Friday
December 6, 2013

# Posts by Francesca

Total # Posts: 155

Discrete Math
Ok thank you for your helpful response! I have a couple of questions though. . . Is the 15th line suppose to be '(k+1)(k+2)/(22k+3)'? Also, the 16th line = RS, which is what exactly?

Discrete Math
Use mathematical induction to establish the following formula. n Σ i² / [(2i-1)(2i+1)] = n(n+1) / 2(2n+1) i=1 Thanks for any helpful replies :)

Discrete Math
Any suggestions?

Discrete Math
Any suggestions?

Discrete Math
Thank you so much for your response! But I have completed that particular question. However, can you please help with this one? I am confused. . . Use mathematical induction to establish the following formula. n Σ i² / [(2i-1)(2i+1)] = n(n+1) / 2(2n+1) i=1 Thanks for...

Discrete Math
Hello?

Discrete Math
Use mathematical induction to prove the truth of each of the following assertions for all n ≥1. n³ + 5n is divisible by 6 I really do not understand this to much. This is what I have so far: n = 1, 1³ - 5(1) = 6, which is divisible by 6 Then I really don't ...

Discrete Math
OK you gave me a lot to think about. . .Thank you so much for your help. Until next time (which may be tomorrow). Thanks again :)

Discrete Math
So, I worked out a couple. . . 1.) 4x ≡ 2(mod 6) x = 0, 4(0) - 2 = -2 is not divisible by 6 x = 1, 4(1) - 2 = 2 is not divisible by 6 x = 2, 4(2) - 2 = 6 is divisible by 6 x = 3, 4(3) - 2 = 10 is not divisible by 6 x = 4, 4(4) - 2 = 14 is not divisible by 6 x = 5, 4(5) -...

Discrete Math
So, once I reduce it to this:x≡80 (mod 148). Then I have to do the trial and error process? Idk, I get how you got 80, but how did get 228, 376, 524. . .I think I see a pattern though each are incremented by 148. Hmm. . .I have another example that I would like to share,...

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