Tuesday

July 22, 2014

July 22, 2014

Total # Posts: 195

**Engineering**

Anyone for the rest please?

**Engineering**

Q1_2_4= 300 mm^2

**Engineering**

In my case it was 500 guys, just try it.

**Engineering**

Anyone please?

**Physics**

Thanks it is omega got it Phy! Anyone for the rest please?

**Physics**

SyLaR it does not deliver right answer for d and f. does it mean 2* the answer of b and c? or maybe a bracket problem, could you check please?

**Physics**

I thought this is formula for d) d)U = (L*I^2)/2 ?

**Physics**

SyLaR no sorry, have not figured d) e and f) out. Could you tell me quick with values assocated with I and L?

**Physics**

Thanks BoobleGum and hmmmm b) worked now with BoobleGum's great explaination Hoever, still have problem with d. d)U = (L*I^2)/2 Here L is the length described as d? and I is the current described in question a)? The result comes wrong with that formula or the value I under...

**Physics**

BoobleGum if you have time, could you help with this one below please? b) L = mu_0*((N/L)^2)*V, V = (pi*R^2)*d Is V the epsilon value or calculated by V = (pi*R^2)*d? I put my values in but it does not give right answer. 1.25663706*10^-6*((2079/0.42)^2)*9 V = (pi*R^2)*d does d...

**Physics**

THanks BoobleGum, see you tomnorrow!

**Physics**

Booblegum thanks, I get a) but b) and d) not. b) L = mu_0*((N/L)^2)*V, V = (pi*R^2)*d Is V the epsilon value or calculated by V = (pi*R^2)*d? I put my values in but it does not give right answer. 1.25663706*10^-6*((2079/0.42)^2)*9 V = (pi*R^2)*d does d=length? d)U = (L*I^2)/2 ...

**Physics**

In b) mu_0*((N/L)^2)*V I don't know which value is L?

**Physics**

Booblegum, what is L value please? I cannot identify. thanks

**Physics**

THanks Booblegum, will try it out again and report back. Booblegum I did not try the first question out with the formula, this was mentioned by another one and I thought it works, just look at my profile under: Thanks lo, can you help with Problem 2? This were you can find wha...

**Physics**

a)B=meu_0*N*I/l b)L=meu_0*N^2*A//l c)I=V/R d)U=1/2(LI^2) I get only c) right could somebody help me with the values, mine is as following: A solenoid has N=2070.0 turns, length d=40 cm , and radius b= 0.2 cm. The solenoid is connected via a switch, S1, to an ideal voltage sour...

**Physics**

Booblegum, this was mentioned in another thread: d) t=-ln(0.25)*2*R*C could you help with question 2 a, b, c please as I think there is something wrong with the formula or I am making a mistake.

**Physics**

a), b) and d) I meant. Help appreciated

**Physics**

Only c) worked for me, I am surely making some wrong with a), c) and d). Did someone figure out with above formula please?

**Physics**

THanks hmmmm, r is the radius b=0.2 cm right?

**Physics**

Thanks guys, what is value A please?

**Physics**

Thanks guys, did somebody have formula for problem 1 and 2?

**Physics**

Can somebody tell me what the value of R is? thanks

**Physics**

Thanks hmmmmm for help!

**Physics**

Thanks bobpursley! The first problem does not give right answer, could you tell, if this is the right calculation as 10^22 and the formula was not right. 1400/6x10^24*pi*(6.37*10^6)^2/3*10^8 Is this formula above right?

**Physics**

TA I meant Problem 2 d) and e) not 1. Do you have them please?

**Physics**

Can you give me the formula then TA please for d) and e) please?

**Physics**

Sorry 03, I think Sylar meant the answer from c) and the capacitor value. I copy the message below: Ah, ok. For d)You have the inductance for answer 2b. And the time for 2c. So. The answer will be 2b*2c^2/2. And for 2f is sqrt(2c*capacitor)*pi/2 can you tell me the value for I...

**Physics**

03 this was mentioned by Slylar in another thread but did not work for me for f) problem 2: And for 2f is sqrt(2c*capacitor)*pi/2 do you have formula for problem 2) d) and e) please?

**Physics**

Thanks lo, can you help with Problem 2?

**Physics**

Phy, yes second problem. Unfortunately, I could also not get it. Does someone know the right formula please?

**Physics**

Many thanks Phy! Could you help with this please. This was provide by hmmmm and anonymous but only c) works for me. Did you get this: formula for question 2 a)B=meu_0*N*I/l b)L=meu_0*N^2*A//l c)I=V/R d)U=1/2(LI^2)

**Physics**

What value is U by the way?

**Physics**

Did somebody figure out problem after the first question please? I dont seem to get it with above formula.

**Physics**

Thanks regz and simonsay!

**Physics**

Simonsay, is that like this below? I have just tried it does not give right answer and says: Expression or statement is incomplete or incorrect. ANy help please and did someone manage? % Define the coefficient matrix a a = N_AB -1,1,-0.7071,0,0,0 N_BC 0,0,-0.7071,1,0,0 N_BE 0,...

**Physics**

Simonsay thanks. Something is wrong with the expression, could you please check? I don't get right answer.

**Physics**

Has somebody formula for HW4_2: Part I?

**Physics**

1_C:-4.05, -4.05,2.59,6.49 Anyone for HW4_2: Part I?

**Physics**

No problem X10, thanks for it anyway!

**Physics**

gggg, for question 1)f) B_0 what is it the formula? Could you give us the value, as the formula from X10 did not work for me. thanks!

**Physics**

Thanks X10, have same problem like P. I don't get it. is this the formula, my speed case value is:200500000 (8.85418782*10^-12)/(200500000) Is there a mistake with my E_0 value?

**Physics**

Got it X10 thanks vey much! can you maybe help with Problem 1) f) case 2? I cannot get the B_0 for case 2. A formula and the value, I would be greatful.

**Physics**

Meant value for b) X10 please?

**Physics**

MAny thanks X10! I dont sem to get the result. could you give ,e your value, so I can find an approximation for mine?

**Physics**

Anyone managed Problem 3) b) formula or value please?

**Physics**

For B_0 the formula seems to be : E_0/c However, I cannot get the result. can anybody work with this or help?

**Physics**

Did anyone got B_0 correct for Problem 1) f)?

**Physics**

Q3 part b I do not have yet, so if anyone has please help. Do you have Q1) f) B_0 for both cases? value and/or formula Anonymous?

**Physics**

OK try for b) 1.5 as n was in my part the answer. try for a) 0.60 and go up some decimals, 0.62.0.64 etc. it must be around that, because values are not very far away from that.

**Physics**

Also somebody could help with Problem 2: What is the value of k in radians per meter?

**Physics**

Q8) a)0.89 b)1.34 Rohan, experiment with some guesses if it does not fit, as you can see the number is quite narrow. I could not figure B_0 out but with your formula managed +-omega in both cases, can you help me with the formula please Rohan?

**Physics**

Rohan, is E_0=8.85418782*10^-12? I don't get the result with the speed of case 1 and 2.

**Physics**

OK, got a) can you help with c) for second problem Phy? maybe the value or formula.

**Physics**

Phy, sorry no formula, was an accident to get the value. But our values are not far off so try to guess a little it must be around my value. Your value did not work for me too. Could you tell me what the value for k and omega is please Phy?

**Physics**

Phy 4 Problem: 0 cos(pi/4) cos(pi/4) 0 -(E_0/c)*cos(pi/4) (E_0/c)*cos(pi/4) 0 cos(pi/4) -cos(pi/4) 0 (E_0/c)*cos(pi/4) (E_0/c)*cos(pi/4) PHy can you give the remaining answers for Problem 1 and 2?

**Physics**

sorry meant some missing from Problem 1, 2 and 3 missing.

**Physics**

Thanks Anonymous I have all other just some part from 1, 2 and 2 missing. If Phy or someone figures out please let us have it or the formula. thanks!

**Physics**

No prob Anonymous. 1)b) is 1.5 by the way, if you have slightly different values, make some guesses, it is normally around that value. with other values it is the same, it must be around that.

**Physics**

Anonymous, do you have 1 f?

**Physics**

Sorry Anonymous, just put the numbers in I don't have the formula. Problem 2: a)? b)1.5 c)First answer: (n*E_0)/c d)all 0 Do you have a) and second and third answer for c) phy?

**Physics**

a)0.197142857148 c)0.197142857148 b) any idea for this?

**PHYSIC**

Many thanks Pa!

**PHYSIC**

Thanks Access! Do you have HW3_2A and 2B?

**Physic**

Anyone?

**Physics**

Sorry DOnny, I did not have the formula until now X10 provided below for Problem 3, maybe enoiugh time: Part a and Part c: d/dt (l (sin((k lambda)/4-t omega)+sin(t omega)))/k where t=2.4*10^-16; omega=3.83*10^15; k=12775810.12; lambda=4.91*10^-7;l=1 Put this value in wolframal...

**Physics**

DOnny, values might vary you need to make some tries but they are usually around that value. Q3: a)0.197142857148 c)0.197142857148 b)? Q5 b) 0 (-4*E_0)/c E_0/c Q 6: a)0 0 (E_0/c)*cos(pi/1) b)0.0269 c)((2*pi)/8)*10^-10 I think the 8*10^10 is omega value for you but in my case i...

**Physics**

For B_0 the formula seems to be : E_0/c However, I cannot get the result. can anybody work with this or help?

**Physics**

Did anyone got B_0 correct for Problem 1) f)?

**Physics**

Which one DOnny? I might able to help

**Physics**

Thanks, now figured out DOnny! values are not far off. Anyone for B_0 Problem 3)b?

**Physics**

The rest I had already DOnny and the values are not very far apart, strangely enough, 1.46 for first part c) is not right in my case even experimenting with lower-higher values. Thanks for your help.

**Physics**

Thanks DOnny. I mean the question for What is the value of k in radians per meter? 5.5z I tried your formula (1.03e11)/(5.5*100) =187272727 This does not work for c) first part, can you help please?

**Physics**

DOnny, could you give us the formula for c) first part? 1.46 did not work for me. thanks By the way, d) all of them 0

**Physic**

Thanks Pa! HW3_2c: 0.79 mm 0.71 m ANyone had chances with others? HW3_2a: HW3_2b: or HW3_3?

**Physic**

Anyone for the first problem and others?

**Physic**

0.4 mm for last problem. Anyone for MPa first problem please?

**Physic**

Thanks Pa! Anyone for HW3_a, b, c,d?

**Physic**

Thanks Anonymous, do you have any of the HW3_3a, b, c, and d?

**Physic**

The last questions: 0.79 mm 0.69 m Anyone for the beggining questions please?

**Statistics**

E(S)= 0 Anyone for SE(S) and P(S=0) ?

**Physics**

a) R/L second a) ? b) 0.000828 c) 0 0.00226 Did anybody get second question a)?Express b in term of, if necessary, R , L , C .

**physics**

Great, thanks gluglu! Anyone for last question in Problem 1?

**physics**

Thanks, gluglu! do you have problem 2?

**physics**

Thanks Access! Where you successful with Problem 2 please? I could only manage 3 and 4. Thanks.

**Physics**

Got it! Anyone for Lightly Damped Undriven Circuit (last problem) a) Express b in term of, if necessary, R, L, C. ? and b) ? I have problems with formula.

**Physics**

I have 1360 as answer. Do you have Problem 4: An LRC Circuit a) and b) please Anonymous?

**physic**

0.4 mm for last problem. Anyone for MPa first problem please?

**Physics**

Helpless it is, 184 MPA Do you have figured out Problem 1 and 2?

**Physics**

No, sorry was not succesful, any other had chance with problems 1 and 2?

**Physics**

Thanks RORO, any luck with the second Problem set?

**Physics**

Thanks Anonymous now it worked. Have you had luck with Problem 2?

**Physics**

Anonymous, tried it out but it says rho_1 not allowed in answer. How did you manage?

**Physics**

Yes, must have something to do with tolerance RORO, try -0.73, there was technical issue before. RORO did you get problem 1 and 2 please?

**Physics**

-0.71 mm Problem 3) 184 MPA Anyone for Problem 1 and 2 please?

**maths**

0.0287

**maths**

a)0.2969 b)0.1347765

**Physics**

Anonymous, I think that is question 3 and was provided by X10. Just use the below formula, it works I tried. Q:3 for part a: B=E/v for part b: (L^2+h^2)/2L for part c: m=rqB/v

**Physics**

Great thanks X10! For Problem 4, second RL Circuit question, could you help with formula? I know that first and last are 0 but the middle one I cannot get.

**Physics**

Guys, I think the formula what X10 provided is for last problem on charged sphere not magnetic field of loop. The values can be found on it. X10 did you figure out Bz for magnetic field of a loop? and anyone for second RL circuit formula please?