Thursday

February 11, 2016
Total # Posts: 1,755

**algebra**

8/26 = m/13 cross multiply means denominator of 1st * numerator of 2nd numerator of 1st * denominator of 2nd 26M = 104 M = 4
*January 19, 2011*

**algebra**

11T/28-T / 4 = 1 rewrite problem 11T/28 - T * 1/4 = 1 11T/(4(28 - t)) = 1 11T/(112 - 4T) = 1 11T = 112 - 4T 15T = 112 T = 7.47
*January 19, 2011*

**advance algebra**

X=smaller number y= bigger number y - x = 192 9x = bigger number 9x - x = 192 8x = 192 x = 24 smaller number bigger number = 9x = 9(24) = 216
*January 19, 2011*

**calculus**

A = Lw 25 = Lw w = 25/L P = 2w + 2L P = 2(25/L) + 2L P = 50/L + 2L
*January 19, 2011*

**Algebra 1**

5x + y = 5x + (3x âˆ’ 11) = 13. where are you getting these problems? there is no way to solve the way you have written this. copy the problem exactly from your book
*January 19, 2011*

**Algebra 1**

no way to solve this
*January 19, 2011*

**math**

cannot solve either as separate equations
*January 18, 2011*

**math**

see your other post
*January 18, 2011*

**ALGEBRA**

4 + x(10 - 8) 4 + 10x - 8x 4 + 2x 2x = -4 x = -2
*January 18, 2011*

**Algebra 1**

5y + 4x = -41 what are you solving for? copy the complete problem from your book there isn't anything to solve for above, unless 5y + 4x = -41 5y = -41 - 4x y = (-41 - 4x)/5 4x = -41 - 5y x = (-41 - 5y)/4 is this what you want there is nothing else to solve for
*January 18, 2011*

**algebra**

don't understand what you need done repost
*January 18, 2011*

**MATH**

881/5 = 176 1/5
*January 18, 2011*

**Algebra 1**

5y + 4x = -41 what are you solving for?
*January 18, 2011*

**Algebra 1**

incomplete problem try again :)
*January 18, 2011*

**Geometry**

a + b + c = 1400 a + b + 600 = 1400 a + b = 800 using Pythagorean theorem a^2 + b^2 = 600^2 a + b = 800 a^2 + b^2 = 600^2 solve simultaneously I got a = 258.579 b = 541.421 or a = 541.421 b = 258.579
*January 18, 2011*

**math(algebra 1)**

2) you are correct x - y = 4 add + y to both sides x - y + y = 4 + y x = 4 + y
*January 18, 2011*

**math(algebra 1)**

1)3x + y = 0, x - y = 4 Pick and equation, and solve for either x or y x - y = 4 x = 4 + y Substitute, x = 4 + y, for x, in the other equation and solve for y x = 4 + y 3x + y = 0 3(4 + y) + y = 0 12 + 3y + y = 0 12 + 4y = 0 4y = -12 y = -3 substitute y = -3 in either equation...
*January 18, 2011*

**Math**

43 heads = 43 animals ( I hope!!) C = number of chickens G = number of goats C + G = 43 2C + 4G = 108 solve simultaneously to find C and G if you are right, C = 32 G = 11
*January 18, 2011*

**algebra**

set up ratio 3/2.5 = x/8 2.5x = 24 x = 9.6 $9.60 for 8
*January 18, 2011*

**5th math**

4 feet = 4 x 12 in/ft = 48 inches from above, this should say write down the most times a factor was used within one factorization
*January 18, 2011*

**5th math**

mean is the average add all the numbers to get the sum divide the sum by the number of numbers you are adding. 33 + 41 + 37 + 27 + 32 = 170 since there are 5 numbers, you divide the sum by 5, to get the mean 170/5 = 34 the mean is 34 LCM 6, 4, 8 LCM is 24 how I was taught ...
*January 18, 2011*

**math**

b. 8th:7th = 2:3
*January 18, 2011*

**Math**

A = 4pir^2 TA = 4(3.14)(5^2) TA = 4(3.14)(25) TA = ?
*January 18, 2011*

**math**

y^2-3y=9 y^2 - 3y = 9 complete the square y^2 - 3y + 9/4 = 9 + 9/4 (y - 3/2)^2 = 45/4 +- (y - 3/2) = 45/4 solve for y y = 3/2 (sqrt5 + 1) y = -3/2 (-1 + sqrt5)
*January 18, 2011*

**algebra 2 and trigonometry**

y^2-3y=9 y^2 - 3y = 9 complete the square y^2 - 3y + 9/4 = 9 + 9/4 (y - 3/2)^2 = 45/4 +- (y - 3/2) = 45/4 solve for y y = 3/2 (sqrt5 + 1) y = -3/2 (-1 + sqrt5)
*January 18, 2011*

**math**

6th - 125 7th - 150 8th- 100 a) ratio 6th:7th 125:150 = 5:6 b) 8th:7th 100:150 = 4:6 = 2:3 c) 6th: total = 125:375 = 5:15 = 1:3 d) 8th:total = 100:375 = 4:15 check your b. ratio 2:3, not 3:2
*January 18, 2011*

**math**

ratio to what? 125 : 150 : 100 5 : 6 : 4
*January 18, 2011*

**Pre-Algebra**

vinegar - pH 3 baking soda - pH 9 9 - 3 = 6 units diff. 10 x 6 = 60x as acidic 10^6 = 1 million, so I can't see how that is right 10^1.77815 = 60 or, 6 x 10^1 = 60 is this a pre-algebra question or science?
*January 18, 2011*

**trig**

restate your question. I don't understand. is this a right triangle? "i have one degree 25" What does this mean? side b = 2.489 * 10^9 ? or 2,489,000,000? post question exactly as written from your book.
*January 18, 2011*

**Pre-Algebra**

:) that's ok. also, you will have better response if posted separate.
*January 18, 2011*

**Pre-Algebra**

vinegar - pH 3 baking soda - pH 9 9 - 3 = 6 units diff. 10 x 6 = 60x as acidic 10^6 = 1 million, so I can't see how that is right 10^1.77815 = 60 I am not a tutor, so you might want to repost this as a separate question
*January 18, 2011*

**Pre-Algebra**

if this is what you mean 1) a^8/a^8 = 1 2) -x^5/-x^4 = x 3) 15/5 * n^9/n = 3n^8 Also, use separate posts for 2 different questions/subjects
*January 18, 2011*

**math**

not enough info to find d and c post the whole problem
*January 18, 2011*

**math 1 digit divisors word problem**

you're welcome :)
*January 18, 2011*

**math 1 digit divisors word problem**

To have a remainder of 8, the divisor must be greater than 8. The only single digit greater than 8 is 9, so 9 must be the divisor. Since 8 is 1 less than 9, the dividend needs to be one less than a multiple of 9. Candidates are values of 3 digits, as the problem states. The ...
*January 18, 2011*

**Emploument English**

true, you are correct
*January 18, 2011*

**Math**

7 1/4 = 29/4 = 58/8 3 3/8 = 27/8 58/8 - 27/8 = 31/8 = 3 7/8
*January 18, 2011*

**math**

see your 1st post
*January 18, 2011*

**math**

7560 = 756. x 10^1 but like Esskay said above, scientific notation would not be used for 7560
*January 18, 2011*

**Sex Ed(English)**

A. 12 weeks
*January 18, 2011*

**math**

x/y - z = rw solve for x x - yz = yrw x = yrw + yz x = y(rw + z) A
*January 18, 2011*

**algebra**

-7 = -1/6x -42 = -x x = 42
*January 18, 2011*

**Sex Ed(English)**

thanks Writeacher, I was not clear :)
*January 18, 2011*

**Sex Ed(English)**

true
*January 18, 2011*

**math**

1/20 of 1.00 = .05 so, 1 nickle or 5 pennies
*January 18, 2011*

**Sex Ed(English)**

VERY correct
*January 18, 2011*

**geometry**

14q + 8 + 8q - 6 = 90 22q + 2 = 90 22q = 88 q = 4 14q + 8 = 64 8q - 6 = 26 64 + 26 = 90
*January 18, 2011*

**Sex Ed(English)**

true
*January 18, 2011*

**math**

5 : x = 25 : 30 5/x = 25/30 cross multiply 150 = 25x x = 6
*January 18, 2011*

**math**

60 x .80 = 48 spent 60 - 48 = 12 left to invest 12 x .80 = 9.60 $9.60
*January 18, 2011*

**Math**

see your 1st post
*January 18, 2011*

**math**

6x - 4y - 3x + y 3x - 3y
*January 18, 2011*

**math**

600 x .06 x 5 = ?
*January 18, 2011*

**MATHAROOO**

think of the midpoint of a line as being the half-point of a line there can only be one point that divides this line into 2 equal parts A--------MP--------B A--------C--------B C is the midpoint of line AB now, you could find the midpoint of segment AC A----MP----C--------B A...
*January 18, 2011*

**Math/Radical Expressions**

If this is your equation g/t + g - g/t - g = 0
*January 18, 2011*

**MATH**

6/330 =0.018182
*January 18, 2011*

**Math**

5x = 4y - 30 2x + 3y +-12 (1) 5x - 4y = -30 (2) 2x + 3y = 12 multiply (1) by 3(5x - 4y = -30) (1) 15x + 12y = -90 multiply (2) by 4(2x + 3y = 12) (2) 8x + 12y = 48 ADD two new equations (1) 15x + 12y = -90 (2) 8x + 12y = 48 23x + 0 = -42 23x = -42 x = -42/23 substitute x = -42...
*January 18, 2011*

**math**

correction-this should be net salary * 12 mo. = annual net salary
*January 18, 2011*

**math**

you have a typo in $2,3500.00 Monthly wage - 468 = net salary net salary * 52 weeks = annual net salary
*January 18, 2011*

**math**

1 1/12 = 13/12 2 = 24/12 24/12 - 13/12 = 11/12 left
*January 18, 2011*

**math**

165/3 = ?
*January 18, 2011*

**algebra**

3x - 5y = 61 3x - y = 17 multiply 1st by -1(3x - 5y = 61) -3x + 5y = -61 3x - y = 17 ADD two equations 0 + 4y = - 44 4y = -44 y = -11 substitute y = -11 in 3x - y = 17 to find x 3x - y = 17 3x + 11 = 17 3x = 6 x = 2 check x = 2, y = -11 in one of the equations I'll leave ...
*January 18, 2011*

**Math**

r = 5, h = 10 SA = 2 pi r^2 + 2 pi r h SA = 2(pi)(5^2) + 2(pi)(5)(10) SA = 2(pi)(25) + 2(pi)(5)(10) SA = 50pi + 100pi SA = 150 pi m^2 do you have the formula for a right circular cylinder? I've checked my math and I get 150pi m^2 if you can post the formula from your book ...
*January 18, 2011*

**Math**

r = 5, h = 10 SA = 2 pi r^2 + 2 pi r h SA = 2(3.14)(5^2) + 2(3.14)(5)(10) SA = 2(3.14)(25) + 2(3.14)(5)(10) SA = 50(3.14) + 100(3.14) SA = 157 + 314 = 471 m^2
*January 18, 2011*

**algreba**

n = number of trees 84n <= 2400 n <= 28.57
*January 18, 2011*

**math**

this is an easy one to graph. just pick some values for x or y and solve for the other value what are you having trouble doing? we can't graph it for you. for y = x + 1 x = 0, y = 1 (0,1) x = 1, y = 2 (1,2) x = 2, y = 3 (2,3) x = 3, y = 4 (3.4) x = 4, y = 5 (4,5) for y = ...
*January 18, 2011*

**Calculus**

forgot to add, there are other forms for this answer post your answer if you are not sure if equil. to above posted answers
*January 18, 2011*

**Calculus**

Answer 1/3 (sqrt(x^2 + 100))^3 - 100(sqrt(x^2+100)) + C this can be transformed into 1/3 (x^2 - 200)(sqrt(x^2 + 100) + C my book had 1st answer (not transformed) let me know if you need more help with this
*January 18, 2011*

**math**

A = Lw A = 9 * 3 A = 27 sq ft/units 27 * 12 = ?
*January 18, 2011*

**math**

I used an online calculator for this Mean = 59.64 Median = 58 Sample standard deviation = 10.19
*January 18, 2011*

**math**

this is a permutations 3 cds / 3 cases = 3! = 3 x 2 x 1 = 6 6 different ways
*January 18, 2011*

**algebra**

900/3 = 300/yr 300/7500 = .04 Or PRT = I R = I/PT R = 900/(7500 * 3) R = .04 = 4%
*January 18, 2011*

**math/algebra**

y = 1/2 x - 4 what do you need to do ?
*January 18, 2011*

**Math**

SA = 2 pi r^2 + 2 pi r h r = 5, h = 10 SA = 2(3.14)(5^2) + 2(3.14)(5)(10) I'll leave the math to you. express answer in sq m
*January 18, 2011*

**Geometry**

right triangle
*January 18, 2011*

**Geometry**

L = 11 w = 13'10" = 13.83' A = Lw A = 11 * 13.83 A = ? sq ft
*January 18, 2011*

**Geometry**

1) L = 120 - 20 = 100 w = 80 - 20 = 60 A = Lw A = 100 * 60 A = 6000 sq ft 2) 12,500/50 = 250 sq ft/dog 6000/250 = 24 dogs
*January 18, 2011*

**Geometry**

12 x 6 = 72 req, space needed x = total space .15x = 72 x = 480
*January 18, 2011*

**Geometry**

x = 1st angle x + 20 = 2nd angle x + x + 20 = 90 2x = 70 x = 35 35, 55
*January 18, 2011*

**Geometry**

using ratios 4'" = 4.75' 4.75 : 6 = x : 19 4.75/6 = x/19 cross multiply 90.25 = 6x x = 15.04167 x = 15 check my math, it's late for me
*January 17, 2011*

**Algebra 2**

L = length w = L - 3 A = Lw 28 = L * (L - 3) 28 = L^2 - 3L L^2 - 3L - 28 = 0 solve by completing the square if you are right L = -4, L = 7 since length can't be neg., throw out -4, so L = 7 and width = 4
*January 17, 2011*

**Math**

C = pi* d or C = 2* pi r C = pi * 10 C = 10pi
*January 17, 2011*

**Math (Algebra 2)**

answer is 5x^3 - 14x^2/3 - 40x/9 + 256/27 + (230/27)/(3x + 1) this is really something you need to do yourself because I can't show you how, I can only give you the answer
*January 17, 2011*

**Algebra 2**

x = heather now 5x = george now 5x + 4 = 3(x + 4) 5x + 4 = 3x + 12 2x = 8 x = 4 heather - 4 george - 20
*January 17, 2011*

**5th math**

I don't think anyone understands what the 'sample space' is, at least that is why I haven't answered. It seems like 5th grade math is harder than calculus!!
*January 17, 2011*

**RATIOS MATH**

x : 6 = 20 : 24 x/6 = 20/24 cross multiply 24x = 120 x = 5
*January 17, 2011*

**MaTh = Algebra = help**

How did you get -2 as an answer? Did you divide 5x by 5 and 10 by five to get 2? YES You lost me right here: How did you do this? x - 2y = 10 -2 - 2y = 10 -2y = 12 y = -6 How did you get the second line? -2 - 2y = 10? to find the value of y, since you know x = -2, you plug x...
*January 17, 2011*

**MaTh = Algebra = help**

x - 2y = 10 3x - y = 0 eliminate y by multiplying 3x - y = 0 by -2 -2(3x - y = 0) = -6x + 2y = 0 ADD the 2 equations x - 2y = 10 -6x + 2y = 0 -5x + 0 = 10 -5x = 10 x = -2 substitute x = -2 in x - 2y = 10, to find y x - 2y = 10 -2 - 2y = 10 -2y = 12 y = -6 check x = -2, y = -6 ...
*January 17, 2011*

**Math**

A = Lw w = width 2w = length 200 = w(2w) 200 = 2w^2 100 = w^2 10 = w P = 2L + 2w w = 10 L = 2w = 20 P = 2(10) + 2(20) P = ?
*January 17, 2011*

**Math**

TA = 6e^2 TA = 6(2^2) TA = 6 (4) TA = 24 m^2
*January 17, 2011*

**Math**

V = 4/3 pi r^3 V = 4/3 pi (5^3) V = ?
*January 17, 2011*

**Math**

A = 4 pi r^2 A = 4 pi (5^2) A = ?
*January 17, 2011*

**Math**

see first link below under related questions your post was answered already below please do not repost without checking to see if your original post was answered
*January 17, 2011*

**Math grade7**

ADD up purchases and earnings -12.00 + 15.00 - 7.00 - 8.50 + 8.00 + 2.00 = - 2.50 x = money she started with x + -2.50 = 22.25 x = 22.25 + 2.50 x = 24.75
*January 17, 2011*

**Math**

I cos (2x/3) dx = 3/2 sin (2x/3) sorry, forgot 0 to pi/2 3/2 sin 2/3 (pi/2) - 3/2 sin 0 3/2 sin (2pi/6) - 0 3/2 sin (pi/3) 3/2 (sqrt3/2) 3 sqrt3/4
*January 17, 2011*

**Math**

Integrate cos (2x/3) dx u = 2x/3 du = 2/3 dx 3/2 du = dx I = integrate symbol I cos (2x/3) dx = I cos u 3/2 du I cos (2x/3) dx = 3/2 I cos u du I cos (2x/3) dx = 3/2 sins u since, u = 2x/3 I cos (2x/3) dx = 3/2 sin (2x/3)
*January 17, 2011*

**Calculus**

7x + 42 = 7(x + 6)
*January 17, 2011*

**math(algebra 1)**

y = -x + 3 y = x + 1 rewrite y + x = 3 y - x = 1 to eliminate the variable x, add the 2 equations together. Since x + -x = 0, the x variable is eliminated ADD y + x = 3 y - x = 1 2y = 4 y = 2 to find x, substitute y = 2 in y + x = 3 2 + x = 3 x = 1 CHECK x = 1, y = 2 y - x = 1...
*January 17, 2011*

**math**

x = kim's points x + 5 = lynn's points 3(x + 5) = camilla's points x + x + 5 + 3(x + 5) = 50 x + x + 5 + 3x + 15 = 50 5x + 20 = 50 5x = 30 x = 6 kim has 6 pts lynn has 11 pts camilla has 33 pts
*January 17, 2011*

**Math**

4 log x - 2 log y + 1/3 log w (4 log x + 1/3 log w) - 2 log y (log x^4 + log w^1/3) - log y^2 log (x^4 w^1/3) - log y^2 log (x^4 w^1/3)/y^2 I am not a tutor
*January 17, 2011*