Wednesday
July 29, 2015

Posts by Henry


Total # Posts: 10,769

physics
D = Xo * t = 800 Ft. Xo * 5 = 800 Xo = 160 Ft/s. Tr + Tf = 5 s. Tr = Tf. Tr+Tr = 5. Tr = 2.5 s. = Rise time. Y = Yo + g*Tr = 0. Yo = -g*Tr = -(-32)*2.5 = 80 Ft/s. 1. Tan A = Yo/Xo = 80/160 = 0.50. A = 26.6o. 2. Vo = Xo + Yoi = 160 + 80i = 179Ft/s[26.6o]. 3. h = Yo*Tr + 0.5g*Tr...
July 28, 2015

Physics
(140-700) = -560 rev/min -560rev/min * 1min/60s * 6.28rad/rev = -58.6 rad/s. = The change in velocity. 60s/560rev * 50rev = 5.36 s. a = (-58.6)/5.36 = -10.9 rad/s^2.
July 28, 2015

math
V = 9 * 16 * sqrt(25) = 720 Cubic units.
July 27, 2015

Physics
a = u*g = 0.55 * (-9.8) = -5.39 m/s^2. V^2 = Vo^2 + 2a*d. Vo^2 = V^2 - 2a*d. = 0 - 2(-5.39)*52 = 561. Vo = 23.7 m/s.
July 26, 2015

maths
7/56 = 10/N. 7N = 560. N = 80.
July 26, 2015

physics
Wt. = M*g.
July 25, 2015

mathematics
P = Po(1+r)^n. Po = $1,024. r = 0.07. n = 1comp./yr. * 3yrs. = 3 Compounding periods. Solve for P. I = P-Po.
July 25, 2015

physics
db = 10*Log I2/I1 = 10*Log I2/6 = 20. Log I2/6 = 2. I2/6 = 10^2 = 100. I2 = 600 W/cm^2.
July 24, 2015

College algebra
2001: t = 0. P(t) = 1500*(2^)^0 = 1500*(1) = 1500 Thousands. Year 2008: t = 2008-2001 = 7 yrs.
July 24, 2015

College Algebra
X, (X+1), (X+2). x + (x+1) + (x+2) = 966. 3x + 3 = 966. 3x = 963. X = 321. X+1 = 322. X+2 = 323.
July 23, 2015

Unisa
Suppose the arc subteding the central angle theta has length 20 pi metres and the radius is 24 metres, then what is theta measured in radians
July 23, 2015

Physics
At what angle are the ropes pulling?
July 22, 2015

Math
15 = 3*5. 18 = 3*3*2. 27 = 3*3*3. GCF = 3x^12.
July 22, 2015

Physics
M1*V1 + M2*V2 = M1*V + M2*V. 7900*5 + 1650*20[30o+180o] = 7900V+1650V 39500 + 33,000[210o] = 9550V 39,500 -28,579 - 16,500i = 9550V. 10,921 - 16,500i = 9550V. 19,787[-56.5o] = 9550V. V = 2.07m/s.[-56.5o] S. of E. = 2.07m/s[304o] CCW from +x-axis.
July 22, 2015

math
Scale Change = (48-44)in/4cm = 1in/cm.
July 22, 2015

math
P = Po*(1+r)^n. Po = $3,000. r = (3%/4)/100% = 0.0075 = Quarterly % rate expressed as a decimal. n = 4Comp./yr. * 5yrs. = 20 Compounding periods. Solve for P. I = P-Po.
July 21, 2015

math
See previous post: Fri, 7-17-15, 11:46 AM.
July 20, 2015

Physics
T1*Cos(180-35) + T2*Cos50 = -36*Cos270. -0.819T1 + 0.643T2 = 0. T1 = 0.785T2. T1*sin(180-35) + T2*sin50 = -36*sin270. 0.574T1 + 0.766T2 = 36. Replace T1 with 0.785T2: 0.574*0.785T2 + 0.766T2 = 36. 0.451T2 + 0.766T2 = 36. 1.22T2 = 36. T2 = 29.6 N. T1 = 0.785T2 = 0.785 * 29.6 = ...
July 19, 2015

Calculus
Can someone show how this question is solved. Consider the curve given by the equation 2y^3 + y^2 - y^5 = x^4 -2x^3 +x^2 Find all points at which the tangent line to the curve is horizontal or vertical. Thanks!
July 18, 2015

Math
Length = L1. Width = L1/4. L2 = L1+10. W2 = L1/4 + 6. A2 = A1 + 128 Ft^2. A2 = (L1*L1/4) + 128. L2*W2 = (L1*L1/4) + 128. (L1+10)*(L1/4) + 6) = (L1*L1/4)+128. Multiply both sides by 4: (L1+10)*(L1)+24 = (L1*L1) + 512. L1^2+10L1+24 = L1^2 + 512. L1^2 - L1^2 + 10L1 + 24 = 512. ...
July 17, 2015

math
8/x = 2. X = 4 = Scale factor. Area = 8/4 * 12/4 = 6 Ft^2.
July 17, 2015

math
Area = 7*12 * 5*12 = 5,040 Ft^2
July 17, 2015

Intermediate algebra
post it.
July 15, 2015

Math
P(6, 4), m = 5. Y = mx + b. 4 = 5*6 + b. b = -26. Y = 5x - 26.
July 15, 2015

science,
4400N./0.02m^2 = 220,000 N./m^2. F = 220,000N/m^2 * 0.04m^2 = 8800 N.
July 15, 2015

physics
h = Vo*t + 0.5g*t^2. h = 2*2.5 + 4.9*2.5^2 = 35.63 m.
July 15, 2015

Geometry
L = Length of a side. A = Apothem = Altitude. L/A = L/L*sin60 = 1/sin60 = 1.1547. So the length of a side is approximately 1.15 times the apothem.
July 13, 2015

science
Unbalanced force.
July 13, 2015

Physics
500[90o] + 400[90o+60o] + F3 = 0 500i -346.41+200i + F3 = 0. -346.41 + 700i + F3 = 0. F3 = 346.41 - 700i = 781N.[-63.7o] = 781N.[63.7o] S. of E.
July 13, 2015

physics
See previous post: Sun, 7-12-15, 10:24 PM.
July 12, 2015

physics
See previous post: Sun, 7-12-15, 10:24 PM.
July 12, 2015

physics
W=0.5M*V2^2-0.5M*V1^2 = 0.5M(V2^2-V1^2)= 450(9^2-36^2) = -546,750 J. mg*h = -546,750. 8820h = 546,750. h = 62. m. 2. W = 450(36^2-9^2) = -546,750 J. Note: The negative sign means the system is doing the work.
July 12, 2015

Physics
Ti*sin(180-65) + T2*sin65 = -Wp*sin270. 1.3*0.90631 + 1.3*90,631 = Wp. Wp = 2.36 N. = Wt. of picture.
July 12, 2015

Physics
1a. 1.3*Cos(180-65) = -T2*Cos65. -0.549 = -0.423T2. T2 = 1.30 N. The Tensions are equal because the angles are equal.
July 12, 2015

Physics
1. Are the two strings tied to the same point on the wall? 2. a = u*g = 0.45 * (-9.8)=-4.41 m/s^2. V^2 = Vo^2 + 2a*d. V = 0. Vo = 7.75 m/s. a = 4.41 m/s^2. Solve for d.
July 12, 2015

Calculus
Thank You very much, I understand it now
July 12, 2015

Calculus
y = g(x) = cos(x) Can someone show how to estimate g'(pi/2) using the limit definition of the derivative and different values of h. Thanks!
July 12, 2015

physics
Glad I could help.
July 11, 2015

physics
4a. Mass = 1*10^-6m^3 * 19,300kg/m^3 = 0.0193 Kg . 4b. Fb = 1*10^-6m^3 * 1000Kg/m^3 = 0.001 Kg. = 0.0098 N. 5. V = 0.25 * 0.5 * 1 = 0.125 m^3. a. Fb = 0.125m^3 * 1000Kg/m^3 = 125 kg. = 1225 N. b. M = 0.125m^3 * 8,600kg/m^3 = c. = Wb = M*g Newtons. 6. V*D = 13 N. V*810 = 13. ...
July 11, 2015

physics
Glad I could help.
July 11, 2015

physics
P = E*I = 120 * 5 = 600 Watts = 600 J/s. Energy = P*t = 600J/s * 55s = 33,000 J.
July 11, 2015

MATH
You did not give the y-intercept nor the point. So I am going to solve a problem with that INFO given. Given: Y-intercept = 4 or(0,4), and P2(2,6). Find the Eq. of the line. P1(0,4), P2(2,6). Slope = (y2-y1)/x2-x1) = (6-4)/(2-0) = 1. Y = mx + b. Y = x + 4.
July 10, 2015

Mathematics
From what I understood in the problem, the required is the total travel time of car X from town A to town B. In the 180minutes, I think that the "80minutes later" is already included so no need to add it up.
July 9, 2015

Mathematics
Let x = speed of car X y = speed of car Y L = distance of AB "meet 80minutes later" L = 80x + 80y (distance = velocity * time) The time for car X to reach town B is: tx = ty + 36 But, tx = L/x and ty = L/y Substitute, tx = ty + 36 [80(x+y)]/x = [80(x+y)]/y + 36 ...
July 9, 2015

Mathematics
A car X left town A for town B at the same time that another car Y left town B for town A, each travelling at constant speed. They met 80 minutes later and car X arrived at town B 36 minutes after car Y reached town A. How long did it take car X to reach town B?
July 9, 2015

Physics
Work = The change in kinetic energy: Work = KE2-KE1 = 0.5*M*V2^2 - 0.5*M*V1^2 = 31*5^2 - 31*2^2 = 651 J. Work = (Fe-30)*d = 651. (Fe-30)*25 = 651. 25Fe - 750 = 651. 25Fe = 1401. Fe = 56 N. = Force exerted.
July 9, 2015

physics
M*g = 95 * 9.8 = 931 N. = Wt. of load. Fp = 931*sin50 = 713.2 N. = Force parallel to the incline. Fn = 931*Cos50 = 598.4 N. = Normal = Force perpendicular to the incline. Fk = u*Fn = 0.10 * 598.4 = 59.84 N. = Force of kinetic friction. a. Work = Fk*d = 59.84 * 30 = 1795 N. b. ...
July 9, 2015

Physics
Correction: b. D1 + D2 = 30+300 = 330 m. 0.5*1.17*t^2 + 0.5*1.1*t^2 = 330. 0.585t^2 + 0.55t^2 = 330. 1.135t^2 = 330. t^2 = 290.75. t = 17.1 s.
July 9, 2015

Physics
D1 = Distance traveled by train on left. D2 = Distance traveled by train on right a. D1 + D2 = 30 m. 0.5a1*t^2 + 0.5a2*t^2 = 30 0.5*1.17*t^2 + 0.5*1.1*t^2 = 30 0.585t^2 + 0.55t^2 = 30. 1.135t^2 = 30. t^2 = 26.43 t = 5.14s. D1 = 0.5*a1*t^2. a1 = 1.17 m/s^2. t = 5.14 s. Solve ...
July 9, 2015

Algebra
F(x) = Y = -8x^2 +3x +7 = 0 Use Quadratic Formula: X = (-B +/- sqrt(B^2-4AC))/2A X = (-3 +/- sqrt(9+224))/-16 X = (-3 +- sqrt233)/-16. X = (-3 +- 15.26)/-16 = -0.767 and 1.14.
July 8, 2015

Calculus
Can someone provide a function that satisfies all of the following: • p(−1) = 3 and lim x→−1 p(x) = 2 • p(0) = 1 and p'(0) = 0 • lim x→1 p(x) = p(1) and p'(1) does not exist Thanks!
July 8, 2015

ITT
PE = 20J. at top of incline. PE = 10J. halfway down the incline. KE + PE = 20 KE + 10 = 20 KE = 10J. KE = 0.5M*V^2 = 10 M = 1kg. Solve for V.
July 8, 2015

Math
Diagram: Draw a rectangle with the vert. sides representing the ht. of the Metro Bldg.(h1).and hor. sides are the distance between bldgs.(45m). Draw a diagonal from lower left to upper right and notice that the alternate interior angles are equal(56o).Extend the vert. side on ...
July 7, 2015

Physics
M*g = 60 * 9.8 = 588 N. = Wt. of the person. Eq1: T1*Cos9.4 + T2*Cos35.3 = 0. T1*Cos9.4 = -T2*Cos35.3. T1 = -0.827T2. Eq2: T1*sin9.4 + T2*sin35.3 =-588[270o]. 0.1633T1 + 0.578T2 = 0 + 588 Replace T1 with -0.827T2: 0.1633*(-0.827T2) + 0.578T2 = 588 -0.135T2 + 0.578T2 = 588 0....
July 7, 2015

physics 20
See Related Questions: Tue, 2-7-12, 11:59 AM.
July 6, 2015

Physics
Yo = 15*sin30 = 7.5 m/s. = Ver. component of initial velocity. Y^2 = Yo^2 + 2g*h = 0. h = -Yo^2/2g = -(7.5)^2/-19.6 = 2.87 m. above the roof. V^2 = Vo^2 + 2g*(h+40) = 0 +19.6*42.87 = 840.25 V = 29 m/s.
July 4, 2015

physics
Glad I could help.
July 3, 2015

physics
1. Work = 0.5M*V^2 = 0.5*1500*20^2 = 300,000 J. 2. hp * 746W/hp = 1492 Watts=1492J/s. P = F*V = Mg * V = 1492 J/s. 200*9.8 * V = 1492 1960V = 1492 V = 0.76 m/s.
July 3, 2015

Math
There is no difference between the number of males or females who go to their primary care physician for an annual exam.
July 3, 2015

Math
2. P = Po*r*t/(1-(1+r)^-t) Po = 9500 - 800 = $8700. r = (9%/12)/100% = 0.0075 = Monthly % rate expressed as a decimal. P = (8700*0.0075*48)/(1-1.0075)^-48 = $10,392. P/t = 10,392/48 = $216.50/mo. 3. P = Po + I = Po + Po*r*t. P = 2419 + 2419*0.052*36 = $2796.36. P/t = 2796.36/...
July 2, 2015

physics
See Related Questions: Tue, 11-23-2010, 5:05 AM.
June 29, 2015

Physics
d1 = Vo*t1 + 0.5g*t1^2 = 59.7 m. 0 + 4.9t1^2 = 59.7. t1^2 = 12.18. t1 = 3.49 s. V1 = Vo + g*t1 = 0 + 9.8*3.49 = 34.2 m/s. V2^2 = V1^2 + 2a*d2 = 3.41^2 = 11.63. 34.2^2 - 3.2d2 = 11.63. -3.2d2 = 11.63-1169.64 = -1158. d2 = 362 m. d2 = V1*t2 + 0.5a*t2^2 = 362. 34.2*t2 - 0.80*t2^2...
June 29, 2015

physics
M*g = 45 * 9.8 = 441 N. = Wt. of trunk. Fn = 441 + F*sin33. Fs = u*Fn = 0.55(441+F*sin33) = 242.6 + 0.3F. (F-Fs) = M*a. (F-(242.6+0.3F) = M*0. F - 242.6 - 0.3 = 0 0.7F = 242.6. F = 347 N.
June 23, 2015

physics
M1*V1 + M2*V2 = M1*V3 + M2*V4 1100*22 + 2300*0 = 1100*(-11) + 2300*V4 24,200 = -12,100 + 2300V4 2300V4 = 36,300 V4 = +15.8 m/s = Velocity of the truck.
June 19, 2015

physics
Correct answer = 92%
June 19, 2015

physics
496/1127 = 0.44 = 44% sin A = 0.85/2.1. A = 23.9o. Fp = 1127*sin23.9 = 457 N. = Force parallel to the ramp. Fn = 1127*Cos23.9 = 1,030 N. = Force perpendicular to the ramp = Normal force. Eff. = Fp/Fap = 457/496 = 0.92 = 92%
June 19, 2015

physics
T1[26.5o] and T2[131.5o], CCW. T1*Cos26.5 + T2*Cos131.5 = 0 T1*Cos26.5 = -T2*Cos131.5 T1 = 0.74T2 T1*sin26.5 + T2*sin131.5 + 115*sin270 = 0. Replace T1 with 0.74T2: 0.74T2*sin26.5 + T2*sin131.5 + 115*sin270 = 0. 0.33T2 + 0.749T2 - 115 = 0 1.079T2 = 115. T2 = 106.6 N. T1 = ....
June 17, 2015

Physics
a. V^2 = Vo^2 + 2g*h = 0 h = -Vo^2/2g = -225/-19.6 = 11.5 m. b. V = Vo + g*Tr = 0. Tr = -Vo/g = -15/-9.8 = 1.53 s. = Rise time. 0.5g*Tf^2 = 11.5-5 = 6.5 m. 4.9Tf^2 = 6.5 Tf^2 = 1.33 Tf = 1.15 s. = Fall time. Tr+Tf = 1.53 + 1.15 = 2.68 s. To catch the ball.
June 17, 2015

Physics
d1 = 0.5a*T1^2 = 45 m. Solve for T1. 0.5*0.88*T1^2 = 45. T1^2 = 102.3 T1 = 10.11 s. to run the 1st 45 m. V = a*T1 = 0.88*10.11 = 8.9 m/s. d2 = V*T2 = 8.9 * T2 = 100-45 = 55 m. T2 = 55/8.9 = 6.18 s. To run the last 55 m. T = T1+T2 = 10.11 + 6.18 = 16.29 s. to run the race.
June 17, 2015

Physics
a = (Fap-Fk)/M = (25-10)/5 3 m/s^2. d = 0.5a*t^2.
June 17, 2015

math help please
Po = 575-25 = $550 = Amount of loan. I = Po*r*t = 550*0.15*2yrs = $165. P = Po + I = 550 + 165 = $715 = Total cost. P/t = 715/24mo. = $29.79/mo.
June 17, 2015

science
F = ma. a = F/m = -2500/1125 = -2.22 m/s^2.
June 17, 2015

physics
V^2 = Vo^2 + 2a*d = 0 10^2 + 2a*0.04 = 0 2a*0.04 = -100 a = -1250 m/s. Note: The negative sign means that the acceleration opposes the motion.
June 17, 2015

secondary
Do you mean: y+2x/4 = x/3 or (y+2x)/4 = x/3 y + 2x/4 = x/3 Multiply both sides by 12: 12y + 6x = 4x. 2x + 12y = 0. m = -A/B = -2/12 = -1/6. (y+2x)/4 = x/3. Multiply both sides by 12: 3y + 6x = 4x. 2x + 3y = 0 m = -A/B = -2/3.
June 16, 2015

furthe math
Parallel lines have equal slopes(gradients): m1 = m2 = -3.
June 16, 2015

further mathematic
Parallel lines have equal gradients(slopes); m1 = m2 = -3.
June 16, 2015

Science
M*g = 9.5 N. M*9.8 = 9.5 M = 0.969 kg. Wt. = M*g = 0.969 * 1.64 = 1.58 N.
June 16, 2015

Maths
Area = 364/16 = 22.75 m^2 Width = W meters. Length = W+3 meters. Area = (W+3) * W = 22.75 W^2 + 3W - 22.75 = 0 Use Quadratic Formula: W = 3.5 meters = Width.
June 15, 2015

basic electronics
R3 = R Ohms. R2 = 2R Ohms. R1 = 2R/3 Ohms. 1/R1 + 1/R2 + 1/R3 = 1/1000 1/(2R/3) + 1/2R + 1/R = 1/1000 3/2R + 1/2R + 1/R = 1/1000 3/2R + 1/2R + 2/2R = 1/1000. 6/2R = 1/1000. 3/R = 1/1000. R/3 = 1000. R = 3000 Ohms. R1 = 2R/3 = 6000/3 = 2000 Ohms. R2 = 2R = 2*3000 = 6000 Ohms. ...
June 14, 2015

Physics
15t = 5 t = 0.333h = 20 min. 11.6t = 5 t = 0.431h = 26 min. T = 26 - 20 = 6 min. waiting time.
June 12, 2015

Physics
Y^2 = Yo^2 + 2g*h = 0 Yo^2 - 19.6*0.0674 = 0 Yo^2 = 1.32 Yo = 1.15 m/s = Ver. component of initial velocity. Yo = Vo*sin50 = 1.15 Vo = 1.15/sin50 = 1.50 m/s = Initial velocity. Xo = Vo*Cos50 = 1.50*Cos50 = 0.964 m/s = Hor. component of initial velocity. Dx = Xo*T = 1.06 m. 0....
June 12, 2015

Science
1. F max = 20 + 20 = 40 N. @ 0o. 2. The velocity is zero and not changing; therefore, the acceleration is zero also. F = M*a = M*0 = 0.
June 12, 2015

Science
20 + 20 = 40 N. @ 0o. Answer = 0o.
June 12, 2015

physics
Correction: Vo = 49 m/s.
June 11, 2015

physics
First Stone: d = 0.5g*t^2 = 35 m. 4.9t^2 = 35 t^2 = 7.14 t = 2.67 s Second Stone: t = 2.67-2.0 = 0.67 s. to travel 35 m. d = Vo*t + 0.5g*t^2 d = Vo*0.67 + 4.9*0.67^2 = 35 Vo*0.67 = 35 - 2.2 = 32.8 Vo = 49 m
June 11, 2015

science
P = 10*Cos30 = 8.66 N. Q = 10*Cos(90-30) = 5 N.
June 8, 2015

Math
Cos x = -0.40 X = 113.6o
June 7, 2015

physics
Fr = ((Vs+Vt)/(Vs-Vd))*Fd Fr = ((343+42.6)/(343-0))*95300Hz = 107,136 Hz = Freq. reflected.
June 5, 2015

Physics
V^2 = Vo^2 + 2g*h = 1 10^2 - 19.6h = 1 -19.6h = -99 h = 5.05 m.
June 2, 2015

physics
M*g = 25kg * 9.8N/kg = 245 N. = Wt. of block. = Normal(Fn). Fap = 120 N. = Force applied. Fk = u*Fn = 0.34 * 245 = 83.3 N. a = (Fap-Fk)/M m/s^2.
June 2, 2015

Digital Circuits
b. Limit current.
May 31, 2015

geometry
(8,-1), (5,-2), (x,y) 5-8 = 1/3(x-8) -9 = x-8 X = -1 -2-(-1)) = 1/3(y-(-1)) -1 = 1/3(y+1) -3 = y+1 Y = -4
May 31, 2015

geometry
(8,-1), (5,-2), (x,y) x-5 = 1/3(x-8) 3x-15 = x-8 2x = 7 X = 3.5 y-(-2) = 1/3(y-(-1)) y+2 = 1/3(y+1) 3y+6 = y+1 2y = -5 Y = -2.5
May 31, 2015

mechanics of dynamic
55km/h * 2h = 110 km Head start. d1 = d2 110 + 55*t = 80t -25t = -110 t = 4.4 Hours.
May 31, 2015

math
Tan 45 = h/d1 h = d1*Tan45 Tan55 = h/(d1-40) h = (d1-40)*Tan55 h = d1*Tan45 = (d1-40)*Tan55 d1*1 = (d1-40)*Tan55 Divide both sides by Tan55: 0.7d1 = d1-40 0.3d1 = 40 d1 = 133.3 Ft. h = d1*Tan45 = 133.3 * 1 = 133.3 Ft.
May 30, 2015

physics
Tan A = Y/X = 35/-12 = -2.91667 A = -71.1o = 71.1o N. of W.
May 30, 2015

college geometry
Another Method: a. X = (3+5)/2 = 4 Y = (4+1)/2 = 2.5
May 28, 2015

college geometry
a. A(3,4), C(x,y), B(5,1). Points A and B are equidistance from C: x-3 = 5-x X = 4 y-4 = 1-y Y = 2 1/2 b. A(0,2), C(x,y), B(0,6). x-0 = 0-x X = 0 y-2 = 6-y Y = 4 c. Same procedure as a, and b. d. A(2a,0), C(x,y), B(0,2b). x-2a = 0-x 2x = 2a X = a y-0 = 2b-y 2y = 2b Y = b
May 28, 2015

science
F = M*a a = F/M = 52.2/3.47 = 15 m/s^2 V = Vo - a*t V = 0 Vo = 17.4 m/s a = 15 m/s^2 t = ?
May 28, 2015

Trig/Geometry
Tan 15 = h/d Tan 15 = 145/d d = 145/Tan 15 = 541.2 Ft. Or if the angle between the line of sight and the ver.(145Ft) is 15o, then Tan 15 = d/145 d = 145*Tan 15 = 38.85 Ft.
May 28, 2015

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