Saturday

October 1, 2016
Total # Posts: 1,793

**math**

x = hourly rate 40x + 12x = 520 Solve for x

*February 4, 2011*

**Algebra**

Symmetric to y-axis if an equivalent equation is obtained when x is replaced by -x. It is symmetric to the y-axis, not x-axis.

*February 4, 2011*

**Algebra**

4y^4 + 24x^2 = 28 Symmetric to x-axis if an equivalent equation is obtained when y is replaced by -y. 4y^4 + 24x^2 = 28 4(-y)^4 + 24x^2 = 28 4y^4 + 24x^2 = 28 Since, the two equations are equivalent, the graph is symmetric to the x-axis. Symmetric to y-axis if an equivalent ...

*February 4, 2011*

**Algebra**

You need parentheses for the 2nd equation. Is this, y = 1/(x^2 + 5) Or, y = 1/(x^2) + 5

*February 4, 2011*

**algebra**

-7(x+5)(x+8) Use FOIL to expand (multiply out). What do you not understand?

*February 4, 2011*

**math**

This is very simple and quick to graph. Have you tried to graph these? What don't you understand?

*February 4, 2011*

**math**

Tutors do not do your homework. The only way you will learn is by trying to solve these yourself. See your first post/problem below. I worked out one problem in detail. Follow this example to do all these problems. If you get stuck post your work and someone will help you.

*February 4, 2011*

**math**

See your first post. Follow that example to complete this problem. Same concept, different numbers.

*February 4, 2011*

**math**

3x - 4y = 22 2x + 5y = 7 To eliminate variable x, Multiply by -2 (3x - 4y = 22) Multiply by 3 (2x + 5y = 7) Add equations -6x + 8y = -44 6x + 15y = 21 0 + 23y = -23 23y = -23 y = -1 To find x, substitute y = -1, in 2x + 5y = 7 2x + 5y = 7 2x - 5 = 7 2x = 12 x = 6 x = 6, y = -1

*February 4, 2011*

**Algebra**

What is the question?

*February 4, 2011*

**arithmetic**

Convert to inches, then use a ratio. 5'2' = 62" 3' = 36" 3'5" = 41" 62:36 = x:41 62/36 = x:41 Cross multiply and solve for x.

*February 4, 2011*

**Geometry**

TU=4x-1, UB=2x-1, TB=5x TU + UB = TB 4x - 1 + 2x - 1 = 5x Solve for x. Substitute the value you find for x in TU (4x - 1) to find the measure of TU.

*February 4, 2011*

**Math**

f(x) = x^2 + 6x f' = 2x + 6

*February 4, 2011*

**Algebra**

b^3 = 1331 b = 11 This problem is asking for the cube root of 1331. ( b * b * b = 1331 ?) There is really nothing to solve. Just like the square root of 100. You either know the answer off hand, approximate to get the answer, use trial an error, OR use a calculator.

*February 4, 2011*

**Math**

Perimeter p = 2w + 2L L = length (you called height) 0.62L = width p = 3' p = 2w + 2L 3 = 2L + 2(0.62L) 3 = 2L + 1.24L Solve for L (height)

*February 4, 2011*

**math**

See your 1st post

*February 3, 2011*

**math**

x = frogs Jen caught 4x = frogs Lisa caught x + 4x = 25 Solve for x

*February 3, 2011*

**COLLEGE ALGEBRA**

Please don't repost without checking your 1st post for an answer. See your post below.

*February 3, 2011*

**COLLEGE ALGEBRA**

Answered below.

*February 3, 2011*

**algebra**

If this is your problem (5x^4 + 3x^2 - 2x) - (-5x^4 - 3x^2 + 9x) Answer is 10x^4 + 6x^2 - 11x

*February 3, 2011*

**math**

x = number of necklaces 2x = number of earrings 16 + x + 2x = 43 solve for x

*February 3, 2011*

**algebra**

D = RT 88 = Rate of Train B T = Time of Train B 88T = Distance of Train B 80 = Rate of Train A T + .5 = Time of Train A (8:40 - 8:10 = 30 min = .5 h) 80(T + .5) = Distance of Train A Since distances are equal 80(T + .5) = 88T 80T + 40 = 88T 8T = 40 T = 5 Train B will catch up ...

*February 3, 2011*

**math**

What do you mean last step? That is the answer. You can't add -1/4 + (sqrt(3))/4

*February 3, 2011*

**Algebra-still need some help**

Is this a question?

*February 3, 2011*

**Algebra-still need some help**

For the domain, the denominator can't equal zero. -2x - 5 = 0 -2x = 5 x = -5/2 So, x cannot equal -5/2 All x not equal to -5/2 For the numerator, you cannot have a negative inside the square root. x + 6 >= 0 x >= -6 All x >= -6

*February 3, 2011*

**Math**

Please see answer I pasted below. This question was answered by Damon yesterday (and today, at least once already). math - Damon, Wednesday, February 2, 2011 at 7:40pm 1 1 1 1 1 2 1 1 3 assuming at least 3 greeting card choices

*February 3, 2011*

**math**

The question is? 4x + 5 + 29 = 4x + 34

*February 3, 2011*

**math**

x = size of woman's head 8x = size of man's head 8x = 50 x = ?

*February 3, 2011*

**Perimeter and area**

w = width = 9, L = length Area = Lw 81 = 9L L = 9 Perimeter P = 2w + 2L w = 9, L = 9 P = 2(9) + 2(9) P = ?

*February 3, 2011*

**algebra**

Are you adding these two equations? If so, 5x^4 + 3x^2 - 2x -5x^4 - 3x^2 + 9x ------------------- 0 + 0 + 7x The answer is 7x

*February 3, 2011*

**math**

Link doesn't work. There is a space after the last /.

*February 3, 2011*

**Math**

(5x^2 - 4x)(3x^2 + 2x) Use FOIL to expand -8x^2 - 2x^3 + 15x^4 15x^4 - 2x^3 - 8x^2

*February 3, 2011*

**functions**

Functions? This is a geometry problem. The ladder up against the wall forms a right triangle. x = base x + 5 = opposite side 18 = hypotenuse Using the Pythagorean theorem, x^2 + (5 + x)^2 = 18^2 Solve for x 5 + x = how far up the blding the ladder reaches.

*February 3, 2011*

**geometry**

xz = 72 xy = 5x + 3 yz = 8x - 9 5x + 3 + 8x - 9 = 72 13x - 6 = 72 13x = 78 x = 6 So, for y to be the midpoint of xz, xy = yz 5x + 3 = 8x - 9 x = 6 5(6) + 3 = 8(6) - 9 30 + 3 = 48 - 9 33 not = 39 y is not the midpoint

*February 3, 2011*

**Math**

You're welcome :)

*February 3, 2011*

**Math**

Plan A: Salary $750 + .10 of sales Plan B: Salary $1,000 + .08 of sales > $2,000 x = dollar amt of sales 750 + .10x > 1000 + .08(x - 2000) 750 + .10x > 1000 + .08x - 160 750 + .10x > 840 + .08x 0.02x > 90 x > 4500 Plan A better when sales > $4500

*February 3, 2011*

**geometry**

Not enough info. I don't have the figure to look at. Where is JN? Where is JL? Where is KL? Is this a triangle, a square, etc? Without a detailed description, your question cannot be answered.

*February 3, 2011*

**Math**

52/16 = 105/28 The concept is the same as reducing fractions. Do you know how to reduce fractions? Example: 6/12 = 1/2 in lowest terms 25/15 = 5/3 in lowest terms This is what you need to do to your problem.

*February 3, 2011*

**math - please help**

Please see answer I pasted below. This question was answered by Damon yesterday. math - Damon, Wednesday, February 2, 2011 at 7:40pm 1 1 1 1 1 2 1 1 3 assuming at least 3 greeting card choices

*February 3, 2011*

**algebra 1**

x = miles Candice drove 2x = miles Marcus drove x + 2x = 66 = miles driven together 3x = 66

*February 3, 2011*

**algebra**

FYI-"algabra" is not how you spell algebra. 3x^2- 12x - 24 = 0 This equation cannot be solved by factoring. Use the Quadratic Formula, or the method of completing the square. Here is the quadratic formula. x = (-b +- (sqrt(b^2 - 4ac)))/2a 3x^2 - 12x - 24 = 0 a = 3, b...

*February 3, 2011*

**Math**

You question is not clear. Are all these age problems based on the 10 year old, 55 year old and 75 year old or are these separate problems? Are these ages three different people? For example, "at my age of 55, in years, how old was the older person of 75 when I was born?&...

*February 3, 2011*

**Physics **

Please put your school subject in the School Subject box.

*February 2, 2011*

**physics**

See the 3rd link below under Related Questions. A similar question was answered for (a).

*February 2, 2011*

**math**

6 = 14 - 2x add -14 to both sides 6 + -14 = 14 + -14 - 2x -8 = -2x Divide both sides by -2 -8/-2 = -2x/-2 4 = x x = 4

*February 2, 2011*

**physics**

See links below under related questions. Similar problems were answered.

*February 2, 2011*

**math**

Pay attention. Do as many practice problems as you can a night. If you do not understand a certain math concept, ask for help. Practice, study and repeat as needed.

*February 2, 2011*

**math**

D = RT (Distance = Rate x Time) R = D/T 35 min = .58 hour (35/60) D = 25 mi, T = .58 h R = 25/.58 = 43.10 mph to nearest mph = 43 mph

*February 2, 2011*

**math**

Don't listen to emma. She/he is wrong.

*February 2, 2011*

**math**

22-2[5+3(6-1)] Remove the inner most parentheses first 22-2[5+3(5)] Perform the inner most multiplication next 22 - 2[5 + 15] Do addition inside parentheses 22 - 2(20) Perform theultiplication 22 - 40 Subtract -18

*February 2, 2011*

**physics**

You're welcome :)

*February 2, 2011*

**physics**

See first link below under Related Questions. A very similar problem was answered.

*February 2, 2011*

**math**

5z+10(-z+14)=95 5z - 10z + 140 = 95 -5z = -45 z = ?

*February 2, 2011*

**alg and trig**

If you mean, (you should use parentheses) 6x^3-5x^2+15x+5 / (2x^2-x+3) Use polynomial long division, Here's the answer to check to your long division, 6x^3 - 5x^2 + 15x + 5/(2x^2 - x + 3)

*February 2, 2011*

**math**

If you mean, (5x^3 * y^4)/(14x^5 * y^-8)= 5y^12/(14x^2)

*February 2, 2011*

**algebra**

Your problem is not clear. What are you dividing?

*February 2, 2011*

**math**

20 + 40 = 60

*February 2, 2011*

**math**

Square X, s = side Area, A = s^2 100 = s^2 Take square root of both sides 10 = s Square X, s = side Perimeter, P = 4s s = 10 P = 4(10) P = 40 Square Y, s = side Perimeter of Sq. Y = 1/2 Sq. X Perimeter of Sq X = 40, P = 1/2 (40) = 20 P = 4s 20 = 4s s = 5 Square Y, side = s ...

*February 2, 2011*

**math**

Yes, Damon is right. A(5) is the total value. I meant to put, $18,500 + 4610.26 Interest = $23,110.26 after 5 years

*February 2, 2011*

**math**

$18,500 at 4.5% compounded semiannually for 5 years A(t) = P(1 + r/n)^nt A(5) = 18500(1 + 0.045/2)^(2(5)) A(5) = 18500(1 + 0.0225)^10 A(5) = 18500(1.0225)^10 A(5) = 18500(1.24920) A(5) = 23110.26 interest 18,500 + I = total value after 5 yrs

*February 2, 2011*

**Algebra**

f(x)=(4x-1)/(x+7) y = (4x-1)/(x+7) Rewrite as: y = (4x)/(x+7)- 1/(x+7) Multiply both sides by x+7: (x + 7)y = 4x - 1 Expand out terms of the left hand side: xy + 7y = 4x - 1 xy - 4x = -7y - 1 x(y - 4) = -7y - 1 Divide both sides by y - 4: x = (-7y - 1)/(y - 4) f^-1 = (-7x - 1...

*February 2, 2011*

**Math geometry**

A line that bisects an angle divides it into two congruent parts. So if ray AH bisects <GAB, then angle GAH = angle BAH ? You are saying <GAH is acute and <BAH is obtuse? Does the problem state ray AH bisects <GAB or are your looking at a picture and YOU are making...

*February 2, 2011*

**Math geometry**

Need more information. Recheck your problem.

*February 2, 2011*

**Algebra**

Ignore my answer. I did not notice that one measurement is in feet. I compared inches to feet, which you cannot do.

*February 2, 2011*

**Algebra**

Set up a ratio. 10 : 100 = 10/100 = 1/10 The model is 1/10 the size of the Endeavour.

*February 2, 2011*

**,Math 7**

You're welcome :)

*February 2, 2011*

**,Math 7**

Question 2 You are correct. Megan starts with $24.75. She should leave at 11:15. Look at the part under question 4 ABOVE where I say "To check this".

*February 2, 2011*

**Algebra- is my answer right**

The answer is 2 < x < 4 I don't know how to solve this. I have tried various web sites for help. I used an online calculator for the answer but the calculator does not have the steps to solve. I've been trying this since you posted yesterday. Hoping a math tutor ...

*February 2, 2011*

**math**

y = 10h if h = number of hours worked then, $10

*February 2, 2011*

**Math geometry **

You're welcome :)

*February 2, 2011*

**Math geometry **

The midpoint of BC is M(-10,-16) B(-1,8) C = ? xm = 1/2(x1 + x2), ym = 1/2(y1 + y2) -10 = 1/2(-1 + x2) -20 = -1 + x2 -19 = x2 -16 = 1/2(8 + y2) -32 = 8 + y2 -40 = y2 C(-19, -40) check my math

*February 2, 2011*

**Math (HELP PLEASE)**

Set-up equations 1) x - 7 + 3 + 6 - 8 + 1 - 6 = 3 x + 10 - 21 = 3 x - 11 = 3 x = 13 2) x - 12.00 + 15.00 - 7.00 - 8.50 + 8.00 + 2.00 = 22.25 You solve 3) Miguel x + 15 - 4 + 6 - 17 + 22 + 14 = 40 Yoshi x + 12 - 4 + 33 - 7 = 40 You solve 4) 3:35--plane 2:00--less 2h 1:35--check...

*February 2, 2011*

**math**

Arithmetic sequence a, a + d, a + 2d, a + 3d, ...a +(n - 1)d 1)a3 = 10, a7 = 20 Since these are 4 places apart (7 - 3 = 4) a7 = a3 + 4d 20 = 10 + 4d 10 = 4d d = 10/4 = 2.5 So, the common difference, d = 2.5 To find the 1st term a, a3 = a + 2d 10 = a + 2(2.5) 10 = a + 5 a = 5 2...

*February 2, 2011*

**algebra**

3x^3-2x^2y-8xy^2 x(3x^2 - 2xy - 8y^2) x(x - 2y)(3x + 4y)

*February 2, 2011*

**Psych**

I think Ms. Sue said this. Where are the quotes?

*February 2, 2011*

**Business Communication**

Is this a test? The tutors will not complete your homework for you. The tutors will check or offer comments on YOUR work.

*February 2, 2011*

**Algebra **

This isn't a question. This is a statement, telling you why a solution to a word problem should be checked to the original wording of the problem versus the equation written for the problem. This is because the equation, derived from the wording of the problem, could be ...

*February 2, 2011*

**algebra**

If x = -70 -x = 70 Think of '-' meaning -1 -1x = 70 Divide both sides by -1 -1x/-1 = 70/-1 x = -70

*February 2, 2011*

**Math**

You're welcome :)

*February 2, 2011*

**Math**

80% = 30 .80x = 30 x = 30/.80 x = 37.5 total games 20% of 37.5 = 7.5 games lost 30 wins 7.5 lost 37.5 total games Not sure what you are trying to do in Excel.

*February 2, 2011*

**Physics**

See links below under Related Questions. This almost exact problem was answered.

*February 2, 2011*

**Algebra**

the quotient of 12 and the number, x 12/x = quotient x = -3 12/-3 = ?

*February 2, 2011*

**Calculus**

A ball is shot straight up into the air with initial velocity of 47 ft/sec Free fall, s in ft, t in sec s = s0 + v0t - 16t^2 height, s0 = 0 velocity, v0 = 47 s = 0 + 47t - 16t^2 s = 47t - 16t^2 Instantaneous velocity, v v = ds/dt = v0 - 32t v = 47 ft/sec v = 47 - 32t To find ...

*February 2, 2011*

**Math**

360 deg = 1 revolution 1 min = 60 sec 120/360 = 1/3 rev/sec 1/3 per/s * 60 sec/min = ?

*February 2, 2011*

**College Algebra**

3x^2- 12x - 24 = 0 Solve the quadratic equation by completing the square: Divide both sides by 3: x^2 - 4x - 8 = 0 Add 8 to both sides: x^2 - 4x = 8 Add 4 to both sides: x^2 - 4x + 4 = 12 Factor the left hand side: (x - 2)^2 = 12 Take the square root of both sides: |x - 2| = 2...

*February 2, 2011*

**MATH**

Please don't type in all caps. It is rude. On the internet, all caps is equivalent to shouting. 21x^7 and 147x^9 LCM is 21x^7

*February 1, 2011*

**geometry**

You need to draw right triangle ABC. Angle A (vertex angle) = 3 deg side b (base) = 60 mi side c = hypotenuse side a (distance of climb) = unknown tan A = op/hyp = a/b = a/60 tan 3 = a/60 0.0524 = a/60 60(0.0524) = a 3.144 mi = a So the plane climbed 3.144 miles To find how ...

*February 1, 2011*

**Calc**

Looks good to me!

*February 1, 2011*

**calculus**

x^2/(x+1) dx | = integration symbol |x^2/(x + 1) dx Using long divsion |x - 1 + 1/(x + 1) dx |x dx - |1 dx + |1/(x + 1) dx 1/2 x^2 - x + ln |x + 1| + C

*February 1, 2011*

**geometry**

Please do not repost a question without first checking your original post. See your 1st post. This question was answered.

*February 1, 2011*

**Algebra**

You need parentheses. x - (4/-x) + 2 > 0 ? (x - 4)/(-x + 2) > 0 ? Please, re-state the problem with parentheses.

*February 1, 2011*

**math**

129/10 = ?

*February 1, 2011*

**Algebra**

You're welcome

*February 1, 2011*

**Algebra**

(7+u)(3u-1)=0 7 + u = 0 u = -7 3u - 1 = 0 3u = 1 u = 1/3

*February 1, 2011*

**geometry**

Sum of measures of interior angles of a polygon of n sides = (n - 2)* 180 deg (53 - 2)*180 = 51*180 = ?

*February 1, 2011*

**Algebra B**

imaginary number

*February 1, 2011*

**Algebra- is my answer right**

(2b^-4 c^6)^5 = 32c^(30)/(b^(20))

*February 1, 2011*

**Math**

x = gal of 30% solution .30x = value of 30% solution 150 - x = gal of 60% solution .60(150 - x) .50(150) = mixture .30x + .60(150 - x) = .50(150) Solve for x, gal of 30% solution 150 - x = gal of 60% solution

*February 1, 2011*

**Algebra- is my answer right**

(x^2+4x+4)+(y^2-2y+1)=20+16+4 Should be, (x^2 +4x + 4)+(y^2 - 2y +1 )= 20 + 4 + 1 (x^2 +4x + 4)+(y^2 - 2y +1 )= 25 (x + 2)^2 + (y - 1)^2 = 25

*February 1, 2011*

**algebra**

14 - 20x > 14 - 6x -14x > 0 When you divide by a negative, the sense of the inequality is reversed x < 0

*February 1, 2011*