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October 22, 2014

October 22, 2014

Total # Posts: 1,700

**math**

129/10 = ?
*February 1, 2011*

**Algebra**

You're welcome
*February 1, 2011*

**Algebra**

(7+u)(3u-1)=0 7 + u = 0 u = -7 3u - 1 = 0 3u = 1 u = 1/3
*February 1, 2011*

**geometry**

Sum of measures of interior angles of a polygon of n sides = (n - 2)* 180 deg (53 - 2)*180 = 51*180 = ?
*February 1, 2011*

**Algebra B**

imaginary number
*February 1, 2011*

**Algebra- is my answer right**

(2b^-4 c^6)^5 = 32c^(30)/(b^(20))
*February 1, 2011*

**Math**

x = gal of 30% solution .30x = value of 30% solution 150 - x = gal of 60% solution .60(150 - x) .50(150) = mixture .30x + .60(150 - x) = .50(150) Solve for x, gal of 30% solution 150 - x = gal of 60% solution
*February 1, 2011*

**Algebra- is my answer right**

(x^2+4x+4)+(y^2-2y+1)=20+16+4 Should be, (x^2 +4x + 4)+(y^2 - 2y +1 )= 20 + 4 + 1 (x^2 +4x + 4)+(y^2 - 2y +1 )= 25 (x + 2)^2 + (y - 1)^2 = 25
*February 1, 2011*

**algebra**

14 - 20x > 14 - 6x -14x > 0 When you divide by a negative, the sense of the inequality is reversed x < 0
*February 1, 2011*

**Math**

Your question is?
*February 1, 2011*

**Math**

Please put your subject in the School Subject box. w = width 4w + 1 = length P = 2w + 2L 62 = 2w + 2(4w + 1) Solve for w
*February 1, 2011*

**trig**

1 half x ? What does this mean?
*February 1, 2011*

**Finance**

$5,000 @ 5% for 5 yrs then 7% for 5 yrs I = PRT I = 5000(0.05)(5) I = 250(5) I = 1250.00 5000 + 1250.00 = 6250.00 I = PRT I = 6250(0.07)(5) I = 437.50(5) I = 2187.50 6250.00 + 2187.50 = 8437.50
*February 1, 2011*

**Finance**

Is the interest compounded? Compounded daily, quarterly, yearly, etc ?
*February 1, 2011*

**Finance**

What do the numbers 0,1,2,3,4,5 represent?
*February 1, 2011*

**Finance**

A(t) = P(1 + r/n)^nt P = 50,000 r = 0.076 n = 4 (quarterly) t = 4.5 A(4.5) = 50000(1 + 0.076/4)^(4(4.5)) A(4.5) = 50000(1 + 0.019)^(18) A(4.5) = 50000(1.019)^(18) A(4.5) = 50000(1.40325) A(4.5) = 70,162.50 50,000 + 70,162.50 = 120,162.50
*February 1, 2011*

**Finance**

A(t) = Pe^rt A(t) = 100,000(2.718281)^((0.056 * 3.5)) A(t) = 100,000(2.718281)^0.1960 A(t) = 100,000(1.216527) A(3.5) = 121,652.70 100,000 + 121,652.70 = 221,652.70
*February 1, 2011*

**accounting**

Is there a Stockholders equity acct? DB Cash CR Stockholders Equity
*February 1, 2011*

**Physics**

Incomplete problem
*January 31, 2011*

**math**

x = 1st odd integer x + 2 = 2nd odd integer x + 4 = 3rd odd integer x + 6 = 4th odd integer x + x + 2 + x + 4 + x + 6 = -104 4x + 12 = -104 4x = -116 x = -29 -29, -27, -25, -23
*January 31, 2011*

**math**

You are welcome :)
*January 31, 2011*

**math**

Set up a ratio 234 : 100 = 400 : x 234/100 = 400/x cross multiply 234x = 40,000 x = 170.94
*January 31, 2011*

**Complex Numbers**

You are welcome
*January 31, 2011*

**Complex Numbers**

x^2 - 6x + 25 = 0 Subtract 25 from both sides: x^2 - 6x = -25 Add 9 to both sides: x^2 - 6x + 9 = -16 Factor the left hand side: (x-3)^2 = -16 Take the square root of both sides: |x - 3| = 4i Eliminate the absolute value: x - 3 = -4i or x - 3 = 4i Add 3 to both sides: x = 3 - ...
*January 31, 2011*

**geometry**

Area of an equilateral triangle A = 1/4(s^2 * (sqrt(3))
*January 31, 2011*

**Geometry**

Is this the exact wording of your problem? Are you looking at a picture? An angle doesn't have 'sides'. Two lines or rays form an angle. Where are you getting three sides?
*January 31, 2011*

**math**

15 gal/tank x 25 mpg = 375 miles/tank 2500 mi / 375 per tank = 6.67 tank fills = 7 tank fills (Joe always fills tank) 15 gal per tank x 7 tank fills = 105 gal 105 gal x 2.99/gal = $313.95 gas expense
*January 31, 2011*

**math**

3 gal = 12 quarts Each scoop makes 3 quarts 12 quarts / 3 quarts per scoop = 4 scoops
*January 31, 2011*

**math**

V = pi r^2 h V = (3.14)(17^2)(3) V = ?
*January 31, 2011*

**math**

V = pi r^2 h V = (3.14)(6^2)(12) V = ?
*January 31, 2011*

**math**

You must have a typo. None of the choices are correct. starting at5:380p.m ?
*January 31, 2011*

**Math (Algebra 2)**

x^4 + 8x^2 - 20 (x^2 - 2)(x^2 + 10)
*January 31, 2011*

**ap calculus**

By Theorem ∫ e^x dx = e^x + C
*January 31, 2011*

**Geometry**

Perimeter = 36 36 - 18 longest side = 18 This would mean that the remaining TWO sides total 18. The length of any side of a triangle will always be less than the sum of the lengths of the other two sides and greater than the difference of the lengths of the other two sides. 18...
*January 31, 2011*

**algebra**

3.20x = value of blooming annuals 3.20 each plant * x number of plants = ttl cost 1.50y = value of non-blooming annuals 1.50 each plant * y number of plants = ttl cost 3.20x + 1.50y = 49.60
*January 31, 2011*

**algebra**

24 is the total number of plants. x = number of blooming annuals y = number of non-blooming annuals x + y = 24
*January 31, 2011*

**algebra**

"write a linear system of equations" This is a linear system of equations. You can use x and y instead of n and b. x = number of blooming annuals y = number of non-blooming annuals 3.20x = value of blooming 1.50y = value of non-blooming x + y = 24 3.20x + 1.50y = 49....
*January 31, 2011*

**algebra**

b = number of blooming annuals n = number of non-blooming annuals 3.20b = value of blooming 1.50n = value of non-blooming b + n = 24 3.20b + 1.50n = 49.60 Solve the system
*January 31, 2011*

**algebra**

Multiply by -5 (-3x - 4y = 21) Multiply by 4 (8x - 5y = -9) 15x + 20y = -105 32x - 20y = -36 47x + 0 = -141 47x = -141 x = -3 8x - 5y = -9 x = -3 8(-3) - 5y = -9 -24 - 5y = -9 -5y = 15 y = -3
*January 31, 2011*

**Calculus**

I just looked at the graph. You want the area from x = 0 to x = 1. | = integrate symbol | x^9(1 - x) | x^9 - x^10 Then plug in x, from 0 to 1.
*January 31, 2011*

**Calculus**

Were you given (a,b) values? From x = ? to ?
*January 31, 2011*

**Math**

Do you mean, ((cube rt(625y))^3 z^7 ? If so, ((cube rt(625y))^3 z^7 = 625y z^7
*January 31, 2011*

**math**

Do you have a choice of dimensions?
*January 31, 2011*

**Finance**

Income----------46,660 Interest-----------225 Dividends-----------80 Income Adj-------1,150 Sub Total-------48,115 Less Item Ded----7,820 Sub Total-------40,295 Less Exempt------3,400 Taxable Income--36,895 Check my math
*January 31, 2011*

**Finance**

See later post above.
*January 31, 2011*

**math**

b = price of burgers d = price of dogs 2b + 5d = 8.00 5b + 2d = 9.50 Solve simultaneously
*January 31, 2011*

**parts of speech**

What is huour? Is this humor?
*January 31, 2011*

**Geometry**

P = 2L + 2w Since this is a square, L = w P = 2(0.66) + 2(0.66) P = 1.32 + 1.32 P = ?
*January 31, 2011*

**math**

n = number of adults 6.80n = value of adults 387 - n = number of children 3.40(387 - n) = value of children 6.80n + 3.40(387 - n) = 2444.60 Solve for n = number of adults 387 - n = number of children
*January 31, 2011*

**Math**

n = number of ones 1n = value of ones 68 - n = number of fives 5(68 - n) = value of fives n + 5(68 - n) = 172 n + 340 - 5n = 172 -4n = -168 n = 42 n = 42 ones = 42.00 68 - n = 26 fives = 130.00 68 bills = 172
*January 31, 2011*

**Statistic**

Delisha/James, please see your 1st post at 1:21 am under "James". Your post was answered there.
*January 31, 2011*

**finance**

x = total customers need to buy .03x = 840 x = 28,000
*January 31, 2011*

**finance**

$8000 add on interest rate of 11% 8000 x .11 = 880 add on interest/yr 880/yr x 4/yrs = 3520 3520/2 = 1760 1760 total interest on loan 1760 add on interest added to principal 8000 principal + 1760 towards principal = 9760 total loan principal 9760/48 mo = 203.33/month payment ...
*January 31, 2011*

**finance**

18% APR -How is this compounded? Yearly, daily, quarterly, etc?
*January 31, 2011*

**college algebra**

5 + 2(4y - 4) = 3(2y - 1) 5 + 8y - 8 = 6y - 3 8y - 3 = 6y - 3 2y = 0 y = 0
*January 31, 2011*

**math**

Put the words into an equation or mathematical expression. 34 multiplied by d 34 times d 34 x d 34d
*January 30, 2011*

**finance**

I = PRT (Interest = Principal x Rate x Time) 13.2% = .132 6 mo = .5 yr I = 1500 x .132 x .5 I = 198 x .5 I = 99 I don't know what you mean by cost? Interest is a form of 'cost' for the loan.
*January 30, 2011*

**Math**

Slope of the curve at, y = x^6 at x = -3 y' = 6x^5 at x = -3 6(-3)^5 = -1458
*January 30, 2011*

**AP Psychology**

Is this a typo? hueristic?
*January 30, 2011*

**Excel**

I'm not sure I'm following you. Do you just want the total 39.60 in the total column? If so, go to Cell E (col E) and click on 'Auto Sum'. One of the choices are "More Functions". Click on that. A box will come up. Type "Product" in that box...
*January 30, 2011*

**Excel**

You don't want a sum, you want a product. Use auto sum button, and choose more functions, put multiply or product in the search box and choose 'Product'.
*January 30, 2011*

**math**

Please check one of your previous posts. You have posted this exact question 4 times today. It has been answered by 3 different tutors. Exactly what is it that you do not understand?
*January 30, 2011*

**algebra **

-2/5 x = 6/35 Multiply both sides by 35 -14x = 6 x = -6/14 = -3/7
*January 30, 2011*

**algebra 1a**

Assuming you want to solve these simultaneously. 9m + n = 22 m - 3n = 18 To eliminate variable n, mulyiply the first equation by 3 3(9m + n = 22) = 27m + 3n = 66 Now add these two equations together 27m + 3n = 66 m - 3n = 18 28m + 0 = 84 28m = 84 m = 3 Substitute m = 3 in m - ...
*January 30, 2011*

**math**

V = Lwh w = width w - 2 = height w + 4 = length 8(w + 4) = V 8(w + 4) = w(w - 2)(w + 4) Solve for w
*January 30, 2011*

**physics**

thaokieu, the tutors are not here to do YOUR homework. You have to try to solve these yourself. Post your work for each problem and someone will help if you are stuck.
*January 30, 2011*

**Pre-Calculus-Trig**

Chloe, the tutors are not here to do YOUR homework. You have to try to solve these yourself. Post your work for each problem and someone will help if you are stuck. It helps if you draw a picture. The problems I've done for you today all involve right triangles. So read ...
*January 30, 2011*

**algebra 1a**

4(8-2x)+2x<5(9+3x) 32 - 8x + 2x < 45 + 15x 32 - 6x < 45 + 15x -21x < 13 When dividing by a neg number, the sense of the inequality is reversed x > -13/21
*January 30, 2011*

**Pre-Calculus-Trig**

Draw a triangle. The the road would be the base, which is 1 mile or 5280 feet and the side opposite angle A would be 140. You need angle A. You have side a = 140 feet, and side b = 5280 feet. tan A = opp/adj = a/b = 140/5280 tan A = 140/5280 = ? arctan ? = angle A
*January 30, 2011*

**math**

Please don't repost a question without checking to see if your original post was answered. See your 1st post at 4:51 pm. This was answered for you.
*January 30, 2011*

**finance**

P = M/(1 + r)^n P = price M = maturity value r = investor's required annual yield/2 n = number of years to maturity x 2 225 = 1000/(1 + r/2)^22 225(1 + r/2)^22 = 1000 (1 + r/2)^22 = 4.4444 take the 22nd root of each side 1 + r/2 = 1.07015 r/2 = 0.07015 r = .1403 r = 14% ...
*January 30, 2011*

**algebra**

For each equation, pick values for x and solve for y. Pick at least three pair of x,y values and then plot these points. Draw a line connecting these points. Do this for each equation. The point where these line graphs intersect is the solution.
*January 30, 2011*

**accounting**

Are you sure it's only one journal entry? For the $50 mil transaction, $50 DB to Asset Account, $10 mil paid in cash (CR Cash) and the remaining $40 mil is a loan payable (CR Loan Pay). Since $8 mil principal and interest is due each Dec 31, this must be a 5-yr loan (40 ...
*January 30, 2011*

**Algebra II**

Correct!
*January 30, 2011*

**Algebra II**

I = PRT Divide both sides by PT I/PT = R
*January 30, 2011*

**algebra**

And, your question is? y + x = -4 ?
*January 30, 2011*

**Algebra**

Do this the same way as shown in your 1st post.
*January 30, 2011*

**Algebra**

Find ordered pairs to graph these equations. x + y = 6 x = 0, y = 6 x = 2, y = 4 x = 4, y = 2 x = 6, y = 0 x - y = 4 Do the same for this equation. Plot the points, for each equation and draw a line for each set of points. The point of intersection is the solution.
*January 30, 2011*

**accounting**

You're welcome.
*January 30, 2011*

**accounting**

If for the following year, the entry should have been to prepaid insurance, an asset account, not to insurance expense. This is because the expense is not for the current year. The expense belongs in the next fiscal year. Current year entry, should have been DB Prepaid ...
*January 30, 2011*

**Accounting-Journal Entry**

I don't see a question.
*January 30, 2011*

**math**

Do you mean the wall is 12 feet by 16 feet? If so, set up a ratio. 12 : 16 = 4 : x 12/16 = 4/x Cross multiply 12x = 64 x = ?
*January 30, 2011*

**algebra**

Do you mean, 5^2 n + 1 = 1/25 ? 25n + 1 = 1/25 multiply both sides by 25 625n + 25 = 1 625n = -24 n = ?
*January 30, 2011*

**6th grade math**

'tghias' is NOT correct.
*January 30, 2011*

**Math PLEASEE**

Do you mean, x^2 - 4 ? x^2 - 4 = (x - 2)(x + 2)
*January 30, 2011*

**Math- Geometry**

Ratio 5 : 2 5x + 2x = 20 Solve for x.
*January 30, 2011*

**College algebra**

Re-type your problem. What is 7 4 1 4 ?
*January 30, 2011*

**math**

What rectangle? Re-read your problem. If you knew absolutely nothing about this problem, could you solve it with the information given?
*January 30, 2011*

**Calculus **

I guess it depends on your teacher, because (2)^3/2 means (sqrt(2))^3 I've never seen anyone interpret this as (sqrt(2^3)). The first way will always get you the correct, simplified answer. If I were you, I would get in the habit of doing this the first way. Radicals ...
*January 30, 2011*

**Calculus **

2/3(8)-ln3-2/3(sqrt*8) My answer, 16/3 - ln 3 - 4/3(sqrt(2)) You have 16/3, 2/3 (8) = 16/3 Where you went wrong, You have, 2/3 (sqrt(8)) It should be, 2/3 (0 + 2)^3/2 2/3 (2)^3/2 2/3 (sqrt(2))^3 2/3 (2(sqrt(2))) 4/3 (sqrt(2))
*January 30, 2011*

**trigonometry**

Please do not repost questions without checking to see if your original post was answered. Check your earlier post (2:44 am). This question was answered for you.
*January 30, 2011*

**math**

Check your problem. Not enough info is given here to solve this problem.
*January 30, 2011*

**Math**

If he spends the same time doing 3 different activities, 80 hrs/3 = ?
*January 30, 2011*

**math**

n = number of dimes 21 - n = number of quarters .10n = value of dimes .25(21 - n) = value of quarters .10n + .25(21 - n) = 4.20 Solve for n, number of dimes 21 - n = number of quarters
*January 30, 2011*

**7th Math**

Correct!! Good job!
*January 30, 2011*

**7th Math**

70 words in 2 min = 70/2 = 35 wpm 120 words in 3 min = 120/3 = 40 wpm wpm = words per min Can you answer now?
*January 30, 2011*

**calculus**

Verify this equation, y = 4^x-1 You need parentheses. Is it, y = 4^(x - 1)? Or, y = 4^(x) - 1? Or ?
*January 30, 2011*

**Geometry/Trig.**

angle A = 45 deg Special 45-45-90 deg triangles have sides in the ratio of 1:1:(sqrt(2)) OR ratio n : n : n(sqrt(2)) This means, in this problem, side a = 1 (opposite side) side b = 1 (adjacent side) side c = 1*(sqrt(2)) (hypotenuse) tan A = a/b = op/adj tan 45 = ?
*January 30, 2011*

**Calculus**

Verify this equation, y = 4^x-1 You need parentheses. Is it, y = 4^(x - 1)? Or, y = 4^(x) - 1? Or ? Are you Jamal? Please don't change screen names. And, which is it? In this problem, rotation is about the x-axis. In the 'Jamal' problem, rotation is about the y-axis.
*January 30, 2011*

**calculus**

Check your problem. Does the problem state between x = a and x = b?
*January 30, 2011*

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