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November 29, 2015
Total # Posts: 1,744

**math**

you're welcome :)
*January 17, 2011*

**math**

25 < n - 12 37 < n n > 37
*January 17, 2011*

**algebra**

p = pennies 2p - 9 = nickles 3p - 19 = dimes p + 2p - 9 + 3p - 19 = 140 6p - 28 = 140 6p = 168 p = 28 p = pennies = 28 2p - 9 = nickles = 47 3p - 19 = 65
*January 17, 2011*

**Algebra 2 **

g(f(x))= 2(x^2 + 1)^2 = 2 (x^4 + 2x^2 + 1) = 2x^4 + 4x^2 + 2
*January 17, 2011*

**Math**

A = x^2 - 10x + 25 = (x - 5)(x - 5) A = Lw L = (x - 5), w = (x - 5) P = 2w + 2L P = 2(x - 5) + 2(x - 5) P = 2x - 10 + 2x - 10 P = 4x - 20
*January 17, 2011*

**Math**

A = Lw L = 5x + 10 w = 5x - 5 A = (5x + 10)(5x - 5) A = ? expand and collect like terms for your answer
*January 17, 2011*

**Math**

the expression needs to be simplified I tried
*January 17, 2011*

**math**

4 C 2 = combination of 4, taken 2 at a time C(4,2) = (4!/(4 - 2)!)/2! = 4!/(2!2!) C(4,2) = (4x3x2x1)/(2x1x2x1)= 24/4 = 6 total of 6 combinations 1 out of 6 possible combinations I am not a tutor
*January 17, 2011*

**mat h**

x = amt at 3% y = amt at 5% x + y = 2000 .03x + .05y = 84 solve simultaneously for x, y give it a try, post if you need for help x = 800, y = 1200 if you are right
*January 17, 2011*

**math**

6x^2-1 = -1/6 (sqrt6 - 6x)(sqrt6 + 6x)
*January 17, 2011*

**geometry**

if you sketch this you will see that the median from Q, bisects segment PR to write the equation of the median you need to find the midpoint of PR P(0,12), R(-2,2) using the midpoint formula 1/2 (x1 + x2), 1/2 (y1 + y2) 1/2(0 + -2), 1/2(12 + 2) 1/2(-2), 1/2(14) Midpoint (-1,7...
*January 17, 2011*

**Algebra**

3x-2y=10 2x+3y=-2 By substitution 3x - 2y = 10 2x + 3y = -2 3x = 10 + 2y x = 10/3 + 2/3 y 2(10/3 + 2/3 y) + 3y = -2 20/3 + 4/3 y + 3y = -2 20/3 + 4/3 y + 9/3 y = -2 20/3 + 13/3 y = -2 13/3 y = -2 - 20/3 13/3 y = -6/3 - 20/3 13/3 y = - 26/3 y = -26/3 * 3/13 y = - 78/39 = -2 to ...
*January 17, 2011*

**Math**

300 km/h to mph 1 mph = 1.609344 km/hr 300/1.609344 = 186.411358 mph
*January 17, 2011*

**Math**

:) sometimes the easiest problem stumps me!
*January 17, 2011*

**Math**

By Property of Exponential Function, a^0 = 1 (abc)^0 = 1
*January 17, 2011*

**Math**

yes, ^ means squared. if no parentheses, I don't know why I am not a tutor, maybe REINY or another tutor will answer
*January 17, 2011*

**Math**

was the problem written as -(5^2) = -(25)= -25 where, (-5^2) = 25
*January 17, 2011*

**Math**

correct!! :)
*January 17, 2011*

**Math**

set up as equation and solve for N 2/3 N = 4 2N = 12 N = 6 1/2 N = ? N = 6 1/2 6 = ?
*January 17, 2011*

**Math**

22,000 cost before interest less 3,000 down payment 19,000 amount financed 600/mo for 40 mo = 24,000 total cost with interest 24,000 - 19,000 = 5000.00 interest on amt financed 5000/19000 = 26.32% simple interest rate 5000 finance chrg 19,000 amount financed 24,000 installment...
*January 17, 2011*

**math**

you are missing the exponents if (a) should be 2x^2 - 7x - 5 a) 2x^2 - 7x - 5 does not factor, solve by using the quadratic formula or completing the square if you are stuck, post your work and someone will help tutors do not do your homework
*January 17, 2011*

**Algebra II**

is this your problem (x^2 - 1)/1 divided by (x - 1)/(x + 5)? if so, (x^2 - 1)/1 = x^2 - 1 to divide, invert the denominator and multiply, so, (x^2 - 1) * (x + 5)/(x - 1) does this help?
*January 17, 2011*

**math**

2^(x-2)=54 take logarithm of both sides (x - 2)log 2 = log 54 x log 2 - 2 log 2 = log 54 x log 2 = log 54 + 2 log 2 x = (log 54 + 2 log 2)/log 2 find above logs x = 7.75 approx
*January 17, 2011*

**alegebra 2**

recheck your problem, not enough info given
*January 17, 2011*

**Calculus**

If this is your problem 2^-x = 3^(2x+2) take logarithms of both sides -x log 2 = (2x + 2)log 3 -x log 2 = 2x log 3 + 2 log 3 -x log 2 - 2x log 3 = 2 log 3 x (-log 2 - 2 log 3) = 2 log 3 x = -(2 log 3)/(log 2 + 2 log 3) plug in log values x = -0.760188
*January 17, 2011*

**Calculus**

see above post of yours
*January 17, 2011*

**Maths**

(3^-2e^4)^-1 = (1/9 * e^4)^-1 = (e^4/9)^-1 = 1/(e^4/9) = 9/e^4
*January 17, 2011*

**Algebra**

5 - 31 + 29 = ?
*January 17, 2011*

**Phsyics**

see this website to convert I can't post links so, put a / where there is a comma, and the usual other that you put before an address easysurf dot cc,cnver14 dot htm
*January 17, 2011*

**Algebra**

(5 + 31 + 29)/3 = average
*January 16, 2011*

**math**

simple interest I = PRT I = 5000 * .04 * 1.5 I = 300
*January 16, 2011*

**Algebra**

P = 2w + 2L 2*17 + 2L > 94 34 + 2L > 94 2L > 60 L > 30 length > 30 cm
*January 16, 2011*

**Maths**

3x - 6 = 3x/4 multiply both sides by 4 12x - 24 = 3x 9x = 24 x = 24/9 x = 8/3
*January 16, 2011*

**college math 209**

x = - b ± (sqrt(b^2 - 4ac))/2a 3x^2 + x - 8 = 0 a = 3, b = 1, c = -8 what do you need help with? I gave you the formula, you give it a try, post your work if you get stuck. tutors do not do your homework. they are here to help you do your work.
*January 16, 2011*

**college math 209**

(x+4)^2 = 2x^2 + 19x + 46 (x + 4)(x + 4) = 2x^2 + 19x + 46 x^2 + 8x + 16 = 2x^2 + 19x + 46 collect like terms, then solve you try and post back if you need help
*January 16, 2011*

**Writing**

from About dotcom, Homework/Study tips "Individual works of art like paintings and sculptures are underlined or italicized" * Michelangelo's David * Mona Lisa * The Last Supper * The Pieta A photograph, which is much smaller than a work of art, is placed in ...
*January 16, 2011*

**college math 209**

are you missing the exponent for 5y^ ?
*January 16, 2011*

**Algebra**

f = 6p p = f/6
*January 16, 2011*

**algebra 209**

3(sqrt250)= 3*(sqrt 25)* (sqrt 10) = 3 * 5 * (sqrt 10) = 15 (sqrt 10)
*January 16, 2011*

**Algebra**

the function is not clear to me what are the upside down ! ?
*January 16, 2011*

**algebra**

27^2/3 = (cube rt 27)^2 27^2/3 = 3^2 = 9
*January 16, 2011*

**algebra**

u = (sqrt(-u + 6)) u = (sqrt(6 - u)) square both sides u^2 = 6 - u u^2 + u - 6 complete the square u^2 + u = 6 u^2 + u + 1/4 = 6 + 1/4 (u + 1/2)^2 = 25/4 take the square root of both sides + - (u + 1/2) = 5/2 u + 1/2 = 5/2 u = 4/2 = 2 -u - 1/2 = 5/2 -u = 6/2 = 3 u = -3 check ...
*January 16, 2011*

**algebra**

do you mean u = (sqrt(-6 + u)) please use the word 'sqrt' and put in () what is included under the radical we will be able to assist you much faster if what you need is more clear thank you
*January 16, 2011*

**MATH**

Find AC? I assume you have a typo above? BC = BA + AC 5x - 3 = 2x + 5 + AC 3x - 8 = AC since A is the MP of BC and BA = 2x + 5 BC = 2(BA) BC = 2(2x + 5) BC = 4x + 10 BC = BC 5x - 3 = 4x + 10 x = 13
*January 16, 2011*

**college 209**

multiply (2 sqrt 7 -5 sqrt 3)(8 sqrt7-5 sqrt 3) (2 sqrt 7 -5 sqrt 3)(8 sqrt7-5 sqrt 3) 112 - 50(sqrt 21) + 75 187 - 50(sqrt 21)
*January 16, 2011*

**college 209**

square root of ? '2a7' means? does it mean 2(sqrt7)?
*January 16, 2011*

**college 209**

what does the ~ over the a mean? does '2a7' mean 2a^7 ('a' to the 7th power) ?
*January 16, 2011*

**math**

0.5x + 2 = 0.2x - 7 subtract 0.2x from both sides 0.3x + 2 = -7 0.3x = -9 x = -30
*January 16, 2011*

**algebra**

uã6w^3 + wã96wu^2 6w^2 au (w + 16u)
*January 16, 2011*

**math**

15% = .15 .15 * 100 = ?
*January 16, 2011*

**Math/Trig**

Area K = 1/2 r^2 * angle in rads Convert deg to rads 55 deg * pi/180 = 55pi/180 = 11pi/36 rads 11pi/36 rads = .96 rads K = 1/2 (5.7)^2 * .96 K = ?
*January 16, 2011*

**Math/Trig**

Arc length = r * central angle in rads 95 d = 95*pi/180 = 95pi/180 = 19pi/36 19pi/36 = 1.66 rads Arc length s = 2.5 * 1.66 Arc length s = ?
*January 16, 2011*

**math**

I'll do the first to get you started, you try the others and post back and someone will check your answers a. 3/2 x^5 'x’ raised to the power ‘5’, this means the equation is a 5th degree equation. the coefficient is number before the variable, in this ...
*January 16, 2011*

**Algbra**

3/5k - (k + 1/3) = 1/15 (k + 3) remove ( ) 3/5k - k - 1/3 = 1/15k + 3/15 get rid of denominators since 15 is the LCD of 5, 3, 15 multiplying both sides by 15 will do this 15 (3/5k - k - 1/3) = 15(1/15k + 3/15) 9k - 15k - 5 = k + 3 -6k - 5 = k + 3 -7k = 8 k = -8/7
*January 16, 2011*

**math**

I = PRT R = I/PT I = 20(196) - 3500 I = 3920 - 3500 I = 420 T = 20 mo/12 T = 1.667 yr R = I/PT R = 420/(3500 * 1.667) R = 420/5834.5 R = .071986 R = 7.2% check I = PRT I = 3500 x 7.2% x 1.667 yr I = 252 x 1.667 I = 420.084 I am not a tutor
*January 16, 2011*

**algebra**

1 < 3x+5 < 12 -4 < 3x < 7 -4/3 < x < 7/3
*January 16, 2011*

**math**

monitor A 22:12:06 monitor B 22:54:07 diff. = 42:01 42 min 1 sec = 42 + 1/60 42 min 1 sec = 42.01667 min 42.01667/60 = 0.700278 hr R = D/T R = 62/.700278 R = 88.53627 km/hr R = 88.54 km/hr check D = RT D = 88.54 x .70 D = 61.978 62 = 61.978 I am not a tutor
*January 16, 2011*

**Geometry**

Area = s^2 A = 8^2 A = ?
*January 16, 2011*

**algebra**

you need to use brackets to show what is under the radical
*January 15, 2011*

**math**

first find the LCD then solve as you would simultaneous equations in three unknowns try it and post back if you need more help
*January 15, 2011*

**math**

are you missing something 16x + 13z = ?
*January 15, 2011*

**algebra**

(sqrt(6x + 6)) = (sqrt(x + 12)) square both sides 6x + 6 = x + 12 5x = 6 x = 6/5 without the use of ( ) I assumed sqrt of (6x + 6) and sqrt of (x + 12)
*January 15, 2011*

**algebra 1**

The equation of the straight line having slope m and y intercept b is y = mx + b m = 6.7 b = -7 y = 6.7x - 7
*January 15, 2011*

**college math 209**

u - 18 = 2 u = 20
*January 15, 2011*

**college math 209**

is this the equation ?, 2(sqrt5) + 3/(sqrt5) - 1 2(sqrt5) + 3(sqrt5)/5 - 1 to get rid of the radical in 3/(sqrt5). multiply 3/(sqrt5)*sqrt5/sqrt5 = 3(sqrt5)/5
*January 15, 2011*

**algebra 1**

the point would be (0,-3) for the graph plot the point and draw a line through it, this will be a line at y = -3, -3 units below and parallel to the x-axis
*January 15, 2011*

**ALGEBRA**

the rate is 15%
*January 15, 2011*

**6th grade math**

yes, you are correct
*January 15, 2011*

**statistics**

question? you are missing part of the problem
*January 15, 2011*

**Geometry**

Sum of measures of interior angles of a polygon of n sides = (n - 2 )*180 deg polygon with 4 sides, n = 4 (n - 2)*180 (4 - 2)*180 2*180 = 360
*January 15, 2011*

**math**

want do you need to find? this problem is not complete
*January 15, 2011*

**Math**

x = number of graph notebooks y = number of college ruled notebooks 2.64x = total value sold graph notebooks 3.61y = total value sold college notebooks x + y = 50 2.64x + 3.61y = 168.86 Solve these 2 equations together by elimination or substitution method I will use ...
*January 15, 2011*

**algebra**

I made the correction below let her regular rate be $x per hour let her overtime rate be $y per hour first week: 40x + 7y = 390 2nd week: 42x + 8y = 416 1st equat x 8 ---> 320x +56y = 3120 2nd equt x 7 ---> 294x + 56y = 2912 subtract 26x = 208 x = 8 substitute x = 8 40x...
*January 15, 2011*

**algebra 2**

ln(e^18x) = 9 Since, ln e^x = x ln e^18x = 18x 18x = 9 x = 2
*January 15, 2011*

**geometry**

not enough info posted to answer are RS and ST parts of RT ? Not sure if this pic will print right. Ignore if it doesn't. R------------S-------------T 12 13 What is A ?
*January 15, 2011*

**mgt**

who is "her" ?
*January 14, 2011*

**Math**

you have to draw a picture for this. If I did it right, I would think you would want the water line to run in a straight line from MW. To find the point on the water main, step 1--I wrote the equation of the line from M to W, using the given points. Equation MW - y = 4x - 6 ...
*January 14, 2011*

**math**

you're welcome
*January 14, 2011*

**math**

if you can picture this, it forms a rt triangle with the shortest leg 2, the longer leg 3, and you are looking for the hypotenuse. So, h^2 = 2^2 + 3^3 h^2 = 4 + 9 h^2 = 13 h = sqrt 13
*January 14, 2011*

**geometry**

V = Lwh the volume (given) = 24 ft^3 the height (given) = 18" = 1.5' 24 = L*w*1.5 divide both sides by 1.5 16 = Lw You need to find the number of feet in each side of the base since the box has a square base L = W AND, found above, L*w = 16 which of the above answers...
*January 14, 2011*

**business math**

you didn't give a time limit for the $20,000, so I'll assume 5yrs FV = PMT * (((1 + i)^n - 1)/i ) x = amt of PMT i = rate n = no. of payments i = .08/4 quarters = .02 n = 4 * 5 yr = 20 payments 20,000 = x *((1 + .02)^20 - 1 )/.02 20,000 = x *(( 1.02 )^20 - 1)/ .02 20,...
*January 14, 2011*

**algebra**

| x - 8 | < 14 this means x - 8 < 14 x < 22 -x + 8 < 14 -x < 6 x > -6 therefore, -6 < x < 22
*January 14, 2011*

**Math/Trig**

Area K = 1/2 r^2 * angle in rads Convert deg to rads 125 deg * pi/180 = 25pi/36 rads K = 1/2 * 3^2 * 25pi/36 K = ? m^2 you do the math Area K is expressed in m^2 (in this case)
*January 14, 2011*

**Algrebra II-please check my answer**

1. (-9/7, 0) you are correct 2. correct, but should be written as 2 <= x <= 8
*January 14, 2011*

**geometry**

30-60-90 special triangle has sides in the ratio of 1 : sqrt 3 : 2 (a:b:c) sin A = a/c = 1/2 hypotenuse = c = h side a = h - 12 (opposite 30 deg angle) set-up a ratio 1/2 = (h - 12)/h cross multiply h = 2(h - 12) h = 2h - 24 -h = -24 h = 24 hypotenuse = 24 side a (opposite 30 ...
*January 14, 2011*

**algebra**

x^2 - x - 6 list factors of -6, -6 x 1 = -6 6 x -1 = -6 -3 x 2 = -6 3 x -2 = -6 which factors of -6, when added, = -1 -6 + 1 = -5 N0 6 + -1 = 5 NO -3 + 2 = -1 YES x^2 - x - 6 = (x - 3)(x + 2) x^2 - 5x - 24 list factors of -24, -24 x 1 = -24 24 x -1 = -24 -12 x 2 = -24 12 x -2...
*January 14, 2011*

**algebra**

yes, you are correct
*January 14, 2011*

**geometry**

is this a triangle, square, rectangle or ? are AB, ST, AC sides, medians, or ? are A, T angles ?
*January 14, 2011*

**symbols**

assuming all the men take the same amount of time to milk each cow, 53 cows / 4 men = 13.25 cows each since you can't milk a fraction of a cow three men would milk 13 cows each and one man would milk 14 so the answer would be no, each man does not milk the same number of ...
*January 14, 2011*

**Algebra**

see you post below, I showed you there
*January 14, 2011*

**Algebra**

(1) x + y = 105 (2) 3x + 1.5y = 250 multiply equation (1) by -3 -3 (x + y = 105) = -3x - 3y = -315 add the two equations together -3x - 3y = -315 3x + 1.5y = 250 0 - 1.5y = - 65 -1.5y = -65 y = 43.33 student tkts x + y = 105 x + 43.33 = 105 x = 61.67 student tkts are you sure ...
*January 14, 2011*

**Algebra**

x = adult tkts y = student tkts 3x = value of adult tkts 1.5y = value of student tkts x + y = 105 3x + 1.5y = 250 solve these equation together for your answer post back if you need more help
*January 14, 2011*

**8th grade math**

not enough info to solve this,
*January 13, 2011*

**Pre-Calculus**

3. 30-60-90 special triangle draw this out to see that you need to find side a (shorter side) of triangle ABC 30-60-90 triangle have sides in the ratio of 1 : sqrt 3 : 2 (a : b : c) Since side b = 10 cos 30 = b/c = 10/c since ratio of b/c = sqrt 3/2 sqrt 3/2 = 10/c cross ...
*January 13, 2011*

**Pre-Calculus**

I think the tutors like you to post each problem as a separate post.
*January 13, 2011*

**trigonometry**

my trig book has tables in degrees and minutes for example, look-up sin 24 deg 40 min and sin 24 deg 50 min. cal. the correction and add to the smaller angle for sin, tan, sec (subtract the correction for cos, cot, csc) sin 24d 40' = .4173 sin 24d 50' = .4200 ...
*January 13, 2011*

**3 G Math**

9 x 8 x any number = 72 x any number 2 x 9 x 4 = 72 the second one the FINAL answer is 72 the first one will be higher if you multiply 72 by any other number but 1, because 72 x 1 = 72, then they will be equal but if any number is greater than 1, then the first will be higher ...
*January 13, 2011*

**4th grade**

you have to post the question you need help with
*January 13, 2011*

**Geometry**

I can't believe I didn't think to do it your way!!! so much easier to do AND understand that's why you are the tutor thank you I've learned so much from your posts! I wish I had you to ask questions when I was taking math.
*January 13, 2011*

**Geometry**

I don't understand what you are asking use this formula TA = 2Lw + 2Lh + 2wh use these dimensions 1st use, L = 2, w = 3, h = 4 then quadruple the dimensions to compare how the area changed 2nd use L = 8, w = 12, h = 16 (I quadrupled the dimensions for you) you can use any ...
*January 13, 2011*