Monday

April 27, 2015

April 27, 2015

Total # Posts: 1,735

**physics**

thaokieu, the tutors are not here to do YOUR homework. You have to try to solve these yourself. Post your work for each problem and someone will help if you are stuck.
*January 30, 2011*

**Pre-Calculus-Trig**

Chloe, the tutors are not here to do YOUR homework. You have to try to solve these yourself. Post your work for each problem and someone will help if you are stuck. It helps if you draw a picture. The problems I've done for you today all involve right triangles. So read ...
*January 30, 2011*

**algebra 1a**

4(8-2x)+2x<5(9+3x) 32 - 8x + 2x < 45 + 15x 32 - 6x < 45 + 15x -21x < 13 When dividing by a neg number, the sense of the inequality is reversed x > -13/21
*January 30, 2011*

**Pre-Calculus-Trig**

Draw a triangle. The the road would be the base, which is 1 mile or 5280 feet and the side opposite angle A would be 140. You need angle A. You have side a = 140 feet, and side b = 5280 feet. tan A = opp/adj = a/b = 140/5280 tan A = 140/5280 = ? arctan ? = angle A
*January 30, 2011*

**math**

Please don't repost a question without checking to see if your original post was answered. See your 1st post at 4:51 pm. This was answered for you.
*January 30, 2011*

**finance**

P = M/(1 + r)^n P = price M = maturity value r = investor's required annual yield/2 n = number of years to maturity x 2 225 = 1000/(1 + r/2)^22 225(1 + r/2)^22 = 1000 (1 + r/2)^22 = 4.4444 take the 22nd root of each side 1 + r/2 = 1.07015 r/2 = 0.07015 r = .1403 r = 14% ...
*January 30, 2011*

**algebra**

For each equation, pick values for x and solve for y. Pick at least three pair of x,y values and then plot these points. Draw a line connecting these points. Do this for each equation. The point where these line graphs intersect is the solution.
*January 30, 2011*

**accounting**

Are you sure it's only one journal entry? For the $50 mil transaction, $50 DB to Asset Account, $10 mil paid in cash (CR Cash) and the remaining $40 mil is a loan payable (CR Loan Pay). Since $8 mil principal and interest is due each Dec 31, this must be a 5-yr loan (40 ...
*January 30, 2011*

**Algebra II**

Correct!
*January 30, 2011*

**Algebra II**

I = PRT Divide both sides by PT I/PT = R
*January 30, 2011*

**algebra**

And, your question is? y + x = -4 ?
*January 30, 2011*

**Algebra**

Do this the same way as shown in your 1st post.
*January 30, 2011*

**Algebra**

Find ordered pairs to graph these equations. x + y = 6 x = 0, y = 6 x = 2, y = 4 x = 4, y = 2 x = 6, y = 0 x - y = 4 Do the same for this equation. Plot the points, for each equation and draw a line for each set of points. The point of intersection is the solution.
*January 30, 2011*

**accounting**

You're welcome.
*January 30, 2011*

**accounting**

If for the following year, the entry should have been to prepaid insurance, an asset account, not to insurance expense. This is because the expense is not for the current year. The expense belongs in the next fiscal year. Current year entry, should have been DB Prepaid ...
*January 30, 2011*

**Accounting-Journal Entry**

I don't see a question.
*January 30, 2011*

**math**

Do you mean the wall is 12 feet by 16 feet? If so, set up a ratio. 12 : 16 = 4 : x 12/16 = 4/x Cross multiply 12x = 64 x = ?
*January 30, 2011*

**algebra**

Do you mean, 5^2 n + 1 = 1/25 ? 25n + 1 = 1/25 multiply both sides by 25 625n + 25 = 1 625n = -24 n = ?
*January 30, 2011*

**6th grade math**

'tghias' is NOT correct.
*January 30, 2011*

**Math PLEASEE**

Do you mean, x^2 - 4 ? x^2 - 4 = (x - 2)(x + 2)
*January 30, 2011*

**Math- Geometry**

Ratio 5 : 2 5x + 2x = 20 Solve for x.
*January 30, 2011*

**College algebra**

Re-type your problem. What is 7 4 1 4 ?
*January 30, 2011*

**math**

What rectangle? Re-read your problem. If you knew absolutely nothing about this problem, could you solve it with the information given?
*January 30, 2011*

**Calculus **

I guess it depends on your teacher, because (2)^3/2 means (sqrt(2))^3 I've never seen anyone interpret this as (sqrt(2^3)). The first way will always get you the correct, simplified answer. If I were you, I would get in the habit of doing this the first way. Radicals ...
*January 30, 2011*

**Calculus **

2/3(8)-ln3-2/3(sqrt*8) My answer, 16/3 - ln 3 - 4/3(sqrt(2)) You have 16/3, 2/3 (8) = 16/3 Where you went wrong, You have, 2/3 (sqrt(8)) It should be, 2/3 (0 + 2)^3/2 2/3 (2)^3/2 2/3 (sqrt(2))^3 2/3 (2(sqrt(2))) 4/3 (sqrt(2))
*January 30, 2011*

**trigonometry**

Please do not repost questions without checking to see if your original post was answered. Check your earlier post (2:44 am). This question was answered for you.
*January 30, 2011*

**math**

Check your problem. Not enough info is given here to solve this problem.
*January 30, 2011*

**Math**

If he spends the same time doing 3 different activities, 80 hrs/3 = ?
*January 30, 2011*

**math**

n = number of dimes 21 - n = number of quarters .10n = value of dimes .25(21 - n) = value of quarters .10n + .25(21 - n) = 4.20 Solve for n, number of dimes 21 - n = number of quarters
*January 30, 2011*

**7th Math**

Correct!! Good job!
*January 30, 2011*

**7th Math**

70 words in 2 min = 70/2 = 35 wpm 120 words in 3 min = 120/3 = 40 wpm wpm = words per min Can you answer now?
*January 30, 2011*

**calculus**

Verify this equation, y = 4^x-1 You need parentheses. Is it, y = 4^(x - 1)? Or, y = 4^(x) - 1? Or ?
*January 30, 2011*

**Geometry/Trig.**

angle A = 45 deg Special 45-45-90 deg triangles have sides in the ratio of 1:1:(sqrt(2)) OR ratio n : n : n(sqrt(2)) This means, in this problem, side a = 1 (opposite side) side b = 1 (adjacent side) side c = 1*(sqrt(2)) (hypotenuse) tan A = a/b = op/adj tan 45 = ?
*January 30, 2011*

**Calculus**

Verify this equation, y = 4^x-1 You need parentheses. Is it, y = 4^(x - 1)? Or, y = 4^(x) - 1? Or ? Are you Jamal? Please don't change screen names. And, which is it? In this problem, rotation is about the x-axis. In the 'Jamal' problem, rotation is about the y-axis.
*January 30, 2011*

**calculus**

Check your problem. Does the problem state between x = a and x = b?
*January 30, 2011*

**Intermediate Accounting**

For compounded annually R = rate, n = number of years FV = orig investment * ((1 + R)^n) 1,000,000 = 182,696 * (1 + R)^15 5 = (1 + R)^15 (15th root(5)) = 1 + R 1.11 = 1 + R .11 = R please check my math
*January 30, 2011*

**math **

D = RT Distance = Rate x Time T = D/R R = D/T
*January 30, 2011*

**trig**

x = 225 degrees
*January 30, 2011*

**trig**

Do you mean -(sqrt(2))/2 ?
*January 30, 2011*

**Geography 7**

The usual term for the place where two (or more) rivers meet is "confluence". From wiki answers dot com
*January 30, 2011*

**Math(Please check)**

derivative of f(x)=7x-19 at x=2 f'(x) = 7 f'(2) = 7
*January 30, 2011*

**science**

"The moon is much smaller than the earth. As a result, the force of gravity on the moon is only about one sixth as strong as gravity on earth. Gravity is what holds us down on the earth's (or moon's) surface. If you were to weigh yourself on a scale here on earth ...
*January 29, 2011*

**Chemistry**

If you would like a timely answer to your post, please post your school subject in the "School Subject" box.
*January 29, 2011*

**Physics**

See the first link below under Related Questions. A somewhat similar problem was answered. The link might be helpful if no one else answers.
*January 29, 2011*

**geometry**

s = side of square P = 4s 30 <= 4s <= 64 30/4 <= s <= 16 15/2 <= s < 16
*January 29, 2011*

**mat/116**

Try to solve these inequalities first. Compound inequalities with 'Or', are solved separately and the solutions have 'or' between them. Example. If the solution to the first was x < 2 and the solution for the second was x > 4, then the solution would be, ...
*January 29, 2011*

**Math**

Thanks so much MathMate!!
*January 29, 2011*

**Math**

If possible, could a math tutor check the math post question that "daylo3" asked at 6:42 pm today, that I answered? I don't usually answer posts that I am not 100% sure of the answer. I would like to know if the way I approached this problem is correct? Thanks in...
*January 29, 2011*

**Algebra**

194 * 10^3 = 194,000 Scientific notation 1.94 x 10^5
*January 29, 2011*

**Math**

Since, the problem states to use R and C for the equation, change the x to C. So, the equation would be, R = 1.4C - 7 Instead of, R = 1.4x - 7
*January 29, 2011*

**Math**

A.) Cost 85, Retail 112 Cost 175, Retail 238 For the equation (x,R), x = cost (85,112), (175,238) Since linear, use y = mx + b R = mx + b slope m = 238 - 112/(175 - 85) slope m = 126/90 = 1.4 R = 1.4x + b To find b, plug in (85,112) 112 = 1.4(85) + b 112 = 119 + b b = -7 R = 1...
*January 29, 2011*

**trig**

Leave in radical form means don't simplify the sqrt (radical) to exact value. Example, exact value of (sqrt(2))= 1.4142 All your answers are correct. Always simplify radicals, ie,(like you did), but wasn't sure, (sqrt(52)) = 2(sqrt(13)) don't leave as (sqrt(52)) (...
*January 29, 2011*

**MATH: Pre-Cal/Trig**

A = wL x = width of garden x + 6 = length of garden Area of garden = x(x + 6) x + 6 = width of garden and walkway x + 6 + 6 = x + 12 = length of garden and walkway Area of garden and walkway = (x + 6)(x + 12) Area of garden and walkway - 288 = area of garden (x + 6)(x + 12) - ...
*January 29, 2011*

**algebra**

Commutative Property (think commute or move around)is the one that refers to moving stuff around. For addition, the rule is a + b = b + a From purplemath dot com
*January 29, 2011*

**Math**

Assuming you mean 4 - 7^(2x) = 1 7^(2x) = 3 Take logarithm to base 7 of both sides 2x log 7 = log 3 x = log 3/(2 log 7) x = 0.4771/(2 * 0.8451) x = 0.4771/1.6902 x = 0.2823
*January 29, 2011*

**Personal Finance**

b. Future value of an asset with interest compounded annually, (you didn't mention how to compound) n = number of years R = rate FV = Original investment * ((1 + R)^n) Cal. Future value of salary, 6%/year 1st year--23,000 2nd year---23,000 + 1,380 = 24,380 3rd year---24,...
*January 29, 2011*

**chemistry**

Your post in incomplete. What is your question?
*January 28, 2011*

**math**

Assuming you earn a total of $70. x = amt earned Sat 2x = amt earned Sun 1/2 x = amt earned Fri x + 2x + 1/2 x = 70 Solve for x
*January 28, 2011*

**Income Tax**

My answer above is assuming you meant the United States. I don't know, if your question is for a different country.
*January 28, 2011*

**Income Tax**

I would say true.
*January 28, 2011*

**Algebra**

MP = (1,3), A = (8,2), B = (x2,y2) Midpoint x = 1/2(x1 + x2) Midpoint y = 1/2(y1 + y2) 1 = 1/2(8 + x2) 2 = 8 + x2 x2 = -6 3 = 1/2(-2 + y2) 6 = -2 + y2 y2 = 8 B = (x2,y2) = (-6,8)
*January 28, 2011*

**geometry**

By "around" do you mean perimeter? A six figured polygon with equal sides, is called a regular hexagon.
*January 28, 2011*

**economics**

then? Is this problem complete?
*January 28, 2011*

**math**

Not subtraction. Division would be used to solve this problem.
*January 28, 2011*

**math**

Convert all the fractions to fractions with the same denominator, using the LCD. A. 18/30 B. 20/30 C. 15/30 D. 21/30 Now, wouldn't the largest fraction be closest in value to 1?
*January 28, 2011*

**math**

Is this the exact wording of the problem? Assuming "then subtract from result" is referring to the unknown number n, 7(n/3) - n = 36 7n - 3n = 108 4n = 108 n = 27
*January 28, 2011*

**Business Math**

I = PRT (Interest = Principal * Rate * Time) .04 interest/yr = .003 mo (.04/12) I = 6000 * 0.003 * 7 You can take it from here.
*January 28, 2011*

**Integrated Physics and Chemistry**

I found Ideal Mechanical Advantage.
*January 28, 2011*

**geometry **

Your post was answered below. Please don't repost a question without first checking to see if your 1st post was answered.
*January 28, 2011*

**Mathl**

Please put the school subject name in the "School Subject" box. Thank you.
*January 28, 2011*

**geometry**

Thanks drwls. I could not understand this post at all. :)
*January 28, 2011*

**geometry**

See your first post.
*January 28, 2011*

**bedmass**

There is no need to multiply the left side of the equation by 2.
*January 28, 2011*

**Math**

If you would like a math tutor to help with your problem in a timely manner, please follow directions and put the school subject in the "School Subject" box.
*January 28, 2011*

**geometry**

I do not understand your post. Exterior angle? Where? Which one? "find the other interior opposite angle" Other? Interior? Opposite what? "and the third angle of each triangle" How many angles do you expect someone to find? Please re-read your post. Think ...
*January 28, 2011*

**Algebra B**

You need to use parentheses. x-4/x+3 = x-1/x+2 Is the problem, x - 4/(x+3) = (x-1)/x + 2 x - 4/x + 3 = x - 1/(x+2) Or x - 4/x + 3 = x - 1/x + 2 Can you see the difference in these equations? This is probably why no one answered your question.
*January 27, 2011*

**math 9 helppp**

Well, you arrived at the same answer, but the equation is not correct for the problem. Your equation doesn't make sense. Where did you get 380? 380/7 = 54.29 not 55, even rounded it would be 54 or 54.30 not 55. And, it is 3.50 fee/ticket. You can't randomly subtract 3....
*January 27, 2011*

**math 9 helppp**

The equation is 7x = 385 - 7(3.50) 7x = 385 - 24.50 7x = 360.50 x = 51.5 EACH ticket has a 3.50 service fee
*January 27, 2011*

**Calc.**

| x^3*sqrt(x^2 + 1) dx | = integral sign | x^2 (sqrt(x^2 + 1)) x dx u = x^2 du = 2x dx 1/2 du = x dx 1/2 | u (sqrt(u + 1)) du w = u + 1 dw = du u = w - 1 1/2 | (w - 1) (sqrt(w)) dw 1/2 | (w - 1) w^1/2 dw 1/2 | w^3/2 dw - 1/2 | w^1/2 dw 1/2 (2/5 w^5/2) - 1/2 ( 2/3 w^3/2) + C 2/...
*January 27, 2011*

**algebra**

Not correct 121t^4 + 44t + 4
*January 27, 2011*

**Math**

I pasted below an example that reiny (tutor here) did recently. 10 and 55 are done in this example. Follow what reiny did for 45. EXAMPLE 10 = 2*5 75 = 3*5*5 55 = 5*11 The GCF is the largest number that divides into all three numbers, in this case 5 the GCF ≤ the ...
*January 27, 2011*

**math**

(6x^2-3x-9)-(2x^2+8x+3) Remove parentheses and change the sign of the terms inside the parenthese Combine like terms 6x^2 - 3x - 9 - 2x^2 -8x - 3 I leave the rest to you
*January 27, 2011*

**algebra**

Add the two 3x^2 + 7x - 3 + 5x + 2 = ?
*January 27, 2011*

**Geometry**

Correct
*January 27, 2011*

**algebra**

2z^2 IS 2z^2 or 2*z*z
*January 27, 2011*

**Math**

The time x cannot be negative. You must have made a mistake. The two equations are, distance gone by car = 64x distance gone by truck = 56(x+1/4) Since the distances are equal, 64x = 56(x + 1/4) 64x = 56x + 56/4 64x = 56x + 14 8x = 14 x = 1.75 From above (Reiny's ...
*January 27, 2011*

**math**

If P1(x1,y1) and P2 (x2,y2) are two points on a line, the number m defined by the equation Slope m = (y2 - y1)/(x2 - x1) is called the slope of the line.
*January 27, 2011*

**math**

3.4 + (5x - 1.7) plug 2.2 in for x 3.4 + 5(2.2) - 1.7 3.4 + 11.0 - 1.7 You can take it from here
*January 27, 2011*

**MATH**

Slope-intercept form y = mx + b m = slope b = y-intercept 5X - 2Y = -10 2y = 5x + 10 y = 5/2 x + 5 Slope m = 5/3 y-intercept b = 5
*January 27, 2011*

**Pre-Algebra Math**

$1167 ttl value of bills $147 ttl value of other bills $1020 value of tens and twenties n = number of tens and twenties 10n = ttl value of tens 20n = ttl value of twenties 10n + 20n = 1020 Solve for n, number of tens and twenties (equal number of both)
*January 27, 2011*

**Algebra**

2x + 5y = 4 Add -2x to both sides 5y = -2x + 4 divide both sides by 5 y = -2/5 y + 4/5 So, slope m = -2/5 Perpendicular lines, the slopes are negative reciprocals of each other. Slope = -2/5 m1 * m2 = -1 -2/5 * m2 = -1 m2 = -1/(-2/5) m2 = 5/2 Now you have to find b, for the ...
*January 27, 2011*

**Math**

I'm not sure what your question is ? 1 mile = 5280 feet 2 miles = 2 * 5280 ft = ? feet You can do the multiplication
*January 27, 2011*

**math**

Perimeter ABCD = 54 L = 12 in Perimeter LMNO = x L = 2.4 ft = 28.8 in P = 2w + 2L Use Ratio to find x (perimeter LMNO) 12/28.8 = 54/x Cross multiply 12x = 1555.2 x = 129.6 LMNO P = 129.6 L = 28.8 P = 2w + 2L 129.6 = 2w + 2(28.8) Solve for w, width of LMNO
*January 27, 2011*

**Calc.**

After all that, I confused myself and did the wrong problem I think. IF your problem is |x cos(x^2) dx just like your 2nd reply says, ignore the above. I wrote down | x cos (x^2) but integrated | x cos^2 x dx So, your very first post IS correct if it is cos x^2 and not cos^2 x...
*January 27, 2011*

**Calc.**

| x cos(x^2) dx The first line should be | x cos^2 x I forgot to change it.
*January 27, 2011*

**Calc.**

| x cos(x^2) dx | = integral symbol By half-angle cos^2 x = 1/2 (1 + cos 2x) | x 1/2 (1 + cos 2x) dx 1/2 | x + x cos 2x dx 1/2 | x dx + 1/2 | x cos 2x dx 1/4 x^2 + 1/2 | x cos 2x dx Integrate | x cos 2x dx by Integration by Parts u = x, dv = cos 2x dx du = dx, v = 1/2 sin 2x 1...
*January 27, 2011*

**Calc.**

S b= sqrt(Pi) a= 0 xcos(x^2)dx What is "S b = sqrt(Pi) a= 0" What are you integrating? Is it this? x cos(x^2) dx ? from a = 0 to b = (sqrt(pi))?
*January 27, 2011*

**Bobpursely**

Thank you, drwls!
*January 27, 2011*

**Bobpursely**

FYI-Many questions are under the name "Anonymous". If you expect a particular tutor to help you, you need to be more specific.
*January 27, 2011*

**Help**

sorry about the typo!
*January 27, 2011*