Wednesday

May 4, 2016
Total # Posts: 1,776

**Algebra 2**

L = length w = L - 3 A = Lw 28 = L * (L - 3) 28 = L^2 - 3L L^2 - 3L - 28 = 0 solve by completing the square if you are right L = -4, L = 7 since length can't be neg., throw out -4, so L = 7 and width = 4
*January 17, 2011*

**Math**

C = pi* d or C = 2* pi r C = pi * 10 C = 10pi
*January 17, 2011*

**Math (Algebra 2)**

answer is 5x^3 - 14x^2/3 - 40x/9 + 256/27 + (230/27)/(3x + 1) this is really something you need to do yourself because I can't show you how, I can only give you the answer
*January 17, 2011*

**Algebra 2**

x = heather now 5x = george now 5x + 4 = 3(x + 4) 5x + 4 = 3x + 12 2x = 8 x = 4 heather - 4 george - 20
*January 17, 2011*

**5th math**

I don't think anyone understands what the 'sample space' is, at least that is why I haven't answered. It seems like 5th grade math is harder than calculus!!
*January 17, 2011*

**RATIOS MATH**

x : 6 = 20 : 24 x/6 = 20/24 cross multiply 24x = 120 x = 5
*January 17, 2011*

**MaTh = Algebra = help**

How did you get -2 as an answer? Did you divide 5x by 5 and 10 by five to get 2? YES You lost me right here: How did you do this? x - 2y = 10 -2 - 2y = 10 -2y = 12 y = -6 How did you get the second line? -2 - 2y = 10? to find the value of y, since you know x = -2, you plug x...
*January 17, 2011*

**MaTh = Algebra = help**

x - 2y = 10 3x - y = 0 eliminate y by multiplying 3x - y = 0 by -2 -2(3x - y = 0) = -6x + 2y = 0 ADD the 2 equations x - 2y = 10 -6x + 2y = 0 -5x + 0 = 10 -5x = 10 x = -2 substitute x = -2 in x - 2y = 10, to find y x - 2y = 10 -2 - 2y = 10 -2y = 12 y = -6 check x = -2, y = -6 ...
*January 17, 2011*

**Math**

A = Lw w = width 2w = length 200 = w(2w) 200 = 2w^2 100 = w^2 10 = w P = 2L + 2w w = 10 L = 2w = 20 P = 2(10) + 2(20) P = ?
*January 17, 2011*

**Math**

TA = 6e^2 TA = 6(2^2) TA = 6 (4) TA = 24 m^2
*January 17, 2011*

**Math**

V = 4/3 pi r^3 V = 4/3 pi (5^3) V = ?
*January 17, 2011*

**Math**

A = 4 pi r^2 A = 4 pi (5^2) A = ?
*January 17, 2011*

**Math**

see first link below under related questions your post was answered already below please do not repost without checking to see if your original post was answered
*January 17, 2011*

**Math grade7**

ADD up purchases and earnings -12.00 + 15.00 - 7.00 - 8.50 + 8.00 + 2.00 = - 2.50 x = money she started with x + -2.50 = 22.25 x = 22.25 + 2.50 x = 24.75
*January 17, 2011*

**Math**

I cos (2x/3) dx = 3/2 sin (2x/3) sorry, forgot 0 to pi/2 3/2 sin 2/3 (pi/2) - 3/2 sin 0 3/2 sin (2pi/6) - 0 3/2 sin (pi/3) 3/2 (sqrt3/2) 3 sqrt3/4
*January 17, 2011*

**Math**

Integrate cos (2x/3) dx u = 2x/3 du = 2/3 dx 3/2 du = dx I = integrate symbol I cos (2x/3) dx = I cos u 3/2 du I cos (2x/3) dx = 3/2 I cos u du I cos (2x/3) dx = 3/2 sins u since, u = 2x/3 I cos (2x/3) dx = 3/2 sin (2x/3)
*January 17, 2011*

**Calculus**

7x + 42 = 7(x + 6)
*January 17, 2011*

**math(algebra 1)**

y = -x + 3 y = x + 1 rewrite y + x = 3 y - x = 1 to eliminate the variable x, add the 2 equations together. Since x + -x = 0, the x variable is eliminated ADD y + x = 3 y - x = 1 2y = 4 y = 2 to find x, substitute y = 2 in y + x = 3 2 + x = 3 x = 1 CHECK x = 1, y = 2 y - x = 1...
*January 17, 2011*

**math**

x = kim's points x + 5 = lynn's points 3(x + 5) = camilla's points x + x + 5 + 3(x + 5) = 50 x + x + 5 + 3x + 15 = 50 5x + 20 = 50 5x = 30 x = 6 kim has 6 pts lynn has 11 pts camilla has 33 pts
*January 17, 2011*

**Math**

4 log x - 2 log y + 1/3 log w (4 log x + 1/3 log w) - 2 log y (log x^4 + log w^1/3) - log y^2 log (x^4 w^1/3) - log y^2 log (x^4 w^1/3)/y^2 I am not a tutor
*January 17, 2011*

**geometry**

A 45-45-90 deg triangle is one-half a square. The length of a leg opposite a 45 deg angle equals one-half the length of the hypotenuse times the square root of 2. to find one of the sides of the square, c = a * sqrt2 (the diagonal) 8(sqrt2) = a * sqrt2 a = 8 P = 4s P = 4 * 8 P...
*January 17, 2011*

**Math**

integrate (x+1)sqrt(2-x)dx u = (sqrt(2 - x)) u^2 = 2 - x x = 2 - u^2 - 2u du = dx I = integral sign I (2 - u^2 + 1)u -2u du I (3 - u^2)-2u^2 du I (-6u^2 + 2u^4) du -6 I u^2 du + 2 I u^4 du 2 I u^4 du - 6 I u^2 du 2 (1/5 u^5) - 6 (1/3 u^3) 2/5 u^5 - 2u^3 substitute back in for ...
*January 17, 2011*

**Math**

see your post above answered already
*January 17, 2011*

**math**

see solution above, I figured that the second '=' sign was supposed to be '+'
*January 17, 2011*

**math**

-3(4b-10) = .5(-24b+60) -12b + 30 = -12b + 30 all values of b are solutions
*January 17, 2011*

** math**

3 (g-3) = 6 3g - 9 = 6 3g = 15 g = 5
*January 17, 2011*

**Math**

The measure of an interior angle is one half of the measure of the intercepted arc.
*January 17, 2011*

**math**

A parallelogram is a four sided figure with its opposite sides parallel to each other. A rectangle is a parallelogram whose four angles are all 90' so draw a parallelogram such that the sides, (width), are parallel to each other but NOT perpendicular to the base (so the 90...
*January 17, 2011*

**math**

see first link below under related questions REINY already answered part of this if you are having trouble, post your work and someone will help if you are stuck tutors do not do your homework for you
*January 17, 2011*

**geometry**

use the Pythagorean theorem 25^2 = b^2 + x^2 now solve for b
*January 17, 2011*

**math**

1 7/5 1 = 5/5 5/5 + 7/5 = 12/5 is this what you need? or 1 7/5 = 12/5 = 2 2/5 because 12 divided by 5 = 2 2/5
*January 17, 2011*

**math**

you're welcome :)
*January 17, 2011*

**math**

25 < n - 12 37 < n n > 37
*January 17, 2011*

**algebra**

p = pennies 2p - 9 = nickles 3p - 19 = dimes p + 2p - 9 + 3p - 19 = 140 6p - 28 = 140 6p = 168 p = 28 p = pennies = 28 2p - 9 = nickles = 47 3p - 19 = 65
*January 17, 2011*

**Algebra 2 **

g(f(x))= 2(x^2 + 1)^2 = 2 (x^4 + 2x^2 + 1) = 2x^4 + 4x^2 + 2
*January 17, 2011*

**Math**

A = x^2 - 10x + 25 = (x - 5)(x - 5) A = Lw L = (x - 5), w = (x - 5) P = 2w + 2L P = 2(x - 5) + 2(x - 5) P = 2x - 10 + 2x - 10 P = 4x - 20
*January 17, 2011*

**Math**

A = Lw L = 5x + 10 w = 5x - 5 A = (5x + 10)(5x - 5) A = ? expand and collect like terms for your answer
*January 17, 2011*

**Math**

the expression needs to be simplified I tried
*January 17, 2011*

**math**

4 C 2 = combination of 4, taken 2 at a time C(4,2) = (4!/(4 - 2)!)/2! = 4!/(2!2!) C(4,2) = (4x3x2x1)/(2x1x2x1)= 24/4 = 6 total of 6 combinations 1 out of 6 possible combinations I am not a tutor
*January 17, 2011*

**mat h**

x = amt at 3% y = amt at 5% x + y = 2000 .03x + .05y = 84 solve simultaneously for x, y give it a try, post if you need for help x = 800, y = 1200 if you are right
*January 17, 2011*

**math**

6x^2-1 = -1/6 (sqrt6 - 6x)(sqrt6 + 6x)
*January 17, 2011*

**geometry**

if you sketch this you will see that the median from Q, bisects segment PR to write the equation of the median you need to find the midpoint of PR P(0,12), R(-2,2) using the midpoint formula 1/2 (x1 + x2), 1/2 (y1 + y2) 1/2(0 + -2), 1/2(12 + 2) 1/2(-2), 1/2(14) Midpoint (-1,7...
*January 17, 2011*

**Algebra**

3x-2y=10 2x+3y=-2 By substitution 3x - 2y = 10 2x + 3y = -2 3x = 10 + 2y x = 10/3 + 2/3 y 2(10/3 + 2/3 y) + 3y = -2 20/3 + 4/3 y + 3y = -2 20/3 + 4/3 y + 9/3 y = -2 20/3 + 13/3 y = -2 13/3 y = -2 - 20/3 13/3 y = -6/3 - 20/3 13/3 y = - 26/3 y = -26/3 * 3/13 y = - 78/39 = -2 to ...
*January 17, 2011*

**Math**

300 km/h to mph 1 mph = 1.609344 km/hr 300/1.609344 = 186.411358 mph
*January 17, 2011*

**Math**

:) sometimes the easiest problem stumps me!
*January 17, 2011*

**Math**

By Property of Exponential Function, a^0 = 1 (abc)^0 = 1
*January 17, 2011*

**Math**

yes, ^ means squared. if no parentheses, I don't know why I am not a tutor, maybe REINY or another tutor will answer
*January 17, 2011*

**Math**

was the problem written as -(5^2) = -(25)= -25 where, (-5^2) = 25
*January 17, 2011*

**Math**

correct!! :)
*January 17, 2011*

**Math**

set up as equation and solve for N 2/3 N = 4 2N = 12 N = 6 1/2 N = ? N = 6 1/2 6 = ?
*January 17, 2011*

**Math**

22,000 cost before interest less 3,000 down payment 19,000 amount financed 600/mo for 40 mo = 24,000 total cost with interest 24,000 - 19,000 = 5000.00 interest on amt financed 5000/19000 = 26.32% simple interest rate 5000 finance chrg 19,000 amount financed 24,000 installment...
*January 17, 2011*

**math**

you are missing the exponents if (a) should be 2x^2 - 7x - 5 a) 2x^2 - 7x - 5 does not factor, solve by using the quadratic formula or completing the square if you are stuck, post your work and someone will help tutors do not do your homework
*January 17, 2011*

**Algebra II**

is this your problem (x^2 - 1)/1 divided by (x - 1)/(x + 5)? if so, (x^2 - 1)/1 = x^2 - 1 to divide, invert the denominator and multiply, so, (x^2 - 1) * (x + 5)/(x - 1) does this help?
*January 17, 2011*

**math**

2^(x-2)=54 take logarithm of both sides (x - 2)log 2 = log 54 x log 2 - 2 log 2 = log 54 x log 2 = log 54 + 2 log 2 x = (log 54 + 2 log 2)/log 2 find above logs x = 7.75 approx
*January 17, 2011*

**alegebra 2**

recheck your problem, not enough info given
*January 17, 2011*

**Calculus**

If this is your problem 2^-x = 3^(2x+2) take logarithms of both sides -x log 2 = (2x + 2)log 3 -x log 2 = 2x log 3 + 2 log 3 -x log 2 - 2x log 3 = 2 log 3 x (-log 2 - 2 log 3) = 2 log 3 x = -(2 log 3)/(log 2 + 2 log 3) plug in log values x = -0.760188
*January 17, 2011*

**Calculus**

see above post of yours
*January 17, 2011*

**Maths**

(3^-2e^4)^-1 = (1/9 * e^4)^-1 = (e^4/9)^-1 = 1/(e^4/9) = 9/e^4
*January 17, 2011*

**Algebra**

5 - 31 + 29 = ?
*January 17, 2011*

**Phsyics**

see this website to convert I can't post links so, put a / where there is a comma, and the usual other that you put before an address easysurf dot cc,cnver14 dot htm
*January 17, 2011*

**Algebra**

(5 + 31 + 29)/3 = average
*January 16, 2011*

**math**

simple interest I = PRT I = 5000 * .04 * 1.5 I = 300
*January 16, 2011*

**Algebra**

P = 2w + 2L 2*17 + 2L > 94 34 + 2L > 94 2L > 60 L > 30 length > 30 cm
*January 16, 2011*

**Maths**

3x - 6 = 3x/4 multiply both sides by 4 12x - 24 = 3x 9x = 24 x = 24/9 x = 8/3
*January 16, 2011*

**college math 209**

x = - b ± (sqrt(b^2 - 4ac))/2a 3x^2 + x - 8 = 0 a = 3, b = 1, c = -8 what do you need help with? I gave you the formula, you give it a try, post your work if you get stuck. tutors do not do your homework. they are here to help you do your work.
*January 16, 2011*

**college math 209**

(x+4)^2 = 2x^2 + 19x + 46 (x + 4)(x + 4) = 2x^2 + 19x + 46 x^2 + 8x + 16 = 2x^2 + 19x + 46 collect like terms, then solve you try and post back if you need help
*January 16, 2011*

**Writing**

from About dotcom, Homework/Study tips "Individual works of art like paintings and sculptures are underlined or italicized" * Michelangelo's David * Mona Lisa * The Last Supper * The Pieta A photograph, which is much smaller than a work of art, is placed in ...
*January 16, 2011*

**college math 209**

are you missing the exponent for 5y^ ?
*January 16, 2011*

**Algebra**

f = 6p p = f/6
*January 16, 2011*

**algebra 209**

3(sqrt250)= 3*(sqrt 25)* (sqrt 10) = 3 * 5 * (sqrt 10) = 15 (sqrt 10)
*January 16, 2011*

**Algebra**

the function is not clear to me what are the upside down ! ?
*January 16, 2011*

**algebra**

27^2/3 = (cube rt 27)^2 27^2/3 = 3^2 = 9
*January 16, 2011*

**algebra**

u = (sqrt(-u + 6)) u = (sqrt(6 - u)) square both sides u^2 = 6 - u u^2 + u - 6 complete the square u^2 + u = 6 u^2 + u + 1/4 = 6 + 1/4 (u + 1/2)^2 = 25/4 take the square root of both sides + - (u + 1/2) = 5/2 u + 1/2 = 5/2 u = 4/2 = 2 -u - 1/2 = 5/2 -u = 6/2 = 3 u = -3 check ...
*January 16, 2011*

**algebra**

do you mean u = (sqrt(-6 + u)) please use the word 'sqrt' and put in () what is included under the radical we will be able to assist you much faster if what you need is more clear thank you
*January 16, 2011*

**MATH**

Find AC? I assume you have a typo above? BC = BA + AC 5x - 3 = 2x + 5 + AC 3x - 8 = AC since A is the MP of BC and BA = 2x + 5 BC = 2(BA) BC = 2(2x + 5) BC = 4x + 10 BC = BC 5x - 3 = 4x + 10 x = 13
*January 16, 2011*

**college 209**

multiply (2 sqrt 7 -5 sqrt 3)(8 sqrt7-5 sqrt 3) (2 sqrt 7 -5 sqrt 3)(8 sqrt7-5 sqrt 3) 112 - 50(sqrt 21) + 75 187 - 50(sqrt 21)
*January 16, 2011*

**college 209**

square root of ? '2a7' means? does it mean 2(sqrt7)?
*January 16, 2011*

**college 209**

what does the ~ over the a mean? does '2a7' mean 2a^7 ('a' to the 7th power) ?
*January 16, 2011*

**math**

0.5x + 2 = 0.2x - 7 subtract 0.2x from both sides 0.3x + 2 = -7 0.3x = -9 x = -30
*January 16, 2011*

**algebra**

uã6w^3 + wã96wu^2 6w^2 au (w + 16u)
*January 16, 2011*

**math**

15% = .15 .15 * 100 = ?
*January 16, 2011*

**Math/Trig**

Area K = 1/2 r^2 * angle in rads Convert deg to rads 55 deg * pi/180 = 55pi/180 = 11pi/36 rads 11pi/36 rads = .96 rads K = 1/2 (5.7)^2 * .96 K = ?
*January 16, 2011*

**Math/Trig**

Arc length = r * central angle in rads 95 d = 95*pi/180 = 95pi/180 = 19pi/36 19pi/36 = 1.66 rads Arc length s = 2.5 * 1.66 Arc length s = ?
*January 16, 2011*

**math**

I'll do the first to get you started, you try the others and post back and someone will check your answers a. 3/2 x^5 'x’ raised to the power ‘5’, this means the equation is a 5th degree equation. the coefficient is number before the variable, in this ...
*January 16, 2011*

**Algbra**

3/5k - (k + 1/3) = 1/15 (k + 3) remove ( ) 3/5k - k - 1/3 = 1/15k + 3/15 get rid of denominators since 15 is the LCD of 5, 3, 15 multiplying both sides by 15 will do this 15 (3/5k - k - 1/3) = 15(1/15k + 3/15) 9k - 15k - 5 = k + 3 -6k - 5 = k + 3 -7k = 8 k = -8/7
*January 16, 2011*

**math**

I = PRT R = I/PT I = 20(196) - 3500 I = 3920 - 3500 I = 420 T = 20 mo/12 T = 1.667 yr R = I/PT R = 420/(3500 * 1.667) R = 420/5834.5 R = .071986 R = 7.2% check I = PRT I = 3500 x 7.2% x 1.667 yr I = 252 x 1.667 I = 420.084 I am not a tutor
*January 16, 2011*

**algebra**

1 < 3x+5 < 12 -4 < 3x < 7 -4/3 < x < 7/3
*January 16, 2011*

**math**

monitor A 22:12:06 monitor B 22:54:07 diff. = 42:01 42 min 1 sec = 42 + 1/60 42 min 1 sec = 42.01667 min 42.01667/60 = 0.700278 hr R = D/T R = 62/.700278 R = 88.53627 km/hr R = 88.54 km/hr check D = RT D = 88.54 x .70 D = 61.978 62 = 61.978 I am not a tutor
*January 16, 2011*

**Geometry**

Area = s^2 A = 8^2 A = ?
*January 16, 2011*

**algebra**

you need to use brackets to show what is under the radical
*January 15, 2011*

**math**

first find the LCD then solve as you would simultaneous equations in three unknowns try it and post back if you need more help
*January 15, 2011*

**math**

are you missing something 16x + 13z = ?
*January 15, 2011*

**algebra**

(sqrt(6x + 6)) = (sqrt(x + 12)) square both sides 6x + 6 = x + 12 5x = 6 x = 6/5 without the use of ( ) I assumed sqrt of (6x + 6) and sqrt of (x + 12)
*January 15, 2011*

**algebra 1**

The equation of the straight line having slope m and y intercept b is y = mx + b m = 6.7 b = -7 y = 6.7x - 7
*January 15, 2011*

**college math 209**

u - 18 = 2 u = 20
*January 15, 2011*

**college math 209**

is this the equation ?, 2(sqrt5) + 3/(sqrt5) - 1 2(sqrt5) + 3(sqrt5)/5 - 1 to get rid of the radical in 3/(sqrt5). multiply 3/(sqrt5)*sqrt5/sqrt5 = 3(sqrt5)/5
*January 15, 2011*

**algebra 1**

the point would be (0,-3) for the graph plot the point and draw a line through it, this will be a line at y = -3, -3 units below and parallel to the x-axis
*January 15, 2011*

**ALGEBRA**

the rate is 15%
*January 15, 2011*

**6th grade math**

yes, you are correct
*January 15, 2011*

**statistics**

question? you are missing part of the problem
*January 15, 2011*