. R2 = 2R Ohms. R1 = 2R/3 Ohms. 1/R1 + 1/R2 + 1/R3 = 1/1000 1/(2R/3) + 1/2R + 1/R = 1/1000 3/2R + 1/2R + 1/R = 1/1000 3/2R + 1/2R + 2/2R = 1/1000. 6/2R = 1/1000. 3/R = 1/1000. R/3 = 1000. R = 3000 Ohms. R1 = 2R/3 = 6000/3 = 2000 Ohms. R2 = 2R = 2*3000 = 6000 Ohms. ...
June 14, 2015

Physics
15t = 5 t = 0.333h = 20 min. 11.6t = 5 t = 0.431h = 26 min. T = 26 - 20 = 6 min. waiting time.
June 12, 2015

Physics
Y^2 = Yo^2 + 2g*h = 0 Yo^2 - 19.6*0.0674 = 0 Yo^2 = 1.32 Yo = 1.15 m/s = Ver. component of initial velocity. Yo = Vo*sin50 = 1.15 Vo = 1.15/sin50 = 1.50 m/s = Initial velocity. Xo = Vo*Cos50 = 1.50*Cos50 = 0.964 m/s = Hor. component of initial velocity. Dx = Xo*T = 1.06 m. 0....
June 12, 2015

Science
1. F max = 20 + 20 = 40 N. @ 0o. 2. The velocity is zero and not changing; therefore, the acceleration is zero also. F = M*a = M*0 = 0.
June 12, 2015

Science
20 + 20 = 40 N. @ 0o. Answer = 0o.
June 12, 2015

physics
Correction: Vo = 49 m/s.
June 11, 2015

physics
First Stone: d = 0.5g*t^2 = 35 m. 4.9t^2 = 35 t^2 = 7.14 t = 2.67 s Second Stone: t = 2.67-2.0 = 0.67 s. to travel 35 m. d = Vo*t + 0.5g*t^2 d = Vo*0.67 + 4.9*0.67^2 = 35 Vo*0.67 = 35 - 2.2 = 32.8 Vo = 49 m
June 11, 2015

science
P = 10*Cos30 = 8.66 N. Q = 10*Cos(90-30) = 5 N.
June 8, 2015

Math
Cos x = -0.40 X = 113.6o
June 7, 2015

physics
Fr = ((Vs+Vt)/(Vs-Vd))*Fd Fr = ((343+42.6)/(343-0))*95300Hz = 107,136 Hz = Freq. reflected.
June 5, 2015

Physics
V^2 = Vo^2 + 2g*h = 1 10^2 - 19.6h = 1 -19.6h = -99 h = 5.05 m.
June 2, 2015

physics
M*g = 25kg * 9.8N/kg = 245 N. = Wt. of block. = Normal(Fn). Fap = 120 N. = Force applied. Fk = u*Fn = 0.34 * 245 = 83.3 N. a = (Fap-Fk)/M m/s^2.
June 2, 2015

Digital Circuits
b. Limit current.
May 31, 2015

geometry
(8,-1), (5,-2), (x,y) 5-8 = 1/3(x-8) -9 = x-8 X = -1 -2-(-1)) = 1/3(y-(-1)) -1 = 1/3(y+1) -3 = y+1 Y = -4
May 31, 2015

geometry
(8,-1), (5,-2), (x,y) x-5 = 1/3(x-8) 3x-15 = x-8 2x = 7 X = 3.5 y-(-2) = 1/3(y-(-1)) y+2 = 1/3(y+1) 3y+6 = y+1 2y = -5 Y = -2.5
May 31, 2015

mechanics of dynamic
55km/h * 2h = 110 km Head start. d1 = d2 110 + 55*t = 80t -25t = -110 t = 4.4 Hours.
May 31, 2015

math
Tan 45 = h/d1 h = d1*Tan45 Tan55 = h/(d1-40) h = (d1-40)*Tan55 h = d1*Tan45 = (d1-40)*Tan55 d1*1 = (d1-40)*Tan55 Divide both sides by Tan55: 0.7d1 = d1-40 0.3d1 = 40 d1 = 133.3 Ft. h = d1*Tan45 = 133.3 * 1 = 133.3 Ft.
May 30, 2015

physics
Tan A = Y/X = 35/-12 = -2.91667 A = -71.1o = 71.1o N. of W.
May 30, 2015

college geometry
Another Method: a. X = (3+5)/2 = 4 Y = (4+1)/2 = 2.5
May 28, 2015

college geometry
a. A(3,4), C(x,y), B(5,1). Points A and B are equidistance from C: x-3 = 5-x X = 4 y-4 = 1-y Y = 2 1/2 b. A(0,2), C(x,y), B(0,6). x-0 = 0-x X = 0 y-2 = 6-y Y = 4 c. Same procedure as a, and b. d. A(2a,0), C(x,y), B(0,2b). x-2a = 0-x 2x = 2a X = a y-0 = 2b-y 2y = 2b Y = b
May 28, 2015

science
F = M*a a = F/M = 52.2/3.47 = 15 m/s^2 V = Vo - a*t V = 0 Vo = 17.4 m/s a = 15 m/s^2 t = ?
May 28, 2015

Trig/Geometry
Tan 15 = h/d Tan 15 = 145/d d = 145/Tan 15 = 541.2 Ft. Or if the angle between the line of sight and the ver.(145Ft) is 15o, then Tan 15 = d/145 d = 145*Tan 15 = 38.85 Ft.
May 28, 2015

physics eduction
k = 50N/(25-20)cm = 10N/cm. Length = 20cm + 100N*1cm/10N = 30 cm.
May 28, 2015

physics
Fn = 8.7[125o] + 12.9[0o] X = 8.7*Cos125 + 12.9 = 7.91 N. Y = 8.7*sin125 = 7.13 N. Fn = sqrt(X^2+Y^2) = sqrt(7.91^2*7.13^2) = 10.65 N.
May 28, 2015

Science
Correct.
May 27, 2015

physics
a = F/M = 35/0.2 = 175 m/s^2 V = Vo + a*t = 0 + 175 * 0.018 = 3.15 m/s
May 27, 2015

Algebra 1
Eq1: Y = x^2 + 5x - 9 Eq2: Y = 2x + 1 ? In Eq1, replace Y with 2x + 1 2x + 1 = x^2 + 5x - 9 x^2 + 5x - 9 - 2x - 1 = 0 x^2 + 3x -10 = 0 -10 = -2*5. Sum = -2 + 5 = 3 = B. (x-2)(x+5) = 0 x-2 = 0 X = 2 Y = 5.(Substitute 2 for x in Eq1 or Eq2) x+5 = 0 X = -5 Y = -9(Substituted -5 ...
May 25, 2015

Algebra
Viruses = 30 * 9/3 * 2 = 180
May 25, 2015

math
P = Po(1+r)^n r = (0.06/4) = 0.015 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs. = 20 Compounding periods. P = 8500(1.015)^20 = 11,448.27 I = = (P-Po)/T = (11448.27-8500)/5 = 589.65 = Int. per yr. APR = 589.65/8500 = 0.0694 = 6.94%
May 22, 2015

physics
Vo = 30mi/h = 30*5280Ft/3600s = 44 Ft/s V^2 = Vo^2 + 2g*h = 0 h = -Vo^2/2g + ho = -(44^2)/-64 + 160 = 190.25 Ft above gnd. V^2 = Vo^2 + 2g*h = 0 + 64*190.25 = 12,176 V = 110.3 Ft/s.
May 21, 2015

physics
D = -52 + 44[146.8o] + 25i D = -52 + -36.8 + 24.1i + 25i D = -88.8 + 49.1i, Q2.
May 21, 2015

physics
Density = M/V = 7.55kg/680m^3 = 0.0111kg/m^3 Note: The vol. of the water dispersed = The Vol. of the statue.
May 21, 2015

math
V = Vo + Vo*r*t V = 8000 + 8000*(0.10/360)*240 = \$8,533.33
May 20, 2015

physical science
Fg = M*g = 675 N. M*9.8 = 675 M = 69 kg
May 20, 2015

Physics
Fp = Mg*sin A = Force parallel to the incline and acting downward. When the angle is increased, Fp increases which increases the acceleration: a = Fp/M. Friction is assumed to be negligible. The increase in acceleration results in an increase in velocity: V = a*t.
May 19, 2015

physics
Xo = 40*Cos60 = 20 mi/h.
May 18, 2015

math
An oil painting is worth \$400. Its value increases by 7% each year(compounded annually) What is the value of the painting after 6 years? How would the graph change of the initial value of the oil painting was more than \$400? Less than \$400?
May 18, 2015

math
V = Vo(1+r)^6 Vo = 400 r = 0.07 V = ?
May 18, 2015

science
PE = M*g*h Joules M = 5kg g = 9.8 m/s^2 h = 100 m PE = ?
May 18, 2015

physics
Vbc = Vb + Vc = 6m/s[115o] Vb - 3 = 6*cos115 + 6*sin115 Vb - 3 = -2.54 + 5.44i Vb = 0.46 + 5.44i, Q1 Tan A = Y/X = 5.44/0.46 = 11.82609 A = 85.2o N. of E. = 4.8o W. of N. = Direction. Vb = Y/sin A = 5.44/sin 85.2 = 5.46 m/s.
May 18, 2015

Physics
F = -40 + 50[23o] X = -40 + 50*Cos23 = 6.02 N. Y = 50*sin23 = 19.5 N.
May 18, 2015

physics
M*g = 8 * 9.8 = 78.4 N. = Wt. of block. Fp = 78.4*sin40 = 50.4 N. = Force parallel to the incline. Fn = 78.4*cos40 = 60.1 N. = Normal force Fk = u*Fn = 0.35 * 60.1 = 21 N. = Force of friction. a = (Fp-Fk)/M = (50.4-21)/8 = 3.68 m/s^2 d = 0.5a*t^2 = 0.5*3.68*3^2 = 16.54 m.
May 18, 2015

PHYSICS
Vbw = 1km/15Min = 1km/0.25h = 4km/h = Velocity of boat with respect to the water. Vbw = Vb + Vw = 4i 5i + Vw = 4i Vw = -1i = 1km/h[-90o] = 1km/h Due South
May 18, 2015

PHYSICS
Vsw = Vs + Vw = 10 + 5i, Q1. Tan A = Vw/Vs = 5/10 = 0.500 A = 26.6o E. of N. Direction = 26.6o W. of N.
May 18, 2015

math
P = Po + Po*r*t P = 10000 + 10000*(0.1219/360)*60 P = 10000 + 203.17 = \$10,203.17 On 60th day. I = (10,203.17-5000)*(0.1219/360)*60 = \$105.71 For last 60 days. It = 203.17 + 105.71 = \$308.88 = Total int. paid. I = 10000*(0.1219/360)*120 = \$406.33 For 120 days. 406.33 - 308.88...
May 16, 2015

algebra
12x + 16y = 150
May 14, 2015

math
See Related Questions: Fri, 8-31-12, 1:49 AM.
May 14, 2015

math
See previous post: Thu, 5-14-15, 1:23 PM
May 14, 2015

math
1. 16t^3 - 50t^2 + 36t = 2t(8t^2 - 25t + 18) A*C = 8*18 = 144 = -9*(-16). Sum = -25 = B. 2t((8t^2-16t) - (9t-18)) 2t(8t(t-2) - 9(t-2)) = 2t(8t-9)(t-2) 4. y^2 + 12y + 35 35 = 7*5, Sum = 7 + 5 = 12 = B. (y+7)(y+5)
May 14, 2015

math
12N * 20N = 360 240N^2 - 360 = 0 2N^2 - 3 = 0 2N^2 = 3 N^2 = 1.5 N = 1.225 = 122.5% %Increase = 122.5% - 100% = 22.5% = The amount each dimension is increased. Length = 20 * 1.225 = 24.5 Ft. Width = 12 * 1.225 = 14.7 Ft. Area = 24.5 * 14.7 = 360.15 Ft^2.
May 13, 2015

Math
d = 15*cos58 = 7.95 m. = Distance from base of the wall. Cos A = d/L = 7.95/12.6 = 0.63086 A = 50.9o
May 13, 2015

geometry
a. (h,k) = (2,-3) b. r = sqrt 9 = 3 D = 2*r = 2 * 3 = 6
May 13, 2015

Math
P = Po + Po*r*t P = 2500 + 2500*(0.11/12)*6 = Note: (0.11/12) = Monthly % rate.
May 13, 2015

Physics
2Hz = 2 cycles/s(c/s). Circumference = pi*2r = 3.14 * 10 = 31.4 m. V = 2c/s * 6.28rad/c = 12.56 rad/s
May 13, 2015

Math
Score = 4 * 14 = 56 Points
May 13, 2015

Math
P = Po + Po*r*t = \$1312.50 1200 + 1200*(r/12)*9 = 1312.50 900r = 1312.50 - 1200 = 112.50 r = 0.125 = 12.5% APR.
May 13, 2015

Math
Cost = 100% - 3% = 97% of original price 0.97Po = 4195.25 Po = \$4,325
May 13, 2015

Electronics, Physics, Math
E = 30 Vdc R1 = 80 Ohms R2 = 1,000 Ohms R3 = 4,200 Ohms V2 = ? I = E/(R1+R2+R3) = 30/5,280 = 0.00568A V2 = I * R2 =
May 12, 2015

Physics
Impulse = F*t = 25 * 0.16 = 4
May 12, 2015

algebra 2
Y = x^2 - 5x + 4 h = Xv = -B/2A = 5/2 = 2.50 = Value of X at the vertex. k = 2.5^2 - 5*2.5 + 4 = -2.25 = Value of Y at the vertex. D(2.5,Y1), V(2.5,-2.25), F(2.5,Y2) In a y-parabola, the y-coordinates vary while the x-coordinates remain constant and is equal to h(2.50). The ...
May 12, 2015

physics
M1*V1 + M2*V2 = M1*V + M2*V 1030*3.4 + 1140*0 = 1030V + 1140V V = ?
May 12, 2015

physics
Select: R1 = 33k R2 = 120k R3 = 120k 1/Req = 1/33k + 1/120k + 1/120k = 0.0469697k Req = 21.3k
May 12, 2015

Electronics, Physics
Correction: Rt = 10 + (60*5)/(60+5) = 10 + 4.62 = 14.62 Ohms.
May 12, 2015

Electronics, Physics
Rt = 10 * (60*5)/(60+5) = 10 + 4.62 = 14.62 Ohms = Total resistance. Note: Based on the values given, the total resistance will be less than 15 ohms.
May 12, 2015