Calculus
Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(t)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me m...
Minima Maxima
Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(t)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me m...
Followup-Calculus-Extrema
I got +/-4.99 and +/-7.99 when I typed the keyword 'local maximum x^2-4/(1+cos(x)^2)' into the equation box. It just gave me a list of maxima.
Followup-Calculus-Extrema
Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(t)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me m...
MATH HELP!!
Mr. Reiny's doing permutations. A permutation is when order matters. In this case, you can't have any ties: you can only have one person for first place, one person for second place, and similarly one person for third place. Therefore, there are 12 horses competing for...
Extrema-Check my work please?
Find and classify the relative maxima and minima of f(x) if f(x)= defint a=0 b=x function= t^2-4/(1+cos(x)^2) dt x^2-4/(1+cos(x)^2)= 0 x^2-4=0 x^2=4 x= +/- 2 So I got relative maximum as -2 and 2. And relative minimum as zero. However, when I graph it on Wolfram, it gives me m...
Sums-Calc
I see what I did now. Thanks
Sums-Calc
find the upper and lower bounds for definite integral sign, a=1, b=6, sqrt(x) dx. partitions are as follow: x0=1, x1= 3, x2=6 of the interval [1,6] upper sum: 3sqrt(3) + 3sqrt(6) lower sum: 3sqrt(3) + 3 but this is incorrect. can someone explain what i did wrong please
Upper-lower bounds-solved
find the upper and lower bounds for definite integral sign, a=1, b=6, sqrt(x) dx. partitions are as follow: x0=1, x1= 3, x2=6 of the interval [1,6] upper sum: 3sqrt(3) + 3sqrt(6) lower sum: 3sqrt(3) + 3 but this is incorrect. can someone explain what i did wrong please
definite integral
wow I didn't think it was so simple. thank you !
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