Monday

April 21, 2014

April 21, 2014

Total # Posts: 1,699

**alg. 2**

2.25 + .15x = 1.50 + .18x solve for x

**math **

incomplete problem

**Junior Math**

(t^2-1)/(t^2+7t+10) - (2t+4)/(t^2-t-6) factor the denominators first (t^2-1)/(t+2)t+5) - (2t+4)/(t-3)(t+2) LCD is (t+2)(t+5)(t-3) Now, can you combine over the LCD?

**ALGEBRA**

x + 2y - 4 = 0 x + 2y = 4 to find x-intercept, y = 0 x + 2(0) = 4 x = 4 x-intercept = (4.0) slope intercept form (which you got right above) y = mx + b for Line A is y = -1/2 x + 2 slope m = -1/2 If two lines are perpendicular, the slope of one is the negative reciprocal of th...

**math **

5/4 x + 1/8 = 5/8 + x 5/4 x = 4/8 + x multiply both sides by 8, (LCD of 4 and 8) then solve for x

**math **

you need to use parentheses 5/4x1 divided by 8x = 5/8 + x ? what is "4x1"?

**Algebra 1**

you're very welcome :)

**Algebra 1**

f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ? 5^2 = 5 x 5 = 25 f(5) = 5^2 + 3 f(5) = 25 + 3 f(5) = 28

**Algebra 1**

No, f(5) does not = 10 f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ? 5^2 = ? 5^2 + 3 = ? show me how you got 10

**Algebra 1**

f(x) = x^2 + 3 f(2) = 2^2 + 3 f(2) = ? 2^2 = 4 f(2) = 2^2 + 3 f(2) = 4 + 3 f(2) = 7 the answer for f(2) is 7 when x = 2, the function value = 7 now, you do the other one

**Algebra 1**

just plug in the values for x and solve f(x) = x^2 + 3 f(2) = 2^2 + 3 f(2) = ? f(x) = x^2 + 3 f(5) = 5^2 + 3 f(5) = ?

**math 5th grade**

5/5 * 2/3 = ? 100, 10, 1, 1/10

**Math**

I = PRT 525 = 3500 *.06 * T Solve for T (time) this is simple interest

**rectangular area **

you're welcome

**rectangular area **

A = Lw 240 = 24w w = ?

**To helper**

I do when they post more than one of the same type problem, but I understand and will only set up for now on

**Cylinder Height**

r = radius 3r = height (h) SA = 2(pi)(r)(h) + 2(pi)(r^2) SA = 2(pi)(r)(3r) + 2(pi)(r^2) SA = 6(pi)(r^2) + 2(pi)(r^2) SA = 8(pi)r^2 402 = 8(pi)r^2 402 = 8(3.14)r^2 402 = 25.12r^2 16.00318 = r^2 rounding 16.00318 = 16 16 = r^2 r = 4 height = 3r = 3(4) = 12

**algebra**

|x + 5| > 9 remove absolute value sign x + 5 > 9 x > 4 -x - 5 > 9 -x > 14 when you divide by a negative, reverse the sense of the inequality x < -14 x > 4 x < -14

**math **

(3xy - 10) - (xy + 5) 3xy - 10 - xy - 5 2xy - 15

**TO Helper**

I figured those were yours. I'm going through those now (and others). I try to help everyone I can. I don't exactly understand the donut problem either because the equation doesn't seem to work if all donuts were sold. I'm hoping REINY or another math tutor loo...

**TO Helper**

the screen name "Anonymous" belongs to anyone who left the name field blank, so I have no idea which posts are yours. I scan all problems and help where I can. I am not a tutor so I only help on problems I am sure of.

**MATH ALGEBRA**

2x- 3y + 30 = 0 ? to find x and y intercepts, put equation in the form ax + by = c x intercept = (c/a, 0) y intercept = (0, c/b) to find x-intercept, y = 0 2x - 3(0) = -30 2x = -30 x = -15 x intercept = (c/a, 0) x intercept = (-15, 0) to find y-intercept, x = 0 2(0) - 3y = -30...

**4th Grade**

2/9 * 36 = 72/9 = 8

**Algebra 1**

-0.2x < -10 divide both sides by -0.2 when dividing by a neg, reverse the sense of the inequality x > 50

**algerbra**

yes, you are correct

**alg. 2**

x^2 - 16x + 4 = 0 x^2 - 16x = -4 (-16^2)/4 = 256/4 = 64 x^2 - 16x + 64 = -4 + 64 x^2 - 16x + 64 = 60 (x - 8)^2 = 60

**MATH_ALGEBRA**

you're welcome :)

**MATH_ALGEBRA**

(1) F + 1000P = 32 (2) F + 3500P = 44.50 you have to solve these 2 equations simultaneously By elimination method, to eliminate F, multiply one of the equations by -1 -1(F + 1000P = 32)= -F - 1000P = -32 Now ADD these two equations together -F - 1000P = -32 F + 3500P = 44.50 0...

**MATH-ALGEBRA**

y = 2/5x - 3 P (0,5) parallel lines have equal slopes slope intercept form of an equation y = mx + b m = slope, b = y-intercept parallel to y = 2/5x - 3, and through P(0, 5) m = 2/5 y intercept = 5 so, the equation would be D. y = 2/5x + 5

**math**

A = B + 5 B = C + 7 C = THE DIFFERENCE BETWEEN 13 AND 9 D = A - B C = 13 - 9 = 4 B = C + 7 = 4 + 7 = 11 A = B + 5 = 11 + 5 = 16 D = A - B = 16 - 11 = 5 A = 16 B = 11 C = 4 D = 5

**algebra**

quadratic formula x = (-b +- (sqrt(b^2 - 4ac)))/2a 1) x^2 = 9 x^2 - 9 a = 1, b = 0, c = -9 x = 0 +- (sqrt(0^2 - 4(1)(-9)))/2(1) x = + - (sqrt(0 + 36))/2 x = +- (sqrt36)/2 x = +- 6/2 x = +- 3 x = 3, -3 you try number 2

**math**

Supplementary angles: two angles whose measures total 180 deg x = 1st angle 3x - 4 = 2nd angle x + 3x - 4 = 180 solve for x to find the angles

**algebra**

for michele (3x-2)/(5)-2<(2x-3)/(2) multiple both sides by LCD of 10 2(3x - 2) - 20 < 5(2x - 3) 6x - 4 - 20 < 10x - 15 6x - 24 < 10x - 15 -9 < 4x -9/4 < x x > -9/4

**Math**

if this your problem | 1 - 4x/3 | < 3 remove absolute value sign 1 - 4x/3 < 3 and -1 + 4x/3 < 3 1 - 4x/3 < 3 -4x/3 < 2 -4x < 6 x > -6/4 x > -3/2 -1 + 4x/3 < 3 4x/3 < 4 4x < 12 x < 3 so solution is -3/2 < x < 3

**math**

from above .03 = value of mixture this should be x + 100 = mixture total number of oz

**math**

x = number oz of cheaper tea .02x = value of cheaper tea 100 = number oz of better tea .05 * 100 = 5.00 = value of better tea .03 = value of mixture .03(x + 100) = value of mixture .02x + 5.00 = .03(x + 100) .02x + 5.00 = 3.00 + .03x 2.00 = .01x x = 200 200 oz of .02 tea

**Intermediate Algebra**

V = 2(pi * L^2) or V = 2pi * 2L^2

**algebra**

(4/(x + 2) - 4/x)/2 = 1 rewrite as (4/(x + 2) - 4/x) * 1/2 = 1 4/(2(x + 2)) - 4/2x = 1 4/(2x + 4) - 4/2x = 1 LCD 2x(2x + 4) (8x - 4(2x + 4))/(2x(2x + 4)) = 1 multiply both sides by 2x(2x + 4) 8x - 4(2x + 4) = 2x(2x + 4) 8x - 8x -16 = 4x^2 + 8x -16 = 4x^2 + 8x 4x^2 + 8x + 16 = ...

**math!!!**

g(x) = 2x^2 + x - 1 The degree of an equation that has not more than one variable in each term is the exponent of the highest power to which that variable is raised in the equation. b. 2 is the answer

**math!!!**

h = -6(t - 2.5)^2 + 38.5 plug in a few values for t when t = 1, h = 25 when t = 2, h = 37 when t = 2.5, h = 38 when t = 3, h = 37 you try, what do you think the answer is

**Algebra**

x = each base vertex angle = 1/2x + 10 solve x + x + 1/2x + 10 = 180

**Algebra II**

3/x^3 divided by 1/x^2 is this your problem? instead of dividing, invert and multiply 3/x^3 * x^2/1 = 3x^2/x^3 = 3x^-1 = 3/x

**algebra**

8/26 = m/13 cross multiply means denominator of 1st * numerator of 2nd numerator of 1st * denominator of 2nd 26M = 104 M = 4

**algebra**

11T/28-T / 4 = 1 rewrite problem 11T/28 - T * 1/4 = 1 11T/(4(28 - t)) = 1 11T/(112 - 4T) = 1 11T = 112 - 4T 15T = 112 T = 7.47

**advance algebra**

X=smaller number y= bigger number y - x = 192 9x = bigger number 9x - x = 192 8x = 192 x = 24 smaller number bigger number = 9x = 9(24) = 216

**calculus**

A = Lw 25 = Lw w = 25/L P = 2w + 2L P = 2(25/L) + 2L P = 50/L + 2L

**Algebra 1**

5x + y = 5x + (3x âˆ’ 11) = 13. where are you getting these problems? there is no way to solve the way you have written this. copy the problem exactly from your book

**Algebra 1**

no way to solve this

**math**

cannot solve either as separate equations

**math**

see your other post

**ALGEBRA**

4 + x(10 - 8) 4 + 10x - 8x 4 + 2x 2x = -4 x = -2

**Algebra 1**

5y + 4x = -41 what are you solving for? copy the complete problem from your book there isn't anything to solve for above, unless 5y + 4x = -41 5y = -41 - 4x y = (-41 - 4x)/5 4x = -41 - 5y x = (-41 - 5y)/4 is this what you want there is nothing else to solve for

**algebra**

don't understand what you need done repost

**MATH**

881/5 = 176 1/5

**Algebra 1**

5y + 4x = -41 what are you solving for?

**Algebra 1**

incomplete problem try again :)

**Geometry**

a + b + c = 1400 a + b + 600 = 1400 a + b = 800 using Pythagorean theorem a^2 + b^2 = 600^2 a + b = 800 a^2 + b^2 = 600^2 solve simultaneously I got a = 258.579 b = 541.421 or a = 541.421 b = 258.579

**math(algebra 1)**

2) you are correct x - y = 4 add + y to both sides x - y + y = 4 + y x = 4 + y

**math(algebra 1)**

1)3x + y = 0, x - y = 4 Pick and equation, and solve for either x or y x - y = 4 x = 4 + y Substitute, x = 4 + y, for x, in the other equation and solve for y x = 4 + y 3x + y = 0 3(4 + y) + y = 0 12 + 3y + y = 0 12 + 4y = 0 4y = -12 y = -3 substitute y = -3 in either equation...

**Math**

43 heads = 43 animals ( I hope!!) C = number of chickens G = number of goats C + G = 43 2C + 4G = 108 solve simultaneously to find C and G if you are right, C = 32 G = 11

**algebra**

set up ratio 3/2.5 = x/8 2.5x = 24 x = 9.6 $9.60 for 8

**5th math**

4 feet = 4 x 12 in/ft = 48 inches from above, this should say write down the most times a factor was used within one factorization

**5th math**

mean is the average add all the numbers to get the sum divide the sum by the number of numbers you are adding. 33 + 41 + 37 + 27 + 32 = 170 since there are 5 numbers, you divide the sum by 5, to get the mean 170/5 = 34 the mean is 34 LCM 6, 4, 8 LCM is 24 how I was taught fact...

**math**

b. 8th:7th = 2:3

**Math**

A = 4pir^2 TA = 4(3.14)(5^2) TA = 4(3.14)(25) TA = ?

**math**

y^2-3y=9 y^2 - 3y = 9 complete the square y^2 - 3y + 9/4 = 9 + 9/4 (y - 3/2)^2 = 45/4 +- (y - 3/2) = 45/4 solve for y y = 3/2 (sqrt5 + 1) y = -3/2 (-1 + sqrt5)

**algebra 2 and trigonometry**

y^2-3y=9 y^2 - 3y = 9 complete the square y^2 - 3y + 9/4 = 9 + 9/4 (y - 3/2)^2 = 45/4 +- (y - 3/2) = 45/4 solve for y y = 3/2 (sqrt5 + 1) y = -3/2 (-1 + sqrt5)

**math**

6th - 125 7th - 150 8th- 100 a) ratio 6th:7th 125:150 = 5:6 b) 8th:7th 100:150 = 4:6 = 2:3 c) 6th: total = 125:375 = 5:15 = 1:3 d) 8th:total = 100:375 = 4:15 check your b. ratio 2:3, not 3:2

**math**

ratio to what? 125 : 150 : 100 5 : 6 : 4

**Pre-Algebra**

vinegar - pH 3 baking soda - pH 9 9 - 3 = 6 units diff. 10 x 6 = 60x as acidic 10^6 = 1 million, so I can't see how that is right 10^1.77815 = 60 or, 6 x 10^1 = 60 is this a pre-algebra question or science?

**trig**

restate your question. I don't understand. is this a right triangle? "i have one degree 25" What does this mean? side b = 2.489 * 10^9 ? or 2,489,000,000? post question exactly as written from your book.

**Pre-Algebra**

:) that's ok. also, you will have better response if posted separate.

**Pre-Algebra**

vinegar - pH 3 baking soda - pH 9 9 - 3 = 6 units diff. 10 x 6 = 60x as acidic 10^6 = 1 million, so I can't see how that is right 10^1.77815 = 60 I am not a tutor, so you might want to repost this as a separate question

**Pre-Algebra**

if this is what you mean 1) a^8/a^8 = 1 2) -x^5/-x^4 = x 3) 15/5 * n^9/n = 3n^8 Also, use separate posts for 2 different questions/subjects

**math**

not enough info to find d and c post the whole problem

**math 1 digit divisors word problem**

you're welcome :)

**math 1 digit divisors word problem**

To have a remainder of 8, the divisor must be greater than 8. The only single digit greater than 8 is 9, so 9 must be the divisor. Since 8 is 1 less than 9, the dividend needs to be one less than a multiple of 9. Candidates are values of 3 digits, as the problem states. The lo...

**Emploument English**

true, you are correct

**Math**

7 1/4 = 29/4 = 58/8 3 3/8 = 27/8 58/8 - 27/8 = 31/8 = 3 7/8

**math**

see your 1st post

**math**

7560 = 756. x 10^1 but like Esskay said above, scientific notation would not be used for 7560

**Sex Ed(English)**

A. 12 weeks

**math**

x/y - z = rw solve for x x - yz = yrw x = yrw + yz x = y(rw + z) A

**algebra**

-7 = -1/6x -42 = -x x = 42

**Sex Ed(English)**

thanks Writeacher, I was not clear :)

**Sex Ed(English)**

true

**math**

1/20 of 1.00 = .05 so, 1 nickle or 5 pennies

**Sex Ed(English)**

VERY correct

**geometry**

14q + 8 + 8q - 6 = 90 22q + 2 = 90 22q = 88 q = 4 14q + 8 = 64 8q - 6 = 26 64 + 26 = 90

**Sex Ed(English)**

true

**math**

5 : x = 25 : 30 5/x = 25/30 cross multiply 150 = 25x x = 6

**math**

60 x .80 = 48 spent 60 - 48 = 12 left to invest 12 x .80 = 9.60 $9.60

**Math**

see your 1st post

**math**

6x - 4y - 3x + y 3x - 3y

**math**

600 x .06 x 5 = ?

**MATHAROOO**

think of the midpoint of a line as being the half-point of a line there can only be one point that divides this line into 2 equal parts A--------MP--------B A--------C--------B C is the midpoint of line AB now, you could find the midpoint of segment AC A----MP----C--------B A-...

**Math/Radical Expressions**

If this is your equation g/t + g - g/t - g = 0

**MATH**

6/330 =0.018182

**Math**

5x = 4y - 30 2x + 3y +-12 (1) 5x - 4y = -30 (2) 2x + 3y = 12 multiply (1) by 3(5x - 4y = -30) (1) 15x + 12y = -90 multiply (2) by 4(2x + 3y = 12) (2) 8x + 12y = 48 ADD two new equations (1) 15x + 12y = -90 (2) 8x + 12y = 48 23x + 0 = -42 23x = -42 x = -42/23 substitute x = -42...

**math**

correction-this should be net salary * 12 mo. = annual net salary

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