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August 1, 2015

August 1, 2015

Total # Posts: 1,739

**math(algebra 1)**

1)3x + y = 0, x - y = 4 Pick and equation, and solve for either x or y x - y = 4 x = 4 + y Substitute, x = 4 + y, for x, in the other equation and solve for y x = 4 + y 3x + y = 0 3(4 + y) + y = 0 12 + 3y + y = 0 12 + 4y = 0 4y = -12 y = -3 substitute y = -3 in either equation...
*January 18, 2011*

**Math**

43 heads = 43 animals ( I hope!!) C = number of chickens G = number of goats C + G = 43 2C + 4G = 108 solve simultaneously to find C and G if you are right, C = 32 G = 11
*January 18, 2011*

**algebra**

set up ratio 3/2.5 = x/8 2.5x = 24 x = 9.6 $9.60 for 8
*January 18, 2011*

**5th math**

4 feet = 4 x 12 in/ft = 48 inches from above, this should say write down the most times a factor was used within one factorization
*January 18, 2011*

**5th math**

mean is the average add all the numbers to get the sum divide the sum by the number of numbers you are adding. 33 + 41 + 37 + 27 + 32 = 170 since there are 5 numbers, you divide the sum by 5, to get the mean 170/5 = 34 the mean is 34 LCM 6, 4, 8 LCM is 24 how I was taught ...
*January 18, 2011*

**math**

b. 8th:7th = 2:3
*January 18, 2011*

**Math**

A = 4pir^2 TA = 4(3.14)(5^2) TA = 4(3.14)(25) TA = ?
*January 18, 2011*

**math**

y^2-3y=9 y^2 - 3y = 9 complete the square y^2 - 3y + 9/4 = 9 + 9/4 (y - 3/2)^2 = 45/4 +- (y - 3/2) = 45/4 solve for y y = 3/2 (sqrt5 + 1) y = -3/2 (-1 + sqrt5)
*January 18, 2011*

**algebra 2 and trigonometry**

y^2-3y=9 y^2 - 3y = 9 complete the square y^2 - 3y + 9/4 = 9 + 9/4 (y - 3/2)^2 = 45/4 +- (y - 3/2) = 45/4 solve for y y = 3/2 (sqrt5 + 1) y = -3/2 (-1 + sqrt5)
*January 18, 2011*

**math**

6th - 125 7th - 150 8th- 100 a) ratio 6th:7th 125:150 = 5:6 b) 8th:7th 100:150 = 4:6 = 2:3 c) 6th: total = 125:375 = 5:15 = 1:3 d) 8th:total = 100:375 = 4:15 check your b. ratio 2:3, not 3:2
*January 18, 2011*

**math**

ratio to what? 125 : 150 : 100 5 : 6 : 4
*January 18, 2011*

**Pre-Algebra**

vinegar - pH 3 baking soda - pH 9 9 - 3 = 6 units diff. 10 x 6 = 60x as acidic 10^6 = 1 million, so I can't see how that is right 10^1.77815 = 60 or, 6 x 10^1 = 60 is this a pre-algebra question or science?
*January 18, 2011*

**trig**

restate your question. I don't understand. is this a right triangle? "i have one degree 25" What does this mean? side b = 2.489 * 10^9 ? or 2,489,000,000? post question exactly as written from your book.
*January 18, 2011*

**Pre-Algebra**

:) that's ok. also, you will have better response if posted separate.
*January 18, 2011*

**Pre-Algebra**

vinegar - pH 3 baking soda - pH 9 9 - 3 = 6 units diff. 10 x 6 = 60x as acidic 10^6 = 1 million, so I can't see how that is right 10^1.77815 = 60 I am not a tutor, so you might want to repost this as a separate question
*January 18, 2011*

**Pre-Algebra**

if this is what you mean 1) a^8/a^8 = 1 2) -x^5/-x^4 = x 3) 15/5 * n^9/n = 3n^8 Also, use separate posts for 2 different questions/subjects
*January 18, 2011*

**math**

not enough info to find d and c post the whole problem
*January 18, 2011*

**math 1 digit divisors word problem**

you're welcome :)
*January 18, 2011*

**math 1 digit divisors word problem**

To have a remainder of 8, the divisor must be greater than 8. The only single digit greater than 8 is 9, so 9 must be the divisor. Since 8 is 1 less than 9, the dividend needs to be one less than a multiple of 9. Candidates are values of 3 digits, as the problem states. The ...
*January 18, 2011*

**Emploument English**

true, you are correct
*January 18, 2011*

**Math**

7 1/4 = 29/4 = 58/8 3 3/8 = 27/8 58/8 - 27/8 = 31/8 = 3 7/8
*January 18, 2011*

**math**

see your 1st post
*January 18, 2011*

**math**

7560 = 756. x 10^1 but like Esskay said above, scientific notation would not be used for 7560
*January 18, 2011*

**Sex Ed(English)**

A. 12 weeks
*January 18, 2011*

**math**

x/y - z = rw solve for x x - yz = yrw x = yrw + yz x = y(rw + z) A
*January 18, 2011*

**algebra**

-7 = -1/6x -42 = -x x = 42
*January 18, 2011*

**Sex Ed(English)**

thanks Writeacher, I was not clear :)
*January 18, 2011*

**Sex Ed(English)**

true
*January 18, 2011*

**math**

1/20 of 1.00 = .05 so, 1 nickle or 5 pennies
*January 18, 2011*

**Sex Ed(English)**

VERY correct
*January 18, 2011*

**geometry**

14q + 8 + 8q - 6 = 90 22q + 2 = 90 22q = 88 q = 4 14q + 8 = 64 8q - 6 = 26 64 + 26 = 90
*January 18, 2011*

**Sex Ed(English)**

true
*January 18, 2011*

**math**

5 : x = 25 : 30 5/x = 25/30 cross multiply 150 = 25x x = 6
*January 18, 2011*

**math**

60 x .80 = 48 spent 60 - 48 = 12 left to invest 12 x .80 = 9.60 $9.60
*January 18, 2011*

**Math**

see your 1st post
*January 18, 2011*

**math**

6x - 4y - 3x + y 3x - 3y
*January 18, 2011*

**math**

600 x .06 x 5 = ?
*January 18, 2011*

**MATHAROOO**

think of the midpoint of a line as being the half-point of a line there can only be one point that divides this line into 2 equal parts A--------MP--------B A--------C--------B C is the midpoint of line AB now, you could find the midpoint of segment AC A----MP----C--------B A...
*January 18, 2011*

**Math/Radical Expressions**

If this is your equation g/t + g - g/t - g = 0
*January 18, 2011*

**MATH**

6/330 =0.018182
*January 18, 2011*

**Math**

5x = 4y - 30 2x + 3y +-12 (1) 5x - 4y = -30 (2) 2x + 3y = 12 multiply (1) by 3(5x - 4y = -30) (1) 15x + 12y = -90 multiply (2) by 4(2x + 3y = 12) (2) 8x + 12y = 48 ADD two new equations (1) 15x + 12y = -90 (2) 8x + 12y = 48 23x + 0 = -42 23x = -42 x = -42/23 substitute x = -42...
*January 18, 2011*

**math**

correction-this should be net salary * 12 mo. = annual net salary
*January 18, 2011*

**math**

you have a typo in $2,3500.00 Monthly wage - 468 = net salary net salary * 52 weeks = annual net salary
*January 18, 2011*

**math**

1 1/12 = 13/12 2 = 24/12 24/12 - 13/12 = 11/12 left
*January 18, 2011*

**math**

165/3 = ?
*January 18, 2011*

**algebra**

3x - 5y = 61 3x - y = 17 multiply 1st by -1(3x - 5y = 61) -3x + 5y = -61 3x - y = 17 ADD two equations 0 + 4y = - 44 4y = -44 y = -11 substitute y = -11 in 3x - y = 17 to find x 3x - y = 17 3x + 11 = 17 3x = 6 x = 2 check x = 2, y = -11 in one of the equations I'll leave ...
*January 18, 2011*

**Math**

r = 5, h = 10 SA = 2 pi r^2 + 2 pi r h SA = 2(pi)(5^2) + 2(pi)(5)(10) SA = 2(pi)(25) + 2(pi)(5)(10) SA = 50pi + 100pi SA = 150 pi m^2 do you have the formula for a right circular cylinder? I've checked my math and I get 150pi m^2 if you can post the formula from your book ...
*January 18, 2011*

**Math**

r = 5, h = 10 SA = 2 pi r^2 + 2 pi r h SA = 2(3.14)(5^2) + 2(3.14)(5)(10) SA = 2(3.14)(25) + 2(3.14)(5)(10) SA = 50(3.14) + 100(3.14) SA = 157 + 314 = 471 m^2
*January 18, 2011*

**algreba**

n = number of trees 84n <= 2400 n <= 28.57
*January 18, 2011*

**math**

this is an easy one to graph. just pick some values for x or y and solve for the other value what are you having trouble doing? we can't graph it for you. for y = x + 1 x = 0, y = 1 (0,1) x = 1, y = 2 (1,2) x = 2, y = 3 (2,3) x = 3, y = 4 (3.4) x = 4, y = 5 (4,5) for y = ...
*January 18, 2011*

**Calculus**

forgot to add, there are other forms for this answer post your answer if you are not sure if equil. to above posted answers
*January 18, 2011*

**Calculus**

Answer 1/3 (sqrt(x^2 + 100))^3 - 100(sqrt(x^2+100)) + C this can be transformed into 1/3 (x^2 - 200)(sqrt(x^2 + 100) + C my book had 1st answer (not transformed) let me know if you need more help with this
*January 18, 2011*

**math**

A = Lw A = 9 * 3 A = 27 sq ft/units 27 * 12 = ?
*January 18, 2011*

**math**

I used an online calculator for this Mean = 59.64 Median = 58 Sample standard deviation = 10.19
*January 18, 2011*

**math**

this is a permutations 3 cds / 3 cases = 3! = 3 x 2 x 1 = 6 6 different ways
*January 18, 2011*

**algebra**

900/3 = 300/yr 300/7500 = .04 Or PRT = I R = I/PT R = 900/(7500 * 3) R = .04 = 4%
*January 18, 2011*

**math/algebra**

y = 1/2 x - 4 what do you need to do ?
*January 18, 2011*

**Math**

SA = 2 pi r^2 + 2 pi r h r = 5, h = 10 SA = 2(3.14)(5^2) + 2(3.14)(5)(10) I'll leave the math to you. express answer in sq m
*January 18, 2011*

**Geometry**

right triangle
*January 18, 2011*

**Geometry**

L = 11 w = 13'10" = 13.83' A = Lw A = 11 * 13.83 A = ? sq ft
*January 18, 2011*

**Geometry**

1) L = 120 - 20 = 100 w = 80 - 20 = 60 A = Lw A = 100 * 60 A = 6000 sq ft 2) 12,500/50 = 250 sq ft/dog 6000/250 = 24 dogs
*January 18, 2011*

**Geometry**

12 x 6 = 72 req, space needed x = total space .15x = 72 x = 480
*January 18, 2011*

**Geometry**

x = 1st angle x + 20 = 2nd angle x + x + 20 = 90 2x = 70 x = 35 35, 55
*January 18, 2011*

**Geometry**

using ratios 4'" = 4.75' 4.75 : 6 = x : 19 4.75/6 = x/19 cross multiply 90.25 = 6x x = 15.04167 x = 15 check my math, it's late for me
*January 17, 2011*

**Algebra 2**

L = length w = L - 3 A = Lw 28 = L * (L - 3) 28 = L^2 - 3L L^2 - 3L - 28 = 0 solve by completing the square if you are right L = -4, L = 7 since length can't be neg., throw out -4, so L = 7 and width = 4
*January 17, 2011*

**Math**

C = pi* d or C = 2* pi r C = pi * 10 C = 10pi
*January 17, 2011*

**Math (Algebra 2)**

answer is 5x^3 - 14x^2/3 - 40x/9 + 256/27 + (230/27)/(3x + 1) this is really something you need to do yourself because I can't show you how, I can only give you the answer
*January 17, 2011*

**Algebra 2**

x = heather now 5x = george now 5x + 4 = 3(x + 4) 5x + 4 = 3x + 12 2x = 8 x = 4 heather - 4 george - 20
*January 17, 2011*

**5th math**

I don't think anyone understands what the 'sample space' is, at least that is why I haven't answered. It seems like 5th grade math is harder than calculus!!
*January 17, 2011*

**RATIOS MATH**

x : 6 = 20 : 24 x/6 = 20/24 cross multiply 24x = 120 x = 5
*January 17, 2011*

**MaTh = Algebra = help**

How did you get -2 as an answer? Did you divide 5x by 5 and 10 by five to get 2? YES You lost me right here: How did you do this? x - 2y = 10 -2 - 2y = 10 -2y = 12 y = -6 How did you get the second line? -2 - 2y = 10? to find the value of y, since you know x = -2, you plug x...
*January 17, 2011*

**MaTh = Algebra = help**

x - 2y = 10 3x - y = 0 eliminate y by multiplying 3x - y = 0 by -2 -2(3x - y = 0) = -6x + 2y = 0 ADD the 2 equations x - 2y = 10 -6x + 2y = 0 -5x + 0 = 10 -5x = 10 x = -2 substitute x = -2 in x - 2y = 10, to find y x - 2y = 10 -2 - 2y = 10 -2y = 12 y = -6 check x = -2, y = -6 ...
*January 17, 2011*

**Math**

A = Lw w = width 2w = length 200 = w(2w) 200 = 2w^2 100 = w^2 10 = w P = 2L + 2w w = 10 L = 2w = 20 P = 2(10) + 2(20) P = ?
*January 17, 2011*

**Math**

TA = 6e^2 TA = 6(2^2) TA = 6 (4) TA = 24 m^2
*January 17, 2011*

**Math**

V = 4/3 pi r^3 V = 4/3 pi (5^3) V = ?
*January 17, 2011*

**Math**

A = 4 pi r^2 A = 4 pi (5^2) A = ?
*January 17, 2011*

**Math**

see first link below under related questions your post was answered already below please do not repost without checking to see if your original post was answered
*January 17, 2011*

**Math grade7**

ADD up purchases and earnings -12.00 + 15.00 - 7.00 - 8.50 + 8.00 + 2.00 = - 2.50 x = money she started with x + -2.50 = 22.25 x = 22.25 + 2.50 x = 24.75
*January 17, 2011*

**Math**

I cos (2x/3) dx = 3/2 sin (2x/3) sorry, forgot 0 to pi/2 3/2 sin 2/3 (pi/2) - 3/2 sin 0 3/2 sin (2pi/6) - 0 3/2 sin (pi/3) 3/2 (sqrt3/2) 3 sqrt3/4
*January 17, 2011*

**Math**

Integrate cos (2x/3) dx u = 2x/3 du = 2/3 dx 3/2 du = dx I = integrate symbol I cos (2x/3) dx = I cos u 3/2 du I cos (2x/3) dx = 3/2 I cos u du I cos (2x/3) dx = 3/2 sins u since, u = 2x/3 I cos (2x/3) dx = 3/2 sin (2x/3)
*January 17, 2011*

**Calculus**

7x + 42 = 7(x + 6)
*January 17, 2011*

**math(algebra 1)**

y = -x + 3 y = x + 1 rewrite y + x = 3 y - x = 1 to eliminate the variable x, add the 2 equations together. Since x + -x = 0, the x variable is eliminated ADD y + x = 3 y - x = 1 2y = 4 y = 2 to find x, substitute y = 2 in y + x = 3 2 + x = 3 x = 1 CHECK x = 1, y = 2 y - x = 1...
*January 17, 2011*

**math**

x = kim's points x + 5 = lynn's points 3(x + 5) = camilla's points x + x + 5 + 3(x + 5) = 50 x + x + 5 + 3x + 15 = 50 5x + 20 = 50 5x = 30 x = 6 kim has 6 pts lynn has 11 pts camilla has 33 pts
*January 17, 2011*

**Math**

4 log x - 2 log y + 1/3 log w (4 log x + 1/3 log w) - 2 log y (log x^4 + log w^1/3) - log y^2 log (x^4 w^1/3) - log y^2 log (x^4 w^1/3)/y^2 I am not a tutor
*January 17, 2011*

**geometry**

A 45-45-90 deg triangle is one-half a square. The length of a leg opposite a 45 deg angle equals one-half the length of the hypotenuse times the square root of 2. to find one of the sides of the square, c = a * sqrt2 (the diagonal) 8(sqrt2) = a * sqrt2 a = 8 P = 4s P = 4 * 8 P...
*January 17, 2011*

**Math**

integrate (x+1)sqrt(2-x)dx u = (sqrt(2 - x)) u^2 = 2 - x x = 2 - u^2 - 2u du = dx I = integral sign I (2 - u^2 + 1)u -2u du I (3 - u^2)-2u^2 du I (-6u^2 + 2u^4) du -6 I u^2 du + 2 I u^4 du 2 I u^4 du - 6 I u^2 du 2 (1/5 u^5) - 6 (1/3 u^3) 2/5 u^5 - 2u^3 substitute back in for ...
*January 17, 2011*

**Math**

see your post above answered already
*January 17, 2011*

**math**

see solution above, I figured that the second '=' sign was supposed to be '+'
*January 17, 2011*

**math**

-3(4b-10) = .5(-24b+60) -12b + 30 = -12b + 30 all values of b are solutions
*January 17, 2011*

** math**

3 (g-3) = 6 3g - 9 = 6 3g = 15 g = 5
*January 17, 2011*

**Math**

The measure of an interior angle is one half of the measure of the intercepted arc.
*January 17, 2011*

**math**

A parallelogram is a four sided figure with its opposite sides parallel to each other. A rectangle is a parallelogram whose four angles are all 90' so draw a parallelogram such that the sides, (width), are parallel to each other but NOT perpendicular to the base (so the 90...
*January 17, 2011*

**math**

see first link below under related questions REINY already answered part of this if you are having trouble, post your work and someone will help if you are stuck tutors do not do your homework for you
*January 17, 2011*

**geometry**

use the Pythagorean theorem 25^2 = b^2 + x^2 now solve for b
*January 17, 2011*

**math**

1 7/5 1 = 5/5 5/5 + 7/5 = 12/5 is this what you need? or 1 7/5 = 12/5 = 2 2/5 because 12 divided by 5 = 2 2/5
*January 17, 2011*

**math**

you're welcome :)
*January 17, 2011*

**math**

25 < n - 12 37 < n n > 37
*January 17, 2011*

**algebra**

p = pennies 2p - 9 = nickles 3p - 19 = dimes p + 2p - 9 + 3p - 19 = 140 6p - 28 = 140 6p = 168 p = 28 p = pennies = 28 2p - 9 = nickles = 47 3p - 19 = 65
*January 17, 2011*

**Algebra 2 **

g(f(x))= 2(x^2 + 1)^2 = 2 (x^4 + 2x^2 + 1) = 2x^4 + 4x^2 + 2
*January 17, 2011*

**Math**

A = x^2 - 10x + 25 = (x - 5)(x - 5) A = Lw L = (x - 5), w = (x - 5) P = 2w + 2L P = 2(x - 5) + 2(x - 5) P = 2x - 10 + 2x - 10 P = 4x - 20
*January 17, 2011*