# Posts by Hebe

Total # Posts: 3

**Calculus-check my answers please**

dy/dx= (y^2 -1)/x 1. Give the general equation of the curves that satisfy this equation. 2. Show that the straight lines y=1 and y=-1 are also solutions 3. Do any of the curves you found in 1) intersect y=1? My Ans: 1. The general solution i found out to be x^2 + C = (y-1)/(y+...

*November 7, 2006*

**Calculus**

dy/dx= (y^2 -1)/x 1. Give the general equation of the curves that satisfy this equation. 2. Show that the straight lines y=1 and y=-1 are also solutions. 3. Do any of the curves you found in 1) intersect y=1? i started by dy/(y^2 -1)= dx/x and found that [ln(y-1) - ln(y+1)]/2...

*November 4, 2006*

**Calc.**

Find the area of the region bounded by the parabola y=x^2, the tangent line to this parabola at (1,1) and the x-axis. I don't really get what this question is asking. It looks like the area of right triangle to me...try the graph, and shade the area under the tangent. Find...

*September 26, 2006*

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