Friday

February 12, 2016
Total # Posts: 1,755

**math**

(6x^2-3x-9)-(2x^2+8x+3) Remove parentheses and change the sign of the terms inside the parenthese Combine like terms 6x^2 - 3x - 9 - 2x^2 -8x - 3 I leave the rest to you
*January 27, 2011*

**algebra**

Add the two 3x^2 + 7x - 3 + 5x + 2 = ?
*January 27, 2011*

**Geometry**

Correct
*January 27, 2011*

**algebra**

2z^2 IS 2z^2 or 2*z*z
*January 27, 2011*

**Math**

The time x cannot be negative. You must have made a mistake. The two equations are, distance gone by car = 64x distance gone by truck = 56(x+1/4) Since the distances are equal, 64x = 56(x + 1/4) 64x = 56x + 56/4 64x = 56x + 14 8x = 14 x = 1.75 From above (Reiny's ...
*January 27, 2011*

**math**

If P1(x1,y1) and P2 (x2,y2) are two points on a line, the number m defined by the equation Slope m = (y2 - y1)/(x2 - x1) is called the slope of the line.
*January 27, 2011*

**math**

3.4 + (5x - 1.7) plug 2.2 in for x 3.4 + 5(2.2) - 1.7 3.4 + 11.0 - 1.7 You can take it from here
*January 27, 2011*

**MATH**

Slope-intercept form y = mx + b m = slope b = y-intercept 5X - 2Y = -10 2y = 5x + 10 y = 5/2 x + 5 Slope m = 5/3 y-intercept b = 5
*January 27, 2011*

**Pre-Algebra Math**

$1167 ttl value of bills $147 ttl value of other bills $1020 value of tens and twenties n = number of tens and twenties 10n = ttl value of tens 20n = ttl value of twenties 10n + 20n = 1020 Solve for n, number of tens and twenties (equal number of both)
*January 27, 2011*

**Algebra**

2x + 5y = 4 Add -2x to both sides 5y = -2x + 4 divide both sides by 5 y = -2/5 y + 4/5 So, slope m = -2/5 Perpendicular lines, the slopes are negative reciprocals of each other. Slope = -2/5 m1 * m2 = -1 -2/5 * m2 = -1 m2 = -1/(-2/5) m2 = 5/2 Now you have to find b, for the ...
*January 27, 2011*

**Math**

I'm not sure what your question is ? 1 mile = 5280 feet 2 miles = 2 * 5280 ft = ? feet You can do the multiplication
*January 27, 2011*

**math**

Perimeter ABCD = 54 L = 12 in Perimeter LMNO = x L = 2.4 ft = 28.8 in P = 2w + 2L Use Ratio to find x (perimeter LMNO) 12/28.8 = 54/x Cross multiply 12x = 1555.2 x = 129.6 LMNO P = 129.6 L = 28.8 P = 2w + 2L 129.6 = 2w + 2(28.8) Solve for w, width of LMNO
*January 27, 2011*

**Calc.**

After all that, I confused myself and did the wrong problem I think. IF your problem is |x cos(x^2) dx just like your 2nd reply says, ignore the above. I wrote down | x cos (x^2) but integrated | x cos^2 x dx So, your very first post IS correct if it is cos x^2 and not cos^2 x...
*January 27, 2011*

**Calc.**

| x cos(x^2) dx The first line should be | x cos^2 x I forgot to change it.
*January 27, 2011*

**Calc.**

| x cos(x^2) dx | = integral symbol By half-angle cos^2 x = 1/2 (1 + cos 2x) | x 1/2 (1 + cos 2x) dx 1/2 | x + x cos 2x dx 1/2 | x dx + 1/2 | x cos 2x dx 1/4 x^2 + 1/2 | x cos 2x dx Integrate | x cos 2x dx by Integration by Parts u = x, dv = cos 2x dx du = dx, v = 1/2 sin 2x 1...
*January 27, 2011*

**Calc.**

S b= sqrt(Pi) a= 0 xcos(x^2)dx What is "S b = sqrt(Pi) a= 0" What are you integrating? Is it this? x cos(x^2) dx ? from a = 0 to b = (sqrt(pi))?
*January 27, 2011*

**Bobpursely**

Thank you, drwls!
*January 27, 2011*

**Bobpursely**

FYI-Many questions are under the name "Anonymous". If you expect a particular tutor to help you, you need to be more specific.
*January 27, 2011*

**Help**

sorry about the typo!
*January 27, 2011*

**Help**

Yes, x = 3 See your 1st post. I had a typo, and corrected it below.
*January 27, 2011*

**Help**

This problem was solved below for you. How many tutors do you need to solve this for you?
*January 27, 2011*

**college algebra**

1500sqrt(2)+1450 unless you use the value of (sqrt(2)), these two expressions cannot be added.
*January 27, 2011*

**Math**

Ignore above. I thought it was 3x = 1, not 3x - 8 = 1 x = 3
*January 27, 2011*

**Math**

Correct!
*January 27, 2011*

**Math**

(cubed root 3x-8)-1=0 Take the cube rt of both sides 3x - 1 = 0 3x = ? I'll leave this for you to finish
*January 27, 2011*

**Math correct or not**

Not correct
*January 27, 2011*

**Math**

Are you asking for the area of this box? A = Lw A = 2 2/3 * 2 2/3 A = 8/3 * 8/3 A = 64/9 = 7 1/9 sq ft
*January 27, 2011*

**algebra**

s = 4x - 3 V = s^3 V = (4x - 3)^3 V = (4x - 3)^2 (4x - 3) I leave the multiplication to you.
*January 27, 2011*

**finance**

This question asks "from your personal experiences". Post your personal experiences and a tutor will offer comments.
*January 27, 2011*

**7th grade math: Pythagorean Thereom**

It could be, 9 + 40 = 49 a^2 + b^2 = 41^2 a + b = 49 Solving simultaneously a = 9, b = 40 or a = 40, b = 9 41^2 = 9^2 + 40^2 1681 = 81 + 1600 1681 = 1681
*January 27, 2011*

**7th grade math: Pythagorean Thereom**

Do you mean that the two unknown sides total 49, or all three sides total 49?
*January 27, 2011*

**Gym**

Going up, down, diagonal what? Adding, multiplying, etc to equal 24? What exactly does the problem state to do?
*January 27, 2011*

**trig**

Correct!
*January 27, 2011*

**Precalc**

No solutions exist
*January 27, 2011*

**Algebra 1**

2x + 5y = 4 Add -2x to both sides 5y = -2x + 4 divide both sides by 5 y = -2/5 y + 4/5 So, slope m = -2/5 Perpendicular lines, the slopes are negative reciprocals of each other. Slope = -2/5 m1 * m2 = -1 -2/5 * m2 = -1 m2 = -1/(-2/5) m2 = 5/2 Now you have to find b, for the ...
*January 27, 2011*

**algebra**

R = 221.19x - 0.2x^2 R = 221.19 (273) - 0.2(273)^2 R = 221.19 (273) - 0.2(74,529) R = ?
*January 27, 2011*

**Math **

To understand this you really need to sketch this out. Think of the x/y axis on a graph, with the y-axis as North and the x-axis as East. Both boats are traveling from the North (top of the y-axis), toward East (down toward the x-axis). The first bearing, forms a 47 deg. angle...
*January 27, 2011*

**Exponents**

Meant to comment, If you square x^-2, x^-2 * x^-2 = x-4 = 1/x^4 1/^4 = 81 square root of both sides 1/x^2 = 9 You are back to the above.
*January 27, 2011*

**Exponents**

x^(-2) = 9 Since, x^(-2) = 1/x^2 1/x^2 = 9 Multiply both sides by x^2 1 = 9x^2 1/9 = x^2 square root of both sides + - 1/3 = x
*January 27, 2011*

**Math EASY**

Like Ms. Sue said. I just did this based on info you provided.
*January 27, 2011*

**Math EASY**

(83 + 3/5 + 5/5)/3 (83 + 60 + 100) = 243/3 = 81 81%
*January 27, 2011*

**adult education-Psycology?**

If you would like help in a timely manner please follow directions and put your school subject in the "School Subject" box.
*January 27, 2011*

**MATH**

If I am picturing this correctly, a right triangle is formed, with the hypotenuse c = 75 cm. Since the top of the wall is 5.4 m above ground, 5.4 - side a = height above ground to the roof edge. Angle A = 180 - (23 + 90) = 82 degrees sin 82 = op/hyp = a/c = a/75 0.9903 = a/75 ...
*January 27, 2011*

**arithmetic**

5/6 * 4 Since 4 = 4/1, you multiply the numerator of 5/6 times 4, and the denominator of 5/6 * 1 5/6 * 4/1 = 20/6 = 10/3
*January 27, 2011*

**5th math**

x = number of boys x + 4 = number of girls x + x + 4 = 30 2x + 4 = 30 2x = 26 x = 13 x = number of boys = 13 x + 4 = number of girls = 13 + 4 = 17 13 boys + 17 girls = 30
*January 27, 2011*

**5th grade**

Pat, I read that wrong. 77/35 * 285 = ?
*January 26, 2011*

**5th grade**

All that info and all the problem wants is the cost for 285? .77 each x 285 = ?
*January 26, 2011*

**5th math**

w = width, L = length Perimeter = 2w + 2L 60 = 2w + 2L 60 = 2(w + L) Divide both sides by 2 30 = w + L Since a square has equal sides and w + L = 30 15 + 15 = 30 So each side is 15 15 + 15 + 15 + 15 = 60 I don't know if a 5th grader does this type of problem like I did. If...
*January 26, 2011*

**Algebra 1**

2x + 5y = 4 Add -2x to both sides 5y = -2x + 4 divide both sides by 5 y = -2/5 y + 4/5 So, slope m = -2/5 Perpendicular lines, the slopes are negative reciprocals of each other. Slope = -2/5 m1 * m2 = -1 -2/5 * m2 = -1 m2 = -1/(-2/5) m2 = 5/2 Now you have to find b, for the ...
*January 26, 2011*

**Algebra 1**

Did you see the answer to your post below? Post your work so I can see where you are having trouble.
*January 26, 2011*

**5th math**

Mean is the average ADD the number of letters and divide by the number of numbers. 105 + 97 + 88 + 86 = sum Average = sum/4
*January 26, 2011*

**5th math **

28.5 min for 4 miles 28.5 min/4 mi = 7.125 min each mile So, this is your equation 4k = 28.5 k = 28.5/4
*January 26, 2011*

**algebra**

-4x - 12 = 0 Add 12 to both sides -4x - 12 + 12 = 0 + 12 -4x = 12 Divide both sides by -4 x = ?
*January 26, 2011*

**Algebra 1**

x + 6 = length of sidewalk x + 4 = width of sidewalk A = Lw A = (x + 6)(x + 4) (x + 6)(x + 4) = 39 Expand and solve for x
*January 26, 2011*

**pre algebra-math**

helper - please choose another 'Name' I've been using this name and it is very confusing when you use the same name. Thank you so much. Just put a number next to the name, if you want to use 'helper'.
*January 26, 2011*

**pre algebra-math**

yes^ please help 18/12 and 3/27
*January 26, 2011*

**...**

you mean 18/12 then the other question is 3/27!!!
*January 26, 2011*

**Algebra 1**

(6,7);6x+y=9. y = mx + b 6x + y = 9 y = -6x + 9 m = -6 m1*m2 = -1 -6*m2 = -1 m2 = 1/6 So, the slope of the perpendicular line is 1/6. y = 1/6 x + b Now find b with point (6,7). y = 1/6 x + b 7 = 1/6 (6) + b 7 = 6/6 + b 7 = 1 + b b = 6 y = 1/6 x + b y = 1/6 x + 6
*January 26, 2011*

**Algebra 1**

Your equation is not complete. 6x + = 9?
*January 26, 2011*

**ALGEBRA**

V = e^3 (e = edge) 64 = e^3 e = 4 Can you take it from here?
*January 26, 2011*

**Algebra**

Remaining angle = 180 - (55 + 47) Supplementary angles total 180 degrees You should be able to try this now.
*January 26, 2011*

** 7th grade math**

Area = ((b1 + b2)/2)* h 4 = ((b1 + b2)/2)* 1 4 = ((b1 + b2)/2) Multiply both sides by 2 8 = b1 + b2 So, the sum of base1 and base2 = 8 I don't know what you mean by 'best numbers'?
*January 26, 2011*

**Algebra**

Find the mean (average) 1 + 2 + 4 + 5 + 6 + 8 + 9 + 10 + 10 = sum Average = sum/9 The median is the middle value, 6 mean - median = postive difference Then express this difference as a fraction
*January 26, 2011*

**Pre Calc**

If I am understanding this picture, a right triangle is formed with angle A = 50 degrees and side b = 23 (15 + 8). You need the length of a, which is the streetlamp. tan A = opp/adj = a/b = a/23 tan 50 = a/23 1.19 = a/23 Solve for a, for your answer
*January 26, 2011*

**math**

x = one angle 2x = largest angle 1/3 x = smallest angle x + 2x + 1/3 x = 180 Solve for x
*January 26, 2011*

**Reading APE**

Did you read this? Tell us what you think and someone will proof your answer.
*January 26, 2011*

**algbra**

You need more parentheses in your problem. t = (r + k)/(2w)? t = r + (k/(2w)) ? t = r + (k/2) w ? Or?
*January 26, 2011*

**Algebra**

Answer is 2a^(-4)c^4 a^6/a^10 = a^(6-10) = a^-4
*January 26, 2011*

**Precalc**

You're welcome!
*January 26, 2011*

**Precalc**

solve 5(2^(3x)) = 8 5(2^(3x)) = 8 2^3x = 8/5 2^3x = 1.6 take logarithms of both sides 3x log 2 = log 1.6 Divide both sides by 3 log 2 x = log 1.6/(3 log 2)
*January 26, 2011*

**Pre-Algebra**

2/3 m - 5 = n Multiply both sides by 3 2m - 15 = 3n 2m = 3n + 15 m = ?
*January 26, 2011*

**L Pre-Cal**

3x-5y+5=1 5x-2y+3z=0 7x-y+3z=0 Do you have a typo? 3x - 5y + 5? = 1 There is no z term in equation 1?
*January 26, 2011*

**pythagrean theorem**

Ms. Sue is correct. I get 12.5 too.
*January 26, 2011*

**math**

Convert a) through e) to addition expressions Change the sign to + and change the sign of the number to the opposite of what it is. a) -6 - 9 = -6 + (-9) b) -10 - (-12) = -10 + 12 Now you do c), d) and e)
*January 26, 2011*

**math**

m = (-1-3)/(2-(-4) You had 3, should be 2
*January 26, 2011*

**math**

A(-4,3) and B(2,-1) If you have points A(x1,y1) and B(x2,y2) Slope m = (y2 - y1)/(x2 - x1)
*January 26, 2011*

**Math**

V = lwh Divide both sides by lh w = V/lh
*January 26, 2011*

**math**

Assuming simple interest, I = PRT Interest = Principal x Rate x Time 525 = 3500(.06)T 525 = 210T T = ? years
*January 26, 2011*

**ALGEBRA/PLEASE HELP**

LCM = (1 - 2t)(1 + 2t)
*January 26, 2011*

**Algebra 1**

Put the line in slope-intercept form, y = mx + b m = slope, b = y-intercept
*January 26, 2011*

**Math**

r = 2s - 8 2s = r + 8 s = 1/2 r + 4
*January 26, 2011*

**geometry **

Without seeing the diagram, not enough info. You would have to give a description that would allow for the tutor to understand where exactly this cord is, among other things. Could you solve this problem if all you knew was the info you posted? Think about that when posting a ...
*January 26, 2011*

**math**

x = amount for 3 2/5 x = amount for 2 5(2/5 x) = amount for 1 x + 2/5 x + 5(2/5 x) = 102,000 Solve for x
*January 26, 2011*

**algebra2**

Yes, b is the missing variable. But 3a^2b^2x still does not = 6a^2b^2x 6a^2b^2x = 6a^2b^2x
*January 26, 2011*

**math**

Find the inverse of f and see if it is g.
*January 26, 2011*

**Math**

Then post your answer, and ask for the answer to be checked. Less work for the tutor's, to type "yes" or "no", then to type out how the problem is done.
*January 26, 2011*

**Math**

Can you do any of these type problems? Post your work where you are stuck and someone will help. Tutors will not do your homework.
*January 26, 2011*

**math**

See the 1st link below under Related Questions. This exact problem was answered.
*January 26, 2011*

**algebra**

a4b + a5b + 3 What factors do all expressions have in common? Answer, none This cannot be factored. All you could do is, a4b + a5b + 3 ab (4 + 5) + 3
*January 26, 2011*

**algebra**

and the cost is 55.00 labor is 4.00 ? How about some periods or commas. Sometimes, if tutors cannot make out your post, they move on to one that they can understand.
*January 26, 2011*

**Algebra 1**

(6,7);9x+y=6 Put in y = mx + b form 9x + y = 6 y = -9x + 6 So slope m = -9 Perpendicular lines have slopes that are negative reciprocals of each other. Meaning, m1 x m2 = -1 m1 = -9 -9 x m2 = -1 m2 = 1/9 So, the slope of the line will be 1/9 y = 1/9 x + b To find b, P(6,7) y...
*January 26, 2011*

**Algebra 1**

Do you need a line parallel to 9x + y = 6? Or? I'm happy you understand!! Good work.
*January 26, 2011*

**Algebra 1**

(-8,6); 2x = 3y + 4 3y = 2x - 4 y =(2/3)x - 4/3 So, slope m = 2/3 Use y = mx + b and P(-8,6) to find the equation parallel You know m = 2/3, so you have to find b. y = 2/3 x + b Put in x any y values and solve for b. 6 = 2/3 (-8) + b See how my equation is different than yours...
*January 26, 2011*

**Algebra 1**

Esther, see your post below at 3:11pm that I answered. I gave you detailed instructions on how to do this almost exact problem. You will never learn without attempting the problem yourself. Post all your work if your are stuck.
*January 26, 2011*

**algebra2**

Correct, (x - 3)(x + 5)
*January 26, 2011*

**algebra2**

x(x-3) + 5(x-3) What factors do both expressions have in common? Answer, (x-3) Can you factor now?
*January 26, 2011*

**algebra2**

Correct!!
*January 26, 2011*

**algebra2**

15Rx - 3Rex What factors do the two expressions have in common? Answer, 3Rx. Can you factor now?
*January 26, 2011*

**geometry**

Your question makes no sense. Please post the question exactly as it appears from your homework. If the side = 140 in., that is the length of that side. There is nothing to calculate for that side.
*January 26, 2011*

**math**

Your question is unclear. A can of lemonade concentrate has a capacity of 355 mL. Does this mean that the can of concentrate makes 355mL of lemonade ? Or, do you mean that 355mL combined with 4 cans of water, for the total amount of lemonade? If the second, without knowing the...
*January 26, 2011*