Chemistry
Diamond tips are used because they are harder than most materials we would drill into. Diamond is the hardest material, with the possible exception of some forms of boron nitride.
Chemistry
*10 moles of Na2SO4 is 3*10=30 moles of particles. *Convert 0.500 kg H2O to moles. *Total moles = 30 + moles of H2O *Mole fraction of H2O = X(H2O) = (moles H2O) / Total moles. *Look up the vapor pressure of H2O at 30ºC = P(H2O) *Vapor pressure of solution = [X(H2O)]*[P(H...
chemistry
There IS, the cubic meter, m^3. The basic SI units in the "MKS" system are the meter, the kilogram, and the second. Derived units such as those for volume, velocity, force, energy, etc, are "SI" as long as they are based on the basic SI units. Example: The ...
Chemistry
It could a number of things only known to your teacher and/or the author of the printed instructions for the lab. It sounds like an experiment to determine the density of a material. When you measure the mass and the volume of an object, you have the data needed to calculate i...
Chemistry
1. We identify substances from their physical and chemical properties. 2. If we know the density of a substance, we can calculate the mass of a sample from the volume or the volume from the mass. 3. The density of a substance is taken into account in determining how that subst...
Biochemistry
500.00g / 89 g/mol = 5.62 moles 1 mole = 1000 millimoles (5.62 moles)(1000 mmol/mole) 5620 millimoles. Are you sure the mass is 500.0 grams? Could it me milligrams?
Chemistry
Moles of Ti = 3.0g / 47.87g/mol = 0.0627 moles Ti 8.0g Cl2 / 70.9g/mol = 0.113 mol Cl2 Available ratio: (0.113 mol Cl2) / (0.0627 moles Ti) = 1.80 mol Cl2 / 1mole Ti Needed Ratio: The Cl2 / Ti mole ratio in the balanced chemical equation = 2 mol Cl2 / 1 mol Ti The comparison ...
Chemistry
The reaction is: C7H8 + Br2 --> C7H7Br + HBr Find the molar masses of C7H8 and of C7H7Br The theoretical yield is: (1.5g C7H8)(mol.mass C7H7Br / mol.mass C7H8)
chemistry
Unsaturated fats (oils) contain one or more double bonds that are chemically active. That makes them vulnerable to oxidation and to breaking of the long fatty acid chain at the double bond into shorter fatty acid chains. What does this tell you about the relative stability of ...
Chemistry!
1. Yes 2. Yes
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