Saturday

May 23, 2015

May 23, 2015

Total # Posts: 1,738

**Physics **

See the links below under related questions. At least three of the links have answers to this almost exact question.
*January 25, 2011*

**math**

You're welcome.
*January 25, 2011*

**math**

The formula for perimeter is, P = 2w + 2 L 30 = 2w + 2L 30 = 2(w + l) 15 = w + l So, for a perimeter of 30, you want to sketch rectangles that the width and length total 15. Some possible rectangles, 14 + 1 = 15 13 + 2 = 15 12 + 3 = 15 11 + 4 = 15 10 + 5 = 15 9 + 6 = 15 8 + 7...
*January 25, 2011*

**Physics**

The first link below does have an answer. Whether it is a complete answer, I wouldn't know. You have to scroll down quite a bit for the answer. I am pasting that answer here. Maybe it will help you get started. Physics - drwls, Tuesday, March 23, 2010 at 9:48pm First you ...
*January 25, 2011*

**Physics**

See the 1st link below under Related Questions. A similar problem was answered.
*January 25, 2011*

**CP Geometry**

(sqrt(-60/5)) Break it down ((sr(-1))(sr(4))(sr(3))(sr(5)))/(sr(5)) 2i (sqrt(3))
*January 25, 2011*

**Physics**

See the 1st two links below under Related Questions. This almost exact problem was answered.
*January 25, 2011*

**math**

Lisa, I hope I didn't sound mean to you. That is not my intention. You will never learn unless you try. It takes practice. :) Is there something in particular you don't understand about dealing with fractions?
*January 25, 2011*

**math**

Tutors do not do your homework. It is obvious that you are struggling with this. The only way you will learn is practice. Try these problems YOURSELF. If you have a specific question we will be more than happy to help, but YOU must attempt these problems first.
*January 25, 2011*

**math**

And, ignore how I said that I do it. Do it your way, however you were taught. Your way IS correct. I just prefer to do it the way I was taught. I don't want to confuse you. :)
*January 25, 2011*

**math**

Ok, sorry, your answer 8 25/72, was the SUM, not the final answer, which is the average. 8 25/72 is correct for the sum. You have to divide the sum by 2, for the average. So however you were adding is correct.
*January 25, 2011*

**math**

What grade are you in? Unless there is a new way taught for adding fractions, you can't do it like that. You have to convert each mixed number to a fraction 3 2/9 = 29/9 5 1/8 = 41/8 Then you add 29/9 + 41/8 Find the LCD 232/72 + 369/72 = 601/72 601/72 divided by 2, ...
*January 25, 2011*

**math**

Not correct. Post your work so I can see what you are doing wrong, because you are not even close. :)
*January 25, 2011*

**math**

Yes, always. All fractions have to have the same denominator to add.
*January 25, 2011*

**Math**

How did you get 40 from that? Do you mean 200/(x - 1) = 200/(x + 10) cross multiply 200(x + 10) = 200(x - 1) 200x + 2000 = 200x - 200 NO solution to this
*January 25, 2011*

**Math**

Thank you. :)
*January 25, 2011*

**Math**

Please see your 1st post for an answer. And, please don't repost a question without first checking to see if your original post was answered. Please have patience. The tutors volunteer their time to help you. Sometimes it takes awhile for a post to be answered. You have ...
*January 25, 2011*

**Trig **

I apologize. The answer hadn't been posted when you posted this.
*January 25, 2011*

**Trig **

See your 1st post for the answer. And, please check your original post for an answer before reposting.
*January 25, 2011*

**general**

Thank you Kristin.
*January 25, 2011*

**math**

What is 300 + 20? Answer, 320 Is this what you need? If so, you couldn't attempt this?
*January 25, 2011*

**Math**

y = sqrt(x^2 + 2x) square both sides y^2 = x^2 + 2x x^2 + 2x = y^2 complete the square x^2 + 2x + 1 = y^2 + 1 (x + 1)^2 = y^2 + 1 take the square root of both sides + x + 1 = (sqrt(y^2 + 1)) - x - 1 = (sqrt(y^2 + 1)) x = -1 + - (sqrt(y^2 + 1)) interchange x and y y = -1 +- (...
*January 25, 2011*

**Math**

D = RT (Distance = Rate x Time) Normal Rate R = rate T = time RT = 200 Increased Rate/less time R + 10 T - 1 (R + 10)(T - 1) = 200 Solve these two equation simultaneously. (R + 10)(T - 1) = 200 RT = 200 Expand the first equation and substitute RT = 200, for RT in that ...
*January 25, 2011*

**geometry**

If you sketch this out, the ladder, up against the wall, forms right triangle. Using the Pythagorean theorem, you need to find c, the hypotenuse. c^2 = 6^2 + 18^2 Solve for c, the length of the ladder.
*January 25, 2011*

**math**

1 square inches = 0.00694444 square feet 12 sq inches = 0.08333 sq ft 1 square ft = 144 sq inches 12 inches squared = 144 sq inches you are both right
*January 25, 2011*

**math**

(h+t)^6 = (h + t)(h + t)(h + t)(h + t) (h + t)(h + t) You would have to expand and multiply it out or use the binomial theorem. Or maybe a calculator of some sorts
*January 25, 2011*

**math**

You have to try this yourself. It is the only way you will learn. I've already done at least one of these problems for you. First, find the LCD for each . Post your work if you get stuck.
*January 25, 2011*

**Math**

See 1st post.
*January 25, 2011*

**Math**

You're welcome.
*January 25, 2011*

**Math**

0.2|-8| = 1.6 0.2 * 8 = 1.6 |5|-|-7| = - 2 5 - 7 = - 2
*January 25, 2011*

**math**

3/2 / 4/5 + 1/2 * 1/2 You need parentheses. Do you mean (3/2 / 4/5 + 1/2) * 1/2 ? or 3/2 / 4/5 + (1/2 * 1/2)?
*January 25, 2011*

**math**

Duplicate post. See your 1st post.
*January 25, 2011*

**math**

8/24 + 9/24 + 1/24 = 18/24 = 3/4 (3/4)/3 = 3/4 * 1/3 = 3/12 = 1/4 Average = 1/4
*January 25, 2011*

**math**

1/3 + 3/8 + 1/24 Find the LCD. In this case, LCD = 24 8/24 + 9/24 + 1/24 = ? Take the sum and divide by 3 for the average.
*January 25, 2011*

**Math(geometry)**

Cross off 8 + 0 = 8. Can't have a side of 0.
*January 25, 2011*

**Math(geometry)**

Formula for perimeter, P = 2L + 2w 2L + 2w = 16 2(L + w)= 16 L + w = 8 You need numbers that add to 8. 8 + 0 = 8 7 + 1 = 8 6 + 2 = 8 See how many you can come up with. There might be any easier way, that I'm not thinking about. Good luck
*January 25, 2011*

**math**

x = the number 6x = x + 6 Solve for x
*January 25, 2011*

**math**

164/24 = 6 20/24 = 6 5/6
*January 25, 2011*

**math - algebra**

I hit 'post answer' too soon. See below. Dan, Fran, and Stan have 194 cards. Dan has 24 less than Fran, and Stan has 35 more than Fran. How many do each of them have? Let x = the number of cards that Fran has. x + x - 24 + x + 35 = 194 3x + 11 = 194 3x = 183 x = 61
*January 25, 2011*

**math - algebra**

Are you sure that this is the exact wording for this problem? Need to know info for either Dan or Stan. You posted this almost exact same problem yesterday. I pasted that post below.
*January 25, 2011*

**public finance**

Not enough info. "calculate the MTR for his labor earnings"? More than this is missing too. Mortgage interest expense, itemized deductions, etc.
*January 25, 2011*

**Pre-Algebra**

D = RT (distance = rate x time) R = rate 8R >= 420 R >= 52.5
*January 25, 2011*

**Math Algebra**

2m +3n=4 -m + 2n= 5 Multiply by 2 (-m + 2n = 5) -2m + 4n = 10 2m + 3n = 4 Add the two equation 0 + 7n = 14 7n = 14 n = 2 To find m, substitute n = 2 in 2m + 3n = 4 and solve for m I'll let you finish Check your answers when you find m
*January 25, 2011*

**geometry**

P = 2w + 2L w = width, L = length Since, this is a square, w = L P = 2w + 2w P = 4w 2011 = 4w w = 2011/4 = 502.75 A = Lw Since this is a square, w = L = 502.75 A = (502.75)(502.75) A = ? square inches
*January 25, 2011*

**Math**

correct :)
*January 25, 2011*

**Math**

Are the sides of triangle BCE, BC, BE and EC ? In rectangle ABCD, is side BC opposite to side AD? If so, AD = BC = 3 If so, since BCE is an equilateral triangle, (all three sides equal)therefore BE = BC = EC = 3. I don't have the advantage of seeing the diagram you are, so...
*January 25, 2011*

**Algebra**

Formula for perimeter P = 2w + 2L x = length (L) y = width (w) 2x + 2y <= 60
*January 25, 2011*

**Math Geometry**

A line that bisects an angle divides it into two congruent parts. A triangle = 180 degrees 2(27) + 2(34) + x = 180 x = ?
*January 25, 2011*

**Math**

Not equal. You are solving an inequality. x > 0.5
*January 25, 2011*

**Math Geometry**

A right triangle has an angle of 90 degrees. The sum of the angles in a triangle = 180 degrees. 90 + 16 + x = 180 x = ?
*January 25, 2011*

**Math**

7 + 3 = 10 coins 3/10 = fraction of nickles fraction of dimes = ?
*January 25, 2011*

**calculus**

[1/(x^2+1)] By Formula, âˆ«1/(1 + x^2)dx = tan^-1(x) + C
*January 25, 2011*

**physics**

See the 3rd link below under Related Questions. This almost exact problem was solved there.
*January 25, 2011*

**math**

3/2 / 7/10 /5/2 without parentheses, I will divide in order. (3/2)/(7/10) = 3/2 * 10/7 = 30/14 (30/14)/(5/2) = 30/14 * 2/5 = 60/70 = 6/7
*January 25, 2011*

**math**

6y = -8x - 18 Put the equation in slope-intercept form, by solving for y 6y = -8x - 18 Divide both sides bu 6 y = -8/6 x - 18/6 Reduce fractions y = -4/3 x - 9/3 Now, the equation is in slope-intercept form. y = mx + b, where m = slope and b = y-intercept Slope m = ? y-...
*January 25, 2011*

**math**

x = total employees .80x = 720 Solve for x.
*January 25, 2011*

**social studies**

Thank you Ms. Sue! :)
*January 25, 2011*

**social studies**

The tutors here don't have a copy of your text book. This is something YOU need to do. READ section 6 of chapter 6. I'm sure you can find 10 important facts. Try.
*January 25, 2011*

**Algebra**

Ratio = 4:3 = 4/3 4/3 = x/(2/3) Cross multiply 3x = 4 * 2/3 Can you solve for x now?
*January 25, 2011*

**math**

To find the range, put the numbers in order. Range = highest - lowest
*January 25, 2011*

**geometry**

Complementary angles = 90 degrees x = one angle 1/3 x = other angle x + 1/3 x = 90 Combine terms and solve for x. Then use the above formula to find the other angle.
*January 25, 2011*

**Math**

I said the above because you have the shaded picture to look at, I don't.
*January 25, 2011*

**Math**

See your 1st post below. I just finished your problem. Let me know if you think I understood your problem.
*January 25, 2011*

**Math**

8x^2+18x-5 (2x + 5)(4x - 1) My method or steps is trial and error. You need to find factors of 8x^2 that also add to 18x. The same for factors of 5. It takes practice. The only way you learn is by practice. Do as many problems as you can and eventually it gets easier.
*January 25, 2011*

**algebra**

You're welcome.
*January 25, 2011*

**algebra**

I assume you need to solve these equations simultaneously ? 3x + 5y = 0 2x - 5y = -9 Solving by elimination method. The object is to eliminate one of the variables, either x or y. Since you have +5y in the first equation and -5y in the second equation, you ADD the two ...
*January 25, 2011*

**Math**

If I am following your problem. The area of ONE shaded face = 64 cm^2 Since, this face is a square, the length L equals the height h. L = H Cuboid SA = 2Lw + 2Lh + 2wh Since you have the SA (surface area) of one face, and L = H, SA = 2Lh SA = 2LL (L = h) 64 = 2L^2 32 = L^2 L...
*January 25, 2011*

**math**

See your 1st post below. I worked out the almost exact problem for you. Using the below post as an example, you should be able to at least try to do this problem. Post your work if you get stuck so someone can help you.
*January 25, 2011*

**math**

You don't state if this is compounded interest. Assuming simple interest, I = PRT (interest = principal x rate x time) 9006 - 8765 = 241 interest 241 = 8765 x R x T 241 = 8765 x R x 1 241 = 8765R Solve for R, the rate of interest Multiply R x 100 = percent
*January 25, 2011*

**math in topics**

Are you sure that is ALL the info you are given? The problem doesn't state how many students? Please recheck your problem.
*January 25, 2011*

**math**

Let x = number of trip miles (x - 2) = miles greater than first 2 1.50 + 1.20(x - 2)
*January 25, 2011*

**math**

f(x)=x^2+12x+37 y = x^2 + 12x + 37 Solve for x x^2 + 12x = y - 37 Complete the square x^2 + 12x + 36 = y - 37 + 36 (x + 6)^2 = y - 1 Take the square root of both sides +- (x + 6) = (sqrt(y - 1)) x + 6 = (sqrt(y - 1)) -x - 6 = (sqrt(y - 1)) x = -6 +- (sqrt(y - 1)) Interchange x...
*January 25, 2011*

**Science**

If you go to google dot com and put in "Seals" in the search box it will bring up more info than you could possibly use. I can't post links, otherwise I would do it for you.
*January 25, 2011*

**Math**

REINY answered your earlier post and she said to try doing it yourself. She did a similar example for you to follow. I pasted her example below. Post your work if you get stuck. Math - Reiny, Tuesday, January 25, 2011 at 12:09pm slope of line through the two points = (6-2)/(3-...
*January 25, 2011*

**biology**

About what I posted above. You probably have this already. This was a response to the exact question you posted here and there. I did a google search with your question and it directed me to your? other post on that website. I didn't realize this until after I posted above...
*January 25, 2011*

**biology**

From cholesterol heart attack dot com Physiological response: "John survived because he grew collateral coronary arteries. The coronary arteries supply the heart muscle with oxygenated blood. Chronic high cholesterol results in plaque accumulating inside the coronary ...
*January 25, 2011*

**equations calculus**

This exact question was answered for you yesterday. Please check your posts for an answer before reposting. I have pasted below the answer to this post. calculus - drwls, Monday, January 24, 2011 at 11:39pm Rewrite it as an equation for y in terms of x. y - 0.5 x = y This ...
*January 25, 2011*

**Calculus**

This is calculus? h(x)= x^3-x^2+x+6 h(-8) Plug -8 in for x and do the math.
*January 25, 2011*

**Intermediate Accounting**

Your question isn't clear. Calculate what? Do you need to calculate the portion of insurance that is a current expense for the year 2011 and the portion that is a prepaid expense or prepaid asset? 4000/2 = 2000. = 1 year expense 2000./12 = monthly expense for 1 year Jan ...
*January 25, 2011*

**math in topics**

"how many new are needed on campus" ... How many new ? New what? The answers don't make sense for the question asked. Re-read your whole post for clarity.
*January 25, 2011*

**fraction**

2/3 0f 9 Multiply 2/3 x 9 = 18/3 = 6 1/6 x 12 = ?
*January 24, 2011*

**CP Geometry**

I knew if was a riddle. That's why I asked "What" ! :)thanks
*January 24, 2011*

**CP Geometry**

(sqrt5) * (sqrt15)= (sqrt75)= =(sqrt25)(sqrt3)= 5(sqrt3) What do you call it when the nurse gives you a shot you hardly feel? What?
*January 24, 2011*

**latin**

BElimicus, testanmento When you are about to have heard, so much so astounded by was, when ninil could reply, without prejudice to these things, laughing, he added. From Google translator
*January 24, 2011*

**Algebra **

This is something you will have to do. Because of formatting, it is not possible to graph here.
*January 24, 2011*

**alegebra**

5 x -4 x 6 = -120 Product means to multiply the numbers.
*January 24, 2011*

**Math**

Do you have an equation for line h? If you do, post it here. It is needed to find the equation of line f.
*January 24, 2011*

**Math**

Do you have an equation for line h? If you do, post it here. It is needed to find the equation of line g.
*January 24, 2011*

**Math**

You are welcome!
*January 24, 2011*

**Math**

Plot the point(s) on a graph to see which quadrant it is in. Or, you can memorize this. For example, Quadrant I, the points are all positive, ie, (x,y). In Quadrant II, the points would be of the form (-x,y) Quadrant III, (-x,-y) Quadrant IV, (x,-y)
*January 24, 2011*

**Pre algebra**

44 ft/sec x 60 sec = 2640 ft/min 2640 ft/min x 60 mi/hr = 158,400 ft/hr 158,400 ft/hr / 5280 ft/mi = 30 mph
*January 24, 2011*

**math**

A = Art, B = Ben In 5 years art will be twice as old as ben. A + 5 = 2(B + 5) 5 years ago art was 3 times as old as ben. A - 5 = 3(B - 5) A + 5 = 2(B + 5) A + 5 = 2B + 10 A = 2B + 5 Substitute, A = 2B + 5, in A - 5 = 3(B - 5) 2B + 5 - 5 = 3(B - 5) 2B = 3B - 15 B = 15 Ben is 15...
*January 24, 2011*

**math**

You're welcome!
*January 24, 2011*

**math**

John sets off 4 seconds after Tom does, and finishes the lap 2.5 seconds sooner than Tom does. So, John's total time will be 6.5 sec less than Tom's time. Do you understand? Also, If you solved correctly, R = 20 and T = 32.5. Remember, the problem wants each racers'...
*January 24, 2011*

**math**

RT = D T = time for Tom T - 6.5 = time for John (-4s + -2.5s) R = rate for Tom R + 5 = rate for John D = 650 RT = D RT = 650 (R + 5)(T - 6.5) = 650 Solve these equations simultaneously. Expand (R + 5)(T - 6.5) = 650 Then substitute, RT = 650 for RT in the expansion.
*January 24, 2011*

**Math**

correct :)
*January 24, 2011*

**Math**

If two non vertical lines are parallel, their slopes are equal. Can you answer now?
*January 24, 2011*

**Calculus**

I forgot the very first line, where I rewrote the integral sin^3 x/cosx dx=|(sin^2 x sin x)/cos x dx sin^3 x/cos x dx = |sin^2 x tan x dx see above
*January 24, 2011*

**Calculus**

sin^3 x/cosx dx | = integral sign |sin^2 x tan x dx |(1 - cos^2 x)tan x dx |tan x - cos^2 x tan x dx |tan x - cos^2 x (sin x/cos x) dx |tan x - sin x cos x dx |tan x dx - |sin x cos x dx ln (sec x) - |sin x cos x dx u = cos x du = sin x dx ln (sec x) - |u du ln |sec x| - 1/2 u...
*January 24, 2011*

**math**

If I understand your poorly worded problem. w = width w + 3 = length P > 24 P = 2w + 2L 2w + 2(w + 3) > 24 Solve for w, the width
*January 24, 2011*