Saturday

December 3, 2016
Total # Posts: 1,805

**Math**

Answered in a later post.

*January 23, 2011*

**algebra**

x = liters of 3% solution 3 - x = liters of 10% solution .03x = value 3% solution .10(3 - x) = value 10% solution 3 = liters of 7.9% mixture .079(3) = 0.237 = value 7.9% mixture .03x + .10(3 - x) = 0.237 Solve for x, which is number of liters of 3% solution. (3 - x) = number ...

*January 23, 2011*

**math **

(1/2)^x = 1152 rewrite as, 2^(-x) = 1152 Take the logarithm to the base 2 of both sides: -x log 2 = log 1152 -x = (log(1152))/(log(2)) Divide both sides by -1: x = -(log(1152))/(log(2)) x = - 3.061452/0.3010299 x = -10.1699

*January 23, 2011*

**algebra 2**

See links below under Related Questions. This exact question was answered.

*January 23, 2011*

**geometry**

Triangle has 180 degrees 22.5 + 101 = 123.5 180 - 123.5 = 56.5 A. 56.5 Obtuse triangle: An obtuse triangle is a triangle having an obtuse angle. Obtuse angle: An obtuse angle is an angle whose measure is more than 90 degrees and less than 180 degrees. B. Obtuse triangle

*January 23, 2011*

**ela**

FYI, you might be helped faster if you followed directions and put the name of your school subject in the box instead of whatever 'ela' is. This way, a tutor that is familiar with your subject can answer.

*January 23, 2011*

**algebra**

I don't think this problem is correct or that it can be solved. Either that, or the problem is poorly worded (to me). If they are each saving to buy the same CD's and Juan is only short $3.00, how can it be that when they combine their money they still do not have ...

*January 23, 2011*

**Math**

What do you mean by 'condense'? Is that what your problem directions say?

*January 23, 2011*

**college math 209**

You need to use parentheses in this problem. What are the ? for or mean? Square root of 48 or 48yv^2 or ? Same for the other square root. Please use parentheses and retype your problem here in a reply post.

*January 23, 2011*

**Pre-Calc**

sqrt(x-6)+sqrt(x+10) = 8 sqrt(x-6) = 8 - sqrt(x+10) Square both sides x - 6 = (8 - sqrt(x + 10))^2 Expand out terms on the right hand side x - 6 = x - 16sqrt(x + 10) + 74 16sqrt(x + 10) = 80 Divide both sides by 16 sqrt(x + 10) = 5 Square both sides x + 10 = 25 x = 15

*January 23, 2011*

**Math**

3p^2 + 4p^2 = 63 7 p^2 = 63 Divide both sides by 7: p^2 = 9 Take the square root of both sides: p = -3 or p = 3

*January 23, 2011*

**Math**

See your post above.

*January 23, 2011*

**algebra**

RT = D (rate * time = distance) 4.1 = Emma's rate 3.7 = Mason's rate T = Emma's time T + .08 = Mason's time (48/60 = 0.8h) 4.1T = Emma's distance 3.7(T + 0.8) = Mason's distance Distances are equal to each other 3.7(T + 0.8) = 4.1T 3.7T + 2.96 = 4.1T 0....

*January 23, 2011*

**math**

A = Lw P = 2L + 2w Lw = 25 2L + 2w = 25 Solve these two equations simultaneously for your answer.

*January 23, 2011*

**MATH**

Changed subject

*January 23, 2011*

**MATH**

x^4 - x^2 - 6 (x^2 - 3)(x^2 + 2)

*January 23, 2011*

**Calc**

See the links below under Related Questions. Similar problems have been posted before and some of the info in those posts maybe be helpful.

*January 23, 2011*

**algebra 2**

yes, make one up

*January 22, 2011*

**algebra 2**

Plug a value for x (price of the suit) in each equation and then solve each equation. This way you can see if one results in a lower price. Explain why or why not, one equation results in a lower price.

*January 22, 2011*

**Algebra 1**

3y + 6x + 3 = 9 + 6x Subtract 6x from both sides 3y + 6x - 6x + 3 = 9 + 6x - 6x 3y + 3 = 9 Subtract 3 from both sides 3y + 3 - 3 = 9 - 3 3y = 6 Divide both sides by 3 3y/3 = 6/3 y = 2

*January 22, 2011*

**Algabra**

Time = Distance/Rate x = Javier's rate x + 5 = Kathy's rate 57/x = Javier's time 72/(x+5) = Kathy's time Since their time is equal, 57/x = 72/(x + 5) 72x = 57(x + 5) Solve for x

*January 22, 2011*

**Calculus **

1/(sqrt3)arctan(5/(29(sqrt3))= 0.0572826 Check you values for 1/a and x/a maybe that's where you got hung up | dx/(a^2 + x^2) (3/4 + w^2) a^2 = 3/4 a = (sqrt3)/2 x^2 = w^2 x = w So, you should have got, 1/2(1/(sqrt3/2)arctan (w/(sqrt3/2)) which simplified is, 1/2(2/(sqrt3)...

*January 22, 2011*

**Calculus **

1/2[2/(sqrt3)arctan(2(x^2+1/2)/(sqrt3) I distributed the 1/2, but backed it out for my above answer...I don't think I made any errors backing it out. Here is the answer, with the 1/2 distributed. I know this answer is right because I double check it with an online ...

*January 22, 2011*

**Calculus **

integrate x/(x^4+x^2+1) | = integrate symbol u = x^2 du = 2x dx 1/2 du = x dx 1/2 | du/(u^2 + u + 1) Complete the square u^2 + u = -1 u^2 + u + 1/4 = -1 + 1/4 (u + 1/2)^2 + 3/4 1/2 | du/((u + 1/2)^2 + 3/4) w = u + 1/2 dw = du 1/2 | dw/(w^2 + 3/4) 1/2 | dw/(3/4 + w^2) And, ...

*January 22, 2011*

**beginning algebra**

u^2 - u - 30 = 0 Using the quadratic formula, x =(-b +- (sqrt(b^2 - 4ac))/2a a = 1, b = -1, c = -30 x = 1 +- (sqrt(-1^2 - 4(1)(-30))/2 x = (1 +- (sqrt(1 + 120))/2 x = (1 +- (sqrt(121))/2 x = (1 +- 11)/2 x = (1 + 11)/2 = 6 x = (1 - 11)/2 = -5

*January 22, 2011*

**beginning algebra**

This was answered the first time you posted it. I pasted the answer below. (u - 1)^2 = 2u^2 - 3u - 29 u^2 - 2u + 1 = 2u^2 - 3u - 29 u^2 - u - 30 = 0 This does not factor. Solve by using the quadratic formula or the method of completing the square. Post your answer and someone ...

*January 22, 2011*

**College Algebra**

You're welcome and good luck :).

*January 22, 2011*

**College Algebra**

I'll try, but the formatting here doesn't allow for easy alignment of columns. xxxxxxxxxxxxx-3x^2 - 9x - 9 -2x^2+3x-3 |6x^4 + 9x^3 + 0x^2 + 0x +9 ------------6x^4 - 9x^3 + 9x^2 subtraction-------18x^3 - 9x^2 ------------------18x^3 - 27x^2 + 27x subtraction...

*January 22, 2011*

**College Algebra**

First rearrange and simplify the numerator to: 6x^4 + 9x^3 + 9 Just divide as your would with any long division problem. If you post your answer I can tell you if you are correct. Is there something in particular you do not understand?

*January 22, 2011*

**Calculus**

You are correct!! Good job :)

*January 22, 2011*

**Math Need an explanation**

thanks REINY. After seeing your post, the problem, as I typed without parentheses, is apparent. I don't know why I didn't see that! Parentheses are nice though.

*January 22, 2011*

**Math Need an explanation**

You need to use parentheses in your problem 5^2/3x25^2/3=25 I have no idea what this means? Is this your problem? 5^2/3 x 25^2/3 = 25 This does not equal 25.

*January 22, 2011*

**MATH EMERGENCY**

In this form Ax + By + C = 0 Slope m = -A/B y-intercept b = -C/B You are looking for, a negative slope Slope m = -A/B And, a positive y-intercept C/B So, Ax + By - C = 0 Can you answer now?

*January 22, 2011*

**Precalculus Someone help please**

((3^-3 * 3^5)/3^-2)^-1/2 ((1/3^3 * 243)/(1/3^2))^-1/2 ((1/27 * 243)/(1/9))^-1/2 ((243/27)/(1/9))^-1/2 (9/(1/9))^-1/2 81^-1/2 1/(sqrt81) = 1/9

*January 22, 2011*

**Algebra**

x = 1st angle 2x = 2nd angle x + 2x = 180 Solve for x

*January 22, 2011*

**Math**

[(-1/2)^-2]^3 (1/(-1/2)^2)^3 = 1/(1/4)^3 = 1/(1/64)=64

*January 22, 2011*

**Math**

8^(-4/3)= (cube rt 8)^-4 8^(-4/3)= 2^-4 = 1/(2^4) = 1/16 Do you understand?

*January 22, 2011*

**COLLEGE ALGEBRA**

(2r + 8)/4 = (3r - 6)/3 Yes, you are correct, r = 8.

*January 22, 2011*

**COLLEGE ALGEBRA**

Not correct Post your work and someone can explain what you are doing wrong. First simplify 8/4 and 6/3 and then combine like terms.

*January 22, 2011*

**Algebra**

Please see your 1st post for response.

*January 22, 2011*

**Algebra**

C = 6000/(200 - 2x) C = 6000/(200 - 2(75)) C = 6000/(200 - 150) C = 6000/50 C = 120 mil 120,000,000 million or, is it C = 6000/(200 - 2(.75)) C = 6000/(200 - 1.5) C = 6000/198.5 C = 30.2267 mil 30,226,700 million I think it's the first, but I am not a tutor

*January 22, 2011*

**Algebra**

Re-check your problem. I think you are missing a part here. pollution in a lake modeled by ?

*January 22, 2011*

**algebra**

I don't think this problem is correct or that it can be solved. Either that, or the problem is poorly worded (to me). If they are each saving to buy the same CD's and Juan is only short $3.00, how can it be that when they combine their money they still do not have ...

*January 22, 2011*

**Math**

FIFO-first in, first out 300 @ 11.00 150 @ 10.50 200 @ 10.75 175 @ 10.00 100 @ 12.00 Beginning Inventory Total = 925 Ending Total = 300 Difference = sold = 625 FIFO-first in, first out Items sold are assumed to be subtracted from the first ones purchased. Go down from the top ...

*January 22, 2011*

**algebra**

x = lbs of cheaper coffee 10x = value of cheaper coffee 4 = lbs of better coffee 4 * 20 = 80 = value of better coffee 20 + x = lbs of mixture 5(20 + x) = value of mixture 10x + 80 = 5(20 + x) Solve for x

*January 22, 2011*

**Math**

Simplify 7sqrt(3/6) Breakdown the radicals 7 (sqrt3)/(sqrt6) 7 (sqrt3)/(sqrt3)(sqrt2) 7/(sqrt2) Rationalize the denominator 7/(sqrt2)*(sqrt2)/(sqrt2) 7/2 (sqrt2) or 7(sqrt2)/2

*January 22, 2011*

**chemistry**

Have you attempted to do any of the problems you have posted? Post your work and explain where you are stuck and someone will help you. Tutors do not do your homework for you.

*January 22, 2011*

**Algebra**

f(x)=8x2+4*4x you need to use parentheses do you mean? 8x^2 + 4*4x or? f(x)=(8x^2 + 4)*4x

*January 22, 2011*

**College Algebra**

What in particular do you need help with? Use long division as you would with any other long division problem. If you post your answer I can check it for you.

*January 22, 2011*

**beginning algebra**

(u - 1)^2 = 2u^2 - 3u - 29 u^2 - 2u + 1 = 2u^2 - 3u - 29 u^2 - u - 30 = 0 This does not factor. Solve by using the quadratic formula or the method of completing the square. Post your answer and someone will check it for you.

*January 22, 2011*

**beginning algebra**

15v^4w^8 and 9vw^5x^4 You need to find the least common factors that these two expressions have in common. LCM = 3vw^5

*January 22, 2011*

**beginning algebra**

2 + 7/y = 3/5 Get rid of the denominators Multiply both sides by y 2y + 7 = 3/5 y Multiply both sides by 5 10y + 35 = 3y Subtract 10y from both sides 35 = -7y Divide both sides by -7 -5 = y y = -5

*January 22, 2011*

**Algebra 1B**

incomplete problem. are you sure you are not missing part of the problem? your problem cannot be solved as stated.

*January 22, 2011*

**computers**

see the first two links below under related questions. this exact question was posted and answered below. also, you might want to look at some of the links supplied within these posts.

*January 22, 2011*

**algebra**

reread your post, not enough info is given and it doesn't make sense. copy the problem exactly from your book.

*January 21, 2011*

**algebra1**

yes, that is correct

*January 21, 2011*

**xacc280**

post the subject in the 'school subject' box' along with your specific question. What is "week 2, day 7 assignment"?

*January 21, 2011*

**phy**

see 1st link below under related questions. a very similar question was answered.

*January 21, 2011*

**Geometry**

sorry, I didn't know that. you should have said that in your 1st post above. the tutors would see that this question was answered and refer you to the original answer.

*January 21, 2011*

**Geometry**

This was answered by DrRuss on 1/21 at 6:39 am. I can't link so I pasted his answer below. I would start with a drawing as I do for most problems. Draw a reactangle 4x one side and b the other. The perimeter is then 4x+b+4x+b=11 8x+2b=11 if this is folded to a tube then ...

*January 21, 2011*

**biology**

see 1st link below under related questions. this exact question was posted recently. a link is provided with info that you might find useful.

*January 21, 2011*

**geometry**

and? please recheck your problem. not enough info.

*January 21, 2011*

**Physics**

see link 1 below under related questions. a very similar problem was answered.

*January 21, 2011*

**algerbra**

not enough info, please re-check your problem.

*January 21, 2011*

**ALGEBRA**

see your first post below, I solved it for you and explained

*January 21, 2011*

**maths**

P = a + b + c add the three sides P = 8x - 7w + 3x + 9y + 3y + 5w combine like terms

*January 21, 2011*

**math**

by the cofunction property cos B = sin A so, if angle B = 33 angle A = ?

*January 21, 2011*

**precalc**

Sine is an odd function, sin(-Î¸)= -sin Î¸

*January 21, 2011*

**precalculus**

2 rads to converts radian to degrees, multiply by 180/pi 2 * 180/pi = (2 * 180)/3.14 = ?

*January 21, 2011*

**algebra**

3x + 9y = 18 y = mx + b solve for y, 9y = -3x + 18 y = -3x/9 + 18/9 simplify the equation

*January 21, 2011*

**Math**

A = pi r^2 pi = 3.14 r = 5 A = (3.14)*(5^2) A = (3.14)*(25) A = ? m^2 do the multiplication for your answer I don't know what this sentence means. Is this the same as the surface area and it would be 10m?

*January 21, 2011*

**ALGEBRA**

I followed that 3 + x(12*4) = 24 multiply 12*4 3 + 48x = 24 subtract 3 from both sides 3 - 3 + 48x = 24 - 3 48x = 21 divide both sides by 48 48x/48 = 21/48 x = 21/48 reduce fraction x = 7/16

*January 21, 2011*

**ALGEBRA**

what is 'pemdas'?

*January 21, 2011*

**ALGEBRA**

3 + x(12*4) - 24 if that is the problem then, 3 + 48x - 24 48x - 21 48x = 21 x = 21/48 x = 7/16 you can only combine 'like terms' x terms can only be added to other x terms, constant terms can only be added to other constant terms. do you understand?

*January 21, 2011*

**ALGEBRA**

I need to see the original problem first to help you. why did you add 48x + 3 to equal 51x? then the 'x' is gone in the next line?

*January 21, 2011*

** Statistics**

see 1st link below under 'Related Questions' for this exact problem

*January 21, 2011*

**Taxes**

No. Each partner includes his or her share of the partnership's income or loss on his or her personal tax return.

*January 21, 2011*

**5th grade**

17,13,27,33,25 put the numbers in order, from smallest to largest 13, 17, 25, 27, 33 the median is the number in the middle so, the median would be 25 for the mean, add all the numbers and then divide the sum by the number of numbers that you added. 13 + 17 + 25 + 27 + 33 = ? ...

*January 20, 2011*

**Algebra -- Help**

Train A has a lead of 12 min. RT = D T = time train B T + .20 = time train A 90T = distance train B 80(T + .20) = distance train A 80(T + .20) = 90T 80T + 16 = 90T 16 = 10T T = 1.6 hours train B overtake train A = 1.6 hours

*January 20, 2011*

**geomitry**

x = 1st angle 90 - x = 2nd angle 5x - 16 = 3rd angle x + 90 - x + 5x - 16 = 180 solve for x

*January 20, 2011*

**math**

what is the figure? square, cube, sphere, etc?

*January 20, 2011*

**algebra**

-6m + 3/11 = 77/11 to solve subtract 3/11 from both sides then divide both sides by -6

*January 20, 2011*

**Pre-algebra**

A = 1/2 bh multiply both sides by 2 2A = bh to find h, divide both sides by b can you finish this?

*January 20, 2011*

**math**

sketch a right triangle A = 55 degrees c = 50 a = unknown (kite height) sin 55 deg = a/c = a/50 = 0.8192 solve for a

*January 20, 2011*

**help math ahhhh**

9. 5x + 4y = 1 3x ? 4y = 7 what does ? mean ?

*January 20, 2011*

**mathematics**

simplify 2/(x^(-3/2))= 2x^(3/2)

*January 20, 2011*

**AiMS MATH**

Natural numbers are the counting numbers, 1, 2, 3, etc Integers are the counting numbers, together with their opposites and zero. whole numbers are the counting numbers without the zero. Rational numbers are the set of all numbers that can be written as quotients, ie, 1/2. ...

*January 20, 2011*

**math**

yes, correct good job! :)

*January 20, 2011*

**math**

5 * (thirdrt 48) - (thirdrt 750) breakdown the radicals 5 * (3rt 8)(3rt 6) - (3rt 125)(3rt 6) can you do this now?

*January 20, 2011*

**math i need help please**

B. what are you having trouble with? did you find r (common ratio)? post what you found for r and the first term so I can understand what part of this you don't understand.

*January 20, 2011*

**MATH I NEED HELP PLEASE! **

Reposting a problem in all caps is rude. it's like you are shouting.

*January 20, 2011*

**Analytical Geometry**

(sin^2 x)/(sec^2 x - 1) (sin^2 x)/(tan^2 x) (sin^2 x)/(sin^2 x/cos^2 x) (sin^2 x) * (cos^2 x/sin^2 x) cos^2 x therefore, (sin^2 x)/(sec^2 x - 1) = cos^2 x

*January 20, 2011*

**geometry **

is this a triangle? is this a right triangle? need more specific info to solve

*January 20, 2011*

**MATH HELP ME NOW PLEASE!!**

see your above latest post

*January 20, 2011*

**algebra **

w = width 4w + 6 = length P = 2w + 2L 42 = 2w + 2(4w + 6) Solve for w

*January 20, 2011*

**algebra **

y = 2x + 5 y = 3x substitute, y = 3x in y = 2x + 5 y = 2x + 5 3x = 2x + 5 solve for x, use x value to find y What do the "?" mean? I see them in most of your posted problems. In this case, the "?" in this problem are part of the answer, so it didn't ...

*January 20, 2011*

**arithmetic**

Add 17 + 5 = 22 therefore, 17/18 + 5/18 = 22/18

*January 20, 2011*

**math **

G = Glen's present age B = Ben's present age B = 4/7 G G + 15 + B + 15 = 63 substitute, B = 4/7 G G + 15 + 4/7 G + 15 = 63 Solve for G

*January 20, 2011*

**Trig**

cos^2 x = 1 take square root of both sides +- cos x = 1 cos x = 1 cos x = -1 for what angle value is cos = 1 and cos = -1 ?

*January 20, 2011*

**physics**

should have added above, 1 mi = 5280 feet 1 mi = 1609.344 meters 1 mi/min = 60 mi/hr 1 mi/min = 88 ft/sec 1 mi/min = 26.8224 meters/sec sorry for the confusion. I wish there was a 'do over' button. :)

*January 20, 2011*