Math
P = Po*e^rt r*t = (3%/100%) * 2yrs. = 0.06 P = 2000*e^0.06 = $2123.67
Algebra
V = Vo + g*t t = (V-Vo)/g = (0-45)/-32 = 1.41 s. ht. = 6 + 45*1.41 - 0.5*32*(1.41)^2 = 37.64 Ft.
math
d = Vo*t + 0.5a*t^2 d = 4.5*7 + 0.5*2.5*7^2 = 92.75 m.
algebra
10/3x + 4/3 = (7+x)/2x Multiply both sides by 6x: 2*10 + 8x = 3(7+x) 20 + 8x = 21+3x 8x-3x = 21-20 = 1 5x = 1 X = 1/5.
Algebra
NOTE: B^2 = (-3)^2 = 9.
Algebra
Y = x^2 - 3x + 6. B^2 = (-3) = 9. 4*A*C = 4*1*6 = 24. B^2 - 4AC = 9 - 24 = -15 = The value under the radical. Since the value under the radical is negative, there are 2 imaginary solutions. Therefore, the graph does not touch or cross the x-axis. So there are no x-intercepts. ...
algebra-word problem
X+11 = 121 h.
algebra-word problem
X = The # of hours before the increase. (X+11) = The # of hours after the increase. (x+11)/x = 1.1 1.1x = x+11 1.1x - x = 11 0.1x = 11 X = 110 h.
college physics
Power = 7.0hp * 746W/hp = 5222 Watts = 5222 Joules/s. Mass = 475Lbs * 0.454kg/Lb = 215.65 kg.= Mass of boiler. d = 38Ft./3.3Ft/m = 11.52 m. Work=F*d = mg * d=215.65*9.8 *11.52= 24,346 Joules. t = 24346J * 1s/5222J = 4.66 s.
applied physics
Fp = 35*cos40 = 26.8 N. = Force parallel to yard. Work = Fp*d = 26.8 * 900 = 24,130 Joules
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