If f(x) = (e^(x))sin(x) what is the 1000th derivative? Step are needed and the general rule/pattern
Wrong. B. 67 hundredths means 0.67 which is 67%. The decimal places goes, tenths, hundredths, thousandths, ten thousandths, hundred thousandths, and so on.
I was wondering if you could help me with understanding how an infrared detector works. It is just a cheap one that comes with an emitter from Radioshack. I can't find any websites that tell me what I want to know. What makes the detector detect infrared? I just don't ...
To do this problem you just need to use a few simple equations: V = V0 + at X = X0 + V0*t + .5*a*(t^2) and V^2 = V0^2 + 2*a*(X - X0) where V0 equals the initial velocity X0 equals the initial height t equals the time a is just the acceleration (gravity in this case [9.81 m/s^2...
I am assuming that the 1-.06 is actually 1.06. Therefore... g(x) = 5 5 / 23 = .21739 log(.21739) = x * log(1.06) log(.21739) / log(1.06) = x = -26.18999 For the first problem: A = Pe^(rt) 800 = 500 * e^(0.085 * t) 800 / 500 = 1.6 1.6 = e^(0.085 * t) Because ln() cancels out e^...
Use factorials I think.
Youth Criminal Justice Act essay? Thesis: The YCJA should be strictly enforced, if it is to be successful. Give 4 possible body paragraph ideas!
The specific heat of a solution is X J/g*degreesC and its density is Y g/mL. The solution was formed by combining Z mL of solution A with Z mL of solution B, with each solution initially at J degreesC. The final temperature of the combined solutions is D. The heat capacity of ...
Question simplified: a) how do you get q of reaction if you have q of solution, b) how do you get q of reaction of you have q of calorimiter, c) how do you get q of solution if you have q of chemicals, d) in general, should q of chemicals equal q of solution, e) should q of ca...
If you have the q cal of a reaction, then obviously you can convert to q chem by negating your q cal. But what if you need to get to q rxn (q of the reaction)? Also, my textbook is claiming that the q rxn = -(q sol + q cal). How does that figure into this?
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