Saturday

October 25, 2014

October 25, 2014

Total # Posts: 108

**math**

u = 2d or u - 2d = 0 u + d = 5 so the matrix would be 1 -2 0 1 1 5 add -1 times the 1st row to the 2nd row. Then you get 1 -2 0 0 3 5 multiply the 2nd row by 1/3: 1 -2 0 0 1 5/3 The 2nd row tells us that d = 5/3, so u = 10/3
*March 16, 2010*

**Math**

A+B = 60 (1) A/3 = B/2 A = 3B/2 (2) combine (1) and (2) 3B/2+B = 60 3B/2+2B/2 = 60 5B/2 = 60 B = 24 A = 36
*March 15, 2010*

**math**

x = original # of pieces w = gave to wife = 10x/100 m = gave to meg = 3 (x-w-m)/4 = j = gave to joe 18 = x - w - m - j combine and solve for x
*March 11, 2010*

**TRIG MATH**

sin = opposite / hypotenuse so, hypotenuse = 8 opposite leg = 7 adjacent leg = sqrt(8^2 - 7^2) = sqrt(15) 1/cot = tan tan = opposite / adjacent = 7/sqrt(15) in the 4th quadrant the tangent is negative, so add a minus sign: 1/cot(theta) = -7/sqrt(15)
*March 11, 2010*

**grade 12 trig**

cos(A) -1 = 0 or cos(A) = 1 arccos(1) = A = 0
*March 11, 2010*

**Precalculus**

distance = velocity x time or time = distance / velocity total time=d1/v1+d2/v2=2.5 hrs (1) where d1 = car distance = 30 (2) v1 = car speed d2 = train distance = 120 - d1 (3) v2 = train velocity = v1+20 (4) combine (1), (2), (3), and (4) and solve for v1
*March 11, 2010*

**geometry**

It doesn't seem like there is enough information to determine the answer
*March 11, 2010*

**physics**

a)centripetal acceleration is v^2/r. In this case, v is 30 mi/hr and r = 200 ft. The inertial force would be: F = ma = mv^2/r (1) This would be the friction force required to keep the car on its path. b) The static friction is: F = uN (2) where u is the static friction ...
*March 11, 2010*

**calculus/physics**

Assuming an ideal spring (linear) and using Hooke's law, the force generated by the spring is: F = -kx (1) where x is the distance the spring is stretched from the rest position. So, substituting the info into (1) you get: -10 = -k(2) or k = 5 lb/in work is the 1st ...
*March 11, 2010*

**math**

if you bisect one of the angles, you have a right triangle with a hypotenuse of 1 cm and a short leg of 0.5 cm. Using the Pythagorean theorem, the height would be: height = square root (1^2 - 0.5^2)
*March 11, 2010*

**Math**

Oops. Thanks for the correction.
*March 11, 2010*

**Math**

let the 3 dimensions be a, b, and c where a and b are the bottom edges and c is the height. v is the volume s is the surface area a = 7b v = abc = 7b^2c or rearranging, c = v/7b^2 s = ab + 2ac + 2bc = 7b^2 + 14bc + 2bc = 7b^2 + 16bc = 7b^2 + 16bv/7b^2 = 7b^2 + (v16/7)/b set ...
*March 11, 2010*

**Math**

From 1920 to 1980 is 60 years. The record was shortened by 1.2 seconds. The slope of the line is the rise over the run, or: -1.2/60 for t=0, R(t) = 46.6 so the y intercept is 46.6. The format of a line is y = mx + b where m is the slope and b is the y intercept. So, a) so the ...
*March 11, 2010*

**Math**

rearranging the given line, y = (9/5)x - 4/5 (1) which has the form y = mx + b (2) where m is the slope and b is the y intercept. The new line would have the same slope to be parallel, so it would have the form: y = (9/5)x + b (3) to solve for b, input the given coordinates, ...
*March 11, 2010*

**Math(Please check)**

It doesn't look right to me sec Q - 1/sec Q = 1/cos - cos = 1/cos - cos^2/cos = (1-cos^2)/cos = sin^2/cos
*March 11, 2010*

**Geometry**

using the Pythagorean theorem, opposite side = sqrt(13^2-12^2) sin x = opposite side / 13 tan x = opposite side / 12
*March 11, 2010*

**Physics**

Newton's law of gravitation: F = G m1 m2 /r^2 let m2 = mass of ice cube and s = G m1/r^2 so, F = s m2 rearranging, s = m2/F let V = orbital speed centripetal acceleration = V^2/r For an object to remain in orbit s must equal the centripetal acceleration so, s = V^2/r
*March 10, 2010*

**statistics**

12.60 - 23.00 = A A / -1.30 = standard deviation
*March 10, 2010*

**math **

if you are traveling along the leg of the star, the deflection angle is the angle you have to turn to get to the next leg. d = deflection angle at a point = 180 - 12 = 168 since there are points, the total point deflection angle at the points is 1680. x = dent angle = 180+y y...
*March 10, 2010*

**calculus**

It could be interpreted as the azimuth, which in surveying applications is typically measured in a clockwise direction from north.
*March 10, 2010*

**calculus**

180+arctan(12/-5) = 112.6
*March 10, 2010*

**rotations**

a = angular acceleration I = rotational inertia w = angular velocity v = linear velocity Torque = RxFT = Ia so, a = RxFT/I = (R/I)(4t-0.10t^2) w = integral(a) with respect to t v= wR
*March 10, 2010*

**Algebra 2**

It looks right to me. The easiest way to check is to plug the number back into the formula: e^.6931 = 2 2*2-3 = 4-3 = 1
*March 10, 2010*

**algebra**

Permutations of 9 objects taken 5 at a time = 9!/(9-5)! where 4! = 4x3x2x1 and 9! = 9x8x7x6x5x4x3x2x1
*March 10, 2010*

**ALGEBRA**

yes, it could be. You just need to change the sign, so you would have 8-y over y-4 PLUS 7y-9 over y-4
*March 10, 2010*

**college**

dist from station to trains = D ta = time in hours from when A passes station to when trains A & B meet. D = 80ta D = 88(ta-15/60) solve for ta Time at catch-up = 1:20 AM + ta
*March 10, 2010*

**psychology**

NO. 500 = A - A x 0.28 = A (1-.28) = .72A so, A = 500/0.72 = 694
*March 10, 2010*

**trig 30**

csc=1/sin cot=cos/sin so, csc^2-1/cotcsc = ((1/sin^2)-1)sin/(cos/sin) = sin((sin/sin^2)-sin)/(cos) = (sin^2/sin^2-sin^2)/cos = (1-sin^2)/cos = cos^2/cos = cos A ((sin^2/sin^2)-sin/(sin^2 cos)
*March 10, 2010*

**Pre-Cal**

1) it is not correct. The second term would be log3(-2) and you can't take the log of a negative number. 2) it is not correct. The base angle would be 45 degrees, so the cotangent would be 1.
*March 10, 2010*

**trig **

9cos^2(t)+3cos(t)=0 subtract 3cos(t) from both sides 9cos^2(t)=-3cos(t) divide both sides by 3cos(t) 3cos(t)=-1 cos(t)=-1/3 t=arccos(-1/3)
*March 10, 2010*

**Math 157**

# of ways of selecting winning quintuple = permutations of 5 objects = 5! = 5 x 4 x 3 x 2 x 1 probability of winning = n!/(r!(n-r)!) = 44!/(5!39!)
*March 10, 2010*

**math**

x = original # of tickets y = original price you have 2 equations: xy = 180 (x-2)(y+9)=180+36 substitute equation 1 into 2 and solve.
*March 10, 2010*

**math**

16-15.2 = 0.8 0.8/0.03 = n = 26 standard deviations so, erf(n/sqrt(2)) = approximately 1 so, 50% of the data would be between 15.2 and 16.
*March 10, 2010*

**calculus**

The formulas given look like they are for sinusoids and not circles.
*March 10, 2010*

**Maths**

the graph of y=sin(theta) is moved vertically along the y axis a distance of q to obtain y=sin(theta)+q.
*March 10, 2010*

**math**

= (y/3)(y^2+5y+6) = (y/3)(y+2)(y+3)
*March 10, 2010*

**Algebra**

= (18+4)r^2 +7s = 22r^2+7s
*March 10, 2010*

**math**

for example, for x = 2, y = 0 x = 3, y = -1/3 x = 4, y = -2/3 x = 5, y = -1
*March 9, 2010*

**math**

A = amt invested at 8.5% B = amt invested at 10% A + B = 50000 or A = 50000 - B income = 0.085A + 0.10B = 4700 substitute A in terms of B and solve
*March 9, 2010*

**Algebra II**

c = # of chest freezers u = # of upright freezers c+u>=100 or u >= 100-c assume a total of 100 units cost = 250c + 400u = 250c +400(100-c) = 250c + 40000 - 400c = 40000 - 150c = 800 - 3c so obviously the more type c units, the lower the total cost. profit = 40c + 60u >...
*March 9, 2010*

**Geometry**

cos(x)=15/17 so x = arccos(15/17) tan(76) = 13/x so x = 13/tan(76)
*March 9, 2010*

**maths**

dmA/dt = cmB^2/mA where c is a constant mB=m-mA so dmA/dt = c (m-mA)^2/mA = (c/mA)(mA^2-2mmA+m^2) = cmA-2cm+cm^2/mA integrate with respect to t
*March 9, 2010*

**trignometry**

sin(a+b)/cos(a)cos(b) = = (sin(a)cos(b)+cos(a)sin(b))/cos(a)cos(b) = sin(a)cos(b)/(cos(a)cos(b) + cos(a)sin(b)/(cos(a)cos(b) = sin(a)/cos(a) + sin(b)/cos(b) = tan(a) + tan(b)
*March 9, 2010*

**math**

It would take 10 minutes.
*March 9, 2010*

**chemistry**

Moles of solute = 16 g / 60 g/M = = 0.267 M volume of H2O = 39g/1.3 g/ml = 30 ml = 0.03 l molarity = 0.267 M / 0.03 l = 8.89 M/l
*March 9, 2010*

**math**

the probability that the 1st marble is red is 10/13. So, the probability that both marbles are red is (10/13)^2 or (100/169)
*March 9, 2010*

**MATH214**

(a) 3y = x - 10 substitute in the 2nd equation 3(x-2) = x - 10 3x - 6 = x - 10 simplifing... 2x = -4 or x = -2 and y = -4 this is a unique solution (b) this system has infinitely many solutions and cannot be solved without more information. 3x + 3y = 15 divide equation by 3 (3...
*March 9, 2010*

**Calculus **

y = (x-2)^2 y = x^2-4x -4 dy = 2xdx - 4dx so, dy/dx = 2x-4 dx/dt = 2 so, dy/dt = dy/dx dx/dt = 2(2x-4) = 4x-8 for x=1 then dy/dt = 4(1)-8 = -4 units per second
*March 9, 2010*

**Calculus **

dx/dt = 2 inches/min V = x^3 so, dV/dt = 2^3 = 8 cubic inches/min
*March 9, 2010*

**intermediate algebra**

Area = A x B Total length = 3000 = A + 2B B = (3000-A)/2 so, Area = A x (3000-A)/2 = = 3000A/2 - (1/2)A^2 take 1st derivative 0 = 1500 - A and solve for A A = 1500 and B = 750
*March 8, 2010*

**Physics...not sure what formula to use**

mb = mass of bullet vb = velocity of bullet ma = mass of bag vab = velocity of bag and bullet from conservation of momentum: mb*vb = (ma + mb)*vab then from conservation of energy: (ma + mb)*vab^2/2 = (ma + mb)*g*h
*October 25, 2008*

**Geometry**

A: it depends how the cube is painted. If the 3 blue sides of the original cube share a common corner then 7 of the smaller cubes have at least 2 sides that are blue. If 2 opposite faces of the original cube are blue then 6 of the 27 have at least 2 faces that are blue. B: 19 ...
*October 25, 2008*

**math**

books = (2ft x 12in/1ft)/(0.75in/book)
*October 17, 2008*

**math**

sa = 4 x pi x r^2 so r = sqrt( sa/(4 x pi))
*October 16, 2008*

**Math**

2x^2-5x = x(2x-5) = 0 x = 0, 5/2
*October 16, 2008*

**Math**

There is no answer. x would have to be less than zero which is beyond the bounds where the equation is valid.
*October 16, 2008*

**ENGLISH**

If there are more than three authors you can use: Doe, Mary Jane, et al.
*October 16, 2008*

**math**

That is what I got also.
*October 16, 2008*

**physics**

centripetal acceleration = a = v^2/L Period = T = 2 x pi x L / v m = mass of stone tension = f = m x a L1 = L x 1.01 if f and m are constant, then a is constant. Then v1 = sqrt(a x L1) T1 = 2 x pi x L1/v1 percentage change = 100x(T1-T)/T
*October 16, 2008*

**math**

zero
*October 16, 2008*

**alg2**

function of x equals x minus the absolute value of x, where x is greater than zero.
*September 11, 2008*

**Science**

flooding, water pollution, and eutrophication can be a problem in either ocean or freshwater. Aquifer depletion, overdrawing surface water, and saltwater intrusion are freshwater problems.
*September 11, 2008*

**calculus**

the function is not continuous when the denominator is zero, or... 0 = x^2+1 solving for x then x = i It is a removable discontinuity since it can be repaired by replacing a single point.
*September 11, 2008*

**math**

0 = 4x^4-18x^2 = 4x^2(x^2-9/2) = 4x^2(x+sqrt(9/2))(x-sqrt(9/2))
*August 25, 2008*

**electronics**

connect your ipod to an FM transmitter
*August 25, 2008*

**Physics**

v0 = 20m/s D = dist from int. = 110 - v0 x 0.50 t0 = time to stop final velocity must equal zero... 0 = v0 - a x t0 t0 = v0/a D = v0 x t0 - a x t0^2/2 substitute for t0... D = v0^2/a - a x (v0/a)^2/2 solve for a...
*August 25, 2008*

**Econimics**

Profit = revenue - TC Revenue = [Price] x [tons of coal] Take the first derivative of profit with respect to Q and set this equal to zero, then solve for Q.
*August 25, 2008*

**accounting**

with a loan
*August 25, 2008*

**Physics**

two more equations are: m1+m2=M v2-v1=20m/s
*April 10, 2008*

**Science**

the formula for water is H2O. Therefore, two atoms of hydrogen are released for each atom of oxygen. You could test the gases by putting them in a balloon and seeing which one floats.
*April 10, 2008*

**Geometry**

circumference = pi*D = 10m, so D = 10m/pi = 3.183m radius = D/2 = 1.59m
*April 9, 2008*

**precal log**

4^(2x-5)=2^2*(2x-5) 8^(x-3)=2^3*(x-3) so 2(2x-5)=3(x-3) simplifying, 4x-10=3x-9 x=1
*April 9, 2008*

**chemistry**

1/2N2+3/2H2 => NH3 or 1/3N2+H2 => 2/3NH3 so 12*2/3 = 8 moles HN3
*April 9, 2008*

**Math**

More information is needed besides the mean to answer the question.
*April 9, 2008*

**trig**

to convert degrees to rad, multiply by pi and divide by 180.
*April 8, 2008*

**trig**

I'm not sure I understand what angle the 56.4 degrees represents, but assuming it is the difference in horizontal azimuth to the pillar from the 1st setup to the 2nd setup then solution is: If the distance to the pillar is "P" then: tan(56.4)=10/P or P=10/tan(56....
*April 8, 2008*

**trig**

The three angles of a triangle equal 180 degrees. The third angle is 80 degrees. Therefore, it is not a right triangle.
*April 8, 2008*

**trig**

sin(a)/cos(a)=tan(a) tan(a)*cos(a)=sin(a)*cos(a)/cos(a)=sin(a)
*April 8, 2008*

**trig**

if c is one of the legs of the triangle then it equals four. If it is the hypotenuse then it equals: c=sqrt(5^2+3^2)
*April 8, 2008*

**College Calculus (Binomial Series)**

Taylor series is as follows: f(x)=f(a)+f'(a)(x-a)/1!+f''(a)(x-a)^2/2!+f'''(a)(x-a)^3/3!+...
*April 8, 2008*

**Calc**

compound interest formula is: FV=PV(1+(r/n))^(nT) As n approaches infinity, this formula becomes: FV=PV*e^(rt) for the 1st $1000 invested: FV=1000*e^(.07*20) for the 2nd $1000 invested: FV=1000*e^(.07*19) and so on for 20 years. The sum total of future values minus $20,000 ...
*April 8, 2008*

**math**

z-score = (raw score - mean)/standard deviation
*April 8, 2008*

**SOCIAL STUDIES**

Frederick the Great
*April 8, 2008*

**Adv. Math**

Assuming compound interest with a period of 1 year, the annual rate would be 4.3%
*April 7, 2008*

**accounting**

"Record wages expense incurred and to be paid next month" Payable implies an expense you owe.
*April 7, 2008*

**accounting**

Cash 10,000 debit Brown, Equity 10,000 credit
*April 7, 2008*

**accounting**

Decrease in liabilities of $71,000
*April 7, 2008*

**Legal**

I believe an easement is correct.
*April 7, 2008*

**Geometry**

A line from the center of the curve to the midpoint of the chord is 8ft. If h=half of the chord length then 10^2=h^2+8^2, or h=sqrt(10^2-8^2) = 6 the chord length is 2*h or 12ft.
*April 7, 2008*

**Math**

Since the equation is for a line, you really only need two points. If you plug x=0 into the equation, the value of y is also zero. This gives you the first point (0,0). For x=1, y=k, so the second point is (0,k). The graph of the equation is a line passing through these two ...
*April 7, 2008*

**Math**

2x-4y+5=a so rearranging, -4y=a-2x-5 or y=-a/4+2x/4+5/4 The slope of this line is 2/4. A line normal to this would have a slope of minus the inverse, or -4/2, or -2. So the equation of normal line would be: y=-2x
*April 6, 2008*

**Geometry**

screen height = h screen width = w h = w*3/4 (1) 27 = sqrt(h^2+w^2) = sqrt((3w/4)^2+w^2) solve this equation for w calculate h from (1) movie width = screen width movie height = m m=w/2 darkened strip = (h-m)/2
*April 6, 2008*

**Algebra 2**

(x-h)^2/a^2+(y-k)^2/b^2=1 is the equation for an ellipse, where (h,k) is the center, a is the semimajor axis, and b is the semiminor axis.
*April 6, 2008*

**science**

If you take a sample of air in your neighborhood and compare the concentration of various contaminants with the maximum allowed values, the maximum allowed values would be the air quality standards. If you measure the output of various compounds from a piece of equipment, such...
*April 6, 2008*

**Math Algebra 2**

I got a maximum profit of $4200 with 40 pants and 80 shirts.
*April 6, 2008*

**Math Algebra 2**

human hrs = 160, or 2x+6y=160 machine hrs = 200, or 2x+9y=200 minimum of 15 pants, or y>=15 must make more shirts than pants, or x>=y the maximum profit is where the equation 25x+55y=profit has a local maximum. One way to determine this is using the 1st derivative and ...
*April 6, 2008*

**math**

a circle has 360 degrees or 2 pi radians, so: radians = 2.7*pi/180
*April 6, 2008*

**math**

Log10x = -7 is the same as 10^-7 = x or x = 0.0000001
*April 6, 2008*

**Math**

The problem asked for the ratio of length to width, with the length being the smaller of the two numbers. Therefore, the ratio would have to be less than one. If you are allowed to round off, then the nearest whole number ratio would be one. If you want to reduce the fraction ...
*April 6, 2008*