Friday

May 6, 2016
Total # Posts: 1,776

**Math**

8x^2+18x-5 (2x + 5)(4x - 1) My method or steps is trial and error. You need to find factors of 8x^2 that also add to 18x. The same for factors of 5. It takes practice. The only way you learn is by practice. Do as many problems as you can and eventually it gets easier.
*January 25, 2011*

**algebra**

You're welcome.
*January 25, 2011*

**algebra**

I assume you need to solve these equations simultaneously ? 3x + 5y = 0 2x - 5y = -9 Solving by elimination method. The object is to eliminate one of the variables, either x or y. Since you have +5y in the first equation and -5y in the second equation, you ADD the two ...
*January 25, 2011*

**Math**

If I am following your problem. The area of ONE shaded face = 64 cm^2 Since, this face is a square, the length L equals the height h. L = H Cuboid SA = 2Lw + 2Lh + 2wh Since you have the SA (surface area) of one face, and L = H, SA = 2Lh SA = 2LL (L = h) 64 = 2L^2 32 = L^2 L...
*January 25, 2011*

**math**

See your 1st post below. I worked out the almost exact problem for you. Using the below post as an example, you should be able to at least try to do this problem. Post your work if you get stuck so someone can help you.
*January 25, 2011*

**math**

You don't state if this is compounded interest. Assuming simple interest, I = PRT (interest = principal x rate x time) 9006 - 8765 = 241 interest 241 = 8765 x R x T 241 = 8765 x R x 1 241 = 8765R Solve for R, the rate of interest Multiply R x 100 = percent
*January 25, 2011*

**math in topics**

Are you sure that is ALL the info you are given? The problem doesn't state how many students? Please recheck your problem.
*January 25, 2011*

**math**

Let x = number of trip miles (x - 2) = miles greater than first 2 1.50 + 1.20(x - 2)
*January 25, 2011*

**math**

f(x)=x^2+12x+37 y = x^2 + 12x + 37 Solve for x x^2 + 12x = y - 37 Complete the square x^2 + 12x + 36 = y - 37 + 36 (x + 6)^2 = y - 1 Take the square root of both sides +- (x + 6) = (sqrt(y - 1)) x + 6 = (sqrt(y - 1)) -x - 6 = (sqrt(y - 1)) x = -6 +- (sqrt(y - 1)) Interchange x...
*January 25, 2011*

**Science**

If you go to google dot com and put in "Seals" in the search box it will bring up more info than you could possibly use. I can't post links, otherwise I would do it for you.
*January 25, 2011*

**Math**

REINY answered your earlier post and she said to try doing it yourself. She did a similar example for you to follow. I pasted her example below. Post your work if you get stuck. Math - Reiny, Tuesday, January 25, 2011 at 12:09pm slope of line through the two points = (6-2)/(3-...
*January 25, 2011*

**biology**

About what I posted above. You probably have this already. This was a response to the exact question you posted here and there. I did a google search with your question and it directed me to your? other post on that website. I didn't realize this until after I posted above...
*January 25, 2011*

**biology**

From cholesterol heart attack dot com Physiological response: "John survived because he grew collateral coronary arteries. The coronary arteries supply the heart muscle with oxygenated blood. Chronic high cholesterol results in plaque accumulating inside the coronary ...
*January 25, 2011*

**equations calculus**

This exact question was answered for you yesterday. Please check your posts for an answer before reposting. I have pasted below the answer to this post. calculus - drwls, Monday, January 24, 2011 at 11:39pm Rewrite it as an equation for y in terms of x. y - 0.5 x = y This ...
*January 25, 2011*

**Calculus**

This is calculus? h(x)= x^3-x^2+x+6 h(-8) Plug -8 in for x and do the math.
*January 25, 2011*

**Intermediate Accounting**

Your question isn't clear. Calculate what? Do you need to calculate the portion of insurance that is a current expense for the year 2011 and the portion that is a prepaid expense or prepaid asset? 4000/2 = 2000. = 1 year expense 2000./12 = monthly expense for 1 year Jan ...
*January 25, 2011*

**math in topics**

"how many new are needed on campus" ... How many new ? New what? The answers don't make sense for the question asked. Re-read your whole post for clarity.
*January 25, 2011*

**fraction**

2/3 0f 9 Multiply 2/3 x 9 = 18/3 = 6 1/6 x 12 = ?
*January 24, 2011*

**CP Geometry**

I knew if was a riddle. That's why I asked "What" ! :)thanks
*January 24, 2011*

**CP Geometry**

(sqrt5) * (sqrt15)= (sqrt75)= =(sqrt25)(sqrt3)= 5(sqrt3) What do you call it when the nurse gives you a shot you hardly feel? What?
*January 24, 2011*

**latin**

BElimicus, testanmento When you are about to have heard, so much so astounded by was, when ninil could reply, without prejudice to these things, laughing, he added. From Google translator
*January 24, 2011*

**Algebra **

This is something you will have to do. Because of formatting, it is not possible to graph here.
*January 24, 2011*

**alegebra**

5 x -4 x 6 = -120 Product means to multiply the numbers.
*January 24, 2011*

**Math**

Do you have an equation for line h? If you do, post it here. It is needed to find the equation of line f.
*January 24, 2011*

**Math**

Do you have an equation for line h? If you do, post it here. It is needed to find the equation of line g.
*January 24, 2011*

**Math**

You are welcome!
*January 24, 2011*

**Math**

Plot the point(s) on a graph to see which quadrant it is in. Or, you can memorize this. For example, Quadrant I, the points are all positive, ie, (x,y). In Quadrant II, the points would be of the form (-x,y) Quadrant III, (-x,-y) Quadrant IV, (x,-y)
*January 24, 2011*

**Pre algebra**

44 ft/sec x 60 sec = 2640 ft/min 2640 ft/min x 60 mi/hr = 158,400 ft/hr 158,400 ft/hr / 5280 ft/mi = 30 mph
*January 24, 2011*

**math**

A = Art, B = Ben In 5 years art will be twice as old as ben. A + 5 = 2(B + 5) 5 years ago art was 3 times as old as ben. A - 5 = 3(B - 5) A + 5 = 2(B + 5) A + 5 = 2B + 10 A = 2B + 5 Substitute, A = 2B + 5, in A - 5 = 3(B - 5) 2B + 5 - 5 = 3(B - 5) 2B = 3B - 15 B = 15 Ben is 15...
*January 24, 2011*

**math**

You're welcome!
*January 24, 2011*

**math**

John sets off 4 seconds after Tom does, and finishes the lap 2.5 seconds sooner than Tom does. So, John's total time will be 6.5 sec less than Tom's time. Do you understand? Also, If you solved correctly, R = 20 and T = 32.5. Remember, the problem wants each racers'...
*January 24, 2011*

**math**

RT = D T = time for Tom T - 6.5 = time for John (-4s + -2.5s) R = rate for Tom R + 5 = rate for John D = 650 RT = D RT = 650 (R + 5)(T - 6.5) = 650 Solve these equations simultaneously. Expand (R + 5)(T - 6.5) = 650 Then substitute, RT = 650 for RT in the expansion.
*January 24, 2011*

**Math**

correct :)
*January 24, 2011*

**Math**

If two non vertical lines are parallel, their slopes are equal. Can you answer now?
*January 24, 2011*

**Calculus**

I forgot the very first line, where I rewrote the integral sin^3 x/cosx dx=|(sin^2 x sin x)/cos x dx sin^3 x/cos x dx = |sin^2 x tan x dx see above
*January 24, 2011*

**Calculus**

sin^3 x/cosx dx | = integral sign |sin^2 x tan x dx |(1 - cos^2 x)tan x dx |tan x - cos^2 x tan x dx |tan x - cos^2 x (sin x/cos x) dx |tan x - sin x cos x dx |tan x dx - |sin x cos x dx ln (sec x) - |sin x cos x dx u = cos x du = sin x dx ln (sec x) - |u du ln |sec x| - 1/2 u...
*January 24, 2011*

**math**

If I understand your poorly worded problem. w = width w + 3 = length P > 24 P = 2w + 2L 2w + 2(w + 3) > 24 Solve for w, the width
*January 24, 2011*

**algebra**

3(4x+6)+7x Distribute the 3 12x + 18 + 7x 19x + 18 19x = -18 x = ?
*January 24, 2011*

**Math**

RT = D (rate x time = distance) 800 = rate of 2nd jet T = time of 2nd jet 800T = distance of 2nd jet 600 = rate of 1st jet T + .75 = time of 1st jet (3/4h = .75h) 600(T + .75) = distance of 1st jet Distances are equal 600(T + .75) = 800T Solve for T
*January 24, 2011*

**Math**

y = x + 3 Pick values for x, solve for y Example, x = 0 y = x + 3 y = 0 + 3 y = 3 (0, 3) x = -1 y = x + 3 y = -1 + 3 y = 2 (-1,2) x = 1 y = x + 3 y = 1 + 3 y = 4 (1,4) Picks more values for x as needed. Use these points to graph.
*January 24, 2011*

**Algebra 2**

L = no. of liters of 80% solution .80L = value of 80% solution 10 - L = no. of liters of 40% solution .40(10 - L) = value of 40% solution .48(10) = value of mixture .80L + .40(10 - L) = .48(10) Solve for L L = no. of liters of 80% solution 10 - L = no. of liters of 40% solution
*January 24, 2011*

**geometry**

Ratio of sides is 6:15 = 6/15 = 2/5 Ratio of perimeter is 22:x 2:5 = 22:x 2/5 = 22/x cross multiply and solve for x
*January 24, 2011*

**algebra**

w = width 7w = length P = 2w + 2L P = 2w + 2(7w) I leave it to you to simplify.
*January 24, 2011*

**Math**

7a - 4 + 2a = 3a - 2 9a - 4 = 3a - 2 6a = 2 a = ?
*January 24, 2011*

**algebra**

n = number 2n = 28 n = 14
*January 24, 2011*

**algebra**

see above post
*January 24, 2011*

**math**

10 = 5(t - 10) - 2t 10 = 5t - 50 - 2t 10 = 3t - 50 Can you finish?
*January 24, 2011*

**math**

see your other post
*January 24, 2011*

**Math**

The "mode" is the value that occurs most often. If no number is repeated, then there is no mode for the list.
*January 24, 2011*

**diameter**

x = diameter of 1 circle x + 8 = diameter of 2nd circle x + x + 8 = 28 2x + 8 = 28 Solve for x
*January 24, 2011*

**Geometry**

AB = 4, CD = 7 2*AB = 8 1*CD = 7 2*AB - CD = 1 2*(4) - 7 = 1 8 - 7 = 1
*January 24, 2011*

**Trigonometry **

1025 * pi/180 = 1025pi/180 = 205pi/36
*January 24, 2011*

**algebra**

12^-2 = 1/12^2 = 1/144
*January 24, 2011*

**GEOMETRY**

see your earlier post
*January 24, 2011*

**Pre Algebra**

length = L width = w Ratio = L:w = 10:7 = L:70 10:7 = L:70 10/7 = L/70 cross multiply 700 = 7L L = 100 L = 100, w = 70 P = 2w + 2L P = ?
*January 24, 2011*

**Physics**

See the third link below under Related Questions. This almost exact problem was solved.
*January 24, 2011*

**Physics**

See the first two links below under Related Questions. This almost exact problem was solved.
*January 24, 2011*

**Physics**

See link 2 below under Related Questions. This almost exact problem was solved.
*January 24, 2011*

**Physics? Help Needed**

FYI-If you want help, it is important that you put the school subject name in the 'School Subject' box. I changed it for you.
*January 24, 2011*

**Math Urgent**

(sqrt(5)) + (sqrt (20)) Breakdown (sqrt(20)) (sqrt(5)) + (sqrt(4))(sqrt(5)) (sqrt(5)) + 2(sqrt(5)) Can you add them now?
*January 24, 2011*

**math**

"I tried several combinations using -3,2,and -1 in place of m but still not coming out right." Are you missing part of this problem? There is no 'm' anywhere in your posted problem to replace?
*January 24, 2011*

**Geometry**

you're welcome
*January 24, 2011*

**Geometry**

I got angle NMO = 61 same method as above, but correction for LMO = x + 32 Therefore, angle LMO = angle NMO angle NMO = angle LMN - angle LMO angle NMO = 5x - 23 - (x + 32) angle NMO = 5x - 23 - x - 32 angle NMO = 4x - 55 angle LMO = angle NMO x + 32 = 4x - 55 3x = 87 x = 29 ...
*January 24, 2011*

**Geometry**

Thank you. That's much better. If I am understanding your description, A line that bisects an angle divides it into two congruent parts. Therefore, angle LMO = angle NMO angle NMO = angle LMN - angle LMO angle NMO = 5x - 23 - (x + 3) angle NMO = 5x - 23 - x - 3 angle NMO...
*January 24, 2011*

**Geometry**

What is LMN? For example, is this a line segment, triangle, or ? How did you get 45.75? You need to post a better explanation. Think of it like this. If you knew absolutely nothing about this problem could you solve it with just the info you posted?
*January 24, 2011*

**Math Please Help**

by the formula v = (-53 ï¿½ âˆš3349)/30 âˆš3349 = 57.87 Calculate v using 57.87 as the exact value for âˆš3349.
*January 24, 2011*

**math/ CIRCUMFERENCE of a circle**

- find out how many feet are in 1 yard - divide 5280 feet by 2 (which would equal half a mile) - take that number and divide by how many feet the circumference of the wheel is
*January 24, 2011*

**6th grade math**

5 / 1/3 5 x 3 = 15 1/3 x 3 = 3/3 = 1 15/1 Then find the quotient, 15/1 = 15 IF you did have to divide 5 by 3/9 you would multiple 5 by the reciprocal of 3/9, so 5 / 3/9 = 5 x 9/3 = 45/3 Yes, you were correct IF you had to divide by 3/9.
*January 24, 2011*

**algebra**

I answered your post below with this same question. Please check to see if your post was answered before re-posting. I pasted the answer here for you. x = liters of 3% solution 3 - x = liters of 10% solution .03x = value 3% solution .10(3 - x) = value 10% solution 3 = liters ...
*January 23, 2011*

**Math**

log2(log4x)=1 Rewrite as (log((log(x))/(log(4))))/(log(2)) = 1 Divide both sides by 1/(log(2)): log((log(x))/(log(4))) = log(2) Cancel logarithms by taking exp of both sides: (log(x))/(log(4)) = 2 Divide both sides by 1/(log(4)): log(x) = 2 log(4) Cancel logarithms by taking ...
*January 23, 2011*

**financial analysis**

I am pretty sure it is a current asset. A current asset has a life of one year or less (e.g., inventory) while a noncurrent asset has a life in excess of one year (e.g., machinery).
*January 23, 2011*

**Math**

Answered in a later post.
*January 23, 2011*

**algebra**

x = liters of 3% solution 3 - x = liters of 10% solution .03x = value 3% solution .10(3 - x) = value 10% solution 3 = liters of 7.9% mixture .079(3) = 0.237 = value 7.9% mixture .03x + .10(3 - x) = 0.237 Solve for x, which is number of liters of 3% solution. (3 - x) = number ...
*January 23, 2011*

**math **

(1/2)^x = 1152 rewrite as, 2^(-x) = 1152 Take the logarithm to the base 2 of both sides: -x log 2 = log 1152 -x = (log(1152))/(log(2)) Divide both sides by -1: x = -(log(1152))/(log(2)) x = - 3.061452/0.3010299 x = -10.1699
*January 23, 2011*

**algebra 2**

See links below under Related Questions. This exact question was answered.
*January 23, 2011*

**geometry**

Triangle has 180 degrees 22.5 + 101 = 123.5 180 - 123.5 = 56.5 A. 56.5 Obtuse triangle: An obtuse triangle is a triangle having an obtuse angle. Obtuse angle: An obtuse angle is an angle whose measure is more than 90 degrees and less than 180 degrees. B. Obtuse triangle
*January 23, 2011*

**ela**

FYI, you might be helped faster if you followed directions and put the name of your school subject in the box instead of whatever 'ela' is. This way, a tutor that is familiar with your subject can answer.
*January 23, 2011*

**algebra**

I don't think this problem is correct or that it can be solved. Either that, or the problem is poorly worded (to me). If they are each saving to buy the same CD's and Juan is only short $3.00, how can it be that when they combine their money they still do not have ...
*January 23, 2011*

**Math**

What do you mean by 'condense'? Is that what your problem directions say?
*January 23, 2011*

**college math 209**

You need to use parentheses in this problem. What are the ? for or mean? Square root of 48 or 48yv^2 or ? Same for the other square root. Please use parentheses and retype your problem here in a reply post.
*January 23, 2011*

**Pre-Calc**

sqrt(x-6)+sqrt(x+10) = 8 sqrt(x-6) = 8 - sqrt(x+10) Square both sides x - 6 = (8 - sqrt(x + 10))^2 Expand out terms on the right hand side x - 6 = x - 16sqrt(x + 10) + 74 16sqrt(x + 10) = 80 Divide both sides by 16 sqrt(x + 10) = 5 Square both sides x + 10 = 25 x = 15
*January 23, 2011*

**Math**

3p^2 + 4p^2 = 63 7 p^2 = 63 Divide both sides by 7: p^2 = 9 Take the square root of both sides: p = -3 or p = 3
*January 23, 2011*

**Math**

See your post above.
*January 23, 2011*

**algebra**

RT = D (rate * time = distance) 4.1 = Emma's rate 3.7 = Mason's rate T = Emma's time T + .08 = Mason's time (48/60 = 0.8h) 4.1T = Emma's distance 3.7(T + 0.8) = Mason's distance Distances are equal to each other 3.7(T + 0.8) = 4.1T 3.7T + 2.96 = 4.1T 0....
*January 23, 2011*

**math**

A = Lw P = 2L + 2w Lw = 25 2L + 2w = 25 Solve these two equations simultaneously for your answer.
*January 23, 2011*

**MATH**

Changed subject
*January 23, 2011*

**MATH**

x^4 - x^2 - 6 (x^2 - 3)(x^2 + 2)
*January 23, 2011*

**Calc**

See the links below under Related Questions. Similar problems have been posted before and some of the info in those posts maybe be helpful.
*January 23, 2011*

**algebra 2**

yes, make one up
*January 22, 2011*

**algebra 2**

Plug a value for x (price of the suit) in each equation and then solve each equation. This way you can see if one results in a lower price. Explain why or why not, one equation results in a lower price.
*January 22, 2011*

**Algebra 1**

3y + 6x + 3 = 9 + 6x Subtract 6x from both sides 3y + 6x - 6x + 3 = 9 + 6x - 6x 3y + 3 = 9 Subtract 3 from both sides 3y + 3 - 3 = 9 - 3 3y = 6 Divide both sides by 3 3y/3 = 6/3 y = 2
*January 22, 2011*

**Algabra**

Time = Distance/Rate x = Javier's rate x + 5 = Kathy's rate 57/x = Javier's time 72/(x+5) = Kathy's time Since their time is equal, 57/x = 72/(x + 5) 72x = 57(x + 5) Solve for x
*January 22, 2011*

**Calculus **

1/(sqrt3)arctan(5/(29(sqrt3))= 0.0572826 Check you values for 1/a and x/a maybe that's where you got hung up | dx/(a^2 + x^2) (3/4 + w^2) a^2 = 3/4 a = (sqrt3)/2 x^2 = w^2 x = w So, you should have got, 1/2(1/(sqrt3/2)arctan (w/(sqrt3/2)) which simplified is, 1/2(2/(sqrt3)...
*January 22, 2011*

**Calculus **

1/2[2/(sqrt3)arctan(2(x^2+1/2)/(sqrt3) I distributed the 1/2, but backed it out for my above answer...I don't think I made any errors backing it out. Here is the answer, with the 1/2 distributed. I know this answer is right because I double check it with an online ...
*January 22, 2011*

**Calculus **

integrate x/(x^4+x^2+1) | = integrate symbol u = x^2 du = 2x dx 1/2 du = x dx 1/2 | du/(u^2 + u + 1) Complete the square u^2 + u = -1 u^2 + u + 1/4 = -1 + 1/4 (u + 1/2)^2 + 3/4 1/2 | du/((u + 1/2)^2 + 3/4) w = u + 1/2 dw = du 1/2 | dw/(w^2 + 3/4) 1/2 | dw/(3/4 + w^2) And, ...
*January 22, 2011*

**beginning algebra**

u^2 - u - 30 = 0 Using the quadratic formula, x =(-b +- (sqrt(b^2 - 4ac))/2a a = 1, b = -1, c = -30 x = 1 +- (sqrt(-1^2 - 4(1)(-30))/2 x = (1 +- (sqrt(1 + 120))/2 x = (1 +- (sqrt(121))/2 x = (1 +- 11)/2 x = (1 + 11)/2 = 6 x = (1 - 11)/2 = -5
*January 22, 2011*

**beginning algebra**

This was answered the first time you posted it. I pasted the answer below. (u - 1)^2 = 2u^2 - 3u - 29 u^2 - 2u + 1 = 2u^2 - 3u - 29 u^2 - u - 30 = 0 This does not factor. Solve by using the quadratic formula or the method of completing the square. Post your answer and someone ...
*January 22, 2011*

**College Algebra**

You're welcome and good luck :).
*January 22, 2011*

**College Algebra**

I'll try, but the formatting here doesn't allow for easy alignment of columns. xxxxxxxxxxxxx-3x^2 - 9x - 9 -2x^2+3x-3 |6x^4 + 9x^3 + 0x^2 + 0x +9 ------------6x^4 - 9x^3 + 9x^2 subtraction-------18x^3 - 9x^2 ------------------18x^3 - 27x^2 + 27x subtraction...
*January 22, 2011*

**College Algebra**

First rearrange and simplify the numerator to: 6x^4 + 9x^3 + 9 Just divide as your would with any long division problem. If you post your answer I can tell you if you are correct. Is there something in particular you do not understand?
*January 22, 2011*