Wednesday

April 23, 2014

April 23, 2014

Total # Posts: 8,530

**Inverse Trig**

Y = arcsin1 = The angle whose sine is 1= 90o.

**Physics**

V=d/t = 300/0.75=400 km/h[135o]. Without wind. V = 400[135] + 80[270o] X == 400*cos135 = -282.8 km/h. Y = 400*sin135 + 80*sin270 = 202.8 km/h. Tan Ar = Y/X = 202.8/-282.8 = -0.71727 Ar = -35.65o = Reference angle. A = -35.65 + 180 = 144.3o V = X/cosA = -282.8/cos144.3 = 348 km...

**Physics**

Vp + Vw = 200kn/h[90o] Vp + (-50) = 200i Vp = 50 + 200i = 206.2km/h[76o]

**Physics**

Vo = 6.2m/s[10o] Xo = 6.2*cos10 = 6.106 m/s. Yo = 6.2*sin10 = 1.077 m/s. 1. h = ho + (Y^2-Yo^2)/2g h = 11 + (0-(1.077)^2)/-19.6 = 11.06 m. Above gnd. 2. h = 0.5g*t^2 = 11.06 m. 4.9t^2 = 11.06 t^2 = 2.257 t = 1.50 s. 3. d = Xo * t = 6.106m/s * 1.50s=9.17 m. 4. Y^2=Yo^2 + 2g*h= ...

**physics**

What is the air temperature?

**physics**

What is the temperature of the air?

**physics**

db1 = 10*Log(I/Io) db1 = 10*Log(10^(-11)/10^(-12) = 10*Log(10^(-11)*10^12) = 10*Log(10) = 10*1 = 10. db2 = 10*Log(10^(-8)/10^(-12) = 10*Log(10^(-8)*10^12) = 10*Log(10^4) = 10 * 4 = 40. 40 - 10 = 30db Difference.

**physics**

F = (9/5)C + 32 = 46o 1.8C = 46-32 = 14 C = 7.78o V=0.6T + 331 = 0.6*7.78 + 331=335.7 m/s. L = V*(1/F) = V/F = 335.7/1640=0.2047 m.

**Physics**

F = 120N.[130o] Fx = 120*cos130 = -77.13 N. Fy = 120*sin130 = 91.93 N.

**physics**

Mass = 1800Lb * 0.454kg/Lb = 817.2 kg V=30mi/h * 1600m/mi * 1h/3600s=13.33 m/s KE=0.5m*V^2 = 0.5*817.2*13.33^2 = 72,604 Joules. KE = 0.5m*(2V^2) = .5m*4V^2 = 4 times as great. KE = 0.5*0.002*500^2 = 250 J.

**personal finances**

B. is my choice.

**trig**

Mass = 725Lbs * 0.454kg/Lb = 329.2 kg. m*g = 329.2 * 9.8 = 3226 N. = Wt. of trailer. Fp = 3226*sin36 = 1896 N. = Force parallel to the ramp. F = Fp = 1896 N. Required.

**math**

A. I = Po^r*t = 1629.53*(0.1950/365)*21 = $18.28 B. Same procedure as A.

**math**

P = Po(1+r)^n Po = $1000. r = (3%/12)/100% = 0.0025 = Monthly % rate expressed as a decimal. n = 10yrs. * 12Comp/yr = 120 Compounding periods. Plug the above values into the given Eq and solve for P. I = P - Po

**Physical sciences**

Vd=100,000m/1h * 100000m/3600s=27.8 m/s = Velocity of driver. Fd = ((Vs-Vd)/(Vs+Ve))*Fe Fd = ((343-27.8)/(343+0))*900Hz Fd = (315.2/343) * 900 = 827 Hz = Freq. heard by driver. Vs = Velocity of sound in air. Ve = Velocity of the sound emitter (siren). Fe = Freq. emitted.

**consumer math**

I = Po*r*t = $60. 472.46*r*1 = 60 r = 0.127 = 12.7% = APR 0.25 * 629.95 = $157.49 = Down payment. 629.95 - 157.49 = $472.46=Amt. financed. (472.46+60)/12 = 532.46/12 = $44.37/mo. 472.46 + 60 = $532.46 = Total paid.

**physics**

Do/Dw = 0.84 Do/1 = 0.84 Do = 0.84 g/cm^3 = Density of the object Do/Df = 0.74 0.84/Df = 0.74 0.74Df = 0.84 Df = 1.135 g/cm^3 = Density of the fluid.

**math**

(680cm^3/s) / (1767cm^2/s) = 0.3848 cm = 0.003848 m.

**Geometry**

Divide both sides of Eq1 by (-4): Eq1: +3x + 2y = 5 Eq2: -3x + 9y = -27 Sum: 11y = -22 Y = -2 In Eq1, replace Y with (-2) and solve for X: 3x + 2*(-2) = 5 3x - 4 = 5 3x = 9 X = 3 Solution set: (x,y) = (3,-2)

**physics**

Circumference=pi*2r = 3.14 * 4m=12.57 m. V = 1800rev/min * 12.57m/rev * 1min/60s= 377 m/s.

**math**

Tan(90-31) = Y1/31 Tan(59) = Y1/31 = 1.66428 Y1=31 * 1.66428 = 51.6 = Ht. of shorter tower. Y1+Y2 = 51.6 + 31*sin25 = 64.7 m. = Ht. of taller tower.

**physical science**

d = V*t = 800 m. V * 5/2 = 800 V = 320 m/s.

**science**

Momentum = m*V = 20 * 5 = 100 kg-m/s.

**Physics**

C(-1.5,0.5), P(x,y) r^2 = (x+1.5)^2 + (y-0.5)^2 = 3^2 x^2+3x+2.25 + y^2-y+0.25 = 9 x^2+3x + y^2-y = 9-2.25-0.25 = 6.5 x^2+3x=(3/2)^2 + y^2-y+(-1/2)^2 = 6.5 x^2+3x+9/4 + y^2-y+1/4 = 26/4+9/4+1/4 x^2+3x+9/4 + Y^2-y+1/4 = 36/4 Multiply both sides by 4: 4x^2+12x+9 + 4y^2-4y+1 = 36...

**algebra**

Isn't there a sign between 30,000 and 1?

**maths**

KE = 0.5m*V^2 = 1000 J. 0.5*0.0081V^2 = 1000 0.00405V^2 = 1000 V^2 = 246,913 V = 497 m/s.

**Physics**

Vo = 210m/s[70o] Xo = 210*cos70 = 71.82 m/s. Yo = 210*sin70 = 197.3 m/s. 1. h = (Y^2-Yo^2)/2g=(0-197.3^2)/-19.6 = 1986 m.

**physics**

d = 0.5a*t^2 = 6 m. 0.5a*3.3^2 = 6 5.445a = 6 a = 1.102 m/s^2. V^2 = Vo^2 + 2a*d = 0 + 2.204*6 = 13.22 V = 3.64 m/s.

**Math**

P = 6 + 6*0.019*42 = 10.8 Billion.

**Algebra**

sqrt(-70)^2 = sqrt(70*(-1))^2 = 70*i^2 = 70 * (-1) = -70

**physics**

V=110km/h = 110,000m/3600s = 30.56 m/s. a=(V-Vo)/t = (30.56-0)/0.005=6111 m/s^2. F = m*a = 0.35 * 6111 = 2139 N.

**physics**

a = (V-Vo)/t = (30-0)/4 = 7.5 m/s^2.

**physics**

d = 53 + 53/5 = 63.6 m. T = d/r = 63.6/5 = 12.72 s.

**physics**

Fs = m*g = 127kg * 9.8N/kg = 1245 N. = Wt. of skier and toboggan. sin A = Y/r = 1.65/2.53 = 0.6522 A = 40.7o Fk = u*mg-u*T*sinA Fk = 1245u - u*148*sin40.7 Fk = 1245u - 96.5u = 1148u 148*cos40.7 - 1148u = m*a = m*0 = 0 1148u = 112.2 u = 0.098

**Physical sciences**

Fc = m*g = 330kg * 9.8N/kg = 3234 N. = wt. of crate. Fp = 3234*sin30 = 1617 N. = Force parallel to the incline. Fe - Fp = m*a Fe - Fp = m*0 = 0 Fe = Fp = 1617 N. = Force exerted.

**physics**

Circumference=pi*2r = 3.14 * 0.53=1.665 m. Va = 33.4m/s * 6.28rad/1.665m=126 rad/s a=(V-Vo)/t = (126-0)/11.6=10.87 rad/s^2.

**Physics**

Correction: Fk = u*Fc-u*Fap*sin27.3 Fk = 0.442*218.54 - 0.442*Fap*sin27.3 Fk = 96.6 - 0.203Fap Fap*cos27.3-(96.6-0.203Fap) = m*a 0.889Fap - 96.6 + 0.203Fap = m*0 1.092Fap = 96.6 Fap = 88.5 N. = Force applied. W = Fap*cos27.3 * d W = 88.5*cos27.3 * 9.3 = 731.3 J.

**Physics**

Fc = m*g = 22.3kg * 9.8N/kg = 218.54 N = Wt. of cart. Fk = u*Fc = 0.442 * 218.54 = 96.6 N. = Force of kinetic friction. Fap*cos27.3-Fk = m*a Fap*cos27.3-96.6 = m*0 = 0 Fap*cos27.3 = 96.6 N. W=Fap*cos27.3 * d = 96.6 * 9.3=898.3 J. Fap = Force applied = Tension in rope.

**Math**

X Tickets @ $75 each. (3500-X) Tickets @ $110 each. 75x + 110(3500-x) = 245,000+0.25*245,000 75x + 385,000-110x = 306,250 -35x = 306,250-385,000 = -78,750 X = 2250 Seats @ $75 each. 3500-x=3500-2250 = 1250 seats @ @110each

**math**

9x^2 * x^3 = 32 x^5 = 32 x^5 = 2^5 x = 2

**Physict**

d = d1(V2/V1)^2 = 15(150/50)^2 = 135 m.

**math**

0.05 * 173,000,000

**math word problem**

See previous post: Mon, 4-7-14, 3:36 PM.

**math**

See previous post.

**geometry**

2. m AB = (5-2)/(2-0) = 3/2. m BC = (0-5)/(3-2) = -5/1 = -5. 3. A'(-4,4), B'(-2,7), C'(1,2). 4. m AB' = (7-4)/(-2+4) = 3/2. m BC' = (2-7)/(1+2) = -5/3

**Math word problems**

L = 15x + 15y L = 15(x + y) x = 5 3/8 Yards y = 3/4 Yard L = Total length x + y = 5 3/8 + 3/4 = 43/8 + 6/8 = 49/8 = 6 1/8 Yards. L=15 * 49/8 = 91.875 Yards = 91 7/8 Yds.

**physics**

KE = m*V^2/2 = 4 * 4^2/2 = 32 Joules.

**Math**

See previous post: Sat, 4-5-14, 10:04 PM.

**physics**

Freq. = 5*10^6rad/s * 1rev/6.28rad = 7.958*10^5 rev/s = 7.958*10^5 Hz. Xl = WL = (6.28*7.958*10^5)*100*10^-6 = 500 Ohms. Xc=1/WC = 1/(6.28*7.958*10^5)*100*10^-12 = 2000 Ohms. Z = R + j(Xl-Xc) = 30 + j(500-2000) = 30 - j1500 = 1500.3Ohms [-88.9o] I = V/Z = 1.0[0o]/1500.3[-88.9]...

**Math**

P(t) = 100(1-e^-0.12*3) P(3) = 100(1-0.6977) = 30.23% Fails. 100% - 30.23% = 69.7% Usable.

**Math**

The largest exponent of the variable is 2. Therefore, it is a 2nd degree polynomial.

**College Physics**

F1 = 8.2N[125o] F2 = 6.40N[233.4o] A. Fx = 8.2*cos125 + 6.40*cos233.4 = -8.519 N. B. Fy = 8.2*sin125 + 6.40*sin233.4 = 1.579 N. C. F^2 = -8.519^2 + 1.579^2 = 75.07 F = 8.66 N. D. Tan Ar=Fy/Fx = 1.579/-8.519=-0.18535 Ar = -10.5o = Reference angle. A = -10.5 + 180 = 169.5o = 10....

**Algebra**

C = (B/2)^2 = (9/2)^2 = 81/4.

**physical science**

Yes.

**Math, Geometry**

See previous post: Fri,4-4-14,1:14 AM.

**Algebra**

Use Quadratic Formula: X = (-0.8 +- sqrt(0.64+2.96))/-0.04 = -27.43, and 67.43 X = 67.43 m.

**math**

P = Po(1+r)^n Po = $10,000 r = 8%/100% = 0.08 = APR expressed as a decimal. n = 1comp/yr. * 18yrs. = 18 Compounding periods. Solve for P.

**Math**

Correction: c. % Grade = Slope expressed as a percentage.

**Math**

a. Y/X = Y/2.5 = 0.06 Y/2.5 = 0.06 Y = 0.15 Miles = 792 Ft. b. Y/X = Y/90 = 0.06 Y = 90 * 0.06 = 5.4 Miles = 28,512 Ft. c. % Grade = Slope expressed as a decimal.

**math**

P = Po(1+r)^n Po = $8500 r = (12%/4)/100% = 0.03 = Quarterly % rate expressed as a decimal. n = 1yr * 4comp/yr. = 4 compounding periods. Plug the above values into the given Eq and sole for P.

**Physics**

Va=63rev/min * 6.28rad/rev * 1min/60s= 6.594 rad/s. Angle=0.57 + 6.594rad/s*9.5s=63.21 rad. or 0.4132 rad.

**percentages/word problem**

(3456-1600)/1600

**percentages/word problem**

(30.60-18)/18 = 0.70 = 70%

**percentages/word problem**

C + 0.45C = 79.75 1.45C = 79.75 C = $55.00

**Physics**

Correction: Vo = 460.6 rad/s V = 45 rad/s a = -84.3 rad/s^2

**Physics**

Vo=4401rev/min * 6.28rad/rev * 1min/60s= 460.6 m/s V = 430 * 6.28/60 = 45 m/s. a=(V-Vo)/t = (45-460.6)/4.93=-84.3 m/s^2

**physics**

Depth = V*T = 1530 * 3.65/2 = 2792 m.

**PHYSICS**

V = Vo + g*Tr = 0 14 - 9.8Tr = 0 9.8Tr = 14 Tr = 1.43 s. = Rise time. h = ho + Vo*Tr + 0.5g*Tr^2 hmax = 70 + (14*1.43 -4.9*1.43^2)=80 m. Above gnd. hmax = 0.5g*t^2 = 80 4.9t^2 = 80 t^2 = 16.33 Tf = 4.04 s = Fall time. Tr+Tf = 1.43 + 4.04 = 5.47 s. = Time to strike gnd. V=Vo + ...

**physics**

Incomplete.

**physics.**

The liquid with the highest density will have the largest percentage of its' volume above the water. Find the density of each liquid and compare them.

**Pre Algebra**

(9+3+4+16+11+5+T)/7 = 6. Solve for T.

**Physics**

d = V*t = 1500m/s * 1.5/2 = 1125 m.

**PHYSICS!!!**

T = d/V = 200/7 = 28.57 s.

**physics**

P = F * d/t = mg * d/t P = 66*9.8 * 14/44 Joules/s.

**Physic**

The voltage across a battery is equal to the e m f of the battery only when there is no load on the battery. When a resistive load is connected across the terminals, a portion of the voltage is lost across the internal resistance of the battery.

**Physics Help**

L = V(1/F) + 0 Slope = V. V is a constant. y-intercept = 0

**physics**

All of the parameters change.

**physics**

PE = m*V^2 = 0.164 J. .0508*V^2 = 0.164 V^2 = 3.228 V = 1.80 m/s.

**Physics**

Va=219rev/20s * 6.28rad/rev=68.8 rad/s a=(V-Vo)/t = (68.8-0)/20=3.44 rad/s^2. Circumference=pi*2r = 6.28 * 68=427 cm= 4.27 m. d = 219revs * 4.27m/rev = 935.2 m.

**Physics -- check answers please**

1. My answer is zero, because the car did not move backwards. However, you should get a 2nd opinion. 2. KE = 0.5*m*V^2 = 40 Joules KE = 0.5*5*V^2 = 40 2.5V^2 = 40 V^2 = 16 V = 4 m/s. 3c. 4a. PE + KE = Constant 5. I don't know what you mean by 4 100 J If you mean 400 J. the...

**business mat**

I = Po*(r/360)*t = $15 740(r/360)*59 = 15 43,660r/360 = 15 121.28r = 15 r = 0.1237 = 12.37%/yr.

**business Math**

(115-100)/100 = 0.15 = 15%.

**Business Math**

I = Po*r*t = $1.307 45,000*(0.04/365)*t = 1307 Solve for t in days. NOTE: Exact interest is based on 365 days per year instead of 360 days.

**Algebra**

X = 3y^2 K = Yv = -B/2A = 0/6 = 0 h = Xv = 3 * 0^2 = 0 D(X1,K), V(h,K), F(X2,K). D(X1,0), V(0,0), F(X2,0) DV = 0-X1 = 1/4a = 1/12 0-X1 = 1/12 X1 = -1/12 VF = X2-0 = 1/4a = 1/12 X2 = 1/12

**physics**

a = (Fap-Fk)/m = (160-24)/20 = 6.8 m/s^2

**physics**

V = Vo + a*t = 30 m/s 0 + a*4 = 30 a = 30/4 = 7.5 m/s^2.

**Math**

Can you clarify your problem?

**Math**

(150-73)/150 = 0.51 = 51%

**science**

750W * 1hp/746W = 1.0 hp.

**math**

post it.

**phisecs**

Power = 19kW = 19000W = 19,000 Joules/s. Power = F*V = F * 29 = 19,000 J./s F = 19,000/29 = 655.2 N.

**phisecs**

a = (V^2-V0^2)/2d a = (0-17^2)/40 = - 7.23 m/s^2.

**algebra**

x-1 = x+5 x-x = 5+1 0 = 6. No Solution.

**Physics**

What is the mass of the crate?

**Physics**

V=90mi/h * 1600m/mi * 1h/3600s.= 40 m/s. a = (V-Vo)/t = (40-0)/0.5 = 80 m/s^2.

**Physics**

Work = F*h = mg * h = 6*9.8 * 4=235.2 J. Work = F*h = 12 * 5 = 60 J. Work = 5*8 = 40 J. PE = mg*h = 5 * 8 = 40 J.

**Physics**

L = V/F = 199 m. F = V/199 = 300*10^6/199=1.51*10^6 cy/s= 1.51*10^6 Hz. WL = 1/WC C = 1/W^2*L C=1/(6.28*1.51*10^6)^2*785*10^-6=0.0142 nanofarads.

**World History**

What role did the Jacobins play in the French Revolution? The Jacobins reached an agreement with moderate French leaders to end the revolution. The Jacobins opened French gov't to full participation by women. The Jacobins returned France to a monarchy by supporting Napoleo...

**History**

How was James I's rule of England similar to peter the great's rule of Russia? Both reduces the size of their empire. Both increased their own power without approval by other government entitles. Both relied heavily on the opinions of their subjects when making decisio...

**Electricity**

Q = C*V = 10*10^-9F * 5V = 50*10^-9 Coulombs.

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