# Posts by Henry

Total # Posts: 13,444

**algebra**

1,2,3,4,5,6. 1,2,3,4. 2,3,4,5. 3,4,5,6. 4,5,6,1. 5,6,1,2. 6,1,2,3. 6 Ways.

**Math**

20,322*12/.004 = 60,966,000 Sheets. The answer is B.

**Physics**

Please proof-read your problem.

**classical mechanics**

A projectile is launched down ward from the top of inclined plane of angle alpha in the direction making an angle beta with the incline. assuming the projectile hits the incline, find the expression for the range and determine the maximum expression for the range down the ...

**calculus.can you help me on these as well@sir collins**

let sin^7x =(sin^2(x))^3sin(x) dx. sin^6x= (sin^2(x))^3 integral of(sin^2(x))^3sinx using identity sin^2x= 1-cos^2x integral of (1-cos^2x)^3sinx dx what if u=cosx du=-sinx. -integral(-u^6+3u^4-3u^2+1)du. =-(-u^7/7+3u^5/5-u^3+u)+k substituting for u give us the following -(-...

**Math**

Range = (1200)^2*sin(2A)/32 = 3000, 45,000*sin(2A) = 3000, sin(2A) = 0.0667, 2A = 3.82, A = 1.9 Degrees.

**math**

Train B travels X mi/h. Train A travels (x-6) mi/h. X*t/(x-6)t = 230/200, X/(x-6) = 230/200, 200x = 230x-1380, -30x = -1380, X = 46 mi/h, x-6 = 46-6 = 40 mi/h.

**Physcis- Energy**

KE = 0.5M*V^2.

**Math**

(4/11)/24 = (7/11)/L, (4/11)L = 24(7/11), L = 42 litres in tank.

**science**

W = F*d = M*g * d = 69*9.8 * 10 = 6762 Joules. P = W/t = 8762 J./12s. = 564 J./s = 564 Watts.

**physics**

a helium nuclide of mass M1 moving with initial velocity V is incident on a stationary of mass M1. After collision M1 was deflected through an angle x and M2 an angle y. If the velocities of the nuclides after collision were V1 and V2 respectively, show that for an elastic ...

**science**

a helium nuclide of mass M1 moving with a velocity Vo is incident on a stationary nuclide of mass M2. After collision M1 was deflected through an angle x and M2 an angle y. If the velocities of the nuclides after collision were V1 and V2 respectively show that for an elastic ...

**Algebra**

A. V = Vo + g*Tr = 0, Tr = -Vo/g = Rise time. T1 = Tr + Tf = Time to rise from launching point(90Ft.) to max ht. and return to launching point. Tr = Tf; Therefore, T1 = 2Tr = -2Vo/g. Vo*T2 - 16T2^2 = 90, 50T2-16*50^2 = 90, 50T2-40,000 = 90, 50T2 = 40,090, T2 = 802 Seconds To ...

**science**

M1*V1 + M2*V2 = M1*V3 + M2*V4. 8*10 - 12*2 = 8*3 + 12*V4. 80-24 = 24 + 12V4. 12V4 = 32, V4 = 2.67 m/s, East.

**Personal Finance**

I chose C.

**Reverse math confused**

C = (p-2)1.2 = 9.00, p = $9.50.

**Polynomials**

6t+2 + 9t-6 = 15t - 4. = Total earnings.

**phy**

d = 2844rev * 6.28rad/rev = 17,860 radians. a. V^2 = Vo^2 + 2a*d. V = 136 rad/s, a = 0.130 rad/s, Vo = ?. b. V = Vo + a*t. V = 136 rad/s, a = 0.130 rad/s^2, t = ?. 2

**Science**

V = Vo + a*t = 15 m/s, Vo = 25 m/s, a = -2 m/s^2, t = ?.

**Math help**

a. C = 4.70d. b. C = 4.70d - 1 = 4.70*4 - 1 = $17.80. C = 4.70*7 = $32.90.

**Math help!**

d = 66t.

**maths**

Vo = 40.000m/3600s = 11.11 m/s. V = Vo + a*t = 0, 11.11 - 0.5t = 0, -0.5t = -11.11, t = 22.22 s.

**Find the area of the segment of a circle of radious 21 cm and corresponding central angle 30**

As = 30/360 * Ac = 30/360 * 3.14*21^2 = 115.4 cm^2.

**math**

-16x^2 + 24x + 16 = 0. A. Divide by 8: -2x^2 + 3x + 2 = 0, A*C = -2*2 = -4 = -1 * 4. Sum = -1 + 4 = 3 = B, -2x^2 + (-x+4x) + 2 = 0, (-2x^2-x) + (4x+2) = 0, -x(2x+1) + 2(2x+1) = 0, (2x+1)(-x+2) = 0, 2x+1 = 0, X = -1/2. -x+2 = 0, X = 2. X-intercepts: (-1/2,0), (2,0). B. Since ...

**Math**

V = 390mi/h[28o]N of W. D = 390mi/h[28o] * 3h = 1170 mi[28o]N. of W. Dn = 1170*Cos28 = Dw = 1170*sin28 =

**pre algebra**

Width = W cm. Length = W+6 cm. ((W+6)-3)(W+3) = 64 cm^2. (W+3)(W+3) = 64, W^2+6W+9 = 64, W^2+6W-55 = 0, -55 = -5*11, -5+11 = 6 = B, (W-5)(W+11) = 0, W-5 = 0, W = 5. W+11 = 0, W = -11. Original Dimensions: W = 5 cm, L = 5+6 = 11 cm.

**PHY 1004**

Range = Vo^2*sin(2A/g. A = 30o, g = 9.8 m/s^2.

**Physics**

1. Basically, a loudspeaker converts electrical energy to sound.

**Math**

P = Po(1+r)n = 100,000. r = 0.072/2 = 0.036 = Semi-annual % rate expressed as a decimal. n = 2Comp./yr. * t yrs. = 2t Compounding periods. 73,000(1.036)^2t = 100,000. (1.036)^2t = 100,000/73,000 = 1.370, 2t*Log1.036 = Log1.370, 2t = Log1.370/Log1.036 = 8.90, t = 4.45 Years.

**math**

See previous post.

**math**

2x^2 + 6x - 5 = 0. Use Quadratic Formula: X = (-6 +- Sqrt(36+40))/4 = (-6 +-(8.72)/4 = 0.679, and -3.68.

**physics**

P = E^2/R = 120^2/29 = 497 Watts = 0.497 kW. Cost = 0.497 * 5.6 * 7.35cents/kWh.

**physics**

1. P = E*I = 120 * 15 = 1800 W. 1800/1500 = 1.2 or 1 Dryer. 2. 1500W. = 1.5kW. Cost = 1.5 * 6.3 * 0.078 =

**Physics**

T = 2pi*Sqrt(L/g) = 6.28*Sqrt(1/1.63) = 4.92 s.

**physics**

M*g = 20 N., g = 20/M = 20/6.5 = 3.08 m/s^2.

**Physics**

Vo = 217km[26.9o], a. Xo = 217*Cos26.9 = b. Yo = 217*sin26.9 =

**Algebra**

Sqrt(363) - 3Sqrt(27) = Sqrt(121*3) - 3Sqrt(3*9) = 11Sqrt(3) - 3*3Sqrt(3) = 11Sqrt(3) - 9Sqrt(3) = 2Sqrt(3).

**math**

4c =< 9, C =< #2.25 Per doz.

**Math**

Grandfather: X years old. Father: x-26 years old. Son: (x-26)-29 = x-55. x + x-26 + x-55 = 135, 3x - 81 = 135, 3x = 216, X = 72, x-26 = 46, x-55 = 17.

**Sarah**

Can you explain your problem in words instead of drawing a diagram? I understand electrical circuits, but I don't understand your diagram.

**Math**

Beginning bal. = 1761.

**algebra**

V1 = X km/h, V2 = x + 18 km/h. d1 + d2 = 150 km. 3x + 3(x+18) = 150, 6x + 54 = 150, 6x = 96, X = 16 km/h, x+18 = 16 + 18 = 34 km/h = V2 = Speed of the faster car.

**science**

Vo = 180m/s[55o]. a. Range = Vo^2*sin(2A)/g = 180^2*sin(110)/9.8 = 3107 m. b. Same procedure as "a" except g = 1.6 m/s^2.

**physics**

Xc = 1/WC = -1/(314.2*20*10^-6) = -159.2 Ohms. Z(Ohms) = 30 -j159.2 = 162[-79.3o]. I = E/Z = 100[0o]/162[-79.3] = 0.617A[79.3o].

**physics**

a. Xl = E/I = 3.6/2.5*10^-4 = 1.44*10^4 Ohms. b. Xl = 2pi*F*L = 14,400, L = 14,400/(6.28*1.6*10^6) = Henrys.

**Science**

V1 = 15 + 3 = 18 km/h. V2 = 15 - 3 = 12 km/h.

**MATH**

P = Po + Po*r*t = 2200 + 2200*(0.07/360)*100 = P = 2200 + 2200*(0.07/365)*100 =

**math**

Correction: 4- 1 1/2 = 2 1/2 Pizza without pepperoni. 1 1/2 - 5/6 = 3/2 - 5/6 = 9/6 - 5/6 = 4/6 = 2/3 Pizza with pepperoni remaining. 4 - 5/6 = 24/6 - 5/6 = 19/6 = 3 1/6 Pizza left. (2/3)/(19/6) = 2/3 * 6/19 = 12/57 = 4/19 Of total pizza left has pepperoni.

**math**

4- 1/1/2 = 2 1/2 Pizzas without pepperoni. 2 1/2 - 5/6 = 5/2 - 5/6 = 15/6 - 5/6 = 10/6 = 5/3 = 1 2/3 pizzas with pepperoni remaining. 4 - 5/6 = 24/6 - 5/6 = 19/6 = 3 1/6 Pizzas left. (5/3)/(19/6) = 5/3 * 6/19 = 30/57 = 10/19 Of total pizza left has pepperoni.

**math**

g = C/5 + J/5 + S/5. C = Classic CDs, J = Jazz CDs, and S = Soft rock CDs.

**Physics**

Vo = 2.19m/s[25.1o]. Yo = 2.19*sin25.1 = 0.93 m/s. a. Y^2 = Yo^2 + 2g*h = 0, 0.93^2 - 19.6h = 0, -19.6h = -0.865, h = 0.0441 m. b. Y = Yo + g*t = 0, 0.93 - 9.8t = 0, -9.8t = -0.93, t = 0.095 s. c. V = Vo = 2.19 m/s.

**Physics**

F = 32N[30o] + 56N[0o]? + 38N[60o] = 27.7+16i + 56 + 19+32.9i = 102.7 + 48.9i = 118N{25.5o]. F = M*a, a = F/M = 118[25.5o]/118 = 1 m/s^2[25.5o].

**Mechanics**

Wb = M*g = 6 * 9.8 = 58.8 N. = Wt. of block = Normal(Fn). Fap-Fk = M*a, 22.5-Fk = 6*1.25 = 7.5, Fk = 15 N. = Force of kinetic friction. u = Fk/Fn = 15/58.8 = 0.255.

**Physics- Circuits Current & Voltage Problem**

The above note does not apply to R2.

**Physics- Circuits Current & Voltage Problem**

E1 = 40V., R1 = 80 Ohms. E2 = -360V., R2 = 20 Ohms. E3 = 80V., R3 = 70 Ohms. Ro = 200 Ohms. Convert the 3 voltage sources to a single current source: Is = E1/R1+E2/R2+E3/R3 = 40/80 - 360/20 + 80/70 = -16.9A., Downward. Determine current through Ro: 1/Rs = 1/R1+1/R2+1/R3 = 1/80...

**math**

Adult: $X each. Student: $Y each. Eq1: 7x + 16y = 120. Eq2: 13x + 9y = 140. Multiply Eq1 by 13, Eq2 by 7, and subtract: 91x + 208y = 1560 91x + 63y = 980 Diff.:145y = 580. Y = $4.00.

**Physics**

V = Vo + a*t = 0 + 2*2 = 4 m/s. a. d1 = v*t = 4 * 4 = 16 m. V = Vo + a*t = 0, 4 + a*10 = 0, a = -0.4 m/s^2. V^2 = Vo^2 + 2a*d2 = 0, 4^2 - 0.8*d = 0, -0.8d2 = -16, d2 = 20 m. b. Vavg = (d1+d2)/(t1+t2) = (16+20)/(4+10) = 2.57 m/s.

**Physics**

Vo = 108,000m/3600s = 30 m/s. V = Vo + a*t = 0, a = -Vo/t = -30/5 = -6.0 m/s^2.

**PHYSICS**

R = (10-0.0025*12)/0.0025 = 9.97/0.0025 = 3,988 Ohms.

**PHYSICS**

Add a resistor in series with the coil: R+12 = E/I = 10/0.0025 = 4,000, R = 4,000-12 = 3,988 Ohms.

**College Algebra**

a. Y = 2^w + 7.

**math\**

Po*0.03*1 + (Po+750)*0.05*1 = 157.50. 0.03Po + 0.05Po + 37.50 = 157.50, 0.08Po = 120, Po = $1500 @ 3%. 1500 + 750 = $2250 @ 5%.

**science**

M*g = 40*9.8 = 392 N. Fp = 392*sin20 = 134.1 N. = Force parallel to the incline = Force required to pull the body up the incline.

**Math**

V = -2000t + 20,000 = 14,000. t = ?.

**Math**

A. J(2,1), K(-5,1), L(-5,2), M(2,2). B. L = 2 - (-5 = 7, W = 2-1 = 1. P = 2L + 2W = 2*7 + 2*1 = 16 Units.

**Physics**

a. P = E^2/R = (120)^2/R = 5.00 W., R = (120)^2/5 = 2,880 Ohms. P = (230)^2/2880 = 18.4 W. b. U.S.A.: 120I = 5.0, I = 0.0417A. Rome: 230I = 18.4, I = 0.08A. I = 1.2 * 0.0417 = 0.050A = Current at which the razor will be damaged. Yes. c. Np/Ns = Vp/Vs = 230/120 = 1.92/1. d. R...

**Physics**

Vt = 72,000m/h * 1h/3600s = 20 m/s. a. Fp = (Vs+Vp)/(Vs-Vt) * Ft =(343+0)/(343-20) * 600 = 637.2 Hz. b. Fp = (Vs-Vp)/(Vs+Vt) * Ft =

**physics**

M1*V1 + M2*V2 = M1*V3 + M2*V4, 2*10 + 3*0 = 2*V3[30o] + 3*4, 20 = 2V3[30o] + 12, 2V3[30] = 8. 2[30] = 8/V3, 1.732 + i = 8/V3, 8/V3 = 2, 2V3 = 8, V3 = 4 m/s. = Speed of 2kg ball.

**physics**

t = 54rev * 1min/3500rev = 0.0154 min. = 0.93s. Vo = 3550 rev/min * 6.28rad/rev * 1min/60s = 372 rad/s. V = Vo + a*t = 0, a = -Vo/t = -372/0.93 = -400 rad/s^2.

**Physics**

Work = F*d = Mg * d = 20*9.8 * 10 = 1960 J.

**physics**

Incomplete.

**Physical Science**

Density = 500g/50cm^3 = 10g/cm^3.

**Science**

Defective light bulb, defective switch, dead battery or miswired.

**math**

^thats wrong yo it don't work

**Engineering Accounting**

The Equation used most often for home and auto loans: P = Po*r*T/(1-(1+r)^-T) (Po*0.01*72)/(1-1.01^(-72)) = 38,060, 0.72Po/0.51150 = 38,060, 1.41Po = 38,060, Po = $27,038.67. = Cost of car.

**Engineering Accounting**

P = 3500 + (480*72) = 38,060. P = Po(1+r)^n = 38,060, r = 0.12/12 = 0.01/mo., n = 72 Compounding periods. Po(1.01)^72 = 38,060, 2.047Po = 38,060, Po = $18,592.16. = Price of car.

**Engineering Accounting**

Price = 3500 + (480*72) =

**Business math**

1. P = Po(1+r)^n. r = 0.046/2 = 0.023 = Semi-annual % rate. n = 2Comp./yr. * 8.5yrs. = 17 Compounding periods. P = 26,000(1.023)^17 = $38,270.058. 8.5yrs. = 102 Months. 38,270.058/102 = $375.20/Mo. 2. I = 38,270.06 - 26,000 = $12,270.06.

**Math**

I = Po*r*t = (1350-300)*(0.1425/12)*1 = $12.47. I = 1350*(0.1425/12)*1 = $16.03. Int. Saved = 16.03 - 12.47 =

**math**

T = Time until app. 60*(T-10/60) = 45*(T+5/60), 60T-10 = 45T + 3.75, 15T = 13.75, T = 0.91667 h = 55 Min.

**math !**

Glad I could help!

**math !**

A = 15 * 6*8 = 720 Sq. in.

**math**

A = 6*4 + 3*8 == 48 Ft^2, Cost = 20 * 48 =

**science**

4D.

**Math**

(14 2/9)% = (128/9)% = (128/9)%/100% = 128/900 = 32/225 = the ratio.

**math**

12/4 = L/6, L = ?.

**Physics**

M1*V1 + M2*V2 = M1*V + M2*V, 64.8*9.2 + 24.4*0 = 64.8V + 24.4V, 596.16 = 89.2V, V = 6.68 m/s.

**Physics**

a. My answer: 207.5 J/s = 207.5 W. b. Work = F*d = Mg*d = 2400*9.8 * 1.3 = 30,576 Joules. T = 30,576J. * 1s./207.5J. = 147.4 s.

**physics**

Incomplete.

**Physics**

7.90h * 3600s/h = 28,440 s. = 2.84*10^4 s. P = 5.90*10^6/2.84*10^4 = 207.5 J/s. = 207.5 Watts.

**Physics**

a. 6.28/360o = x/82.9o, x = 82.9 * 6.28/360 = 1.45 Radians. b. 6.28rad/rev * 6revs =

**Whats the answer**

2-11x^2-8x+6x^2 = -5x^2-8x+2.

**electronics**

What does Tr and ZT mean?

**physics 101**

30mi/h * 1600m/mi * 1h/3600s. =

**algebra**

Sqrt(39sqrt(6-4)) == Sqrt(39sqrt2) = Sqrt(55.15) = 7.43

**Algebra**

L = Sqrt(x^2+Y^2) = Sqrt(9^2+13^2) = 15.8 Ft.

**Math**

TanA = 60/91 = 0.65934, A = 33.4o. E. of N.

**Math**

X => 3, Y = 2.

**math help**

See your previous post.

**Math (Grade 12)**

1. Equity = 367,685-108,653. 2. 0.564 * Equity =