Sunday

August 2, 2015

August 2, 2015

Total # Posts: 1,739

**algebra**

Ann/Sam, none of your problems make sense. I have no idea what you are trying to do.
*February 18, 2011*

**algebra**

Ann/Sam, none of your problems make sense. I have no idea what you are trying to do.
*February 18, 2011*

**foundationd of personal finance**

Pack your lunch at home instead of eating out every day (assuming you work). Bring a thermos of coffee to work instead of stopping at Starbucks.
*February 18, 2011*

**Geometry**

V = pi r^2 h units^3 r = 5, h = 4 V = (3.14)(5^2)(4) units^3 V = ?
*February 18, 2011*

**Algebra HELP**

In the future, please number each problem. 1. 18/5 2. all values of x ( all real numbers) 3. all values of x ( all real numbers) 4. no solution
*February 18, 2011*

**Algebra**

8x^2 - 16xy + 8y^2 Factor out 8 8(x^2 - 2xy + y^2) Now, using the form of, square of a difference a^2 - 2ab + b^2 = (a - b )^2 8(x^2 - 2xy + y^2) = 8(x - y)^2
*February 18, 2011*

**Algebra again. Help**

Recheck your problem. As your problem is stated, Reiny is correct.
*February 18, 2011*

**Algebra: Help please**

Please see this link for a definition. http://www.mathsisfun.com/definitions/monomial.html
*February 18, 2011*

**geometry**

Your question is not clear. "if df equals 300m, find df. round to the nearest tenth." Find df? df = 300m
*February 18, 2011*

**calculus--No question**

What is your question?
*February 17, 2011*

**P I **

84 - 60 = 24 (24/60) * 100 = % of increase = ?
*February 17, 2011*

**Math**

If you expect an answer to your question please put your school subject in the School Subject box.
*February 17, 2011*

**MPG**

525 mi /17.5 gal = mi/gal = ?
*February 17, 2011*

**Math**

If you expect an answer to your question please put your school subject in the School Subject box.
*February 17, 2011*

**notation**

If you mean percent, 5/8 = 0.625 * 100 = 62.5%
*February 17, 2011*

**commission rate**

150/3000 = 0.05 * 100 = 5%
*February 17, 2011*

**math**

g = grams of 99% cocoa 0.99g = value of 99% cocoa 200 - g = grams of 70% cocoa 0.70(200 - g) = value of 70% cocoa 0.86(200) = value of mixture 0.99g + 0.70(200 - g) = 0.86(200) Solve for g, grams of 99% cocoa 200 - g = grams of 70% cocoa
*February 17, 2011*

**To helper -**

I'm sorry, I have been having problems with my email. Soon as my son-in-law arrives home he can check from his computer (somehow?). I've had nothing but problems since I upgraded to Outlook from Outlook Express.
*February 17, 2011*

**Algebra**

q = number of quarters 3q - 4 = number of dimes 0.25q = value of quarters 0.10(3q - 4) = value of dimes 0.25q + 0.10(3q - 4) = 7.85 Solve for q, number of quarters 3q - 4 = number of dimes
*February 17, 2011*

**Algebra**

45t^2 - 72t + 24 Only 3 can be factored from each term.
*February 17, 2011*

**math**

4 2/3 = 14/3 15 * 14/3 = 210/3 = 70 Alternate way 15 * 4 2/3 = 15 * 4 + 15 * 2/3 = 60 + 30/3 = 60 + 10 = 70
*February 17, 2011*

**math**

13 1/3 divide by 6 2/9 13 1/3 = 40/3 6 2/9 = 56/9 Dividing is the same as multiplying by the reciprocal (13 1/3)/(6 2/9) = 40/3 * 9/56 = 120/56 = 2 8/56 = 2 1/7 I'm not sure what your question was, but it appears that you arrived at the correct answer.
*February 17, 2011*

**pre algebra**

Dividing is the same as multiplying by the reciprocal. (1/2)/(2/3) = 1/2 * 3/2 = 3/4
*February 16, 2011*

**algebra**

x = miles walked x + 5.75 = miles jogged(3/4 = .75) x + x + 5.75 = 15 Solve for x, miles walked
*February 16, 2011*

**math**

5.1 x 10^-6 Since the exponent is negative, count 6 places to the left from where the decimal point is. 5.1 x 10^-6 = 0.0000051
*February 16, 2011*

**Math**

Two Angles are Supplementary if they add up to 180 degrees. 180 - 35.5 = ?
*February 16, 2011*

**math**

Since you didnt specify, based on simple interest, 9 1/2% annual rate = 0.095 0.095/360 days = 0.000264 daily rate I = PRT I = 750 * 0.000264 * 200 I = ?
*February 16, 2011*

**Calculus**

sec^3 x tan x dx | = integral symbol Rewrite as | sec^2 x sec x tan x dx u = sec x du = sec x tan x | u^2 du 1/3 u^3 + C Substitute back in, u = sec x 1/3 sec^3 x + C
*February 16, 2011*

**math--Arianna check your problem**

25 = 5^3x-1 You need to use parentheses. Is it, 5^(3x - 1) ? Or, 5^(3)x - 1 ? Or, ?
*February 16, 2011*

**Math- Algebra II**

correct, no solution
*February 16, 2011*

**algebra**

x = plan 1 y = plan 2 175x = plan 1 cost 200y = plan 2 cost The two equations are, (Divided by 1000 for easier calculation) x + y = 38 175x + 200y = 7200 Solve these equations simultaneously to find x and y. (if you are correct, x = 16, y = 22)
*February 16, 2011*

**math**

5/t^1/4 - 6/t^2/3 I rewrite as, (my preference) 5t^(-1/4) - 6t(-2/3) h' = -1/4 * 5t^(-5/4) - (-2/3 * 6t^(-5/3)) h' = -5/4t^(-5/4) + 12/3t(-5/3) h' -5/4t^(-5/4) + 4t(-5/3) h' = 4/(t^(5/3)) - 5/(t(^5/4))
*February 16, 2011*

**accounting**

You also need to do an entry for the difference of 6500.
*February 16, 2011*

**Survey of Math 140**

Simple interest 10% = 0.1 /365 = 0.000274 daily interest 3/8 to 5/26 = 79 days 79 * 0.000274 = 0.021646 (79 day interest rate) * $4000 = $86.58 interest this period 5/27 to 7/31 = 65 days 65 * 0.000274 = 0.01781 (65 day interest rate) * $2700 ($4000 - 1300) = 48.08 interest ...
*February 16, 2011*

**Math**

(x+1)(4x^2-8x+7) u = x + 1 v = 4x^2 - 8x + 7 Use the product rule, d/dx (uv) = u dv/dx + v du/dx d/dx (uv) = (x+1)(8x-8)+(4x^2-8x+7)(1) You can take it from here
*February 16, 2011*

**physics for scientists and engeneers I**

assuming the 27 was really horizontal, then the change in velocity has to be determined. To get 43m high (that is pretty high)... 1/2 m vi^2=mg(43) vi=sqrt (86*9.8) change momentum=massball*deltaV ok,to get deltaV, deltaV=sqrt(86*9.8) j +27i) then force= changemometum/time you...
*February 15, 2011*

**Physics**

Doesn't one get a rainbow when a diamond bends light,each color in a slightly different directon?
*February 15, 2011*

**Physics**

what do currents do?
*February 15, 2011*

**intermediate algebra-check my answer**

You were given the points, (x1, y1) = (-8, -6) and (x2, y2) = (0, 0) y = 3/4 x + b Use one of the given points, for example, (-8, -6) Solve for b -6 = 3/4(-8) + b b = 0 Therefore, the equation is y = 3/4 x + 0 y = 3/4 x I guess I miss-understood you. I didn't realize that ...
*February 15, 2011*

**intermediate algebra-check my answer**

y = ax + b m = 3/4 y = 3/4 x + b You need to find b for this equation. Substitute one of the given points into your equation and solve for b. Then use that b value for your equation.
*February 15, 2011*

**Calculus (I Truly Need Help) Continued**

From algebra, do you know how to find the inverse? The same method is used. Have you tried to find the inverse?
*February 15, 2011*

**math**

(10,-4), (-3,10) Slope m = (y2 - y1)/(x2 - x1) m = (10 + 4)/(-3 - 10) m = 14/-13 = -14/13 = -1.07692
*February 15, 2011*

**Math**

Area of circle = pi r^2
*February 15, 2011*

**math**

Slope intercept form, y = mx + b (6,4), (-6,-6) m = (-6 - 4)/(-6 - 6) m = -10/-12 = 5/6 To find b, use (6,4) m = 5/6 4 = 5/6 (6) + b 4 = 30/6 + b 4 = 5 + b b = -1 Equation y = 5/6 x - 1
*February 15, 2011*

**Geometry**

I'll find one side. Triangle ABC, angle A = 36 side c (hypotenuse) = 9 To find side a (opposite side) sin A = op/hyp = a/c = a/9 sin 36 = a/9 0.5878 = a/9 9 * 0.5878 = a a = 5.2902 Area = 1/2 bh In this case, (right triangle) A = 1/2 ab (side a, side b) I found side a, you...
*February 14, 2011*

**Geometry**

Triangle ABC, angle A = 55 deg side b = 43 tan A = op/adj = a/b = a/43 tan 55 = a/43 a = 43 * 1.4281 a = 61.4083 cos 55 = adj/hyp = b/c = 43/c cos 55 = 43/c c = 43/0.5736 c = 74.9651 I'll let you finish (not sure what 'length of triangle' is) Length of triangle = ?
*February 14, 2011*

**exponents**

Please give an example.
*February 14, 2011*

**geometry**

Area = Lw Diagonal d^2 = L^2 + w^2 26^2 = L^2 + 10^2 676 = 100 + L^2 L^2 = 576 L = 24 L = 24, w = 10 A = Lw A = 24(10) A = ?
*February 14, 2011*

**matemáticas**

Is this the question? The rectangular base perimeter of a piano is 16 feet. What are all the possible dimensions of the piano, using only whole numbers of feet?
*February 14, 2011*

**math**

This is a dumb question (my opinion only). If he has an empty stomach, wouldn't the minimum volume be the volume of the pizza? This is a complete guess. Sphere volume = 4/3 pi r^3
*February 14, 2011*

**Alegbra**

What are you trying to do with these equations? Please post the exact directions to your problem.
*February 14, 2011*

**College algebra**

See your post below for a detailed example of how to complete this problem.
*February 14, 2011*

**College algebra**

Slope-intercept form of the equation y = mx + b m = slope = 6/7 y = 6/7 x + b To find b, use point (0,3), where x = 0 and y = 3. Solve for b. y = 6/7 x + b 3 = 6/7(0) + b 3 = 0 + b b = 3 So, the equation is y = 6/7 x + 3
*February 14, 2011*

**Math**

x = people in audience 1/2 x = left 1st 1/3 (1/2 x) = 1/6 x = left next 1/4 (1/3)(1/2)x = 1/24 x = left last x - (1/2 x + 1/6 x + 1/24 x) = 9 Solve for x
*February 14, 2011*

**English**

I guess you don't want your question answered. You waste tutor's time when you don't follow directions and put your school subject in the School Subject box.
*February 14, 2011*

**math**

6xy is the correct answer.
*February 14, 2011*

**algebra**

3x + 4 > 9, Solve the inequality 3x + 4 > 9 3x > 5 x > 5/3 = 1.67 Therefore, for x to be a solution, x > 1.67 You should be able to finish the problem from here.
*February 14, 2011*

**math**

3^5 + 3^5 + 3^5 243 + 243 + 243 = ?
*February 14, 2011*

**algebra**

V = 1/3*6300*7 Multiply both sides by the denominator 3 3v = (6300)(7) 3v = 44,100 v = 14,700
*February 14, 2011*

**geometry**

Draw a rhombus with the diagonals. 4 right triangles are formed. The intersection of the diagonals of a rhombus form 90 degree (right) angles (property of a rhombus). The diagonals of a rhombus bisect each other. This means that they cut each other in half. So, each of the ...
*February 14, 2011*

**maths**

(0.008)^x = 1/25 x log 0.008 = log 1/25 -4.828314 x = -3.218876 x = -3.218876/-4.828314 x = ?
*February 14, 2011*

**Math**

x^3 = 27 Take cube root of both sides x = 3 Because, 3 * 3 * 3 = 27 I'm not sure what your 2nd problem is. Is your problem, x^4 = 16 ? If so, x^4 = 16 Take the forth root of both sides x = +- 2 Because, 2 * 2 * 2 * 2 = 16 Or, -2 * -2 * -2 * -2 = 16 FYI, 4^3 = 4 * 4 * 4 = ...
*February 14, 2011*

**Math Trivia**

The web link provided gave the answer. I pasted it below. The calculation was done wrong. The 2 dollars should not be added to 27 but subtracted to get 25 dollars. Put in another way, $25 is with the owner of the Hotel, each of the 3 guests received $1 from the clerk, and he ...
*February 13, 2011*

**math**

Answered in previous post.
*February 13, 2011*

**math**

If I am picturing this correctly, a right triangle is formed, with the diagonal of 75' being the hypotenuse. x = one leg (vertical height) x + 15 = other leg (horizontal distance) Use the Pythagorean theorem, c^2 = a^2 + b^2 75^2 = x^2 + (x + 15)^2 Solve for x
*February 13, 2011*

**TRIG**

2 sin Î¸ + 3 = 2 2 sin Î¸ = -1 sin Î¸ = -1/2 Î¸ = ?
*February 13, 2011*

**algebre**

x = shortest side 2x = 2nd side x + 30 = 3rd side x + 2x + x + 30 = 102 Solve for x, and use to determine the dimensions as defined above
*February 13, 2011*

**math **

(7x + 4)(2x + 4) Use FOIL-First, Outer, Inner, Last First-7x * 2x = 14x^2 Outer-7x * 4 = 28x Inner-4 * 2x = 8x Last-4 * 4 = 16 Put together, 14x^2 + 28x + 8x + 16 Combine like terms, 14x^2 + 28x + 8x + 16 14x^2 + 36x + 16 All the problems you have posted are done the same way...
*February 13, 2011*

**math**

See your post with the detailed answer of how these type problems are done. All the problems you posted are done the same exact way. Time to get to work.
*February 13, 2011*

**math**

See your post with the detailed answer of how these type problems are done. All the problems you posted are done the same exact way. Time to get to work.
*February 13, 2011*

**math**

See your post with the detailed answer of how these type problems are done. All the problems you posted are done the same exact way. Time to get to work.
*February 13, 2011*

**math**

See your post with the detailed answer of how these type problems are done. All the problems you posted are done the same exact way. Time to get to work.
*February 13, 2011*

**math**

You don't state if the interest is simple or compounded. For simple interest, I = PRT (Interest = Principal*Rate*Time) I = 300 * 0.03 * 30 I = ?
*February 13, 2011*

**college Trig**

Triangle ACB, C = 70 deg, a = 70, b = 50 find side c Use Law of Cosines--Case III (Given two sides and the included angle) c^2 = a^2 + b^2 - 2ab cos C c^2 = 70^2 + 50^2 - 2(70)(50) cos 70 Solve for c
*February 13, 2011*

**algebra**

28x^2 - 196xy + 343y^2 7(x^2 - 28xy + 49y^2) 7(2x - 7y)(2x - 7y) 7(2x - 7y)^2
*February 13, 2011*

**finance**

I'm not sure either Ms. Sue after seeing your answer. I multiplied out 10yrs at your rate and your answer is closer. I have to think about this more.
*February 13, 2011*

**finance**

1.55 - .79 = .76 increase in 10 yrs 0.76/0.79 = 0.962025 = 96.2025% increase in 10 years 96.2025%/10 = annual growth rate
*February 13, 2011*

**math**

x = larger number y = smaller number xy = 50 x/y = 2 or x = 2y Substitute, x = 2y in xy = 50 2y * y = 50 2y^2 = 50 y^2 = 25 y = +- 5 To find x, Substitute y = +- 5 in either equation xy = 50 5x = 50 x = 10 -5x = 50 x = -10 Numbers are 10, 5 or -10, -5
*February 13, 2011*

**math**

1/4 + 3/10 First, find the common denominator, 20. 5/20 + 6/20 = ?
*February 13, 2011*

**statistics**

y = 100 + 1.2x 130 = 100 + 1.2x Solve for x 30 = 1.2x x = 30/1.2 = ?
*February 13, 2011*

**math**

Please check your 1st post for an answer before reposting. This question was answered earlier today.
*February 12, 2011*

**For bobpursley**

I will email as soon as I can. My email is not working at this moment and I don't know why. My son-in-law is looking into it right now.
*February 12, 2011*

**algebra**

See your 1st post below.
*February 12, 2011*

**algabra**

For multiplication, the rule is a(bc) = (ab)c In numbers, this means 2(3×4) = (2×3)4 Can you do your problem now?
*February 12, 2011*

**math**

(8,-4) and (-7,9). Midpoint =(x1 + x2)/2, (y1 + y2)/2 Mx = (8 + -7)/2 = 1/2 = 0.5 My = (-4 + 9)/2 = 5/2 = 2.5 Midpoint (0.5, 2.5)
*February 12, 2011*

**algebra**

(6/-2)/-1/4 = -3 * -4/1 = 12 Division is the same as multiplying by the reciprocal.
*February 12, 2011*

**algebra**

5p + 15 What factors do both expressions have in common, 5. 5p + 15 = 5(p + 3)
*February 12, 2011*

**algebra**

2/9 * 2y/2y = 4y/18y
*February 12, 2011*

**Algerbra**

You're welcome :)
*February 12, 2011*

**Algerbra**

f(x) = -4x - 3 The slope-intercept form of an equation, where m = slope and b = y-intercept. y = mx + b Since your equation is already in the slope-intercept form, y = mx + b y = -4x - 3 Slope m = -4 y-intercept b = -3
*February 12, 2011*

**Algebra**

Look below "Post Answer" button. See "Related Questions", click the first link "Algebra". This almost exact question is answered there.
*February 12, 2011*

**Algebra**

Check your equation. I think it should be y = -1777x + 27,153 You have +1777x
*February 12, 2011*

**Algebra 1**

y = 3x - 1 y = -x + 1 Find points for each equation, then plot the points for each, draw a line connecting these points for each equation. The point of intersection is the solution. y = 3x - 1 x = 0, y = -1 x = -1, y = -4 x = 1, y = 2 x = 1/2, y = 1/2 So, you would plot the ...
*February 12, 2011*

**geometry**

tan 8 degrees = 0.1405 0.1405 * 100 = 14.05% grade
*February 12, 2011*

**Algebra**

You're welcome :)
*February 12, 2011*

**Algebra**

D = RT (Distance = Rate * Time) 120 = rate of Train B T = time of Train B 120T = distance of Train B 100 = rate of Train A T + 0.25 = time of Train A (5:25 - 5:10 = 15 min = 60/15 = 0.25 h) 100(T + 0.25) = distance of Train A Distances are equal 120T = 100(T + 0.25) 120T = ...
*February 12, 2011*

**algebra **

Slope = rise/run = 8/29 = ?
*February 12, 2011*

**Biology**

I would think the volume of a cylinder formula, as long as the cup diameter is uniform from top to bottom (not an older type cup where it is wider at the top than at the bottom of the cup).
*February 12, 2011*

**algebra**

w = width 2w + 1 = length P = 2w + 2L 302 = 2w + 2(2w + 1) Solve for w, the width. length = 2w + 1
*February 12, 2011*

**calculus**

To find the slope of the tangent line at a point means to find the derivative of f(x). f(x) = 3 - 5x f' = 0 - 5 f' = -5 Then, normally, you would plug in the given point, (-1, 8), to find the slope. But since f' = 5 with no variable x, for instance, there is ...
*February 11, 2011*